Fred's teacher gave the class the
quadratic function f(x) = 4x² + 16x+9
State two different methods Fred could use to solve the equation f(x) = 0.

Using one of the methods stated in part a, solve f(x) = 0 for x, to the nearest
tenth.

Answer:

[tex]f(x)= \sin(6x)+3[/tex]

Step-by-step explanation:

The parent function of this graph is:  y = sin(x)

The sine function is periodic, meaning it repeats forever.

Standard form of a sine function:

[tex]f(x) = \sf A \sin (B(x + C)) + D[/tex]

The parent function y = sin(x) has the following:

From inspection of the given graph:

[tex]\sf If\:Period=\dfrac{\pi}{3} \implies \dfrac{2 \pi}{B}=\dfrac{\pi}{3}\implies B=6[/tex]

Substituting the values into the standard form:

[tex]\implies f(x) =1 \sin (6(x + 0)) + 3[/tex]

[tex]\implies f(x) = \sin (6x) + 3[/tex]

Therefore, the equation of the given trigonometric graph is:

[tex]f(x)= \sin(6x)+3[/tex]

Answer(s):

[tex]\displaystyle y = cos\:(6x - \frac{\pi}{2}) + 3 \\ y = -sin\:(6x \pm \pi) + 3 \\ y = sin\:6x + 3[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{12}} \hookrightarrow \frac{\frac{\pi}{2}}{6} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{3}} \hookrightarrow \frac{2}{6}\pi \\ Amplitude \hookrightarrow 1[/tex]

OR

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{3}} \hookrightarrow \frac{2}{6}\pi \\ Amplitude \hookrightarrow 1[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cos\:6x + 3,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{12}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{12}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{12}} = \frac{\frac{\pi}{2}}{6}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = cos\:(6x - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-\frac{5}{12}\pi, 2],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{12}, 2],[/tex]they are obviously [tex]\displaystyle \frac{\pi}{3}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{3}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Hello, the detailed solution is given below.

Lines L and M are parallel. That's why [tex]B[/tex] angle and [tex]50^{o}[/tex] are equal.

Co-interior angles lie between two lines and on the same side of a transversal. If the two lines are parallel, then co-interior angles add to give [tex]180^{o}[/tex] and so are supplementary.

After that, [tex]C[/tex] angle found as [tex]85^o[/tex].

As [tex]A[/tex] angle and [tex]C[/tex] angle must be equal due to the parallel, the missing angles as;

[tex]A=85\\B=50\\C=85[/tex]

Good luck! If you have any questions, then feel free to ask in comments!

The solution to the equation x² – 4x + 4 = 2x + 1 + x² is x = 2.5 and the graph is shown in the picture.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have an equation:

x² – 4x + 4 = 2x + 1 + x²

After solving:

-4x + 4 = 2x + 1

6x = 3

x = 1/2 = 0.5

Thus, the solution to the equation x² – 4x + 4 = 2x + 1 + x² is x = 2.5 and the graph is shown in the picture.

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Answer:

b. 15%

Step-by-step explanation:

because it is 3 oranges and 3 is equal to 15%

Answer:

172

Step-by-step explanation:

100 + 24 ÷ 4 × 12

Remember PEMDAS

100 + 6 × 12

100 + 72

172

Hope this helps!

Based on the calculations, the measure of angle Q to the nearest whole degree is equal to 53°. The correct answer is option C.

The complete question is attached with the answer below.

The angle is defined as the span between two intersecting lines or surfaces at or close to the point where they meet.

Based on the triangle attached in the image above, we can deduce the following parameters:

Side QM = 18 units.

Side MN = 17 units.

Side QN = 20 units.

In this scenario, we would apply the cosine trigonometry function to determine the measure of angle Q:

MN² = QM² + QN² - 2(QM)(QN)cosθ

17² = 18² + 20² - 2(18)(20)cosθ

289 = 324 + 400 - 720cosθ

720cosθ = 724 - 289

720cosθ = 435

θ = cos⁻¹(435/720)

θ = cos⁻¹0.6042

θ = 52.8 ≈ 53°.

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Answer:





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Question



A father is 30years older than his son. In 12years, the man will be three times as old as his son. Find their present ages.

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Solution



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Let the present age of the son be x years

Then father's age will be (x+30) years

Given after 12 years father will be three times as old as his son

Therefore,

(x+12)3=x+30+12

3x+36=x+42

3x−x=42−36

2x=6

x=3

x+30=3+30=33

So, the present age of son is 3 years and present age of the father is 33 years

Answer:

[tex]k=4[/tex]

Step-by-step explanation:

Using the diagram, we can conclude that the given angles are vertical angles. Vertical angles are opposite angles that are formed when two lines intersect. Vertical angles are always congruent.

Using this information we can set up an equation.

[tex]7k-6=2k+14[/tex]

Subtract 2k from both sides.

[tex]7k-2k-6=2k-2k+14\\5k-6=14[/tex]

Add 6 to both sides

[tex]5k-6+6=14+6\\5k=20[/tex]

Divide both sides by 5

[tex]\frac{5k}{5}=\frac{20}{5}\\k=4[/tex]

CHECK:

7(4) - 6 = 28 - 6 = 22

2(4) + 14 = 8 + 14 = 22

22 = 22

Answer:

A) -4, -2

Step-by-step explanation:

The translation vector is the distance

point A: (3, 1)

point A': (-7, -3)

3 + (-7) = -4

1 + (-3) = -2

The amount of glue that eric used for his project is [tex]\mathbf{ 1\dfrac{11}{16}}[/tex]

The interpretation of the line plot involves a careful approach to how a series of data points are connected on coordinate planes.

From the Glue for summer project line plot:

The amount of glue Eric used for the project is;

[tex]\mathbf{=\dfrac{3}{4}\times 2\dfrac{1}{4}}[/tex]

[tex]\mathbf{=\dfrac{3}{4}\times \dfrac{9}{4}}[/tex]

[tex]\mathbf{=\dfrac{27}{16}}[/tex]

[tex]\mathbf{= 1\dfrac{11}{16}}[/tex]

Therefore, we can conclude that the amount of glue used by Eric for this project is: [tex]\mathbf{ 1\dfrac{11}{16}}[/tex]

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Answer:

  84 cm²

Step-by-step explanation:

The figure has a uniform horizontal cross section, so its area is the product of that cross section length and its vertical dimension.

__

  A = bh

  A = (6 cm)(14 cm) = 84 cm²

The area of the shape is 84 square centimeters.

_____

Additional comment

You could decompose the figure into a rectangle with base 6 and height 8, and a parallelogram with base 6 and height 14-8=6. The area formula is the same for each: A = bh, so the area of the composite figure is ...

  A = 6×8 +6×(14 -8)

  = 6×(8 +(14 -8))

  = 6×14 . . . . same as above.

Answer:

the answer is 3

Answer:

Hi,

Step-by-step explanation:

Let's say y=a*b^x the equation of the exponential function.

0.9=a*b^1 (1)

1.62=a*b² (2)

(2)/(1) ==> b=1.62/0.9=1.8

and

0.9=a*1.8 ==> a=0.5

y=0.5*1.8^x

answer:

483.5

step by step explanation:

2x-45y=22

2x-45(21)=22

2x-945=22

2x =22+945

2x=967

x=483.5

Answer:

Step-by-step explanation:

Volume = (1/3) * base_area * height

1/3 * 4 * 4 * 9 =

48 cm³

Answer: B.

Explanation and reasoning:

Using the given information, the diver's score is 6.2

From the question, we are to calculate the diver's score

From the given information,

The five judges score a dive as 6.0, 6.3, 6.2, 6.8, and 6.1.

Since the highest and lowest scores are discarded

Then, we will discard 6.8 and 6.0

The remaining scores are 6.1, 6.2, and 6.3

Now, the diver's score will be the average of the remaining scores

∴ The diver's score = (6.1 + 6.2 + 6.3) /3

The  diver's score = 18.6 / 3

The diver's score = 6.2

Hence, the diver's score is 6.2

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Answer:

1) (9/20)x  2) (11/20)x

Step-by-step explanation:

x = total area of the field.

In the first two days he plowed (1/5)x + (1/4)x = (9/20)x

He still needs to plow x - (9/20)x = (11/20)x

Answer:

206.17

Key(s):

[tex]A = 2\pi \frac{d}{2} h + 2\pi \left(\frac{d}{2}\right)^2[/tex]

Substitute d for the actual diameter, 7.5, and h for the height, which is 5.

Step-by-step explanation:

[tex]A = 2\cdot\pi \cdot\frac{7.5}{2} \cdot5 + 2\cdot\pi \cdot\left(\frac{7.5}{2}\right)^2[/tex] ≈ 206.17(2 DP)

Answer:

x = 5 and y = 22

Step-by-step explanation:

See attached image.

Answer:

Based on the data given on Northlake High School, we can infer that B. A greater percentage of second-lunch students (39%) eat outside.

What does the data on the First and Second lunches show?

The percentage of second-lunch students who eat outside is:

= Second lunch students who eat outside / Second lunch students

Solving gives:

= 0.18 / 0.46 x 100%

= 0.3913 x 100%

= 39%

This shows that the percentage of students eating their second lunch outside is 39%.

so the answer is B

Step-by-step explanation:

Answer:

212

Step-by-step explanation:

85 here is 100%

And 900 is also 100%

That's for the different comparisons. So now, what we do is, we should divide 85 by 900, and then, whatever is our answer, multiply that by 20.

That is surely going to equal how many students are going to say that Math is Awesome for 900 student survey.

Step 1

85/900=10.5882352941

Let's round that to make it

10.5

Step 2

10.5x20=210

That means, if we go exactly, like multiplying all of those numbers, then our answer should be 212 or 200.

Just to be sure that our answer is correct, we will do it with 10.58 now.

Step 3

10.58x20=211.6

So now it looks like it's most probably going to be 212

But still, let's do 10.588 now.

Step 4

10.588x20=211.76

Okay, let's do it again, with 10.5882

Step 5

10.5882x20=211.764

Okay, so I just multiplied the whole number this time, and I still got a decimal, so that means that your answer is 212 basically.

The value of the variable a is 19.66 and the value of the valriable b is 20.21.

For any triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c,

we have, by the law of sines,

[tex]\rm \dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b} = \dfrac{sin\angle C}{c}[/tex]

Remember that we took

The sine angle is the length of the side opposite to that angle.

Then the third angle of the triangle will be

x + 75 + 35 = 180

                x = 70

[tex]\rm \dfrac{\sin 75^o}{b} = \dfrac{\sin 35^o}{12} = \dfrac{\sin 70^o}{a}[/tex]

From the first two-term, we have

sin 75 / b = sin 35 / 12

b = 20.21

From the last two-term, we have

sin 70 / a = sin 35 / 12

a = 19.66

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Explanation:

Provided 2 length sides and one angle also need to find one missing side.

So, use cosine rule:

a² = b² + c² - 2bc cos(A)

c² = 9² + 11² - 2(11)(9) cos(57)

c² = 94.16147

c = √94.16147 = 9.70 cm

d² = 5² + 7² - 2(5)(7) cos(48)

d² = 27.16

d = √27.16 = 5.21

5² = 7² + 9² - 2(7)(9) cos(H)

-126cos(H) = 25 - 49 - 81

cos(H) = -105/-126

cos(H) = 5/6

H = cos⁻¹(5/6) = 33.56°

8² = 4² + 7² - 2(4)(7) cos(J)

-56cos(J) = 64 - 16 - 49

cos(J) = -1/-56

J = cos⁻¹(1/56) = 88.98°

Passcode: 3142

Answer:

it would end up being about $40.73

Step-by-step explanation:

multiply 0.078 by 3 then multiply that by 33

Answer:

hope you can understand

Answer:

what ya need man I can help but give me a question