Answer:
I was able to solve questions 2 through 4 using the, "center = (h, k)" formula.
2. (3, -1)
3. (1, 2)
4. (-5, 2)
Hope it helps.
You wish to take a flight from Nevada to New York. Use the point (-4, 0) to represent Nevada, and the (5, 2) to represent New York. The airline has partitioned the flight so that you have a layover. The flight distance is partitioned in a ratio of 3:1. Determine the ordered pair that represents the location of the layover.
Using proportions, it is found that the ordered pair that represents the location of the layover is given by: (2.75, 1.5).
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, the flight distance is partitioned in a ratio of 3:1, hence:
L - Nv = 3/4(Ny - Nv).
This ratio is applied for both coordinates, hence, for the x-coordinate:
[tex]x + 4 = \frac{3}/{4}(5 + 4)[/tex]
[tex]x = \frac{27}{4} - \frac{16}{4}[/tex]
[tex]x = \frac{11}{4}[/tex]
x = 2.75.
For the y-coordinate:
[tex]y = \frac{3}/{4}(2 - 0)[/tex]
[tex]y = \frac{6}{4}[/tex]
x = 1.5.
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Question 11
Solve the simultaneous equations
4x + 2y = 9
x - 2y = 1
The value of x and y is (5,2)
We have given that,
4x + 2y = 9 ........(1)
x - 2y = 1.......(2)
We have to solve the simultaneous equation
What is the simultaneous equation?
A set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.
adding equations 1 and 2 so we get,
4x + 2y = 9
x - 2y = 1
----------------
5x-0y=10
[tex]5x=10\\x=10/2\\x=5[/tex]
Use the value of x in equation 2 so we get,
[tex]5-2y=1[/tex]
[tex]-2y=1-5[/tex]
[tex]-2y=-4[/tex]
[tex]y=-4/-2[/tex]
[tex]y=2[/tex]
Therefore the value of x and y is (5,2)
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For this graph, mark the statements that are true.
M
-1-
A. The range is the set of all real numbers.
B. The domain is the set of all real numbers.
C. The domain is the set of all real numbers greater than or equal to
-2.
D. The range is the set of all real numbers greater than or equal to
zero.
The true statements for this graph are:
B. The domain is the set of all real numbers.
D. The range is the set of all real numbers greater than or equal to zero.
What is a domain?A domain can be defined as the set of all real numbers for which a particular function is defined. For this graph, the vertex of the parabola is (1, 0) and as such, the equation will be given by:
y = (x - h)² + k
y = (x - 2)² + 0
y = x² -4x + 4
Therefore, the graph's domain include a set of all real numbers.
What is a range?A range refers to a set of all real numbers that connects with the elements of a domain. For this graph, we can observe that only real numbers greater than or equal to zero (0) are connected to the values on the x-axis of the domain.
In conclusion, we can logically deduce that the true statements for this graph are:
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You pick a card at random.
3 4 5
what is p(not less than 5)?
write your answer as a fraction or whole number.
Help which one is right?
Answer:
I think it is c
Step-by-step explanation:
I graphed it
Which system of inequalities is shown?
AY
O A. y>x
y> 2
OB. y
y<2
OC. y
y> 2
OD. y> x
y< 2
119
-5
S
The correct answer is option C.Which is the inequalities that show the graphs are y < x and y > 2.
What is a graph?A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.
The inequality which is shown in the figure is y < x and y > 2.We can see in the graph when you plot y > 2 then it will cover all the values greater than 2 in the graph.
Similarly, if we plot the inequality y < x on the graph it will cover all the values of y which are less than x and intersect at the point ( 2, 2).
Therefore the correct answer is option C.Which is the inequalities that show the graphs are y < x and y > 2. The graph is attached with the answer below.
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Find the exact value of sec(theta) if cot(theta)= -1/2 and the terminal side of theta lies in quadrant ii.
a. sec(theta)= -sqrt(5)/2
b. sec(theta)= sqrt(t)/2
c. sec(theta)= -sqrt(5)
d. sec(theta)= sqrt(5)
Using trigonometric identities, it is found that the exact value of the secant of the angle is given by:
c. [tex]\sec{\theta} = - \sqrt{5}[/tex]
How is the tangent related to the secant?According to the following identity:
[tex]\sec^2{\theta} = 1 + \tan^2{\theta}[/tex]
The tangent is the inverse of the cotangent, hence in this problem, we have that:
[tex]\tan{\theta} = -2[/tex]
Then, the secant is given as follows:
[tex]\sec^2{\theta} = 1 + (-2)^2[/tex]
[tex]\sec^2{\theta} = 5[/tex]
[tex]\sec{\theta} = \pm \sqrt{5}[/tex]
The angle is in the second quadrant, where the cosine is negative, hence the secant also is and option c is correct, that is:
c. [tex]\sec{\theta} = - \sqrt{5}[/tex]
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Which of the following is not a way to represent the solution of the inequality 5(x + 2) 2 7x + 2(x - 1)?
The following way is a way which can not be used to represent the solution of 5(x + 2) ≥ 7x + 2(x - 1) is "A number line with a closed circle on 3 and shading to the right".
How to solve inequality?5(x + 2) ≥ 7x + 2(x - 1)
5x + 10 ≥ 7x + 2x - 2
5x + 10 ≥ 9x - 2
collect like terms5x - 9x ≥ -2 - 10
-4x ≥ - 12
x ≤ -12/-4
x ≤ 3
Therefore, the correct answer is "A number line with a closed circle on 3 and shading to the right".
The complete question:
Which of the following is not a way to represent the solution of the inequality 5(x + 2) greater than or equal to 7x + 2(x − 1)? . A number line with a closed circle on 3 and shading to the right. . A number line with a closed circle on 3 and shading to the left. . 3 greater than or equal to x . x less than or greater to 3
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Find the perimeter please
Questions:- perimeter
Explanation:- one side is 10 cm another opposite to it
6+x= 10
x= 4 units
so now perimeter
[tex]8 + 8 + 10 + 8 + 4 + 10 \\ 16 + 8 + 4 + 20 \\ 20 + 8 + 20 \\ 40 + 8 = 48 \: units[/tex]
find the mode 4,4,3,9,5
Answer:
4
Step-by-step explanation:
The mode is most common, so it is 4.
Which method correctly solves the equation using the multiplication property of equality and the reciprocal of one-third? one-third (x 9) = negative 12 one-third (x 9 = negative 12. one-third x 3 = negative 4. one-third x = negative 7. x = negative 27. one-third (x 9) = negative 12. x 9 = negative 4. x = negative 13. one-third (x 9) = negative 12. x 3 = negative 12. x = negative 15. one-third (x 9) = negative 12. x 9 = negative 36. x = negative 45.
The solution to the equation one-third (x + 9) = negative 12 is x = -45
How to solve the equation?The equation is given as:
one-third (x + 9) = negative 12
Rewrite properly as:
1/3 (x + 9) = -12
Multiply both sides by 3
x + 9 = -36
Subtract 9 from both sides
x = -45
Hence, the solution to the equation one-third (x + 9) = negative 12 is x = -45
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9 What is the next whole number after twenty thousand ? Write your answer in figures .
10 What is the next whole number after one hundred thousand ? Write your answer in figures .
11 What is the last whole number before five thousand ? Write your answer in figures .
12 What is the last whole number before one million ? Write your answer in figures .
Answer:
9. 20,001
10. 100,001
11. 4,999
12. 999,999
Step-by-step explanation:
MATH dsjahfdhajspjihfjido
The interval at which the function decrease is (-2,0) and the number of tulip bulb in the garden is 12.8
The intervals at which the function decrease?From the table, we can see that the value of the function decreases from 12 to 3 and finally to 0, when the values of x increase from -2 to 0
Hence, the interval at which the function decrease is (-2,0)
The square gardenThe square garden has a side length x.
So, the area (A) of the garden is:
A = x²
From the question, we understand that 5 tulip bulbs are to be planted per unit area.
This means that the number of bulb in the garden is:
n = 1/5 * x²
Evaluate
n = 0.2x²
When the side length of the garden is 8, we have:
n = 0.2 * 8²
Evaluate
n = 12.8
Hence, the number of tulip bulb in the garden is 12.8
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6^2-4(3-√25)^2/|4-8|
the answer is 5 but im not sure on the steps and how to get 5, please help tysm :)
I'm going to assume you start with
[tex]\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|}[/tex]
Let's simplify some pieces of this:
[tex]6^2 = 6\times6 = 36[/tex]
[tex]\sqrt{25} = \sqrt{5^2} = 5[/tex]
[tex](3 - \sqrt{25})^2 = (3 - 5)^2 = (-2)^2 = (-2)\times(-2) = 4[/tex]
[tex]|4 - 8| = |-4| = 4[/tex]
So as a first step we can reduce this to
[tex]\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|} = \dfrac{36-4\times4}4[/tex]
Now,
[tex]36 = 9\times4[/tex]
so every term contains a factor of 4 that we can cancel:
[tex]\dfrac{36-4\times4}4 = \dfrac{9\times4-4\times4}4 = \dfrac{9-4}1 = 9-4 = \boxed{5}[/tex]
as expected.
how many whole weeks are in a year
Answer:
52 weeks are there in a year
Step-by-step explanation:
365/7
[tex]-2\sqrt{15}(-8+10\sqrt{15}[/tex]
We simplify the expression -2√15(-8 + 10√15) = 150 + 16√15
To answer the question, we need to know what surds are
What are surds?Surds are square roots of positive integers.
Since we have -2√15(-8 + 10√15), we simplify the expression
So, -2√15(-8 + 10√15) = -2√15 × (-8) + 10√15 × √15 (expanding the bracket)
= -2× (-8) × √15 + 10 × √(15 × 15)
= 16 × √15 + 10 × √15²
= 16 × √15 + 10 × 15
= 16√15 + 150
= 150 + 16√15
So, we simplify the expression -2√15(-8 + 10√15) = 150 + 16√15
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AABC is reflected across the x-axis and then dilated by a factor of 2 using the
point (-2, 1) as the center of dilation. What is the transformation of A(3, 1)?
6-
C(2,4)
4
B (5, 3)
2+
A (3.1)
4
-2-
OA. A(-6, 2)
B. A (6, -2)
C. A (8,-3)
D. A(3,-1)
-4
-2
N+
746
+00
8
10
The transformation of A is A' = (8, -3)
How to determine the transformation?From the graph, we have:
A = (3,1)
The scale factor and the center of dilation are given as:
k = 2
(a,b) = (-2,1)
The rule of reflection across the axis is:
(x,y) ⇒ (x,-y)
So, we have:
A' = (3,-1)
The rule of dilation is represented as:
(x,y) ⇒ (k(x - a) + a, k(y - b) + b)
So, we have:
A' = (2(3 + 2) - 2, 2(-1 - 1) + 1)
Evaluate
A' = (8, -3)
Hence, the transformation of A is A' = (8, -3)
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Two independent random samples of size n1 = 50 and n2 = 75 are drawn from two very large populations: population 1 and population 2. both populations are right skewed. is the use of t procedures still valid?
Answer:
No
Step-by-step explanation:
You should only use t procedures when the sample sizes are less than 30, as that is when the Central Limit Theorem kicks in.
Essentially, t procedures are good for small samples while z procedures are better for larger samples.
In a mathematic test 30 students obtained the following scores
3,4,7,2,9,5,2,1,8,2,3,6,9,3,4,3,4,1,5,3,3,1,7,7,7,5,6,4,6,5
a) Prepare a frequency table for the data
b) Draw a pictogram
c) Construct a barchart
Answer:
a) Prepare a frequency table for the data
Step-by-step explanation:
The table below shows the amount of time a light stays green, red, and yellow (for one cycle) during the day and during the night. Day Night Light is green 2 minutes 3 minutes Light is red 3 minutes 4 minutes Light is yellow 20 seconds 30 seconds Is it more likely for you to have to wait at red light during the day or at night? How much more likely? Show all of your work. WRITER
The table shows that it is more likely to wait at red during daytime by 2.92%.
How to explain the information given?Day
Green = 2 min
Red = 3 min
Yellow = 20 sec = 0.333 min
Total day cycle time= 5.33 min
Night
Green = 3 min
Red = 4 min
Yellow = 30 sec = 0.5 min
Total night cycle time= 7.5 min
Pday= 3 min/5.33 min= 0.5625
Pnight= 4 min/7.5 min= 0.5333
Pdifference= 0.02917 = 2.92%
Therefore it is more likely to wait at red during the daytime by 2.92%.
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A plant can manufacture 50 golf clubs per day at a total daily cost of $4671 and 70 golf clubs per day for a total cost of $5871.
(A) Assuming that daily cost and production are linearly related, find the total daily cost, C, of producing x golf clubs.
(B) Graph the total daily cost for 0≤x≤ 200.
(C) Interpret the slope and y intercept of the cost equation.
(A) C =
(Simplify your answer. Use integers or fractions for any numbers in the oxpropion
The function C(g) that represents the total daily cost, C, of producing x golf clubs is C = 1671 + 60g
What is linear equation?It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have:
A plant can manufacture 50 golf clubs per day at a total daily cost of $4671 and 70 golf clubs per day for a total cost of $5871.
Let's suppose x is the fixed cost and y is the variable cost.
4671 = 50y + x …(1)
5871 = 70y + x …(2)
1200 = 20y
y = 60
x = 1671
Total cost:
C(g) = 1671 + 60g
g is the number of golf per day.
Slope = 60
y- Intercept = 1671 (from the graph)
Thus, the function C(g) that represents the total daily cost, C, of producing x golf clubs is C = 1671 + 60g
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what is P(2 or divisor of 9)?
please explain!
The probability that a divisor of 2 or 9 is chosen when the spinner is spun once is 2/3.
What is the probability?
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
P(2 or divisor of 9) = section that has a divisor of 2/ total number of sections + section that has a divisor of 2/ total number of sections
1/3 + 1/ 3 = 2/3
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HELLPPPPP ASAAPPPP.
g more than the quotient of b
and f
A graph shows the number of texts, numbered 10 to 100, on the x-axis, and the total cost in dollars, numbered 3 to 27, on the y-axis. A straight red line with a positive slope, labeled Emilia, begins at (0, 10), and a straight blue line with a positive slope, labeled Hiroto, begins at (0, 20). Both lines intersect at point (50, 22.5).
Hiroto’s texting plan costs $20 per month, plus $0.05 per text message that is sent or received. Emilia’s plan costs $10 per month and $0.25 per text. Using the graph below, which statement is true?
(50, 22.5) is the solution of the system of equations, therefore, the true statement would be: Both plans cost the same when 50 texts are sent.
What is the Solution of a System of Linear Equations?A solution to the system of linear equations is the point of intersection where both line of each equation meet.
The solution to the system of linear equations given in the graph attached below is (50, 22.5).
(50, 22.5) implies that both plans will cost the total amount when 50 text are sent.
The true statement using the graph would be: Both plans cost the same when 50 texts are sent.
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Answer:
Both plans cost the same when 22 texts are sent
Step-by-step explanation:
on edge
The first term in an arithmetic sequence is -3. If the sequence has a common difference of 8, what is the 30th term in the sequence?
Will give brainliest to right answer :))
Answer:
229
Step-by-step explanation:
(my work for the problem is in the photo I attached)
(I also wrote this step-by-step in the photo because I can explain things better as I do them)
This will be a little bit confusing without me writing out the numbers, so mainly this is if you can't read my handwriting
-3 + 8 = 5 ; 5 + 8 = 13
(1st term) (2nd term) (3rd term)
Instead of adding 8 repeatedly (repeated addition), we can use multiplication.
To get the 3rd term in this sequence, we had to add 8 twice, which could also be done by multiplying 8 twice (8 x 2)
13 + 8 = 21
(4th term)
to get the 4th term, we added 8 three times (or, 8 x 3)
So, if we are looking for the 30th term in a sequence, we will have to add 8, 29 times (8 x 29) to our original term.
8 x 29 = 232
-3 + 232 = 229
This means that the 30th term of the sequence will be 229.
Your friend simplifies the expression. Is your friend correct?
( i didnt mean to click yes )
Reason:
The friend should have multiplied the exponents.
This is what the steps should look like:
[tex](r^6)^4 = r^{6*4}\\\mbox{ \ \ \ \ \ \ } =r^{24}[/tex]
The reason for the multiplication is because we have four copies of [tex]r^4[/tex] added together. Repeated addition can be shortened to multiplication.
In other words,
[tex](r^6)^4 = (r^6)*(r^6)*(r^6)*(r^6) = r^{6+6+6+6} = r^{6*4} = r^{24}[/tex]
15 Points, please help me dude I keep getting troll answers.
64
x=154(vertically opposite angle)
d =p
then mpn =154-90 = 64
angle epm is straight angle
Find the solution
a2-b2=9
a.b=3
a+b=?
Answer:
a
2
=9a+b
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
(a²+b²)²=(a²-b²)²+4a²b²=(a²-b²)²+4(ab)²=9²+4×3²=9²(1+4)
a²+b²=3√5
(a+b)²=a²+b²=2ab=3√5+2(3)=3(2+√5)
a+b=√3√(2+√5)
a simple question
1. Why x/∞=0 for x real numbers. can you explain it?
2.why x/0 for x real numbers is infinity (∞)?
STOP COPY PASTE THIS IS NOT A SERIOUS QUESTION BUT BECAUSE I AM CURIOUS!
DON'T ANSWER JUST FOR A POINTS BUT TO HELP PEOPLE!
Neither of these statements are true.
x/∞ = 0 is a nonsensical statement. It's more accurate to say
[tex]\displaystyle \lim_{y\to\infty} \frac xy = 0[/tex]
for any real number x. The important bit is that y is an arbitrarily large number as it approaches ∞. To convince yourself that this expression approaches 0 as y gets larger and larger, try fixing x and pick any increasing sequence of numbers for y.
For example, let x = 1 and take y from the sequence of increasing powers of 10, {10, 10², 10³, …}, which grows without bound. Then
1/10 = 0.1
1/10² = 0.01
1/10³ = 0.001
and so on. Naturally, the larger the power of 10 and thus the larger y gets, the closer x/y gets to 0.
Similarly, x/0 is nonsense, but the "limit-ized" version of the claim is also incorrect. For any fixed real number x, the limit
[tex]\displaystyle \lim_{y\to0} \frac xy[/tex]
does not exist. Suppose x > 0. If y approaches 0 from above, then y > 0 and x/y > 0 and
[tex]\displaystyle \lim_{y\to0^+} \frac xy = +\infty[/tex]
which you can convince yourself is true by reversing the example from before. Let x = 1 and take y from the sequence of decreasing powers of 10, {1/10, 1/10², 1/10³, …}, which converges to 0. Then
1/(1/10) = 10
1/(1/10²) = 100
1/(1/10³) = 1000
and so on. The smaller y gets (while still being positive), the larger x/y becomes.
But now suppose y < 0 and that y approaches 0 from below. Then x/y < 0, and
[tex]\displaystyle \lim_{y\to0^-} \frac xy = -\infty[/tex]
The limits from either side do not match, so the limit as y approaches 0 does not exist.
You can use the same reasoning for when x < 0.
The case of x = 0 is special, however. Since y is approaching 0, it's never actually the case that y = 0. 1/y is then some non-zero real number, and multiplying it by x = 0 makes x/y = 0. Then
[tex]\displaystyle \lim_{y\to0} \frac 0y = 0[/tex]
So in general,
[tex]\displaystyle \lim_{y\to0} \frac xy = \begin{cases}0 & \text{if }x = 0 \\ \text{does not exist} & \text{otherwise}\end{cases}[/tex]