As the car falls off the cliff, what is happening to the kinetic energy of the falling car?

Answers

Answer 1

Answer:

It loses potential energybut gains kinetic energy.

Explanation:

Answer 2
As the car falls of the cliff, kinetic energy increases while potential energy is decreasing.

Related Questions

What type of motion a particle has if its velocity-time graph is as mentioned below? i) Graph is parallel to the time axis ii)Graph is a straight line passing through the origin and having a constant slope.​

Answers

The velocity time graph is used to plot the velocity of a body against the time.  

What is the velocity time graph?

The velocity time graph is used to plot the velocity of a body against the time.  The slope of this graph is called the velocity.

Now the following are true regarding the scenarios below;

Graph is parallel to the time axis - This is constant velocity

Graph is a straight line passing through the origin and having a constant slope. - There is a uniform acceleration.

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Determine the force p required to (a) raise and (b) lower the 40-kg cylinder at a slow, steady speed. the coefficient of friction between the cord and its supporting surface is 0.30.

Answers

Answer:

T - M g - Ff = M a     describes the acceleration of the object

T = M g + Ff      if the object moves at constant speed  (a = zero)

Ff = μ M g = .3 * 40 * 9.8 = 118 N     the force of friction

Ff will be in a direction opposite to the motion

M g = 40 kg * 9.8 m/s = 392 N

a) T = M g + Ff   for an object moving upwards

T = 392 + 118 = 510 N

b) T = M g - Ff     for an object moving downwards

T = 392 - 118 = 274 N

the yacht shown below has a mass of 8300kg. determine its weight in air [ Acceleration due to gravity, g = 10 N kg¹
[tex]w = mg [/tex]

Answers

Answer:

83000kg

Explanation:

mass=8300kg

g=10

w=mg

8300×10=83000kg

A spring with a spring constant of 350 N/m pulls a door closed. How much work is done as the spring pulls the door at a constant velocity from an 85.0-cam stretch to a 5.0-cm stretch?

Answers

The work done to stretch the spring will be 112 J.

What is spring force?

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

The given data in the problem is;

F is the spring force =?

K is the spring constant= 8.5 N/m

x is the length by which spring got stretched = 1.2m

The work is done to stretch the spring is;

[tex]\rm W= \frac{1}{2} kx^2 \\\\ W=\frac{1}{2} \times 350 \times (0.850-0.050)^2 \\\\ W=0.5 \times 350 \times (0.80)^2 \\\\W=112 \ J[/tex]

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Scientists are making plans to put a probe in orbit around Earth. They want the probe to enter the orbit shown below.

An illustration of the earth with a concentric circle around the earth with arrowheads in the counterclockwise direction. At the top of the circle is a black dot with a vector labeled Y away from the center of the circle, a vector labeled W toward the center of the circle, a vector tangent to the circle and clockwise labeled Z and a vector labeled X tangent to the circle and counterclockwise.
Which arrow shows the direction that the probe should be moving in order for it to enter the orbit?

Answers

An arrow which shows the direction that the probe should be moving in order for it to enter the orbit is X.

What is an orbit?

An orbit can be defined as the curved path through which a astronomical (celestial) object such as planet Earth, in space move around a Moon, Sun, planet or star.

In this scenario, if the scientists want the probe to enter the orbit they should ensure that probe moves in direction X. This ultimately implies that, the probe must move in the same direction as the orbit, in order to enter it.

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Answer:

(b)

Explanation:

X

This diagram shows half of the magnetic field of a bar magnet. Carefully draw in the other
half of the field.
Which way does the magnetic field go? Tick the correct box.
From the north pole to the south pole of the magnet. From the south pole to the north pole of the magnet..

Answers

Answer:

Explanation:

If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?

Answers

The kinetic energy of the phone right before it hits the ground is 9J.

Kinetic energy of the phone

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

m is mass of the phonev is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

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If the _ of the proteins changes, this is called a mutation

Answers

Answer:

If the DNA of the proteins changes, this is called a mutation.

Explanation: Hope it helps you :))))

Have a good day

Click this link to view O*NET’s Work Styles section for Postal Service Mail Carriers. (Common work styles are listed near the top and less-common work styles are near the bottom.) According to O*NET, which common work styles do Postal Service Mail Carriers need? Select four options.

dependability
creativity
leadership
integrity
self-control
attention to detail

Answers

The common work styles do Postal Service Mail Carriers need creativity, integrity, self-control and attention to detail.


What is postal mail service carriers?

They commonly sort mail and orchestrate it arranged by their conveyance course. They convey the mail by walking or any vehicle. They also gather mail and convey it to the post office. Mail transporters answer clients inquiries, provide forms, and look out for surprising conditions on their course.

Thus, the common workstyles they should need to have are creativity, integrity, self-control and attention to detail.

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Answer:

1456

Explanation:

Every summer I drive to Pennsylvania. It is 895 km to get there. If I average 100 km/hr, how much time will I spend driving?

Answers

Answer the time you bee spending driving iss 795 because 895-795=100

Explanation:

A car started its journey at point A. After 30 seconds, the car had reached point B. The car stops at point B for 10 seconds. Then, the car turned around and arrived at point A after 15 seconds. The car stopped at point A for 20 seconds. The car then went on his way and get to the point C after 10 seconds. Find the velocity from 30 to 40s

Answers

Since the displacement is equal to zero, the velocity from 30 to 40s will also be zero.

Velocity

Velocity is the distance travelled by a body in a specific direction per time taken. It is measured in meter per second. That is, m/s

Given that a car started its journey at point A. After 30 seconds, the car had reached point B. The car stops at point B for 10 seconds. Then, the car turned around and arrived at point A after 15 seconds. The car stopped at point A for 20 seconds. The car then went on his way and get to the point C after 10 seconds.

To find the velocity from 30 to 40s, we must realize that velocity can also be defined as;

Velocity = displacement / time

The displacement from point A to B and back to A is equal to zero.

Therefore, The velocity from 30 to 40s is also zero.

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How are distance and displacement related?​

Answers

Answer: They both give us a notion about the position of an object

Explanation:

Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0°.

If the ball moves through the air for 3.2 seconds, what is the horizontal distance traveled by the ball? Round your answer to the nearest tenth.

Answers

Answer: 30

Explanation:

A motor with a power of 7.0 × 104 watts lifts a loaded elevator to a height of 20.00 meters for 40 seconds. what is the force exerted by the motor on the elevator? a. 1.4 × 104 newtons b. 7.0 × 104 newtons c. 1.4 × 105 newtons d. 2.1 × 105 newtons e. 3.5 × 105 newtons

Answers

Answer:

  c.  1.4×10^5 N

Explanation:

Work is the product of power and time. It is also the product of force and distance. We can equate these two products to find the distance.

__

  Wt = Fd

  (7.0×10^4 N·m/s)(40 s) = F(20 m)

  F = (7.0×10^4)(40/20) N = 1.4×10^5 N

The force exerted by the motor is 1.4×10^5 newtons.

The 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate.

Answers

The direction of the friction force F exerted by the horizontal surface on the crate will be in the left direction.

How to depict the force?

From the information given, the 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied.

mg = 200 ×  0.2248 × 9.8 = 440.608

The static friction force will be:

= 0.5 × 440.608

= 220.304N

Therefore, the static friction is greater than the force applied. Therefore, there'll be a static friction acting on the box on the left direction.

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Two 1-kg objects, C and D, increase in temperature by the same amount, but the
thermal energy transfer of object C is greater than the thermal energy transfer of
object D. If object C has a specific heat of 235 J/kg-K, which material might object
D be made of?
(A) aluminum
(B) brass
(C) iron
(D) lead

Answers

The object D is made up of material Lead. The correct option is D.

What is specific heat?

The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.

Two 1-kg objects, C and D, increase in temperature by the same amount, but the thermal energy transfer of object C is greater than the thermal energy transfer of object D. The object C has a specific heat of 235 J/kg-K.

Q = m C ΔT

Qc > Qd

The energy transfer is proportional to specific heat.

Specific heat of D must be less. The possible material with specific heat less than the given value is for Lead material.

Thus, the correct option is D.

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If a rock is thrown downward with an initial speed 6ms then what is the rocks velocity after 4 sec

Answers

Answer:

[tex]\huge\boxed{\sf V_f=45.2 \ m/s}[/tex]

Explanation:

Given Data:

Initial velocity = [tex]V_i[/tex] = 6 m/s

Time = t = 4 sec

Acceleration due to gravity = g = 9.8 m/s²

Required:

Final velocity = [tex]V_f[/tex] = ?

Formula:

[tex]v_f=v_i+gt[/tex]

Solution:

Put the givens in the formula

[tex]V_f=6 +(9.8)(4)\\\\V_f=6+39.2\\\\V_f=45.2 \ m/s\\\\\rule[225]{225}{2}[/tex]

What would happen if the atmosphere consisted of pure oxygen.

Answers

Answer:

Then our fires would become massive.

Explanation:

Hope this helps

Engineers are trying to improve a race car. Their goal is to increase the acceleration of the car using the same engine. Which change shows the best application of Newton’s laws of motion to achieve this goal?

increasing the inertia of the car
decreasing the reaction force
increasing the action force
decreasing the mass of the car

Answers

Decreasing the mass of the car will help increase the acceleration of the car using application of Newton’s laws of motion.

What is Newton's law of motion?

This law discusses the relationship between motion of a substance and the forces acting on it.

Heavy objects are more difficult to move which is why decrease in mass will help increase the acceleration.

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Answer: decreasing the mass of the car

Explanation: this is for a TLDR trust

Please select the word from the list that best fits the definition
the resistance of an object to moving or to stopping
a. gravity
b. inertia
c. gravitational force

Answers

Answer:

inertia

Explanation:

the resistance of an object to moving or to stopping

a. gravity

b. inertia

c. gravitational force

how does the egg drop project apply to everyday life​

Answers

Answer:

Explanation:

It apply on how you will protect the egg because you protect the egg at all cost. It's very similar on who is protecting you, You need someone to be there for you always because an egg can't survive on it's own. Just like your life your can't be always rolling around like an egg you need to be safe and always with the person who cares for you. An egg is safe when they are together in a tray just like family and friends.

A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 16 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 35 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
OA. 5420 N
OB. 3360 N
OC. 4280 N
O D. 6550 N

Answers

The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

Conservation of energy

The amount of energy lost due to  air resistance while she was bouncing is determined from the principle of conservation of energy.

ΔE = P.E - Ux

ΔE = mgh - ¹/₂kx²

ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²

ΔE = 3,360 J

Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

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When the defibrillator is in use, a potential difference of 4800 V is applied across the
person's chest.
A charge of 0.16 coulombs passes through the person's chest in 4.0 ms
Calculate the resistance of the person's chest.

Answers

If a defibrillator is in use with the given potential difference and charge in the given time, the resistance of the person's chest is 120 Ohms.

What is the resistance of the person's chest?

From Ohm’s law;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that;

Potential difference v = 4800VCharge Q = 0.16CTime elapsed t = 4.0ms = ( 4/1000 )s = 0.004sResistance R = ?

First, we calculate the current I.

Since current is the electric charge transferred per unit time.

I = Q/t

I = 0.16C / 0.004s

I = 40A

Now, the resistance of the person's chest will be;

V = I × R

R = V / I

R = 4800V / 40A

R = 120Ω

Therefore, If a defibrillator is in use with the given potential difference and charge in the given time, the resistance of the person's chest is 120 Ohms.

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8. A round tube weighs 30 kg. If the tube is stood on end, it pushes down on the floor with a pressure of 20 N/m². How many square inches is the end of the tube​

Answers

Answer:

22785 square inches

Explanation:

As the mass of the tube is 30kg, therefore it is exerting a force of 30g N(30g = 30 × 9.8 = 294)So the force is 294 N.Pressure is 20 N/m², as given.As we know Pressure is equal to the force exerted per unit area (P=F/A).Therefore, A=F/P

        A = 294 ÷ 20 = 14.7 m²

As 1 m² = 1550 square inches. Therefore, 14.7 m² = 14.7 × 1550 square inches = 22785 square inches

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Pls help me l will make it brainlest ​

Answers

Answer:

0.04 °C⁻¹

Explanation:

First, we need to calculate linear expansivity, then after finding that value, we can move on to finding the area expansivity.

=============================================================

Finding Linear Expansivity :

⇒ α = Final length - Original length / (Original length × ΔT)

⇒ α = 9 - 4 / (4 × 70 - 20)

⇒ α = 5 / 5 × 50

⇒ α = 0.02

============================================================

Finding Area Expansivity :

⇒ Area Expansivity = 2 × Linear Expansivity

⇒ β = 2 × α

⇒ β = 2 × 0.02

⇒ β = 0.04 °C⁻¹

Calculate the value of the area expansion of a steel rod of lenght 4cm at 20°c after heating attains another length of 9cm at 70°c.

Area = 0.02

Area Expansity = [tex]0.0 {4}^{ - 1} [/tex]

3 What is the displacement of a satellite when it makes a complete round along its circular path?​

Answers

Answer:

0

Explanation:

The displacement is zero since it goes in a full circle and ends up where it started.

To fully complete this project, you will submit the following: complete the data table with values that you determine from the video and calculated. find the average wave speed as asked for in question 3. find the mathematical speed of sound as asked for in question 4. show your calculation. answer to question 5 in complete sentences.

Answers

Since no data table was provided, the wave speed be calculated by taking the mean of speed values.

Also, the mathematically derived speed of sound is 343 m/s at 20 °C.

What is speed of sound in air?

Sound is an example of a mechanical wave and require a material medium for it's transmission.

The speed of sound in air has been determined to be about 343 m/s at 20 °C.

The average wave speed can be calculated using the formula:

Average wave speed = (initial speed + final speed)/2

The formula relating speed of a wave, frequency, and wavelength is given below:

Speed = wavelength × frequency.

It is important to note that in this question, no data table or video was provided.

Therefore, the wave speed be calculated by taking the mean of speed values obtained in the experiment as shown in the video.

Also, the mathematically derived speed of sound is 343 m/s at 20 °C.

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When the switch is closed electrons will flow from.

Answers

The statement is true, when the switch is closed electrons will flow.

What is current?

Current can be defined as the rate of flow of charges or electrons in a given circuit.

Q = It

I = Q/t

where

Q is charget is timeI is currentWhat is a Closed circuit?

A closed circuit is a type of circuit in which the wire connection of the circuit is complete and in which current flows.

Switch can be used close or open a circuit.

Thus, the statement is true, when the switch is closed electrons will flow.

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Calculate the energy used by a radio of power 30W in 1 minute.

Answers

Answer:

1.8kJ

Explanation:

Formula :

Energy used = Power x time

===============================================================

Given :

⇒ Power = 30 W

⇒ Time = 1 minute = 60 seconds

=============================================================

Solving :

⇒ Energy used = 30 W × 60 s

⇒ Energy used = 1,800 J

⇒ Energy used = 1.8kJ

Answer:

1800 joule (1.8kJ)

Explanation:

Formula:

Power = Work / Time

30 = Work / 60

Work = 1800 joule

Work = 1.8kJ

Energy = Work done = 1.8kJ

Hence, Energy used is 1.8kJ.

A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. what is the vertical velocity of this motion? a. 18.3 meters/second b. 43.3 meters/second c. 25.0 meters/second d. 28.9 meters/second e. 32.1 meters/second

Answers

A bicyclist moving at a constant speed takes 10.0 seconds to travel 500 meters down a path inclined 30.0° downward from the horizontal. the vertical velocity of this motion is mathematically given as

V' = 25 m/s. Option C.

What is the vertical velocity of this motion?

Generally, the equation for the Inclined Component is mathematically given as

V=d/s

Therefore

V = 500/10

V= 50 m/s

In conclusion, for the vertical Component

[tex]V'= dsin \theta[/tex]

V'= 50Sin30

V' = 25 m/s

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