At constant pressure, the volume of a gas is directly proportional to temperature as measured on the __ temperature scale.

Answer: 0.01 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(26.1)(0.505)=(1950)M_{B}\\M_{B}=\frac{(26.1)(0.505)}{1950} \approx \boxed{0.01 \text{ M}}[/tex]

Answer:

A chemical property example is fire.

Explanation:

Hope this helps!

Answer:

dipole-induced dipole forces

Explanation:

KI(aq) has potassium and iodine ions in water. Water is a polar molecule. So the type of force must be ion-dipole.

Answer:

Explanation:

Applying Boyle's Law :

Q1

Q2

The moles of unknown weak acid (HA) in a 100L solution are required to produce a solution with pH 2 is 0.002 moles.

The acid dissociation constant of an acid is given by the formula below:

[tex]K_a= \frac{[A^{-}][H_3O^{-}]}{[HA]}[/tex]

Where

Since, the Ka is given at equilibrium concentrations, [H3O+] = [A-]

[A-] = 10^-2

Making [HA] subject of the formula:

[tex][HA]= \frac{[10^{-2}][10^{-2}]}{5 \times 10^{ - 3} } = 0.02[/tex]

Moles of acid = 0.1 × 0.02 = 0.002 moles

Therefore, the moles of unknown weak acid (HA) in a 100L solution are required to produce a solution with pH 2 is 0.002 moles.

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Taking into account definition of percent yield, the percent yield for the reaction is 82.56%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield= \frac{actual yield}{theorical yield}x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

Replacing in the definition of percent yields:

[tex]percent yield= \frac{0.71 g}{0.86 g}x100[/tex]

Solving:

percent yield= 82.56%

Finally, the percent yield for the reaction is 82.56%.

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125 g/mol is the molar mass of unknown gas. Hence, option C is correct.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 2 atm

V= 15 L

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=300 K

Putting value in the given equation:

[tex]\frac{PV}{RT}[/tex]=n

n= [tex]\frac{2 \;atm\; X \;15 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 300}[/tex]

Moles = 1.21866 moles

Now,

Moles =[tex]\frac{mass}{molar \;mass}[/tex]

1.21866 =[tex]\frac{153 g}{molar \;mass}[/tex]

Molar mass= 125.54 mole/gram

125 g/mol is the molar mass of unknown gas. Hence, option C is correct.

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The increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.

The equilibrium of the gas is based on the pressure of the gas. With the increase in pressure, the equilibrium moves towards making fewer molecules of gas.

The gas equilibrium is proportional to the equilibrium K.

Increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.

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Answer:

1.) Anaphase ------> D.) The chromosomes are separated and move to opposite sides of the cell.

2.) Prophase -------> B.) The DNA is organized into connected rods called chromosomes.

3.) Metaphase -------> A.) Chromosomes line up at the center of the cell.

4.) Telophase ------> C.) New cells begin to form.

0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.

Pressure is defined to be the amount of force exerted per area

80% of pressure is exerted by nitrogen gas.

So, 20% of pressure will be exerted by oxygen gas.

20% of 2.0 atm = 0.4 atm

Hence, 0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.

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Answer: 1.57 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}[/tex]

The  properties which keep the water temperature from changing much are;

The specific heat capacity is the property of a substance that shows how much its temperature changes when it is exposed to heat.

Thus, the  properties which keep the water temperature from changing much are;

Missing parts:

A red-hot iron nail is immersed in a large bucket of water. Although the nail cools down sufficiently to be held bare-handed, the temperature of the water barely increases. Which properties keep the water temperature from changing much?

A.) water's high heat conductivity

B.) water's high specific heat capacity

C.) the iron nail's high heat conductivity

D.) the large mass of water

E.) the iron nail's high specific heat capacity

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Answer: waters high specific heat capacity the large mass of water

Explanation:

i got it right

Answer:

Methylamine

Explanation:

First count how many carbons there are (there's one). This will give the prefix meth-

Next we can see that this is in the organic functional group amine, as it has a nitrogen at the end with no oxygens. This will give it the suffix -amine.

Now we can give this compound a name:

Methylamine

(the yl is a suffix to make the meth- prefix complete)

We can infer that there are various intermolecular forces between water and ammonia.

The intensity of the intermolecular interactions between a substance's molecules affects its boiling point. Although water and ammonia have comparable molecular sizes and weights, their boiling points differ considerably. This implies that the intermolecular interactions between ammonia and water are different.

The powerful intermolecular force of hydrogen bonding causes water molecules to be drawn to one another. When the hydrogen atom of one water molecule is drawn to the oxygen atom of another water molecule, hydrogen bonding takes place.

As a result, the water molecules are held together by a web of intermolecular forces. These hydrogen bonds need a lot of energy to form. Consequently, water has a high boiling point.

On the other hand, dipole-dipole interactions between molecules occur between ammonia molecules. The nitrogen atom in the polar molecule ammonia (NH3) is more electronegative than the hydrogen atoms.

The hydrogen atoms are somewhat positively charged as a result of this polarity, while the nitrogen atoms are partially negatively charged. Ammonia has a lower boiling point because the dipole-dipole interactions between its molecules are less than the hydrogen bonds in water.

As a result, we can infer that the intensity of the intermolecular forces between water (hydrogen bonding) and ammonia (dipole-dipole interactions) differs based on the drastically different boiling temperatures of the two substances.

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Energy is the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other forms.

The detonation of an atomic bomb releases enormous amounts of thermal energy, or heat, achieving temperatures of several million degrees in the exploding bomb itself. This thermal energy creates a large fireball, the heat of which can ignite ground fires that can incinerate an entire small city.

When the circuit is complete, there is a flow of charge (electric current). The electrons moving through the wire transfer energy to the wire in the form of heat. The particles in the wire, therefore, have more kinetic energy and so the temperature increases.

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Answer:ss

Explanation:ss

Answer:

Y E S

Explanation:

Hibiscus tea has plenty of skin care qualities, from helping your natural levels of collagen and elastin to reducing breakouts to balancing oil production. Hibiscus is known for its rich level of antioxidants, including vitamin C and beta-carotene.

I hope this helps ✍(◔◡◔)

The answer is the current passing between the electrodes is 10.56 mA., the direction of current is towards the negative electrode.

Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field.

Electric charge can be positive or negative (commonly carried by protons and electrons respectively).

Like charges repel each other and unlike charges attract each other

Given that,

Number of sodium ions at the negative electrode, Na⁺ =  2.68 *10¹⁶

Number of chloride ions at the positive electrode,Cl⁻ = 3.92 *10¹⁶

(a) The current flowing in the circuit is due to the positive as well as negative charges such that total charge becomes:

Q= n e

Q = (Na⁺ +Cl⁻) e

Q= (2.68 *10¹⁶ +3.92 *10¹⁶) (1.6*10-19)

Q = 0.01056 C

The current is given by :

I=Q/t  = 0.01056 /1 = 10.56mA

So, the current passing between the electrodes is 10.56 mA.

b) Since, positive ions are moving towards the negative electrode.

And, current is the flow of ions or electrons therefore, the direction of current is towards the negative electrode.

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The current is given by :

So, the current passing between the electrodes is 10.56 mA.

(b) The direction of electric current is towards negative electrodes.

Answer: 341.6k

Explanation:

R= 0.0821

n= 0.46moles

v= 13.3L

p= 734mmhg = 734/760 = 0.97

[tex]T = \frac{p*v}{n*R}[/tex]

[tex]T = \frac{0.97*13.3}{0.46*0.0821}[/tex]

T= 341.6k

Answer:

10100101

Explanation:

this is for the other person alt.

Answer:

Bacteria by binary fission

Starfish

Fungi

Explanation:

[tex]\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}[/tex]

Organisms which apply binary fission are:

[tex]\green\star[/tex]More things to learn about reproduction:

[tex]\blue\star[/tex]There are two modes of reproduction. They are:

Asèxual mode: The mode of reproduction where single parent is enough to give birth another organisms. Eg: Amoeba

Sèxual mode: The mode of reproduction where both parents, male and female are necessary. Eg: Human.

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Answer:

[tex]\displaystyle \text{p} K_a \approx 3.856[/tex]

Explanation:

Because 3.005 grams of potassium lactate is added to 100. mL of solution, its concentration is:

[tex]\displaystyle \begin{aligned} \left[ \text{KC$_3$H_$_5$O$_3$}\right] & = \frac{3.005\text{ g KC$_3$H_$_5$O$_3$}}{100.\text{ mL}} \cdot \frac{1\text{ mol KC$_3$H_$_5$O$_3$}}{128.17 \text{ g KC$_3$H_$_5$O$_3$}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ &= 0.234\text{ M}\end{aligned}[/tex]

By solubility rules, potassium is completely soluble, so the compound will dissociate completely into potassium and lactate ions. Therefore, [KC₃H₅O₃] = [C₃H₅O₃⁺]. Note that lactate is the conjugate base of lactic acid.

Recall the Henderson-Hasselbalch equation:

[tex]\displaystyle \begin{aligned}\text{pH} = \text{p}K_a + \log \frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]} \end{aligned}[/tex]

[Base] = 0.234 M and [Acid] = 0.500 M. We are given that the resulting pH is 3.526. Substitute and solve for pKₐ:

[tex]\displaystyle \begin{aligned} (3.526) & = \text{p}K_a + \log \frac{(0.234)}{(0.500)} \\ \\ 3.526 & = \text{p}K_a + (-0.330) \\ \\ \text{p}K_a & = 3.856\end{aligned}[/tex]

In conclusion, the pKₐ value of lactic acid is about 3.856.

You could let the air out of the balloon while it is under the water with a container filled with water upside down over it. And measure the water displacement.

Combined gas equation: P1V1/T1 = P2V2/T2

Solving for V2:

V2 = P1V1T2/P2T1

T1 = 20 °C = 293.15 K

T2 = 30 °C = 303.15 K

V2 = (1.5 × 3.0 × 303.15)/(2.5 × 293.15)

V2 = 1.86 L

Answer:

1.b

2.b

3.a

4.a

Explanation:

use the rate laws when answering this.

If the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.

The Gibb Free Energy is used to obtain the feasibility of a reaction. If the Gibbs free energy is positive the reaction is not spontaneous. If the value is negative, the reaction is spontaneous while a zero values indicates equilibrium.

From the equation;

ΔG = ΔH - TΔS, it follows that if the enthalpy is positive and the entropy is positive, the Gibbs energy will always be positive, and the reaction will never be feasible.

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