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this is the correct answer
Related Questions
What is the kinetic energy of a 36N toy car which is moving at 5 m/s?
Answers
Explanation: in the picture
A person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill. What is the biker's total energy?
a) 1,944 J
b) 2,484 J
c) 1,764 J
d) 720 J
Answers
Answer:
Explanation:
Total mechanical energy is
E = mgh + ½mv²
E = m(gh + ½v²)
E = 90(9.8(2.0) + ½4²)
E = 2,484 J answer b)
A person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill. the total energy of the biker would be 2484 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As given in the problem a person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill.
The total kinetic energy of the biker
KE = 1/2 × m × v²
= 0.5 × 90 × 4²
= 720
Similarly, the total potential energy of the biker
PE = m × g × h
=90 × 9.8 × 2
= 1764 Joules
The total energy of the biker = 720 + 1764
= 2484 Joules
Thus, the total energy of the biker would be 2484 Joules .
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The function of which system is to transport food, oxygen and enzymes, etc. to all cells and to remove carbon dioxide and wastes from cells?
Answers
Answer:
the cardiovascular system
A particle of mass m is fired upwards from the surface of a planet of mass M
and radius R with velocity
Show that the maximum height the particle attains is R/3.
Answers
At the maximum height the particles position has been shown as [tex]\frac{R}{3}[/tex].
The given parameters;
mass of the particle, = Mradius of the particle, = Rmaximum height the particle attains = R/3The velocity of the particle is given as;
[tex]v^2 = \frac{GM}{2R}[/tex]
The total mechanical energy of the particle is given as;
[tex]-\frac{GMm}{R} + \frac{1}{2} mv^2 = - \frac{GMm}{R} + \frac{1}{2} mv^2[/tex]
At maximum height the final velocity of the particle is zero.
[tex]-\frac{GMm}{R} + \frac{1}{2} mv^2 = - \frac{GMm}{R +h}[/tex]
[tex]-\frac{GMm}{R} + \frac{1}{2} m\times \frac{GM}{2R} = - \frac{GMm}{R +h}\\\\-\frac{GMm}{R} + \frac{GMm}{4R} = - \frac{GMm}{R +h}\\\\- \frac{3GMm}{4R} = - \frac{GMm}{R +h}\\\\- \frac{3}{4R} = - \frac{1}{R+ h} \\\\3(R+ h) = 4R\\\\3R + 3h = 4R\\\\3h = 4R - 3R\\\\3h = R\\\\h = \frac{R}{3}[/tex]
Thus, at the maximum height the particles position has been shown as [tex]\frac{R}{3}[/tex].
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A +8.75 μC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 μC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85×108N/C is directed parallel to the wire, as shown in the figure. (Figure 1)
Part A
Find the tension in the wire.
Express your answer with the appropriate units.
Part B
What would the tension be if both charges were negative?
Express your answer with the appropriate units.
Answers
(a) The tension on the wire when the two charges have opposite signs is 383.5 N.
(b) The tension on the wire if both charges were negative is 3.640.25 N.
The given parameters;
first charge, q₁ = 8.75 μC second charge, q₂ = -6.5 μC electric field, E = 1.85 x 10⁸ N/Cdistance between the two charges, r = 2.5 cm(a)
The attractive force between the charges is calculated as follows;
[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N[/tex]
The force on the negative charge due to the electric field is calculated as follows;
[tex]F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N[/tex]
The tension on the wire is the resultant of the two forces and it is calculated as follows;
[tex]T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N[/tex]
(b) when the two charges are negative
The repulsive force between the two charges is calculated as follows;
[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N[/tex]
The force on the first negative charge due to the electric field is calculated as follows;
[tex]F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N[/tex]
The force on the second negative charge due to the electric field is calculated as follows;
[tex]F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N[/tex]
The tension on the wire is the resultant of the three forces and it is calculated as follows;
[tex]T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N[/tex]
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ounces is In the apothecary system of measurement, equal to one apothecary pound. a) eight b) 16 c) 12 d) four
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A ball is projected with an angle o from the top of a tower of height h with velocity vo. The ball strikes the ground after a certain time t, then show a vo sino 2gh 1 + 1 + vo-sin20 t/
Answers
Answer:
dvnuncxtumvd7ojf433f and tv36v54f vs Craig
define potential difference as used in electricity
Answers
Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit.
Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... The energy is transferred to the electrical components in a circuit when the charge carriers pass through them. We use a voltmeter to measure potential difference (or voltage).
Which statement correctly describes the relationship between thermal energy and particle movement?(1 point)
As thermal energy increases, there is more particle movement.
As thermal energy increases, there is more particle movement.
As thermal energy increases, there is less particle movement.
As thermal energy increases, there is less particle movement.
As thermal energy increases, particle movement does not change.
As thermal energy increases, particle movement does not change.
As thermal energy increases, it is not possible to predict particle movement.
As thermal energy increases, it is not possible to predict particle movement.
Answers
Answer:
As thermal energy increases,there is more particle movement
9. Steradian is the angel which lies in:
a) One dimension
b) Two dimensions
Answers
Answer:
B
Explanation:
B
How can stretching affect the range of motion of the neck? Hypothesis
Answers
Answer:
reduce passive stiffness and increase range of movement during exercise.
Explanation:
stretching performed as part of a warm up prior to exercise is thought to reduce passive stiffness and increase range of movement during exercise. in general it appears that is static stretching is most beneficial for athletes requiring flexibility for their sports.
How much time does it take for a school bus traveling at 15 m/s north to get a distance of 600 meters north?
Possible answers:
40 seconds
9,000 seconds
615 seconds
0.025 seconds
Answers
Answer:
40s
Explanation:
How do you explain this arrangement of fossils? What might have happened?
Answers
Answer:
The question lacks a photo to fully answer correctly
If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.
If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.
Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.
Answer:
Peripatus, which lived around 570 MYA, is in the top layer of rock. The trilobites that lived later, between 498 MYA and 445 MYA, appear in the bottom layer. Based on superposition, younger layers of rock are expected to be on top. The rock layers have been overturned, placing the younger layer on the bottom.
Explanation:
actually answer plauto
Fossils show that some animals _____.
are extinct
had not seen rain
liked the cold
made noise
Answers
Answer:I think Fossils show that some animals are extinct
Explanation:
Please mark as brainliest for me.Thanks
Help !!!
I solved Anthor one but didn’t understand this one ??
Answers
Answer:
Explanation:
It's a velocity•time chart. As distance = vt, the area under the curve between limits is the distance traveled.
Pic is fuzzy so I will ASSUME the horizontal axis is seconds and vertical is meters per second.
0 s ≤ t ≤ 5 s = ½(5 - 0)(30 - 0) = 75 m
5 s ≤ t ≤ 10 s = (10 - 5)(30 - 0) = 150 m
10 s ≤ t ≤ 15 s = ½(30 + 20)(15 - 10) = 75 m
0 s ≤ t ≤ 25 s = 75 + 150 + 75 + 20(20 - 15) + ½(20)(25 - 20) = 450 m
How did ancient organisms become fossil fuels?
Answers
Answer:
One of the most widespread beliefs about fossil fuels — oil, natural gas and coal — is that these substances started out as dinosaurs. There’s even an oil company, Sinclair, that uses an Apatosaurus as its icon. That dino-source story is, however, a myth. What is true: These fuels got their start long, long ago — at a time when those “terrible lizards” still walked the Earth.
Fossil fuels store energy in the bonds between the atoms that make up their molecules. Burning the fuels breaks apart those bonds. This releases the energy that originally came from the sun. Green plants had locked up that solar energy within their leaves using photosynthesis, millions of years ago. Animals ate some of those plants, moving that energy up the food web. Others plants just died and decayed.
Any of these organisms, when they die, can be turned into fossil fuels, notes Azra Tutuncu. She’s a geoscientist and petroleum engineer at the Colorado School of Mines in Golden. But it takes the right conditions, including an oxygen-free (anoxic) environment. And time. A whole lot of time.
The coal we burn today got its start some 300 million years ago. Back then, dinosaurs roamed the Earth. But they didn’t get incorporated into coal. Instead, plants in bogs and swamps died. As this greenery sunk to the bottom of those wet areas, it partially decayed and turned into peat. Those wetlands dried out. Other materials then settled down and covered the peat. With heat, pressure and time, that peat transformed into coal. To extract coal, people now have to dig deeply into the earth.
Ancient living organisms are buried quickly and altered by intense heat and pressure to form fossil fuels. Fossil fuels include solid coal, liquid petroleum, and liquid natural gas.
Source; Goo_gle
if this was helpful then please mark me the brainliest
if i was not helpful then i am very sorry
can anyone heelp me pls
Answers
Answer:
Capsule : solid
Suspension : liquid
lotion : semisolid
Explanation:
a person on a bike (m=90 kg) is traveling 4 m/s at the top of a 2 m hill. what is the bikers total energy?
A) 1,944 J
B) 2,484 J
C) 1,764 J
D) 720 J
Answers
Answer:
720 J
Explanation:
Kinetic Energy = 1/2 * m *(v*v)
M= 90 kg
V=4 m/s
KE=1/2 * 90 * (4*4)
KE= 45*16= 720 J
[tex]\frac{m}{s}[/tex]Answer: D) 720 J
Explanation:
Given : m=90kg
Total Energy = K. E. + P. E. =[tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex]+mgh
Since bike is present over a surface of Earth (top of hill) hence h=0m.
Therefore,
Total Energy= [tex]\frac{1}{2}[/tex]*90kg*[tex](4m/s)^{2}[/tex]+(90kg)*(9.81[tex]\frac{m}{s}^2[/tex])x(0)
= 720 J
Hence total energy of bike is equal to 720 J
somebody please help me with this
Answers
Answer:
C.
Explanation:
That is the main part of a cell, apart of the nervous system and controls all the other functions of the cell.
I hope this helped
Brainliest if it did? No pressure!
Have a great day! :D
in a closed system of a cannon and cannonball, which changes would both results in an increase in the kinetic energy of the cannonball when fired from the cannon?
A) decrease the mass of the cannon or decrease the mass of the cannonball
B) increase the mass of the cannon or decrease the mass of the cannonball
C) decrease the mass of the cannon or increase the mass of the cannonball
D) increase the mass of the cannon or increase the mass of the cannonball
Answers
Changes that would results in an increase in the kinetic energy of the cannonball in a closed system, when it is fired from the cannon is B:increase the mass of the cannon or decrease the mass of the cannonball.
A closed system can be considered one that is not been affected by external forces. With the conservation of momentum, there would be collisions as well inexplosions.This explains that when a cannon is fired, there would be gain of forward momentum by the cannon ball, while the cannon experience backward momentum.For the kinetic energy of the cannonball to increase, when fired from the cannon, then the mass is the cannon would be increased or the mass of the cannonball would be decreased.
Therefore, option B is correct.
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What is the initial velocity (in m/s) of a car if it takes 10 seconds to travel a kilometer
while accelerating at 2 m/s??
Answers
A faulty fireworks rocket launches but never discharges. If the rocket launches
with an initial velocity of 33.0 ft/s at an angle of 85.0°, how far away from the
launch site does the rocket land?
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Answer:
a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0∘ above the horizontal. During the flight, the rocket explodes into two pieces of equal mass (see Fig. 8.32). (a) What horizontal distance from the launch point will the center of mass of the two pieces be after both have landed on the ground? (b) If one piece lands a horizontal distance of 26.0 m from the launch point, where does the other piece land?
A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string. (a) If the breaking strength of the string is 120 N, what’s the minimum angle the string can make with the horizontal? (b) At this minimum angle, what’s the rock’s speed?
Answers
(a) The minimum angle the string can make with the horizontal is 4.4 ⁰.
(b) The rocks speed at the minimum angle is 165.7 m/s.
The given parameters;
mass of the rock, m = 940 g = 0.94 kglength of the string, L = 1.3 mTension on the string, T = 120 NThe net force on the string is calculated as follows;
[tex]Tsin(\theta) = mg\\\\Tcos(\theta) = \frac{mv^2}{r} \\\\\frac{Tsin(\theta)}{Tcos(\theta)} = \frac{mg r}{mv^2} \\\\tan(\theta) = \frac{rg}{v^2} \\\\v^2 = \frac{rg}{tan (\theta)} \\\\v = \sqrt{\frac{rg}{tan (\theta)}}[/tex]
The minimum angle the string can make with the horizontal is calculated as follows;
[tex]Tsin(\theta) = mg\\\\sin(\theta) = \frac{mg}{T} \\\\sin(\theta) = \frac{0.94 \times 9.8}{120} \\\\sin(\theta) = 0.0767\\\\\theta = sin^{-1} (0.0767)\\\\\theta = 4.4 \ ^o[/tex]
The rocks speed at the minimum angle is calculated as follows;
[tex]v = \sqrt{\frac{rg}{tan(\theta)} } \\\\v = \sqrt{\frac{1.3 \times 9.8}{tan(4.4)} } \\\\v = 165.7 \ m/s[/tex]
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How much heat must be added to 160 g of ice at 0°C to melt the ice completely? The latent heat of fusion of ice is 80 cal/g.
The amount of heat required is
cal
Answers
Pls help and thank u need asap!
Answers
Answer:
ill help if u help me?its 4am
HELP!!! I HAVE NO IDEA!!!!!!!!!!!!!
1. A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?
a. 0.4 kg
b. 1.6 kg
c. 2.4 kg
d. 0.8 kg
2. Which of the following would be a situation with unbalanced forces?
a. Two people pulling on the same side of a wheelbarrow
b. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d. Two people not touching a crate that is sitting stationary.
3. Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary
a. The force of gravity on the object is different if it is stationary or not.
b. The force of friction on the object is different if it is stationary or not
c. The force of the push on the object is different if it is stationary or not
d. The normal force on the object is different if it is stationary or not.
Thanks In Advance!! (I will mark brainliest) :)
Answers
Answer:
Explanation:
The engine should create the same force
1) F = ma
F = M(½a)
therefore
ma = ½Ma
m = ½M
M = 2m
M = 2(0.8)
M = 1.6 kg
2) Unbalanced forces
a. Two people pulling on the same side of a wheelbarrow
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
3) b. The force of friction on the object is different if it is stationary or not
What is the main tenet of mechanical philosophy
Answers
Answer:362
Explanation:
i just want the points
Answer:
Some ancient philosophies held that the universe is reducible to completely mechanical principles—that is, the motion and collision of matter. This view was closely linked with materialism and reductionism, especially that of the atomists and to a large extent, stoic physics.
Explanation:
Hope this helps.
From what material did the moon form?How are eras and periods of the geologic time scale named?
Answers
Answer:
this
Explanation:
because of this its this ok
Answer: They are named for the places where geologists first described rocks or fossils from that time.
Explanation: ingenuity
Two particles of a gas collide. Why is this considered an elastic collision? (1 point)
O They bounce off each other, conserving momentum only.
O They stick together, conserving momentum.
O They bounce off each other, conserving energy only.
O They bounce off each other, conserving energy and momentum.
Answers
They bounce off each other, conserving energy and momentum.
This is considered an elastic collision because they bounce off each other, conserving energy only.
Gas is the state of matter that is made up of particles which freely move about its container and they bounce off each other.
As the particles move over each other they collide without exerting any force in each other. This is known as elastic collision.
Kinetic energy is conserved in elastic collisions which occurs between gas molecules.
While in inelastic collision, momentum is conserved and kinetic energy is not.
Because the gas particles do not stick together as they collide, no force is exerted and kinetic energy is therefore conserved.
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A Wheatstone Bridge type circuit is shown (10marks) R1=20ohms, R2=10ohms, R3=8ohms, R4=5ohms, and R5=2ohms and also has 10V battery. Determine A. the p.d. between terminals B and D, and (5 marks) B. The value to which R4 must be adjusted in order to reduce the current through R3 to zero (balance the bridge). (5marks)
Answers
Answer:
Dunno
Explanation:
Dunno