Fill in the blank question.
Your sibling drops your house keys down to you from the second-floor window, as shown in the image. What is the velocity of the keys when you catch them?

The work done by the man during these 2 minutes is zero.

A force must be applied in order to produce work, and there must also be motion or displacement in the force's direction. The amount of work performed by a force acting on an item is equal to the force's magnitude times the distance travelled in the force's direction. Work has only magnitude and no direction. As a result, work is a scalar quantity.

According to the question, a man holds a 1.00-kg box above his head for 2 minutes. No displacement happens in this two minutes. So, no work is done by the man.

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Because friction always opposes motion, according to Newton's second law of motion, F f 804 N.

Vehicle operation on a surface- When a truck is being driven, the engine exerts a force on the wheel that propels the vehicle forward. The vehicle can't move ahead because of the friction between both the wheels as well as the ground. Consequently, the car keeps from skidding.

The resistance between the surfaces can be decreased by using lubricants like oil or grease. Friction can be decreased by polishing its surface, which makes it smooth.

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When a spring with an initial compression of 5.0 cm is compressed by 0.15, a total compressed of 20 cm is achieved. as it is compressed another 15 cm, the work is completed. spring constant 8.0 n/m

The spring constant can be calculated using the spring constant. Springs that are more rigid are more likely to be challenging to stretch. Elastic substances make up springs. spring constant deforms when external forces are applied, but it returns to its original position once the force is removed. A linear elastic deformation has occurred with the spring. The relationship curve between force and displacement is linear.

A type of compressed spring that generates linear force is the spring.

Work completed, w = 0.5 k x - 0.5 ky

W= 1/2K (x^2 - y^2 )

W = 1/2 ( 8 ) / (20 * 10^ -2 ) ^2 - ( 5* 10 ^-2 ) ^2 J

W = 0.15 J

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Answer:

Explanation:

c. Assertion is correct but reason isn't

Consider two satellites s1 and s2 in circular orbits with periods of 8 hours and 16 hours . satellites will be 80129 m and  130829 m high above the earth's surface

h1 = [tex]{(GM(e) * T^{2} / 4 pi^{2} )}^{1/3}[/tex] - R(e)

  = ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] * [tex]8^{2}[/tex] / 4 * [tex]3.14^{2}[/tex]) - 6371

  = 80129 m

h2 = (6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] * [tex]16^{2}[/tex] / 4 * [tex]3.14^{2}[/tex]) - 6371

  = 130829 m

satellites will be 80129 m and  130829 m high above the earth's surface

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Answer:Simple, it gets used up by the phone.

Explanation:Your phone uses the energy stored in the battery to perform the functions it does. Chemical energy gets converted to light (display), sound (speakers), electrical (internal processing of the phone), thermal (phone getting heated up), and to other forms.

The correct option is 10 to 100 Hz. A low pass and high pass filter are cascaded to create a band pass filter. It has two reactive elements, making it a second order filter.

The signal strength to frequency graph looks like this because this filter favors high frequencies: We may do a variety of signal processing operations using the low-pass and high-pass filters, including picking out a certain frequency band. We can easily sketch the perfect filter response since the -3dB point is also quite near to the place where the "unity gain" line and the asymptote for the filter's roll-off curve intersect.

Drawing piecewise-linear approximations for filter performance is no longer necessary in modern times thanks to the usage of computers, but this was not the case when electrical circuit design and analysis first started. Even with the introduction of electronic calculators, the majority of these activities were still done by hand.

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The disadvantages of unconventional oil and gas extraction as belonging to tar sands mining are as follows:-

Oil and gas extraction:-

Tar sand mining:-

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Disclaimer:- your question is incomplete, please see below for the complete question.

Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining.

a. ther hydraulic fracturing or tar Hydraulic fracturing Tar sands.

b. mining Answer Bank local groundwater contamination huge lakes of acidic and toxic.

C. wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property

D.The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes

The parallax angle for the star Hadar is 0.010 arcseconds. 100 PC far away is Hadar.

Parallax angle is a displacement or distinction in the apparent function of an item considered alongside two one-of-a-kind lines of sight and is measured by the attitude or semi-perspective of inclination among those two lines. because of foreshortening, close-by objects display a bigger parallax than farther items when found from distinct positions, so parallax may be used to determine distances.  

To a degree of big distances, including the gap between a planet or a star from Earth, astronomers use the precept of parallax. right here, the term parallax is the semi-perspective of inclination between sightlines to the megastar, as observed while Earth is on contrary sides of the solar in its orbit. those distances shape the lowest rung of what's called "the cosmic distance ladder", the first in a succession of methods by which astronomers determine the distances to celestial items, serving as a basis for other distance measurements in astronomy forming the higher rungs of the ladder.

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The terminal speed of the marble is 0.588 m/s.

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Applying the conservation of momentum law we find the final velocity of

                        a) the car = 0.37 m/s in the opposite direction.

                        b) the van = 1.39 m/s

Define elastic collision between particles?

The given informations in the question are-

Mass of van = mv = 1140 kg

Mass of car = mc = 745 kg

Initial velocity of car = v1_i =  2.25 m/s

Applying conservation of momentum, the final velocity of the car is found out using the formula,

v1_f = (mc - mv) x v1_i / (mc + mv)

Putting the values we get,

v1_f = (745 - 1140) x 1.77 / (745 + 1140)

       = - 395 x 1.77 / 1885

       = - 0.37  m/s

The negative sign indicates that after collision it is moving in the opposite direction to its initial speed.

The final velocity of the van, is found out using the formula,

v2_f = 2 x mc x v1_i / (mv +mc)

Putting the values we get,

v2_f  = 2 x 745 x 1.77 / (745 + 1140)

        =  1.39 m/s

Hence, the final velocity of

                        a) the car = 0.37 m/s in the opposite direction.

                         b) the van = 1.39 m/s

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The maximum height H to which she rises above the end of the track that is slanted upward by 48° above the horizontal at its end is 1.11 m

KE = 1 / 2 m v²

PE = m g h

According to law of conservation of energy,

KE ( Initial )  + PE ( Initial ) = KE ( Final ) + PE ( Final )

h ( Initial ) = 0

v ( Initial ) = 6.9 m / s

g = 9.8 m / s²

h = 0.4 m

1 / 2 m vi² + m g hi = 1 / 2 m v² + m g h

1 / 2 m vi² = 1 / 2 m v² + m g h

vi² = v² + 2 g h

6.9² = v² + ( 2 * 9.8 * 0.4 )

v² = 47.61 - 7.84

v² = 39.77 m / s

H = vi² sin²θ / 2 g

θ = 48°

H = 39.77 * sin²48° / ( 2 * 9.8 )

H = 21.78 / 19.6

H = 1.11 m

Therefore, the maximum height H to which she rises above the end of the track is 1.11 m

The given question is incomplete. The complete question is;

The drawing shows a skateboarder moving at 6.9 m/s along a horizontal section of a track that is slanted upward by 48° above the horizontal at its end, which is 0.40 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track.

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Answer:

The temperature of the early solar system explains why the inner planets are rocky and the outer ones are gaseous.

Explanation:

The outer planets are much larger than the inner planets. Because of their large mass and cooler temperature, they have a very different composition; they are mostly made of light elements with extended atmospheres in a gaseous form. Outer planets exist in much bigger systems than inner planets.

The reason for different composition of planets has to do with how the solar system formed. In the early solar system, there was a disk of material rotating around the Sun, from which the planets eventually formed. However, to form planets required some kind of initial clump in the protoplanetary disk. These clumps were probably formed from collisions of solid particles. Different elements become solid at different temperatures: the most common elements, hydrogen and helium, never became solid, but hydrogen compounds (like water) can solidify at colder temperatures, like those in the outer solar system. In the inner solar system, it was too hot for these compounds to solidify; only rocks and metals can solidify at these temperatures. Hence, only small planetesimals formed in the inner solar system.

Gamma rays is a form of electromagnetic radiation that has photons with the highest energy.

Gamma rays are a form of electromagnetic radiation (EMR). They are the similar to X-rays, distinguished only by the fact that they are emitted from an excited nucleus.

The energy of the photon is directly proportional to the frequency, that is Ε α υ. It means that if the photon has high frequency, then the energy of that photon will be high, and if the photon has lower frequency then the energy that the photon will be less.
Here it is given to determine the radiation that has high energy, which in turn means that radiation with the highest frequency is needed to be found. Hence, from the data of electromagnetic spectrum, the radiation with the highest frequency is the gamma rays with frequencies up to 10^19 Hz.
As gamma rays have the highest frequency, gamma rays will also have the highest energy, with energy extending up to few trillion electron volts.
Hence, the radiation with the highest energy is gamma rays.

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Answer:

Average acceleration of the car = 3 m/s²

Explanation:

According to the question,

Initial velocity of the car ([tex] \rm v_i [/tex]) = 20 m/s

Final velocity of the car ([tex] \rm v_f [/tex]) = 35 m/s

Time interval of uniform acceleration (t) = 5 s

By using [tex] 1^{st} [/tex] kinematic equation and substituting value we get:

[tex] \rm \implies v_f = v_i + at \\ \\ \rm \implies at = v_f - v_i \\ \\ \rm \implies a = \dfrac{v_f - v_i }{t} \\ \\ \rm \implies a = \dfrac{35 - 20 }{5} \\ \\ \rm \implies a = \frac{15}{5} \\ \\ \rm \implies a = 3 \: m {s}^{ - 2} [/tex]

[tex] \therefore [/tex]

Average acceleration of the car is 3 m/s²

Answer:

below

Explanation:

vf = 76.5

vf= at

76.5 = 9.81 t     shows t = 7.798 s

d = 1/2 a t^2 = 1/2 ( 9.81)(7.798)^2 = 298.3 m

Following cooling, a white dwarf becomes too cold and dark to emit visible light.

Like our Sun, medium-mass stars generate helium by fusing hydrogen within their cores. Our Sun is now performing this. An outward pressure results from the heat the Sun produces during the nuclear fusion of hydrogen into helium. The Sun will run out of hydrogen in its core in about 5 billion years.

The Sun begins to collapse when it runs out of hydrogen to fuse, tipping the scales in favor of gravity. However, compacting a star makes it heat up once more, allowing it to fuse what little hydrogen is left in a shell surrounding its core.

We can learn about the age of the universe from white dwarfs. Our galaxy and the age of the universe would be lowered if we could calculate how long it takes for a white dwarf to cool into a black dwarf.

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We have to multiply the actual load current times by 1.25 (2017 NEC: 210.20(A)).

NEC 210.20(A) Continuous and Noncontinuous Loads:

The rating of the overcurrent device must be no less than the noncontinuous load plus 125 percent of the continuous load when a branch circuit delivers continuous loads or any combination of continuous and noncontinuous loads.

With one exception, the ampere rating of the overcurrent device may not be less than the total of the continuous load and the noncontinuous load when the assembly, including the overcurrent devices safeguarding the branch circuit(s), is rated for operation at 100% of its rating.

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The current in the circuit is 0.5 A

what is current?

An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is a typical way to represent current.

I = V/R

I = 9/18

I = 0.5 A

Therefore, the current in the circuit is 0.5

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The circuit's current is 0.5 A.

What is current?

An electric current is a flow of charged particles, such as electrons or ions, across a conductor or space. It is calculated as the net rate of charge flow through a surface or into a control volume. Charge carriers are moving particles that can be one of numerous sorts depending on the conductor. Electrons flowing over a wire are frequently used as charge carriers in electric circuits. They can be either electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons are the charge carriers in plasma, an ionised gas.

I = V/R

I = 9/18

I = 0.5 A

Therefore, the current in the circuit is 0.5

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Reaction time is the skill that mostly helps candace respond as the puck flies in her direction

Reaction time (RT) is a measure of the quickness with which a person responds to some sort of stimulus. It is defined as the interval of time between the stimulus and  voluntary response in the subject.

Her reaction time is really quick , She reacts quickly to the different areas that the puck is going and is able to go across the crease to stop it

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Divided by the amount of time passed, the average speed is obtained. The limit of average velocity as elapsed time approaches zero is the instantaneous velocity of an object. v (t) = d d t x (t). v (t) = d d t x (t).

The average velocity rate of change is a measure of how much one variable has changed overall relative to another. The instantaneous rate of change, also known as the derivative, quantifies the precise rate at which one variable changes in relation to a precise, extremely small change in another variable.Average speed is the ratio of an object's total distance travelled to its total travel time. Average acceleration is calculated by dividing the change in velocity by the amount of time that has passed; instantaneous acceleration is the acceleration at a specific time. Average acceleration is the acceleration at a specific moment in time; instantaneous acceleration is the velocity change divided by the amount of time that has passed. As a result, only when the body is moving at a constant speed can instantaneous speed and average speed be equal. Instantaneous speed and instantaneous velocity have the same magnitude.

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the answer is WE GO DOWN 89W8 >#*#,'

An astronomer states that star p has a lower absolute brightness than star q. Option B. b star q gives off more light than star p.

According to astronomers Stars have a wide variety of obvious brightness measured right here on this planet. The version of their brightness is resulting from both versions of their luminosity and versions of their distance.

The plain brightness of a star is proportional to one divided by means of its distance squared. that is, if you took a star and moved it twice as some distance away, it might appear 1/4 as bright; in case you moved it four times the distance, it'd appear 1/sixteen as brilliant.

Apparent value is the brightness of a celeb because it seems to the observer. this is what stargazers look at after they take a look at the sky and notice that a few stars are brighter than others. Absolute significance is the brightness of a star from a distance of 10 parsecs away

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The coefficient of kinetic friction between the puck and surface id 0.20.

What is coefficient of kinetic friction?

Coefficient of kinetic friction is the ratio between frictional force present in the motion of two surfaces that are in contact to the normal force that presses the two surface together.

It is calculated mathematically as: μ = F/N, where

F= frictional force and N= normal force.

v2 = u2 +2as

0= 62 + 2a9

18a + 36= 0

18a = -36

a= -2

friction =  μ × normal force

or friction =ma

ma=  μN

ma=  μ(mg)

μ = a/g where g = 9.8 N

μ= -2/9.8

⇒0.20.

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The power pushing at 113 N for a distance of 9 meters. The time taken is 0.22 seconds.

Power :

Power is defined as the speed at which work is performed on an object.

work done = Force x Distance

Power = Work done/ Time

Power = (Force x Distance)/Time

Power = 226 Watt

Force = 113 N

Distance taken = 9 meters

To calculate power we use :

Power = (Force x Distance)/Time

266W = (113N x 9s)/Time

Time = 266W/(113N x 9m)

Time = 266W/(113N x 9m)

Time = 0.22 seconds

The power pushing at 113 N for a distance of 9 meters. The time taken is 0.22 seconds.

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The number of turns the winding have in an air-filled toroidal solenoid that has a mean radius of 15.0cm and a cross-sectional area of 5.00cm2 is 2745 turns

According to Ampere's law,

B = μo N I / 2 π r

Φ[tex]_{B}[/tex] = B A

Φ[tex]_{B}[/tex] = μo N I A / 2 π r

B = Magnetic field

μo = Absolute permeability of free space

N = Number of turns

I = Current

r = Radial distance

A = Cross sectional area

U = Energy stored

U = 1 / 2 L I²

L = 2 U / I²

L = N Φ[tex]_{B}[/tex] / I

μo = 4 π * [tex]10^{-7}[/tex] H / m

U = 0.39 J

r = 15 cm = 0.15 m

I = 12.5 A

A = 5 cm² = 5 * [tex]10^{-4}[/tex] m²

Equating,

2 U / I² = N Φ[tex]_{B}[/tex] / I

2 U / I² = μo N² I A / 2 π r I

4 π r U / μo I² A = N²

N² = ( 4 * 3.14 * 0.15 * 0.39 ) / ( 4 * 3.14 * [tex]10^{-7}[/tex] * 12.5² * 5 * [tex]10^{-4}[/tex] )

N² = 0.74 / 9812.5 * [tex]10^{-11}[/tex]

N² = 7.54 * [tex]10^{6}[/tex]

N = 2.745 * 10³

N = 2745 turns

Therefore, the number of turns the winding have are 2745 turns

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Answer:

Below

Explanation:

The accelerateinon, a, of the watermelon is just the acceleration of gravity on Earth = 9.81 m/s^2

the height will be found by

Height = 1/2 a t^2 = 1/2 (9.81)(3.50)^2 = 60.1 m

Each constituent of the Milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession are classified accordingly.

The constituents of the Milankovitch cycles as pertaining to orbital eccentricity are:

The constituents of the Milankovitch cycles as pertaining to axial tilt are:

The constituents of the Milankovitch cycles as pertaining to axial precession are:

Therefore, each constituent of the Milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession are classified accordingly.

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