Complete the passage.

Sound waves and some earthquake waves are
waves. Ocean, light, and other earthquake waves are
waves.

Explanation:

mass=50g

velocity=42cm/s

Kinetic energy

As we know that

[tex]{\boxed{\sf kinetic\:energy={\dfrac {1}{2}}mv^2}}[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf k.v={\dfrac {1}{{\cancel{2}}}}\times 50\times {\cancel{42}}^2 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf k.v=50\times 21^2 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf k.v=50×441 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf k.v=22050MJ [/tex]

[tex]\therefore[/tex][tex]{\underline{\boxed{\bf Kinetic\:energy=22Joule}}}[/tex]

Answer:

The Moon rotating around Earth and the Earth rotating around the Sun

Explanation:

Answer:

the rotation of Earth on its axis

Explanation:

Did it on study island

Answer: The acceleration due to gravity is the constant pull towards the core of the earth due to gravity on earth. It is abbreviated by the letter g and is equal to -9.81 m/s².

Explanation:

Answer:

F = 5.9 N

Explanation:

Given that,

Mass of water, m₁ = 1000 kg

Mass of the Sun, [tex]m_2=1.99\times 10^{30}\ kg[/tex]

Distance between two bodies, [tex]r=1.5\times 10^{11}\ m[/tex]

We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N[/tex]

or

F = 5.9 N

Hence, the correct option is (b).

Answer: 40 N

Explanation: Use the formula

F = m a

to solve this.

F = (8 kg) (5 m/s²)

F = 40 kgm/s²

F = 40 N

The given value are:

Acceleration,

Mass,

The force will be:

→ [tex]Force (F) = Mass(m)\times Acceleration (a)[/tex]

By substituting the values, we get

                   [tex]= 5\times 8[/tex]

                   [tex]= 40 \ N[/tex]

Thus the response above is right.

Learn more about force here:

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Answer:

The kinetic coefficient of friction of the sled on the snow is 0.05

Explanation:

The given parameters are;

The weight of the sled Jill is pulling, W = 200 N

The force with which Jill is pulling the the sled = 10 Newtons

The nature of the speed with which the sled is pulled = Constant speed

Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;

The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction, [tex]F_k[/tex]

The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow, [tex]\mu _k[/tex]

[tex]F_k[/tex] = W × [tex]\mu _k[/tex]

[tex]\mu _k[/tex] = [tex]F_k[/tex]/W = 10 N/(200 N) = 0.05

The kinetic coefficient of friction of the sled on the snow = [tex]\mu _k[/tex] = 0.05.

Answer:

The potential difference between the plates of the capacitor is 300V

Explanation:

Given;

capacitance of the capacitor, C = 5μF = 5 x 10⁻⁶ F

charge of the capacitor, Q = 1500μC = 1500 x 10⁻⁶ C

The potential difference between the plates of the capacitor is given by;

V = Q / C

Where;

V is the  potential difference between the plates

Q is the charge of the capacitor

C is the capacitance

[tex]V = \frac{Q}{C} \\\\V = \frac{1500*10^{-6}}{5*10^{-6}} \\\\V = 300 \ volts[/tex]

Therefore, the potential difference between the plates of the capacitor is 300V

Answer:

acceleration will be twice as much

Answer:

Explanation:

(b) The initial velocity is added to that due to acceleration by gravity. The velocity is increased linearly by gravity at the rate of 9.8 m/s². The average velocity of the pebble will be its velocity halfway through the 2-second time period.* That is, it will be ...

  4 m/s + (9.8 m/s²)(2 s)/2 = 13.8 m/s . . . . average velocity

__

(a) The distance covered in 2 seconds at an average velocity of 13.8 m/s is ...

  d = vt

  d = (13.8 m/s)(2 s) = 27.6 m

The water is about 27.6 m below ground.

_____

* We have chosen to make use of the fact that the velocity curve is linear, so the average velocity is half the sum of initial and final velocities:

  vAvg = (vInit + vFinal)/2 = (vInit + (vInit +at))/2 = vInit +at/2

__

If you work this in a straightforward way, you would find distance as the integral of velocity, then find average velocity from the distance and time.

  [tex]\displaystyle d=\int_0^t{(v_0+at)}\,dt=v_0t+\dfrac{1}{2}at^2=t\left(v_0+a\dfrac{t}{2}\right)\\\\v_{avg}=\dfrac{d}{t}=v_0+a\dfrac{t}{2}\qquad\text{the formula we started with}[/tex]

Answer:

B) He can demonstrate that water can be boiled on a simple kitchen stove.

Explanation:

Took the test edge2020 :)

He can demonstrate that water can be boiled on a simple kitchen stove.

The following information should be considered;

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Answer:mass

Explanation:

Answer:first of all what is your question and i can give and example which is Use them when you have 2 forces named Fa & FF or Fg & Ff acting in opposite directions on an object and you need to know the resultant of your 2 forces.

Explanation:

i searched it up

Answer: it is turned into thermal energy

C. it is transformed into thermal energy

Explanation:

A compass needle acts as a Magnet

Answer:

Hi. U should do like this

Answer:

3.335641 nanoseconds for meters

Answer:

0.323232....m/s2

Explanation:

acceleration=V/t

32m/s/99s=0.3232m/s2

Answer:it’s the graph starts on the origin but is going down

Explanation: khan academy

Answer:

producer

Explanation:

grass is producing

by photosynthesis

Explanation:

force(f)=250N

acceleration(a)=5m/sec²

mass(m)=?

now,

f=m.a

f=m

a

m=250

5

m=50kg

i hope so,

Answer:

The force must increase

Explanation:

According to newton's second law "force is the product of mass and acceleration".

      Force  = mass  x acceleration

Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.

There must be an increase in the force in order to make both automobiles attain the same speed.

Answer:

(a) 3.06 s

(b) 45.92 m

(c) 6.12 s

(ch) 1.43 s

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

[tex]\displaystyle h_m=\frac{v_o^2}{2g}[/tex]

Similarly, the time it needs to reach the maximum height is:

[tex]\displaystyle t_m=\frac{v_o}{g}[/tex]

The object's speed (vf) after time t is:

[tex]v_f=v_o-g.t[/tex]

The baseball is thrown up at vo=30 m/s.

(a) It's required to calculate the time it needs to reach the maximum height:

[tex]\displaystyle t_m=\frac{30}{9.8}=3.06[/tex]

[tex]t_m=3.06~s[/tex]

(b) The maximum height is:

[tex]\displaystyle h_m=\frac{30^2}{2(9.8)}=45.92[/tex]

[tex]h_m=45.92~m[/tex]

(c) The time needed to travel up is the same time required to return to the starting point:

[tex]t_f=2*t_m=2*3.06[/tex]

[tex]t_f=6.12~s[/tex]

(ch) The speed will be vf=16 m/s at a certain time. Using the equation

[tex]v_f=v_o-g.t[/tex]

We solve for t:

[tex]\displaystyle t=\frac{v_f-v_o}{g}[/tex]

[tex]\displaystyle t=\frac{30-16}{9.8}[/tex]

t = 1.43 s

Answer:

The policeperson will not be able to catch the speeder in 10 seconds

Explanation:

The maximum acceleration of the 2020 Ford police interceptor, a = 4.4 m/s²

The rate at which the speeding car is moving, v = 70 mph (31.3 m/s)

The time after which the policeperson takes off = 1 second

The time, t, at which the policeperson catches the speeding car is given as follows;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the Ford police interceptor = 0

∴ s = 0 × t + 1/2·a·t² = 1/2·a·t²

s = 1/2·a·t²

s = v × (t + 1)

Equating both equations, gives;

v × (t + 1) = 1/2·a·t²

Substituting the values, we get;

31.3 × (t + 1) = 1/2 × 4.4 × t²

31.3·t + 31.3 = 2.2·t²

2.2·t² - 31.3·t - 31.3 = 0

By the quadratic formula, we have;

t = (31.3 ± √((-31.3)² - 4×2.2×(-31.3))/(2 × 2.2)

t ≈ -0.938 seconds or t ≈ 15.165 seconds

The policeperson will catch the speeder in approximately 15.165 seconds

Therefore, the policeperson will not be able to catch the speeder in 10 seconds.

Answer:

1=false and 2=1st answer is correct

Answer:

0.13m/s

Explanation:

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