An unknown compound is not soluble in water, but dissolves in a 5% solution of NaOH. a) What conclusions can you made about the molecular weight and functional group identity of this unknown compound? b) Draw the structure of an organic compound that would produce these experimental results. Draw the form of the molecule that would exist in the 5% NaOH solution.

Answer:  fuel and oxygen are reactants.

Explanation:

Answer:

fuel and oxygen

Explanation:

I take test

Answer:

Explanation:

because

Neon and Krypton, both are belongs to Inert or Noble gas Group

Answer:

Potassium Permanganate

Explanation:

A solution is defined as the mixture of two or more substances. The substance that is in big proportion is called as Solvent, the substance that is in low amount is called as Solute.

In an aqueous solution, the solvent is the water. As the aqueous solution is 0.879M KMnO4, the solute is:

Answer:

You need 375 mL of BaCl2 solution.

Explanation:

M1V1=M2V2

Dilution formula. Substitute known values and solve for V1.

M1 = 2.0 M

M2 = 1.50 M

V2 = 500 mL

(2.0 M)(V1) = (1.50 M)(500 mL)

V1 = (1.50 M)(500 mL) / (2.0 M)

V1 = 375 mL

Answer:

ok i dont get your question fully but i'll answer

When copper sulfate is dissolved in water in a beaker, a bright blue liquid or solution is formed. If copper sulfate is added until no more will dissolve, a saturated solution is formed. And some blue crystals will remain at the bottom of the beaker due to crystallization reaction. It is the process by which a solid form, where the atoms or molecules are highly organized into a structure known as a crystal.

The correct answer among the given options in the question is option "b. A good leaving group is a weak base"

Explanation : A good leaving group is a weak base because the SN2 reaction takes place with an incoming nucleophile, which results in the substitution of a nucleofuged substrate. Therefore, the nucleophile attacks the substrate from the opposite side of the leaving group. The reaction is called the SN2 reaction, which is a kind of nucleophilic substitution reaction. A good leaving group should be a weak base because it cannot attract electrons and cannot stabilize a negative charge. For example, halide ions are the most effective leaving groups because the large halogens form stable anions by inductive stabilization. Therefore, a weak base is a good leaving group.

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The Ksp for PbCl₂ at 298 K is approximately [tex]1.12 \times 10^{(-5)}[/tex].

To determine the Ksp (solubility product constant) for PbCl₂ at 298 K, we can use the Nernst equation and the standard reduction potentials of the PbCl₂/Pb and Pb²⁺/Pb couples.

The balanced half-reactions for the two couples are as follows:

PbCl₂ + 2e⁻ → Pb + 2Cl⁻

Pb²⁺ + 2e⁻ → Pb

Given that the standard reduction potentials (Eo) for the PbCl₂/Pb and Pb²⁺/Pb couples are -0.268 V and -0.126 V, respectively, we can calculate the standard cell potential (E°cell) using the equation:

E°cell = E°reduction + E°oxidation

E°cell = -0.268 V + (-0.126 V)

E°cell = -0.394 V

Now, we can use the Nernst equation to relate the cell potential to the Ksp:

Ecell = E°cell - (RT / nF) ln(Q)

Since the reaction quotient (Q) for the precipitation of PbCl2 is equal to the concentration of Pb²⁺ and Cl⁻ ions, and assuming standard conditions (T = 298 K, n = 2, and F is the Faraday constant), we can simplify the equation to:

Ecell =E°cell - (0.0592 / 2)log10(Q)

Since the reaction is at equilibrium, the cell potential (Ecell) is zero. Therefore, we can rewrite the equation as:

0 = E°cell - (0.0592 / 2) log10(Ksp)

Solving for Ksp, we have:

[tex]Ksp = 10^{(\frac {E^{0}cell}{\frac {0.0592}{2}})}[/tex]

[tex]Ksp = 10^{(\frac {-0.394}{\frac {0.0592}{2}})}[/tex]

Calculating this expression gives us:

Ksp ≈ [tex]1.12 \times 10^{(-5)}[/tex]

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Answer:

9.

Explanation:

.

Answer:

Consumers must consume other organisms to get the food that they need and are known as Heterotrophs as they cannot make their own glucose. These consumers eat producers (plants). Herbivores are considered as first order consumers. These consumers eat consumers and producers (animals and plants).

Since we have sufficient sodium fluoride (NaF), the magnesium (Mg) will be our limiting reactant, and we will use its coefficient in the balanced equation to determine our molar ratio between the product of interest which, in this case, is sodium (Na).

We are given the mass of magnesium, 23.56 grams, which we must convert to moles by dividing the mass by the molar mass of magnesium: (23.56 g)/(24.305 g/mol) = 0.9693 mol Mg.

According to the balanced equation given, the molar ratio between sodium and magnesium is 2:1. That is, for every 2 moles of Na that are produced, one mole of Mg is consumed or reacted. The upshot is that the number of moles of sodium produced will be double the number of moles of Mg reacted. Since we have 0.9693 moles of Mg available to react, we will obtain (0.9693 mol Mg)(2 mol Na/1 mol Mg) = 1.939 mol Na.

Finally, we multiply our moles of sodium by the molar mass of sodium to get the mass: (1.939 mol Na)(22.99 g/mol) = 44.57 grams Na.

So, 44.57 grams of sodium will be produced.

The answer is given to four significant figures.

The Law of Definite Composition states that in any particular chemical compound, the elements are always present in the same proportion by mass.

Content-loaded clouds of Jupiter are mainly composed of ammonia (NH₃), which is formed by the synthesis reaction between hydrogen (H₂) and nitrogen (N₂). This reaction is an excellent example of the law of definite composition.

Ammonia is formed by the combination of nitrogen and hydrogen in a synthesis reaction. The reaction produces a compound with a unique formula and mass. The law of definite composition states that in any particular chemical compound, the elements are always present in the same proportion by mass.

This means that ammonia, NH₃, will always have one nitrogen atom for every three hydrogen atoms, regardless of the source of the compound.

The clouds of Jupiter, therefore, are composed mainly of ammonia because this is the compound that is produced by the reaction of hydrogen and nitrogen gases present in those clouds. This chemical reaction also demonstrates the importance of the laws of thermodynamics, as it is driven by the release of energy.

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Answer:

56.2÷6.02×10^23

=9.34×10^23

Explanation:

Divide the given mass of the atom by the mass of an Atom (the avogadro's constant) to find the number of atoms in the given mass.

The required lattice energy of CaBr2(s) is -1851 kJ/mol.

a) The lattice energy is inversely proportional to the size of the ion. The smaller the ion, the more energy required to maintain it. So, the greater the charges on the ions, the higher the lattice energy. The following is the correct ranking:1. MgO2. BeO3. LiCl4. Na2O5. Na2Sb) The Lattice Energy of CaBr2(s) is given by the following expression:Ca(s) + Br2(g) → CaBr2(s) ΔH°f = - 675 kJ/mol ΔH°f (Ca) = 179 kJ/mol ΔH°f (Br) = 112 kJ/mol I1(Ca) = 590 kJ/mol I2(Ca) = 1145 kJ/mol E(Br) = - 325 kJ/mol The following is the correct solution:Ca(g) → Ca+(g) + e- ΔH° = I1(Ca) = 590 kJ/mol Ca+(g) → Ca2+(g) + e- ΔH° = I2(Ca) = 1145 kJ/molBr(g) → Br-(g) ΔH° = E(Br) = - 325 kJ/molCa(s) + Br2(g) → CaBr2(s) ΔH°f = - 675 kJ/mol We may create the following equation by combining the above equations:Ca(s) + Br2(g) → Ca2+(g) + 2Br-(g) ΔH°rxn = - 675 kJ/mol + 2(112 kJ/mol) - 590 kJ/mol - 1145 kJ/mol - (- 325 kJ/mol) ΔH°rxn = - 675 kJ/mol + 224 kJ/mol - 590 kJ/mol - 1145 kJ/mol + 325 kJ/mol ΔH°rxn = - 1851 kJ/mol

Thus, the lattice energy of CaBr2(s) is -1851 kJ/mol.

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Answer:

An element's mass number (A) is the sum of the number of protons and the number of neutrons. The small contribution of mass from electrons is disregarded in calculating the mass number.

The counter ion in the coordination compound [Co(NH3)4Cl2]NO3 is NO3-.

In a coordination compound, there is a central metal ion or atom that is surrounded by ligands. The ligands coordinate to the metal ion through donation of electron pairs. In this compound, the central metal ion is cobalt (Co), which is coordinated to four ammonia (NH3) ligands and two chloride (Cl) ligands.

The counter ion is the ion that balances the charge of the entire coordination compound. In this case, the coordination compound carries a net charge of 0 because the total charges of the ligands (4NH3 with no charge and 2Cl- with a -1 charge each) sum up to 0. Therefore, to balance the charge, a counter ion is required.

The counter ion in this compound is NO3-, which is a nitrate ion. The nitrate ion carries a -1 charge, which balances the overall charge of the coordination compound.

The counter ion in the coordination compound [Co(NH3)4Cl2]NO3 is NO3-. It serves to balance the charge of the coordination compound, which has a net charge of 0 due to the coordination of the ligands.

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Answer:

moles = no. of molecules / Avogadro's number

         = 2.26 x 10^33 / 6.022 x 10^23

         = 3752906011

Round to significant figures which is 3 = 3.75 x 10^9 mol

Explanation: The formula for finding how many moles of a substance when given the amount of molecules is: moles = number of molecules / Avogadro's number

For the following aqueous equilibria;

a. NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

NH₃ (conjugate base) and NH₄⁺ (conjugate acid)

H₂O (conjugate acid) and OH⁻ (conjugate base)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, NH₃ is a weaker base than H₂O, and NH4+ is a stronger acid than OH-. Therefore, the weaker side is the left side of the equation: NH₃(aq) + H₂O(l).

b. HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

HCN (conjugate base) and H₃O⁺ (conjugate acid)

H₂O (conjugate acid) and CN⁻ (conjugate base)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, HCN is a weaker base than H₂O, and H₃O⁺ is a stronger acid than CN-. Therefore, the weaker side is the left side of the equation: HCN(aq) + H₂O(l).

c. NH₄⁺(aq) + CO₃²⁻(aq) ⇌ NH₃(aq) + HCO₃⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

NH₄⁺ (conjugate acid) and NH₃ (conjugate base)

CO₃²⁻ (conjugate base) and HCO₃⁻ (conjugate acid)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, NH₃ is a weaker base than NH₄⁺, and HCO₃⁻ is a stronger acid than CO₃²⁻. Therefore, the weaker side is the right side of the equation: NH₃(aq) + HCO₃⁻(aq).

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Answer:

High pressure.

Explanation:

The weather should have clear skies, if it is a Large "L" it would be could be stormy.

Hope this helps! have a great day!

Answer:

DUE TO GRAVITATIONAL COLLAPSE SOLAR SYSTEM IS FORMED , ORBITS ARE CURVED TRAJECTORIES AND SIZE AND COMPOSTION OF PLANET ARE VERY UNIQUE AND COMPOSED OF ROCKS AND METALS and evolution of solar system has began 4.5 billion years ago,due to gravitational collapse of a small particle from a giant cloud.

Answer:

1O3 --> 1O + 1O2

Explanation:

Put 1 in every blank

Answer:

There are needed 375mL of the 2.0M BaCl₂ solution completing to 500mL with water.

Explanation:

We can find with the volume and concentration of the barium chloride the moles of BaCl₂ required. With the moles and the concentration of our stock solution we can know the volume of the 2.0M BaCl₂ solution required as follows:

Moles required:

0.500L * (1.50mol / L) = 0.750 moles BaCl₂

Volume stock solution:

0.750 moles BaCl₂ * (1L / 2.0mol) = 0.375L

Answer:

the answer is A,atomic number

Hydrogen is the only exception, as it has only one valence electron.

The Lewis symbol for an atom includes its symbol and valence electrons represented as dots. The following are the Lewis symbols for neutral atoms with their electron dots and pairs of dots:- Hydrogen (H): 1 electron; Lewis symbol: H •- Helium (He): 2 electrons; Lewis symbol: He ••- Carbon (C): 4 electrons; Lewis symbol: C •• ••- Nitrogen (N): 5 electrons; Lewis symbol: N •• •• •••- Oxygen (O): 6 electrons; Lewis symbol: O •• •• ••••- Fluorine (F): 7 electrons; Lewis symbol: F •• •• ••• •••The number of valence electrons for each atom is determined by the group number on the periodic table. Hydrogen is the only exception, as it has only one valence electron.

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The  true statement is, the leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.

Nucleophilic acyl substitution describes a class of substitution reactions involving nucleophiles and acyl compounds.

Also, nucleophilic acyl substitution is a type of substitution reaction involving an acyl group and a nucleophile.

Thus, the statement that is true regarding nucleophilic acyl substitution is, the leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.

Thus, in nucleophilic acyl substitution, a nucleophile displaces the leaving group, resulting in a carbonyl compound.

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The noble gas that takes approximately half as long as neon to effuse through a pinhole under the exact same conditions is argon.

The rate of effusion for a gas is inversely proportional to the square root of its molar mass. The molar mass of neon (Ne) is approximately 20.18 g/mol, while the molar mass of argon (Ar) is approximately 39.95 g/mol.

Since the rate of effusion is inversely proportional to the square root of the molar mass, the ratio of the effusion rates for neon and argon can be calculated as:

(√Molar mass of argon) / (√Molar mass of neon) = (√39.95) / (√20.18) ≈ 1.41

This means that neon effuses at approximately 1.41 times the rate of argon under the same conditions. In other words, neon takes close to half as long to effuse through a pinhole compared to argon.

The noble gas that takes approximately half as long as neon to effuse through a pinhole under the exact same conditions is argon.

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Answer: I don’t know sorry

Explanation:

Answer: The standard emf for each of the following reactions are:

1. 2.87V    2. 3.21V   3. -3.91V.

Explanation: The standard emf of the given reaction is given by the formula:EMF= E°(reduced) - E°(oxidized)

1. H2(g) + F2(g) → 2H+(aq) + 2F-(aq).The balanced equation is:H2(g) + F2(g) → 2H+(aq) + 2F-(aq)The standard reduction potentials are given by:E°(H+(aq)/H2(g)) = 0V and E°(F-(aq)/F2(g)) = +2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 2.87 - 0= 2.87V

2. Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq).The balanced equation is:Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq)The standard reduction potentials are given by:E°(Cu2+(aq)/Cu(s)) = 0.34V and E°(Ca2+(aq)/Ca(s)) = -2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 0.34 - (-2.87)= 3.21V

3. 2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The balanced equation is:2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The standard reduction potentials are given by:E°(Cl2(g)/2Cl-(aq)) = +1.36V and E°(Br2(l)/2Br-(aq)) = +1.09V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 1.36 - (5*1.09)= -3.91V.

Hence,The standard emf for each of the following reactions are:1. 2.87V2. 3.21V3. -3.91V.

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Answer:

Explanation:

The first thing that you need to do here is to calculate the theoretical yield of the reaction, i.e. what you get if the reaction has a

100

%

yield.

The balanced chemical equation

N

2

(

g

)

+

3

H

2

(

g

)

→

2

NH

3

(

g

)

tells you that every

1

mole of nitrogen gas that takes part in the reaction will consume

3

moles of hydrogen gas and produce

1

mole of ammonia.

In your case, you know that

1

mole of nitrogen gas reacts with

1

mole of hydrogen gas. Since you don't have enough hydrogen gas to ensure that all the moles of nitrogen gas can react

what you need



3 moles H

2

>

what you have



1 mole H

2

you can say that hydrogen gas will act as a limiting reagent, i.e. it will be completely consumed before all the moles of nitrogen gas will get the chance to take part in the reaction.

So, the reaction will consume

1

mole of hydrogen gas and produce

1

mole H

2

⋅

2 moles NH

3

3

moles H

2

=

0.667 moles NH

3

at

100

%

yield. This represents the reaction's theoretical yield.

Now, you know that the reaction produced

0.50

moles of ammonia. This represents the reaction's actual yield.

In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every

100

moles of ammonia that could theoretically be produced.

You know that

0.667

moles will produce

0.50

moles, so you can say that

100

moles NH

3

.

in theory

⋅

0.50 moles NH

3

.

actual

0.667

moles NH

3

.

in theory

=

75 moles NH

3

.

actual

Therefore, you can say that the reaction has a percent yield equal to

% yield = 75%

−−−−−−−−−−−−−

Consider if the reaction is conducted with 3 moles of hydrogen and 2 moles of nitrogen as it in the balanced reaction, and if only 4.1 g of ammonia is produced, then the percent yield will be 12%.

The ratio of  the actual yield to the theoretical yield multiplied by 100 is the percent yield. No simple reactions can achieve a 100 % yield.

As per the given reaction, 3 moles of hydrogen reacts with 2 moles of nitrogen and produce 2 moles of ammonia. Molar mass of ammonia is 17 g/mol. Thus, 2 moles are 34 g/mol.

Assume that if the theoretical yield is 34 g, then the percent yield for actual yield of  4.1 g is,

4.1 /34 ×100 = 12.1 %.

Now lets assume that only one mole of hydrogen is reacted here, number of moles of ammonia produced by one mole of hydrogen is :

=  1 mole × 2 mol / 3 moles

= 0.66 moles.

0.66 moles = 0.66 × 17 g/mol = 11.22 g.

For a theoretical yield of 11.22 g, the percent yield will be

= 4.1 /11.22

= 36.6 %.

Therefore, by assuming if 3 moles of hydrogen are reacted then percent yield will be 12% for 4.1 g of actual yield and 36 % if only one mole of hydrogen is reacted.

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