can be ignored, what will be the maximum height that the pendulum can
reach - that is, what is the height at point B? (Recall that g = 9.8 m/s²)
B
A
4
SUBMIT
15 m
O A. 30 m
OB. 20 m
OC. 45 m
OD. 25 m

By applying the relationship of side lengths to interior angles in a triangle, a possible measure of line segment TS is 4.0 ft.

In Geometry, the relationship of side lengths to interior angles in a triangle include the following:

Based on the above theory, we can logically deduce that angle GF < TS or TS > GF because 42° is greater than 56°.

TS > 3.2 ft.

Therefore, a possible measure of line segment TS is 4.0 ft.

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Complete Question:

In the triangles, TR = GE and SR = FE. If Line segment G F = 3.2 ft, which is a possible measure of Line segment TS? 1.6 ft 3.0 ft 3.2 ft 4.0 ft.

Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

Answer:

Absolutely no real-life phenomena/ uses are possible that are related to any branch of physics, except:

1 The device you are reading this answer on. (quantum mechanics, electronics )

2 The air conditioner in your room. ( electromagnetism, electronics )

3 The satellites and space stations in space which will help in the deciphering of the universe will help us look for a suitable planet when we render the earth useless. ( general and special relativity, classical mechanics )

4 Ohh. I forgot, do you wear clothes, well they are made in factories where factories run on the principles of thermodynamics, which is physics.

5 Ever gone somewhere? Well, the transportation uses classical mechanics, thermodynamics, electromagnetism, relativity ( if you know Global Positioning System )

6 GPS itself! It’s used in online maps, navigating, and this sort of stuff. It works on general relativity.

Honestly, this list is endless.

Let the upstream breadcrumb's position act as the origin, so the position at time [tex]t[/tex] of upstream crumb [tex](B_U)[/tex], duck [tex](D)[/tex], and downstream crumb [tex](B_D)[/tex] are, respectively,

[tex]x_{B_U} = \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

[tex]x_D = d\,\mathrm m + v_D t[/tex]

[tex]x_{B_D} = 2d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

where [tex]d[/tex] is the distance (in m) between the duck and either crumb at the start, and [tex]v_D[/tex] is the velocity of the duck relative to the Earth.

To get both breadcrumbs, the duck has to choose between chasing the upstream or downstream crumb first.

• If the upstream crumb is chosen first, then [tex]v_D[/tex] is 2.0 - 1.0 = 1.0 m/s. Find the time it takes for the duck to reach the upstream crumb:

[tex]x_{B_U} = x_D \implies \left(2.0\dfrac{\rm m}{\rm s}\right) t = d + \left(1.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = d \, \mathrm s[/tex]

In this time, the duck covers a distance of

[tex]x_D = d\,\mathrm m + \left(1.0\dfrac{\rm m}{\rm s}\right) (d\, \mathrm s) = 2d \, \mathrm m[/tex]

while the downstream crumb will have traveled a distance of

[tex]x_{B_D} = 2d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) (d \,\mathrm s) = 4d \,\mathrm m[/tex]

putting a total distance of [tex]2d+4d=6d\,\mathrm m[/tex] between the duck and the remaining crumb.

Take the duck's new position to be the new origin. When the duck turns around and travels with the current, its speed [tex]v_D[/tex] will be 2.0 + 1.0 = 3.0 m/s. Then at time [tex]t[/tex], the duck and remaining crumb have position relative to the new origin given by

[tex]x_D' = \left(3.0\dfrac{\rm m}{\rm s}\right) t[/tex]

[tex]x_{B_D}' = 6d \,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

Find the time the duck needs to catch up to the downstream crumb:

[tex]x_D' = x_{B_D}' \implies \left(3.0\dfrac{\rm m}{\rm s}\right) t = 6d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = 6d \,\mathrm s[/tex]

Then the total time the duck needs to get both crumbs is [tex]d + 6d = 7d \,\mathrm s[/tex].

• If instead the downstream crumb is chased down first, we start with [tex]v_D[/tex] = 3.0 m/s, so that

[tex]x_D = x_{B_D} \implies d\,\mathrm m + \left(3.0\dfrac{\rm m}{\rm s}\right) t = 2d\,\mathrm m + \left(2.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = d \, \mathrm s[/tex]

In this time, the duck covers a distance of

[tex]x_D = d\,\mathrm m + \left(3.0\dfrac{\rm m}{\rm s}\right) (d\,\mathrm s) = 4d \,\mathrm m[/tex]

while the upstream crumb moves

[tex]x_{B_U} = \left(2.0\dfrac{\rm m}{\rm s}\right) (d\,\mathrm s) = 2d \,\mathrm m[/tex]

The distance between the duck and remaining crumb is then [tex]4d-2d=2d\,\mathrm m[/tex]. Now the duck turns around with speed [tex]v_D[/tex] = 1.0 m/s. If the crumb's new position is taken to be the origin, then

[tex]x_{B_U}' = \left(2.0\dfrac{\rm m}{\rm s}\right) t[/tex]

[tex]x_D' = 2d\,\mathrm m + \left(1.0\dfrac{\rm m}{\rm s}\right) t[/tex]

Find the time it takes for the duck to get the last crumb:

[tex]x_{B_U}' = x_D' \implies \left(2.0\dfrac{\rm m}{\rm s}\right)t = 2d\,\mathrm m + \left(1.0\dfrac{\rm m}{\rm s}\right) t \\\\ \implies t = 2d\,\mathrm s[/tex]

Then the duck can get both crumbs in a total of [tex]d+2d=3d\,\mathrm s[/tex].

To get both crumbs in the shortest time, the duck should go after the downstream crumb first. This path over 2 times faster than the other.

Answer:-2.5m/s^2

Explanation:

facts

The acceleration of the object would be -2.5 m/s², the negative sign represents the deaccelerating motion of the object.

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

acceleration =change in velocity/change in time

The slope of the velocity time graph represents the acceleration of the object.

The slope of the graph = change in the y coordinates (velocity)/ change in the x coordinate (time)

The slope of the graph =( 10-40)/( 12-0)

                                      = -2.5 m/s²

Thus, the acceleration of the object comes out to be  -2.5 m/s².

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Answer:

5.9 × 10⁶m

Explanation:

                         = 12.7×10⁶ - 6.8 × 10⁶

                         = 5.9 × 10⁶m

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Answer:

Option C

Explanation:

According to the formula

So

If we use wide wire we increase the area of cross section so resistance decreases

Answer:

A wheel on a car, however, rotates around the car's axle, so it does have rotational motion. For this example, if you were to pick a single point on the edge of the wheel, you could also say that it has circular motion.

The lists from greatest to lowest change in velocity.Dustin → Diego → Kira. Option A is correct.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The acceleration is obtained one by one from the given data as the ratio of the velocity to the time.

For the acceleration of each, you can refer to the excel table attached below.

The velocity changes are listed from largest to least. Dustin and Diego Kira.

Hence, option A is the right answer.

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Answer:

D. Kira → Diego → Dustin

Explanation:

Got 100% on the test. Y'all have a good day! :p

The separation between the lines of the grating is 13.33μm.

The diffraction grating is the continuous lines with very minute slits or grating space in mm.  It divides light composed of various wavelengths into light components by particular wavelength.

dsinθ = nλ

Substitute n =3, λ =490 x 10⁻⁹ m and angle θ =6.33°, we get

d = [3 x 490 x 10⁻⁹ /sin 6.33°]

d = 13.33 x 10⁻⁶ m

Thus, the separation between the lines of the grating is 13.33μm.

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Answer:

Force exerted on the car is 7030 N.

Explanation:

It is given that,

Mass of the car, m = 740 kg

Initial speed of the car, u = 19 m/s

Final speed of the car, v = 0

Time taken, t = 2 s

Let F is the force exerted on the car during this stop. We know that it is equal to the product of force and acceleration. Mathematically, it is given as :

F=m\times \dfrac{v-u}{t}F=m×tv−u

F=740\times \dfrac{0-19}{2}F=740×20−19

F = -7030 N

So, the force exerted on the car during this stop is 7030 N. Hence, this is the required solution.

The birds, bats, insects, airplanes, rockets, and hot air balloons achieve their flight by creating high pressure below the aircraft and low pressure above it

They both consist of fundamentally simple building blocks. They are composed of substances or mass. Atmospheric and molecular building blocks make up the world.

In order to create high pressure below the aircraft and low pressure above it, airplanes employ specially built wings.

The wing receives sufficient airflow past it to counteract the weight and drag of the aircraft by utilizing a device to provide thrust, such as a propeller.

High pressure underneath the aircraft and low pressure above it is produced by specially constructed wings used by airplanes.

The wing receives enough airflow through it by the use of a thrust-generating device, like a propeller, to overcome the weight and drag of the aircraft.

The differences between how living and non-living things fly;

1. Moving both living and non-living objects consumes energy. Flying animals utilize their wings to create both lift and propulsion by moving them in relation to the body.

In contrast to most air vehicles, where the components that generate lift, wings, and thrust engines or propellers are distinct, the wings stay stationary.

Animal aviators like birds as well as natural parachuters like patagial as well as human inventions like aircraft as well as rockets that can power spacecraft and spaceplanes are just a few examples of the many things that can fly.

Hence, birds, bats, insects, airplanes, rockets, and hot air balloons achieve their flight by creating high pressure below the aircraft and low pressure above it

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Hello!

Using the equation for the magnetic force on a current-carrying wire:
[tex]F_B = \vec{B} \times i\vec{L}[/tex]

[tex]F_B[/tex] = Magnetic Force (0.38 N)
B = Magnetic field strength (T)
i = Current in wire (4.75 A)
L = Length of wire (0.25 m)

This is a cross product, so we can rewrite the equation as:
[tex]F_B = BiLsin\phi[/tex]

Where φ is the angle between the magnetic field vector and the length vector. In this instance, since the field is perpendicular to the wire, sin(90) = 1. We can simplify the equation to:
[tex]F_B = BiL[/tex]

Rearrange the equation to solve for 'B':
[tex]B = \frac{F_B}{iL}[/tex]

Plug in given values and solve.

[tex]B = \frac{0.38}{(4.75 * .25)} = \boxed{0.32 T}[/tex]

The strength of the magnetic field will be 0.32 T.Option B is correct.

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

Given data:

(I) current = 4.75-A

(B)induced magnetic field strrength=?

(L)length of the wire=0.25-m

(F)Magnetic force=0.38 N

The strength of the magnetic field is found as:

[tex]\rm F_B=BILsin \theta \\\\\ \theta = 90^0 \\\\ \rm F_B=BIL \\\\[/tex]

Substitute the values:

[tex]\rm 0.38 = B \times 4.75 \times 0.25 \\\\\ B= \frac{0.38}{4.75 \times 0.25 } \\\\\ B=0.32 \ T[/tex]

The strength of the magnetic field will be 0.32 T.

Hence, option B is correct.

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The magnitude of the electric field at the third vertex of the triangle is determined as zero.

The electric field at the third vertex of the equilateral triangle due to the other charges placed on the first and second vertices is calculated as follows;

E = E(13) + E(23)

E = (kq₁)/r² + (kq₂)/r²

where;

E =  (kq₁)/r² - (kq₂)/r²

E = 0

Thus, the magnitude of the electric field at the third vertex of the triangle is determined as zero.

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Answer:

the correct answer is Jupiter has moons orbiting it

The maximum height the ball will reach 7.316 ft. This height is less than a standard soccer goal's height.

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

Maximum height reached is given by

H = u²sin²θ /2g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Consider the soccer ball is kicked toward a goal at a speed of 35 mph and an angle of 25 ° from horizontal,

Given is the speed 35mph = 35 x 1609/3600 = 15.65 m/s, θ =25 ° and g = 9.81 m/s²

Substituting the values, we get

H = (15.65)² (sin25 °)² / 2 x 9.81

H = 2.23 m

in feet, H = 7.316 ft

Thus, the maximum height is 7.316 ft. This height is less than  a standard soccer goal's height, which is 8 feet from the ground.

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Answer:

power=work done÷time taken

2×5=10

10÷10=1

ans 1J per second

The quarks that compose a baryon may have charges of +(2/3)e and -(1/3)e which means have negative and positive charges.

Quarks are the most fundamental particles that make up the atomic nucleus. All solid matter that we know is made of three particles, which are the up and down quarks, 'u' and 'd', and the electron.

Quark is one of the two basic elements that make up matter and is the only one of the particles that interacts through all four fundamental forces.

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Olivia is on a swing at the playground. The kinetic energy is increasing and her potential energy decreasing at point X.

The kinetic energy of an object is the ability to do work by virtue of its motion and potential energy is the ability to do work by virtue of its position.

At point W and Z, Olivia is at the maximum displacement from the mean position, where kinetic energy is zero and potential energy is maximum.

At point Y, it is approaching to increase its potential energy and decreasing kinetic energy. Opposite to this, at point X, kinetic energy is increasing and potential energy is decreasing.

Thus, the kinetic energy is increasing and her potential energy decreasing at point X.

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By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.

First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:

S = ut + ½gt²

49 = 0(t) + ½ × 9.8 × t²

49 = 4.9t²

t² = 49/4.9

t = √10

t = 3.16 seconds.

Now, we can determine the speed at which he threw the second stone:

Note: Time = 3.16 - 1 = 2.16 seconds.

S = ut + ½gt²

49 = u(2.16) + ½ × 9.8 × 2.16²

49 = 2.16u + 22.86

2.16u = 49 - 22.86

u = 26.14/2.16

u = 12.10 m/s.

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Answer:

Mass

The kilogram (kg) is the SI unit of mass and it is the almost universally used standard mass unit.

Gravity and weight

Since the acceleration due to the force of gravity (g) equals aproximately 9.8 meters/s2, the weight of an object with a mass of 1 kilogram is 9.8 newtons under standard conditions on the Earth's surface.

Answer:

The mass of an object is a measure of the object's inertial property, or the amount of matter it has in it

The weight of an object is a measure of the force/impact  exerted on the object by gravity, or the force needed to support it

The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.

Hope This Helped

A hypothesis about what might happen in the lab might be 'oxygen will react with hydrogen to form water molecules'.

A hypothesis is a given explanation of a particular scientific question emerged by observing the real world.

Hypotheses are explanations that must be tested (either confirmed or rejected) by using the scientific method.

In conclusion, a hypothesis about what might happen in the lab might be 'oxygen will react with hydrogen to form water molecules'.

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The magnitude of the acceleration of the car is determined as 1.11 m/s².

The acceleration of the train is determined as the rate of change of velocity with time.

The magnitude of the acceleration of the car is calculated as follows;

a = v/t

a = 50/45

a = 1.11 m/s²

Thus, the magnitude of the acceleration of the car is determined as 1.11 m/s².

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The two elements that have the same number of dots around their chemical symbols in their electron dot are Germanium and Silicon.

The valence electron of an atom can be represented by a lewis dot diagram.

Germanium and silicon belonging to group 14 of the periodic table has 4 dots around their chemical symbols in their electron dot.

Thus, the two elements that have the same number of dots around their chemical symbols in their electron dot are Germanium and Silicon.

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Explanation:

w = mg

on earth

w = mg

w = 60 × 9.8 = 588 N

on moon

w = mg

w = 60 × 1.6 = 96 N

on Mars

w = mg

w = 60 × 3.7 = 222 N

In this question,we solve it using the formulae below:

W=mg.

So to find the weight of the object in 1.Earth.Enter the given data on formula:

W=mg

W=60×9.8

2.Weight on the moon.

W=mg

W=60×1.6

3.Weight on Mars.

W=mg

W=60×3.7

You can find the magnitude of the resultant vector : (B). By adding the magnitudes of the two vectors

A vector can be defined as any quantity which possesses magnitude and also has direction.

A Vector quantity is very useful because This type of quantity gives more details to the student or teacher analyzing it.

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