Function g can be thought of as a translated (shifted) version of f(x) = x^2

The numbers of hours per week teenagers spend playing a sport or outdoor game is 2.4 or 2[tex]\frac{1}{15}[/tex] hours.

What is Averaging?

This refers to the mean value, which is equal to the ratio of all the numbers added and divided by the number of a given set of values present in the set of values.

Average= x₁+x₂+x₃+x₄..........xn

                        n

Where,

x₁+x₂+x₃+x₄..........xn = Given set of values

                             n= Number of a given set of values

From the question:

The number of hour per week spent playing a port or a game outdoors:

3; 2; 0; 6; 3; 3; 3; 1; 1; 2

number of teenagers,n =10

Average= 3+ 2+ 0+ 6+3+3+3+ 1+ 1+2

                                  10

               =2.4 or 2[tex]\frac{1}{15}[/tex] hours.

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The perimeter of the smaller square would be = 12feet. That is option B.

Perimeter can be defined as the summation of all the sides and edges of an object.

Scale factor is also defined as the ratio of difference between an original object and a newly formed object.

A square has four sides and it's perimeter = 24 ft

This means that the sides of the square= 24/4 = 6ft.

If the original (smaller square) dialted by a factor of 1/2 to have 6 ft as its sides, it means that it's original side of the small square is 3ft.

This is because to form the bigger square, 1/2 × 6 = 3ft.

Therefore, the perimeter of small square = 3+3+3+3 = 12ft.

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The nth term of this quadratic sequence 4,9,16,25,36 is [tex]n^{2} + 2n + 1[/tex]

Given that:

the given sequence is 4,9,16,25,36

nth term of quadratic sequence is [tex]an^{2}+bn+c[/tex]

Now lets find out the value of each variable a,b,c

a = second difference divide by 2

lets find out second difference

4,9,16,25,36

the first difference between the terms are

5,7,9,11

The second difference between the terms

2,2,2

the value of a = second difference / 2

[tex]a = \frac{2}{2} = 1\\[/tex]

a = 1

Now we find the value of b

3a + b = first term of first difference

3a + b = 5

3(1) + b = 5

3 + b = 5

b = 5 - 3

b = 2

Now find the value of c

a + b + c = first term

a + b + c = 4

1 + 2 + c = 4

3 + c = 4

c = 1

Now we replace all the values to find the nth term

 [tex]an^{2}+bn+c\\ \\n^{2}+2n+1[/tex]

Hence the answer is the nth term of this quadratic sequence 4,9,16,25,36 is [tex]n^{2} + 2n + 1[/tex].

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It is possible that the ball may reach a height of 5 meters in accordance with the quadratic formula.

The height of the ball as a function of time is represented by a quadratic equation, in which we must determine if the ball may reach a height of 5 meters. First, substitute the height in the quadratic equation:

- 5 · t² + 9 · t + 2 = 5

5 · t² - 9 · t + 3 = 0

Second, use the quadratic formula to determine the roots of the resulting quadratic equation:

t = - (- 9) / (2 · 5) ± [1 / (2 · 5)] · √[(- 9)² - 4 · 5 · 3]

t = 9 / 10 ± (1 / 10) · √(81 - 60)

t = 9 / 10 ± √21 / 10

t = (9 ± √21) / 10

Since all roots of the quadratic equations are real, then the ball can reach a height of 5 meters above the ground.

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[tex](\stackrel{x_1}{-8}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-10}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-8)}}} \implies \cfrac{-18}{1 +8} \implies \cfrac{ -18 }{ 9 } \implies - 2[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{- 2}(x-\stackrel{x_1}{(-8)}) \implies y -8 = - 2 ( x +8) \\\\\\ y-8=-2x-16\implies {\Large \begin{array}{llll} y=-2x-8 \end{array}}[/tex]

The length of x is 4.1.

Given:

Base = 9 + 4.5 = 13.5

From figure:

= [tex]\sqrt{9^{2}+5^{2} }[/tex]

= [tex]\sqrt{81+25}[/tex]

= [tex]\sqrt{96}[/tex]

= 9.797

4.5 opposite is equal to 4.5.

5 opposite equal to 5 and remaining to x - 5.

According to pythagorean theorem:

= [tex]\sqrt{4.5^{2}+(x-5)^{2} }[/tex]

[tex]13.5^{2} +x^{2} =(\sqrt{96}+\sqrt{4.5^{2} +(x-5)^{2} })^{2}[/tex]

[tex]\sqrt{13.5^{2} +x^{2} }[/tex] - [tex]\sqrt{96} = \sqrt{20.25+x^{2} +25 -10x}[/tex]

squaring on both sides

182.25 + [tex]x^{2}[/tex] - 96 = [tex]x^{2}[/tex] - 10x + 45.25

10x = 45.25 + 96 - 182.25

10x = 41

x = 4.1.

Therefore the value of x is 4.1.

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The value of the fraction 28/63 in the simplest form is 4/9.

A fraction is simply a piece of a whole. The number is represented mathematically as a quotient where the numerator and denominator are split. In a simple fraction, the numerator as well as the denominator are both integers.

In this case, we want to reduce 28/63 yo the simplest term. This will be illustrated thus:

= 28/63

= (7 × 4) / (9 × 7)

= 4 / 9

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Answer:

angle a = 74 degrees

angle b = 106 degrees

angle c = 106 degrees

angle d = 65 degrees

angle e = 65 degrees

Step-by-step explanation:

Angle a:

the Alternate Interior Angles Theorem makes angle a equal to 74 degrees

Angle b:

First find angle c, and angle b is equal to angle c because angle b and c are Corresponding angles

Angle c:

angle c = 180 degrees - 74 degrees

angle c = 106 degrees

Angle d:

angle d corresponds with 65 degrees, therefore the are the same.

Angle e:

angle d and e are opposite angles, therefore they are the same.

Answer: T= 1

Step-by-step explanation:

the slope of the given point is m=−3/4

1353 numbers of minutes he has used his phone in a month.

What do you mean by algebraic expression?

In mathematics, an algebraic expression is an expression composed of integer constants, variables, and algebraic operations (addition, subtraction, multiplication, division, and exponentiation by exponents that are rational numbers).

Algebraic equations are equations that contain only algebraic expressions.

Algebraic expression is the idea of ​​using letters or alphabets to represent numbers without specifying the actual value. Algebra Basics taught us how to use letters like x, y, and z to represent unknown values. These characters are called variables here.

It is given that Chang pays a monthly fee of $27, and he pays an additional $0.07 per minute of use.

Let m be the additional minutes

Then charge for additional minutes is $0.07m

Now , it is also given that least he has been charged in a month is

$121.71.

⇒ 0.07m + 27 = 121.71

⇒ 0.07m = 121.71 - 27

⇒ 0.07m = 94.71

⇒ m = 94.71/0.07 = 1353

Therefore, 1353 numbers of minutes he has used his phone in a month.

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Answer:

1/2

Step-by-step explanation:

(-6-(-4)/(3-7)

(-6+4)/-4

-2/-4

1/2

Answer:

enter a function and from there you approximate hope it helps

The value is 5/2 and 35/2 pounds.

Comparing two amounts of the same units and determining the ratio tells us how much of one quantity is in the other. Two categories can be used to categorize ratios.

Part to whole ratio is one, and part to part ratio is the other. The part-to-part ratio shows the relationship between two separate entities or groupings.

For instance, a class has a 12:15 boy-to-girl ratio, whereas the part-to-whole ratio refers to the relationship between a particular group and the entire.

The ratios of  the given table

Table 10,

[tex]\begin{aligned}&\Rightarrow \frac{5}{3}=\frac{1}{x} \\&\Rightarrow x=\frac{3}{5} \\&\Rightarrow \frac{5}{3}=\frac{12}{x}=\frac{12+3}{15} \\&\Rightarrow x=\frac{12}{5}\end{aligned}[/tex]

Table 9,

[tex]\begin{aligned}&\frac{10}{4}=\frac{5}{2} \\&\frac{5}{2}=\frac{x}{1} \\&x=\frac{5}{2} \\&\frac{5}{2}=\frac{x}{7} \\&x=\frac{35}{2}\end{aligned}[/tex]

[tex]\begin{array}{rccc}\text { 9) pounds } & 10 & \frac{5}{2} & \frac{35}{2} \\\text { Weeks } & 4 & 1 & 7 \\\text { 10) tons } & 5 & 1 & 12 \\\text { days } & 3 & \frac{3}{5} & \frac{12}{5}\end{array}[/tex]

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The number of pairs that must be randomly selected from the set {1,3,5,7,9,11,13,15} to guarantee that at least one pair of these numbers add up to 16 is 5.

In the given set {1,3,5,7,9,11,13,15}, there are four pairs that sum up to 16, which are (1,15), (3,13), (5,11), and (7,9). Let k numbers be picked from the set. Consider k = 5, then using the pigeonhole principle, for one of the pairs described above, both of the endpoints must have been picked. Hence, if 5 numbers are picked from the set, then there exists a pair with a sum of 16.

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Answer: The number of no votes is 1876 votes.

What is the ratio?

"The ratio is a term that is used to compare two or more numbers. It is used to indicate how big or small a quantity is when compared to another".

For the given situation,

Let x be the number of votes.

The ratio of yes votes : no votes = 3x:2x

Total = 5x

Total votes = 4690 votes

⇒

Divide by 5 on both sides,

⇒

Thus the number of no votes =

⇒

⇒

Hence we can conclude that the number of no votes is 1876 votes.

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Step-by-step explanation:

The statement that best compares the graph of G(x) with the graph of F(x) is the graph of G(x) is the graph of F(x) compressed vertically, flipped over the x-axis, and shifted 7 units to the left.

According to the question,

We have the following information:

F(x) = x² and G(x) = -1/4 (x+7)²

Now, the graph of G(x) will be the graph of F(x) but there will be certain changes in the graph according to its function.

Now, in this function, 7 is added to x then it means that it will shift 7 units to left.

There is a negative sign before the function which says that is flipped over the x-axis.

Now, the factor 1/4 in the multiplication says that it has been compressed.

Hence, the correct option is D.

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Answer:

4/9

Step-by-step explanation:

Area of a triangle is 1/2*base*height

1/2*2/3*4/3 = 8/18 = 4/9

Answer:

x = 13  x = 1

Step-by-step explanation:

(13-7) = 6

6^2 = 36

1-7 = -6

(-6)^2 = 36

Answer:

3.82%

Step-by-step explanation:

If in a class of 25 students, 14 are boys and 11 are girls. On a unit test, 6 boys and 6 girls made an A grade. If a student is chosen at random from the class, The probability of choosing a boy or an A student 4 / 5

From the question, we have the following data

Total number of students = 25

The total number of boys = 14

The students that are A male students = 6

Then we would have probability of having an A male student to be:

Total boys + A male students / total

= 14 + 6 / 25

= 4 / 5

Hence the probability is 4 / 5

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Answer:

a is right (prime number is always a even number)

Answer:

A.

a prime number may be an even or an odd number

Since in the question we reject the alternative hypothesis hence type II error occurs.

What is Type I error?

When the null hypothesis is true but rejected in hypothesis testing, type 1 errors often confused with false positives occur. A general assertion or default attitude that there is no connection between two measurable phenomena is known as the null hypothesis.

What is Type II error?

Type II errors take place when you fail to reject the null hypothesis even though it is untrue.

The average number of insect parts per 100 gm in this problem is 75. This number cannot be demonstrated by the test to be larger than 75. This indicates that the test is producing a "false negative" since it is not detecting these insect parts.

Hence, this is a Type II error.

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Answer:

6

Step-by-step explanation:

Each coordinate is six times the corresponding coordinate in the preimage.

Answer:

4 metters por el significado

Circumference = pi x d

Circumference = 3.14 x 24 =  75.36

I hope this helps!

The statement “A teacher compares the pretests and posttest scores of students” is an example of matched pairs design.

Given data;

A teacher contrasts the results of her class's standardized test with the entire country's results. An instructor contrasts the results of the students' pre-and post-tests. A teacher computes the average grade received by students on two tests and checks to see if it is greater than 80%. An instructor contrasts the results of students who were taught using a computer-based method with those of post-students whose students ought to use a more conventional approach.

⇒

The statement “A teacher compares the pretests and posttest scores of student” using here would be approach-test because the sample “the students’ scores” are being compared with the two different treatments” and pretest and posttest scores.

A matched pairs design is demonstrated with the sentence "A teacher compares the pretests and posttest scores of students."

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