Charles, the 75 kg trampoline artist, lands on a trampoline with a speed of 9.0 m/s.
If the trampoline behaves like a spring with a spring constant of 52,000 N/m, what maximum distance will Charles push down the trampoline before bouncing back up? (Hint: at maximum compression, Charles is not moving.)

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 10 × 15

We have the final answer as

Hope this helps you

Answer:

The correct option is;

11.95

Explanation:

The given parameters are;

The height from which the rock is dropped = 700 meters

The time for the to hit the ground is given by the relation, h = u·t + 1/2·g·t²

Where;

h - The height = 700 meters

u = The initial velocity = 0

t = The time taken for the rock to cover the height, h, and hit the ground

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we have by substitution,

700 = 0 × t + 1/2 × 9.81 × t²

∴ t = √(700/(1/2 × 9.81)) ≈ 11.95

The time for the rock to hit the ground, t ≈ 11.95 seconds.

Answer:

The total mass of the solution should be 107 grams

Explanation:

Solutions

A solution is a homogeneous mixture consisting of a solute dissolved into a solvent. The solute is the substance that is being dissolved, while the solvent is the dissolving medium.

The relationship between the masses is:

[tex]m_s=m_o+m_v[/tex]

Where:

ms = mass of the solution

mo = mass of the solute

mv = mass of the solvent

If you were to mix mo=7 gr of sugar into mv=100 gr of water, then the total mass of the solution should be:

[tex]m_s=7~gr+100~gr[/tex]

[tex]m_s=107~gr[/tex]

The total mass of the solution should be 107 grams

Answer:

if your talking about the velocity after the ball falls, it would be -100m/s

Explanation:

Answer:

I do not know, but I think I would use the scientific method and use my drawing skills to paint some nice Christmas things.

Explanation:

Answer:

  ≈ 6.68 m/s

Explanation:

A suitable formula is ...

  vf^2 -vi^2 = 2ad

where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.

We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.

Then ...

  vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s

  vf ≈ 6.68 m/s

The ball hits the ground with a speed of about 6.68 meters per second.

__

We assume the launch direction is either up or down.

Explanation:

i need to know the full question

Answer:

As far as it could go

Explanation:

It rolled with it's potential energy, dropping to kinetic energy ;-;

Answer:

encyclopedia most reliable I think

[tex]\huge\boxed{Option D}[/tex]

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

Answer:

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed.

Explanation:

Hope this helps :)

Answer:

Examples of Uniform Motions.

The hr. ...

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed

Answer:its D

Explanation: but i think u meant to put not in the question but if u did mean to put not then its A

Answer:

The value is  [tex]w = 7.54 \ m[/tex]        

Explanation:

From the question we are told that

     The length of the crack is  [tex]a = 0.3 \ m[/tex]

     The  frequency is  [tex]f = 30.0 \ kHz = 30 *10^{3} \ Hz[/tex]

      The distance outside the cave that is being consider is  [tex]D = 100 \ m[/tex]

      The speed of sound is [tex]v_s = 340 \ m/s[/tex]

Generally the wavelength of the wave is mathematically represented as

        [tex]\lambda = \frac{v}f}[/tex]

=>     [tex]\lambda = \frac{340 }{30*10^{3}}[/tex]

=>     [tex]\lambda = 0.0113 \ m/s[/tex]

Generally for a  single slit the path difference between the interference patterns of the sound wave and the center  is mathematically represented as  

          [tex]y = \frac{ n * \lambda * D}{a}[/tex]

=>     [tex]y = \frac{ 1 * 0.0113 * 100}{0.3}[/tex]

=>     [tex]y = 3.77 \ m[/tex]

Generally the width of the sound beam is mathematically represented as

         [tex]w = 2 * y[/tex]

=>      [tex]w = 2 * 3.77[/tex]

=>      [tex]w = 7.54 \ m[/tex]        

option b )2004........

Answer:

See the answer below

Explanation:

If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.

If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.

Answer:

ok

Explanation:

Have a nice day!

Answer:

it can make it stronger!

Answer:

The strength of the magnet in this case is directly proportional to the total voltage sum of all of the batteries

Answer:

Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)

Explanation:

Answer:

a

  [tex]v_2 = 5.6 \ m/s[/tex]

b

   [tex]P_2 = 80600 \ Pa[/tex]

Explanation:

From the question we are told that  

     The pressure of the water in the pipe is  [tex]P_1= 110 \ kPa = 110 *10^{3 } \ Pa[/tex]

      The speed of the water  is [tex]v_1 = 1.4 \ m/s[/tex]

       The original area of the pipe is  [tex]A_1 = \pi \frac{d^2 }{4}[/tex]

       The  new area of the pipe is  [tex]A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}[/tex]

Generally the continuity equation is mathematically represented as

       [tex]A_1 * v_1 = A_2 * v_2[/tex]

Here [tex]v_2[/tex] is the new velocity  

So

        [tex]\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2[/tex]

=>     [tex]\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2[/tex]

=>    [tex]d^2 * 1.4 = \frac{d^2}{4} * v_2[/tex]

=>    [tex]1.4 = 0.25 * v_2[/tex]

=>     [tex]v_2 = 5.6 \ m/s[/tex]

Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the  Bernoulli's equation for constant height to calculate the pressure

This is mathematically represented as

             [tex]P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2[/tex]

Here [tex]\rho[/tex] is the density of water with value  [tex]\rho = 1000 \ kg /m^3[/tex]

             [tex]P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ][/tex]

=>          [tex]P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ][/tex]

=>          [tex]P_2 = 80600 \ Pa[/tex]

Answer:

Wheres the charts??

Explanation:

Not a straight up answer, but moreover to help you get it: (Circuit Boards)

Aside from the tasks it performs, perhaps the most important function of a circuit board is providing a way to integrate the electronics for a device in a compact space. A PCB allows components to be correctly connected to a power source while being safely insulated. Also, circuit boards are less expensive than other options because they can be designed with digital design tools and manufactured in high volume using factory automation.

Partially straight up, helping you  get the answer: (Copper Chloride)

Copper(II) chloride is the chemical compound with the chemical formula CuCl 2. This is a light brown solid, which slowly absorbs moisture to form a blue-green dihydrate.

Answer:

blc losing is part of life and u learn how do it again with losing and then you get up and comes to be a winner

Explanation:

Answer:

1.the sun must be lined up with the moon and earth all must be aligned for this to happen

Explanation:

Answer:

The speed is 4m/s because the size is the same.

Explanation:

The speed of the second ball after the collision is 4 m/s.

According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced. As a result, momentum cannot be gained or lost.

Let the mass of each billiard ball is m.

Before collision speed of first billiard ball: u = 4 m/s.

Before collision speed of second billiard ball: U= 0 m/s.

After collision speed of first billiard ball: v = 0 m/s.

After collision speed of second billiard ball: V= ?

From conservation of momentum, we can write:

Total momentum before collision = Total momentum after collision

mu +M.0 = m.0 + m.V

u = V

V = 4 m/s.

The speed of the second ball after the collision is 4 m/s.

Learn more about momentum here:

https://brainly.com/question/29113044

#SPJ2

Answer:

17.5 m/s

Explanation:

We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.

Answer:

22400 Joules

Explanation:

Apply the formula:

KE = 1/2 . 40 . 1120

KE = 20 . 1120

KE = 22400 Joules

Answer:

The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.

Explanation:

Hope this helps :)

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.2 × 20

We have the final answer as

Hope this helps you

Answer:

The ball only accelerates during the brief time that the club is in contact

with it. After it leaves the club face, it takes off at a constant speed.

If it accelerates at 20 m/s² during the hit, then

  Force = (mass) x (acceleration) = (0.2kg) x (20 m/s²) = 4 newtons .

Explanation:

Answer:

if it is moving or air is flowing over it yes

Explanation: