To test Hou= 103 versus Hy #103 a simple random sample of size n = 35 is obtained. Does the population have to be normally distributed to test this hypothesis? Why? O A. Yes, because the sample is random
OB. No, because n >=30. OC. No, because the test is two-tailed OD. Yes, because n>=30.
No, the population does not have to be normally distributed to test the hypothesis in this scenario. The correct answer is OB. No, because n >= 30.
In hypothesis testing, the assumption of normality is primarily related to the sampling distribution of the test statistic rather than the population distribution itself.
The Central Limit Theorem states that for a sufficiently large sample size (typically n >= 30), the sampling distribution of the sample mean or proportion tends to follow a normal distribution, regardless of the shape of the population distribution.
In this case, the sample size is given as n = 35, which satisfies the condition of having a sufficiently large sample size (n >= 30).
Therefore, we can rely on the Central Limit Theorem, which implies that the sampling distribution of the test statistic (such as the sample mean) will be approximately normal, even if the population distribution is not.
The choice of a two-tailed test or the fact that the sample is random does not determine whether the population needs to be normally distributed.
It is the sample size that plays a key role in allowing us to make inferences about the population based on the Central Limit Theorem.
Hence, the correct answer is OB. No, because n >= 30. The assumption of normality is not required in this scenario due to the sufficiently large sample size.
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Can someone please help me with this questions please help me I really need help please.
Answer:
C) Line A does not intersect Line B.
Step-by-step explanation:
Line A passes through (6 ,-30) & (-2 , 10)
Line B passes through (-4 , 28) & (2 , -2)
Find the slopes for each line. To find the slope, use the slope formula:
slope (m) = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]
Line 1:
Let:
[tex](x_1 , y_1) = (6 , -30) \\(x_2 , y_2) = (-2 , 10)[/tex]
Plug in the corresponding numbers to the corresponding variables:
m = [tex]\frac{10 - (-30)}{-2 - 6} = \frac{10 + 30}{-8} = \frac{40}{-8} = \frac{-5}{1}[/tex]
Line 2:
Let:
[tex](x_1 , y_1) = (2 , -2)\\(x_2 , y_2) = (-4 , 28)[/tex]
Plug in the corresponding numbers to the corresponding variables:
m = [tex]\frac{28 - (-2)}{-4 - (2)} = \frac{28 + 2}{-4 - 2} = \frac{30}{-6} = \frac{-5}{1}[/tex]
The two lines share the same slope, therefore, they are parallel to each other. This means that they do not intersect at any given point.
Find the surface area of the prism.
Answer:
30 i think
Step-by-step explanation:
A line has a slope of 2/3 and y-intercept of (0,3). Which of the following represents the equation of the line?
Answer:
just believe and ask for forgiveness
Step-by-step explanation:
god lovesyou amen you shall pass
Please awnser correctly! I will mark you Brainliest!
Sean is employed as a truck driver. He drives x hours a week and is paid $21.60 per hour. Also he is paid $250 for food per week. This week he earned a total of $1,114. How many hours did he drive?
Answer:
Hours driven= 40 hours
Step-by-step explanation:
Giving the following information:
Variable income= $21.6 per hour
Fixed income= $250
Total income= $1,114
To calculate the number of hours driven, we need to use the following formula:
Total income= fixed income + hourly rate*number of hours
1,114 = 250 + 21.6*x
864 = 21.6x
864 / 21.6 = x
40=x
Hours driven= 40 hours
1 A very small takeaway cafe with 2 baristas has customers arriving at it as a Poisson process of rate 60 per hour. It takes each customer 3 min- utes, on average, to be served, and the service times are exponentially distributed. Interarrival times and service times are all independent of each other. There is room for at most 5 customers in the cafe, includ- ing those in service. Whenever the cafe is full (i.e. has 5 customers in it) arriving customers don't go in and are turned away. Customers leave the cafe immediately upon getting their coffee. Let N(t) be the number of customers in the cafe at time t, including any in service. N(t) is a birth and death process with state-space S = {0, 1, 2, 3, 4, 5}. (a) Draw the transition diagram and give the transition rates, An and Un, for the process N(t). (b) If there is one customer already in the cafe, what is the probability that the current customer gets her coffee before another customer joins the queue?
The probability that the current customer gets their coffee before another customer joins the queue, given that there is one customer already in the cafe, is 0.5.
(a) The transition diagram for the birth and death process N(t) with state-space S = {0, 1, 2, 3, 4, 5} is as follows:
rust
Copy code
----> 0 ----> 1 ----> 2 ----> 3 ----> 4 ----> 5 ---->
Un=60 An=0 Un=60 An=0 Un=60 An=0 Un=0
In this diagram, the transitions from state i to i+1 represent the arrival of a customer, denoted by An, with a rate of 60 per hour. The transitions from state i to i-1 represent the departure of a customer, denoted by Un, with a rate of 60 per hour when the cafe is not empty (i.e., i > 0). The transition from state 5 to state 4 has a rate of 0 since no customer can enter the cafe when it is full.
(b) If there is one customer already in the cafe (state 1), the probability that the current customer gets their coffee before another customer joins the queue can be calculated using the concept of first-passage time. The probability can be obtained by calculating the probability that the process reaches state 0 before reaching state 2.
Let P(i) denote the probability of reaching state 0 before reaching state 2, starting from state i. We have:
P(1) = An / (An + Un)
In this case, An = 60 and Un = 60, so:
P(1) = 60 / (60 + 60) = 0.5
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which is the other end point of a line segment with one end point at (-2, -5) and midpoint at (3,2)
Answer:
(8,9)
Step-by-step explanation:
<|--------------------|--------------------------|>
(-2,-5) (3,2)
-2-3 = -5 = | -5 | = 5
-5-2=-7 = | -7 | = 7
3+5=8
2+7=9
(8,9)
A triangular prism has a triangular face with a base of 13.5 feet and a height of 18 feet. Its volume is 2,187 cubic feet. What is the length of the triangular prism?
Answer:
The prism has a length x and a width x. Since it is a square at the base both length and width are the same amount x. The height is "half the length of one edge of the base". Since the base is x, this makes it 1/2x.
The volume's prism is found using V = l*w*h. Substitute and simplify.
13.5 = x*x*1/2x
13.5 = 1/2 x^3
27 = x^3
3 = x
The prism is 3 by 3 by 1.5.
Step-by-step explanation:
brainliest?
Simplify the expression 5 + (15 + x).
A. 5x + 20
B. x + 20
C. x + 5
D. x+ 15
Answer:
the answer is B
I hope you a good day!
Answer:
B
Step-by-step explanation:
You can't do anything in the parentheses because you can't add x to 15 yet since x is unknown. Thus, you add 5 to 15 and get 20 + x or B, x + 20
What is the area, in square centimeters, of the shaded part of the rectangle below?
Answer:
Step-by-step explanation:
17*8= the entire rectangle which is 136
Area of triangle=(base*height)divided by 2
The base of the white triangle is 4 because 8-4=4 and the height is 17
17*4=68
68/2=34
34= the area of the triangle
Area of the rectangle-area of the triangle=102
102 is your answer.
hopefully i did this right:)
A cylinder has a radius of 15 feet. Its volume is 5,652 cubic feet. What is the height of the cylinder?
Answer:
8
Step-by-step explanation:
I just put it in the calculator thint
use the midpoint rule with the given value of n to approximate the integral. round the answer to four decimal places.
Using the midpoint rule with the given value of n, we can approximate the integral. The answer, rounded to four decimal places, will be explained in the following paragraphs.
The midpoint rule is a numerical method used to approximate definite integrals. It involves dividing the interval of integration into n subintervals of equal width and evaluating the function at the midpoint of each subinterval. The approximated value of the integral is obtained by summing the products of the function values at the midpoints and the width of each subinterval.
To calculate the integral using the midpoint rule, we need to know the value of n, which determines the number of subintervals. The larger the value of n, the more accurate the approximation becomes. However, increasing n also requires more computational effort.
Once we have determined the value of n, we divide the interval of integration into n subintervals of equal width. Then, we evaluate the function at the midpoint of each subinterval and multiply it by the width of the subinterval. Finally, we sum up all these products to obtain the approximate value of the integral.
Rounding the answer to four decimal places ensures that the approximation is presented with a reasonable level of precision. It is important to note that while the midpoint rule provides a reasonable estimate, it may not always yield an exact result due to the inherent limitations of numerical methods for integration.
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If a translation of the figure above is plotted 7 units to the right and 2 units up, where will point A' be located on the new figure?
A. (7,2)
B. (-12,3)
C. (12,3)
D. (2,7)
If a translation of the figure above is plotted 7 units to the right and 2 units up, the (12,3) point A' will be located on the new figure.
What is translation?The process of changing the location of the image on the coordinate system will be known as the translation. Here the image is translated as;
The given coordinate of the point is:- (7, 2)
Then it is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s range(involving values of y) or in it’s domain(involving values of x because we just count 7 units to the right and then 2 units up.
Hence If a translation of the figure above is plotted 7 units to the right and 2 units up, the (12,3) point A' will be located on the new figure.
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Mary has 12 boards. She cuts the boards into pieces that are each 1/3 of a board long. How many pieces will she have?
Answer:
36
Step-by-step explanation:
if you have one board and divde it by 3 you get 3 equally sized boards
and if you cut all 12 of them you get 36 equally sized boards.
ASAP What is 94737638 x -9376383889483 this is a real question plz help!!!
Answer:
-8.8829646e+20
Step-by-step explanation:
Answer:
Step-by-step explanation:
Remark
94737638 x -9376383889483
The exact answer can be found by using the calculator that comes with windows (windows 7 if you are using that. Windows 10 for sure.). It can give exact answers up to 18 digits (or that's what I thought. This question is an astonishing 21 digits). The answer to this question is
-888,296,462,670,872,461,154
I don't know if Apple has a calculator that comes with its operating system. I would think so, but I don't know. I use a PC.
Which distribution do you use when you are testing a population mean and the standard deviation is known? Assume sample size is large.
O normal distribution
O uniform distribution
O Student's t-distribution
O binomial distribution
O Poisson distribution
The option A is correct answer which is Normal distribution.
What is Normal distribution?
A sort of continuous probability distribution for a random variable with a real value is called a normal distribution or a Gaussian distribution in statistics.
When testing a population mean and the standard deviation with large sample size so we used Normal distribution.
Hence, the option A is correct answer which is Normal distribution.
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Plz help, will give brainliest.
Answer:
1) X = 10 Therefore, 10 + 2 + 10 = 22.
2) B = 2 Therefore, 15 = 8(2) - 5 + 2(2)
3) B = -0.9 Therefore, -10 + 4(3(-0.9) + 10) = 19.
A swimming pool is 20 ft wide and 40 ft long and its bottom is an inclined plane, the shallow end having a depth of 3 ft and the deep end, 9 ft.
Suppose the pool is full of water, and assume that the weight density of water is62.5\,lb/ft^3.
(a) Find the hydrostatic force (in lb) on the shallow end. (include units)
Hydrostatic force = (b) Find the hydrostatic force (in lb) on the deep end. (include units)
Hydrostatic force = (c) Find the hydrostatic force (in lb) on one of the sides that extends from the shallow end to the deep end. (include units)
Hydrostatic force = (d) Find the hydrostatic force (in lb) on the bottom of the pool. (include units)
Hydrostatic force =
The pool's hydrostatic force is 1,500 pounds at the shallow end, 4,500 pounds at the deep end, 1,500 pounds on each side from shallow to deep, and 0 pounds at the bottom.
(a) To compute the pressure the water exerts at that depth and multiply it by the shallow end's surface area, we must first measure the hydrostatic force on the shallow end. The equation P = gh, pressure is P, is the fluid's density, acceleration from gravity is g, the depth is h, determines the pressure that a fluid exerts at a given depth.
In this case, the depth of the shallow end is 3 ft. The weight density of water is given as 62.5 lb/ft³.
Plugging in these values, we have,
P = (62.5 lb/ft³) * (32.2 ft/s²) * (3 ft)
P = 1,500 lb/ft².
To find the hydrostatic force, we multiply this pressure by the surface area of the shallow end, which is the width times the length,
Hydrostatic force = 1,500 lb/ft² * (20 ft * 40 ft)
Hydrostatic force = 1,500 lb. Therefore, the hydrostatic force on the shallow end is 1,500 lb.
(b) Using the same method as in part (a), we find that the pressure exerted by the water at the depth of the deep end, which is 9 ft, is ,
P = (62.5 lb/ft³) * (32.2 ft/s²) * (9 ft)
P = 4,500 lb/ft².
Multiplying this pressure by the surface area of the deep end (20 ft * 40 ft), we get the hydrostatic force on the deep end,
Hydrostatic force = 4,500 lb/ft² * (20 ft * 40 ft)
Hydrostatic force = 4,500 lb.
Therefore, the hydrostatic force on the deep end is 4,500 lb.
(c) The depth of the side is varying linearly from 3 ft to 9 ft. Taking the average depth, we have (3 ft + 9 ft) / 2 = 6 ft.
Using the formula,
P = (62.5 lb/ft³) * (32.2 ft/s²) * (6 ft),
We find that the pressure is 3,000 lb/ft².
Multiplying this pressure by the surface area of the side (20 ft * 6 ft), we get the hydrostatic force,
Hydrostatic force = 3,000 lb/ft² * (20 ft * 6 ft)
Hydrostatic force = 1,500 lb.
(d) Since the bottom of the pool is horizontal, the depth remains constant throughout, which is 3 ft. Plugging this value into the formul,
P = (62.5 lb/ft³) * (32.2 ft/s²) * (3 ft),
p = 1,500 lb/ft², we find that the pressure is 1,500 lb/ft². However, since the bottom is horizontal, the surface area facing upward cancels out the surface area facing downward, resulting in a net force of 0 lb.
Therefore, the hydrostatic force on the bottom of the pool is 0 lb.
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Natalie made blueberry muffins for a bake sale. Each muffin cost her about $0.25 to make. She spent $8.75 to make all of the muffins. Natalie sold each muffin for $0.50 more than it cost her to make.
What is the total amount of money that Natalie received from selling her muffins?
Answer:
$17.5
Step-by-step explanation:
Answer:
26.25
Step-by-step explanation:
I took the test
Consider the following IVP: y' = ty + t², 0≤ t ≤ 2, y(0) = 1 The exact solution of this IVP is y(t) = y = -t² − 2(t+1) + 3et a. Use Euler's method with step size h = 0.1 to approximate y(1) (you can use Matlab and set a table of values)
The value of y(1) is found to be approximately 2.6742 based on the approximate values obtained using Euler's method.
First, we divide the interval [0, 1] into 10 subintervals (h = 0.1), resulting in 11 points including the initial point.
Using the Euler's method, we start with the initial condition y(0) = 1 and iterate the following formula for each step:
y_(i+1) = y_i + h * (t_i * y_i + t_i^2)
Calculating the values iteratively, we obtain a table of values for t and y as follows:
t | y
0.0 | 1.0000
0.1 | 1.1000
0.2 | 1.2110
0.3 | 1.3343
0.4 | 1.4708
0.5 | 1.6228
0.6 | 1.7920
0.7 | 1.9802
0.8 | 2.1892
0.9 | 2.4202
1.0 | 2.6742
Therefore, using Euler's method with a step size of h = 0.1, the approximate value of y(1) is 2.6742.
Euler's method is a numerical method used to approximate the solution of ordinary differential equations (ODEs). It uses small steps to approximate the derivative and iteratively updates the solution at each step. In this case, we applied Euler's method with a step size of h = 0.1 to approximate the solution y(1) for the given initial value problem. By calculating the values iteratively using the formula y_(i+1) = y_i + h * (t_i * y_i + t_i^2), we obtained a table of values that approximate the solution. The value of y(1) is found to be approximately 2.6742 based on the approximate values obtained using Euler's method.
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Proving parallel lines. Find the value of x so that l // m. State the converse worksheet due tomorrow help please.
Answer:
x = 17Step-by-step explanation:
Find the diagram attached
The sum of the two adjacent angles is 180 degrees. Hence;
8x-9 + 53 = 180
8x + 44 = 180
Subtract 44 from both sides of the equation
8x + 44 - 44 = 180 - 44
8x = 136
Divide both sides by 8
8x/8 = 136/8
x = 17
Hence the value of x is 17
I need steps for this (need answers asap)
Answer:
(2x-7)(x+12)
Step-by-step explanation:
2x²+17x-84
(2x )(x )
We were told to use 7 and 12 to equal 84. Let's try 12 in the first bracket and 7 in the second:
(2x 12)(x 7): (2x)(7) and (12)(x) = 14x and 12x, which we cant make 17x from
Now let's try 7 in the first bracket and 12 in the second:
(2x 7)(x 12): (2x)(12) and (7)(x) = 24x and 7x, which we CAN use to make 17x if the 7x is negative, ie place a '+' before the twelve in the second bracket and a '-' before the seven in the first bracket.
(2x-7)(x+12)
Double check: (2x-7)(x+12)=2x(x+12)-7(x+12)=2x²+24x-7x-84=2x²+17x-84
Pls help ASAP find the slope !!
Answer:
4,-4 I think
Step-by-step explanation:
My brain is off right now so might be wrong
A homeowner installs a solar heating system, which generates 20 savings at a rate of 300e t dollars per year, t years after installation. Find a formula for the total savings after t years. If the system cost 30000 dollars to install, when will the savings match the installation cost
Answer:
"35.84 years" is the appropriate solution.
Step-by-step explanation:
The given values are:
Rate of savings generation,
[tex]s'(t)=300e^{\frac{t}{20} }[/tex]
System cost to install,
= $30000
Now,
The total savings will be:
⇒ [tex]s(t)=\int\limits s'(t) \ dt[/tex]
On substituting the values, we get
⇒ [tex]= \int\limits 300e^{\frac{t}{20} } \ dt[/tex]
⇒ [tex]s(t)=\frac{300e^{\frac{t}{20} }}{\frac{1}{20} }+c[/tex]
When,
Savings = 0
t = 0, then
⇒ [tex]0=6000e^o+c[/tex]
⇒ [tex]c=-6000[/tex]
The formula will be:
⇒ [tex]s(t)=6000[e^{\frac{t}{20} }-1][/tex]
On putting the values in the above formula, we get
⇒ [tex]30000=6000(e^{\frac{t}{20} }-1)[/tex]
[tex]5=e^{\frac{t}{20}}-1[/tex]
[tex]e^{\frac{t}{20} }=6[/tex]
On taking log, we get
⇒ [tex]\frac{t}{20} =log \ 6[/tex]
[tex]t=20 log 6[/tex]
[tex]=35.84 \ years[/tex]
PLEASE HELP ASAP !!
Which graph represents a solution to 6x + 4 = 31?
Answer:
A.
Step-by-step explanation:
Jane needs 6 1/2 of fabric to make a dress. She has one piece of fabric that is 1 1/2 yards and another piece of fabric that is 3 1/4 yards. How many more yards of fabric does Jane need to make the dress?
Answer:
1 1/2
Step-by-step explanation:
1 1/2 + 3 1/2 = 5
6 1/2 - 5 =1 1/2
18. In the photograph of a father and his daughter, the daughter's height is 2 cm and the father's height is 5 cm. If the father's height is actually 185 cm, how tall is the daughter?
Answer:
114cm
Step-by-step explanation:
When you're in a situation like this, you use ratios!
If the father's height is 5cm, and actually 185cm, the ratio of photo height and actual height is 1:57.
When we use this, the father is 57 times taller than him inside the photo, so since the daughter (in photo) is 2 cm, her height should be 2*57 cm.
2*57 = 114, which concludes to 114 cm.
:)
HELP PLEASE 50 POINTS
expression with its simplified form.
5.The employees of Xitrex, Inc., are paid each Friday. The company’s fiscal year-end is June 30, which falls on a Wednesday for the current year. Salaries and wages are earned evenly throughout the five-day work week, and $13,000 will be paid on Friday, July 2.
Required:
1. Prepare an adjusting entry to record the accrued salaries and wages as of June 30, a reversing entry on July 1, and an entry to record the payment of salaries and wages on July 2.
2. Prepare journal entries to record the accrued salaries and wages as of June 30 and the payment of salaries and wages on July 2 assuming a reversing entry is not recorded.
The entry to record the payment of salaries and wages on July 2 is a debit to Salaries and Wages Payable and a credit to Cash.
1. The adjusting entry on June 30 is necessary to recognize the expense for salaries and wages earned but not yet paid. It increases the Salaries and Wages Expense account and creates a liability in the Salaries and Wages Payable account.
The reversing entry on July 1 is made to simplify the subsequent accounting process and ensure accurate financial reporting. On July 2, when the payment is made, the Salaries and Wages Payable account is reduced, and Cash is decreased by the same amount.
2. Without a reversing entry, the journal entry on June 30 still recognizes the expense for salaries and wages earned but unpaid. The Salaries and Wages Expense account is debited, reflecting the expense, and the Salaries and Wages Payable account is credited, indicating the liability.
On July 2, when the payment is made, the Salaries and Wages Payable account is reduced, and Cash is decreased by the same amount. The absence of a reversing entry means that the Salaries and Wages Expense account will continue to reflect the total expense accrued throughout the fiscal year, rather than resetting to zero at the beginning of the new period.
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