Explanation:
given Time Period = 5 Sec
Amplitude = 1m, Wave length = 15 m
using time period = 1/ frequency , Frequency = 1/5 cycles per sec = 0.2 sec = 12 per min
wave speed= Frequency * Wave length
speed = 0.2*15 = 3m/s
5. Alex worked out for 4 hours and lost 3 lbs. during that time. What is the range of water that he should drink in ounces after his workout?
9 ounces bc if he does then he wont be so like ugh I'm out of wonder land yeah 9 ounces deffo
Lisa made the electromagnet shown. A nail with wire coiled around it has its head labeled S to the right and its point labeled N to the left. The end of the wire leading to the S is attached to the positive terminal of a battery. The end of the wire leading to the N is attached to the negative terminal of the battery. What can Lisa do to increase the strength of the electromagnet? She can use a nail with weaker magnetic properties. She can change the direction of the nail. She can increase the number of wire loops. She can reduce the current in the wire.
Answer:
C. She can increase the number of wire loops.
Explanation:
The more wire loops the more energy.
For a coil of wire, the magnetic field strength is increased by increasing the number of coils around the nail.
What is electromagnet?An electromagnet is a soft metal core shaped into a magnet by the passing the electric current through a coil surrounding it.
The end of the wire leading to the S is attached to the positive terminal of a battery. The end of the wire leading to the N is attached to the negative terminal of the battery. The current begins to flow. Current cant be changed to increase magnetic field strength, but the no of coils will definitely increase it.
Thus, To increase the strength of the electromagnet, Lisa can increase the number of wire loops.
Learn more about electromagnet.
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A solid cylinder has a mass of 5 kg and radius of 2 m and is fixed so that it is able to rotate freely around its center without friction. A 0.02 kg bullet is moving from right to left with an angular momentum of 9 kgm2s just before it strikes the cylinder near its bottom and gets stuck at the outer radius. What is the angular velocity (magnitude and direction) of the cylinder bullet system after the impact
Answer:
0.893 rad/s in the clockwise direction
Explanation:
From the law of conservation of angular momentum,
angular momentum before impact = angular momentum after impact
L₁ = L₂
L₁ = angular momentum of bullet = + 9 kgm²/s (it is positive since the bullet tends to rotate in a clockwise direction from left to right)
L₂ = angular momentum of cylinder and angular momentum of bullet after collision.
L₂ = (I₁ + I₂)ω where I₁ = rotational inertia of cylinder = 1/2MR² where M = mass of cylinder = 5 kg and R = radius of cylinder = 2 m, I₂ = rotational inertia of bullet about axis of cylinder after collision = mR² where m = mass of bullet = 0.02 kg and R = radius of cylinder = 2m and ω = angular velocity of system after collision
So,
L₁ = L₂
L₁ = (I₁ + I₂)ω
ω = L₁/(I₁ + I₂)
ω = L₁/(1/2MR² + mR²)
ω = L₁/(1/2M + m)R²
substituting the values of the variables into the equation, we have
ω = L₁/(1/2M + m)R²
ω = + 9 kgm²/s/(1/2 × 5 kg + 0.02 kg)(2 m)²
ω = + 9 kgm²/s/(2.5 kg + 0.02 kg)(4 m²)
ω = + 9 kgm²/s/(2.52 kg)(4 m²)
ω = +9 kgm²/s/10.08 kgm²
ω = + 0.893 rad/s
The angular velocity of the cylinder bullet system is 0.893 rad/s in the clockwise direction-since it is positive.
Who's Madame Marie curie?
Explanation:
In 1911, Marie was awarded a second Nobel Prize in Chemistry for her discovery of the elements polonium and radium. In honor of the 100-year anniversary of her Nobel award, 2011 was declared the "International Year of Chemistry."
Electrical current is the flow of ____________
A) helium
B) protons
C) atoms
D) electrons
How much voltage is required to make 0.56 A flow through a 72-ohm resistance? [V = I x R]
A)48 V
B)36 V
C)40 V
D)52 V
WILL GIVE BRAINLIEST!!!
Solution :
A) Electric current is the flow of electrons .
B) We know, by ohm's law :
V = I × R
Putting given values in above equation, we get :
V = 0.56 × 72 V
V = 40.32 V
Hence, this is the required solution.
show the relation between degree Celsius and degree fahrenheit??
I hope you understand....
pls help will mark brainliest, pls
Answer:
The answer is true. This is correct.
One twin sets off on a long space voyage traveling at 0.9 c, while the other stays on Earth. When she returns 60 years later, the traveling sister has hardly aged at all, while her twin has aged 60 years. Which aspect of relativity is demonstrated in this situation
Answer:
This is the twin paradox.
what are the four importance of apron?
Answer:
To prevent our clothes from dust, dirt, spills and debris during cooking, serving, cleaning or performing a creative task. Aprons protect your clothes and acts as a protective barrier.
An object of mass m slides down an incline with angle 0.
Which expression
shows the net force on the object along the surface of the incline?
A. mg cos(0) - FN
B. mg cos(0)
C. mg sin(0)
D. mg sin(0) - FN
Answer:
C. mg sin(θ)
Explanation:
The plane is incline and the only force acting in the object is the gravity, so you multiply mg per sin(θ) because sin(θ) gave you the part of the gravity acting in the horizontal direction parallel with the inclined surface
The expression shows the net force on the object along the surface of the incline is mg sin(θ). The correct option is C.
What is Net force?When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
An object of mass m slides down an incline with angle (θ).
The plane is incline and the only force acting in the object is the gravity, The weight or gravity acting in the horizontal direction parallel with the inclined surface is mg sin(θ).
Thus, the correct option is C.
Learn more about net force.
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Whenever an object exerts a force on another object, the second object exerts a force o the same amount, but in the ______ direction to that of the first object. (Fill in the blank)
Answer:
Opposite
Explanation:
Newton's third law of motion states that for every action there is an equal but opposite reaction.
Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move etc,
For example, while driving down the road, a firefly strikes the windshield of a car (Action) and makes a quite obvious mess in front of the face of the driver (Reaction) i.e the firefly hit the car and the car hits the firefly.
The ultimately implies that, in every interaction, there is a pair of equal but opposite forces acting on the two interacting physical objects.
Hence, whenever any physical object exerts a force (action) on another physical object, the second physical object exerts a force (reaction) of the same amount, but acting in opposite direction to that of the first physical object.
Cart A with a mass equal to 24 kg is moving to the right at 3.2 m/s. It collides with Cart B that
has a mass of 32 kg and is moving to the left with a velocity of 12.8 m/s. After the collision,
Cart A has a velocity of 2.9 meters per second to the left. What is the speed of the Cart B after
the collision?
Answer:
Explanation:
According to the Law of Momentum Conservation, what happens after the collision has to equal what happened before the collision because momentum cannot be created nor destroyed; it has to go somewhere else. Like energy eventually dissipates into heat. The equation for this is:
[tex][m_Av_A+m_Bv_B)]_b=[(m_Av_A+m_Bv_B)]_a[/tex] and filling in our info, calling right positive and left negative:
[(24(3.2) + 32(-12.8)] = [(24(-2.9) + 32(vB)] and
[(77 - 410)] = [(-7.0 × 10¹ + 32vB)] and
-330 = -7.0 × 10¹ + 32vB and
-260 = 32vB so
vB = -8.1 m/s Thus, cart B is moving to the left at a velocity of 8.1 m/s
(I used the rules for sig dig very intentionally and correctly; I'm not sure how strict your teacher is about them. I require my students to use the rules to perfection, as I did here.)
Calculate the potential energy stored in an object of mass 50 kg at a height of 20 m from the
ground.
(g=10 m/s2)
Answer:
potential energy=mgh
=50×10×20
=10000 J
A 4kg and 5kg bodies moving on a frictionless horizontal surface at a velocity of ( -6i )m/s and ( +3 )m/s respectively. Collide a head on elastic collision. What is the velocity ( magnitude and direction) of the each body after collision?
Answer:
4 kg → +4 m/s
5 kg → -5 m/s
Explanation:
The law of conservation of momentum states that:
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'left side → velocities before collisionright side → velocities after collisionYou'll notice that we have two missing variables: v₁' & v₂'. Assuming this is a perfectly elastic collision, we can use the conservation of kinetic energy to set the initial and final velocities of the individual bodies equal to each other.
v₁ + v₁' = v₂ + v₂'Let's substitute all known variables into the first equation.
(4)(-6) + (5)(3) = (4)v₁' + (5)v₂' -24 + 15 = 4v₁' + 5v₂' -9 = 4v₁' + 5v₂'Let's substitute the known variables into the second equation.
(-6) + v₁' = (3) + v₂' -9 = -v₁' + v₂' 9 = v₁' - v₂'Now we have a system of equations where we can solve for v₁ and v₂.
-9 = 4v₁' + 5v₂' 9 = v₁' - v₂'Use the elimination method and multiply the bottom equation by -4.
-9 = 4v₁' + 5v₂' -36 = -4v₁' + 4v₂'Add the equations together.
-45 = 9v₂'-5 = v₂'The final velocity of the second body (5 kg) is -5 m/s. Substitute this value into one of the equations in the system to find v₁.
9 = v₁' - v₂'9 = v₁' - (-5) 9 = v₁' + 5 4 = v₁'The final velocity of the first body (4 kg) is 4 m/s.
We can verify our answer by making sure that the law of conservation of momentum is followed.
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' (4)(-6) + (5)(3) = (4)(4) + (5)(-5)-24 + 15 = 16 - 25 -9 = -9The combined momentum of the bodies before the collision is equal to the combined momentum of the bodies after the collision. [✓]
When the sun and moon work together ____________ are formed on Earth.
a
Frankentides
b
Neap Tides
c
Spring Tides
d
Dark Tides
Answer:
C. Spring Tides is the answer.
In a longitudinal wave, amplitude can be measured from the distance between high pressure areas of the wave called what?
Answer:
The high pressure areas in a longitudinal wave are called compressions.
Lake is home to a large number of trout. Identify what is most likely to happen if a chemical is dumped into the lake. It is a science question
Answer:
The correct option is C) III. That is, the trout will suffer from disease.
Explanation:
Note: This question is not complete as the options are not included. The complete question with the options is therefore provided before answering the question as follows:
A lake is home to a large number of trout. Identify what is most likely to happen if a chemical is dumped into the lake.
I. The trout will not be affected by the pollution.
II. The number of trout will increase.
III. The trout will suffer from disease.
A) I
B) I and II
C) III
D) II and III
The explanation of the answer is now provided as follows:
Natural selection is the process that took place in the lake. Only those trouts that were fit to survive, or those that have alleles that allow them adapt to new conditions, live and multiply in the presence of an external environmental effect like pollution. In such a circumstance, the fittest organisms would have survived, and the population's allelic frequency would have grown through time. Due to pollution, creatures harboring the other alleles died, causing the total frequency of alleles to alter.
Therefore, the correct option is C) III. That is, the trout will suffer from disease.
Particles of light are known as A. electrons. B. neutrinos. C. photons. D. bosons.
Answer:
C. photons
hope this helps
have a good day :)
Explanation:
Answer:
The answer would be c
Explanation:
How is the annostructure on the chocolate related to the nanostructure of the grating?
help me plss:(
Answer:
From butter in croissants to cocoa solids in chocolate, edible fats pack a flavor punch that delights like no other macronutrient we consume. Fats are the most energy dense macronutrients, providing more than twice as many kilocalories per gram as proteins or carbohydrates, which may be the reason we've developed a taste for them.
Explanation:
Describe how to determine the thickness of a sheet of a paper without a caliper.
Answer:
Divide the total measurement of the stack/ream of paper by the number of sheets. For example: 2 inches/100 pages = 0.01-inches sheets.
In case you measured the stack, and it gave you less than an inch, then you need to do the same. For example: 0.5-inches/100 sheets = 0.005-inches per sheet.
Answer:
Divide the total measurement of the stack/ream of paper by the number of sheets. For example: 2 inches/100 pages = 0.01-inches sheets.
In case you measured the stack, and it gave you less than an inch, then you need to do the same. For example: 0.5-inches/100 sheets = 0.005-inches per sheet.
Explanation:
Determine the small gravitational force F which the copper sphere exerts on the steel sphere. Both spheres are homogeneous, and the value of r is 50 mm. Express your result as a vector.
Solution :
We know that the volume of sphere is given by :
[tex]$V=\frac{4}{3}\pi r ^3$[/tex]
Given r = 50 mm
The density of copper is :
[tex]$\rho_c = 8910 \ kg/m^3$[/tex]
The density of steel is :
[tex]$\rho_s = 7830\ kg/m^3$[/tex]
Therefore, mass of copper is :
[tex]$m_c= V . \rho$[/tex]
[tex]$m_c= \frac{4}{3} \pi (0.05)^3 \times 8910$[/tex]
= 4.665 kg
= 4665 g
Similarly, mass of steel is :
[tex]$m_s= V . \rho$[/tex]
[tex]$m_s= \frac{4}{3} \pi (0.025)^3 \times 7830$[/tex]
= 0.512 kg
= 512 g
Now the distance between the centers of the particles is by Pythagoras theorem,
[tex]$l^2=(4r)^2+(2r)^2$[/tex]
l = 4.472 x r
= 4.472 x 50
= 224 mm
= 0.224 m
From the law of gravitation,
We know, [tex]G = 6673 \times 10^{-11} \ m^3 / kg-s^2[/tex]
∴ [tex]$F=G\times \frac{m_c \times m_s}{l^2}$[/tex]
[tex]$F=6.673 \times 10^{-11}\times \frac{4.665 \times 0.512}{(0.224)^2}$[/tex]
[tex]$F = 3.176 \times 10^{-9} \ N$[/tex]
Now,
[tex]$\alpha = \tan^{-1} \left( \frac{2r}{4r}\right)$[/tex]
= [tex]$26.56^\circ$[/tex]
Therefore, we can write it in the vector form as
[tex]$\text{F}=F(-i . \cos \alpha - j. \sin \alpha)$[/tex]
[tex]$\text{F}=3.176 \times 10^{-9}(-i . \cos 26.56 - j. \sin 26.56)$[/tex]
[tex]$\text{F}=(-2.840\ i- 1.420 \ j) \times 10^{-9} \ N$[/tex]
How much larger is the diameter of Jupiter compared to the diameter of Saturn?
If you stood on Mars and lifted a 15kg pack,you would be pulling with a force greater than...
Answer: See answers below.
Explanation: In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
Choices:
A. Most kinetic energy and least potential energy
B. Most potential energy and least kinetic energy
C. Potential energy is equal to kinetic energy
D. Potential energy is increasing
E. Potential energy is decreasing
F. Kinetic energy is increasing
G. Kinetic energy is decreasing
Directions: Write one letter from the choices above in each of the spaces.
1. When the minion hits the ball at position one, what choices best describe the energy present. (choose 3)
___________, ___________, _____________
2. Position 2 (choose 2) ____________, ___________
3. Position 3 (choose 3) _____________, ____________, ______________
4. Position 4 (choose 2) ______________, _____________
5. Position 5 (choose 2) ______________, _____________
6. Positions 6 (right when the ball is about to touch the ground ___________, ____________, _____________
Answer:
I think there's a pdf for the questions you need
WorksheetKineticVsPotentialEnergy.pdf
Explanation:
When storm clouds produce lighting and thunder, what kind of energy is produced?
Answer:
Static Electricity
Explanation:
I think this is what your asking
Light travels through space at a speed of 3.0 x 108 m/s. A space probe is
traveling toward Earth at 2.5 * 108 m/s when one of its spotlights is turned
on. What speed would an observer on Earth measure for the light from the
spotlight?
O A. 2.5 * 108 m/s
O B. 3.0 x 108 m/s
O c. 5.5 x 108 m/s
O D. 0.5 x 108 m/s
Explanation:
The answer is (B). The speed of light is the same for all observers regardless of their motion relative to the light source.
The speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
The given data in the problem is;
The speed of light is, [tex]\rm C =3 \times 10^8\ m/sec[/tex]
All frames of reference have the same speed of light in a vacuum. Therefore the speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
Hence option B is correct.
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Which statement best describes the Sun Earth-Moon system?
Answer:
A
Explanation:
A. The Moon orbits the Earth, and the Earth-Moon system orbits the Sun
B. The Earth and Moon both orbit the Sun separately
C. The Sun orbits the Earth-Moon system
D. The Moon revolves around Earth but not the Sun
Physicist ____ was found to have completely made up some of the data on which his astounding discoveries were made.
Answer:
Jan Hendrik Schön I believe
PLEASE HELP 40 POINTS
Liar, not even 40 points....
In the fastest measured tennis serve, the ball left the racquet at 73.14 m/s . A served tennis ball is typically in contact with the racquet for 32.0 ms and starts from rest. The direction of the velocity of the ball just after it left the racquet is the positive x direction. Assume constant acceleration. Part A What was the x component of the ball's acceleration during this serve
Answer:
2.286 km/s²
Explanation:
Since acceleration a = (v - u)/t where u = initial horizontal velocity of ball = 0 m/s (since it starts from rest), v = final horizontal velocity of ball at serve = 73.14 m/s and t = time taken for serve = 32.0 ms = 0.032 s
Substituting the values of the variables into the equation, we have
a = (v - u)/t
a = (73.14 m/s - 0 m/s)/0.032 s
a = 73.14 m/s/0.032 s
a = 2285.625 m/s²
a = 2.285625 km/s²
a ≅ 2.286 km/s²
So, the x - component of the ball's acceleration during the serve is 2.286 km/s²