Find the volume of the box.
3 ft
4 ft
5 ft
The volume of the box is
cubic feet________

Answer:

Multiply

1/3

Step-by-step explanation:

You can divide by 3 or multiply by 1/3. Since it looks like 3 is grayed out, I guess you have to use the latter.

Answer:

its -4.5??? what is the question you're asking

[tex]\sf\purple{0.5}[/tex] ✅

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] \frac{50}{100} \\ = \frac{1}{2} \\ = 0.5[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]

Answer:

$1140 or $540

Step-by-step explanation:

450*1.2=540

540+600=1140

Answer:

a) The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b) The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c) The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d) The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

Standard error:

The standard error is:

[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

Margin of error:

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}} = zs[/tex]

The confidence interval is:

Sample proportion plus/minus margin of error. So

[tex](\pi - M, \pi + M)[/tex]

In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.

This means that [tex]n = 1500, \pi = \frac{1305}{1500} = 0.87[/tex]

a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?

[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}} = \sqrt{\frac{0.87*0.13}{1500}} = 0.0087[/tex]

0.0087*100% = 0.87%.

The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

Then

[tex]M = zs = 1.96*0.0087 = 0.0171[/tex]

0.0171*100% = 1.71%

The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.

87% - 1.71% = 85.29%

87% + 1.71% = 88.71%.

The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.

The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

Answer:

I need a picture to see what it represents.

Answer:

The average speed of the 747 was of 580 miles per hour.

Step-by-step explanation:

We use the following relation to solve this question:

[tex]v = \frac{d}{t}[/tex]

In which v is the velocity, d is the distance and t is the time.

A small airplane flies 1015 miles with an average speed of 290 miles per hour.

We have to find the time:

[tex]v = \frac{d}{t}[/tex]

[tex]290 = \frac{1015}{t}[/tex]

[tex]290t = 1015[/tex]

[tex]t = \frac{1015}{290}[/tex]

[tex]t = 3.5[/tex]

1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;

The time of the Boeing 747 is:

[tex]t = 3.5 - 1.75 = 1.75[/tex]

Distance of [tex]d = 1015[/tex], the velocity is:

[tex]v = \frac{d}{t} = \frac{1015}{1.75} = 580[/tex]

The average speed of the 747 was of 580 miles per hour.

Answer:

y = 5 sin (2x) + 4

Step-by-step explanation:

this is sines function,

the amplitude is [9 - (-1)]/2 = 10/2 = 5

the period is 2πx/π = 2x

the x-axis of actual function is at y = 4

so, the function is :

y = 5 sin (2x) + 4

Answer:

50 yard South, 40 yard east 60 yard northwest

9514 1404 393

Answer:

  A = 49π/36 or 59π/36

Step-by-step explanation:

The given angle is coterminal with the same angle modulo 2π.

  (563/36)π = 14π +(59/36)π

so the coterminal angle is 59π/36 ≈ 1.6389π, a 4th-quadrant angle. The 3rd-quadrant angle with the same sine value is found by subtracting this angle from 3π:

  A = 3π -(59π/36) = 49π/36

The two values of A that satisfy the equation are ...

_____

In degrees, the two angles are 245° and 295°.

Answer:

0.0344 = 3.44% probability that a newborn pup has a weight above 24.0 lbs.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 22.0 lbs and standard deviation of 1.1 lbs.

This means that [tex]\mu = 22, \sigma = 1.1[/tex]

Find the probability that a newborn pup has a weight above 24.0 lbs.

This is 1 subtracted by the p-value of Z when X = 24. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{24 - 22}{1.1}[/tex]

[tex]Z = 1.82[/tex]

[tex]Z = 1.82[/tex] has a p-value of 0.9656.

1 - 0.9656 = 0.0344

0.0344 = 3.44% probability that a newborn pup has a weight above 24.0 lbs.

Answer:

20 is the father's 20 is the son

Step-by-step explanation:

20+20=40

40/2=20

40-20=20

another way:

20:n= 40

40-20=20

20:20=40

Answer:

Step-by-step explanation:

let the age of son be x

x+x+20=40

2x=40-20

x=20/2

x=10

since age of a father is 20 more than his son's so,

x+20=father's age

10+20

30

therefore fathers age is thirty years and son age is 10 years

Answer:

y = 0.47

x = 0.91

Step-by-step explanation:

From the right angled triangle Given :

Applying trigonometry :

To Obtain y :

We use :

Tan θ = opposite / hypotenus

Tan 25 = y / 1

y = 1 * tan 25

y = 0.4663076 * 1

y = 0.47

For x :

We use :

Cosθ = adjacent / hypotenus

Cos 25 = x / 1

0.9063077 = x / 1

x = 0.9063077 * 1

x = 0.9063077

Hence, x = 0.91

Answer:

2 doctors to 9 patients

Step-by-step explanation:

Divide each by 3. They cant be simplified more.

Answer:

Therefore WE accept the Null hypothesis [tex]H_0[/tex] That 50.0% versus 52.4%.difference is real

Step-by-step explanation:

Sample size A [tex]n_a=100[/tex]

Sample size B [tex]n_b=250[/tex]

Positive draw from box A [tex]n_a=50[/tex]

Positive draw from box b [tex]n_b=131[/tex]

Generally the equation for Probability of Positive draw from Box A is mathematically given by

 [tex]P_1=\frac{50}{100}[/tex]

 [tex]P_1=50%[/tex]

Therefore

 [tex]1-P_1=50\%[/tex]

Generally the equation for Probability of Positive draw from Box A is mathematically given by

 [tex]P_1=\frac{131}{250}[/tex]

 [tex]P_1=52.4%[/tex]

Therefore

 [tex]1-P_1=47.6\%[/tex]

Generally the equation for Standard error S.E is mathematically given by

 [tex]S.E=\sqrt{\frac{n_1(p_1)*(1-P_1)}{n_1^2}+\frac{n_2(P_2(1-p^2))}{n_2^2}}[/tex]

 [tex]S.E=\sqrt{\frac{100(0.50)*(50)}{100^2}+\frac{(250)(0.524(47))}{250^2}}[/tex]

 [tex]S.E=0.592[/tex]

 [tex]S.E=59.2\%[/tex]

Therefore

 [tex]Z=\frac{50-52.4}{59.2}[/tex]

Generally

 [tex]P value P>0.05[/tex]

Therefore WE accept the Null hypothesis [tex]H_0[/tex] That 50.0% versus 52.4%.difference is real

Answer:

your awnser would be [4, −6]

Step-by-step explanation:

hope this helps

Answer:

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

1. Let x represent the number of apples left. Then the number of mangosteens left is 1/6x. The starting number in each case is the number left plus the number sold. The starting numbers are equal, so we have ...

  x + 201 = (1/6)x +366

  5/6x = 165 . . . . . . . . . . subtract 1/6x+201

  x = 198 . . . . . . . . multiply by 6/5

198 apples were left.

__

2. Let d represent the cost of a drink. The cost of a drink is 3/5 the cost of a snack, so the cost of a snack is 5/3 the cost of a drink. Then Alice's total expenditure was ...

  15d +12(5/3d) = 42

  35d = 42 . . . . . . . . . . . . . . collect terms

  d = 42/35 = 6/5 = 1.20 . . . divide by 35

The cost of a drink was $1.20.

Answer:

5.25

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

Answer:

[tex]0.4138[/tex]

Step-by-step explanation:

Given

[tex]x \to storm[/tex]

[tex]\mu_x = 1.0[/tex]

[tex]y \to fire[/tex]

[tex]\mu_y = 1.5[/tex]

[tex]z \to theft[/tex]

[tex]\mu_z = 2.4[/tex]

Let the event that the above three factors is greater than 3 be represented as:

[tex]P(A > 3)[/tex]

Using complement rule, we have:

[tex]P(A > 3) = 1 - P(A \le 3)[/tex]

This gives:

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

-----------------------------------------------------------------------------------------------------------

The exponential distribution formula of each is:

[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]

So, we have:

[tex]k = 3; \mu_x = 1[/tex]

[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]

[tex]k=3; \mu_y = 1.5[/tex]

[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]

[tex]k = 3; \mu_z = 2.4[/tex]

[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]

-----------------------------------------------------------------------------------------------------------

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]

[tex]P(A > 3) = 1 - 0.5862[/tex]

[tex]P(A > 3) = 0.4138[/tex]

Answer:

22×2/5=8.8

Step-by-step explanation:

Hope it helps you

Answer:

55

Step-by-step explanation:

2/5n = 22

multiply each side by 5/2 to get:

n = 110/2

n = 55

Answer:

A: 1 solution: the lines intersect at one point

B: (3,4), reference graph for solution

Step-by-step explanation:

A: solutions are equivalent to how many intersections two lines have, and we can see that these lines intersect once and won't intersect again

B: luckily the intersection point is super easy to plot, so we can just reference the graph for our solution!

Answer:

You never attached anything so ill just say the answer is 4

Step-by-step explanation:

If you want a serious answer please edit your question so it is answerable.

:) Have a good day

Answer: 4

Step-by-step explanation:

I got this same question buddy im here to see the answer but there were not any

Answer:

Option D would be the correct answer!

Hope this helps!