Brass is an alloy composed of 55% copper and 45% zinc by weight. You have 25 ounces of copper. How many ounces of zinc do you need to make brass? Round your answer to the nearest tenth

Answers

Answer 1

To make brass with 25 ounces of copper, one requires 20.4 ounces of zinc to maintain the required ratio in order to make brass, an alloy that is 55% copper and 45% zinc by weight.

According to the question,

The weight percentage of copper in brass = 55%

The weight percentage of zinc in brass = 45%

Given, the weight of copper = 25 ounces

Let the mass of brass be x

We can say, 55% of x is 25 ounces

[tex]\frac{55}{100}* x= 25\\ \\x=\frac{25*100}{55} \\\\x=\frac{500}{11}[/tex]

Weight of zinc in this alloy = 45% of x

[tex]= \frac{45}{100}*\frac{500}{11}\\\\ =\frac{45*5}{11}=20.45[/tex]

Therefore, the weight of zinc is 20.4 ounces.

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Related Questions

An object is placed 16.2 cm from a first converging lens of focal length 11.6 cm. A second converging lens with focal length 5.00 cm is placed 10.0 cm to the right of the first converging lens.(a) Find the position q1 of the image formed by the first converging lens. (Enter your answer to at least two decimal places.)cm(b) How far from the second lens is the image of the first lens? (Enter your answer to at least two decimal places.)cm beyond the second lens(c) What is the value of p2, the object position for the second lens? (Enter your answer to at least two decimal places.)cm(d) Find the position q2 of the image formed by the second lens. (Enter your answer to at least two decimal places.)cm(e) Calculate the magnification of the first lens.(f) Calculate the magnification of the second lens.(g) What is the total magnification for the system?(h) Is the final image real or virtual (compared to the original object for the lens system)?realvirtualIs it upright or inverted (compared to the original object for the lens system)? upright

Answers

The final image is real since it is located to the right of the second lens. It is also upright since the magnification is positive.

(a) Using the thin lens formula, 1/f = 1/p + 1/q, where f is the focal length, p is the object distance, and q is the image distance, we have:

1/f = 1/p - 1/q1

Substituting the given values, we get:

1/11.6 = 1/16.2 - 1/q1

Solving for q1, we get:

q1 = 6.97 cm

Therefore, the image formed by the first lens is located 6.97 cm to the right of the lens.

(b) The image formed by the first lens acts as an object for the second lens. Using the thin lens formula again, we have:

1/f = 1/p2 + 1/q1

Substituting the given values, we get:

1/5 = 1/p2 + 1/6.97

Solving for p2, we get:

p2 = 3.32 cm

The distance from the second lens to the image of the first lens is then:

q2 = p2 + q1 = 3.32 + 6.97 = 10.29 cm

Therefore, the image of the first lens is located 10.29 cm to the right of the second lens.

(c) The object distance for the second lens is simply the image distance of the first lens:

p2 = q1 = 6.97 cm

(d) Using the thin lens formula again, we have:

1/f = 1/p2 + 1/q2

Substituting the given values, we get:

1/5 = 1/6.97 + 1/q2

Solving for q2, we get:

q2 = 13.95 cm

Therefore, the final image is located 13.95 cm to the right of the second lens.

(e) The magnification of the first lens is given by:

m1 = -q1/p = -6.97/16.2 ≈ -0.43

(f) The magnification of the second lens is given by:

m2 = -q2/p2 = -13.95/3.32 ≈ -4.20

(g) The total magnification of the system is given by the product of the magnifications of the two lenses:

m = m1 × m2 ≈ 1.81

(h) The final image is real since it is located to the right of the second lens. It is also upright since the magnification is positive.

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Please help!!!

006
A survey was conducted at a local mall in which 100 customers were asked what flavor of soft drink they preferred. The results of the survey are in the chart. Based on this survey if 300 customers were asked their preference how many would you expect to select cola as their favorite flavor? Answer in units of customers.

Answers

Answer: 87

Step-by-step explanation: 3 x 29=87 because you are multiplying the amount of people in the survey by 3

The two triangles shown are similar. Find the value of y

Answers

Answer:

[tex] \frac{y}{28} = \frac{7}{25} [/tex]

[tex]25y = 196[/tex]

[tex]y = 7.84[/tex]

√3x + √2x-1/√3x -√2x-1 = 5
prove that x = 3/2

Answers

Answer:

this is a correct answer 5√6/2

Solve the expression 9 + (20 x one fourth) − 6 ÷ 2 using PEMDAS. (1 point)


8

11

13

16

Answers

Answer:

B) 11

Step-by-step explanation:

PEMDAS=parenthesis, exponents, multiplication, division, addition, and subtraction.

First start with the parenthesis:

20 x 1/4=5

9 + (5) - 6 ÷ 2

We don't have exponents or multiplication, so go onto division:

-6 ÷ 2 = -3

9+5-3

Finally addition and subtraction:

9+5-3=11

Hope this helps!

what is the easiest way to solve quadratic problems using the quadratic formula in a step by step sequence?

Answers

The text is asking for a step-by-step sequence to solve quadratic problems using the quadratic formula.

A quadratic equation is a polynomial equation of the second degree, meaning it contains at least one squared term. The standard form of a quadratic equation is ax² + bx + c = 0, where a, b, and c are constants and x is the variable. The quadratic formula is used to find the solution(s) of a quadratic equation. The formula is x = (-b ± sqrt(b² - 4ac)) / 2a.

Answer:

Step-by-step explanation:

put your equation into

ax²+bx+c

determine a, b, and c

plug into formula

simplify numbers under the square root first (b²-4ac)

then simplify the root.  ex.  √12 can be simplified to 2√3

then reduce if the bottom can be reduced with both of the terms on top

find the slope of the parametric curve x=-4t^2-4, y=6t^3, for , at the point corresponding to t.

Answers

The slope of the parametric curve x=-4t^2-4, y=6t^3 at the point corresponding to t is -9t/4.

To find the slope of the parametric curve x=-4t^2-4, y=6t^3 at the point corresponding to t, follow these steps:
1.  Find the derivatives of both x and y with respect to t:
   dx/dt = -8t
   dy/dt = 18t^2
2. The slope of the parametric curve is the ratio of the derivatives, dy/dx.

    To find this, divide dy/dt by dx/dt:

    dy/dx = (dy/dt) / (dx/dt)

              = (18t^2) / (-8t)
3. Simplify the expression:
   dy/dx = -9t / 4
So, the slope of the parametric curve x=-4t^2-4, y=6t^3 at the point corresponding to t is -9t/4.

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Consider the curve x2/3+y2/3=4.
Let L be the tangent line to this curve at the point (1,3√3), and let A and B be the x- and y-intercepts of L.
What is the length of the line segment AB?
(a) 8
(b) √38
(c) 8√3
(d) √3
(e) 31/38

Answers

If the curve x2/3+y2/3=4 and Let L be the tangent line to this curve at the point (1,3√3), and let A and B be the x- and y-intercepts of L, then the length of line segment AB is √38 (option b).

Explanation:

To find the length of line segment AB, follow these steps:

Step 1: We need to first find the equation of tangent line L at the given point (1, 3√3) on the curve x^(2/3) + y^(2/3) = 4.

Step 1. Find the derivative dy/dx using implicit differentiation:
(2/3)x^(-1/3) + (2/3)y^(-1/3)(dy/dx) = 0

Step 2. Solve for dy/dx (the slope of tangent line L) at point (1, 3√3):
(2/3)(1)^(-1/3) + (2/3)(3√3)^(-1/3)(dy/dx) = 0
dy/dx = -1/2

Step 3. Use the point-slope form to find the equation of tangent line L:
y - 3√3 = -1/2(x - 1)

Step 4. Find the x- and y-intercepts (A and B) of line L:
x-intercept (A): y = 0
0 - 3√3 = -1/2(x - 1)
x = 2 + 6√3

y-intercept (B): x = 0
y - 3√3 = -1/2(0 - 1)
y = 3√3 + 1/2

Step 5. Calculate the length of the line segment AB using the distance formula:
AB = √[(2 + 6√3 - 0)^2 + (3√3 + 1/2 - 0)^2] = √38

The length of line segment AB is √38 (option b).

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Give the correct singular, affirmative, formal command of each of the following verbs. 1. tener: 2. conocer: 3. buscar: 4. ir: 5. ser:

Answers

The singular, affirmative and formal command for each of the following are as follows: 1.tener: tenga, 2.conocer: conozca 3.buscar:busque 4.ir:vaya 5.ser:sea

What Spanish Affirmative and Negative commands?

The indicative, subjunctive, and imperative verb moods are the three primary categories of verb moods in Spanish.

When discussing actual actions, events, conditions, and facts, the indicative mood is utilized.The subjunctive mood, which denotes subjectivity, is typically employed to express a personal assertion or query.The imperative mood is used to issue clear instructions or directives. In other words, the imperative mood is employed to direct others as to what they should or should not do. As a result, Spanish has two command forms: Affirmative commands, also known as the positive imperative tense, are used to give specific instructions for something to occur. Spanish command phrases known as "negative commands” are used to issue clear directives against actions that should not happen(i.e., to tell people what not to do).

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A Nyquist plot of a unity-feedback system with the feedforward transfer function G(s) is shown in Figure. If G(s) has one pole in the right-half s plane, is the system stable? If G(s) has no pole in the right-half s plane, but has one zero in the right-half s plane, is the system stable?

Answers

In a Nyquist plot, If G(s) has one pole in the right-half s plane, the system is marginally stable.

If G(s) has no pole in the right-half s plane, but has one zero in the right-half s plane, the system is stable.

In a Nyquist plot, the stability of a system can be determined by examining the number of encirclements of the -1 point. If the number of encirclements is equal to the number of right-half plane poles, then the system is unstable. If the number of encirclements is less than the number of right-half plane poles, then the system is marginally stable. If the number of encirclements is greater than the number of right-half plane poles, then the system is stable.

In the first case where G(s) has one pole in the right-half s plane, the Nyquist plot will encircle the -1 point once in the clockwise direction. Therefore, the number of encirclements is less than the number of right-half plane poles, which means the system is marginally stable.

In the second case where G(s) has one zero in the right-half s plane, the Nyquist plot will not encircle the -1 point at all. Therefore, the number of encirclements is less than the number of right-half plane poles, which means the system is stable.

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there is no 3 × 3 matrix a so that a2 = −i3.

Answers

Based on the analysis, there is no 3x3 matrix A such that A^2 = -I_3. To understand this analysis let's consider whether there exists a 3x3 matrix A such that A^2 = -I_3, where I_3 is the 3x3 identity matrix.


Step:1. Start by assuming that there is a 3x3 matrix A such that A^2 = -I_3.
Step:2. Recall that the determinant of a matrix squared (det(A^2)) is equal to the determinant of the matrix (det(A)) squared: det(A^2) = det(A)^2.
Step:3. Compute the determinant of both sides of the equation A^2 = -I_3: det(A^2) = det(-I_3).
Step:4. For the 3x3 identity matrix I_3, its determinant is 1. Therefore, the determinant of -I_3 is (-1)^3 = -1.
Step:5. From step 2, we know that det(A^2) = det(A)^2. Since det(A^2) = det(-I_3) = -1, we have det(A)^2 = -1.
Step:6. However, no real number squared can equal -1, which means det(A)^2 cannot equal -1.
Based on the analysis, there is no 3x3 matrix A such that A^2 = -I_3.

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assume the random variable x is normal distributed with a mean of 395 and a standard deviation of 23. if x = 35, find the corresponding z-score.

Answers

The corresponding z-score for a random variable x that is normally distributed with a mean of 395 and a standard deviation of 23, when  x = 35 is:  -15.65

To find the z-score, you can use the following formula:

z = (x - μ) / σ

where z is the z-score, x is the value of the random variable, μ is the mean, and σ is the standard deviation.

Step 1: Identify the values.
x = 35, μ = 395, and σ = 23.

Step 2: Substitute the values into the formula.
z = (35 - 395) / 23

Step 3: Calculate the z-score.
z = (-360) / 23 = -15.65

So, the corresponding z-score for x = 35 is approximately -15.65.

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AABC is translated 4 units to the left and 8 units up. Answer the questions to find the coordinates of A after the translation.



1. Give the rule for translating a point 4 units left and 8 units up.



2. After the translation, where is A located




Now reflect the figure over the y-axis. Answer to find the coordinates of A after the reflection

3. Give the rule for reflecting a point over the y-axis


4. What are the coordinates of A after the reflection?


5. is the final figure congruent to the original figure? How do you know?​

Answers

The shape and size of the figure are unchanged. and other soltuions are below

The rule for translating a point 4 units left and 8 units up.

The rule for translating a point 4 units left and 8 units up is (x, y) → (x - 4, y + 8).

After the translation, where is A located

Using the above rule

After the translation, the new coordinates of A are (3, 13).

The rule for reflecting a point over the y-axis

The rule for reflecting a point over the y-axis is (x, y) → (-x, y).

The coordinates of A after the reflection?

Using the above rule

After the reflection, the coordinates of A become (-7, 5).

Is the final figure congruent to the original figure?

The final figure is congruent to the original figure because translation and reflection are both rigid transformations, which preserve distance and angles between points.

Therefore, the shape and size of the figure are unchanged.

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Find the average value fave of the function f on the given interval. f(x) = x2 (x3 + 30) [-3, 3] = fave Find the average value have of the function h on the given interval. In(u) h(u) = [1, 5] u = h ave Find all numbers b such that the average value of f(x) = 6 + 10x - 9x2 on the interval [0, b] is equal to 7. (Enter your answers as a comma-separated list.) b = Suppose the world population in the second half of the 20th century can be modeled by the equation P(t) = 2,560e0.017185t. Use this equation to estimate the average world population to the nearest million during the time period of 1950 to 1980. million people

Answers

Answer:

Step-by-step explanation:

To find the average value of the function f(x) = x^2(x^3 + 30) on the interval [-3, 3], we use the formula:

fave = (1/(b-a)) * ∫[a,b] f(x) dx

where a = -3 and b = 3.

So, we have:

fave = (1/(3-(-3))) * ∫[-3,3] x^2(x^3 + 30) dx

fave = (1/6) * [∫[-3,3] x^5 dx + 30∫[-3,3] x^2 dx]

fave = (1/6) * [0 + 30(2*3^3)]

fave = 2430

Therefore, the average value of the function f on the given interval is 2430.

To find the average value of the function h(u) = In(u) on the interval [1, 5], we use the formula:

have = (1/(b-a)) * ∫[a,b] h(u) du

where a = 1 and b = 5.

So, we have:

have = (1/(5-1)) * ∫[1,5] ln(u) du

have = (1/4) * [u ln(u) - u] from 1 to 5

have = (1/4) * [(5 ln(5) - 5) - (ln(1) - 1)]

have = (1/4) * (5 ln(5) - 4)

have = 0.962

Therefore, the average value of the function h on the given interval is approximately 0.962.

To find all numbers b such that the average value of f(x) = 6 + 10x - 9x^2 on the interval [0, b] is equal to 7, we use the formula:

fave = (1/(b-a)) * ∫[a,b] f(x) dx

where a = 0 and b = b.

So, we have:

7 = (1/b) * ∫[0,b] (6 + 10x - 9x^2) dx

7b = [6x + 5x^2 - 3x^3/3] from 0 to b

7b = 2b^2 - 3b^3/3 + 6

21b = 6b^2 - b^3 + 18

b^3 - 6b^2 + 21b - 18 = 0

Using synthetic division, we find that b = 2 is a root of this polynomial equation. Dividing by (b-2), we get:

(b-2)(b^2 - 4b + 9) = 0

The quadratic factor has no real roots, so the only solution is b = 2.

Therefore, the only number b such that the average value of f(x) on the interval [0, b] is equal to 7 is 2.

To estimate the average world population to the nearest million during the time period of 1950 to 1980, we need to find:

ave = (1/(1980-1950)) * ∫[1950,1980] P(t) dt

ave = (1/30) * ∫[1950,1980] 2560e^(0.017185t) dt

Using the formula for integrating exponential functions, we get:

ave = (1/30) * [2560

help quick/100 points Select all of the following statements that are true. If 6 > 10, then 8 · 3 = 24. 6 + 3 = 9 and 4 · 4 = 16 If 6 · 3 = 18, then 4 + 8 = 20 5 · 3 = 15 or 7 + 5 = 20

Answers

Answer:

The statements that are true are:

6 + 3 = 9 and 4 · 4 = 16 (both are true statements)

5 · 3 = 15 or 7 + 5 = 20 (at least one of these statements is true, since the word "or" means that only one of the two statements needs to be true for the entire statement to be true)

The other two statements are false:

If 6 > 10, then 8 · 3 = 24 (this statement is false, because the premise "6 > 10" is false, and a false premise can never imply a true conclusion)

If 6 · 3 = 18, then 4 + 8 = 20 (this statement is false, because the conclusion "4 + 8 = 20" does not follow logically from the premise "6 · 3 = 18")

Write the complex number e^i pi/3 in the form a + bi. a = and b =. Write the complex number e^i 4 pi/3 in the form a + bi. a = and b = Write the complex number z = 6 - 4i in polar form: z = r(cos theta + i sin theta) where r = and theta = The angle should satisfy 0 lessthanorequalto theta < 2 pi

Answers

z = 2√13(cos 5.49 + i sin 5.49) in polar form.

We can use Euler's formula, e^(iθ) = cos(θ) + i sin(θ), to write complex numbers in polar form.

1. For e^(iπ/3), we have:

e^(iπ/3) = cos(π/3) + i sin(π/3) = 1/2 + i√3/2

Therefore, a = 1/2 and b = √3/2.

2. For e^(i4π/3), we have:

e^(i4π/3) = cos(4π/3) + i sin(4π/3) = -1/2 - i√3/2

Therefore, a = -1/2 and b = -√3/2.

3. For z = 6 - 4i, we can find the magnitude (or modulus) of z, r, using the Pythagorean theorem:

|r| = √(6^2 + (-4)^2) = √52 = 2√13

To find the angle, theta, we can use the inverse tangent function:

tan⁻¹(-4/6) = -tan⁻¹(2/3) ≈ -0.93 radians

However, since we want the angle to satisfy 0 ≤ θ < 2π, we need to add 2π to the angle if it is negative:

θ = 2π - 0.93 ≈ 5.49 radians

Therefore, z = 2√13(cos 5.49 + i sin 5.49) in polar form.

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6 soccer players share 5 oranges as fraction

Answers

Answer:5/6

Step-by-step explanation: Theres 6 people that you are splitting 5 oranges among. so you do the equation 5÷6 or 5/6 which is the answer your looking for

Answer:

5/6

Step-by-step explanation:

=0.8333.......................

find the length of the curve. note: you will need to evaluate your integral numerically. round your answer to one decimal place. x = cos(2t), y = sin(3t) for 0 ≤ t ≤ 2

Answers

The length of the curve is approximately 4.7 units when rounded to one decimal place.

Explanation:

To find the length of the curve, follow these steps:

Step 1: To find the length of the curve, we need to use the formula:

length = ∫(a to b) √(dx/dt)^2 + (dy/dt)^2 dt

Step 2: In this case, we have x = cos(2t) and y = sin(3t) for 0 ≤ t ≤ 2, First, find the derivatives dx/dt and dy/dt so we can find dx/dt and dy/dt as:

dx/dt = -2sin(2t)
dy/dt = 3cos(3t)

Step 3: Substituting these into the formula, we get:

length = ∫ (0 to 2) √((-2sin(2t))^2 + (3cos(3t))^2) dt

length = ∫ (0 to 2) √(4sin^2(2t) + 9cos^2(3t)) dt
This integral must be evaluated numerically.

Step 4: Using a calculator or software to evaluate the integral numerically, we get:

length ≈ 4.7

Therefore, the length of the curve is approximately 4.7 units when rounded to one decimal place.

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Find the point on y=x3+6x2-15x+1 at which the gradient is zero

Answers

To find the point(s) on the curve y = x^3 + 6x^2 - 15x + 1 at which the gradient is zero, we need to find where the derivative of the curve is zero.

Taking the derivative of y with respect to x, we get:

y' = 3x^2 + 12x - 15

To find where the gradient is zero, we need to solve the equation y' = 0:

3x^2 + 12x - 15 = 0

Dividing both sides by 3, we get:

x^2 + 4x - 5 = 0

Factoring the quadratic equation, we get:

(x + 5)(x - 1) = 0

So the solutions are x = -5 and x = 1.

To find the corresponding points on the curve, we substitute each value of x back into the equation y = x^3 + 6x^2 - 15x + 1:

When x = -5, y = (-5)^3 + 6(-5)^2 - 15(-5) + 1 = -99

When x = 1, y = 1^3 + 6(1)^2 - 15(1) + 1 = -7

Therefore, the points on the curve at which the gradient is zero are (-5, -99) and (1, -7).

Can someone help me please? I've been trying to solve this for a while now, please help. Thank you

Answers

Answer:

-1(-4)=-5

Step-by-step explanation:

as h = -1

What is the overall order of the following reaction, given the rate law?
X + 2 Y → 4 Z Rate = k[X][Y]
3rd order
1st order
2nd order
5th order
6th order

Answers

The overall order of the reaction is 2nd order.

Option B is the correct answer.

We have,

The overall order of a chemical reaction is the sum of the orders of the reactants in the rate law.

In this case,

The rate law is given as:

Rate = k[X][Y]

The order with respect to X is 1, and the order with respect to Y is 1.

Therefore, the overall order of the reaction is:

1 + 1 = 2

Thus,

The overall order of the reaction is 2nd order.

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At the same time a 70 feet building casts a 50 foot shadow, a nearby pillar casts a 10 foot shadow. Which proportion could you use to solve for the height of the pillar?

Answers

The height of the pillar is 14 feet.

How to find height ?

We can use the ratio of the building's height to the length of its shadow to solve for the pillar's height and apply it to the pillar as well. This is because similar-shaped objects will produce shadows that are proportional to their size.

Let h represent the pillar's height, and let's establish a proportion:

height of building / length of building's shadow = height of pillar / length of pillar's shadow

Substituting the given values:

70 / 50 = h / 10

We can simplify this proportion by cross-multiplying:

70 x 10 = 50h

700 = 50h

And solving for h:

h = 700 / 50 = 14

Therefore, the height of the pillar is 14 feet.

In conclusion, we can solve for the pillar's height by establishing a ratio between the building's height and the length of its shadow and applying that ratio to the pillar.

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which equation represents the relationship show in the graph?

Answers

let's firstly get the EQUATion, of the graph before we get the inequality.

so we have a quadratic with two zeros, at -6 and 8, hmmm and we also know that it passes through (-2 , 10)

[tex]\begin{cases} x = -6 &\implies x +6=0\\ x = 8 &\implies x -8=0\\ \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{original~polynomial}{a ( x +6 )( x -8 ) = \stackrel{0}{y}}\hspace{5em}\textit{we also know that } \begin{cases} x=-2\\ y=10 \end{cases}[/tex]

[tex]a ( -2 +6 )( -2 -8 ) = 10\implies a(4)(-10)=10\implies -40a=10 \\\\\\ a=\cfrac{10}{-40}\implies a=-\cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{1}{4}(x+6)(x-8)=y\implies -\cfrac{1}{4}(x^2-2x-48)=y \\\\\\ ~\hfill {\Large \begin{array}{llll} -\cfrac{x^2}{4}+\cfrac{x}{2}+12=y \end{array}}~\hfill[/tex]

now, hmmm let's notice something, the line of the graph is a solid line, that means the borderline is included in the inequality, so we'll have either ⩾ or ⩽.

so hmmm we could do a true/false region check by choosing a point and shade accordingly, or we can just settle with that, since the bottom is shaded, we're looking at "less than or equal" type, or namely ⩽, so that's our inequality

[tex]{\Large \begin{array}{llll} -\cfrac{x^2}{4}+\cfrac{x}{2}+12\geqslant y \end{array}}[/tex]

Is W a subspace of the vector space? If not, state why. (Select all that apply.) W is the set of all vectors in R whose components are Pythagorean triples. (Assume all components of a Pythagorean triple are positive integers.) O W is a subspace of R3. W is not a subspace of R because it is not closed under addition W is not a subspace of R because it is not closed under scalar multiplication

Answers

No, W is not a subspace of R3 because it is not closed under vector addition and scalar multiplication, even though it contains the zero vector.

A set must meet three requirements to be a subspace of a vector space: (1) it must include the zero vector, (2) it must be closed under vector addition, and (3) it must be closed under scalar multiplication.

While W includes the zero vector (0, 0, 0), vector addition does not close it. For example, the triples (3, 4, 5) and (5, 12, 13) are both Pythagorean, but their addition (8, 16, 18) is not. As a result, W does not meet the second requirement and is not a subspace of R3.

Under scalar multiplication, W is likewise not closed. When we multiply the Pythagorean triple (3, 4, 5) by -1, we obtain (-3, -4, -5), which is not a Pythagorean triple. Therefore, W does not satisfy the third condition and is not a subspace of R.

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Write the transformation matrix and the resultant matrix that will translate the triangle, (-2, 4), given the triangles vertices are at A(-1, 3), B(0, -4) and C(3, 3).

Answers

The resultant matrix represents the vertices of the translated triangle, with A' at (-3, 7), B' at (-2, 0), and C' at (1, 7).

Define the term transformation matrix?

A transformation matrix is a mathematical matrix that represents a geometric transformation of space.

To translate the triangle by (-2, 4), we need to add -2 to the x-coordinates and add 4 to the y-coordinates of each vertex. The transformation matrix for this translation is:

[tex]\left[\begin{array}{ccc}1&0&-2\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}0&1&4\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}0&0&1\end{array}\right][/tex]

To apply this transformation to the vertices of the triangle, we can represent each vertex as a column vector with a third coordinate of 1:

[tex]A=\left[\begin{array}{ccc}-1&3&1\end{array}\right][/tex]

[tex]B=\left[\begin{array}{ccc}0&-4&1\end{array}\right][/tex]

[tex]C=\left[\begin{array}{ccc}3&3&1\end{array}\right][/tex]

To apply the translation, we multiply each vertex by the transformation matrix:

[tex]A'=\left[\begin{array}{ccc}1&0&-2\end{array}\right] \left[\begin{array}{ccc}-1&3&1\end{array}\right] \left[\begin{array}{ccc}-3&7&1\end{array}\right][/tex]

      [0 1  4] × [ 0 -4  1] = [-2  0  1]

      [0 0  1]   [ 1  3  1]   [-1  7  1]

[tex]B'=\left[\begin{array}{ccc}1&0&-2\end{array}\right] \left[\begin{array}{ccc}0&-4&1\end{array}\right] \left[\begin{array}{ccc}-2&-4&1\end{array}\right][/tex]

      [0 1  4] × [ 0 -4  1] = [-2   0  1]

      [0 0  1]   [ 0  3  1]   [-2   7  1]

[tex]C'=\left[\begin{array}{ccc}1&0&-2\end{array}\right] \left[\begin{array}{ccc}3&3&1\end{array}\right] \left[\begin{array}{ccc}1&7&1\end{array}\right][/tex]

      [0 1  4] × [ 3  3  1] = [ 1  7  1]

      [0 0  1]   [ 3  3  1]   [ 1  7  1]

The resultant matrix represents the vertices of the translated triangle, with A' at (-3, 7), B' at (-2, 0), and C' at (1, 7).

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a faulty watch gains 10 seconds an hour if it is correctly set to 8 p.m. one evening what time will it show when the correct time is 8 p.m. the following evening​

Answers

The watch gains 4 min till 8:00 PM in the next evening and show 8:04 pm the next evening.

What does it gain?

Considering that,

A broken watch adds ten seconds per hour.

Find the number of hours between 8:00 PM this evening and 8:00 PM the following evening.

There are 24 hours in a day.

number of seconds the defective watch gained.

1 hour equals 10 seconds

24 hours ÷ by 10

24 * 10 is 240 seconds.

Now figure out how many minutes your defective watch has gained.

60 s = 1 minute

240 sec = 240/60

= 4 min

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Missing parts;

A faulty watch gains 10 seconds an hour. If it is set correctly at 8:00 pm one evening, what time will it show when the correct time is 8:00 pm the following evening

Let adj A 1 2 1 where adj A is the adjugate of matrix A, 1 1 2 with det A >0 and AX = A + X. Find det A and matrix X.

Answers

det(A) = ad - bc.

Matrix X is X = [8/5 -6/5, -2, 2/5 2/5]

What method is used to calculate det A and matrix X?

We know that the adjugate of a 2x2 matrix is:

adj(A) = [d -b, -c a]

A = [a b, c d]

det(A) = ad - bc.

So, from the given adj(A), we have:

d - b = 1

-c = 2

-a = 1

d - c = 1

We have c = -2. Then, from the fourth equation, we have d = 1 - c = 3. Substituting these values into the first and third equations, we get:

b = 2

a = -1

So, the matrix A is:

A = [-1 2, -2 3]

We are given that AX = A + X. Substituting the matrix A and simplifying, we get:

AX = A + X

=> A(X - I) = X - A

=> (X - I)(-A) = X - A

=> X - I = (-A)⁻¹ (X - A)

=> X - I = A⁻¹ (X - A)

=> X = A⁻¹ X - A⁻¹ A + I

=> X = A⁻¹ (X - A) + I

Since we know A, we can find its inverse:

A⁻¹ = 1/(ad - bc) [d -b, -c a] = 1/5 [3 -2, 2 -1]

Substituting this into the above equation, we get:

X = 1/5 [3 -2, 2 -1] (X - [-1 2, -2 3]) + I

Simplifying this, we get:

X = 1/5 [4X + 5, -6X - 10, -2X - 10, 3X + 5]

Equating the corresponding elements on both sides, we get the following system of equations:

4x + 5 = x

-6x - 10 = 2

-2x - 10 = 1

3x + 5 = 3

Solving this system of equations, we get:

x = -1

Therefore, det(A) = ad - bc = (-1)(3) - (2)(-2) = -1 + 4 = 3.

And, matrix X is:

X = [8/5 -6/5, -2, 2/5 2/5]

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consider a wave form s(t)=5 sin 10 π t 2 sin 12 π t. the signal s(t) is sampled at 10 hz. do you expect to see aliasing? select true if the answer is yes or false otherwise.

Answers

The statement "consider a wave form s(t)=5 sin 10 π t 2 sin 12 π t. the signal s(t) is sampled at 10 hz. do you expect to see aliasing" is true because aliasing is expected.

When sampling a signal s(t) = 5 sin(10πt) * 2 sin(12πt) at 10 Hz, you can expect to see aliasing. The Nyquist sampling theorem states that a signal should be sampled at least twice the highest frequency present in the signal to avoid aliasing.

The two sinusoids in s(t) have frequencies of 5 Hz (10πt) and 6 Hz (12πt). The highest frequency is 6 Hz, so according to the Nyquist theorem, the signal should be sampled at least at 12 Hz (2 times the highest frequency) to avoid aliasing. Since the signal is sampled at 10 Hz, which is lower than the required 12 Hz, aliasing will occur.

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You want to buy a new cell phone. The sale price is $149
. The sign says that this is $35
less than the original cost. What is the original cost of the phone?

Answers

Answer:

In this problem it is saying that it is $35 less than the original cost so to find this you need to add. This should be just $149 + $35 to solve it which is a total of $184 which is the original cost for the phone.

$184 is your answer

Step-by-step explanation:

$114

as the question says the price is $35 less than the original cost, which means 149-35 which equal 144.

Right triangle ABC is inscribed in circle E. Find the area of the shaded region. Round your answer to the nearest tenth if necessary. C 8 A 15 E B​

Answers

To find the area of the shaded region, we need to find the area of triangle ABC and subtract the area of sector AEC.

First, we can use the Pythagorean theorem to find the length of side BC:

BC^2 = AB^2 - AC^2
BC^2 = 15^2 - 8^2
BC^2 = 169
BC = 13

Now we can find the area of triangle ABC using the formula:

area = (1/2) * base * height
area = (1/2) * 15 * 8
area = 60

To find the area of sector AEC, we need to find the measure of angle AEC. Since triangle ABC is inscribed in circle E, we know that angle AEC is a central angle that intercepts arc AC. The measure of angle AEC is therefore equal to half the measure of arc AC.

The circumference of circle E is 2πr, where r is the radius. Since triangle ABC is inscribed in circle E, the diameter of circle E is equal to side AC. The radius of circle E is therefore half the length of AC:

r = (1/2) * AC
r = (1/2) * 15
r = 7.5

The circumference of circle E is 2πr:

circumference = 2πr
circumference = 2π(7.5)
circumference = 15π

Since arc AC is one-third of the circumference of circle E, its measure is:

arc AC = (1/3) * circumference
arc AC = (1/3) * 15π
arc AC = 5π

The measure of angle AEC is therefore:

angle AEC = (1/2) * arc AC
angle AEC = (1/2) * 5π
angle AEC = (5/2)π

To find the area of sector AEC, we can use the formula:

area = (1/2) * r^2 * θ
area = (1/2) * 7.5^2 * (5/2)π
area = (1/2) * 56.25 * 2.5π
area = 70.3125π

Finally, we can find the area of the shaded region by subtracting the area of sector
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