Over the period of a year, Julie’s net worth decreased. Which of the following could be true? a. Julie’s assets and liabilities decreased by the same amount. b. Julie’s assets and liabilities increased by the same amount. c. Julie’s assets increased by more than her liabilities. d. Julie’s assets decreased by more than her liabilities. Please select the best answer from the choices provided A B C D Mark this and return Save and Exit
Assets are the goods you possess that can generate future economic advantage. The correct option is D.
What are assets and liabilities?Assets are the goods you possess that can generate future economic advantage. Liabilities are amounts owed to other parties. In a nutshell, assets put money in your pocket, while liabilities take money out!
Given Over the period of a year, Julie’s net worth decreased. Therefore, the statement that is true is Julie’s assets decreased by more than her liabilities.
Hence, the correct option is D.
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the ratio of the length of an arc of the circle to the circumference of the circle is 3:7, if the diameter of the circle is 14cm calculate to three significant figures the (a) perimeter of the minor circle (b) area of the minor circle, take thither=22/7
The perimeter and area of this minor circle are equal to 32.857 units and 88.345 units² respectively.
How to calculate the perimeter of the minor circle?First of all, we would determine the circumference of this circle by using this formula:
C = πD
C = 22/7 × 14
C = 44 units.
For the length of an arc of the circle:
Arc length/Circumference = 3/7
Arc length = 3/7 × C
Arc length = 3/7 × 44
Arc length = 18.857 units.
Now, we can calculate the perimeter:
Perimeter = 2r + arc length
Perimeter = 2(14/2) + 18.857
Perimeter = 14 + 18.857
Perimeter = 32.857 units.
The area of the minor circle.Mathematically, the area of a minor circle is given by this formula:
Area = θr²/2
But, we would have to find the angle in radians:
18.857/32.857 = θ/360
θ = 3.6059 radians.
Substituting the given parameters into the formula, we have;
Area = (3.6059 × 7²)/2
Area = 88.345 units².
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Please help! photo is attached, will give brainliest.
Answer:84
Step-by-step explanation:
Okay. Are you taking calc? Dv/dt =d/dt(L(t)^3)=d/dt[(sqrt(14)+2t)^3]= 6(Sqrt(14)+2t)^2)=44. We defined t=0 to be time at which length is sqrt(14). Does that work?
There are 9 students performing in the talent show, 7 of whom will perform a dance.
If 6 students are randomly chosen to perform during the first section of the show, what is the
probability that all of them will perform a dance?
Write your answer as a decimal rounded to four decimal places.
please help me to solve all the questions would appreciate it if its with full working
∠ KGH is equal to 77°. This is arrived at by using the knowledge of the total angles in Parallel Lines.
What are the total angles on a straight line?
According to the laws of lines and angles, the total number of angles that can exist on a straight line is 180°.
If ∠CED = 25° and ∠BFL = 78°, then: ∠KGH = 180-(25+78), which is equals 77°. This is because the total angles on a straight-line total 180°
What is ∠LKJ?Recall that in angles in parallel lines:
Corresponding Angles are always congruent, Alternate Angles are always congruent, and Interior According always sum up to 180°Hence,
We can derive ∠LKJ because it is congruent with ∠BGJ.
To get ∠BGJ, we must get ∠LFH because both of them are interior angles and sum up to 180°.
To get ∠LFH, we must subtract ∠BFL from 180° because they are both angles on a straight line.
Hence ∠LFH = 180 - 78 = 102°
Recall that ∠LFH and ∠BGJ are interior angels. Hence
∠BGJ = 180 - 102 = 78°.
Since ∠BGJ is a corresponding ∠ with ∠LKJ, therefore
∠LKJ = 78°
What is ∠ALM?
∠ALM is ∠BFL because they are both corresponding angles and are therefore congruent.
What are the solutions to section B?Because ∠ACB and ∠BAC are equal, therefore sides AB and BC are equal in length. We can tell that ∠ACB and ∠BAC are equal because the total angles in the triangle are equal to 180°2. The name given to the triangle mentioned above is Obtuse
Triangle. This is because one of the angles exceeds 90°.
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.Find the distance between the two points
(3, 5) and (4, 6) to the nearest tenth.
PLEASE PLEASE PLEASE I HAVE 20 MINUNTES
Answer:
E. 38°
Explanation:
A rhombus has 360° interior angle.
Half of the other side has 180° angle.
Solve for x:
sum of interior angles = 180°
x + 14 + x + 14 + x + x = 180°
4x + 28° = 180°
4x = 180° - 28°
4x = 152°
x = 152°/4 = 38°
Sum of half interior angles=180°
So
x+x+14+x+x+14=1802x+2(x+14)=1802x+2x+28=1804x+28=1804x=152x=38°Option E
Which could be the entire interval over which the function, f(x), is positive?
Why?
Notice that f(x) is positive when -2 < x < 1. In other words, f(x) is positive when x = -1 and when x = 1.
This interval of -2 < x < 1 translates directly to the interval notation of (-2, 1)
Unfortunately this interval notation looks identical to ordered pair notation. Be sure not to mix the two concepts up.
The parenthesis in interval notation tell the reader "do not include the endpoints". We cannot include x = -2 nor x = 1 because these values make f(x) zero, but we want f(x) > 0.
Something like choice D is a non-answer because the value x = 2 is in the interval (1,4), but f(2) = -8 which isn't positive. We can rule choice D out because of it. Choices A and C are similar situations.
What is the volume of the following solid figure?
Answer: 450
Step-by-step explanation:
The volume is (1/2)(5)(12)(15)=450.
Drag each tile to the correct box.
Each tile shows an investor’s tax bracket along with the tax-free yield of a bond the investor purchased. Use the formula to determine the taxable equivalent yield of each investment, and then order the investments from least to greatest return.
taxable equivalent yield =
100 PTS
The order the investments from least to greatest return,
tax bracket is 22% and tax-free yield is 3% < tax bracket is 35% and tax-free yield is 3% < tax bracket is 24% and tax-free yield is 4% < tax bracket is 12% and tax-free yield is 5% < tax bracket is 12% and tax-free yield is 5%
What is a fraction?A fraction is written in the form of p/q, where q ≠ 0.
Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.
We know the value of a fraction gets larger when the numerator becomes larger and the denominator gets smaller.
Given, Each tile shows an investor’s tax bracket along with the tax-free yield of a bond the investor purchased.
(tax-free yield)/(100 - tax bracket).
Now, tax bracket is 24% and tax-free yield is 5%.
= 5/100 - 24.
= 5/76.
= 0.0658.
Similarly,
tax bracket is 12% and tax-free yield is 5%
= 0.0641.
tax bracket is 22% and tax-free yield is 3%
= 0.0384.
tax bracket is 24% and tax-free yield is 4%
= 0.0526.
tax bracket is 35% and tax-free yield is 3%
= 0.0461.
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Jace gave $100 to her daughter Kailey and asked her to spend three parts and save two parts of the total amount. How much did Kailey spend and how much did she save?
Step-by-step explanation:
spending 3 parts and saving 2 parts means that there are 3+2 = 5 parts in the whole.
the whole being $100.
one of the 5 parts is then 100/5 = $20.
so, she spent 3×20 = $60 and saved 2×20 = $40.
The equation y + 6 = one-third (X minus 9) is written in point-slope form. What is the equation written in slope-intercept form? y = one-third x minus 3 y = one-third x + 9 y = one-third x minus 9 y = one-third x + 3
The equation written in slope-intercept form is y = (1/3)x -9
What is a linear Equation ?A linear equation is that which can be represented in the form of y =mx +c , m is the slope and c is the intercept.
The given equation is
y+6 = 1/3(x-9)
To determine the slope and the intercept this equation needs to be solved
y+6 = (1/3)x - 3
y = (1/3)x -9
Therefore this is the slope intercept format , here
the slope = 1/3
intercept = -9
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-4(3x+2/6)
Solving for x
Answer:
x = [tex]-\frac{1}{9}[/tex]
Step-by-step explanation:
FOIL what is in the parentheses by multiplying terms by -4.
[tex]-4(3x+\frac{2}{6})[/tex]
-4(3x) = -12x and -4(2/6) = -4/3
now add these products: [tex]-12x-\frac{4}{3}[/tex]
That is the simplified product ^, but assuming you're supposed to set the equation to equal 0...
Set equation to 0 and add the fraction to both sides. Rewrite as [tex]-12x=\frac{4}{3}[/tex]
Divide both sides by -12 to get variable, x, alone. Multiplying 4/3 by -1/12 is the same as dividing 4/3 by -12. The negative sign from the -12 make the quotient negative.
x = [tex]-\frac{1}{9}[/tex]
Answer:
x = -1/9
Step-by-step explanation:
FOIL what is in the parentheses by multiplying terms by -4.
-4(3x) = -12x and -4(2/6) = -4/3
now add these products:
That is the simplified product ^, but assuming you're supposed to set the equation to equal 0...
Set equation to 0 and add the fraction to both sides. Rewrite as
Divide both sides by -12 to get variable, x, alone. Multiplying 4/3 by -1/12 is the same as dividing 4/3 by -12. The negative sign from the -12 make the quotient negative.
x= 1/9
What are the domain and range of g(x)= √x-3?
A. D: [3, ∞) and R: [0, ∞)
B. D: [–3, ∞) and R: [0, ∞)
C. D: (–3, ∞) and R: (–∞, 0)
D. D: (3, ∞) and R: (–∞, 0)
Answer:
I guess, A is the wanted answer, but
A and D together are the really correct answer.
Step-by-step explanation:
if I understand this correctly, then
g(x) = sqrt(x - 3)
the domain of a function is the definition of all valid x (input) values.
the range of a function is the definition of all valid y (result) values.
well, the content (the arguments) of a square root cannot be negative (at least not while dealing with real numbers).
so, the answer options B and D are automatically out, because the domain contains values that would make the arguments of the square root negative.
I guess your teacher wants to focus only on the positive results of the square root, so A is the correct number.
BUT formally, without designated restrictions, a square root has always 2 solutions : a positive and a negative one.
because (-x)² = (x)² = x².
so, I would have to say that the really correct answer is
A + D, because the range contains both, the positive and the negative numbers.
tess saids this shape is a rhombus. Jack says the shape is a square. Who is correct?
Tess and Jack are both correct with their claims
How to determine who is correct?The attached image completes the question
From the complete question, we have the following highlights
The shape has equal side lengthsThe angles at the vertices of the shape are right anglesThe above properties represent a square
A rhombus can also have the above properties when the vertices are at 90 degrees
Hence, Tess and Jack are both correct with their claims
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Use the points (0, 4) and (-2, 3) to find the slope of the line and give the equation of this line.
Answer:
Choice C: [tex]m=\frac{1}{2}; y=\frac{1}{2} x+4[/tex]
Step-by-step explanation:
To find your slope do:
[tex]\frac{y^2-y^1}{x^2-x^1}[/tex]
[tex]\frac{3-4}{-2-0}=\frac{-1}{-2} =\frac{1}{2}[/tex]
that's how you get 1/2
4 is just the y-int.
The required equation of line passes through (0, 4) and (-2, 3), has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.
What is the equation?The equation is the values of two expressions that are equal.
What is the slope of the line?The slope of the line is the tangent angle made by the line with horizontal. i.e. m =tanx where x in degrees.
The slope of the equation line passing through (0, 4) and (-2, 3)
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m = (3 - 4) / (-2-0)\\m = -1/-2\\m = 1/2[/tex]
Strand form of the equation of the line,
[tex]y-y_1 = m(x-x_1)[/tex]
Putting values in the standard form of the equation of the line.
y - 4 = 1/2 * (x - 0)
y = 1/2 * x + 4
[tex]y = \frac{1}{2} x + 4[/tex]
Thus, the required equation of line passes through (0, 4) and (-2, 3), has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.
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factor the following expressions
got really sick and missed a bunch of school, would really appreciate the help !
Answer:
i hope this will help you
Which of the following statements are true?
f(x)
g(x)
. A. Both graphs have exactly one asymptote.
B. Both graphs have been shifted and flipped.
. C. Both graphs are exponential functions.
0 D. Both graphs are logarithmic functions
The true statements are; A. Both graphs have exactly one asymptote. C. Both graphs are exponential functions. B. Both graphs have been shifted and flipped.
What are exponential functions?When the expression of function is such that it involves the input to be present as an exponent (power) of some constant, then such function is called exponential function.
There usual form is specified below. They are written in several such equivalent forms.
For example, y^x
, where a is a constant is an exponential function.
The graphs are exponential functions because as x increases, the y approaches infinity.
Here, the graphs have exactly one asymptote.
we can see that both graphs appear to have been shifted and flipped especially when at their respective coordinates.
The true statements are;
A. Both graphs have exactly one asymptote.
C. Both graphs are exponential functions.
B. Both graphs have been shifted and flipped.
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Tricia is going too write patterns a, b, and c using the rule "add 15." the first number in each pattern is shown below. Use the drop-down menus too describe the patterns. Pattern A: 5
Pattern B: 10
Pattern C: 15
Each patter will blank
A: contain odd numbers only
B: alternate between odd and even numbers
C: Include a number with 2 in the ones place
D: Include a number with 1 in the tens place
Answer:
Number 40 appeared in Pattern B. Also, according to the rule, each pattern will increase.
Step-by-step explanation:
Let's develop each sequence. Remembe that the rule is "add 15", that's what we need to create each sequence starting from the given initial number.
Pattern A.

Pattern B.

Pattern C.

As you can observe, number 40 appeared in Pattern B. Also, according to the rule, each pattern will increase
If a sample proportion is 0.65, which range of possible values best describes
an estimate for the population parameter?
O A. (0.5, 0.89)
• B. (0.5, 0.8)
• C. (0.65, 0.7)
• D. (0.6, 0.69)
The range of possible values that best describes an estimate for the population parameter is; (0.5, 0.8)
How to estimate proportion?The range of possible values that best describes an estimate for the population parameter is; (0.5, 0.8).
When we are talking about population parameters, we also have to look at the way of estimating the population, we have to add two extremes and divide by 2.
Thus, the correct one is;
(0.5 + 0.8)/2 = 0.65
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Which of the following polynomial functions is graphed below?
-70
60
50
20
-10
O A. f(x) = (x + 5)(x − 1)2(x+1)
B. f(x) = (x - 5)(x-1)²(x - 1)
OC. f(x) = (x+2)(x-3)²(x+4)
D. f(x)=(x-2)²(x-3)(x-4)
-10-
-20
-30-
-40
10
The option (C) f(x) = (x+2)(x-3)²(x+4) is correct because in the graph the minimum value of function is less than 40.
What is polynomial?Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]
We have a graph of a polynomial.
From the graph we can clearly see there is three x-intercept where the value of a polynomial function becomes zero.
The minimum value of function is less than 40
At x = 3, f(3) = 0
At x = -2, f(-2) = 0
At x = -4, f(-4) = 0
Thu graph of a function will be:
[tex]\rm y\ =\ \left(x+2\right)\left(x-3\right)^{2}\left(x+4\right)[/tex]
Thus, the option (C) f(x) = (x+2)(x-3)²(x+4) is correct because in the graph the minimum value of function is less than 40.
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Which statement best compares savings accounts and money market accounts?
OA. A regular savings account has fewer restrictions on withdrawals than a money market account
but at a lower interest rate.
OB. A regular savings account has fewer restrictions on withdrawals than a money market account
but at a higher interest rate.
C. A money market account has fewer restrictions on withdrawals than a regular savings account
but at a lower interest rate.
OD. A money market account allows for more withdrawals than a regular savings account but at a
higher interest rate.
Answer:
Its Option C.
Step-by-step explanation:
I took this quiz and got this correct, atleast I think...??
The solution for which of the following is neither a interger nor a fraction 4x+7=x+2 ,5x-8=x+4, 3x+2=5x+2, none of the above
Answer:
none of the above
Step-by-step explanation:
4x + 7 = x + 2
4x - x + 7 = x - x + 2
3x + 7 = 2
3x + 7 - 7 = 2 - 7
3x = -5
3x / 3 = -5 / 3
x = -5 / 3 = -1.667
5x - 8 = x + 4
5x - x - 8 = x - x + 4
4x - 8 + 8 = 4 + 8
4x = 12
4x / 4 = 12 / 4
x = 3
3x + 2 = 5x + 2
3x - 5x + 2 = 5x - 5x + 2
-2x + 2 = 2
-2x + 2 - 2 = 2 - 2
-2x = 0
x = 0
Integers, As a whole number that can be written without a remainder,
x = 3
x = 0
(Mixed) Fraction
x = -5 / 3 = -1.667
PLEASE HELP!!!!!! WHATS THE ANSWER
Answer:
3
Step-by-step explanation:
pls mark brainliest
Does anyone know the correct answer
Answer:
[tex]2\sqrt{5}[/tex] is an irrational number.
[tex](\sqrt{3} )^2[/tex] is a rational number.
Step-by-step explanation:
Krista got paid $43.75 for working 3.5 hours. How much did she earn per hour?
Answer:
12.5
Step-by-step explanation:
divide 43.75 by 3.5 to get your answer
Susan, Enrique and Martin are going for a meal.
Susan pays £26, Enrique pays £20 and Martin pays £18.
What fraction of the meal did each friend pay for?
Answer:
13/32 Susan
5/16 Enrique
9/32 Martin
Step-by-step explanation:
26+20+18=64
26/64=13/32
20/64=5/16
18/64=9/32
Please help me with this.
Answer:
ok umm this looks hard can u give mor info?
Step-by-step explanation:
What substitution should be used to rewrite 16(x³ + 1)² − 22(x³ + 1) − 3 = 0 as a quadratic equation?
O u = (x³)
Ou= (x³ + 1)
Ou = (x³ + 1)^2
Ou= (x³ + 1)^3
The correct answer is option B which is u = ( x³ + 1).
What is a quadratic equation?The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.
Given expression is as follows:-
16(x³ + 1)² − 22(x³ + 1) − 3 = 0
Put u = ( x³ + 1) the equation will become:-
16u² -22u-3 = 0
Now the above equation has become a quadratic equation.
Therefore the correct answer is option B which is u = ( x³ + 1).
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Part 3 - Discussion/Explanation Question
In what ways can vertical, horizontal, and oblique asymptotes be identified? Use a mathematical example to
explain the ways.
Step-by-step explanation:
Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.
For example,
[tex] \frac{1}{x - 5} [/tex]
Set the expression in the denominator equal to 0, because you can't divide by 0.
[tex]x - 5 = 0[/tex]
[tex]x = 5[/tex]
So the vertical asymptote is x=5.
Disclaimer if you see something like this
[tex] \frac{(x - 5)(x + 3)}{(x - 5)} [/tex]
x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.
Horizontal:
If we have a function like this
[tex] \frac{1}{x} [/tex]
We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.
Remember a constant can be represent by
[tex]a \times {x}^{0} [/tex]
For example,
[tex]1 = 1 \times {x}^{0} [/tex]
[tex]2 = 2 \times {x}^{0} [/tex]
And so on,
and
[tex]x = {x}^{1} [/tex]
So our equation is basically
[tex] \frac{1 \times {x}^{0} }{ {x}^{1} } [/tex]
Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.
So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.
Consider the function
[tex] \frac{3 {x}^{2} }{ {x}^{2} + 1} [/tex]
As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator
So in this case,
[tex]x = \frac{3}{1} [/tex]
Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.