Solute content in 50.0 mL of 0.488 M K4[Cu(CN)6] is 10.3 g.
The solution has a molarity of 0.0757 M.
In 439 mL of 0.0250 M CuSO4 solution, 1.75 g of solute is contained.
a. The first step is to use the formula:
number of moles = Molarity × volume (in liters)
We need to convert the given volume (in mL) to liters by dividing it by 1000:
50.0 mL = 50.0/1000 = 0.0500 L
Now we can substitute the given values and solve for the number of moles:
number of moles = 0.488 mol/L × 0.0500 L = 0.0244 mol
Finally, we can convert the number of moles to grams using the molar mass of K4[Cu(CN)6]:
mass of solute = number of moles × molar mass = 0.0244 mol × 422.88 g/mol = 10.3 g
Therefore, 50.0 mL of 0.488 M K4[Cu(CN)6] contains 10.3 g of solute.
b. We can use the formula:
Molarity = number of moles/volume (in liters)
First, we need to convert the given mass (in grams) to moles using the molar mass of (NH₄)₂SO₄:
number of moles = 4.00 g / 132.14 g/mol = 0.0303 mol
Next, we need to convert the given volume (in mL) to liters by dividing it by 1000:
400.0 mL = 400.0/1000 = 0.400 L
Now we can substitute the given values and solve for the molarity:
Molarity = 0.0303 mol / 0.400 L = 0.0757 M
Therefore, the molarity of the solution is 0.0757 M.
c. We can use the formula:
number of moles = Molarity × volume (in liters)
First, we need to convert the given mass (in grams) to moles using the molar mass of CuSO₄:
number of moles = 1.75 g / 159.61 g/mol = 0.01097 mol
Now we can substitute the given values and solve for the volume (in liters):
0.01097 mol = 0.0250 mol/L × volume (in L)
volume (in L) = 0.01097 mol / 0.0250 mol/L = 0.439 L
Finally, we can convert the volume to mL by multiplying by 1000:
volume (in mL) = 0.439 L × 1000 mL/L = 439 mL
Therefore, 1.75 g of solute in 0.0250 M CuSO₄ solution is present in 439 mL of solution.
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Baliz reply asap, help indeed needed lol
In the SI system of units [International System of Units], the mole is one of seven base units. It is frequently used in chemical calculations. However, a mole of something is just a particular quantity of it. It is not a unit of measure in the way that meters, seconds, and kilograms are. Calculations performed with the number of moles of a substance could also be performed with the number of particles of a substance. Based on this information, do you think that the mole should be considered a base unit in the SI system? Explain why or why not.
Based on the information given, the mole should be considered a base unit in the SI system because it serves as a universally accepted measure of the amount or quantity of substances.
The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
SI units refer to units of measurement that are universally accepted for measuring the properties of quantities of objects.
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Red light has a __________ wavelength than violet light
Red light has a longer wavelength than violet light. Wavelength is the distance between two consecutive peaks or troughs of a wave, and it determines the color of light. The range of visible light wavelengths is between approximately 400 nanometers (nm) for violet light to 700 nm for red light. So, red light has a longer wavelength and lower frequency than violet light.
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41.6 g Al(NO3)3m Are added to a flask, how many liters of water should be added to create a 0.450 M solution?
To calculate the volume of water needed to create a 0.450 M solution of Al(NO3)3, we need to use the formula:
Molarity = moles of solute / volume of solution in liters
First, we need to determine the number of moles of Al(NO3)3 we have:
moles of Al(NO3)3 = mass / molar mass
molar mass of Al(NO3)3 = 1 x atomic mass of Al + 3 x atomic mass of N + 9 x atomic mass of O = 1 x 26.98 + 3 x 14.01 + 9 x 16.00 = 212.99 g/mol
moles of Al(NO3)3 = 41.6 g / 212.99 g/mol = 0.195 mol
Next, we can rearrange the formula above to solve for the volume of solution:
volume of solution = moles of solute / molarity
volume of solution = 0.195 mol / 0.450 M = 0.433 L
Therefore, we need to add 0.433 L (or 433 mL) of water to 41.6 g of Al(NO3)3 to create a 0.450 M solution.
Calculate the heat change in joules for melting 12.0 g
of ice at 0 ∘C
The heat change required to melt 12.0 g of ice at 0°C is 4,002.6 joules.
To calculate the heat change in joules for melting 12.0 g of ice at 0°C, we need to use the specific heat of fusion of ice and the heat equation. The specific heat of the fusion of ice is 333.55 J/g.
The heat equation is:
Q = m × ΔH
where Q is the heat change, m is the mass of the substance, and ΔH is the specific heat of fusion.
Therefore, the heat change required to melt 12.0 g of ice at 0°C can be calculated as follows:
Q = 12.0 g × 333.55 J/g
Q = 4,002.6 J
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what is chemical equitation
Answer:
A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities on the right-hand side.
Explanation:
Good luck!
Answer:
A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and chemical formulas.
What is in a chemical equation?
A chemical equation (see an example below) consists of a list of reactants (the starting substances) on the left-hand side, an arrow symbol, and a list of products (substances formed in the chemical reaction) on the right-hand side.
Hope this helps :)
Pls brainliest...
In a certain experiment, 0.969 mol sampe of Cu is allowed to react with 246mL of 6.60M HNO3 according to the following reaction:
Cu(s) + HNO3(aq) -> Cu(NO3)2(aq) + H2O + NO(g)
a) What is the limiting reactant?
b) How many grams of H2O is formed?
C) How many grams of the excess reactant remain after the limiting reactant is completely consumed?
The moles of Nitric Acid present (1.6244 mol) is more than twice the moles of Cu (0.969 mol). Therefore, Copper is the limiting reactant. Therefore, 17.45 g of water is formed. Since we can't have negative moles.
How is the limiting reactant determined?The number of moles of each reactant can be calculated by dividing the volume of each solution by its molarity. You can identify which reactant is the limiting one in the balanced chemical equation by dividing the number of moles of each reactant by its stoichiometric coefficient.
a) Calculating the moles of copper and nitric oxide and comparing their stoichiometric ratios will help us identify the limiting reactant.
From the given information, the moles of Cu is 0.969 mol.
The moles of Nitric Acid can be calculated using the formula:
moles of Nitric Acid = (molarity) x (volume in liters)
moles of Nitric Acid = (6.60 mol/L) x (246/1000 L)
moles of Nitric Acid = 1.6244 mol
The balanced equation shows that 1 mol of Cu reacts with 2 mol of Nitric Acid.
The moles of Nitric Acid present (1.6244 mol) is more than twice the moles of Copper (0.969 mol). Therefore, Copper is the limiting reactant.
b)We can see from the balanced equation that 1 mol of Copper reacts to create 1 mol of water. As a result, the amount of Water generated will be 0.969 mol, which is identical to the amount of Copper that was reacted.
mass of water = moles of water x molar mass of water, where the molar mass of water is 18.015 g/mol.
mass of water = 0.969 mol x 18.015 g/mol
mass of water = 17.45 g (rounded to two decimal places)
Therefore, 17.45 g of water is formed.
c) Copper is the limiting reactant, hence no Nitric Acid will be completely oxidised. We must first figure out how many moles of Nitric Acid are needed to react with all of the Copper in order to compute how much extra Nitric Acid is still there.
From the balanced equation, we know that 1 mol of Cu reacts with 2 mol of Nitric Acid. Therefore, the moles of Nitric Acid required to react with 0.969 mol of Copper will be:
moles of Nitric Acid = 2 x 0.969 mol
moles of Nitric Acid = 1.938 mol
The initial moles of Nitric Acid present is 1.6244 mol. Therefore, the moles of excess Nitric Acid remaining after the reaction is:
moles of excess Nitric Acid = initial moles of Nitric Acid - moles of Nitric Acid required
moles of excess Nitric Acid = 1.6244 mol - 1.938 mol
moles of excess Nitric Acid = -0.3136 mol
Since we can't have negative moles, we know that all of the Nitric Acidwill be consumed, and there is no excess Nitric Acid remaining.
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CAN SOMEONE HELP WITH THIS QUESTION?
If the weight of Magnesium Metal is 0.6 g
1- FIND MOLES OF magnesium METAL
2- FIND CHANGE IN T CALORIMETER
3- Find q calorimeter
4- Find q reaction
5- Find the change in heat reaction per mole of Mg consumed
1- FIND MOLES OF magnesium METAL
Moles of Magnesium Metal = 0.6 g/24.31 g/mol = 0.0246 mol
What is Magnesium?Magnesium is a silvery-white alkaline earth metal that is a very abundant element in the Earth's crust. It is the eighth most abundant element in the universe.
2- FIND CHANGE IN T CALORIMETER
The change in temperature of the calorimeter is not given, so it cannot be calculated.
3- Find q calorimeter
The heat absorbed or released by the calorimeter is qcalorimeter = mCΔT, where m is the mass of the calorimeter, C is the specific heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter. Since the mass and change in temperature of the calorimeter are not given, qcalorimeter cannot be calculated.
4- Find q reaction
The heat absorbed or released by the reaction is qreaction = nCΔT, where n is the number of moles of the reactant, C is the specific heat capacity of the reaction, and ΔT is the change in temperature of the reaction. Since the number of moles of the reactant and change in temperature of the reaction are not given, qreaction cannot be calculated.
5- Find the change in heat reaction per mole of Mg consumed
The change in heat per mole of Mg consumed is qMg = qreaction/n, where qreaction is the heat absorbed or released by the reaction and n is the number of moles of Mg. Since qreaction and n are not given, qMg cannot be calculated.
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What materials formed the solar system?
Answer:
The solar system formed from a cloud of gas and dust, known as the solar nebula, that collapsed under its own gravity about 4.6 billion years ago. As the solar nebula collapsed, it formed a spinning disk of gas and dust, with most of the material concentrated at the center. Over time, the material in the disk began to clump together due to gravity, forming small rocky and icy planetesimals, which collided and merged to form larger bodies. These larger bodies eventually became the planets, moons, asteroids, and other objects that make up the solar system today. The exact composition of the solar nebula and the materials that formed the solar system varied depending on the distance from the Sun and the temperature and pressure conditions in different regions of the nebula. Generally, the inner solar system (including the Sun, Mercury, Venus, Earth, and Mars) is composed mostly of rocky materials, while the outer solar system (including the gas giants Jupiter, Saturn, Uranus, and Neptune, as well as the dwarf planet Pluto) is composed mostly of ices, such as water, ammonia, and methane, as well as gases like hydrogen and helium.
short term answer: dust and gas.
Explanation: learned it in 5th grade science class, bye have a great day !
1. What will be the final concentration of the solution indicated that will result from the
following dilutions?
a. 14.0 ml of a 4.2 M Na2CO3 solution is diluted to 86.0 ml.
Taking into account the definition of dilution, the final concentration of the solution is 0.68 M.
Definition of dilutionDilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, and the volume of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal concentrationIn this case, you know:
Ci: 4.2 MVi: 14 mLCf: ?Vf: 86 mLReplacing in the definition of dilution:
4.2 M× 14 mL= Cf× 86 mL
Solving:
(4.2 M× 14 mL)÷ 86 mL= Cf
0.68 M= Cf
In summary, the final concentration is 0.68 M.
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What would the expected temperature change be (in F) if 0.5 gram sample of water released 0.0501 j of heat energy? The specific heat of liquid water 4.184 j/g
The expected temperature change would be approximately 4.32°F if 0.5-gram sample of water released 0.0501 j of heat energy.
The specific heat of a substance is the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius. The expected temperature change can be calculated using the formula:
q = m × c × ΔT
where q is the heat energy released, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.
Rearranging the formula to solve for ΔT, we get:
ΔT = q ÷ (m × c)
Substituting the given values, we get:
ΔT = 0.0501 J ÷ (0.5 g × 4.184 J/g°C)
ΔT ≈ 2.4°C or 4.32°F
When a substance undergoes a change in temperature, it either gains or loses heat energy.
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Fill the blanks
According to the Arrhenius definition, acids produce ---------------- ions when dissolved in water, and bases produce -------------------- ions when dissolved in water.
A) Protons, ammonium
b) Hydroxide, hydronium
C) ammonium, hydronium
d) hydronium, hydroxide
The Correct answer is D
Hydronium
hydroxide
Among the elements of the main group, the first ionization energy increases
from left to right across a period.
from right to left across a period.
when the atomic radius increases.
down a group.
The first ionisation energy increases over time from left to right among the major group of elements. answer is option (a).
What is Ioniztion?When an element loses its valence electron, its oxidation number increases (a process known as oxidation), and this energy loss is known as ionisation (Ei).
Earth alkaline metals, which are located immediately next to alkaline metals, have higher ionisation energies than alkaline metals because they have two valence electrons, while alkaline metals, which are located far left in the main group, have the lowest ionisation energies and are easiest to remove.
Because they contain a large number of valence electrons, nonmetals are far to the right in the main group and have the highest ionisation energy.
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The complete question is,
Among the elements of the main group, the first ionization energy increases
a. from left to right across a period.
b. from right to left across a period.
c. when the atomic radius increases.
d. down a group.
Reaction 1 : 4 NH 3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l) ΔG° = −1010 kJ/molrxn
Reaction 2 : 2 NO 2(g) → 2 NO(g) + O2(g) ΔG° = 70 kJ/molrxn
Reaction 3 : 4 NO 2(g) + O2(g) + 2 H2O(l) → 4 HNO 3(aq) ΔG° = −170 kJ/molrxn
Based on the values of ΔG° for the three reactions represented above, what is the value of ΔG° for the reaction
represented below?
4 NH3(g) + 8 O2(g) → 4 HNO 3(aq) + 4 H2O(l)
(A) −1040 kJ/molrxn
(B) −1110 kJ/molrxn
(C) −1250 kJ/molrxn
(D)−1320 kJ/molrxn
* Please explain how you got to the answer you did
Based on the values of ΔG° for the three reactions represented above, the value of ΔG° for the reaction given is −1320 kJ/molrxn. The correct option is D.
To determine the value of ΔG° for the given reaction, we can use Hess's law, which states that the change in enthalpy (ΔH) for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the original reaction.
The same principle applies to Gibbs free energy (ΔG), so we can use the ΔG° values for the three given reactions to calculate the ΔG° for the target reaction.
We can use Reaction 1 and Reaction 2 to obtain the following overall reaction, which is the reverse of Reaction 3:
[tex]4 NH_3(g) + 6 O_2(g) --- > 4 NO(g) + 6 H_2O(l)[/tex] ΔG° = 1010 kJ/molrxn
[tex]2 NO_2(g) + O_2(g) --- > 2 NO(g) + O_2(g)[/tex] ΔG° = -70 kJ/molrxn (reverse of Reaction 2)
Next, we can add the two reactions above to obtain:
[tex]4 NH_3(g) + 8 O_2(g) + 2 NO_2(g) --- > 4 NO(g) + 4 HNO_3(aq)[/tex] ΔG° = 940 kJ/molrxn
Finally, we can use Reaction 3 to obtain the target reaction by adding 4 HNO3(aq) and subtracting 2 H2O(l):
[tex]4 NH_3(g) + 8 O_2(g) --- > 4 HNO_3(aq) + 4 H_2O(l)[/tex] ΔG° = -170 kJ/molrxn
Therefore, the answer is (D) −1320 kJ/molrxn.
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Convert atm to Pa, using the numbers below
1.30 atmospheres is equivalent to 131723 pascal.
How to calculate atm to pascal?Atmospheres is a unit of measurement for pressure equal to 101325 Pa with symbol: atm.
Pascals, on the other hand, is the International System of Units (SI unit), the derived unit of pressure and stress, which is equivalent to one newton per square metre.
1 atmosphere = 101325 pascals
Therefore, 1.30 atm is equivalent to 1.3 × 101325 = 131723 Pa.
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2Co + O2 = 2CO2
In this reaction 10.8 mole of carbon dioxide was produced .calculate the number of moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide
Sonce the stoichiometric coefficients for both carbon dioxide and carbon monoxide are the same, the moles of CO2 formed and the moles of CO used are the same, therefore if 10,8 mole of carbon dioxide are being produced, then you would need 10,8 moles of carbon monozide
Sharna then mixed cabbage-water with lemon juice. Lemon juice is acidic. What colour was the mixture?
When all the soil pores are essentially water-filled, flow is termed _______________ .
Unsaturated
Saturated
Gravitional
Rapid
1, The activation energy of the reaction is 71 KJ/Mol how many time is greater the rate constant for the reaction at temperature of 170°c and 150°c.
Answer:
cual es el propósito de este experimento
What is the cell potential for the reaction
Mg(s)+Fe^2+(aq)→Mg^2+(aq)+Fe(s)
at 89 degrees celsius when [Fe2+] = 2.80 M
and [Mg2+] = 0.110 M
solve and show steps. I have tried 2.86 and 6.2653 and both were not correct
show answer in 3 sig figs
The cell potential for the reaction Mg(s)+Fe2+(aq)Mg2+(aq)+Fe(s) is 2.87 V at 89 degrees Celsius.
The Nernst equation can be used to compute this: Where E° cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transported, F is the Faraday constant, and Q is the reaction quotient, E cell is defined as E° cell - (RT/nF)lnQ.
E° cell = -2.37 V, R = 8.314 J/K-mol, T = 362 K, n = 2, F = 96485 C/mol, and Q = [Mg2+]/[Fe2+] = 0.110/2.80 = 0.039 in this instance. The Nernst equation using these values as input produces the result E cell = -2.37 - (8.314*362/2*96485)ln(0.039) = 2.87 V.
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If an equal quantity of heat is added to equal masses of Copper and Water, estimate the final
temperature difference
The temperature of copper would rise by 263.8°C more than the temperature of water if we added the same amount of heat to equal masses of each substance.
What do you mean by specific heat capacity?Specific heat capacity is the amount of heat energy required to raise the temperature of one unit mass of a substance by one degree Celsius or Kelvin. To estimate the final temperature difference, we can use the specific heat capacity of each substance.
The specific heat capacity of copper is 0.385 J/g°C, while the specific heat capacity of water is 4.184 J/g°C. This means that water requires over ten times as much heat energy as copper to raise its temperature by one degree Celsius.
If we add an equal quantity of heat (in joules) to equal masses of copper and water, we can expect the temperature of copper to rise much more than the temperature of water. In fact, we can calculate the temperature difference using the following formula:
Q = mCΔT
where Q is the amount of heat added, m is the mass of the substance, C is its specific heat capacity, and ΔT is the change in temperature.
If we assume that we add the same amount of heat to equal masses of copper and water (let's say 100 grams each), then we can set up two equations using the specific heat capacities of each substance:
Q = 100 * 0.385 * ΔT (for copper)
Q = 100 * 4.184 * ΔT (for water)
Since Q is the same in both equations (we added the same amount of heat to each substance), we can set the two equations equal to each other and solve for ΔT:
100 * 0.385 * ΔT = 100 * 4.184 * ΔT
0.385 * ΔT = 4.184 * ΔT
3.799 * ΔT = Q (where Q is the amount of heat added)
ΔT = Q / 3.799
So, if we added 1000 joules of heat to 100 grams each of copper and water, we can expect the temperature difference between the two substances to be:
ΔT = 1000 / 3.799 = 263.8°C
This means that the temperature of copper would rise by 263.8°C more than the temperature of water if we added the same amount of heat to equal masses of each substance. However, it's important to note that this is a theoretical estimate, and in reality, there would be some loss of heat to the surroundings, which would affect the final temperature difference.
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ACTIVITY: SOLUTION CONCENTRATION VS. CONDUCTIVITY
Here is your goal for this lesson:
Graph experimental data and interpret results for peer review
A chemistry student carried out an experiment with a conducting apparatus (ammeter) similar to the one below. This ammeter measures in milliamperes (mA). The following data was taken.
Solution Reading
0.1 M H2SO4 150 mA
0.1 M Ba(OH)2 150 mA
To 30 mL of the Ba(OH)2 solution, 10 mL portions of H2SO4 were added until a total of
50 mL of H2SO4 were used. The following results were recorded.
DATA TABLE
Total H2SO4 Added Meter Reading Observations
0 mL 150 mA Ba(OH)2 and H2SO4 clear, colorless
10 mL 65 mA milky white precipitate forms
20 mL 31 mA more precipitate forms
30 mL 0 mA precipitate heavy and settles
40 mL 29 mA no added precipitate seen to form
50 mL 62 mA no change seen
Questions
1. Did you plot the data? yes or no
2. Did you label your graph axes? no or yes
3. Did you give your graph a title? no or yes
4. Does the Ba(OH)2 solution contain ions? yes or no
5. Does the H2SO4 solution contain ions? yes or no
6. Explain the data.
Is there any evidence that a reaction has occurred?
7. Does the conductivity increase or decrease?
8. Does the number of ions in solution increase, decrease, or remain constant?
9. What is the indicator of the number of ions in solution?
10. How does this evidence indicate that the reaction has occurred between ions?
11. The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2.Write a balanced equation for this reaction.
12. When the conductivity is at a minimum, what must be true about the amount of Ba(OH)2?
13. Why does it not conduct at this low point?
14. Why does it conduct more before and after this minimum point?
The data obtained from the experiment shows a clear indication that a reaction has occurred between the H₂SO₄ and Ba(OH)₂ solutions. As the H₂SO₄ solution is added to the Ba(OH)₂ solution, the ammeter reading decreases indicating a decrease in conductivity.
The decrease in conductivity is due to the formation of an insoluble white precipitate, BaSO₄, as seen in observations. When no more H₂SO₄ is added, the ammeter reading stabilizes, indicating that the reaction has reached completion, as seen in observations e and f.
The formation of BaSO₄ precipitate indicates that the sulfate ion, SO₄²⁻, from H₂SO₄, has reacted with the barium ion, Ba²⁺, from Ba(OH)₂, forming an insoluble salt. This is a typical example of a precipitation reaction, where two aqueous solutions are mixed, resulting in the formation of an insoluble solid product.
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The question is inappropriate; The complete question is:
A chemistry student carried out an experiment with a conducting apparatus (ammeter) similar to the one below. This ammeter measures in milliamperes (mA). To 30 mL of the Ba(OH)2 solution, 10 mL portions of H2SO4 were added until a total of 50 mL of H2SO4 were used.
Explain the data. Is there any evidence that a reaction has occurred? How does this evidence indicate that the reaction has occurred between ions?
A researcher wants to determine the success rate of a driver’s education program conducted in high schools in a particular state. Which method would assure random selection of a sample from the population? The researcher should select one high school in the state and survey all of the students in that school who are enrolled in the training program. The researcher should randomly select one high school in the state and survey a random batch of students who are enrolled in the training program. The researcher should randomly select a city in the state and survey all students in that city who are enrolled in the training program. The researcher should randomly select students from among all the students in the state who are enrolled in the training program.
The method that would assure random selection of a sample from the population is:
The researcher should randomly select students from among all the students in the state who are enrolled in the training program.
This method ensures that all students enrolled in the driver's education program in the state have an equal chance of being selected for the study. Random selection helps to eliminate bias and increases the likelihood that the sample is representative of the entire population.
The other options listed would not assure random selection of a sample from the population.
Selecting one high school or one city could introduce bias into the sample, as the success rate of the driver's education program may vary between different schools or cities.
Thus, selecting a random batch of students from one high school could also introduce bias into the sample, as the students selected may not be representative of all students enrolled in the driver's education program in the state.
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metallic magnesium can be made by the electrolysis of molten MgCl2. how many minutes are needed to plate out 25g Mg from molten MgCl2 using 3.5 A of current?
Answer:
56,522 seconds = 942 minutes
Explanation:
n(Mg) = m/M(Mg) = 25 g / 24.31 g/mol = 1.03 mol of Mg
Q = n × 2 F = 1.03 mol × 2 × 96,485 C/mol = 197,820 C
t = Q / I = 197,820 C / 3.5 A = 56,522 s
Question 7 (Essay Worth 5 points) (03.02 MC) Is this a scientific model? Use complete sentences to explain why or why not. !!PLS HELP :( !!!
The image is not a scientific model
Is this a scientific model?A scientific model is a condensed representation of a real-world occurrence that helps scientists understand and justify it. In order to make predictions or test hypotheses, scientists utilize models. They could be intellectual, mathematical, or physical.
On the other hand, a NASA image is a visual representation of a real-world item, situation, or phenomenon that has been captured by a spacecraft or telescope. Images from NASA are accurate depictions, not simplified renditions, of what was observed in space.
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What is the rate of reaction (M/s) for the following process if the rate of change for NOBr was measured as -0.5 M/s.
2NOBr(g) ↔ 2NO(g) + Br2(g)
The rate of the reaction for the following process if the rate of change for NOBr was measured as -0.5 M/s. is 0.25 M/s.
The rate of a reaction is typically expressed as the rate of change of the concentration of a reactant or product over time. For the given reaction:
[tex]2NOBr(g)[/tex] ↔[tex]2NO(g)[/tex] [tex]+[/tex] [tex]Br_{2}[/tex](g)
The rate of the reaction can be expressed as:
[tex]rate = -1/2 * d[NOBr]/dt[/tex]
where [tex]d[NOBr]/dt[/tex] is the change in the concentration of NOBr over time, and the negative sign indicates that the concentration of NOBr is decreasing over time.
If the rate of change for NOBr was measured as -0.5 M/s, we can substitute this value into the above equation to find the rate of the reaction:
rate = -1/2 * (-0.5 M/s)
= 0.25 M/s
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How many liter of CO2 gas at STP will contain 2136 molecules?
Answer: 2136 molecules of CO2 at STP will occupy a volume of 8.91 × 10^-24 L
Explanation:
STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 L of volume. Also, 1 mole of any gas contains 6.022 × 10^23 molecules.
1 mole of CO2 contains = 6.022 × 10^23 molecules
Therefore, 2136 molecules of CO2 will be present in a volume of:
= (1 mole CO2 / 6.022 × 10^23 molecules CO2) × (22.4 L / 1 mole CO2) × (2136 molecules CO2 / 1)
= 8.91 × 10^-24 L
A compound containing only sulfur and phosphorus is 50.9% S by mass; the molar mass is 252 g/mol. What are the empirical and molecular formulas of the compound?
The compound's empirical formula is [tex]S_2P[/tex]. We must ascertain the molar mass of the empirical formula in order to derive the molecular formula.
What is compound?A substance created when two or more elements are chemically mixed in a specific ratio is referred to be a compound. In general, compounds differ from mixes, which are made up of various ingredients in a random arrangement. Compounds contain things like carbon dioxide ([tex]Co_2[/tex]), table salt ([tex]Nacl[/tex]), and water ([tex]H_2o[/tex]). Chemical reactions can transform compounds into less complex ones.
[tex]S_2P[/tex] has a molar mass of 120 g/mol. The empirical formula must be multiplied by two to obtain the molecular formula, which is [tex]S_4P_2[/tex], because the compound's molar mass is 252 g/mol.
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Question 14(Multiple Choice Worth 3 points)
[FW.03]The amount of dissolved oxygen in water may decrease because of the
decrease in density of water
increase in plants in the water
decrease in temperature of water
O increase in organic matter in the water
The amount of dissolved oxygen in water may decrease because of the decrease in temperature of water. therefore, the correct option is option C.
Remember the adage "like dissolves like." This indicates that for substances to form solutions, their intermolecular forces must be comparable. When a water-soluble solute is added to a solvent, the solute and solvent particles may come into contact.
When a liquid or solid solute is present, the interactions among the solute and solvent particles become so powerful that the individual particles of solute split from one another and enter the solution encircled by solvent molecules. The amount of dissolved oxygen in water may decrease because of the decrease in temperature of water.
Therefore, the correct option is option C.
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Can you help me solve number 4?
The pressure of the gas in the flask, given that the temperature is reduced to -15 is 0.38 mmHg
How do i determine the pressure of the gas?From the question given above, the following data were obtained:
Initial pressure (P₁) = 338 mmHgInitial temperature (T₁) = 72 °C = 72 + 273 = 345 KInitial volume (V₁) = 0.225 LNew volume (V₂) = 150 LNew temperature (T₂) = -15 °C = -15 + 273 = 258 KNew pressure (P₂) = ?The new pressure of the gas can be obtained by using the combined gas equation as shown below:
P₁V₁ / T₁ = P₂V₂ / T₂
(0.225 × 338) / 345 = (P₂ × 150) / 258
Cross multiply
345 × 150 × P₂ = 0.225 × 338 × 258
Divide both sides by (345 × 150)
P₂ = (0.225 × 338 × 258) / (345 × 150)
P₂ = 0.38 mmHg
Thus, we can conclude the pressure of the gas is 0.38 mmHg
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A 2135 ml sample of N₂ has a pressure of 95.4KPa at 135°C. What is the volume of the sample if temperature is
increased to 223°C and the pressure is kept constant?
B. 2595 ml
A. 913 ml
C. .3484 ml
D. 900 ml
Answer:
The correct answer is C: 3484 ml