(Comparing Data MC)


The line plots represent data collected on the travel times to school from two groups of 15 students.

A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 10,16,20, and 28. There are two dots above 8 and 14. There are three dots above 18. There are four dots above 12. The graph is titled Bus 14 Travel Times.

A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 8, 9,18, 20, and 22. There are two dots above 6, 10, 12,14, and 16. The graph is titled Bus 18 Travel Times.


Compare the data and use the correct measure of variability to determine which bus is the most consistent. Explain your answer.


Bus 14, with an IQR of 6

Bus 18, with an IQR of 7

Bus 14, with a range of 6

Bus 18, with a range of 7

Answer: y+6

Step-by-step explanation:

In order to do this, we do 6 more than y. More than is going to be addition, and we get y+6 since it is 6 more than y.

Answer:

Step-by-step explanation:

100%

all 3 can be divided into 36

Answer: 100%

Step-by-step explanation:

Because we know 1,2,3 can all go into 36 (36 is able to be divided by 1,2,3) and we want the percentage of the divisor of 36. We can determine that it would be 100% Since whatever card we pick, can be divided into 36. Sorry if that made no sense, I'm not the best at explaining this.

so first off, we know the hyperbola has a horizontal traverse axis, so that means equation wise, the positive fraction is the one with the "x" variable on it, center is the origin, meaning (h,k) is just (0,0), and we know the value for the distances "a" and "c", let's find "b".

[tex]\textit{hyperbola, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} h=0\\ k=0\\ c=71000\\ a=45000 \end{cases}\implies \cfrac{(x- 0)^2}{ 45000^2}-\cfrac{(y- 0)^2}{ b^2}=1 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{c}{71000}=\sqrt{\underset{ a }{45000^2}+b^2}\implies 71000^2=45000^2+b^2 \\\\\\ 71000^2-45000^2=b^2\implies \sqrt{71000^2-45000^2}=b\implies 54918.12\approx b \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(x- 0)^2}{ 45000^2}-\cfrac{(y- 0)^2}{ 54918.12^2}=1\implies {\Large \begin{array}{llll} \cfrac{x^2}{ 45000^2}-\cfrac{y^2}{ 54918.12^2}=1 \end{array}}[/tex]

Answer:16000

Step-by-step explanation:

b

Answer:

$8.45

Step-by-step explanation:

$1.25 + $1.25 =$2.50

$3.96 + $2.50 + $2.50 = $8.95

$8.95 - $ 0.50= $8.45

So that's how I got my and.

Jalissa's mom spent $8.45 at the coffee shop.

Steps:-

Add:

First cup of coffee. $3.95

Additional refill ($1.25×2). $2.50

Bagel. $2.50

Less: Discount. ($0.50)

Total Amount spent by

Jalissa's mom. $8.45

Answer:6/35

Step-by-step explanation:

Answer:

6/35or 0.1714285714

Step-by-step explanation

Covert to same denominator of 35. This will equal 20/35-14/35 which is 6/35 or 0.1714285714

Step-by-step explanation:

There are 12 months of the year, so there are 12 possible choices for each draw. Since the first paper is replaced before the second draw, each draw can be considered as independent and with replacement.

(a) To draw April and then June, we need to draw April on the first draw (with probability 1/12), and then June on the second draw (with probability 1/12). The probability of both events happening is the product of their probabilities:

P(April and then June) = (1/12) x (1/12) = 1/144

(b) To draw a month ending in r and then a month ending in y, we can choose from the following months: April, June, July, September, and November. There are 5 months that end in r, so the probability of drawing one of them on the first draw is 5/12. After replacing the first paper, there are still 12 months left in the hat, but now we want to draw a month ending in y. There are 4 months that end in y, so the probability of drawing one of them on the second draw is 4/12. Again, the probability of both events happening is the product of their probabilities:

P(month ending in r and then month ending in y) = (5/12) x (4/12) = 5/36

(c) To draw May on the first draw and not draw May on the second draw, the probability of drawing May on the first draw is 1/12, and the probability of not drawing May on the second draw is 11/12 (since there are 11 months left in the hat after May is drawn on the first draw). Again, the probability of both events happening is the product of their probabilities:

P(May and then not drawing May) = (1/12) x (11/12) = 11/144

Therefore, the probabilities are:

(a) 1/144

(b) 5/36

(c) 11/144

Step-by-step explanation:

There are 12 months of the year, so there are 12 possible choices for each draw. Since the first paper is replaced before the second draw, each draw can be considered as independent and with replacement.

(a) To draw April and then June, we need to draw April on the first draw (with probability 1/12), and then June on the second draw (with probability 1/12). The probability of both events happening is the product of their probabilities:

P(April and then June) = (1/12) x (1/12) = 1/144

(b) To draw a month ending in r and then a month ending in y, we can choose from the following months: April, June, July, September, and November. There are 5 months that end in r, so the probability of drawing one of them on the first draw is 5/12. After replacing the first paper, there are still 12 months left in the hat, but now we want to draw a month ending in y. There are 4 months that end in y, so the probability of drawing one of them on the second draw is 4/12. Again, the probability of both events happening is the product of their probabilities:

P(month ending in r and then month ending in y) = (5/12) x (4/12) = 5/36

(c) To draw May on the first draw and not draw May on the second draw, the probability of drawing May on the first draw is 1/12, and the probability of not drawing May on the second draw is 11/12 (since there are 11 months left in the hat after May is drawn on the first draw). Again, the probability of both events happening is the product of their probabilities:

P(May and then not drawing May) = (1/12) x (11/12) = 11/144

Therefore, the probabilities are:

(a) 1/144

(b) 5/36

(c) 11/144

Answer:

31 1/4 units

Step-by-step explanation:

The equation for volume of a rectangular prism is length x width x height.

We know the length of the width and height are given as 2 1/2 u.

In this case we can simply find the height by counting the amount of blocks high it is, which in this case is 5.

Then we multiply the numbers together.

2 1/2 x 2 1/2 x 5 = 31 1/4

I think the answer is 29 cubic units.

12 on the bottom, 9 in the middle, and 8 on the top.

Part A

c = 66 per dress

Part B

$396

Okay, here are the step-by-step calculations:

Part A:

You were given the number 66. So we entered that as the cost (c) per dress in the equation.

Part B:

We were asked to find the cost of 6 dresses.

So we calculate:

Cost per dress (c) = $66

Number of dresses = 6

Total cost of 6 dresses =

$66 x 6 = $396

So the final answer for Part B is: $396

In summary:

We were given: Cost per dress (c) = $66

and asked for cost of 6 dresses

So we calculated: Cost per dress (c) = $66

Number of dresses = 6

Total cost = $66 x 6 = $396

Does this help explain the steps? Let me know if you have any other questions!

Answer:

Step-by-step explanation:

First image:

.0000625  m/s

.0003125 m

Second image:

1080

4320

Third

2240 g

Answer: First image:.0000625  m/s.0003125 mSecond image:10804320Third2240 g

Step-by-step explanation:

Answer:

1. Greater than or equal to

2. a. 4 b. 4 or anything above four

3. Greater than or equal to

4. a. -4 b. -4 or anything above -4

Step-by-step explanation:

Hope this helps

Answer:

The answer is the 4th option! (Reflection across y = -4)

Step-by-step explanation:

If you have any questions please ask me! :)

Part - A = 1/36

Part - B = 1/4

Part - C = 1/6

The numbers on the cube are, 1 , 2 , 3 , 4 , 5 and 6.

Formula to calculate probability =
Total Number of the particular number / Total Number of Numbers

The probability of rolling 1 is 1/6 as there is only one 1 in a numbered cube.

The probability of rolling 6 is 1/6 as there is only one 6 in a numbered cube.

So, the probability of rolling 1 and 6 is 1/6 * 1/6.

The probability of rolling 1 and 6 = 1/36.

The numbers on the cube are, 1 , 2 , 3 , 4 , 5 and 6.

Formula to calculate probability =
Total Number of the particular number / Total Number of Numbers

The probability of rolling an even number is 3/6 = 1/2 because there are 3 even numbers in a numbered cube.

The probability of rolling an odd number is 3/6 = 1/2 because there are 3 odd numbers in a numbered cube.

So, the probability of rolling an even and an odd number is 3/6 * 3/6 = 1/2 * 1/2.

The probability of rolling an even and an odd number = 9/36 = 1/4.

The numbers on the cube are, 1 , 2 , 3 , 4 , 5 and 6.

Formula to calculate probability =
Total Number of the particular number / Total Number of Numbers

The probability of rolling a number that is less than 3 is 2/6 = 1/3 because there are 2 numbers that are less than 3 in a numbered cube.

The probability of rolling a number that is greater than 3 is 3/6 = 1/2 because there are 3 numbers that are greater than 3 in a numbered cube.

So, the probability of rolling a number that is less than 3 and a number that is greater than 3 is 2/6 * 3/6 = 1/3 * 1/2.

The probability of rolling a number that is less than 3 and a number that is greater than 3 is 6/36 = 1/6.

Hope my answer helps you.

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Answer:

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Answer:

74%

Step-by-step explanation:

$1983.20/ $2680 ×100= 74

=74%

Answer:26%

Step-by-step explanation:

Answer:

Growth, Growth, decay, decay, growth, decay, growth, decay

Step-by-step explanation:

Answer: 1/3

Step-by-step explanation:

From the dice numbers only 1 and 2 are factors of 14

P(factor of 14)=2/6= 1/3

Answer:

A factor of 4 can only be 4 itself, which is one of the possible outcomes of rolling a 6-sided dice.

Therefore, the probability of getting a factor of 4 when rolling a 6-sided dice is:

P(getting factor of 4) = 1/6

This can be written as a fraction in the form of 1/n, where n is the total number of possible outcomes (6):

P(getting factor of 4) = 1/6

Step-by-step explanation:

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Answer: 1

Step-by-step explanation:

factors mean numbers that multiply to make other number

1, 2, 3, and 4 are all factors of 36 because thye all go in evenly os

4/4=1

Answer:

The line of reflection is x = 4, since the line x = 4 divides the original polygon and its image into congruent halves.

Step-by-step explanation:

ABCDE polygon graph with vertices at bottom 1 comma 6, 1 comma 3, negative 1 comma 1, 3 commas, 3 commas, and 1 comma. cross-axis reflection.

A polygon is a two-dimensional, closed structure that is flat or planar and has straight sides. It lacks crinkled sides. The edges of a polygon are also referred to as its sides.

Any two-dimensional form that can be made entirely of straight lines is referred to be a polygon. Polygons include forms like triangles, hexagons, pentagons, and quadrilaterals. The name of the shape has a side count indication.

To know more about polygon visit:-

https://brainly.com/question/28276384

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Answer:

C) 11.5%

Step-by-step explanation:

Answer: 1/16

Step-by-step explanation:

Answer: 1/16

Step-by-step explanation:

probability of 4

P(4)=1/4

probability of 6

P(6)=1/4

Because there is an "and" in the question and not an or you mulitiply the 2 probabilities

P(4 and 6)=(1/4)(1/4 = 1/16

Answer:

C) 25%

Step-by-step explanation:

68.75 - 51.56 = 17.19

17.19 / 68.75 = .2500 estimated

0.2500 x 100 = 25.00%

25%

Answer:

The probability that Pedro chooses a yellow ticket and then a purple ticket is A. 3/25

Answer:

The probability that Pedro chooses a yellow ticket and then a purple ticket is A. 3/25

Question 1 — Answer E

Question 2 — Answer B

Question 3 — Answer C

Question 4 — Answer D

Question 5 — Answer A

ANSWER — A regular polygon is a polygon that is equiangular and equilateral.

ANSWER — The squared from of the tiles you walk on indicate that they are polygons.

ANSWER — They teach us how to make patterns, how to use polygon is to make other shape.

ANSWER — The side must be straight.

ANSWER — Three edges of equal length and three angles between each pair of edges to be 60 degree.

Hope my answer helps you.

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