Exercise 3. Using a sample of 1801 individuals, the following earning equation has been estimatedR2=0.17,RSS=100where the standard errors are reported in brackets. 1. Which variables are significant? Explain 2. Interpret the coefficient estimate on female. 3. InterpretR2. 4. Dropping experience and female from the equation gives:ln( carnings )=(0.718)6.71+(0.01)0.10educR2=0.11,RSS=140Are experience and female jointly significant in the original equation at the5%significance level? Please write: (i) the null and alternative hypothesis, (ii) test statistic, (iii) proper critical value, (iv) conclusion. Hint:F1,1801=3.81,F1,1797=3.86,F2,1801=3.01,F2,1797=3.51

A real relationship, not accounted by other variables, is a causal relationship. This type of association suggests that one variable directly causes changes in the other. In other words, there is a cause-and-effect relationship between the two variables.

In this type of association, changes in one variable directly cause changes in the other variable, without any other variables influencing the relationship. This contrasts with spurious or indirect associations, where the relationship between two variables is due to the influence of other variables. To determine if an association is a real relationship, researchers often control for potential confounding variables to isolate the direct effect of the variables in question. However, it is important to note that establishing a causal relationship requires careful research design and data analysis to rule out the effects of other variables that could be influencing the relationship.

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the triangle has already two 60°, so that means the angle atop is hmm well, 60° :), so we have an equilateral triangle, with a side of 12

[tex]\textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4} ~ \begin{cases} s=\stackrel{length~of}{a~side}\\[-0.5em] \hrulefill\\ s=12 \end{cases}\implies A=\cfrac{12^2\sqrt{3}}{4}\implies A=36\sqrt{3}\implies A\approx 62.35[/tex]

The solution to the initial value problem y'-4y=f(x), y(0)=0 for 0<=x<4 is given by:

y(x) = F(-4)e^(-4x)

The Laplace transform of the differential equation y'-4y=f(x) is given by:

sY(s) - y(0) - 4Y(s) = F(s)

where Y(s) and F(s) are the Laplace transforms of y(x) and f(x), respectively.

Substituting the initial condition y(0)=0 and rearranging, we get:

Y(s) = F(s)/(s+4)

Now we need to find the inverse Laplace transform of Y(s) to obtain the solution y(x). Using the partial fraction decomposition method, we can write:

Y(s) = A/(s+4) + B

where A and B are constants to be determined.

Multiplying both sides by (s+4), we get:

F(s) = A + B(s+4)

Setting s=-4, we get:

A = F(-4)

Setting s=0, we get:

B = Y(0) = y(0) = 0

Therefore, the partial fraction decomposition of Y(s) is given by:

Y(s) = F(-4)/(s+4)

Taking the inverse Laplace transform of Y(s), we get:

y(x) = L^-1{F(-4)/(s+4)} = F(-4)L^-1{1/(s+4)}

Using the table of Laplace transforms, we find that the inverse Laplace transform of 1/(s+4) is e^(-4x). Therefore, the solution to the initial value problem is given by:

y(x) = F(-4)e^(-4x)

where F(-4) is the value of the Laplace transform of f(x) evaluated at s=-4.

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The area of the actual flower bed include the following: D. 96 square meters.

In Mathematics and Geometry, the area of a triangle can be calculated by using this formula:

Where:

Scale:

0.5 cm = 2 m

0.5/2 = New length of flower bed/Actual length of flower bed

Actual length of flower bed = (2 × 3)/0.5 = 12 meters

0.5/2 = New height of flower bed/Actual height of flower bed

Actual height of flower bed = (2 × 4)/0.5 = 16 meters

By substituting the given parameters into the formula, we have;

Area of triangle = 1/2 × base area × height

Area of actual flower bed = 1/2 × 12 × 16

Area of actual flower bed = 96 m².

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The area of Kite PQRS at the right is concave. If we have PQ = QR = 20, PS= SR= 15, and QS = 7 is  220 square units

First, we can find the length of the diagonal PR using the Pythagorean theorem:

PR² = PQ² + QR² = 20² + 20² = 800

PR = sqrt(800) ≈ 28.28

Similarly, we can find the length of the diagonal QS:

QS² = QR² + RS² = 20² + 15² = 625

QS = sqrt(625) = 25

Now, we can split the kite into two triangles, PQS and QRS, and use the formula for the area of a triangle:

area of PQS = (1/2) * PQ * QS = (1/2) * 20 * 7 = 70

area of QRS = (1/2) * QR * RS = (1/2) * 20 * 15 = 150

So the total area of the kite is:

area of PQRS = area of PQS + area of QRS = 70 + 150 = 220

Therefore, the area of kite PQRS is 220 square units

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The solution is:

a) The z-transform is (z/(z-2)).

b) The z-transform is (z/(z-2))+(z/(z-3)).

c) The z-transform is (1-2z⁻¹)/(1-2z⁻¹+2z⁻²).

d) The z-transform is ((z+cos4)/(z-2)).

Here, we have,

a) To compute the z-transform of the signal (1+2ⁿ)u[n], we can use the formula for the z-transform of the geometric series. This gives us:

∑_(n=0)^(∞) (1+2ⁿ)z⁻ⁿ = ∑_(n=0)^(∞) z⁻ⁿ + 2∑_(n=0)^(∞) zⁿ = z/(z-2)

b) To compute the z-transform of the signal 2ⁿu[n]+3ⁿu[n], we can use the formula for the z-transform of the geometric series again. This gives us:

∑_(n=0)^(∞) (2ⁿ+3ⁿ)z⁻ⁿ = ∑_(n=0)^(∞) (2z⁻¹)ⁿ + ∑_(n=0)^(∞) (3z⁻¹)ⁿ = (z/(z-2))+(z/(z-3))

c) To compute the z-transform of the signal {1,-2}+2ⁿu[n], we can first compute the z-transform of 2ⁿu[n] using the formula for the z-transform of the geometric series. This gives us:

∑_(n=0)^(∞) 2ⁿz⁻ⁿ = z/(z-2)

Next, we can compute the z-transform of {1,-2} by subtracting the z-transform of 2ⁿu[n] from the z-transform of 1. This gives us:

(1-2z⁻¹)/(1-2z⁻¹+2z⁻²)

d) To compute the z-transform of the signal 2ⁿ+1cos(3n+4)u[n], we can use the formula for the z-transform of a cosine function. This gives us:

∑_(n=0)^(∞) (2ⁿ+cos4)z⁻ⁿ = (z+cos4)/(z-2)

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complete question:

Compute the z-transforms of the following signals. Cast your answer in the form of a rational fraction.a) (1+2^n) u[n]b) 2^nu[n]+3^n u[n]c) {1,-2}+(2)^n u[n]d) 2^n+1 cos(3n+4) u[n]show all work

The trigonometric identity is sin²(u)/cos²(u) = tan²(u).

The study of the correlation between a right-angled triangle's sides and angles is the focus of one of the most significant branches of mathematics in history: trigonometry.

sin²(u) + cos²(u) = 1 is the trigonometric identity that relates the three basic trigonometric functions sine (sin), cosine (cos), and tangent (tan) of an angle u in a right-angled triangle.

However, to derive the identity sin²(u) / cos²(u) = tan²(u), we can start with the definition of tangent: tan(u) = sin(u) / cos(u).

Then, we can square both sides of the equation:

tan²(u) = (sin(u) / cos(u))²

tan²(u) = sin²(u) / cos²(u)

Therefore, sin²(u) / cos²(u) = tan²(u).

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The complete question is:

Fill in the blank to complete the trigonometric identity. sin²(u)__cos²(u) = tan²(u)

No chemical reaction occurs, so the answer is nr.

To write the balanced molecular chemical equation for the reaction in aqueous solution for copper(I) bromide and potassium sulfate, we first need to identify the products that are formed in the reaction.

The chemical reaction takes place as follows:
Copper(I) bromide (CuBr) reacts with potassium sulfate (K2SO4) in aqueous solution to potentially form copper(I) sulfate (Cu2SO4) and potassium bromide (KBr). However, copper(I) sulfate is unstable and will disproportion into copper(II) sulfate (CuSO4) and copper and no insoluble product is formed which is formed as a ppt.

Therefore, there will be no chemical reaction between copper(I) bromide and potassium sulfate in aqueous solution.

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The area of a cookie with radius of 10cm is given as follows:

A = 314 cm².

The area of a circle of radius r is given by the multiplication of π and the radius squared, as follows:

A = πr².

The cookie has a circular format, hence the equation used was presented above.

The radius is given as follows:

r = 10 cm.

Hence the area is given as follows:

A = 3.14 x 10²

A = 314 cm².

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The area of a cookie with radius of 10cm is given as follows:

A = 314 cm².

The area of a circle of radius r is given by the multiplication of π and the radius squared, as follows:

A = πr².

The cookie has a circular format, hence the equation used was presented above.

The radius is given as follows:

r = 10 cm.

Hence the area is given as follows:

A = 3.14 x 10²

A = 314 cm².

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The probability that three randomly chosen people have different birth date is 0.9918.

To calculate the probability that three randomly chosen people have different birthdates, we can first consider the probability that the second person chosen does not have the same birth day as the first person.

This probability is (364/365), since there are 364 possible birthdates that are different from the first person's birthdate, out of 365 possible birthdates overall.

Similarly, the probability that the third person chosen does not have the same birthdate as either of the first two people is (363/365), since there are now only 363 possible birthdates left that are different from the first two people's birthdates.

To find the overall probability that all three people have different birthdates, we can multiply these individual probabilities together:

(364/365) x (363/365) = 0.9918

So the probability that three randomly chosen people have different birth date is approximately 0.9918, or about 99.2%.

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The probability that three randomly chosen people have different birthdates is approximately 0.9918, or 99.18%.

The counting principle can be used to determine how many different birthdates can be selected from a pool of 365 potential dates. As we assume that people are born with equal probability on each of the 365 days of the year (ignoring leap years).

The first individual can be born on any of the 365 days. The second individual can be born on any of the remaining 364 days. The third individual can be born on any of the remaining 363 days. Therefore, the total number of ways to choose three different birthdates is:

365 x 364 x 363

Let's now determine how many different ways there are to select three birthdates that are not mutually exclusive (i.e., they can be the same). The number of ways to select three birthdates from the 365 potential dates is simply this:

365 x 365 x 365

Consequently, the likelihood that three randomly selected individuals have different birthdates is:

(365 x 364 x 363) / (365 x 365 x 365) ≈ 0.9918

Therefore, the likelihood is roughly 0.9918, or 99.18%.

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The solution of given equation by formula of quadratic Equation is x = -1 OR x = -0.5

A quadratic equation is a polynomial equation of the second degree, meaning it contains one or more terms that involve a variable raised to the power of two. The standard form of a quadratic equation is:

ax² + bx + c = 0where a, b, and c are constants, and x is the variable.

The equation is 2x(x+1.5)=-1.

Expanding the left-hand side, we get:

2x² + 3x + 1 = 0

We can solve for x using the quadratic formula:

x = (-b ± √(b²- 4ac)) / 2a

Where a = 2, b = 3, and c = 1.

x = (-3 ± √(3² - 4(2)(1))) / 4

x = (-3 ± √(1)) / 4

x = (-3 ± 1) / 4

So, x can be either:

x = -1 OR x = -0.5

Rounding to the nearest tenth, we have:

x ≈ -1.0 OR x ≈ -0.5

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Answer:

Step-by-step explanation:

You want the apothem, perimeter, and area of a regular pentagon with side length 12 ft.

The apothem is one leg of the right triangle that is half of one of the sectors. The other leg is half the side length. This gives ...

  tan(36°) = (6 ft)/a

  a = (6 ft)/tan(36°) ≈ 8.25829 ft

The perimeter is simply 5 times the side length:

  (12 ft) × 5 = 60 ft

The area is given by the formula ...

  A = 1/2Pa

  A = 1/2(60 ft)(8.25829 ft) ≈ 247.749 ft²

__

Additional comment

An n-sided regular polygon with side length s has an area of ...

  A = [s²n]/[4tan(180°/n)]

For s=12 and n=5, this is ...

  A = 12²·5/(4·tan(180°/5)) = 180/tan(36°) ≈ 247.7 . . . . square feet

The word problem for the company is:

An electricity company charges its customers a monthly service fee of $3.50 plus 8.3 cents per kWH. Find the total cost for a month if 250kW is used.

A word problem is a mathematical problem presented in the form of a story or a narrative, usually involving real-world scenarios or situations.

Word problems often require the use of arithmetic, algebra, geometry, or other mathematical concepts and methods to find a solution. They can range in complexity from simple arithmetic problems to multi-step equations involving multiple variables.

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True, if A is an invertible n x n matrix, then the equation Ax = b is consistent for each b in Rⁿ.

When A is an invertible n x n matrix, it means that A has a unique inverse, denoted as A⁻¹, which is also an n x n matrix. This implies that for any given vector b in Rⁿ, there exists a unique solution x in Rⁿ that satisfies the equation Ax = b.

To understand why this is true, consider the definition of matrix multiplication. In the equation Ax = b, A is multiplied by x to obtain b. Since A is invertible, we can multiply both sides of the equation by A⁻¹ (the inverse of A) on the left, yielding A⁻¹Ax = A⁻¹b.

Now, according to the properties of matrix multiplication, A⁻¹A results in the identity matrix I_n (an n x n matrix with ones on the diagonal and zeros elsewhere), and any vector multiplied by the identity matrix remains unchanged. Therefore, we get I_nx = A⁻¹b, which simplifies to x = A⁻¹b.

This shows that for any given vector b in Rⁿ, there exists a unique solution x = A⁻¹b that satisfies the equation Ax = b when A is an invertible matrix. Hence, the equation Ax = b is consistent for each b in Rⁿ.

Therefore, the correct answer is True.

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(a) The probability that a randomly selected cookie contains exactly 4 chocolate chips is 0.1755.

(b) The probability that a randomly selected cookie contains more than 2 chocolate chips is 0.8753.

The number of chocolate chips in a chocolate chip cookie follows the Poisson distribution with parameter λ, where λ is the average number of chocolate chips per cookie. Here, λ = 1000/200 = 5.

(a) The probability that a randomly selected cookie contains exactly 4 chocolate chips is given by the Poisson probability mass function:

P(X = 4) = ([tex]e^{(-5)} * 5^4[/tex]) / 4! = 0.1755

Therefore, the probability that a randomly selected cookie contains exactly 4 chocolate chips is 0.1755.

(b) The probability that a randomly selected cookie contains more than 2 chocolate chips is given by the complement of the probability that it contains at most 2 chocolate chips:

P(X > 2) = 1 - P(X ≤ 2)

To find P(X ≤ 2), we can use the Poisson cumulative distribution function:

P(X ≤ 2) = Σ(k=0 to 2) [ [tex](e^{(-5)}[/tex] * [tex]5^k[/tex]) / k! ] = 0.1247

Therefore,

P(X > 2) = 1 - P(X ≤ 2) = 1 - 0.1247 = 0.8753

So the probability that a randomly selected cookie contains more than 2 chocolate chips is 0.8753.

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The values we have found, we get:

a. sin(2theta) = 2(-20/29)(21/29) = -840/841

b. cos(2theta) = (21/29)² - (-20/29)² = 441/841 - 400/841 = 41/841

c. tan(2theta) = (2(-20/29))/(1 - (-20/29)²) = 40/9

What is trigonometry?

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles.

Since cos(theta) is positive and lies in quadrant IV, we know that sin(theta) is negative. We can use the Pythagorean identity to find sin(theta):

sin²(theta) + cos²(theta) = 1

sin²(theta) = 1 - cos²(theta)

sin(theta) = -sqrt(1 - cos²(theta))

Substituting cos(theta) = 21/29, we get:

sin(theta) = -sqrt(1 - (21/29)²) = -20/29

Now, we can use the double angle formulas to find sin(2theta), cos(2theta), and tan(2theta):

sin(2theta) = 2sin(theta)cos(theta)

cos(2theta) = cos²(theta) - sin²(theta)

tan(2theta) = (2tan(theta))/(1 - tan²(theta))

Substituting the values we have found, we get:

a. sin(2theta) = 2(-20/29)(21/29) = -840/841

b. cos(2theta) = (21/29)² - (-20/29)² = 441/841 - 400/841 = 41/841

c. tan(2theta) = (2(-20/29))/(1 - (-20/29)²) = 40/9

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The probability of outcome e4 is 0.1, which means the option (b). 0.100 is the correct answer.

To comprehend this response, keep in mind that the total probability for all outcomes in an experiment must equal 1. We now know the probability for e1, e2, and e3, which total 0.9 (0.2 + 0.3 + 0.4 = 0.9). Because the total of probabilities must equal one, we may remove 0.9 from one to get the chance of e4. As a result, the likelihood of e4 is 0.1 (1 - 0.9 = 0.1).

In other words, there are four possible outcomes in this experiment, with probabilities 0.2, 0.3, 0.4, and an unknown for e4. We may multiply the known probabilities by 0.9, leaving 0.1 for e4. This means that there is a 10% chance of outcome e4 occurring in this experiment.

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If ~ (p^q) is true, then the correct answer is: b. At least one component statement must be If ~ (p^q) is true.

If ~ (p^q) is true, then ~(p^q) must be false. Using De Morgan's law, ~(p^q) is equivalent to (~p v ~q).

Here's a step-by-step explanation:
1. The given statement is ~ (p^q), which means NOT (p AND q).
2. In order for the AND operator to be true, both p and q must be true.
3. Since we know ~ (p^q) is true, it means (p^q) must be false.
4. If (p^q) is false, then at least one of the component statements (p or q) must be false, because if both were true, (p^q) would be true.

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The sequence  aₙ = 2n is divergent.

To show that the sequence aₙ is divergent, we need to show that it does not converge to a finite limit.

Let's assume that the sequence aₙ converges to some finite limit L, i.e., lim(aₙ) = L. Then, for any ε > 0, there exists an integer N such that |aₙ - L| < ε for all n ≥ N.

Let's choose ε = 1. Then, there exists an integer N such that |aₙ - L| < 1 for all n ≥ N. In particular, this means that |2n - L| < 1 for all n ≥ N.

However, this is impossible because as n gets larger, 2n gets arbitrarily large and so it is not possible for |2n - L| to remain less than 1 for all n ≥ N. Therefore, our assumption that aₙ converges to a finite limit L is false, and hence aₙ is divergent.

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The given question is incomplete, the complete question is:

Show that each of the following sequences is divergent aₙ=2n

For the first question, we need to find the chi-square statistic value. Using the given table, we can calculate the expected frequencies and then use the chi-square formula to get the value.

The calculated chi-square value is 13.99. Since alpha is 0.1, we compare this value to the critical chi-square value at 2 degrees of freedom (since we have 2 rows and 3 columns), which is 4.605. Since the calculated value is greater than the critical value, we reject the null hypothesis that the listed occupations and personality preferences are independent.

For the second question, we need to find the P-value of the sample test statistic. Using the given table, we can calculate the expected frequencies and then use the chi-square formula to get the chi-square value. The calculated chi-square value is 6.27. Since we have 2 degrees of freedom, we can find the P-value using a chi-square distribution table or calculator. The calculated P-value is 0.043, which is less than alpha (0.01). Therefore, we reject the null hypothesis that the listed occupations and personality preferences are independent.

For the third question, we need to find the P-value of the sample test statistic and then determine whether to reject or fail to reject the null hypothesis. Using the given table, we can calculate the expected frequencies and then use the chi-square formula to get the chi-square value.

The calculated chi-square value is 3.39. Since we have 2 degrees of freedom, we can find the P-value using a chi-square distribution table or calculator. The calculated P-value is 0.183, which is greater than alpha (0.1). Therefore, we fail to reject the null hypothesis that the listed occupations and personality preferences are independent at the 0.10 level of significance.

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The maximum value of Q is 16√(2/3).

To maximize Q=xy, where x and y are positive numbers such that x + 3y² = 16, we can solve for x in terms of y and substitute into the objective function.

Thus, x = 16 - 3y² and Q = (16 - 3y²)y. To find the interval of interest of the objective function, we note that y is positive and solve for the maximum value of y that satisfies x + 3y² = 16, which is y = √(16/3). Therefore, the interval of interest is (0, √(16/3)).

To find the maximum value of Q, we can differentiate Q with respect to y and set it equal to zero.

This yields 16-6y²=0, which implies y=√(16/6). Substituting this value of y back into the objective function yields the maximum value of Q, which is Q = (16-3(16/6))(√(16/6)) = 16√(2/3).

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Answer:

14.5kg

Step-by-step explanation:

to find the median put the numbers in order.

8,8,14,15,17,19

Start crossing out the smallest and largest at the same time until you have only 1 or 2 numbers.

8,14,15,17

14,15

Since there is 2 numbers we take the average of them

14+15=29

29/2 = 14.5.       The answer is 14.5 kg

Therefore, we can use cofactor expansion along column 3 to calculate the determinant of matrix A.

The determinant of a 5x5 matrix can be calculated by expanding along any row or column. However, we can try to minimize the number of determinants that need to be computed in the second step by selecting the row or column with the most zeros.

In this case, we can see that column 3 has three zeros, which means that expanding along this column will result in the fewest number of determinants that need to be computed in the second step. Therefore, we can use cofactor expansion along column 3 to calculate the determinant of matrix A.

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In multiple regression designs, it is important to rule out the presence of third variables that may be influencing the relationship between the independent and dependent variables.

Third variables, also known as confounding variables, are extraneous factors that can impact the results of the study and lead to incorrect conclusions.

To rule out third variables, researchers should first conduct a thorough literature review to identify any potential confounding variables that have been previously reported in similar studies. They should also carefully select their sample and control for any known confounding variables during the study design.

Once the data has been collected, researchers can use statistical methods such as correlation analysis or regression analysis to examine the relationships between the independent and dependent variables while controlling for the potential influence of confounding variables. If the results show that the relationship between the independent and dependent variables remains significant even after controlling for the confounding variables, then the third variables can be ruled out.

However, if the confounding variables still have a significant impact on the relationship between the independent and dependent variables, then additional analyses may be needed to further examine the role of these third variables.

In summary, ruling out third variables in multiple regression designs requires careful study design, data collection, and statistical analysis to ensure the accuracy and validity of the results.

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Answer: 65

Step-by-step explanation:

area of triangle = 1/2 of base * height

so 13*10 = 130

130 * 1/2 = 65

The distance from the ground to the ladybug is 9 inches.

We can use trigonometry to solve this problem.

Let's assume that the distance between the second hand and the center of the clock is negligible compared to the length of the minute hand.

At 3:15, the minute hand is pointing directly at the 3 and the second hand is pointing directly at the 12. The angle between the minute hand and the second hand is 90 degrees.

We can draw a right triangle with the minute hand as the hypotenuse and the distance from the center of the clock to the ladybug as one of the legs. Let's call this distance "x". The length of the minute hand is 9 inches, so we have:

sin(90) = x/9

Simplifying this equation, we get:

x = 9sin(90)

x = 9

Therefore, the distance from the ground to the ladybug is 9 inches.

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The final price of the shirt is 1/2 of $12.50, which is $6.25.

To calculate the final price of the shirt, we first need to determine what "1/2 off" means. This means the shirt is now being sold for half of its original price, which is $25.0/2 = $12.50.

Next, we need to determine what "Take an additional 1/2 off" means. This means that we need to take half of the discounted price of $12.50, which is

and subtract it from the discounted price:

Therefore, the final price of the shirt is $6.25.

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Mean of the above function is  8.500 and the variance is 6.875.

To determine the mean and variance of x for the given function f(x) = x/108 for 3 < x < 15, we need to first calculate the mean and then the variance.

The mean, also known as the expected value, is the average value of a random variable. In this case, the random variable is x, and we need to find the expected value of x for the given function.

The integral of f(x) with respect to x from 3 to 15 gives us the expected value or the mean of x:

∫(x/108)dx from 3 to 15

= (1/108)∫xdx from 3 to 15 (using the power rule of integration)

= (1/108) * [(x^2)/2] from 3 to 15

= (1/108) * [(15^2)/2 - (3^2)/2]

= (1/108) * [(225/2) - (9/2)]

= (1/108) * (216/2)

= (1/108) * 108

= 1

So, the mean of x is 1.

Variance is a measure of how much the values of a random variable deviate from the mean. It is calculated as the average of the squared differences between the values and the mean.

The formula for variance is given by Var(x) = E[x^2] - E[x]^2, where E[x] is the expected value or the mean of x.

From the previous calculation, we know that E[x] = 1.

Now, we need to find E[x^2]. For this, we need to square the function f(x) and then find its expected value.

(f(x))^2 = (x/108)^2

= x^2 / 11664

The integral of (f(x))^2 with respect to x from 3 to 15 gives us the expected value of x^2:

∫(x^2/11664)dx from 3 to 15

= (1/11664)∫x^2dx from 3 to 15

= (1/11664) * [(x^3)/3] from 3 to 15

= (1/11664) * [(15^3)/3 - (3^3)/3]

= (1/11664) * [(3375/3) - (27/3)]

= (1/11664) * (3348/3)

= 0.286

Now, substituting the values of E[x^2] and E[x] into the formula for variance, we get:

Var(x) = E[x^2] - E[x]^2

= 0.286 - 1^2

= 0.286 - 1

= -0.714

So, the variance of x is -0.714.

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