18. A 35.0 G piece of metal wire is heated and the temperature changes from 21°C to 52°C the specific heat of the metal is 0.900 J/G degrees Celsius how much energy was required to heat the metal please show work
Answer:
[tex]\boxed {\boxed {\sf 976.5 \ Joules}}[/tex]
Explanation:
We are asked to find the heat energy. Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:
[tex]q=mc\Delta T[/tex]
Where m is the mass, c is the specific heat, and ΔT is the change in temperature.
We know this is a 35.0 gram piece of wire, the temperature changes from 21 °C to 52°C and the specific heat is 0.900 J/ g °C.
Therefore,
m= 35.0 gc= 0.900 J/g °CΔT= 52 °C - 21°C= 31°CSubstitute these values into the formula.
[tex]q= (35.0 \ g)(0.900 \ J/g \ \textdegree C)(31 \textdegree C)[/tex]
Multiply the first two values. The grams will cancel each other out.
[tex]q=31.5 \ J/ \textdegree C (31 \textdegree C)[/tex]
Multiply again. This time, the degrees Celsius cancel each other out, so the final units are Joules.
[tex]q=976.5 \ J[/tex]
976.5 Joules of energy were required to heat the piece of metal.
What type of reaction is this? FeSO4 + Al(OH)3 → Al2(SO4)3 + Fe(OH)2
How is dry ice different from ordinary ice?
Answer: Well "ordinary ice" is made from water (as we all know) and dried ice is made from carbon dioxide gas
Explanation:
•Hope this helps•
what is the electrolysis of water
Write balanced equations for all the reactions in the catabolism of glucose to two molecules of glyceraldehyde 3-phosphate (the preparatory phase of glycolysis), including the standard free-energy change for each reaction. Then write the overall or net equation for the preparatory phase of glycolysis, with the net standard free-energy change.
Solution :
The balanced chemical equation are
The Catabolism of the glucose takes place in five stages :
1. Glucose + [tex]$ATP$[/tex] → glucose - [tex]$6$[/tex] - phosphate [tex]$+ ADP$[/tex] , [tex]$\Delta G^0=-16.7 \ kJ/mol$[/tex]
2. Glucose - [tex]$6$[/tex] - phosphate → Fructose - [tex]$6$[/tex] - phosphate , [tex]$\Delta G^0=1.7 \ kJ/mol$[/tex]
3. Glucose - [tex]$6$[/tex] - phosphate + [tex]$ATP$[/tex] → [tex]$ADP$[/tex] + Fructose - [tex]$1,6- \text{biophosphate}$[/tex], [tex]$\Delta G^0=-14.2 \ kJ/mol$[/tex]
4. Fructose - [tex]$1,6- \text{biophosphate}$[/tex] → dihydroxyacetonephosphate + glyceraldehyde [tex]$-3 - $[/tex] phosphate, [tex]$\Delta G^0=23.8 \ kJ/mol$[/tex]
5. Dihydroxyacetonephosphate → glyceraldehyde [tex]$-3 - $[/tex] phosphate , [tex]$\Delta G^0=7.5 \ kJ/mol$[/tex]
Therefore, the overall net equations
Glucose + [tex]$2ATP \rightarrow$[/tex] glyceraldehyde [tex]$-3 - $[/tex] phosphate + [tex]$2ADP$[/tex] [tex]$\Delta G^0=2.1 \ kJ/mol$[/tex]
Try moving an electron from the metal to the non metal.What happens?
Answer:
Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.
Explanation:
What is the molecular geometry, or shape, of the molecule shown in the image?
A. bent
B. tetrahedral
C. trigonal planar
D. linear
Answer:
The correct answer to this is C. Trigonal Planner
Explanation:
I got it right..
Last time I'm asking this, answer, this time, 50 points.
Think about a single cell and its parts; for example, think about a cell inside the human body. Now, select an everyday object that could be used as a model for a cell and its parts. In words and/or pictures, describe your model and how it is like the cell.
Explanation:
Well i mean clothes so cells make tissues which help organs clothes can technically help you if you fall it has layers so it woulf be as a cell?
In alpha decay, the parent nucleus loses an alpha particle, which is two protons and two neutrons.
a. True
b. False
Answer:
True
Explanation:
In an alpha decay, the isotope of an element releases two protons and two neutrons. An alpha particle or helium has two protons and two neutrons and hence, in an alpha decay an alpha particle is released.
Hence, the given statement is true
How many grams are present in 3.4
moles of CH2COOH?
Show all work
Answer:
m = 200.6 gr
Explanation:
CH2COOH : n = 3.4 mol
Mr = 12 + 2 + 12 + 2×16 + 1 = 59
n= m / Mr => m = n× Mr => m = 3.4×59 => m = 200.6 gr
1. Find the molarity of 25g of sodium hydroxide dissolved in 1L of water. Identify the solute and solvent in this solution.
please help me
Answer:
.6250 M
The Sodium Hydroxide is the solute, and the water is the solvent.
Explanation:
mol/volume= Molarity
(25/22.99+16+1.008)/1=.6250 M.
Which is a reason to use rate laws?
A. to investigate how the pressure of liquids affects reaction rates
B. to find the new rate when the concentration of reactants changes
C. to calculate the molecular weight of compounds in a reaction
D. to find the number of moles of solute that are dissolved in 1 L of solution
Answer:
B
Explanation:
to find the new rate when the concentration of reactants changes
Use the periodic table below to answer the following questions.
What group of elements are contained in the p-block?
a.
1A
c.
3A
b.
2A
d.
3B
Answer:
answer is D
Explanation:
3B
which of the following is an example of a chemical change?
cutting a log 2.
dissolving sugar
baking a cake
boiling water
Answer: Baking a Cake
Answer:
Baking a cake
Explanation:
Ape-x aprroved
PLEASE HURRY IM TIMED I WILL GIVE BRAINYEST
What is another name for the sunlit zone of the ocean?
A twilight zone
B abyssal zone
C photic zone
D benthic zone
Answer:
The answer is the C. Photic zone.
Explanation:
I wish you good luck! :>
Answer: C photic zone
Explanation:
A student is observing an image of an object that could be a comet, meteoroid or asteroid. Which of the following questions would BEST confirm that the object is a meteoroid?
A.
Was the object once part of an asteroid?
B.
Where is the object located?
C.
Does the object orbit the sun?
D.
Is the object made of rock?
Answer:
A. was the object once part of and asteroid
Explanation:
A is correct because at first asteroid's pieces fall off and burn up to enter the atmosphere and meteoroid's are small while asteroid's are big and rocky
D. Is the object made of rock? The question "Is the object made of rock?" would best confirm that the object is a meteoroid.
What are Meteoroids?Meteoroids are small rocky or metallic objects that are in space and can potentially enter the Earth's atmosphere. By determining if the object is made of rock, it aligns with the characteristics of a meteoroid.
Option A, "Was the object once part of an asteroid?" does not necessarily confirm that the object is a meteoroid since meteoroids can come from various sources, not just asteroids.
Option B, "Where is the object located?" does not provide specific information about the nature of the object and can apply to comets and asteroids as well.
Option C, "Does the object orbit the sun?" is a characteristic shared by comets, asteroids, and meteoroids. It does not specifically confirm that the object is a meteoroid.
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In the laboratory, a general chemistry student measured the pH of a 0.341 M aqueous solution of benzoic acid, C6H5COOH to be 2.351. Use the information she obtained to determine the Ka for this acid.
Answer: [tex]K_a[/tex] for the acid is [tex]5.75\times 10^{-5} [/tex]
Explanation:
[tex]C_6H_5COOH\rightarrow H^+C_6H_5COO^-[/tex]
cM 0 0
[tex]c-c\alpha[/tex] [tex]c\alpha[/tex]
So dissociation constant will be:
[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]
Give c= 0.341 M and = 2.351
[tex]K_a=?[/tex]
[tex]pH=-log[H^+][/tex]
[tex][H^+]=10^{-2.351}=0.0044[/tex]
[tex][H^]=c\alpha=0.0044[/tex]
[tex]K_a=\frac{(0.0044)^{2}}{0.341-0.0044}[/tex]
[tex]K_a=5.75\times 10^{-5} [/tex]
Thus [tex]K_a[/tex] for the acid is [tex]5.75\times 10^{-5} [/tex]
According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s - Al2S3
Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} S=\frac{100g}{32g/mol}=3.125moles[/tex]
The balanced chemical equation is:
[tex]2Al+3S\rightarrow Al_2S_3[/tex]
According to stoichiometry :
3 moles of [tex]S[/tex] require = 2 moles of [tex]Al[/tex]
Thus 3.125 moles of [tex]S[/tex] will require=[tex]\frac{2}{3}\times 3.125=2.08moles[/tex] of [tex]Al[/tex]
Mass of [tex]Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g[/tex]
Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.
Did entropy increase or decrease?
1) 2 SO3 (g) → 2 SO2 (g)+O2 (g)
2) MgCO3 (s) + 2 H3O^+ (aq) → Mg^2+ (aq) + 3 H2 O(I) + CO2 (g)
Answer:
1) increase
2) increase
Explanation:
Entropy is the degree of disorderliness or randomness of a system. It is the measure of the unavailable energy in a system.
Entropy increases with increase in the number of particles. If the number of particles in a system increases from left to right, the entropy of the system increases accordingly.
In reaction 1, the number of particles from left to right increased from two to three hence the entropy was increased.
In reaction 2, the number of particles from left to right increased from three to five hence the entropy was increased.
Chrysanthemic acid occurs as a mixture of esters in flowers of the chrysanthemum (pyrethrum) family.
a. True
b. False
Answer:
A: True
Explanation:
Statement is true because chrysanthemic acid is formed naturally as a result of production of two molecules of dimethylallyl diphosphate which forms pyrophosphate ester.
Thus, it belongs to the pyrethrum family
Coal, oil, and natural gas are called _______.
A.
fossil fuels
B.
renewable resources
C.
nuclear power
D.
solar energy
Answer:
I think it's A. I'm pretty sure.
Explanation:
Answer:
Coal, oil and natural gas are called _________A. fossil fuels
36. Write a balanced chemical equation for each chemical reaction. (a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide. (b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. (c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas. (d) Liquid benzene (C6H6) reacts with gaseous oxygen to form carbon dioxide and liquid water.
Answer:
a) 2Cu(s) + S(s) → Cu₂S(s)
b) 2SO₂(g) + O₂(g) → 2SO₃(g)
c) 4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)
Explanation:
First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.
a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.
Reactants: solid copper (Cu(s)) and solid sulfur (S(s)). Product: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.
The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:
2Cu(s) + S(s) → Cu₂S(s)
(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.
Reactants: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). Products: sulfur trioxide gas (SO₃(s)).
The balanced equation is:
2SO₂(g) + O₂(g) → 2SO₃(g)
We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.
(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.
Reactants: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). Products: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).
The balanced chemical equation is:
4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.
Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).
The balanced chemical equation is:
C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)
In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).
A sample of aluminum foil contains 9.20 x 1023 atoms. What is the mass of the foil?
A sample of aluminum foil contains 9.20 x 1023 atoms, then mass of foil will be 41.24 gram.
Aluminum foil serves as a barrier to air and oxygen, which could heat up food that is cold or frozen. In the end, it is beneficial since it keeps the food's temperature, irrespective of whether it's warm or cold.
Iron and silicon make up the majority of the remaining 2.5% of aluminum foil, which gives it strength as well as puncture resistance. Between big, water-cooled chilling rollers, the molten alloy has been rolled thin as well as solidified. Two layers of foil were run through the mill simultaneously even during final rolling.
It is known that 1 mol = 6.022 × [tex]10^{23}[/tex]
and, 1 mol of aluminum = 27 g.
It is given that, count of Al atoms = 9.20 × [tex]10^{23}[/tex]
So, 9.20 × [tex]10^{23}[/tex] particle has mass = 27 / 6.022 × [tex]10^{23}[/tex] × 9.20 × [tex]10^{23}[/tex]
Which will be equal to 41.24gram.
Therefore, the mass of foil will be 41.24 gram.
To know more about mass
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How many moles of argon gas would be present in a 37.0 liter vessel at 45.00 °C at a pressure of 2.50 atm?
Answer:
3.54 mol
Explanation:
Step 1: Given data
Volume (V): 37.0 LTemperature (T): 45.00 °CPressure (P): 2.50 atmStep 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 45.00°C + 273.15 = 318.15 K
Step 3: Calculate the number of moles (n) of argon gas
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol
witch are the two factors decrease as the kinetic energy of the particles in an object decreases
Answer:
mass and speed are the two factor
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What kind of weather forms with an occluded front?
Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.
Explanation:
What is the formal charge on the phosphorus in the PO43- polyatomic ion?
Answer:
P has a formal charge of 0
Explanation:
Essentially P is in the middle of that ion, and its valence electrons are being used with the 4 Os. Hope that makes sense or helps at least. There's good videos that talk about how this works but I can't link them in brainly
When i make an account for different college can I use the same email username for each one or do I have make a different username email
Answer:
No you have to use a new email unless you delete the other accaount
Explanation:
hope that helps
Does pb(no3)2 + Na3(PO4) = Pb3(PO4)2 + Na(NO3) have a precipitate?
Answer:
Yes, Pb3(PO4)2.
Explanation:
Hello there!
In this case, according to the given balanced chemical reaction, it is possible to use the attached solubility series, it is possible to see that NaNO3 is soluble for the Na^+ and NO3^- ions intercept but insoluble for the Pb^3+ and PO4^2- when intercepting these two. In such a way, we infer that such reaction forms a precipitate of Pb3(PO4)2, lead (II) phosphate.
Regards!
Which ecosystem is the least stable?
A. A rain forest
B. A cornfield
C. A savanna
D. A coral reef