Answer:
acceleration = 16 m/s²
Explanation:
According to Newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it keeping the mass of the object constant.
Mathematically,
F ∝ a
It means that When there is no net force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object in all directions. When the net force is increased or decreased by a factor of X, then acceleration also increased or decreased by a factor of X respectively according to Newton's 2nd law of motion. In our case, net force increased by a factor of 2, So acceleration must also increased by a factor of 2.
F = ma
F = 8m N
2F = 16m N
So,
acceleration = 16 m/s²
3
1 point
Which term is equal to velocity change per second?
gravity
O velocity
O speed
Oacceleration
Answer:
acceleration
hope this helps ;>
A meridional pattern:A. favors formation of major anticyclones.B. inhibits the formation of major cyclones.C. brings mild weather to most of the country.D. is not typically associated with substantial precipitation.
A meridional pattern favors formation of major anticyclones.
Around a low-pressure area, cyclones are quick inward air circulation. In the Northern and Southern hemispheres, respectively, the air moves counterclockwise and clockwise.Storms that are violent and unfavorable weather frequently accompany cyclones.Cyclos, which in Greek means a snake's coils, is the root of the word cyclone. Henry Paddington came up with the term because tropical storms in the Arabian Sea and Bay of Bengal resemble coiled sea serpents.In order for air to blow outward in the northern hemisphere and in the southern hemisphere, air must circulate from a central area of high pressure towards the periphery.This is how a flowing system becomes circular: blowing winds are redirected from their paths by the Coriolis force to the right in the Northern hemisphere and to the left in the Southern hemisphere.To know about Coriolis force -
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In an orthogonal cutting operation, the rake angle = -5°, chip thickness before the cut = 0.2 mm and width of cut = 4.0 mm. The chip ratio 3 = 0.4. Determine (a) the chip thickness after the cut, (b) shear angle, (c) shear strain.
a. The chip thickness after the cut is 0.5 mm
b. The shear angle is 21.05
c. The shear strain is 3.086
a. the chip thickness after the cutThe formula is
r = t / tc
where we have r = 0.4
t = 0.2
0.4 = 0.2 / tc
cross multiply
tc = 0.5 mm
b. The shear angle is the angle at which a chip will detach from the work piece when cutting metal.
tan ∅ = r cos α / 1 - r sin α
= 0.4 cos (-0.5) / 1 - 0.4 sin(-5)
= 0.385
∅ = tan ⁻¹0.385
∅ = 21.05
c. When a medium is subjected to a lateral force, shear strain results. It is possible to produce a shear force wave that moves perpendicular to the direction of the applied force.
r = cot ∅ + tan(∅ - α)
r = cot (21.05)+ tan(22.05 -(-5)
r = 2.598 + 0.488
= 3.086
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can somebody help me i want to do my homework please
The difference between the two plot is shown clearly by the distance between the two waves.
What is wave?Wave is defined as a disruption in an energy-conducting medium without a net movement of particles. Wind is the most frequent cause of waves. Wind-driven waves, sometimes referred to as surface waves, are created by friction between the wind and the water's surface.
The two difference between the two plot are the first is the difference between the distance of two crust and trough between the wave in the plot. The second difference is that the first plot is between displacement and distance from the source and the second graph is plot between displacement and time.
Thus, the difference between the two plot is shown clearly by the distance between the two waves.
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The stars of the milky way are all near a great circle on the celestial sphere. This great circle.
On the celestial sphere, a large circle contains all of the Milky Way's stars. This enormous circle is known as the milky circle. The Milky Way Galaxy is a massive spiral structure with several hundred billion stars, including the sun.
What is the Milky way galaxy?The Milky Way galaxy, which contains our solar system, gets its name from how it appears in the night sky from Earth: a hazy strip of light made up of stars that are too close together to be seen separately.
What are Stars?An astronomical object known as a star is made up of a bright plasma spheroid that is held together by gravity. The Sun is the star that is closest to Earth. Other stars are also visible at night with the unaided eye, but because of their great distances from Earth, they appear as stationary points of light.
Hence, On the celestial sphere, a large circle contains all of the Milky Way's stars. This enormous circle is known as the milky circle. The Milky Way Galaxy is a massive spiral structure with several hundred billion stars, including the sun.
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a rc circuit is consutructed with a (intiialy uncharged) 5 uf capactiro and a 5-ohm resistor which are connected in series to an ideal battery with emf 60
a rc circuit is constructed with a (initially uncharged) 5 uf capacitor and a 5-ohm resistor which are connected in series to an ideal battery with emf 60 is Q = CV = 9.5 x 10^-6 x 70 = 6.65 x 10^-4 C
What is constructed?
To create something by combining or arranging various pieces or components: the act of building a bridge. also: invent and contrive. put together a plan. to create a drawing of a geometrical figure using the appropriate tools and under the required circumstances
a) time constant = RC = 16.5 x 10^3 x 9.5 x 10^-6 = 0.157 s
b) V = V0 ( 1- e ^ -(t/RC))
after very long time,
V = V0 = e = 105 V
c) Q = CV = 9.5 x 10^-6 x 105 = 9.97 x 10^-4 C
d) I = I0 ( e^(-t/RC))
I0 = e/R = 105/16.5x10^3 = 6.36 mA
after very long time I = 0
e) I0/3 = I0 ( e^-t/RC)
e^-t/RC = (1/3)
-t/RC = ln(1/3)
t = 1.10 x RC = 0.172 sec
f)) V = 105( 1 - e^(-t/RC))
V = 105 ( 1 - e^(-(0.172/0.157)) )
V = 70 V
Q = CV = 9.5 x 10^-6 x 70 = 6.65 x 10^-4 C
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A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 231 kg. A small boy of mass m = 48 kg runs tangentially to the merry-go-round at a speed of v = 2.5 m/s and jumps on.
Required the moment of inertia of the merry go round.
a. I = 12 MR2 is the formula for the merry-go-moment round's of inertia.
I = ½ * 231 * (1.3 * 1.3)
I = 195.195 kgm2
b. The boy's angular speed is specified as = v/R = 2.5/1.3 = 1.92 rad/s.
c. I' = I + mR2 is the formula for the merry-go-moment round's of inertia following the boy's jump on it.
I’ = 195.195 + 48 * (1.3 * 1.3)
I’ = 276.315 kg/m2
The conservation of angular momentum principle determines the merry-go-angular round's speed. As a result, I (0) + m R = 'I' and = (48 * 1.92* 1.3) / 276.315 = 0.433 rad/s
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What net force would be required to accelerate a 5 Kg object 2 m/s2? [show all work, including the
equation, substitutions with units, and answer with units]
Answer:
10 Newtons.
Explanation:
F=MA
F=(5kg)(2 m/s^2)
10 N
LAb motion What do the key results indicate?
Answer:The key results explains how you achieve a certain goal. They have to be quantitative, but always measurable in terms of their progress.
Explanation:
What is the total electrical energy used by a 1500 watt hair dryer operating for 6.0 minutes?
a 1500 watt hair dryer uses 1500 J every second.
1500 J = 1500 Ws = 1500/3600 Wh = 0.000417 kWh
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Which equation can be used to solve for acceleration?
0 ₁ = AV
a
O vf = at-vi
0 a = 4/1/20
d
O AV =
The best choice is A. The formula that can be used to calculate the acceleration is a= dv/t
The alteration in a body's velocity with respect to time is referred to as acceleration. Using mathematics, t= dv/awhere: dv is the velocity changeThe amount of time usedMaking the formula's subject the time "t": a =dv/tConsequently, t=dv/a is how the equation that can be utilized to solve the acceleration is written.Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.For more information on acceleration kindly visit to
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a 120kg elevator is supported by a cable in which the the maximum safe tension is 14000N what is the upward acceleration of the elevator
Important Formulas:
[tex]F=ma[/tex]
Force = mass(measured in kg) * acceleration(measured in m/s^2)
__________________________________________________________
Given:
[tex]m=120kg[/tex]
[tex]F=14,000N[/tex]
[tex]a=?[/tex]
__________________________________________________________
Rearrange formula:
[tex]F=ma[/tex]
[tex]\dfrac{F}{m} =\dfrac{ma}{m}[/tex]
[tex]a=\dfrac{F}{m}[/tex]
__________________________________________________________
[tex]a=\dfrac{14,000}{120}[/tex]
[tex]\fbox{a = 116.67 m/s squared}[/tex]
A 120 kg elevator is supported by a cable in which the maximum safe tension is, 14000 N. The upward acceleration of the elevator is 116. 67 m/s².
What is acceleration?Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
This is the formula to calculate the force.
F = ma
we can modify this, a = F/m
Force = mass(measured in kg) x acceleration(measured in m/s²)
Given, mass = 120 kg
Force = 14000 N
Acceleration
Putting the values in the equation
a = F/m
a = 14000 / 120 = 116. 67 m/s²
Therefore, the upward acceleration of the elevator is 116. 67 m/s².
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A ball is projected upward with an initial speed of approximately 30m/s. The diagram at the right represents its position at 1-second intervals of time. At what location will the ball be moving upward with a speed of approximately 10m/s ?
The ball will be moving at a speed of 10m/s when it's at position C.
Using first equation of motion
v=u-at
where
v is final speed
u is initial speed
a is acceleration (here a will be replaced with g as the motion is vertical)
t is time
u = 30m/s
v = 10 m/s
g = -10m/s
By substituting the values ,
10=30 - gr ( taking g as 10)
10t=20
t= 2s
It was given at each position is at the interval of one second each, so the body will be at position C when going upwards at a speed of 10m/s.
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The steps in the heating of the handle of a pan held over a flame are listed below:
Step 1: Heat from the flame travels to the base of the pan
Step 2: Heat from the base of the pan travels through the pan to the part where the handle touches the pan
Step 3: Heat from one end of the handle travels to the other end
By which method is heat transferred in the three steps?
Radiation in Step 1 and conduction in Steps 2 and 3
Conduction in Step 1 and radiation in Steps 2 and 3
Conduction in Step 1 and convection in Steps 2 and 3
Convection in Step 1 and conduction in Steps 2 and 3
Heat transferred in the three steps is Conduction in Step 1 and radiation in Steps 2 and 3.
Which kind of heat transfer can occur in metals?Conduction. The substance itself does not flow when heat is transported through conduction; instead, heat is internally transferred by the vibrations of atoms and molecules. Metals are typically excellent heat conductors because they can also carry electrons, which can carry heat.
The ability of metal to transfer heatIn contrast to atoms, unbound electrons exist in metals. These electrons are free to roam the metal, interacting with the metal atoms and effectively transferring heat to them through collisions. Due of this, metals are generally superior heat conductors than other types of materials.
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A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 231 kg. A small boy of mass m = 48 kg runs tangentially to the merry-go-round at a speed of v = 2.5 m/s, and jumps on.
Required the moment of inertia of the merry go round.
a. I = 12 MR2 is the formula for the merry-go-moment round's of inertia.
I = ½ * 231 * (1.3 * 1.3)
I = 195.195 kgm2
b. The boy's angular speed is specified as = v/R = 2.5/1.3 = 1.92 rad/s.
c. I' = I + mR2 is the formula for the merry-go-moment round's of inertia following the boy's jump on it.
I’ = 195.195 + 48 * (1.3 * 1.3)
I’ = 276.315 kg/m2
The conservation of angular momentum principle determines the merry-go-angular round's speed. As a result, I (0) + m R = 'I' and = (48 * 1.92* 1.3) / 276.315 = 0.433 rad/s
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assume that a rod-drawing operation can be carried out either in one pass or in two passes in tandem. if all die angles are the same and the total reduction is the same, will the drawing forces be different?
The drawing forces will be the same because the drawing process can be thought of as a series of incremental reductions taking place in a single die.
What is the draw force of a rod?The pull on the exit section and the friction forces acting along the tube-mandrel interface transmit draw force to the metal. The drawing forces will be the same unless the surface of the rod changes due to external effects such as the environment or additional lubrication while it is between the two dies. There is also increased reduction on a single die.
Ideally, a die can cut into several segments and make it a tandem process. Also, in a tandem operation, the front tension of one segment becomes the back tension of another.
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in an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression,
The piston's position is given as x = 4.33 cm, piston's velocity is given as v = -5 cm/s and piston's acceleration a = -17.3 m/s².
Given that, piston oscillates with simple harmonic motion so that its position varies according to the expression x = 5 cos( 2t + π/6 ), where x is in centimetres and t is in seconds.
The equation for piston's position is given as
x = 5 cm cos( 2t + π/6 )
At t = 0, x = 5 cos( π/6 ) = 4.33 cm
To find out piston's velocity, we have to differentiate the equation for position with respect to time.
v = dx/dt = -(10 cm/s) sin(2t + π/6)
At t = 0, v = -5 cm/s
To find out piston's acceleration, we have to differentiate the equation for velocity with respect to time.
a = dv/dt = -(20 cm/s²) cos (2t + π/6)
At t = 0, a = -17.3 cm/s²
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Name four planets which never get above freezing at the equators
Answer:
Mercury, Venus, Earth, Mars
A bowling ball rolls 32 meters in 0.8 seconds. Find the average speed (in m/s) of the bowling ball in m/s
The average speed of the bowling ball 40 meter/second..
What is speed?
The pace at which an object's position changes in any direction is referred to as speed.
The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity. Si unit of speed be meter/second.
Given parameters:
Distance travelled by the ball: s = 32 meter.
Time taken by the ball: t = 0.8 second.
So, average speed of the ball = distance travelled/ time taken
= 32 meter/ 0.8 second
= 40 meter/second.
Hence, the average speed of the bowling ball 40 meter/second.
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100 POINTS PLS HELP ASAP
FIND THE AVERAGE SPEE FOR BOTH CARS !
Average time for car 1 is 3.01 sec the distance is 4 feet
Average time for car 2 is 2.99 sec the distance is 4feet
PLS HELP
Answer:
4/3 ft/s
Explanation:
(3.01+2.99)/2 = 3.00
(4 ft)/(3.00 s) = 4/3 ft/s
An 3000-kg car traveling at 70 m/s takes 5 m to stop under full braking The same car under similar road conditions, traveling at 140 m/s, takes m to stop under full braking: A) 15 B) 3 C) 10 D) 20 E) 5
It takes 10 minutes to stop.
What happens when brake is applied in car?
To stop the car, force must act in the opposite direction (Newton's First Law). When a car's brakes are applied, the magnitude of the velocity begins to decrease. As a result, the change in velocity is negative, and the acceleration is also negative.
According to the equation,
[tex]v = u + at[/tex]
after applying brake [tex]v = 0[/tex]
[tex]-u = at\\\\a = \frac{-u}{t} \\\\\a = \frac{-70}{5}\\\\a = - 0.234 m/s^2[/tex]
As it is moving at 140m/s
so,
[tex]-u = at\\\\-140 = -0.234 * t\\\\600s = t\\\\t = 10mins[/tex]
It takes 10 minutes to stop.
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access flooring systems typically consists of modular floor panels that rest on stringers or pedestals. panel sizes typically range from ____ to 24 inches square.
Modular floor panels that rest on pedestals or stringers make up most access flooring systems. Typically, panel dimensions start at 24 by 24 inches square with same distance.
Their dimensions are constant; a raised floor panel is typically 600 mm by 600 mm. A standard access flooring panel in the USA is slightly larger, measuring 24" x 24". (around 610mm). A brand-new and cutting-edge patented solution that comprises of a polished concrete floor panel system that is intended to be put on to a new or retrofit building project is available. The imperfections and traits of a normal polished concrete floor are evident in this appealing, authentic concrete surface. The longest dimension of an object in geometric terms is its distance. International System of Quantities.
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The statement by Newton that for every action there is an equal but opposite reaction is which of his laws of motion?
Answer: The third law.
Explanation:
the maximum allowed coefficient of performance for a heat pump operating between temperatures of 2 oc and 15 o c is:
A heat pump's operating overall efficiency is just 15.88, claims the inquiry.
What is heat in reality? What is the name of heat energy?Heat energy is created by the movement of tiny atoms, ions, or atoms in solid, liquids, and gases. Overheating can be transferred of one thing to another. When two items are already at varying temperatures from one another, a movement or exchange called heat occurs. Atoms and molecules move more quickly and clash when the temperature rises, producing heat generated (also known as heat energy). The power that comes from the heated object's temperature is referred to as thermal energy.
Briefing:Maximum COP of heat pump:
COP = [tex]T_{H} /T_{H} - T_{C}[/tex]
Here, [tex]T_{H}[/tex] = 271 K and [tex]T_{C}[/tex] = 288 K
Hence, COP = 271/288-271
COP = 15.88
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I attached these picture
In the figure, a frictionless roller coaster car of mass m = 826 kg tops the first hill with speed vo = 16.0 m/s at height h = 41.0m. What is the speed of the car (a) point A. (b) point b, and (c) point C? (d) How high will the car go on the last hill, which is too high for it to cross? Use g=9.81 m/s2
The speed of the car at point A is 16 m / s, and the velocity at point B is 24.83 m / s.
What is speed?Speed is the measure of how quickly a moving object changes its distance traveled. It follows that since speed is a scalar, it is a measurement with a magnitude but no direction.
Something that moves quickly and at a high speed, covering a lot of distance quickly. An object moving slowly at a low speed, on the other hand, travels a comparatively short distance in the same amount of time. A thing moving at zero speed doesn't move at all.
Given:
The mass of the car, [tex]m = 826\ kg[/tex],
The initial speed, [tex]u = 16\ m/s[/tex]
(a) The Potential energy [tex](P)[/tex] at point A is the same as the initial because the height of the car is the same.
So, the velocity at point A = 16.0 m/s
(b) Calculate the total energy at the point [tex]E_A = mgh + (1/2)m\times v_A^2 = 833\times 9.81\times 43 + 0.5\times 833\times 16^2[/tex]
[tex]E_A = 432408.39 J[/tex]
And total energy at point [tex]E_B = mgh/2 + (1/2)m\times v(B)^2 = 833\times 9.81\times 43/2 + 0.5\times 833\times v_B^2[/tex] = [tex]E_B =175692.20 + 416.5\times v_B^2[/tex]
Solve the equations,
[tex]432408.39 = 175692.20 + 416.5\times v_B^2[/tex]
[tex]v_B = 24.83 m/s.[/tex]
Therefore, the speed of the car at point A is 16 m / s, and the velocity at point B is 24.83 m / s.
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An acorn rolls off a roof and falls to the ground. Which statement best describes the change in energy?
-the acorns potential energy decreases as it’s kinetic energy increases
-the acorns potential energy is changed to mechanical energy
-the acorns potential energy and kinetic energy increase and decrease together
-the acorns kinetic energy increases until it hits the ground
The statement that best describes the change in energy is the acorns potential energy decreases as it’s kinetic energy increases.
option A is the correct answer.
What is law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
Based on the law of conservation of energy, the total mechanical energy of the acorn will be conserved as it rolls off the roof. This implies that the change in the kinetic energy of the acorn is equal to change in potential energy of the acorn.
ΔP.E = ΔK.E
where;
ΔP.E is change in potential energyΔK.E is change in kinetic energyThe potential energy of the acorn is greatest at the maximum height, and decreases as the acorn fall to the ground. As the potential energy of the acorn decreases, it is being converted into kinetic energy and consequently results in increases of the kinetic energy.
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Answer:
(Question) A city gets its electricity from a dam, where water is stored in a reservoir. How does the water provide the city with its power?
(Answer) Potential energy in the water becomes kinetic energy as it moves through turbines, which turn kinetic energy into mechanical energy that spins a generator, which changes mechanical energy into electricity.
(Question) An acorn rolls off a roof and falls to the ground. Which statement best describes the change in energy?
(Answer) The acorn’s potential energy decreases as its kinetic energy increases.
(Question) An airplane carries 320 passengers from Phoenix to Los Angeles flying at an average speed of 490 miles per hour. On the return flight, the plane carries 164 passengers and travels at the same average speed. What happens to the plane’s kinetic energy?
(Answer) On the return flight, the plane has less kinetic energy.
(Question) A racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. The horse and its jockey have a combined mass of 512 kilograms. How much kinetic energy do they have?
(Answer) 90,480.6 J
(Question) Which object has kinetic energy?
(Answer) balloon rising in the sky
(Question) Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart at a speed of 2 meters per second each way. Which is the best prediction?
(Answer) When it was empty, the cart had less kinetic energy.
(Question) A student fires a toy rocket into the sky. When does the rocket have the most potential energy?
(Answer) when the rocket reaches its highest point
(Question) What is the best description of one billiard ball hitting a second billiard ball?
(Answer) Most of the kinetic energy in the first ball is transferred to the second ball.
(Question) A roller-coaster car is at the top of a hill. The car and its passengers have a combined mass of 1,088 kilograms. If the hill is 62 meters tall, how much potential energy does the car have?
(Answer) 661,068.8 J
(Question) A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill?
(Answer) 592,416 J
(Question) A diagram is drawn showing a swing set with a swing pulled backward prior to release. The diagram shows how the swing will move forward and then backward after it is initially released. At which point in the diagram is all of the energy gravitational potential energy?
(Answer) when the swing is pulled back prior to release
(Question) essay
(Answer) good luck
(Question) essay
(Answer) good luck
Explanation:
I just completed the assignment.
A roller coaster goes over a 12m tall hill then approaches a 30m hill. What is the minimum velocity the roller coaster would need when going over the 12m hill to make it to the top of the 30m hill?
The minimum velocity the roller coaster would need when going over the 12m hill to make it to the top of the 30m hill is 24.25 m/s.
What is the relationship between kinetic energy and potential energy?The relationship between the kinetic energy and potential energy of a body is given by the law of conservation of energy which states that the sum of the energy in a system is conserved.
Hence, the sum of the kinetic energy and the potential energy of a body is given as follows:
Kinetic energy = Potential Energy
Kinetic energy = ¹/₂ mv²
Potential energy = mgh
where;
m is massv is velocityg is the acceleration due to gravityh is the heightAssuming energy is conserved, the energy when going over the top of the 12 m is equal to the energy required to climb the 30 m hill.
¹/₂ mv² = mgh
v = √ 2gh
v = √ 2 * 9.8 * 30
v = 24.25 m/s
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A) How high (in m) a hill can a car coast up (engine disengaged) if friction is negligible and its initial speed is 74.0 km/h? (Enter a number.)
B) If, in actuality, a 750 kg car with an initial speed of 74.0 km/h is observed to coast up a hill to a height 10.0 m above its starting point, how much thermal energy (in J) was generated by friction? (Enter a number.)
C) What is the average force of friction (down the slope) if the hill has a slope 2.5° above the horizontal? (Enter your answer in N. Enter a number.)
(a) The maximum height attained by the car is 21.57 m.
(b) The thermal energy generated by friction is 85,017.6 J.
(c) The average force of friction of the hill is 370.8 N.
What is the maximum height reached by the car?
The maximum height attained by the car is calculated by applying the principle of conservation of energy as follows;
P.E = K.E
mgh = ¹/₂mv²
h = (v²) / (2g)
where;
v is the initial speed of the car = 74 km/h = 20.56 m/sg is acceleration due to gravityh = (20.56²) / (2 x 9.8)
h = 21.57 m
The thermal energy generated by friction is determined from the change in the mechanical energy of the car.
ΔE = K.E - P.E
ΔE = ¹/₂mv² - mgh
where;
m is mass of the carh is the height attainedv is the initial velocityΔE = ¹/₂(750)(20.56)² - (750)(9.8)(10)
ΔE = 85,017.6 J
The average force of friction of the hill is calculated as follows;
Fd = ΔE
where;
d is the horizontal distance travelled by the car along the hilld = h/sin(2.5) = 10 m / sin(2.5) = 229.26 m
F(229.26) = 85,017.6
F = (85,017.6) / (229.26)
F = 370.8 N
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Pls help me rapidly is of physical science:
Nitrogen belong to the group 15/5a period 3. It is also Known as pnictogen family .
The pnictogen family—what is it?Any chemical element in group 15 of the periodic table is a pnictogen. Group 15 is often referred to as the nitrogen family or group. Nitrogen, phosphorus, arsenic, antimony, bismuth, and moscovium make up group 15.
What is Periods ?A row of chemical elements makes up a period in the periodic table.
What is groups?In the periodic chart of chemical elements, a group is a column of elements.
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