Answer:
0.1962N.
Explanation:
Weight is a force, so we use newtons second law which states F=ma. So the weight of a watermelon on earth is 2kg x 9.81m/s², which is 19.62N (newtons). On the moon it weighs 2 x 1.63 which is 3.26N.
The weight of the pen is 0.02 x 9.81, which is 0.1962N. If the pen is not to fall the frictional force needs to be equal to this force,
so the answer is 0.1962N.
(Hope this helps can I pls have brainlist (crown)☺️)
How does the law of conservation of mass apply to this reaction: Mg + HCI + H2 MgClz?
O The equation needs to be balanced. There are fewer hydrogen atoms in the equation than magnesium or chlorine.
© Only the hydrogen needs to be balanced. There are equal numbers of magnesium and chiorine.
Hydrogen and chlorine need to be balanced. There is an equal amount of magnesium on each side
©
The
law of conservation of nÖss has already been
the equation.
applied. There is an equal number of each element on both sides of
saan natin maaaring ipinta ang myural
Answer:
wall,ceiling or other permanent surfaces
Please help me with these answers
Answer:
question 1 is centripetal acceleration question 2 is 4
Explanation:
centripetal acceleration basically is acceleration that only changes velocity but not speed, while for question 2, you divide 10 by 2.5
A drag racer starts at rest and reaches a speed of 386.0 km/h with an average acceleration of 16.5 m/s2. How long does this acceleration take?
Answer:
about 16.5 by-
wait DO UR OWN MATH lol
Explanation:
axit amin có chức năng gì sau đây
Answer:
i dont understand sorry
A ship left the dock and travelled north at 50km/hr for 2 hours then it turned west at 60km/hr for 3 hours. What is the net resultant displacement vector R
Answer:
resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.
Explanation:
assume that the ship started moving from A to B (north at 50km/hr for 2 hours) so the covered distance will be: 50*2 = 100 km
then it moves from B to C so the covered distance will be: 3*60 = 180 km
using Pythagoras, we get the resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.
ILL GIVE U BRAINLIEST!! help me
one or two sentences state whether you would expect the conditions to be a greater hazard for diversity dive down where is the return to the surface and explain your production in terms of gases define prescient
Answer:
Solubility in gasses and liquids increase as pressure increases. This is due to colligative properties. The nitrogen gas levels would increase the farther the diver dives due to the increase of pressure causing the solubility of the nitrogen to increase, thus increasing the amount of it as you go deeper in the ocean.
Explanation:
As they plummet down, the driver would be in more risk. The solubility of gases and liquids increases as pressure increases. This is due to the existence of colligative properties. The nitrogen gas levels grow when the diver descends further into the water due to increased pressure, which causes the nitrogen's solubility to rise, increasing the amount of nitrogen present.
Problem 4:
A body fell vertically from the top of a tower. It covered 123.1 m in the final two seconds
before hitting the ground. Determine the height of the tower rounding your answer to the
nearest two decimal places. Let the acceleration due to gravity g=9.8 m/s2.
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
the total amount of power that a star radiates is called its
Why can’t you compress gas but you cannot compress a liquid
what is the use of telescope
Answer:
The use of a telescope is to see distant objects
Explanation:
For example: you can look through a telescope to see constellations and stars. Hope this helps <3
consider the collision between a car and a light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored
The truck applies the same force to the car that the car applies to the truck. The truck applies the same force to the car that the car applies to the truck. According to Newton's third law, action and reaction have the same magnitude and move in the opposite direction.
What is force?Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.
The direction of the force is the point where force is applied, and the application of force is the point where force is applied.
The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, which are laid out in his Principia Mathematica.
The truck exerts the very same force on the car as the car exerts on the truck. The truck exerts this very same force on the car as the car exerts on the truck.
Action and reaction have the same amplitude and move in the opposite direction, according to Newton's third law.
Thus, this can be the comparison in the given scenario.
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Your question seems incomplete, the complete question is:
Consider the collision between a car and a
light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored.
Compare the forces if the light truck is standing
still when the car hits it.
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal
We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the book is
F=44N
From the question we are told
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as
[tex]F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\[/tex]
F=44N
Therefore
the minimum force that must be applied on the book is
F=44N
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How could you set up the Strong and Weak magnets to show Barry that strong magnets and weak magnets can BOTH repel and attract object's?
Answer:
To show that magnets repel, you must place the strong and weak magnets to another magnet with their poles being both south or both north facing eachother.
To show they attract, place opposite poles near eachother.
How do interest groups and PACs keep us from
our democratic principles? How do they defeat democracy? Look at picture for the question please
Answer:
Interest groups help democracy because they represent the interests of such large numbers of people and encourage political participation by many groups. The stable, cooperative relationship often develops among a congressional committee, an administrative agency, and one or more supportive interest groups.
Interest groups try to influence the government to adopt legislation that would benefit them. Email, letter, faxes, phone calls, providing research and information (to bring about change by proving your cause with facts by funded research).
PLEASE HELP ME!! WILL MARK BRAINLIEST!!!
How many moles of glucose, C6_H12_O6, are in 300 g of glucose? Show your work.
Which of the following is an example of a buoyant force acting on an object?
A. The object remains still despite an applied force.
B. The object travels with straight-line horizontal acceleration.
C. The object floats on top of a fluid.
D. The object travels in uniform circular motion.
Answer:
option c theobject floats on top of a fluidwhat type of wavelengths do ultraviolet rays have?
According to who.int,
"The UV region covers the wavelength range 100-400 nm and is divided into three bands: UVA (315-400 nm) UVB (280-315 nm) UVC (100-280 nm).Mar 9, 2016"
in short 100-400nm
how can you reduce the percentage uncertainty in measurements that you make?
Answer:
For example, one method for estimating the length of time it takes something to occur is to time it once using a stopwatch. You can reduce the uncertainty in this estimate by repeating the measurement and taking the average.
There are a lot of way to reduce the uncertainty however with real life sciences like quantum mechanics it will reveal more about the world and life if we have better measuring tools. Being precise is essential to understanding many parts of life.
Hope this helped! Have a great day!!!
An object is moving initially with a velocity of 5.6 m/s. After 3.1 s the object's velocity is -2.7 m/s. What is the object's average acceleration during this time
Answer:
-2.68m/s²
Explanation:
To find acceleration use the formula:
acceleration = change in velocity ÷ time
change in velocity = -2.7 - 5.6 = -8.3m/s (final velocity - initial velocity)time = 3.1sSubstitute in the values:
acceleration = -8.3 ÷ 3.1
acceleration = -2.67741.. ≈ -2.68m/s²
Hope this helps!
what are the properties of gravitational force
Explanation:
It obeys the inverse square law.
It is always attractive in nature.
It is a long range force. ...
The graviton is the field particle of gravitational force.
Answer:
Gravitational force−Properties:
(1) It is a universal attractive force. It is directly proportional to the product of the masses of the two bodies.
(2) It obey inverse square law.
(3) It is the weakest force known in nature.
13 Henry Wadsworth Longfellow, John Greenleaf Whittier, Oliver Wendell Holmes, and James Russel Lowell were known as
Answer:
William Cullen Bryant, Henry Wadsworth Longfellow, John Greenleaf Whittier, Oliver Wendell Holmes, and James Russell Lowell. These five men made up a group of poets known as the Fireside Poets or the Schoolroom Poets.They were hugely popular in the second half of the 19th century, like the pop stars of their time.
Explanation:
hope this helps if not let me know
an object applies force of 500n on the area if 10m². find the force exerted
Exerted force is called Pressure.
From,
Pressure = Force/Area
P = 500N/10m²
P = 50N/m²
The force exerted is 50N/m²
what is the relationship between electric field lines and equipotential surfaces?
Helppppppp pleaseeee
Answer: (Sorry, but I don't know how to calculate mass)
1. 15 N
2. 0.4921 [tex]\frac{ft}{s^2}[/tex] (feet per second squared)
4. 150 N
5. 8.202 feet per second squared
I NEED A SCIENCE EXPERT TO GIVE ME THE RIGHT ANSWER TO THESE ASAP NO LINKS !!!
Answer:
1 st question: Control variable
2nd question: random variable
3rd question: if the two objects are dropped from the same height they will hit the ground at the same time
Answer:
it IS the control variable
Explanation:
a bicyclist travels with an average velocity of 15km/h north, for 20 minutes .what is his displacement ?
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Displacement is equal to ~
[tex]5 \: \: km[/tex]See the attachment for solution ~
Answer:
It is 24000meter per second
Please help I'll mark brainliest NO LINKS
Answer:C
Explanation:
For parallel connection
1/R=1/R1+1/R2+1/R31/R=1/12+1/6+1/41/R=1+2+3/121/R=1/2R=2ohmFor series connection
Net resistance
R=2+3=5ohm5.) How could we have improved this activity to be more precise?
ball on ramp
Explanation:
I don't understand this question
could you please explain
Explanation:
Well ball on ramp .Which factors are affected?
Centre of massAcceleration due to gravity Mass of ball .Force appliedSo if we put the ball right above the centre of mass it can be best stabled
A student drops a ball off the top of building and records that the ball takes 2.55s to reach the ground. Determine all unknowns and answer the following questions. Neglect drag.
The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
The given parameter;
time of motion of the ball, t = 2.55 sThe equations that model the motion of the ball is given as follows;
[tex]h = v_0_y + \frac{1}{2} gt^2[/tex]
[tex]v_f = v_0_y + gt[/tex]
All the unknown variables in the equations include;
[tex]v_0_y[/tex] is the initial vertical velocity of the ball, = 0g is the acceleration due to gravity = 9.8 m/s²h is the vertical distance traveled by the ball = ?[tex]v_f[/tex] is the final velocity of the ball = ?The vertical distance traveled by the ball is calculated as follows;
[tex]h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m[/tex]
The final velocity of the ball is calculated as follows;
[tex]v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s[/tex]
Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
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