Answer:
A) 0.9844 s
B) x2 = 0.4587 m
C) v = 6.657 m/s
Explanation:
We are given;
Height of take off point above pool; x1 = 1.8 m
Initial take off velocity; u = 3 m/s
Final velocity at highest point before free fall; v = 0 m/s
B) To find the highest point above the board her feet reaches means the distance from take off to the top of the motion just before free fall.
Thus, we will be using equation of motion and we have;
v² = u² + 2gs
Now, let s = x2 which will be the distance between take off and the top before free fall.
So;
v² = u² + 2g(x2)
Now,since the motion is against gravity, g will be negative.
Thus;
v² = u² + 2(-9.81)(x2)
Plugging in the relevant values to give;
0² = 3² - (19.62x2)
19.62(x2) = 9
x2 = 9/19.62
x2 = 0.4587 m
A) We want to find how long her feet is in air.. It means we want to find out the time to get to a distance of x1 and also the time to achieve the distance (x1 + x2) on free-fall.
Thus, using equation of motion;
v = u + gt
Again, g = -9.81
Thus;
0 = 3 - 9.81t1
9.81t1 = 3
t1 = 3/9.81
t1 = 0.3058 s
Now, for the time taken to achieve the distance (x1 + x2) on free-fall, we will use the formula;
s = ut + ½gt²
Where s = (x1 + x2) = 1.8 + 0.4587 = 2.2587 m
And now, u = 0 m/s because the start of the free fall is from maximum height with velocity of 0 m/s. Again, g = - 9.81 m/s²
Thus;
2.2587 = 0 - ½(-9.81)(t2)²
2.2587 = 4.905(t2)²
(t2)² = 2.2587/4.905
(t2)² = 0.4605
t2 = √0.4605
t2 = 0.6786 s
Thus, total time of feet in air = t1 + t2 = 0.3058 + 0.6786 = 0.9844 s
C) Velocity when feet hit the water would be given by;
v = u + gt
Where u = 0 m/s and t = t2 = 0.6786
Since it's in direction of gravity, g = 9.81 m/s
v = 0 + (0.6786 × 9.81)
v = 6.657 m/s
If a car is driving at 10 m/s and is driving for 2 minutes, what is the total distance it will
cover?
Distance = (speed) x (time)
Distance = (10 meter/second) x (2 minutes)
Distance = (10 meter/second) x (2 minutes) x (60 second/minute)
Distance = (10 x 2 x 60) (meter-minute-second / second-minute)
Distance = 1,200 meters
The work done when a force moves a body through a distance of 15m is 1800j. What is the value of the force applied
Answer:
120 Newtons.
Explanation:
Work(Joules) = Force(Newtons) × Distance(Meters)
If we need to find the Force, the equation changes.
To find Force, you have to divide the Work done from the Distance. Have a look at the picture above.
Water forming a droplet is an example of:________.
Answer:
A perfect example of Surface tensionExplanation:
what is surface tension?
simply put, surface tension is the ability of water to act or behave as if it were or were covered by an elastic skin.
other notable examples of surface tension are
Examples of surface tension of water
1. Ants walking on water
2.Razor blades floating on water
3. Capillary action (water rising or falling in a narrow capillary tube)
Should you need further clarification do not hesitate to let me know
Four different vehicles are shown. Assume that all four vehicles are traveling at the same speed on a highway. Which is true about the kinetic energy of the vehicles?
A. The motorcycle has the most kinetic energy because it has the least mass.
B. All of the vehicles have the same kinetic energy because they are moving at the same speed.
C. The delivery van has the greatest kinetic energy because its mass is greater than that of the other
vehicles.
D. The delivery van has the greatest kinetic energy because it has the most tires in contact with the
pavement.
Answer:
Option C. The delivery van has the greatest kinetic energy because its mass is greater than that of the other
vehicles.
Explanation:
Kinetic energy is the energy of an object in motion. Mathematically, it is expressed as:
K.E = ½mv²
Where:
K.E is the kinetic energy.
m is the mass of the object.
v is the velocity of the object.
From the formula above, we can say that:
Kinetic energy is directly proportional to the mass of the object and the square of the velocity of the object. This simply means that objects with higher mass will have a greater kinetic energy than objects will lighter mass even if their velocities are the same.
From the question given above, it is obvious that the delivery van has a greater mass than the rest object.
Therefore, the delivery van will have the greatest kinetic energy because its mass is greater than that of the other
vehicles.
how much heat is required to convert 1 gm of ice into steam
Answer:
Heat required in converting 1g of ice at −10∘C into steam at 100∘C is: latent heat of fusion= 80 cal/g80 cal/g. latent heat of vaporization=540 cal/g.
A particle is moving along the x-axis. Its position as a function of time is given as x=bt-ct^2a) What must be the units of the constants b and c, if x is in meters and t in seconds?b) At time zero, the particle is at the origin. At what later time t does it pass the origin again?c) Derive an expression for the x-component of velocity.d) At what time t is the particle momentarily at rest?e) Derive an expression for the x-component of the particles acceleration, ax
Answer:
We are given x= bt +ct²
So
A. bxt= m
Because m/s*s= m
So b= m/s and c= m/s²
B.
x= bt-ct²
So at x=0 t=0
x=0 t= 2
We have
bt = ct² so t = b/c at x= 0
So b-2ct= 0
B. To find velocity we use
dx / dt = b - 2 Ct
C. At rest wen V= 0
We have t= b/2c
D. To find acceleration we use
dv / dt = - 2C
When We are given x= bt +ct²
Then A. bx.t = mJust Because of the m/s*s= mSo that, b= m/s and c= m/s²Now B. x= bt-ct²the So at x=0 t=0After that x=0 t= 2Now We have bt = ct² so t = b/c at x= 0After that So b-2ct= 0Then B. To find velocity we use that isThen dx / dt = b - 2 CtThen C. At rest wen V= 0We have t= b/2cNow D. To find acceleration we useNow the answer is dv / dt = - 2CLearn more about:
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Which is NOT one of the 11 organ systems of the body?
Integumentary system
Immune system
Skeletal system
Digestive system
Answer:
Immune
Explanation:
because I remember taking that test and I I specifically remember that question and that's the answer
Which of the following describes how the mechanical advantage of a simple machine affects the amount of force needed for work? A. By decreasing the distance over which the input force is applied, less force is needed to do the same amount of work. B. By increasing the distance over which the input force is applied, more force is needed to do the same amount of work. C. By decreasing the distance over which the input force is applied, more force is needed to do the same amount of work. D. By increasing the distance over which the input force is applied, less force is needed to do the same amount of work.
Answer:
The answer is a
Explanation:
1. What does the horizontal axis ordinarily measure on an oscilloscope?
2. What frequency should the function generator be set to if period of 25 us is a desired?
3. If a resistor has the color combination of yellow-violet-red-gold, what is the range of acceptable values of resistance?
4. Given that the voltage from a wall outlet is AC, if you digital multimeter to measure the wall outlet voltage to be 120 V, what is the maximum voltage level provided by the wall outlet
Answer:
1. OK the
1. The horizontal axis of a osclloscope is generally TIME axis.
2. given T =25 micro second
That is = 25E-6 s
Then We f = (1/T) .
So f = 1/(25 x 10^-6) = 40000 Hz =
40 KHz.
3. First Band will be Yellow
Second Band will be Violet
Third Band will be Red
And
Fourth Band will be Gold
Thus, the value of the resistance = (47 x 100)plus or minus 5%
= (4700 plus or minua5%) ohm
the range of the acceptable value of the resistance will now be
= 4465 ohm to 4935 ohm
(4)
The level provided by the wall outlet = 120 x √2 = 169.68 V
The √2 is because the multimeter measures RMS voltage rather than peak voltage and
RMS Voltage is = √2 x peak voltage
For a circuit find the total potential differences if two resistors
of resistance R1 and R2 respectively kept series wise for a
current I passing through it.
-- If the two resistors are connected in series, then they behave like a single resistor whose resistance is (R₁ + R₂) ohms.
-- For any resistance, the potential difference (volts) across the resistance is V = (current) x (resistance) .
-- So in THIS circuit, V = I x (R₁ + R₂) .
The moon is half dark, half lit on two days each month . What causes this?
Answer:
This is caused by the rotation and position of the Earth with respect to the sun.
Explanation:
The constant change of the Moon's surface relative to Earth is called "The moon phases".
These modifications in our satellite are due to the change of position of the satellite with respect to the Earth and the Sun.
During the lunar phases of the third quarter and the first quarter, the moon lights up just a half, being that both only light half, the first quarter lights the right side of the moon, and the last quarter lights the left side.
I REALLY NEED HELP What is a closed physical system A.A system where matter and energy can enter, but not leave the system B.non of the answers are true C.A system where matter and energy can leave, but not enter the system D.A system where matter and energy cannot enter or leave the system
You probably already took this but if anyone wanted to know the answer it's D. "A system where matter and energy cannot enter or leave the system".
(I also took the quiz for it and got it correct)
A closed physical system is a system where matter and energy cannot enter or leave the system. The correct option is D.
What is a physical system?A physical system is any item or part of an object that can be analyzed using physics laws.
An atom and lake water are both examples of physical systems. Everything outside the system is referred to as the environment, and it is ignored in the analysis except for its effects on the system.
A physical system is a collection of parts or elements that, when combined, exhibit behavior that the constituents do not. Matter and energy make up physical systems.
A closed system is a natural physical system that does not allow the transfer of matter into or out of the system, though it does allow the transfer of energy in contexts such as physics, chemistry, or engineering.
Thus, the correct option is D.
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Can you please help me?
Answer:
a= 18.4m
b= 26.2m
Explanation:
Please see the attached picture for full solution.
Which law of motion is this an example of?
Newton's 1st Law of Motion
Newton's 2nd Law of Motion
Newton's 3rd Law of Motion
Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.
Explanation:
Answer: newtons 2nd law of motion because in order to push the object you must put force to the mass and move it causing motion
Explanation:
The inhabitants of a small island begin exporting beautiful clothmade from a rare plant that grows only on their island. Seeing howpopular the small quantity that they export has been, they steadilyraise their prices. A clothing maker from New York, thinking thathe can save money by "cutting out the middleman," decides to travelto the small island and buy the cloth himself. Ignorant of thelocal custom of offering strangers outrageous prices and thennegotiating down, the clothing maker accepts (much to everyone'ssurprise) the initial price of 400 tepizes/m^2. The price of thiscloth in New York is 120 dollars/yard^2.If the clothing maker bought 500m^2 of this fabric, how muchmoney did he lose? Use = 0.625Express your answer in dollars tothree significant figures.
Answer:
Lost Money = $ 53200
Explanation:
First, we calculate the selling price of the cloth:
Selling Price = (Area of Bought Fabric)(Unit Price in America)
Selling Price = (500 m²)($ 120/yard²)(1 yard/0.9144 m)²
Selling Price = $ 71759.4
Now, we calculate the amount that the cloth maker paid (cost) for buying the fabric from America:
Cost = (Area of Fabric Bought)(Unit Selling Price)
Cost = (500 m²)(400 tepizes/ m²)($ 0.625/1 tepize)
Cost = $ 125000
Hence, the money lost is given as:
Lost Money = Cost - Selling Price
Lost Money = $ 125000 - $ 71759.4
Lost Money = $ 53240
Rounding off to 3 significant figures, we get:
Lost Money = $ 53200
A projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible.(a) Is the projectile a freely falling body? (b) What is its acceleration in the vertical direction? (c) What is its acceleration in the horizontal direction?
Answer:
Explanation:
When a projectile is launched at some angle to the horizontal with some speed vi , and air resistance is negligible , it is definitely a freely falling body .
It is so because it is free to accelerate towards the earth with acceleration of g . Air has no resistance , hence no force is acting on it except the gravitational force . Hence it is a freely falling body .
b )
The acceleration in the vertical direction is due to force exerted by the earth that is gravitational force on it . Hence its acceleration is equal to g in vertically downward direction .
c )
It has zero acceleration in horizontal direction . It is so because no force is acting on it in horizontal direction . So no acceleration will be present in horizontal direction . It will move in horizontal direction with constant speed of vi cos θ where θ is the angle vi make with the horizontal .
You travel down the highway at a steady rate of 75 mph (33.53 m/s)  for a total of 25 minutes, calculate how far you traveled in meters
Answer:
50280 meters
Explanation:
33.52 meters/seconds is 2011.2 meters/minutes (multiply by 60)
2011.2 meters/m * 25 minutes = answer
If you move for 4 seconds, and travel a distance of 360 meters, how fast were you going?
Answer:
90 m/s
Explanation:
Time taken = 4 sec
Distance travelled = 360 m
Speed = Distance / Time = 360/4 = 90 m/s
Distance travelled = 360m
Time taken = 4s
We have to find speed[tex].[/tex]
_________________________________
◈ Speed is defined as the ratio of distance travelled to the timr taken.
SI unit : m/s
➝ Speed = Distance / Time
➝ Speed = 360/4
➝ Speed = 90m/s
If A= +4j - 2i - 3k and C= -4i -2j - 3k , which of the following numbers is closest to the magnitude of A-C ?
The magnitude of Dot product of two vectors is 3.
Given vectors are,[tex]A= 4j - 2i - 3k[/tex] and [tex]C= -4i -2j - 3k[/tex]
The dot product two vectors shown below,[tex]A\cdot C=(-4*4)+(-2*-2)+(-3*-3)\\\\A\cdot C=-16+4+9\\\\A\cdot C=-16+13=-3[/tex]
Thus, The magnitude of Dot product of two vectors is 3.
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Choose the correct definition of angular momentum.
the product of the object’s moment of inertia and the object’s angular velocity
the product of the object’s momentum and the object’s angular velocity
the product of the object’s momentum and the object’s moment of inertia
the product of the object’s momentum and the object’s angle through space
The answer is "the product of the object's moment of inertia and the object's angular velocity.
The correct definition of angular momentum would be that it is the product of the object’s moment of inertia and the object’s angular velocity, therefore the correct answer is option A.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem we have to find the correct definition of angular momentum,
The angular momentum of the object = the moment of the inertia of the object × the angular velocity of the particle
The right response is option A since the definition of angular momentum is that it is the product of an object's moment of inertia and its angular velocity.
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Which of the following are properties of a conductor in electrostatic equilibrium? The force on a charge near the conductor is zero. Electric field lines just outside the conductor are perpendicular to the surface. All net charge in the conductor is on the surface. The electric field inside the conductor is zero.
Answer:
The electric field inside the conductor is zero.
Explanation:
In electrostatic equilibrium charges are assumed to be in rest. Therefore no current.
I = 0
From the ohm's law
ΔV= IR = 0
⇒ΔV =0
Therefore, potential V is same through the conductor.
Also, E = -ΔV d = 0
Hence, The electric field inside the conductor is zero.
Enter the following expression in the answer box below: 2gλ3m−−−−√, where λ is the lowercase Greek letter lambda.
Answer:
[tex]\sqrt{\dfrac{2g\lambda^3}{m}}[/tex]
Explanation:
We can write the expression here, but the point of the problem seems to be to see if you can manipulate the controls on the answer box to reproduce that expression.
[tex]\boxed{\sqrt{\dfrac{2g\lambda^3}{m}}}[/tex]
Which law of motion is this an example of? Newton's 1st 2nd or 3rd law?
Answer:
May be it is first law of motion.Based on these units, select any of the following expressions that could be valid expressions?v=a/tt=3√d2/vad=ata=d/t2a=√vd/t3v=at
Answer:
Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at
while the Invalid expressions are; v = a/t and d = at
Explanation:
Given expressions
1) v = a/t
2) t = ∛(d²/va)
3) d = at
4) a = d/t²
5) a = √(vd/t³)
6) v = at
First we get our units of parameters
V = m/s, t = sec, d = m, a = m/s²
so
1)
v = a/t
we substitute in our units of parameters
v = m/s² / s = m/s² × 1/s = m/s³
v ≠ m/s³
therefore it is false
2)
t = ∛(d²/va)
we substitute
t = ∛(m² / m/s × m/s²)
t = ∛(m² / m²/s³)
t = ∛(s³)
t = s
correct, the expression is true
3)
d = at
we substitute
d = m/s² × s
d = m/s² × s/1 = ms/s² = m/s
d ≠ m/s (because d = m)
so expression is false
4)
a = d/t²
we substitute
a = m / s² = m/s²
correct
the expression is true
5)
a = √(vd/t³)
we substitute
a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³) = √(m²/s⁴) = m/s²
so a = m/s²
correct
the expression is true
6)
v = at
we substitute in the units
v = m/s² × s = m/s² ×s/1 = ms/s² = m/s
v = m/s
correct
the expression is correct
One multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm. How many cells does it have? If each side doubles in length how many cells will it then have? Show your work below.
Answer:
W23e45rdfytg
Explanation:
Eawsredtrftgvbyhgtfrd54e
One multicellular organism is a cube. Each of its sides is 3 cm long. If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.
What is the matter?Anything which has mass and occupies space is known as matter , mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
As given in the problem, one multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm.
The volume of the multicellular organism = 3 × 3× 3
= 27 cm³
The number of cells = 27 cm³ / 1 cm³
= 27
Thus, If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.
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A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an amplitude of 81.87 (V/m) at a depth of 100 m. What is the attenuation constant of seawater
Answer:
The value is [tex]\alpha = 0.002 Np/m[/tex]
Explanation:
From the question we are told that
The first amplitude of the wave is [tex]E_{max}1 = 98.02 \ V/m[/tex]
The first depth is [tex]D_1 = 10 \ m[/tex]
The second amplitude is [tex]E_{max}2 = 81.87 \ (V/m)[/tex]
The second depth is [tex]D_2 = 100 \ m[/tex]
Generally from the spatial wave equation we have
[tex]v(x) = Ae^{-\alpha d}cos(\beta x + \phi_o)[/tex]
=> [tex]\frac{v(x)}{v(x)} =\frac{ Ae^{-\alpha d}cos(\beta x + \phi_o)}{ Ae^{-\alpha d}cos(\beta x + \phi_o)}[/tex]
So considering the ratio of the equation for the two depth
[tex]\frac{A}{A_S} = \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}[/tex]
=> [tex]\frac{98.02}{81.87} = \frac{e^{-10 \alpha }}{e^{-100 \alpha }}[/tex]
=> [tex]\alpha = \frac{0.18}{90}[/tex]
=> [tex]\alpha = 0.002 Np/m[/tex]
A wire carries a steady current of 2A.the Charge that passes a cross Section in 2s is
◈ Electric current :
Electric current is defined as the rate of charge flow. (per unit time)
I = Q/tI denotes current
Q denotes charge
t denotes time
Given : I = 2A and t = 2s
To Find : Charge flow in wire (Q)
[tex]:\implies\sf\:I=\dfrac{Q}{t}[/tex]
[tex]:\implies\sf\:2=\dfrac{Q}{2}[/tex]
[tex]:\implies\:\boxed{\bf{\red{Q=4\:C}}}[/tex]
A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The charge that will be in the wire is 4 C.
What is current?A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The capital letter I is a typical sign for current. The ampere, abbreviated as A, is the standard unit.
As it is given to us that the current in the wire is 2A, while the time for which the current flows through the wire is 2 seconds.
[tex]\rm I=\dfrac Qt[/tex]
Substitute the value we will get,
[tex]\rm 2\ A = \dfrac{Q}{2\ sec}\\\\Q = 4\ C[/tex]
Thus, the charge that will be in the wire is 4 C.
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The planet in our solar system whose orbit actually brings it inside the orbit of another planet is
A. Pluto
B. Mercury
C. Mars
D. Neptune
E. Earth
Answer:
Pluto
Explanation:
In our solar system, we have several planet. Pluto is one of the. Pluto is a planet that is highly oval shaped orbit and eccentric that brings it inside the another orbit. It get inside the orbit of Neptune. Sometimes even Neptune get far away from sun in comparison to the dwarf planet Pluto.
It is very strange happening in the world of planet. it occurs in the year of 1979 and 1999. But Pluto never ever crashed into Neptune. It happen because Neptune takes every three lapse that takes around the sun but Pluto makes only two lapse. This happening prevents two bodies from clashes.
Suppose you are designing an amplifier and loudspeaker system to use at a rock concert. You want to make it as loud as possible. How can you design the system to maximize the volume? Explain your answer?
Hi, I’m very confused by this question. Is it referring to the right hand rule to predict where the force and current will face?
Thanks for helping!
Answer is given below
Explanation:
Audio power amplifiers are found in all types of sound systems, including sound reinforcement, public address and home audio systems, as well as musical instrument amplifiers such as guitar amplifiers. This is the last electronic step in the general audio playback series before sending the signal to the loudspeaker. So when we want maximum volume or loud sound, we have to get it with maximum output and high input and low output impedancewhat is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow
The complete question is;
In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?
Answer:
2.185 × 10^(14) electrons/seconds
Explanation:
We are given current as 35 μA = 35 × 10^(-6) Amperes
The value of the charge on one electron is; e = 1.602 × 10^(-19) coulombs
Now, from conversions;
One ampere = one coulomb/second =
Then, 35 × 10^(-6) Ampere's would give;
35 × 10^(-6) Coulombs/sec
Now,
1.602 × 10^(-19) coulombs = 1 electron
Thus;
35 × 10^(-6) Coulombs/sec gives;
(35 × 10^(-6))/(1.602 × 10^(-19)) = 2.185 × 10^(14) electrons /sec
The average number of electrons per second that flow past a fixed reference cross-section perpendicular to the direction of flow is 2.185 × 10⁻¹⁴ electrons /sec
The flow of charge:The question is as given below:
In electronic circuits, it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross-section that is perpendicular to the direction of flow?
Given information:
Current I = 35 μA = 35 × 10⁻⁶ A
charge on electron e = 1.602 × 10⁻¹⁹C
We know that:
I = de/dt, rate of flow of charge.
1A = 1C/s
Thus,
35 × 10⁻⁶ A = 35 × 10⁻⁶ C/s
Now, one electron has a charge of 1.602 × 10⁻¹⁹C
So, the number of electrons for a current of 35 × 10⁻⁶ C/s will be:
n = (35 × 10⁻⁶ C/s) ÷ (1.602 × 10⁻¹⁹C)
n = 2.185 × 10⁻¹⁴ electrons /sec
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