Data Collection
Mass of the original sample of mixture (g) 1.558
Mass of recovered naphthalene (g) 0.483
Mass of recovered 3-nitroaniline (g) 0.499
Mass of recovered benzoic acid (g) 0.467
Calculations:
a. % by mass of naphthalene in original sample.
b. % by mass of 3-nitroaniline in original sample.
c. % by mass of benzoic acid in original sample.
d. total percent recovered.

Answers

Answer 1

Answer:

For a): The mass percent of naphthalene in the original sample is 31.00 %.

For b): The mass percent of 3-nitroaniline in the original sample is 32.03 %.

For c): The mass percent of benzoic acid in the original sample is 29.97 %.

For d): The total percent recovered is 93.00 %.

Explanation:

Percentage by mass is defined as the ratio of the mass of a substance to the mass of the solution multiplied by 100. The formula used for this is:  

[tex]\text{Percent by mass}=\frac{\text{Mass of substance}}{\text{Mass of a solution}} \times 100[/tex]               ......(1)

a):

Mass of naphthalene = 0.483 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

[tex]\%\text{ mass of naphthalene}=\frac{0.483 g}{1.558}\times 100\\\\\%\text{ mass of naphthalene}=31.00 \%[/tex]

b):

Mass of 3-nitroaniline = 0.499 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

[tex]\%\text{ mass of 3-nitroaniline}=\frac{0.499 g}{1.558}\times 100\\\\\%\text{ mass of 3-nitroaniline}=32.03 \%[/tex]

c):

Mass of benzoic acid = 0.467 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

[tex]\%\text{ mass of benzoic acid}=\frac{0.467 g}{1.558}\times 100\\\\\%\text{ mass of benozic acid}=29.97 \%[/tex]

d):

Total mass recovered = [0.483 + 0.499 + 0.467] = 1.449 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

[tex]\text{Total percent recovered}=\frac{1.449 g}{1.558}\times 100\\\\\text{Total percent recovered}=93.00\%[/tex]


Related Questions

How many moles of magnesium nitrate are produced when he reacts 0.34 moles of nitric acid with excess magnesium?

Answers

Jeirurbekwiufbekwididjdeu

A car generates 2552 N and weighs 2250 kg. What is its rate of acceleration

2 m/s ^2
0.88m/s^2
5,742,000m/s^2
1.13m/s^2

Answers

Answer:

[tex]a=1.134\frac{m}{s^2}[/tex]

Explanation:

Hello there!

In this case, by considering the physical definition of force in terms of mass and acceleration:

[tex]F=m*a[/tex]

Given the generated force and the involved mass, we can compute the required acceleration as shown below:

[tex]a=\frac{F}{m}\\\\a=\frac{2552N}{114kg}[/tex]

Yet it is necessary to break out Newtons to:

[tex]a=\frac{2552\frac{kg*m}{s^2} }{114kg}\\\\a=1.134\frac{m}{s^2}[/tex]

Best regards!

Which of the following forces has the smallest energy per bond?
A) iconic bonds
B) covalent bonds
C) hydrogen bonds
D) dispersion bonds

Answers

......A) iconic bonds........

The attractive forces existing between the molecules of a substance are known as the intermolecular forces. Among the given forces dispersion bonds has the smallest energy per bond. Thus option D is correct.

What is Dispersion forces?

The forces which are found in nonpolar molecules like O₂, N₂, Cl₂ etc. as well as in monoatomic gases such as 'He', 'Ne' etc. are called dispersion forces or London forces.

The London force is found to be the weakest intermolecular force and it is known to operate in all types of molecules. This force is also called the induced dipole - induced dipole attraction.

This force is generally resulted from the movement of electron cloud which creates a temporary instantaneous dipole. This distorts the arrangement of electrons of other atoms or molecules which are close to it and also induces a dipole in them.

In this way a large number of nonpolar molecules become polar temporarily and they are attracted by weak attractive forces. The dispersion bonds are easy to form and break.

The dispersion force is the weak attractive force and has the smallest energy per bond.

Thus the correct option is D - Dispersion bonds.

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The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: In the analysis of a 1.54-g sample, 0.0596 g of barium iodate was recovered. Express the results of this analysis as percent potassium iodide.

Answers

Answer: The percentage of potassium iodide in the sample is 2.63 %.

Explanation:

The chemical equation for the reaction of iodide ions with bromine gas follows:

[tex]I^-+3Br_2+3H_2O\rightarrow 6Br^-+IO_3^-+6H^+[/tex]                (i)

The chemical equation for the reaction of iodate ions with barium ions follows:

[tex]Ba^{2+}+2IO_3^-\rightarrow Ba(IO_3)_2[/tex]                 ......(ii)

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of barium iodate = 0.0596 g

Molar mass of barium iodate = 487.13 g/mol

Using equation 1:

[tex]\text{Moles of barium iodate}=\frac{0.0596 g}{487.13 g/mol}\\\\\text{Moles of barium iodate}=1.22\times 10^{-4} moles[/tex]

By Stoichiometry of the reaction (ii):

1 mole of barium iodate is produced by 2 moles of iodate ions

So, [tex]1.22\times 10^{-4} moles[/tex] of barium iodate will be produced by [tex]\frac{2}{1}\times 1.22\times 10^{-4} =2.44\times 10^{-4}moles[/tex] of iodate ions

By the stoichiometry of the reaction (i):

1 mole of iodate ions are produced by 1 moles of iodine ions

So, [tex]2.44\times 10^{-4} moles[/tex] of iodate ions will be produced by [tex]\frac{1}{1}\times 2.44\times 10^{-4} =2.44\times 10^{-4}moles[/tex] of iodine ions

Moles of potassium iodide = Moles of iodide ions = [tex]2.44\times 10^{-4}[/tex]

Since, the molar mass of potassium iodide = 166 g/mol

Using equation 1:

[tex]\text{Mass of potassium iodide}=2.44\times 10^{-4}mol\times 166 g/mol\\\\\text{Mass of potassium iodide}=0.0405 g[/tex]

To calculate the percentage by mass of a substance, the equation used is:

[tex]\text{Percent by mass}=\frac{\text{Mass of a substance}}{\text{Mass of solution}}\times 100[/tex]

Mass of a solution = 1.54 g

Mass of potassium iodide = 0.0405 g

Using above equation:

[tex]\text{Percent potassium iodide}=\frac{0.0405 g}{1.54g}\times 100\\\\\text{Percent potassium iodide}=2.63\%[/tex]

Hence, the percentage of potassium iodide in the sample is 2.63 %.

Expressing the results of potassium iodide in percentage = 2.63%

The chemical reaction of iodine ions with Bromine gas can be expressed as :

I⁻  + 3Br₂  + 3H₂O  -- > 6Br⁻ + IO₃ + 6H⁺ ----- ( 1 )

Chemical reaction between iodate ions with barium ions  can be expressed as :  Ba²⁺  + 2IO⁻₃ ------> Ba ( IO₃ )₂   --------- ( 2 )

Step 1 : Calculate the number of Barium iodate moles

mass of Barium iodate = 0.0596 g

molar mass of Barium iodate = 487.13 g/mol

from equation ( 1 )

moles of Barium iodate = ( 0.0596 ) / ( 487.13 ) = 1.22 * 10⁻⁴ moles

also from equation ( 1 ) the moles of potassium iodide = moles of iodide ions

= 2.44 * 10⁻⁴

molar mass of potassium iodide = 166 g/mol

Next step : Determine the mass of potassium iodide

moles of potassium * molar mass

= 2.44 * 10⁻⁴  * 166 g/mol  = 0.0405 g

Final step : Determine the percentage of potassium iodide in the solution

Percentage = ( mass of potassium iodide / mass of solution ) * 100

                   = ( 0.0405 / 1.54 ) * 100

                   = 2.63%

Hence we can conclude that potassium iodide in percentage = 2.63%

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A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
mass.
Question 1: The empirical formula for this compound is :

Question 2: The molar mass for this compound is 82.98 g/mol.
The Molecular formula for this compound is:

Answers

Answer: 1. The empirical formula is [tex]PNF_2[/tex]  

2. The molecular formula is [tex]PNF_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =[tex]\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles[/tex]

Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles[/tex]

Moles of F =[tex]\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = [tex]\frac{1.20}{1.20}=1[/tex]

For N = [tex]\frac{1.20}{1.20}=1[/tex]

For F =[tex]\frac{2.41}{1.20}=2[/tex]

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is [tex]PNF_2[/tex]

The empirical weight of [tex]PNF_2[/tex]= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1[/tex]

The molecular formula will be=[tex]1\times PNF_2=PNF_2[/tex]

Which one is it for a brialiest

Answers

I’m confused about the question

A 0.10M NH3 solution is 1.3% ionized, calculate the hydrogen ion concentration

Answers

Answer:NH3 + H2O <==> NH4+ + OH-

0.10 x 0.013 = 0.0013 M (this is the hydroxide concentration)

Kw = [H+] [H-]

1.00 x 10^-14 = (x) (0.0013)

x = 7.7 x 10^-12 M

Explanation:

What is the source of Earth's magnetic field according to what you have read in chapter 222

Answers

Answer:

Scientists know that today the Earth's magnetic field is powered by the solidification of the planet's liquid iron core. The cooling and crystallization of the core stirs up the surrounding liquid iron, creating powerful electric currents that generate a magnetic field stretching far out into space.


PLEASE HELP!!!!!!!

Answers

Answer:

2nd option

Explanation:

When NH3(g) reacts with O2(g) to form N2O(g) and H2O(l), 342 kJ of energy are evolved for each mole of NH3(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.

Answers

Answer: [tex]2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ[/tex]

Explanation:

The skeletal thermochemical equation for the reaction is:

[tex]NH_3(g)+O_2(g)\rightarrow N_2O(g)+H_2O(l)+342kJ[/tex]

The balanced  thermochemical equation for the reaction is:

[tex]2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ[/tex]

When 1 mole of [tex]NH_3[/tex] reacts with oxygen , heat released = 342 kJ

Thus when 2 moles of [tex]NH_3[/tex] reacts with oxygen , heat released = [tex]\frac{2}{1}\times 342 kJ=684kJ[/tex]

When 0.20 mol of hydrogen gas and 0.15 mol of iodine gas are heated at 450 °C until equilibrium is established, the equilibrium mixture is found to contain 0.26 mol of hydrogen iodide. The equation for the reaction is as follows
H2((g) + I2(g) ⇋ 2HI(g)
What is the correct expression for the equilibrium constant, Kc?

Answers

Answer:

[tex]Kc=\frac{[HI]^2}{[I_2][H_2]}[/tex]

Explanation:

Hello there!

In this case, for these equilibrium problems it is firstly necessary to know the balanced reaction at equilibrium:

H2((g) + I2(g) ⇋ 2HI(g)

Next, by means of the law of mass action, it turns out possible for us to write the required and correct expression for the equilibrium constant by considering the concentrations and the coefficients in the aforementioned reaction:

[tex]Kc=\frac{[HI]^2}{[I_2][H_2]}[/tex]

Best regards!

Argon occupies a volume of 28.3 L at a pressure of 0.36 atm. Find the volume of argon when the pressure is increased to 0.85 atm.

Answers

Answer:

12

Explanation:

Boyles law

P1 (.36)

V1(28.3)

P2(.85)

V2(?)

P1*V1=P2*V2

plug it in, and you get 12

Convert 0.0338 moles of K3PO4 to grams.

Answers

0.0338 K3PO4 212.27 g K3PO4
——————— x ————————-= 7.17g K3PO4
1 1 mol K3PO4

0.0338x 212.27= 7.174726

Answer : 7.17 g K3PO4
7.17 hope this helps bestie

is sublimation a chemical change or chemical property or physical change?

Answers

Answer:

Physical Change

Explanation:

Sublimation is a physical change. When a substance sublimes, it changes from a solid to a gas without going through the liquid phase.

What would you call the bright blue liquid?​

Answers

Answer: Also known as ‘blue nitro’. (Hope it’s right!)

32.14 mL of a 0.05 M sulfuric acid (H2SO4) solution are required to neutralise 25 mL of a sodium hydroxide (NaOH) solution.
What is the concentration (in mol L-1) of SO42- ions in the final solution?

Answers

The concentration of SO42- ions in the final solution is 0.01 mol L-1.

The neutralisation reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) requires the use of a chemical equation that is balanced:

H2SO4 + NaOH = Na2SO4 + 2H2O

We may deduce from the balanced equation that one mole of H2SO4 reacts with one mole of Na2SO4, meaning that the amount of SO42- ions produced is equal to the amount of H2SO4 utilised.

We may determine how many moles of H2SO4 were used by calculating the amount of 0.05 M H2SO4 solution needed to neutralise 25 mL of NaOH solution:

H2SO4 moles are equal to the product of the volume of H2SO4 (in L) and the concentration of H2SO4 (in mol L-1): 0.03214 L 0.05 mol L-1 = 0.001607 mol

The formation of SO42- ions results in the same amount of moles as the
The resulting solution contains the following amounts of SO42- ions per mole of H2SO4 used:

Moles of SO42- ions/volume of solution (in L) = 0.001607 mol/(0.025 L + 0.03214 L) = 0.01 mol L-1; concentration of SO42- ions (in mol L-1)

As a result, the final solution contains 0.01 mol L-1 of SO42- ions.

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different between intermolecular and intra molecular dehydration​

Answers

Answer: Intermolecular bonds are the forces between the molecules. Intramolecular are the forces within two atoms in a molecule.

Explanation:

Atoms of which elements form bonds without satisfying the octet rule?

Answers

Answer:

Helium and hydrogen......

1. (An example of non-point-source pollution is
A. Wastewater from a leaking pipe.
B. Fertilizer runoff from lawns.
C. Oil from a leaking underground tank.
D. Chemicals released from a paper mill

Answers

Answer:

i think the answer is c.

Explanation:

Step 2: Now that you have counted the atoms on each side, add coefficients to balance the equation. Check your work by updating the number of atoms on each side in the table below (Remember to multiply coefficients by subscripts): NaF + NaBr + CaF2 CaBr2 Reactants Products Na- Na- Br- Br- Ca- Ca- IF- ​

Answers

Answer:

The answers to your questions are given below.

Explanation:

__ NaBr + CaF₂ —> __ NaF + CaBr₂

The above equation can be balance as follow:

NaBr + CaF₂ —> NaF + CaBr₂

There are 2 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 2 before NaF as shown below:

NaBr + CaF₂ —> 2NaF + CaBr₂

There are 2 atoms of Na on the right side and 1 atom on the left side. It can be balance by writing 2 before NaBr as shown below:

2NaBr + CaF₂ —> 2NaF + CaBr₂

Now, the equation is balanced.

Atom >>>> Reactant >>>> Product

Na >>>>>> 2 >>>>>>>>>>> 2

Br >>>>>>> 2 >>>>>>>>>>> 2

Ca >>>>>> 1 >>>>>>>>>>>> 1

F >>>>>>> 2 >>>>>>>>>>>> 2

A substance that contains two or more kinds of atoms is

Answers

A substance that contains two or more kinds of atoms is a molecule.

Two gas particles collide together in a sealed container. What can be said about the kinetic energy of the two gas particles?
a)During the collision, each gas particle transfersall of its kinetic energy to the other particle.
b)The total kinetic energy of both gas particles will remain the same, but they can transfer any amount to each other.
c)The new kinetic energy of each gas particle is the sum of the kinetic energy that each particle is traveling with.
d)The kinetic energy of each gas particle remains the same as kinetic energy cannot be transferred between particles with zero volume.

Answers

Explanation:

c)The new kinetic energy of each gas particle is the sum of the kinetic energy that each particle is traveling with.

Which nitrogenous base is NOT found in DNA? *
A. cytosine
B. guanine
C. uracil
D. adenine

Answers

Answer:

c. uracil

Explanation:

uracil is not found in DNA. the missing base would be thymine

2. Some nitrogen at a pressure of 35.75 p.s.i is in a 100 L container. If the container's volume is reduced to 2250 ml then what is the resulting pressure?​

Answers

Answer:

1455.6

Explanation: you first convert 2250ml to l by dividing by 1000 so you get 2.25l then you use Boyles law which is p1v1=p2v2 then insert values

35.75*100=p2*2.25 then divide both sides by 2.25 then you get 1455.6


How many grams of Co, are produced when 88 g of o, is reacted with an excess of
butane?

Answers

Answer:

[tex]74.5gCO_2[/tex]

Explanation:

Hello there!

In this case, for the described reaction, it is possible to realize there is a 13:8 mole ratio between oxygen (O2) and carbon dioxide (CO2); moreover, since the molar mass of the former is 32.00 g/mol and that of latter is 44.01 g/mol, the produced mass of the required product turns out to be:

[tex]88gO_2*\frac{1molO_2}{32.00gO_2}*\frac{8molCO_2}{13molO_2}*\frac{44.01gCO_2}{1molCO_2} \\\\=74.5gCO_2[/tex]

Best regards!

As mentioned in the kinetic molecular theory, what is the main reason that the volume of gas particles can be considered zero?
a)The bonds present in gas particles are stronger than other bonds, pulling atoms in closer to each other, causing a shorter bond length which greatly decreases the volume.
b)When atoms enter the gas phase, they are less affected by gravity, which lowers their mass and in turn, their volume.
c)The real volume of the gas particles is extremely small when compared to the entire volume of their container.
d)Gas particles constantly expand and contract, which constantly alters their volume. When these volumes are averaged, a value of zero is obtained.

Answers

Answer:

The real volume of the gas particles is extremely small when compared to the entire volume of their container.

d)Gas particles constantly expand and contract, which constantly alters their volume. When these volumes are averaged, a value of zero is obtained

Explanation:

Nitric oxide (NO) reacts with oxygen gas to produce nitrogen dioxide. A gaseous mixture contains 0.66 g of nitric oxide and 0.58 g of oxygen gas. After the reaction is complete, what mass of nitrogen dioxide is formed? Which reactant is in excess? How do you know? Suppose you actually recovered 0.91 g of nitrogen dioxide. What is your percent yield?

Answers

Answer:

NO is the limiting reagent.  

In this reaction 0.886 mole of NO2 is produced

Explanation:

The chemical equation for this reaction is  

2NO(g) + O2(g) → 2NO2(g)

In this limiting reagent reaction, 2 moles of NO reacts with one mole of O2  to produce 2 mole of 2NO2

0.886 mole of NO * (2 mole of NO2/2 mole of NO) = 0.886 mole of NO2

0.503 mole of O2 * (1 mole of NO2/1 mole of O2) = 1.01 mole of NO2

Hence, NO is the limiting reagent.  

In this reaction 0.886 mole of NO2 is produced

PLEASE HURRY! What is the name of this alkane?


A skeletal model has a hexagon ring with points at the top and bottom. C H 3 is bonded to the top point, and a carbon and another C H 3 are bonded to the bottom right point.

1-methyl,3-ethylnonane
1-methyl,5-ethylisohexane
1-ethyl,3-methylcyclohexane
1-ethyl,5-methylcyclohexane

Answers

Answer:

C. 1-ethyl, 3-methylcyclohexane

(Photo for proof at the bottom.)

Explanation:

The 1-ethyl is because you start numbering from the longest branch, towards the next closest branch. Prefix "eth-" means two, there are 2 carbons in the longest branch. 3-methyl is because the next branch is at number 3, and prefix "meth-" means 1, there is 1 carbon in that chain. "Cyclo" in cyclohexane means the skeletal model is shaped like a ring, and the "hexane" means there are 6 carbons in the ring. Prefix "hex" means 6.

Here's a photo of the unit review on Edge. Refer to the 2nd attachment for a visualization.

Please click the heart if this helped.

Answer:

C. 1-ethyl,3-methylcyclohexane

Explanation:

What keeps the Earth orbiting on its current path
in our solar system?

Answers

gravity is the correct answer
Gravitational pull I think

1. What volume of a 2.50M Kl(aq) is needed to make 200 ml of a 1.OOM KI)aq)?

Answers

Answer:

80 ml

Explanation:

From the question,

Applying Dilution formular

MV = mv................... Equation 1

Where M = Molarity of Kl before dilution, V = Volume of Kl before dilution, m = molarity of Kl after dilution, v = volume of Kl after dilution.

make V the subject of the equation

V = mv/M............. Equation 2

Given: m = 1.00 M, v = 200 ml, M = 2.50 M

Substitute these values into equation 2

V = (1.00×200)/2.50

V = 80 ml

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If the appropriate discount rate is 11.37% what is the value of the preferred stock?b: The market price of a share of preferred stock is $20.57 and the dividend is $2.22. What discount rate did the market use to value the stock?c: The market price of a share of preferred stock is $44.20. The market uses a discount rate of 4.94%. What is the dividend?d: Caspian Sea is considering raising $26.00 million by issuing preferred stock. They believe the market will use a discount rate of 9.42% to value the preferred stock which will pay a dividend of $3.44. How many shares will they need to issue? for the circle with equation (x-2)2 (y 3)2 = 9, what is the diameter? TB Problem Qu. 8-229 (Algo) Sthilaire Corporation is working on... Sthilaire Corporation is working on its direct labor budget for the next two months. Each unit of output requires 0.29 direct labor-hours. The direct labor rate is $9 per direct labor-hour. The production budget calls for producing 8,900 units in April and 8,800 units in May. The direct labor workforce is fully adjusted each month to the required workload. Required: Prepare the direct labor budget for the April and May. (Round "labor-hours per unit" answers to 2 decimal places.) April May Required production in units Direct labor-hours per unit Total direct labor-hours needed Direct labor cost per hour Total direct labor cost The demand curve is P = 400 20Qp. The supply curve is P = 150 + 10QS. At market equilibrium, the equilibrium quantity is A. 0.12 B. 10 C. 233.33 D. 8.3 find the metropolitan statistical area population for every MSAthat has a baseball team. Then find the average wins over the pastten years for each team. The regression you need to run usesAverage Which compound would be expected to show intense IR absorption at 1715 cm -1?a. 1-hexeneb. 2-methylhexanec. CH3CH2CO2Hd. CH3CH2CH2NH2 Solve the boundary value problem Au = 0, 0 < x < R, 0 < a < 27, u(R, 6) = 4+3 sin 0, 0 "Required information [The following information applies to the questions displayed below.] On December 31, Hawkin's records show the following accounts. Cash $ 7,500 Accounts Receivable. 700 Supplies 4,500 Equipment 14,300 Accounts Payable 7,200 Common stock 11,500 Retained earnings, December 1 5, 200 Dividends 1,500 Services Revenue 17, 200 Wages Expense 8,000 Rent Expense 2,700 Utilities Expense 1,900 Use the above information to prepare a statement of retained earnings income is $4,600. " The following problem can illustrate the economics of insulating the floor above a vented crawl space. (a) If the composite structure of the floor is made up of carpet (with an R-value of a ft?-hrF/Btu), subfloor (R = 1.0), and air space between the joists (R=0.8), then find the total R-value. (b) If 6" of fiberglass (R = 19) is added between the joists, then find the percentage reduction in heat loss. (e) If there are 6500 degree-days in this area, and the price of fuel is $10 per million Btu, then find the heating cost per square foot per heating season for the un-insulated floor. (d) If 6-in.fiberglass costs $0.40 per square foot, what will be the payback time (as a result of energy savings) on this installation? Which ancient greek words was used to refer to both military battles and to athletic contests?