Assume that a sample is used to estimate a population mean u. Find the margin of error M.E. that corresponds to a sample of size 23 with a mean of 37.6 and a standard deviation of 16.1 at a confidence level of 95%.

Report ME accurate to one decimal place because the sample statistics are presented with this accuracy. M.E. ______

Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Answers

Answer 1

Based on the illustration above, the value of margin of error M.E is 6.961

Margin of error (M.E) is calculated as the product of critical value (CV) and standard error (SE) of sample mean.

The formula for standard error of sample mean is:

SE = σ/√n

where σ is the population standard deviation and n is the sample size. The formula for margin of error is:

M.E. = CV x SE

where CV is the critical value.

The critical value for a 95% confidence level with 22 degrees of freedom (sample size 23 - 1) is 2.074 (rounded to 3 decimal places).

The sample mean is 37.6 and the population standard deviation is 16.1.

Sample size, n = 23.

Using the formula,

SE = σ/√n

SE = 16.1/√23

SE = 3.365 (rounded to 3 decimal places)

Now, using the calculated value of SE and CV,

ME = CV x SE

ME = 2.074 × 3.365

ME = 6.961 (rounded to 1 decimal place)

Therefore, the margin of error (M.E.) is 6.961 (rounded to 1 decimal place).

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Related Questions

Sails come in many shapes and sizes. The sail on the right is a triangle. Is it a right triangle? Explain your reasoning.

Answers

Answer:

not a right triangle

Step-by-step explanation:

you can use the pythagorean theorem to prove whether not this is a right triangle

if this triangle is a right triangle then the following equality should be true

a²+b²=c²

(9.75)²+(3.45)²=(10.24)²

(95.06)+(11.90)=(104.86)

106.96≠104.86

since the following equality is not true, this is not a right triangle.

Please answer no links!!!!!!!!!!!

Answers

Answer:

2 (4, 14)3 (3, 5)
The answer for number 1 is 2- (4,14) and I believe the answer for 2 is (3,5) (I may be mistaken on that one since I didn’t graph it.

P(x) = x2 + x +1
How many terms does this polynomial have?

Answers

Answer:

3

Step-by-step explanation:

2. A cow gives 24litre milk each day. If the milkman sells 75% of the milk, how many
liters of milk is left with him?​

Answers

Answer: 6 liters

Step-by-step explanation:

24 liters

He sells 75%

24 x 0.75 = 18 liters

24 - 18 = 6

He still has 6 liters left

Jasmine has $50 and saves $4.38 every month. Radha has $0 and saves $5.38 every month. Jasmine's savings after x months can be represented by the function f (x) = 4.38 x + 50. Radha's savings after x months can be represented by the function g (x) = 5.38 x. Round your answer to the nearest hundredth.

After how many months will they both have the same amount in savings? Find the values of x for which f (x) = g (x).

After ____ months, Jasmine and Radha will have the same amount in savings.​

Answers

After 50 months, jasmine and Radha will have the same amount in savings

Given f(x)= 5 (6) x for rexeh 1 o elsewhere for a continuous veidon variable z. (a) Compute p(2.4 x <3). (6) Compite Elx)

Answers

a.  the value of P(2.4 < x < 3) is 8.1.

b. the value of E(X) is 10.

Given function is f(x) = 5(6)x for x≥1 and elsewhere for a continuous random variable z.  

a. Compute P(2.4 < x < 3)

For continuous random variable, P(a < x < b) = ∫f(x)dx, where f(x) is the probability density function (PDF).

Here, f(x) = 5(6)x for x≥1 and elsewhere

So, P(2.4 < x < 3) = ∫f(x)dx = ∫2.4^35(6)xdx= 5 ∫2.4^36xdx= 5 [(3^2 - 2.4^2)/2] = 5 [(9 - 5.76)/2] = 5 [1.62] = 8.1

Hence, the value of P(2.4 < x < 3) is 8.1.

b. Compute E(X)Expected value of X is given by E(X) = ∫xf(x)dxFor continuous random variable, E(X) = ∫xf(x)dx, where f(x) is the probability density function (PDF).Here, f(x) = 5(6)x for x≥1 and elsewhereSo, E(X) = ∫xf(x)dx = ∫1∞5(6)x.xdx+ ∫-∞0 0dx= 5 ∫1∞6x^2dx+ 0 = 5 [(6) (x^3)/3]1∞= 5 [(6) (1^3)/3] = 10

Hence, the value of E(X) is 10.

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Given f(x)= 5 (6) x for rexeh 1 o elsewhere for a continuous veidon variable z. We are required to compute p(2.4 < x <3) and E(x).

Compute p(2.4 < x <3)For the given function, f(x) = 5 (6) x for 1 ≤ x ≤ 3 and 0 elsewhere.

So, the total area under the curve will be equal to 5 (6) 2 = 60.

And the required probability is given by the area under the curve from 2.4 to 3.  [Illustration is provided below]

Hence, p(2.4 < x <3) = 3.6

(b)Compute E(x)Expected value of x, E(x) is given by E(x) = ∫xf(x) dx,

which is equal to the area under the curve multiplied by the distance over which the function is spread.

Let's calculate the area under the curve, which is equal to 60, as we have calculated earlier.

Now, we calculate the distance over which the function is spread.

Distance = 3 - 1 = 2 unitsHence, E(x) = 60/2 = 30.

Answer:Therefore, p(2.4 < x <3) = 3.6 and E(x) = 30.

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I need a little more help. Sorry for the spam questions.

Answers

perimeter is 28 and area is 32

Ajjwjjwjwjwjsbsbaa shah sash’s

Answers

Answer:

okay then

Step-by-step explanation:

Answer: gtyrehretr

Step-by-step explanation:

Translate into an equation: Twenty-six more than the product of a number and
17 is -42.

Answers

C) 17n + 26 = -42

“the product of a number and 17” = 17n

“twenty six more than” = + 26

And if the next question has you solve it:
17n + 26 = -42
Subtract 26 from both sides
17n = -68
Divide both sides by 17
n = -4

A fair die is tossed twice and let X1 and X2 denote the scores obtained for the two tosses, respectively

Calculate E[X1] and show that var (X1) =
Determine and tabulate the probability distribution of Y = | X1 – X2 | and show that E[Y] =
The random variable Z is defined by Z = X1 – X2. Comment with reasons (quantities concerned need not be evaluated) if each of the following statements is true or false
E(Z2) = E(Y2)
Var(Z) = Var(Y)

Answers

1. When a fair die is tossed the expected value E[X1] = 3.5 and the variance var(X1) = 35/12.

When a fair die is tossed, each of the six possible outcomes has an equal probability of 1/6. Let X1 denote the score obtained in the first toss.

To calculate the expected value E[X1], we find the sum of all possible values of X1 multiplied by their respective probabilities:

E[X1] = (1 * 1/6) + (2 * 1/6) + (3 * 1/6) + (4 * 1/6) + (5 * 1/6) + (6 * 1/6) = 3.5

To calculate the variance var(X1), we use the formula:

var(X1) = E[X1^2] - (E[X1])^2

First, we find E[X1^2] by taking the sum of the squares of all possible values of X1 multiplied by their respective probabilities:

E[X1^2] = (1^2 * 1/6) + (2^2 * 1/6) + (3^2 * 1/6) + (4^2 * 1/6) + (5^2 * 1/6) + (6^2 * 1/6) = 91/6

Substituting the values into the formula, we calculate var(X1):

var(X1) = (91/6) - (3.5)^2 = 35/12

Therefore, E[X1] = 3.5 and var(X1) = 35/12.

2. The probability distribution of Y = |X1 - X2| is tabulated as follows:

Y |X1 - X2| P(Y)

0 0 1/6

1 1 2/6

2 2 2/6

3 3 1/6

To calculate E[Y], we find the sum of all possible values of Y multiplied by their respective probabilities:

E[Y] = (0 * 1/6) + (1 * 2/6) + (2 * 2/6) + (3 * 1/6) = 1

Therefore, E[Y] = 1.

3. The statements E(Z^2) = E(Y^2) and Var(Z) = Var(Y) are false.

E(Z^2) and E(Y^2) represent the expected values of the squares of the random variables Z and Y, respectively. Since Z = X1 - X2 and Y = |X1 - X2|, the squares of Z and Y have different probability distributions, leading to different expected values.

Similarly, Var(Z) and Var(Y) represent the variances of Z and Y, respectively. Since Z and Y have different probability distributions, their variances will generally not be equal.

Therefore, E(Z^2) ≠ E(Y^2) and Var(Z) ≠ Var(Y).

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8. Which equation is true for all x- and y- values in the table below?

x y
1 7
2 14
3 21
4 28
(1 point)
y = x + 7
y = x – 7
y = x over seven
y = 7x

Answers

Answer:

y = 7x

Step-by-step explanation:

you mutiply 7 times 1=7

you just continue to do that

Donna bought 5 bags of dog treats for $13.10. What is the cost per bag of dog treats?
A. $18.10
B.$3.28
C.$2.62
D.$0.38

Answers

It is answer C because 13.10 divided by 5 is 2.62 Pls mark brainliest


What is the solution to the equation below?
4x+8 = 2(x - 4)
A x = -5
B x = 6
Cx = -8
D x = -4

Answers

Answer:

C

Step-by-step explanation:

4x +8 = 2x -8

4x = 2x - 16

2x = -16

x = -8

calculate the solubility (in g/l) of caso4(s) in 0.250 m na2so4(aq) at 25°c . the sp of caso4 is 4.93×10−5 .

Answers

The given values are: Ksp of CaSO4 = 4.93 × 10⁻⁵, Molarity of Na2SO4 = 0.250(m). Molar mass of CaSO4 = 136.14 g/mol. We can write the equation for the dissolution of CaSO4 in water as:CaSO4(s) ⇌ Ca²⁺(aq) + SO₄²⁻(aq). Let's consider that "x" grams of CaSO4 dissolves in "1 L" of 0.250 M Na2SO4. Since the CaSO4 dissolves according to the following equation:CaSO4(s) ⇌ Ca²⁺(aq) + SO₄²⁻(aq). The concentration of Ca²⁺ ions in the solution will be "x" moles / 1 L. The concentration of SO₄²⁻ ions in the solution will be "x" moles / 1 L. Since the concentration of Na2SO4 in the solution is 0.250 M or 0.250 moles / L, the concentration of SO₄²⁻ ions contributed by Na2SO4 will be (2 × 0.250) M or 0.500 M. In order to determine the value of "x" or the amount of CaSO4 that dissolves, we need to consider the equilibrium of the solution. The Ksp expression for the dissolution of CaSO4 can be written as: Ksp = [Ca²⁺][SO₄²⁻], Ksp = (x)(x) = x². As the dissociation is very small compared to the concentration of Na2SO4, we can consider "0.250" moles of Na2SO4 in "1 L" of the solution completely dissociated. Thus, the final concentrations of Ca²⁺ and SO₄²⁻ ions in the solution will be:[Ca²⁺] = x moles / L[SO₄²⁻] = (x + 0.500) moles /L. Therefore, we can write the expression for the ion product: IP = [Ca²⁺][SO₄²⁻]IP = (x)(x + 0.500)As the value of Ksp is equal to the IP, we can write the expression for Ksp as: Ksp = x² + 0.500xWe can substitute the value of Ksp as 4.93 × 10⁻⁵M:4.93 × 10⁻⁵ = x² + 0.500x. Solving for "x", we get the following quadratic equation: x² + 0.500x - 4.93 × 10⁻⁵ = 0. Solving for "x" using the quadratic formula: x = 0.00796 g/L. Therefore, the solubility of CaSO4(s) in 0.250 M Na2SO4 solution at 25°C is 0.00796 g/L.

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Find the area of the following figure. Show your work

Answers

1 - 7 + 7 + 3 + 3 = 20
2 - 3 + 3 + 4 + 3 = 13
3 - 7 + 7 + 2 + 2 = 18
4 - 2 + 2 + 9 + 9 = 22
5 - 3 + 1 + 3 + 1 = 8
20 + 13 + 18 + 22 + 8
33 + 18 + 22 + 8
33 + 18 + 30
63 + 18
= 81

Tim is making 30 sundaes with mint, chocolate, and vanilla ice cream.
1/5
of the sundaes are mint ice cream and
1/2
of the remaining sundaes are chocolate. The rest will be vanilla. How many sundaes will be vanilla?

Answers

12 sundaes will be vanilla can i please have brainliest

Answer:

12

Step-by-step explanation:

1/5 mint = 6

30 - 6 = 24

Half of 24 is 12

12 is chocolate

so 12 must be vanilla

CAN SOMEONE HELP ME PLEASE

Answers

Answer: 9 x 6 x 6

Step-by-step explanation: 9 x 6=54  54 x 6 = 324 ft

Work out the size of angle x.
42°
Х
123°

Answers

Answer:

42+123+x=180

x=180-165

x=15 degrees

Step-by-step explanation:


Question Help
One taco supreme and two pan pizzas provide 3200 calories. Two taco supremes and one pan pizza
provide 3280 calories. Find the caloric content of each item.

Answers

Answer:

4324eqW

Step-by-step explanation:

3 + 5 =7

Essie has two identical containers she fell one with milk and the other with water if the first container holds about 10 L of milk how much does the second container holds

Answers

Answer:

10 liters of water

Step-by-step explanation:

Given

[tex]A = 10L\ milk[/tex]

Required

How much the second holds

Since they are both identical, then both containers hold the same volume (even if the quantity they hold are different)

Hence:

[tex]B = 10L\ water[/tex]

need help imm struggling ​

Answers

Answer:

1733.33

Step-by-step explanation:

The volume of a pyramid is (length*width*height) divided by 3

Answer:

1733.33

Step-by-step explanation:

v = (lwh)/3

v = (20 x 20 x 13)/3 = 5200/3 = 1733.33

Oatmeal is packaged in a right circular cylindrical container that has a radius of 7 centimeters and a height of 16 centimeters.



What is the surface area of this container in terms of pi?

a. 176
b. 254
c. 322
d. 440

Answers

Answer:

c. 322

Step-by-step explanation:

Surface area of cylinder = 2πr² + 2πrh.

SA in terms of π = π(2r² + 2rh) →

π(2(7)² + 2(7)(16)) →

π(2(49) + 2(112)) → π(98 + 224) → π(322)

Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2500 grams and a standard deviation of 600 grams while babies born after a gestation period of 40 weeks have a mean weight of 2800 grams and a standard deviation of 415 grams. If a 34-week gestation period baby weighs 2875 grams and a 41-week gestation period baby weighs 3175 grams, find the corresponding z-scores. Which baby weighs more relative to the gestation period?
Find the corresponding z-scores. Which baby weighs relatively more? Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.)

A. The baby born in week 34 weighs relatively more since its z-score ____, is smaller than the z-score of ____ for the baby born in week 41
B. The baby born in week 41 weighs relatively more since its z-score ____, is smaller than the z-score of ____ for the baby born in week 34
C. The baby born in week 34 weighs relatively more since its z-score ____, is larger than the z-score of for ____ the baby born in week 41 for the baby born in week 34
D. The baby born in week 41 weighs relatively more since its z-score ____, is larger than the z-score of ____ for the baby born in week 34

Answers

The corresponding z-scores for the given observations can be calculated using the formula:

[tex]\[z = \frac{{x - \mu}}{{\sigma}}\][/tex]

where [tex]\(x\)[/tex] is the observation, [tex]\(\mu\)[/tex] is the mean, and [tex]\(\sigma\)[/tex] is the standard deviation.

For the baby born in week 34 weighing 2875 grams:

[tex]\[z_{34} = \frac{{2875 - 2500}}{{600}} = 0.625\][/tex]

For the baby born in week 41 weighing 3175 grams:

[tex]\[z_{41} = \frac{{3175 - 2800}}{{415}} = 0.904\][/tex]

To determine which baby weighs more relative to the gestation period, we compare the z-scores.

A. The baby born in week 34 weighs relatively more since its z-score 0.625 is smaller than the z-score 0.904 for the baby born in week 41.

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a bag contains 15 red marbles, 15 white beads, 20 green beads, and 25 blue beads. What is the probability of randomly drawing a blue bead?

Answers

Answer:

1/3 or 33%

Step-by-step explanation:

15 + 15 + 20 +25 is equal to 75

25/75 is 1/3

Answer:

1 by 3

Step-by-step explanation:

15 + 15 + 20 + 25 = 75

so,

again,

25 divided by 75 is equal to 1 by 3

the school choir has 110 members there are 20 more girls than boys there are how many boys the choir

Answers

Answer:

65 girls and 45 boys

Step-by-step explanation:

What should be done to both sides of the equation in order to solve y - 4.5 = 12.2?

Answers

Add 4.5

---

hope it helps

Answer: add 4.5 to both sides

Step-by-step explanation: this will allow the 4.5 to be removed from the y side and since you added it to one side you have to add it to the other side. This will give your y the value of 16.7.

Brainliest plz

Assuming the sample was taken from a normal population, test at ů. = 0.05 and state the decision. Họ: H = 13 HA: U < 13 ř= 10 S= 0.7 n = 9

Answers

the test statistic (t = -12.857) is smaller than the critical value (-1.860), we have enough evidence to reject the null hypothesis.

To test the hypothesis regarding the population mean, we can perform a one-sample t-test.

Given:

- Null hypothesis (H₀): μ = 13

- Alternative hypothesis (Hₐ): μ < 13

- Sample mean ([tex]\bar{X}[/tex]) = 10

- Sample standard deviation (s) = 0.7

- Sample size (n) = 9

- Significance level (α) = 0.05

To conduct the t-test, we can calculate the test statistic and compare it with the critical value from the t-distribution.

The test statistic (t-score) is calculated as:

t = ([tex]\bar{X}[/tex] - μ) / (s / √n)

Plugging in the values:

t = (10 - 13) / (0.7 / √9)

t = -3 / (0.7 / 3)

t = -3 / 0.233

t ≈ -12.857

To determine the critical value, we need to find the appropriate degrees of freedom (df) for a one-sample t-test. In this case, df = n - 1 = 9 - 1 = 8.

Using a significance level of α = 0.05 and looking up the critical value for df = 8 in the t-distribution table, we find the critical value to be approximately -1.860.

Since the test statistic (t = -12.857) is smaller than the critical value (-1.860), we have enough evidence to reject the null hypothesis.

Decision: Based on the test results, at α = 0.05, we reject the null hypothesis (H₀: μ = 13). There is sufficient evidence to support the alternative hypothesis (Hₐ: μ < 13), suggesting that the population mean is less than 13.

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Given question is incomplete, the complete question is below

Assuming the sample was taken from a normal population, test at α = 0.05 and state the decision. Họ: μ = 13 HA: μ < 13 [tex]\bar{X}[/tex]= 10 s= 0.7 n = 9

Suppose there is a family with four children. Assume that it is equally probable for a boy or a girl to be born. a. What is the probability of all girls? b. What is the probability of all girls given there is at west one girl? c. What is the probability of at least one boy and one girl?

Answers

a. The probability of all girls in a family with four children is 1/16 or 0.0625.

b. The probability of all girls given there is at least one girl is 1/15 or 0.0667.

c. The probability of having at least one boy and one girl in a family with four children is 15/16 or 0.9375.

a. To calculate the probability of all girls, we need to consider the possible outcomes of each child being a girl. Since each child has an independent probability of being a girl or a boy, the probability of all girls is (1/2) * (1/2) * (1/2) * (1/2) = 1/16 or 0.0625.

b. Given that there is at least one girl, we have three remaining children. The probability of all girls among the three remaining children is (1/2) * (1/2) * (1/2) = 1/8. Therefore, the probability of all girls given there is at least one girl is 1/8 divided by the probability of having at least one girl, which is 1 - (1/2)⁴ = 15/16, resulting in a probability of 1/15 or approximately 0.0667.

c. The probability of having at least one boy and one girl can be calculated by subtracting the probability of having all boys from the total probability space. The probability of having all boys is (1/2)⁴ = 1/16. Therefore, the probability of having at least one boy and one girl is 1 - 1/16 = 15/16 or approximately 0.9375. This probability accounts for all possible combinations of boys and girls in a family with four children, excluding the scenario of having all boys.

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A pump fills a pool at a constant rate. At the end of 1 minute it has filled 6 gallons of water. Which table represents the relationship between the number of minutes and the number of gallons of water in the pool?​

Answers

Answer:

I would need to see the different tables to answer this question.

Rewrite the equation by completing the square. x^{2}+4x-21 = 0

Answers

Answer:

x={3,-7}

Step-by-step explanation:

brackets for list

Solve with quadratic formula

separate the solutions

Square

Answer:

2 for the first box and 25 for the second one.

Step-by-step explanation:

Other Questions
Interest rates adjusted for the effects of inflation are real variables, inflation is a nominal variable. and inflation are real variables. and inflation are nominal variables are nominal variables, inflation is a real variable. Suppose a country has only a sales tax. Now suppose it replaces the sales tax with an income tax that includes a tax on interest income. This would make equilibrium Interest rates fall and the equilibrium quantity of loanable Funds rise. interest rates and the equilibrium quantity of loanable funds fall. interest rates and the equilibrium quantity of loanable funds rise. interest rates rise and the equilibrium quantity of loanable funds fall Which of the following events could explain an increase in interest rates together with a decrease in investment? The government instituted an investment tax credit. None of the others is correct The government reduced the tax rate on savings. The government went from surplus to deficit. Perform mortgage calculations(monthly mortgage payment, adjusted mortgage payment, and an amortization schedule) on a property listed at $850,000. Loan term is 30 years fixed, 20% down payment, rate 4.625%, APR 4.636%. Tiffani Lind earned $2,800 during her biweekly pay period. Sheis married and claims 4 deductions. Her annual earnings to date are$53,459. Calculate her net pay. Assume Social Security is 6.2% (onupPayroll Period Weekly. Biweekly . Semimonthly Monthly Quarterly. . Semiannually Annually Daily or miscellaneous (each day of the payroll period) One Withholding Allowance $76.90 153.80 166.70 333.30 1 The following is a set of data from a sample ofn=5.4 9 4 4 6a. Compute the mean, median, and mode.b. Compute the range, variance, standard deviation, and coefficient of variation.c. Compute the Z scores. Are there any outliers?d. Describe the shape of the data set. If the stock currently sells for $30.70 per share, what is the market-to-book ratio? The priceearnings ratio? 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(b) how many seconds does it take for the propeller to turn through 45? 19. To justify adding 50 units of nitrogen we must see at least what increase in corn production if corn is selling at $2.10/bu.? The graph below shows the supply of cupcakes. Show the effect of an increase in the price of flour, an input to cupcake production.Instructions: Use the tool provided (S2) to draw the new supply curve for cupcakes. your load balancer is configured with a tls certificate and contacts backend web application servers listening on tcp port 8081. users must be able to access the web application using standard tcp port numbers in their web browsers. which listening port should you configure on the load balancer? A random variable x is said to belong to the one-parameter exponential family of distributions if its pdf can be written in the form: Sx;6)=exp[AO)B(x) + C(x)+D(0)] where A(O), DCO) are functions of the single parameter 0 (but not x) and B(x), C(x) are functions of (but not ). Write down the likelihood function, given a random sample X,, X2,...,x, from the distribution with pdf f(x;0). (2 Marks) (b) If the likelihood function can be expressed as the product of a function which depends on 0 and which depends on the data only through a statistic T(x,x2,...,x.) and a function that does not depend on 0, then it can be shown that T is a sufficient statistic for 0. Use this result to show that B(x) is a a sufficient statistic for 0 in the one-parameter exponential family of part (b). (3 Marks) c) If the sample consists of iid observations from the Uniform distribution on the interval (0,0), identify a sufficient statistic for 0. The __________ strategy involves deciding what goods and services the firm should offer to a group of consumers and also making decisions about customer service, brand name, packaging, labeling, product life cycles and new product development. Human Resource Implementation at the InstituteThe institute employs several thousand employees. It is the home of museums, research centers, and offices. Millions of people each year, ranging from visitors to scientists, visit the sites. Like most institutes, it has grown over the years and has outgrown its information technology infrastructure. The aging application systems were based on technology that had become very difficult to change and adapt to the increasing needs of the institute. To address the need for change, the institute developed a vision and plan to update the IT environment. The vision included all areas of the institute. This case study will focus on the governance structure and the implementation of a human resources management system.GovernanceAt the institute, an IT governance structure was put in place to address the modernization. This included the following: The Information Technology Advisory Committee (ITAC) advises and assists the CIO in establishing and implementing IT management policies, procedures, and practices. TheChangeControlBoard(CCB)forhardwareandsoftwarechangestotheITinfra- structure. The CCB addresses the impact of changes to the infrastructure and ensures minimal disruption in services and operations. TheprimaryobjectivesofITManagementReviewBoard(IMRB)are to address project success factors and ensure that risk is managed by completing assessments at key project milestones.This structure ensures consistency throughout the institution by standardizing hardware, software, and data. The following four governing strategies represent fundamental principles for managing IT resources and meeting the information needs of the institute:1. Project management, including a proven implementation methodology and support process, baselined project plans in order to evaluate project progress and ensure the proper mix of functional and technical resources are available and working together on the project.2. Application software and business process reengineering, thereby minimizing modifications.3. Data management standards to ensure the interoperability across systems.4. IT infrastructure: hardware, network, and system software that is current, secure, scalable and consistent across applications.Human resources provide recruiting, compensation and recognition, planning and consult- ing, employee and labor relations, and training services. The legacy system did not have the ability to capture data at the source and use it for multiple purposes, resulting in errors and delays. The integrated HR management system (HRMS) that replaced the legacy system provided information, immediately delivering the services required, and it replaced current labor-intensive paperbound processes.The project to implement the PeopleSoft HRMS took three years and was delivered in phases. The system was in full production and stable in a relatively short time frame.BenefitsThe HRMS ERP investment supports and modernized the institutes HR management systems. In addition, the IT infrastructure was state of the art. The approach had three critical success factors: Implementation team was involved in all aspects of the implementation from the hardware configuration to the "fit-gap" analysis. Allchangeswereevaluatedbasedontheoriginalsetofrequirements. Thisinvolvedthefunctionalusersfromthebeginningallthewaythroughtestingandstabilization.CONCLUSIONThis is a good example of setting up an ERP system implementation effectively from the beginning: It had the support of senior management, the reason for change was developed and conveyed to the organization, and an overall vision for the institution was incorporated into the IT strategic plan. The organization developed measurable goals for the HRMS project (see Appendix A) with actual results documented as each component was implemented to determine the level of success.1. What were the key strategies or success factors for HRMS ERP implementation?2. Why was the governance so important to the project?3. In setting up goals for each system component, what did the institute do that manybusinesses or institutions do not with an ERP implementation? which of the following are best practices when organizing data? select all that apply. 1 point use foldering to organize files into folders delete your old project data align your naming and storage practices with your team apply logical and descriptive naming conventions Considering the error that arises when using a finite difference approximation to calculate a numerical value for the derivative of a function, explain what is meant when a finite difference approximation is described as being second order accurate. Illustrate your answer by approximating the first derivative of the function f(x) = 1/3 - x near x = 0. true or false6. An L/C has a description of the goods at the end of which it states "CIF Shanghai". Here Shanghai should be the destination port. ( ) Umbrella Corporation is considering a project whose cost of capital is 15 percent, and the initial after-tax cost is $5,000,000. The project is expected to provide after-tax operating cash inflows of $1,800,000 in year 1, $1,900,000 in year 2, $1,700,000 in year 3, and $1,300,000 in year 4. What is the net present value for the project? Select one: O a. $9,862.947.17 O b. $1,700,000.00 . -$137,052.82 O d. $8,576,475.80 In airline applications, failure of a component can result in catastrophe. As a result, many airline components utilize something called triple modular redundancy. This means that a critical component has two backup components that may be utilized should the initial component al Suppose a certain critical airine component has a probability of failure of 0.038 and the system that thizes the component is part of a triple modular redundancy (a) What is the probability that the system does not fail? (b) Engineers decide to the probability of failure is too high for this system.