Complete the square
to find the vertex
of this parabola.

y^2+4x - 2y+21=0

Complete The Squareto Find The Vertexof This Parabola.y^2+4x - 2y+21=0

Answers

Answer 1

Answer:

::::::::::::::::::::

(-5,1)

Answer 2

The vertex of the parabola represented by the equation y² + 4x - 2y + 21 = 0 is (-5, 1).

The parabola is represented by the equation y² + 4x - 2y + 21 = 0.

Take the coefficient of y, which is -2, divide it by 2, and square the result:

(-2/2)² = 1

Now, we add and subtract this value inside the parentheses to maintain the equation's balance:

y² - 2y + 1 + 4x + 21 - 1 = 0

Rearranging the terms, we have:

(y² - 2y + 1) + 4x + 20 = 0

Now, the terms inside the parentheses can be written as a perfect square:

(y - 1)² + 4x + 20 = 0

Setting (y - 1)² = 0,

(y - 1)² = 0

y - 1 = 0

y = 1

Substitute y = 1 back into the equation to find the x-coordinate of the vertex:

(1 - 1)² + 4x + 20 = 0

0 + 4x + 20 = 0

4x = -20

x = -5

Therefore, the vertex of the parabola is (-5, 1).

Learn more about the parabola here:

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Complete The Squareto Find The Vertexof This Parabola.y^2+4x - 2y+21=0

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Step-by-step explanation:

Given

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Required

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