Aspirin therapy has been used after ________ or recurrent _________ to reduce the risk of recurrence. Aspirin is contraindicated for anyone with ______________ ___________.

vf = vi + at = 2 m/s + (4 m/s²) (2 s) = 10 m/s

Answer: 2 Forces

Explanation:

1. Normal force- object is on a surface

2. Weight

Answer:

Charge q = 37.27 micro coulombs

Explanation:

Given:

q₁ = q₂ = q

r = 2.5 m

F = 2.0 N

________

q - ?

Coulomb's law:

F =k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²

Charge:

q = √ (F·r² / k)

q = √ (2·2.5² / (9·10⁹) ≈ 37.27·10⁻⁹  C

or q = 37.27 micro coulombs

The correct answer is not 52, but !!! :))

a. ) The period is  1/frequency = 5sec / 9 cycles = 0.555 seconds

b.) the seconds out of phase with the displacements shown would graphs of the velocity and acceleration be 5/18 (0.2777...) sec delayed with respect to displacement

c.) Gravity = (324 π²) (0.2) / 25  =  25.582 m/sec²

What is gravity?

Gravity is defined as a fundamental interaction which causes mutual attraction between all things with mass or energy.

Solving for  the acceleration due to gravity on the surface of the planet, we have the following:

For small swing angles, the period of an ideal pendulum anywhere is

                T = 2pi √(length / local gravity)  .

The astronaut has already done the pendulum and transmitted the data to us, so

we can use his data and this formula to calculate the local gravity where he is located

          P = 2pi √(length / local gravity)

           5/9 sec = 2π √(0.2m / gravity)

        √(0.2m / gravity) =  5/9sec / 2π

Take the reciprocal of each side:    √(gravity) / √(0.2) =  18π / 5

Multiply each side by  √(0.2):    √(gravity) = 18π √(0.2) / 5

Square both sides:      Gravity = (324 π²) (0.2) / 25  =  25.582 m/sec²

The value gotten is about  2.608 times  the Earth's gravity.  

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(a) The speed of the student at the bottom of the hill is 15.34 m/s.

(b) The speed of the student at the presence of friction force is 11.88 m/s.

The speed of the student at the bottom of the hill is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy at the bottom hill = potential energy at maximum height

¹/₂mv² = mgh

where;

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

The speed of the student at the presence of friction force is calculated as;

Kinetic energy at the bottom hill + work done against friction  = potential energy at maximum height

¹/₂mv² + μmgh = mgh

¹/₂v² + μgh = gh

v²  +  2μgh = 2gh

v² = 2gh - 2μgh

v² = (2 x 9.8 x 12) - (2 x 0.4 x 9.8 x 12)

v² = 141.12

v = √141.12

v = 11.88 m/s

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Answer:

Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity

Explanation:

42 times must he repeat this exercise to burn off the energy in one slice of pizza.

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Energy burn by the weightlifter = potential energy

Potential energy = mgh

Potential energy = 25.(9.8)(0.50)

Potential energy = 122.5 Joule.

Assume 25% of efficiency so energy burn = 122.5*25/100

energy burn = 30.625 joule

Number of times = 1260/30.625

Number of times = 42 times.

42 times must he repeat this exercise to burn off the energy in one slice of pizza.

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Echo

Explanation:

It is termed as Echo. Echo is a reflection of sound that arrives at the listener with a delay after the direct sound.

The radial acceleration of the blade tip is  1370 g rad/s².

Radial acceleration is defined as "the acceleration of the object is along the radius, directed towards the center" in uniform circular motion.

Given parameters:

Rotational speed of the helicopter rotor: ω = 600 rev/min

= 600 × 2π/60 rad/min.

= 20π rad/min.

Length of the blade: r = 3.4 m.

Then,   the radial acceleration = ω²r = (20π)²× 3.4 rad/s².

= {(20π)²× 3.4}/9.8 g rad/s².

= 1370 g rad/s².

Hence,  the radial acceleration of the blade tip is  1370 g rad/s².

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Answer:

The force of friction and air resistance slow down the movement of the bus.

c) A forse is changing the motion of the bus

If an evaporator has a vapour pressure drop of 10 psig and the low side pressure is 15 psig,  pressure at the inlet of the evaporator will be 25 psig

change pressure=  low side pressure-pressure drop

change pressure=15-(-10)

change pressure=25 psig

The vapor pressure of a liquid, sometimes referred to as the equilibrium pressure of a vapor above its liquid, is the pressure of the vapor produced by the evaporation of a fluid (or solid) over a sample of the liquid (or solid) in such a closed container (or solid).

Vapor pressure is the term for the force that is produced as liquids evaporate. Three factors commonly have an effect on a vapor press: surface area, intermolecular forces, and temperature. The vapor pressures of molecules change with temperature.

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The total current that is drawn from the mains supply is 5 A.

The term current has to do with the flow of charges in a circuit. Now we have been told that A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. It was also said in the question that when the lights are switched on and working correctly, the current through each lamp is 0.25 A.

Now we have the following information;

Current passing through each lamp = 0.25 A

Number of lamps = 20 lamps

Hence;

Total current = 0.25 A * 20

= 5 A

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1.125 joule work done does air resistance do on the ball

work done= kinetic energy= mΔv²/2

m=0.25kg

Δv=3 m/s

work done= mΔv²/2

work done=-0.25×9÷2

work done=-1.125 joule

When an item is moved across a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work done in physics. By multiplying the length of the path by the component of the force operating along the path, work may be calculated if the force is constant. The work W is equal to the force f times the distance h, or W = mgh, to mathematically describe this idea. The work is W = mas if the force is applied at an angle of to the displacement.

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The net work done on the block over the given distance is 39.4d (joules)

The net work done on the block over the given distance is calculated by applying the following equation as shown below:

W(net) = F(net) x d where;

F(net) = F - μmgcosθ where;

F(net) = 50 N - (0.25 x 5 x 9.8 x cos30)

NF(net) = 50 N - 10.6 NF(net) = 39.4 N

The net work done on the block over the given distance is calculated as: W = 39.4 N x dwhere;

d is the distance moved by the block = length of the incline

W = 39.4d (joules)

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The option that  would increase the mechanical advantage of a lever is option A. Moving the fulcrum closer to the output force.

Mechanical advantage quantifies a lever's effectiveness (how easy it is to lift the load). - When compared to the distance between the load (resistance) and the fulcrum, the advantage relies on the distance between the effort and the latter (effort arm) (resistance arm).

Note that in Levers of Class 1:

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Answer:

hydrogen

Explanation:

The Sun is a huge, glowing sphere of hot gas. Most of this gas is hydrogen (about 70%) and helium (about 28%). Carbon, nitrogen and oxygen make up 1.5% and the other 0.5% is made up of small amounts of many other elements such as neon, iron, silicon, magnesium and sulfur.

The sun is 70% made of Hydrogen.

What is hydrogen?

The element hydrogen has the sign H and the atomic number 1. The lightest element is hydrogen. Under normal conditions, hydrogen is a gas composed of diatomic molecules with the formula H2. It has no colour, no odour, no taste, is non-toxic, and is extremely flammable. Hydrogen is the most prevalent chemical element in the universe, accounting for approximately 75% of all normal matter. The Sun and other stars are mostly made up of hydrogen in the plasma state. The majority of hydrogen on Earth resides in molecule forms like water and organic substances. Each atom of hydrogen's most common isotope (symbol 1H) has one proton, one electron, and no neutrons.

The sun is around 70% made of Hydrogen and 28% Helium

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(a.i) The magnitude of the centripetal acceleration at its edge is 28,197.04 m/s².

(a. ii) In terms of multiple of g, the centripetal acceleration is 2,874.3 g.

(b) The linear speed is determined as 48.96 m/s.

The magnitude of the centripetal acceleration of the workshop grindstone is calculated by applying the following kinematic equation.

a = v²/r = ω²r

where;

The given parameters include;

ω = 5500 rev/min

ω = 5500 rev/min   x   2π rad/rev x  1 min / 60 s

ω = 575.96 rad/s

a = (575.96²) x (0.085)

a = 28,197.04 m/s²

In terms of acceleration due to gravity (g);

a = 28,197.04 m/s² / 9.81 = 2,874.3 g

The linear speed of the grindstone is calculated as follows;

v = ωr

v = 575.96 rad/s  x  0.085 m

v = 48.96 m/s

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Answer: D: 136 N

..

..

Answer:

Explanation:

p₁ = m₁·V₁ = 6300·0.11 = 693 kg·m/s

p₂ = m₂·V₂ = 50·10.4 = 520 kg·m/s

693 kg·m/s > 520 kg·m/s

The horizontal distance travelled by the car in the given time period of 13 seconds is determined as 168.3 m.

The horizontal distance travelled by the car is calculated as follows;

s = ut + ¹/₂acosθ(t²)

where;

s = 0  +  ¹/₂(2) x cos(5.2) x (13)²

s = 168.3 m

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The average acceleration of the hybrid automobile is 0.42 m/s².

The distance travelled by the hybrid automobile during the period of acceleration is 34.5 m.

The average acceleration of the hybrid automobile is the rate of change of velocity of the hybrid automobile with time.

Mathematically, the formula for average acceleration is given as;

a = Δv/Δt

where;

a = (v - u)/t

where;

a = (5.56 - 1.389)/10

a = 0.42 m/s²

The distance travelled by the automobile during the period of acceleration is calculated as follows;

v² = u² + 2as

2as = v² - u²

s = (v² - u²)/(2a)

s = (5.56² - 1.389²) / (2 x 0.42)

s = 34.5 m

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Answer:sin40∘=0.643) Hint: The relationship of angle of incidence and angle of refraction at interface of two media is given by Snell's law.

Explanation:

0.212 m/s²  is the average acceleration of the treadmill.

during this period

initial velocity, u = -1.2 m/s

time= 25 min

final velocity, v=  −6.5 m/s

acceleration = (v-u)÷ t

acceleration =5.3/25

acceleration =0.212 m/s²

The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating. A moving object can occasionally alter its velocity by the same amount every second. a moving object that changes its speed by 10 m/s per second. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration. It is important to distinguish between an item with a constant acceleration and one with a constant velocity. Be not deceived! An object is accelerating if its velocity is changing, whether by a fixed amount or a variable quantity. Additionally, a moving item with a constant speed is not accelerating.

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Answer:

Kate did not do any work on the wall , because the wall did not move

Answer:hope this helpsss

Explanation:

A permanent magnet that is always aligned with the magnetic field of the earth makes up the magnetic needle of a magnetic compass, which is used for navigation.

The magnetic field is produced by an electric current in an electromagnet. Because they are transient magnets, electromagnets lose their magnetic properties as soon as the current is interrupted.

It would take the star 2 seconds to lose all it's mass.

I got this by dividing 12.044×10⁴⁶ by  6.022×10²³

Answer:

W1 = d1 V

W2 = d2 V         weight of balls in air (both have same volume0

w2 = (d2 - p) V     apparent weight of ball 2      (p * V = buoyant force

w2 / w1 = (d2 - p) / (d1 - p)    the liquid exerts the same buoyant force on each ball

Let p be in units of kg / m^3 * g       say 1 N / m^3

Suppose d1 = 2 and d2 = 3     N/m^3 and p = .5 N/m^3

The ratio of apparent weights would be

w2 / w1 = (3 - .5) / (2 - .5) = 1.67 to 1

Answer:

35.2 AU

Explanation:

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

[tex]\boxed{T^2 \propto a^3 \implies T^2=ka^3}[/tex]

Kepler's Third Law

[tex]T^2=\dfrac{4 \pi^2}{GM}a^3[/tex]

where a is the semi-major axis of the ellipse.

If expressed in the following units:

then:

[tex]\implies\dfrac{4 \pi^2}{GM}=1[/tex]

Therefore Kepler's Third Law can be expressed as:

[tex]\boxed{T^2=a^3}[/tex]

Given:

From inspection of the given diagram:

[tex]\implies 2a=x+0.57[/tex]

[tex]\implies a=\dfrac{x+0.57}{2}[/tex]

Substitute these values into the equation and solve for x:

[tex]\implies (75.6)^2=\left(\dfrac{x+0.57}{2}\right)^3[/tex]

[tex]\implies (75.6)^\frac{2}{3}=\dfrac{x+0.57}{2}[/tex]

[tex]\implies 2(75.6)^\frac{2}{3}=x+0.57[/tex]

[tex]\implies x=2(75.6)^\frac{2}{3}-0.57[/tex]

[tex]\implies x=35.1883819...[/tex]

[tex]\implies x=35.2\; \text{AU}[/tex]

Answer:

seismic waves

Explanation: