Discussion - the optimum pH of yeast ADH:
Fill in the gaps with the correct numbers, words or phrases from the list provided below for this question, to
discuss what is known about the optimum pH of yeast ADH.
Some words, phrases or numbers may be used more than once and others not at all. The spelling must be
correct, and the decimal numbers must be written in UK/USA style, with 'dot' not comma', otherwise the
automatic marking system will not recognise the words and numbers used.
Commercial sources describe Yeast alcohol dehydrogenase (EC 1.1.1.1.) as an enzyme with a molecular
weight of Blank 1, a tetrameric Blank 2, an isoelectric point of Blank 3, an optimal pH of Blank 4 and an
ability to recognise several types of alcohols as substrates, but being most active with Blank 5 (Sigma-Aldrich,
2014, citing sources published up to 1993).
The optimal pH is the pH value at which an enzyme has the Blank 6 activity. This is determined mainly by the
structure of the enzyme, but in practice it can be influenced by the experimental protocol and the actual
assay conditions. Silverstein (2016) reported an average optimal pH of Blank 7 for yeast ADH, with a range of
Blank 8, which is broader than that given by Sigma-Aldrich (2014), while Aquino Neto et al. (2011) found that
the activity of yeast ADH in solution was highest in the Blank 9 pH range, which is closer to the neutral pH
than that from Sigma-Aldrich (2014).

In the process of transcription, DNA is used as a template for making another type of nucleic acid called RNA. The process begins when the enzyme binds to a region called the promoter region.

The process of transcription refers to the cellular mechanism which used the genetic information provided by DNA to synthesize a complementary RNA strand to a given fragment of the molecule, which is then used to generate a protein in the case of the messenger RNA molecule or mRNA.

Therefore, with this data, we can see that the process of transcription is based on the use of a fragment of a single strand in the DNA nucleotide sequence which is used as a template to create a single-strand RNA sequence similar to the first but complementary.

Complete question:

Fill in the blanks. In the process of ___, DNA is used as a template for making another type of nucleic acid called ___. The process begins when the enzyme binds to a region called the ____.

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Answer:

The tissue type in the respiratory system complements its function by providing the structural support and specialized features necessary for efficient gas exchange. The respiratory system is responsible for bringing oxygen into the body and removing carbon dioxide, and different tissue types in the respiratory system are adapted to perform these functions effectively.

The lungs are the primary organ of the respiratory system, and they are made up of several different tissue types. The outermost layer of the lungs is the pleura, which is a thin, transparent membrane that surrounds the lungs and allows them to expand and contract during breathing.

Inside the lungs, the tissue is divided into small air sacs called alveoli. The alveoli are lined with a specialized type of tissue called the alveolar epithelium, which is made up of cells with thin, flattened shapes that allow for efficient gas exchange. The alveoli are also surrounded by a network of capillaries, which are small blood vessels that carry oxygen and carbon dioxide between the lungs and the rest of the body.

In addition to the alveoli and capillaries, the lungs also contain a network of tubes called bronchi and bronchioles, which help to distribute air throughout the lungs. The walls of these tubes are made up of smooth muscle tissue, which allows them to expand and contract to regulate the flow of air.

Overall, the tissue types in the respiratory system are well-suited to their functions, providing the structural support and specialized features necessary for efficient gas exchange. This allows the respiratory system to perform its vital role in bringing oxygen into the body and removing carbon dioxide.

Explanation:

The skeletopy of the lungs is defined as the study of the lungs with respect to the relation of the various bones of the body.

The lungs is the main organ of respiratory system of the body which is made up of the right and the left lungs and is located at the thoracic region of the body.

The lungs can be studied in various ways by the anatomist and with respect to its relationship with other structures of the body. These include the following:

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Hormones fall into three primary chemical categories: protein/polypeptides, steroids, and those created from modified amino acids. They are not included in the chemical grouping of carbohydrates.

On the basis of their chemical makeup, the hormones in the human body can be categorized into two main classes. Amino acid-derived hormones include amines, peptides, and proteins. Steroids are those produced from lipids.

Abstract. Steroid hormones are a class of hormones that are made from cholesterol and function in the body as chemical messengers. The growth and operation of the reproductive system are two of the many physiological processes that the steroid hormones control.

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The calculated answer for the torque is  5.357 Nm and the force is 17.28 N for the forearm given in the figure.

We must determine the required torque and the force that the triceps muscle produces in order to answer the issue.

We are aware that the conservation of angular momentum is disrupted when a system receives a net torque, which causes angular acceleration.

Allow the arm to be massless here.

A symbol for the torque is as.

             τ=Iα

Where (I) is the moment of inertia.

α is the angular acceleration.

So,

 τ=mR^2 α

   τ=mRa

Here we have used the relationship between angular and tangential acceleration, which is: α=a/R.

The position vector is:  R = 0.31

The mass is m =2.7

The tangential acceleration is:   a =6.4 m/s2

So, the torque will be,

τ=2.7*0.31*6.4

 =5.3568

So, the required torque is 5.357 Nm.

And we know that torque is:  τ=F.R

So,   force is F =  τ/r

= 5.357/0.31

=17.28 N

The complete question is:

The forearm in the figure(figure 1) accelerates a 2.7 kg ball at 6.4 m/s2 by means of the triceps muscle, as shown. a) Calculate the torque needed. Ignore the mass of the arm. Answer in m*Nb) Calculate the force that must be exerted by the triceps muscle. Answer in N

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