Examine the values of f along the curves that end at (0,0). Along which set of curves is f a constant value?

y= kx^2
y= kx +kx^2
y=kx^3
y=kx

Answer:

Step-by-step explanation:

You want the translation that maps f(x) = x² to g(x) = x² -6x +6.

A graph of the two functions shows g(x) is right 3 units and down 3 units from f(x).

We know the vertex of f(x) = x² is the origin (0, 0). The vertex of g(x) will tell us the translation. Putting that function in vertex form, we have ...

  g(x) = x² -6x +6

  g(x) = (x² -6x) +6

  g(x) = (x² -6x +9) +6 -9 . . . . . add and subtract 9 to complete the square

  g(x) = (x -3)² -3

Compare this to ...

  y = (x -h)² +k . . . . . . has vertex (h, k)

We see that (h, k) = (3, -3).

g(x) is translated right 3 units and down 3 units.

The distribution is skewed left and leptokurtic is the correct shape of distribution. The correct answer is option B.

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A schema is essentially a blueprint or a framework that describes how all the data within a database is organized and structured. Within this schema, entities, attributes, and relationships are defined. Entities refer to objects or concepts within the database, such as customers, orders, or products.

Attributes are the characteristics or properties of these entities, such as a customer's name or an order's date. Relationships describe how these entities are related to or connected to each other, such as a customer placing an order. When external schemas are developed for a business, they define entities, attributes, and relationships specific to a particular aspect of the business. These external schemas are then combined into the overall schema to create a comprehensive view of all the data within the database.

An entity schema is a set of entities and the relationships among them. In an Extreme Scale application with multiple partitions, the following restrictions and options apply to entity schemas: Each entity schema must have a single root defined. This is known as the schema root. an ER model deals with entities and their relationship, whereas a relational schema talks about tuples and attributes. Moreover, an ER model may be easier to understand than a relational schema because we map the cardinalities explicitly (one-to-one, many-to-one, etc.).

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The current through R2 will depend on the values of the components in the circuit and the initial current through the inductor. Without more information, it is not possible to determine the current through R2.

After the switch is open, the current through the inductor will continue to flow in the same direction but will gradually decrease over time. The current through R2 will depend on the values of the components in the circuit and the initial current through the inductor. Without more information, it is not possible to determine the current through R2.
We want to know the current through resistor R2 immediately after the switch is opened, given that the current through the inductor is 20.4 mA. To provide an accurate answer, I would need more information about the circuit, such as the values of the resistors, inductor, and any voltage sources. However, I will explain the concept behind the problem.
When the switch is opened after being closed for a long time, the inductor behaves like a current source due to its stored energy. Since the current through the inductor is given as 20.4 mA, the current flowing through R2 will be the same (20.4 mA) immediately after the switch is opened, assuming there are no other current paths in the circuit.

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The values for x(1) and x(-1) are both 0.

To find the values of x(1) and x(-1) given that x(t) = 2·tri(t/4)*δ(t – 2), we will evaluate the function at these points.

a. x(1):
To find the value of x(1), we need to substitute t = 1 into the function:
x(1) = 2·tri(1/4)*δ(1 - 2)

Since δ(1 - 2) is the Dirac delta function at a point different from zero (specifically, -1), its value is 0.

Therefore,
x(1) = 2·tri(1/4) * 0 = 0

b. x(-1):
To find the value of x(-1), we need to substitute t = -1 into the function:
x(-1) = 2·tri(-1/4)*δ(-1 - 2)

Again, since δ(-1 - 2) is the Dirac delta function at a point different from zero (specifically, -3), its value is 0.

Therefore,
x(-1) = 2·tri(-1/4) * 0 = 0

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The inverse Laplace transform of the function F(s)=(2s+2)/(s^2+2s+5) is f(t) = 2e^(-t) cos((2t)) and the inverse Laplace transform of the F(s)=(2s+1)/(s^2-2s+2) is f(t) = 2te^t + t^2e^t + e^t

To find the inverse Laplace transform of F(s)=(2s+2)/(s^2+2s+5), we need to complete the square in the denominator:

s^2+2s+5 = (s+1)^2 + 4

Now we can write F(s) as:

F(s) = 2(s+1)/(s+1)^2 + 4

Using the formula for the inverse Laplace transform of s-a/((s-a)^2+(b)^2), we can see that the inverse Laplace transform of 2/(s+1)^2 is 2te^(-t). Thus, the inverse Laplace transform of F(s) is:

f(t) = 2e^(-t)cos((2t))

To find the inverse Laplace transform of F(s)=(2s+1)/(s^2-2s+2), we can use partial fraction decomposition:

F(s) = (2s+1)/(s^2-2s+2) = (2s-2)/(s^2-2s+2) + 1/(s^2-2s+2)
      = 2(s-1)/(s-1)^2 + 1/(s-1)^2 + 1

Using the formula for the inverse Laplace transform of 1/((s-a)^2+(b)^2) and 1/((s-a)^(n+1)  we can see that the inverse Laplace transform of 1/(s-1)^2 is te^t. Thus, the inverse Laplace transform of F(s) is:

f(t) = 2te^t + t^2e^t + e^t

Explanation: - To evaluate F(s)=(2s+2)/(s^2+2s+5), First write the given expression in the s-a/((s-a)^2+(b)^2) format then use the formula of the inverse Laplace transform to get the value, similarly, to evaluate  F(s)=(2s+1)/(s^2-2s+2) break the given expression in the summation of the  1/((s-a)^2+(b)^2) and 1/((s-a)^(n+1).

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The number of boxes that can fit into the crate is 7 boxes.

A cuboid has a hexahedron six-faced solid shape and the volume is determined by multiplying the length by width by height. Here; the volume of the crate is determined by finding the volume of the cuboid.

Volume of the cuboid is: 2.4 m × 1.8 m × 1.1 m

Volume of the cuboid  = 4.752 m³

To cm, volume of the cuboid  = 475.2 cm³

Now, since the cube has a length of 60 cm, then the number of boxes that will fit into the crate can be estimated by dividing the volume of the cuboid shape by the length of the cube.

Thus, the number of boxes that can fit into the crate is:

= 475.2 cm/ 60 cm

= 7. 92

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The required decimal numbers are 8.43, 8.403, 8.403, and 8.43.  

In mathematics, place value is the value of a digit in a number based on its position. For example, in the number 123, the digit 3 is in the one's place, representing the value of 3 ones.

Decimal notation is a system of writing numbers using a base value of 10 and the digits 0-9. In decimal notation, each digit in a number represents a multiple of a power of 10. For example, in the number 123.45, The digit 4 is in the tenth place, representing the value of 4 tenths.

Here we have 8.43

The number can be expressed as follows

8.43 = 843 hundredths = 8.43

8.43 = 84 tenths and 3 thousandths = 8.403

8 ones 4 hundredths and 3 thousandths  = 8.403

8.43 = 8 + 0.4 + 0.03 = 8.43  

Therefore,

The required decimal numbers are 8.43, 8.403, 8.403, and 8.43.  

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The equations that represent the circle with diameter 12 are x² + (y - 6)² = 36 and x² + (y + 6)² = 36.

A circle can be represented in polar coordinates by the equation r = a, where an is the circle's radius. In polar coordinates, the circle's centre is found at the origin (0, 0).

We use the links between polar and rectangular coordinates to translate this equation to rectangular coordinates:

X=r cos(theta) and Y=r sin (theta)

When we add r = a to these equations, we obtain:

X = cos(theta) and Y = sin (theta)

Hence, the equation of a circle in rectangular coordinates with radius "a" and origin-based centre.

The standard form of the equation of circle is given as:

(x - h)² + (y - k)² = r²

Here, (h , k) are the center and r is the radius.

For diameter = 12 we have radius = 6. Thus, the square of the radius is 36.

The equations representing this radius are:

x² + (y - 6)² = 36 and x² + (y + 6)² = 36

Hence, the equations that represent the circle with diameter 12 are x² + (y - 6)² = 36 and x² + (y + 6)² = 36.

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The value of the angle is 34 degrees

To determine the value of the variable, we need to the following;

From the information given, we have that the angles are;

73 degrees

73 degrees

x degrees

Equate the angles

73 + 73 +x = 180

collect the like terms

x = 180 - 146

subtract the values

x = 34 degrees

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The general solution of differential equation y" - 8y' + 16y = 4e^4x + e^4x/x is y = C_1e^-4x + C_2 xe^-4x + 4x^2 e^4x + e^4x ln x. So, the correct answer is A).

The given differential equation is

y" - 8y' + 16y = 4e^(4x) + e^(4x)/x

The characteristic equation is

r^2 - 8r + 16 = 0

Solving this equation, we get

r = 4 (repeated root)

So, the homogeneous solution of the differential equation is

y_h = (C_1 + C_2x) e^(4x)

To find the particular solution, we will use the method of undetermined coefficients.

For the first term 4e^(4x), we can take the particular solution as

y_p1 = A e^(4x)

Differentiating and substituting in the differential equation, we get

16A e^(4x) - 32A e^(4x) + 16A e^(4x) = 4e^(4x)

Simplifying, we get

A = 1/4

So, the particular solution for 4e^(4x) is

y_p1 = (1/4) e^(4x)

For the second term e^(4x)/x, we can take the particular solution as

y_p2 = B e^(4x) ln x

Differentiating and substituting in the differential equation, we get

16B ln x e^(4x) - 8B e^(4x) + 16B e^(4x) ln x = e^(4x)/x

Simplifying, we get

B = 1/8

So, the particular solution for e^(4x)/x is

y_p2 = (1/8) e^(4x) ln x

Therefore, the general solution of the given differential equation is

y = y_h + y_p1 + y_p2

y = (C_1 + C_2x) e^(4x) + (1/4) e^(4x) + (1/8) e^(4x) ln x

Hence, the correct option is (a) y = C_1e^-4x + C_2 xe^-4x + 4x^2 e^4x + e^4x ln x.

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The percent of tools should be produced by factories B and C so that a tool picked at random in the market will have a probability of being non defective equal to 96% = 0.96 are 5% and 95% respectively.

We have three factories produce the same tool and supply it to the market. Let's consider three events defined as, A = event for tools produced by factory A

B = event for tools produced by factory B

C = event for tools produced by factory C and N be the count that tools produced by all factories is not defective.

The probability that the tools produced by factory A for the market, P( A) = 30%

= 0.30

The probability that the tools produced by factories B and C for the market, P( B and C) = 70% = 0.70

The Probability that tools are non- defective and that are produced in factory A, P( N/A) = 98%

= 0.98

The Probability that tools are non- defective and that are produced in factory B, P( N/B) = 95%

= 0.95

The Probability that tools are non- defective and that are produced in factory C, P( N/C) = 97% = 0.97

Now, since only three factories supply to the whole market, then by probability law, P(A) + P(B) + P( C) = 1

=> 0.3 + P(B) + P( C) = 1

=> P(B) = 0.7 - P(C) --(1)

We have to determine percent of tools should be produced by factories B and C that is P(C) and P(B) when probability of non defective, P(N) is 96% = 0.96. From the law of total probability law, P(N) is written by, P( N) = P( N/A) P(A) + P( N/B) P(B) + P( N/C) P( C)

=> 0.96 = 0.98 × 0.3 + 0.95 × ( 0.7 - P(C) ) + 0.97 × P(C)

=> 0.96 = 0.98 × 0.3 + 0.95 × 0.7 - 0.95 P(C) + 0.97 × P(C)

=> 0.96 = 0.98 × 0.3 + 0.95 × 0.7 - 0.95 P(C) + 0.97 × P(C)

=> 0.96 = 0.294 + 0.665 + 0.02 × P(C)

=> 0.96 = 0.959 + 0.02 × P(C)

=> 0.02 × P(C) = 0.96 - 0.959

=> 0.02 × P(C) = 0.001

=> P(C) = 0.05 = 5%

from equation (1), P(B) = 1 - P(C)

=> P( B) = 1 - 0.05 = 0.95

Hence, required percentage is 95%.

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The answer of the given question based on the graph is the value of 'a' affects the graph by determining the steepness of the curve.

Slope is a measure of the steepness of a line or a curve. It is defined as  ratio of vertical change (rise) between two points to  horizontal change (run) between  same two points. The slope of a line is constant, while the slope of a curve may change from point to point.

In the equation y = ab(x-h)+k, the value of 'a' affects the graph by determining the steepness of the curve.

If 'a' is positive, the graph will slope upwards as 'x' increases. The larger the value of 'a', the steeper the slope of the curve will be. On the other hand, if 'a' is negative, the graph will slope downwards as 'x' increases. Again, the larger the absolute value of 'a', the steeper the slope of the curve will be.

In general, the value of 'a' controls the vertical scaling of the curve, while the value of 'b' controls the horizontal scaling, and 'h' and 'k' control the horizontal and vertical translations of the curve, respectively. Changing the value of 'a' will stretch or compress the curve vertically, but will not affect the position of the curve on the x-axis.

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The particular solution is [tex]3x^(-1) - 1/27 + 3(9)^(-2)[/tex] based on integration.

To find a particular solution to given equatio we need to integrate twice. First, we integrate with respect to x to get [tex]-3x^(-2)[/tex].

Then, we integrate again with respect to x to get 3x^(-1) + C1, where C1 is a constant of integration.

Next, we use the initial condition 6′ 9 to solve for C1. Taking the derivative of [tex]3x^(-1) + C1[/tex], we get [tex]-3x^(-2)[/tex]. Plugging in x = 9, we get [tex]-3(9)^(-2) = -1/27[/tex].

Therefore, [tex]-1/27 = -3(9)^(-2) + C1[/tex], and solving for C1, we get[tex]C1 = -1/27 + 3(9)^(-2)[/tex].

Thus, the particular solution is [tex]3x^(-1) - 1/27 + 3(9)^(-2)[/tex].
Hi! It seems there might be a typo in your question, making it difficult to understand the exact problem you need help with. However, I will try to address the terms "solution" and "particular."

A "solution" refers to the result or answer obtained when solving an equation, problem, or system of equations. It is the value or values that satisfy the given conditions or equations.

A "particular solution" is a specific instance of a solution, usually when there are multiple solutions or when dealing with differential equations. It is a single example of a valid answer that meets the given criteria.

If you can provide more clarification on your question, I would be happy to help you find the particular solution you're looking for!

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The values for the sums are: a) 20, b) 11, c) 30, and d) -430.

Here are the values for each:

a) ∑_(k=1)^5 (k+1) = (1+1) + (2+1) + (3+1) + (4+1) + (5+1) = 2 + 3 + 4 + 5 + 6 = 20

b) ∑_(j=0)^4 (-2)^j = (-2)^0 + (-2)^1 + (-2)^2 + (-2)^3 + (-2)^4 = 1 - 2 + 4 - 8 + 16 = 11

c) ∑_(i=1)^10 3 = 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 30 (since there are 10 terms, each with a value of 3)

d) ∑_(j=0)^8 (2j+1 - 2^j) = ∑_(j=0)^8 (2j+1) - ∑_(j=0)^8 (2^j)
First, find the two separate sums:
∑_(j=0)^8 (2j+1) = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 = 81
∑_(j=0)^8 (2^j) = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 = 511
Now subtract the two sums: 81 - 511 = -430

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$5744 is Ashley’s monthly payment.

The amount of the down payment made by Ashlee is 15% of $875,000, which is:

Down payment = 0.15 x $875,000 = $131,250

The amount that Ashlee took out on a mortgage is:

Mortgage amount = Purchase price - Down payment

= $875,000 - $131,250

= $743,750

The monthly payment on a mortgage:

[tex]M = P [ i(1 + i)^n ] / [ (1 + i)^n - 1 ][/tex]

where:

M = monthly payment

P = principal amount (mortgage amount)

i = monthly interest rate (annual interest rate / 12)

n = total number of monthly payments (amortization period x 12)

In this case, the annual interest rate is 6.95% and the term is for 5 years, so we need to first calculate the monthly interest rate and the total number of monthly payments.

Monthly interest rate = 6.95% / 12 = 0.57917%

Total number of monthly payments = 20 years x 12 = 240

Substituting these values into the formula, we get:

M = $743,750 [ 0.0057917 (1 + 0.0057917)^240 ] / [ (1 + 0.0057917)^240 - 1 ]

= $5744.002

Therefore, Ashley's monthly payment on the mortgage is $5744.

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The only values of n that work are n = 1 and n = 5.

Let's call the nth element of the set as S(n).

Notice that S(n) is a number that can be written as:

[tex]S(n) = 5 + 50 + 500 + ... + 5 * 10^{n-1}[/tex]

which can be simplified as:

[tex]S(n) = 5 * (1 + 10 + 10^2 + ... + 10^{n-1} )[/tex]

Using the formula for the sum of a geometric series, we can simplify further:

[tex]S(n) = 5 * (10^n - 1) / 9[/tex]

Now, suppose n divides S(n) (that is, S(n) is a multiple of n).

Then we have:

S(n) ≡ 0 (mod n)

[tex]5 * (10^n - 1) / 9[/tex] ≡ 0 (mod n)

Multiplying both sides by 9n, we get:

[tex]5 * (10^n - 1)[/tex] ≡ 0 (mod n)

[tex]5 * 10^n[/tex] ≡ 5 (mod n).

Now, if n divides 5, then n = 1 or n = 5, and both of these values work. So assume that n does not divide 5.

Then, by Fermat's Little Theorem, we have:

[tex]10^{n-1}[/tex] ≡ 1 (mod n)

Multiplying both sides by 10, we get:

[tex]10^n[/tex] ≡ 10 (mod n)

Therefore, we have:

5 × 10 ≡ 5 (mod n)

So n divides 5, which is a contradiction.

Therefore, the only values of n that work are n = 1 and n = 5.

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The value of dy=1.200

To compute δy and dy for [tex]y = 2x - x^2[/tex]  at x = 2 and δx = -0.6, we can use the following formulas:

δy ≈ f'(x) δx

dy ≈ f'(x) dx

where f'(x) is the derivative of f(x) with respect to x.

First, we can find f'(x) by taking the derivative of y with respect to x:

[tex]f(x) = 2x - x^2[/tex]

f'(x) = 2 - 2x

Substituting x = 2, we get:

f'(2) = 2 - 2(2) = -2

Using δy ≈ f'(x) δx and substituting x = 2 and δx = -0.6, we have:

δy ≈ f'(2) δx = (-2)(-0.6) = 1.2

Therefore, δy ≈ 1.2.

Using dy ≈ f'(x) dx and substituting x = 2 and dx = δx = -0.6, we have:

dy ≈ f'(2) δx = (-2)(-0.6) = 1.2

Therefore, dy ≈ 1.2.

Rounding to three decimal places, we have:

δy ≈ 1.200 and dy ≈ 1.200

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The answer is: Test the series for convergence or divergence. [infinity] Σ (-1)n+1/3n² - converges.

To test the series Σ (-1)n+1/3n² for convergence or divergence, we can use the alternating series test. This test states that if a series alternates in sign and the absolute value of its terms decreases monotonically to zero, then the series converges.

In this case, the series Σ (-1)n+1/3n² alternates in sign and the absolute value of its terms is given by 1/3n², which decreases monotonically to zero as n increases. Therefore, we can apply the alternating series test and conclude that the series converges.

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Answer:245/36 π

Step-by-step explanation: you do 50/360 times π(7)^2

Answer:

{-1, 0, 1, 2, 3}

Step-by-step explanation:

. 2-6y<14

-6y < 12

y > 12/-6

y > -2.

1<21-5y

-5y > -20

y < 4.

So -2 < y < 4

and the solution set of integers is

{-1, 0, 1, 2, 3}

Using the open cover definition of compactness, we can show that (1) open ball B(x, 1), (2) set A in R², and (3) an infinite set in a discrete metric space are not compact by exhibiting open covers with no finite sub-covers.


(1) For the open ball B(x, 1) in Rⁿ, consider the open cover consisting of balls B(x, 1-1/n) for n = 2, 3, 4, ... Since each ball excludes a point on the boundary of B(x, 1), no finite sub-collection can cover B(x, 1).

(2) For the set A in R², consider the open cover consisting of rectangles {(-1/n, 1/n) x (0, 1)} for n = 2, 3, 4, ... No finite sub-collection of these rectangles can cover A, as there will always be a gap along the x₁-axis.

(3) In the metric space (M, d) with a discrete metric d, let S be an infinite subset. The open cover consists of balls B(x, 1/2) centered at each point x in S. Since each ball contains only one point, there cannot be a finite sub-cover for the infinite set S.

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Completing the inductive step and identifying where the inductive hypothesis is used, the correct multiple choice answer is: Replacing the quantity in brackets on the left-hand side of part (c) by what it equals by virtue of the Inductive hypothesis, we have (kok+") + (x + 1)² = (x + 1)² +68+4)* (+1)(x+2) as desired.

In an induction proof, the inductive step involves assuming a statement is true for some arbitrary value, say k, and then proving it's true for the next value, k+1.

Here, the inductive hypothesis corresponds to the term (kok+"). By replacing this term on the left-hand side of part (c) with its equivalent based on the inductive hypothesis, we can show that the equation holds for the (k+1) case as well. This is crucial for proving the statement using induction, as it establishes the necessary pattern for all cases.

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The GLB of the set {x : |x - 4| < 1}  is option (d) 3

The set {x : |x - 4| < 1} can be written as the open interval (3, 5), which contains all values of x that satisfy the inequality |x - 4| < 1.

The greatest lower bound (GLB), also known as the infimum, is a concept in mathematics that applies to sets of numbers or other mathematical objects that are partially ordered.

To find the GLB (greatest lower bound) of this interval, we need to look for the greatest value that is less than or equal to every element in the interval.

Since the interval contains all real numbers greater than 3 and less than 5, its GLB is 3. Therefore, the answer is option (d) 3.

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The binomial theorem cannot be used to expand expressions of the form (a - b)^n, where n is an even integer and a and b are real numbers.

The binomial theorem states that for any real numbers a and b, and a non-negative integer n, the expression (a+b)^n can be expanded as the sum of the terms in the form:
(a+b)^n = C(n,0) * a^n * b^0 + C(n,1) * a^(n-1) * b^1 + ... + C(n,n) * a^0 * b^n
where C(n,k) denotes the binomial coefficient, which can be calculated using the formula:
C(n,k) = n! / (k! * (n-k)!)
In this expansion, each term represents a product of the powers of a and b, with the exponents summing up to n. The binomial coefficients, C(n,k), indicate the number of ways to choose k items from a set of n items.
So, the binomial theorem allows us to expand expressions involving the sum of two real numbers raised to a power, using the binomial coefficients and the powers of the real numbers.

The binomial theorem is a powerful formula that allows us to expand expressions of the form (a + b)^n, where n is a non-negative integer. Specifically, the theorem states that (a + b)^n = sum from k=0 to n of (n choose k) * a^(n-k) * b^k, where (n choose k) denotes the binomial coefficient, which is equal to n! / (k! * (n-k)!). However, if we let b = -a, then (a + b)^n becomes (a - a)^n = 0^n = 0. Therefore, the binomial theorem cannot be used to expand expressions of the form (a - b)^n, where n is an even integer and a and b are real numbers. In such cases, we need to use alternative methods such as the difference of squares formula or the factor theorem.

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The solution of the differential equation dx/dt = sin(t²)×t with the initial condition x(0) = 20 is [tex]x(t) = 20 + \int_{0}^{t}tsin(t^2) dt[/tex].

In mathematics, a differential equation is an equation that relates one or more unknown functions and their derivatives. In applications, the functions generally represent physical quantities, the derivatives represent their rates of change, and the differential equation defines a relationship between the two.

To solve the given differential equation dx/dt = sin(t²)×t with the initial condition x(0) = 20 and leaving the answer as a definite integral, follow these steps:

1. Identify the given differential equation:

dx/dt = sin(t²)×t.

2. Recognize the initial condition:

x(0) = 20.

3. Integrate both sides of the equation with respect to t:

∫dx = ∫sin(t²)×t dt.

4. Apply the initial condition to determine the constant of integration:

x(0) = 20.

5. Write the final solution:

[tex]x(t) = 20 + \int_{0}^{t}tsin(t^2) dt[/tex].

So, the solution is [tex]x(t) = 20 + \int_{0}^{t}tsin(t^2) dt[/tex].

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The general solution of the given differential equation is expressed in terms of Bessel functions as y(x) = c1 J₀(x) + c2 Y₀(x) - c3 J₁(x) + c4 Y₁(x), where J and Y are Bessel functions of the first and second kind, respectively, and c1, c2, c3, and c4 are constants.

To express the general solution in terms of Bessel functions, we first need to determine the characteristic equation of the given differential equation. We assume the solution has the form y(x) = x^r, then differentiate twice to get

y'(x) = rx^(r-1)

y''(x) = r(r-1)x^(r-2)

Substituting these expressions into the given differential equation, we get

x^2y''+4xy'+(x^2+2)y = x^2[r(r-1)x^(r-2)] + 4x[rx^(r-1)] + (x^2+2)x^r = 0

Dividing through by x^2, we get

r(r-1) + 4r + (1+2/x^2) = 0

Simplifying and multiplying by x^2, we get the Bessel equation

x^2y'' + xy' + (x^2 - 1)y = 0

The general solution to this differential equation can be expressed in terms of Bessel functions of the first kind, Jv(x), and second kind, Yv(x), as follows

y(x) = c1J0(x) + c2Y0(x)

where c1 and c2 are constants of integration. Therefore, the general solution to the original differential equation can be expressed as

y(x) = c1J0(x) + c2Y0(x) + c3J1(x) + c4Y1(x)

where c3 and c4 are constants of integration determined by the initial conditions.

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The probability that the number of U.S. adults who favor the use of unmanned drones by police agencies is​:

(a) P(3) = 0.2636

(b) P(x≥4) = 0.1814

(c) P(x<8) = 0.9997

(a) To find the probability that exactly three out of twelve U.S. adults favor the use of unmanned drones by police agencies, we can use the binomial probability formula:

P(3) = (12 choose 3) * (0.38)^3 * (1-0.38)^(12-3) = 0.2636

where (12 choose 3) = 12! / (3! * 9!) represents the number of ways to choose 3 out of 12 adults.

(b) To find the probability that at least four out of twelve U.S. adults favor the use of unmanned drones by police agencies, we can use the complement rule and subtract the probability of having three or fewer adults who favor the use of drones from 1:

P(x≥4) = 1 - P(x≤3) = 1 - [(12 choose 0) * (0.38)^0 * (1-0.38)^(12-0) + (12 choose 1) * (0.38)^1 * (1-0.38)^(12-1) + (12 choose 2) * (0.38)^2 * (1-0.38)^(12-2) + (12 choose 3) * (0.38)^3 * (1-0.38)^(12-3)] = 0.1814

(c) To find the probability that less than eight out of twelve U.S. adults favor the use of unmanned drones by police agencies, we can sum up the probabilities of having zero to seven adults who favor the use of drones:

P(x<8) = P(x=0) + P(x=1) + ... + P(x=7) = (12 choose 0) * (0.38)^0 * (1-0.38)^(12-0) + (12 choose 1) * (0.38)^1 * (1-0.38)^(12-1) + ... + (12 choose 7) * (0.38)^7 * (1-0.38)^(12-7) = 0.9997

Note that the probability of having eight or more adults who favor the use of drones is negligible.

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Make the amount of money they have £100 because this makes the question easier.

Colin gets 3/10 of the money, so Colin will get £30.

After Colin has taken his share £70 will be left over.

The ratio give is 3 : 2. So 3 + 2 is equal to 5.

The amount of money left over is then divided by the ratio added in this case its 70/5.

70/5 gives us an answer of 14 .

This means that each share is equal to £14.

Emma gets the ratio of 3 so we do 3 x 14 which gives us he answer of  £42.

And if we do 3 x 2 we get the answer of £28.

We then know Dave gets £26 pounds from the £100 at the start.

26/100 converted to a percentage is 26%.