Answer:
Work required is 328387.5 Joules.
Explanation:
Given the following data;
Mass = 2085kg
Initial velocity, Vi = 13m/s
Final velocity, Vf =22m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
Where;
W is the work required.
Kf is the final kinetic energy possessed by the object.
Ki is the initial kinetic energy possessed by the object.
But Kinetic energy = ½MV²
W = ½MVf² - ½MVi²
Substituting into the equation, we have;
W = ½(2085)*22² - ½(2085)*13²
Simplifying the equation, we have;
W = 1042.5 * 484 - 1042.5 * 169
W = 504570 - 176182.5
W = 328387.5J
Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.
The tension in a string from which a 7 kg
object is suspended in an elevator is equal to
74 N.
A) What is magnitude of the acceleration a of
the elevator? The acceleration of gravity is
9.8 m/s^2. Answer in units of m/s^2
B) What is its direction?
Answer:
0.77 m/s^2
Explanation:
Notice that the weight of the 7 kg mass is calculated via:
weight = m * g = 7 * 9.8 N = 68.6 N
Since the tension in the string is larger (74 N), then the elevator is moving upward and the net force on the object is equal to:
74 N - 68.6 N = 5.4 N
Which tells us that the acceleration of the object is:
F = m * a
5.4 N = 7 kg * a
a = 5.4 /7 m/s^2
a = 0.77 m/s^2
and this must be the same as the acceleration of the elevator since object and elevator are moving together.
The fire department arrive to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away. How fast did they travel?
Answer: The speed is 4 meters per second or 4 m/s.
Explanation:
First, we have the relationship:
Speed = Distance/Time.
In this case, we know that the fire department arrives to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away, this means that:
Time = 210 seconds
Distance traveled in that time = 840m.
Then the speed is:
Speed = 840m/210s = 4 m/s.
The speed is 4 meters per second.
Can u generate energy by impact force?
Answer:
When thinking about the impact force of a falling object, you can calculate the energy of the object at its point of impact if you know the height from which it was dropped.
Explanation:
You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you have found a plank that is 8 feet long, and you show it to your father.
1. Which plank will give you the most mechanical advantage?
Show your step by step work.
Answer:
The 8ft ramp
Explanation:
L/h
5/3
1.66
1.66:1
L/h
8/3
2.66
2.66:1
8ft is the ramp that would give you the most amount of mechanical advantage.
A disc 28 mm in radius rotates at a constant rate of 1.2 x10^5 rev/hr, about its central axis. Determine the tangential speed at a point 12mm from its center
Answer:
157m/s
Explanation:
We can convert 1.2 x10^5 rev/hr, to rad/secs for unit consistency
w=1.2×10^5rev/hr ×( 2π rad)/rev ×1 min/60sec
w=13083rad/sec
We can express the tangential speed inform of angular speed
Given speed at a point= 12mm12×10^-3m
V=wr
=13083rad/sec×12×10^-3
=157m/s
Hence the tangential speed at a point 12mm from its center is 157m/s
By quadrupling the mass of the body hanging on the thread what will become the period of oscillation?
Well, the tension in the thread will probably quadruple, but the hanging body will continue to just hang there.
The question gives us no evidence that it is doing any oscillating, and there's no reason for it to start just because it suddenly got heavier.
Planets A and B have the same size, mass, and direction of travel, but planet
A is traveling through space at half the speed of planet B. Which statement
correctly explains the weight you would experience on each planet?
A. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
O B. You would weigh the same on both planets because your mass
would adjust depending on the planet's speed.
O C. You would weigh less on planet B because it is traveling twice as
fast as planet A.
D. You would weigh more on planet B because it is traveling twice as
fast as planet A
why did the rocky planets form in the inner section of the solar system
Answer:
Because it was too hot for volatile compounds (like water) to condense in the inner solar system, rocky planetesimals formed from compounds with high melting points, such as iron and rocky silicates
(a) A man stands a distance d = 0.325 m from the left end of a platform as shown in the figure. The platform is supported by three lines. Find the tension in each line (in N). Assume the platform is uniform, with length L = 2.00 m and mass 30.5 kg, and the weight of the man is 675 N. (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.)
An object is positioned in front of a concave mirror behind the center of curvature. Choose the ray diagram that shows
the proper positioning of the image.
Answer: it’s the diagram with a small tree on one side and a larger tree on the other side.
The ray diagram that shows the proper positioning of the image is: the first diagram, where the image is smaller than the object.
What is a concave mirror?A concave mirror also known as converging mirror is a type of curved or spherical mirror in which the outside surface is silvered and the inner surface is made to reflect.
The size and the nature of the image of this kind of mirror is relatively dependent on the position of the object with regards the mirror.
Analysis:
When the object is behind the centre of curvature, the image is seen to be real, inverted and smaller than the object.
So, the image of the concave mirror increases in size as the object gets closer to the centre of curvature and would be same size as the object at the centre of curvature.
In conclusion, the ray diagram that shows the proper positioning of the image is the first diagram.
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Which best describes a metal such as Silver (Ag)?
Group of answer choices
Brittle, a good conductor, and ductile.
Lustrous, malleable, and forms cations.
Dull, highly reactive, and a semiconductor.
Low melting point, forms anions, good insulator.
Answer:
Brittle, a good conductor, and ductile.
According to the electronic configuration and position of silver in periodic table it can be inferred that it is brittle , good conductor and ductile.
What is electronic configuration?Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.
Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.
Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.
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Name the examples of compounds and their crystalline structure or shape.
Answer:
Water - Formula: H2O = Hydrogen2 + Oxygen. ...
Hydrogen Peroxide - Formula: H2O2 = Hydrogen2 + Oxygen2 ...
Salt - Formula: NaCl = Sodium + Chlorine. ...
Baking Soda - Formula: NaHCO3 = Sodium + Hydrogen + Carbon + Oxygen3 ...
Octane - Formula: C8H18 = Carbon8 + Hydrogen18
A satellite orbits earth with a mean altitude of 361 km. If the orbit is circular, what are the satellite's time period and speed?
Answer:
v = 7.69 x 10³ m/s = 7690 m/s
T = 5500 s = 91.67 min = 1.53 h
Explanation:
In order for the satellite to orbit the earth, the force of gravitation on satellite must be equal to the centripetal force acting on it:
[tex]F_{gravitation}= F_{centripetal}\\\\\frac{GM_{s} M_{E}}{r^2} = \frac{M_{s} v^2}{r}\\\\\frac{GM_{E}}{r} = v^2\\\\v = \sqrt{\frac{GM_{E}}{r} } \\\\[/tex]
where,
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
Me = Mass of Earth = 5.97 x 10²⁴ kg
r = distance between the center of Earth and Satellite = Radius of Earth + Altitude = 6.371 x 10⁶ m + 0.361 x 10⁶ m = 6.732 x 10⁶ m
v = orbital speed = ?
Therefore,
[tex]v = \sqrt{\frac{(6.67 x 10^{-11}N.m^2/kg^2)(5.97 x 10^{24} kg)}{6.732 x 10^6 m} }\\\\[/tex]
v = 7.69 x 10³ m/s
For time period satellite completes one revolution around the earth. It means that the distance covered by satellite is equal to circumference of circle at the given altitude.
So, its orbital speed can be given as:
[tex]v = \frac{Circumference of Circle at Given Altitude}{T}\\\\v = \frac{2\pi r}{T}\\\\[/tex]
where,
T = Time Period of Satellite = ?
Therefore,
[tex]T = \frac{2\pi r}{v}\\\\T = \frac{(2\pi )(6.732 x 10^6 m}{7.69 x 10^3 m/s}\\\\[/tex]
T = 5500 s = 91.67 min = 1.53 h
7. 100 Joules of work was done to move an object with a force of 15 N. How far did the
object move?
Answer:Distance=6.67 (rounded)
Explanation: Work = Force x Distance.
100 Joules of work= force of 15 N x Distance (?)
The work equation given above can be rearranged to find force or distance if the other variables are known:
Distance=Work / force
Distance=100Joules/15 N
Distance=6.67 (rounded)
An electron (m = 9.1 × 10−31 kg, q = −1.6 × 10−19 C) starts from rest at point A and has a speed of 5.0 × 106 m/s at point B. Only electric forces act on it during this motion. Determine the electric potential difference VA − VB.a) −71 Vb) +71 Vc) −26 Vd) +26 Ve) −140 V
Answer:
-71 V
Explanation:
Given that,
An electron starts from rest at point A and has a speed of 5.0 × 10⁶ m/s at point B.
We need to find the electric potential difference [tex]V_A-V_B[/tex]. It can be calculated by using the conservation of charges as follows :
[tex]qV=\dfrac{1}{2}mv^2[/tex]
m and q are mass and charge on electrons
[tex]V=\dfrac{mv^2}{2(-q)}\\\\V=-\dfrac{9.1\times 10^{-31}\times (5\times 10^6)^2}{2\times 1.6\times 10^{-19}}\\\\V=-71.09\ V[/tex]
So, the electric potential difference is (-71 V). So, the correct option is (a).
A diver makes 0.50 revolutions on the way from a 9.6-m-high platform to the water. Assuming zero initial vertical velocity, find the diver's average angular velocity during a dive.
Answer:
ω = 0.36 rev/s = 2.24 rad/s
Explanation:
First, we will find the time taken by the diver to reach the water. For this we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 9.6 m
Vi = initial vertical velocity = 0 m/s
t = time taken = ?
g = 9.8 m/s²
Therefore,
9.6 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t = √1.95 s²
t = 1.4 s
Now, the average angular speed of diver will be:
ω = No. of Revolutions/t
ω = 0.5 rev/1.4 s
ω = 0.36 rev/s = 2.24 rad/s
When the displacement of a mass on a spring is 12 A, what percentage of the energy is kinetic energy? At what displacement, as a fraction of A, is the energy half kinetic and half potential?
Answer:
75%
[tex]\dfrac{A}{\sqrt{2}}[/tex]
Explanation:
x = Displacement of spring = [tex]\dfrac{1}{2}A=\dfrac{A}{2}[/tex]
k = Spring constant
Total energy of the spring is
[tex]E=\dfrac{1}{2}kA^2[/tex]
Elastic potential energy is given by
[tex]U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}k(\dfrac{A}{2})^2\\\Rightarrow U=\dfrac{1}{2}k\dfrac{A^2}{4}\\\Rightarrow U=\dfrac{1}{4}\times \dfrac{1}{2}kA^2\\\Rightarrow U=\dfrac{1}{4}E[/tex]
Total energy is given by
[tex]E=U+K\\\Rightarrow K=E-U\\\Rightarrow K=E-\dfrac{1}{4}E\\\Rightarrow K=\dfrac{3}{4}E\\\Rightarrow \dfrac{K}{E}=0.75[/tex]
The percentage will be
[tex]\dfrac{K}{E}=0.75\times 100\%\\\Rightarrow \dfrac{K}{E}=75\%[/tex]
The required percentage is 75%
According to the given condition
[tex]\dfrac{E}{2}=\dfrac{1}{2}kx^2\\\Rightarrow \dfrac{\dfrac{1}{2}kA^2}{2}=\dfrac{1}{2}kx^2\\\Rightarrow \dfrac{1}{2}kA^2=kx^2\\\Rightarrow x=\sqrt{\dfrac{1}{2}A^2}\\\Rightarrow x=\dfrac{A}{\sqrt{2}}[/tex]
So, the energy is half when displacement is [tex]\dfrac{A}{\sqrt{2}}[/tex]
Let x be the displacement of spring which is given to be [tex]\frac{1}{2} A=\frac{A}{2}[/tex]
k= spring constant
Total energy of the spring is:
[tex]E=\frac{1}{2} kA^2[/tex]
Elastic potential energy is given as:
[tex]U=\frac{1}{2} kx^2[/tex]
Now on substituting the value of x in above equation:
[tex]U=\frac{1}{2} k\frac{A^2}{4}[/tex]
It can also be written as:
[tex]U=\frac{1}{4} *\frac{1}{2} kA^2 \\\\U=\frac{1}{4} E[/tex] (∵[tex]E=\frac{1}{2} kA^2[/tex])
Total energy can be written as:
E=U+K
⇒K=E-U
⇒K=E-1/4 E
⇒K=3/4 E
⇒[tex]\frac{K}{E} =0.75[/tex]
(i) Now, we need to calculate the percentage of kinetic energy:
[tex]\frac{K}{E} =0.75*100=75\%[/tex]
The percentage of kinetic energy is 75%.
(ii) In second it is asked at what displacement, as a fraction of A, is the energy half kinetic and half potential?
∴[tex]\frac{E}{2} =\frac{1}{2} kx^2[/tex]
On substituting the value of E in above equation we will get:
[tex]x=\sqrt{\frac{1}{2} A^2} \\\\x=\frac{A}{\sqrt{2} }[/tex]
So, the energy is half when displacement is [tex]\frac{A}{\sqrt{2} }[/tex] .
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what process resurfaces Venus?
The catastrophic resurfacing model suggests that planetary resurfacing on Venus occurred through infrequent, planet-wide volcanic events, large enough to bury all earlier material. In other words, resurfacing was a near-instantaneous change to Venus relative to the slow flow of geologic time.
Answer:
Infrequent, planet-wide volcanic events resurface Venus.
Explanation:
[K1 A2 T1 C1] A golfer strikes a golf ball on level ground.
The ball leaves the ground with an initial velocity of 42 m/s [32o
above horizontal].
a. Draw a vector diagram to describe the situation of the of golf
ball with initial velocity.
b. Find the range (horizontal distance) of the golf ball travelled.
c. Find the maximum height (vertical distance) the golf ball
reached.
Answer:
Explanation:
See the file attached .
b ) Range of projectile
= u²sin2θ / g
= 42² sin32 x 2 / g
= 42² sin64 / 9.8
= 161.8 m
c )
Max height = u² sin²32 / 2 g
= 42² sin²32 / 2x 9.8
= 25.27 m .
Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is then loaded with 1,000 kg of bricks. Which of the following would be the new gravitational force between the two trucks?
Answer:
New gravitational force would be: [tex]4.5\,\,\,10^{-5}\,\,\,N[/tex]
Explanation:
Recall the general form of the gravitational force between two objects of masses m1 and m2 separated a distance "d":
[tex]F_g=G\,\frac{m1\,*\, m2}{d^2}[/tex]
which for the 2000 kg trucks becomes:
[tex]F_g=G\,\frac{m1\,*\, m2}{d^2} \\3\,\,\,10^{-5}\,N=G\,\frac{2000\,*\, 2000}{d^2}[/tex]
when we add 1000 kg of bricks to one truck, we get the following unknown force (x) that we need to find:
[tex]F_g=G\,\frac{m1\,*\, m2}{d^2} \\x=G\,\frac{3000\,*\, 2000}{d^2}[/tex]
Now we divide term by term the last equation by the previous one, in order to cancel out common factors to both equation (G, d^2) and get the following equation:
[tex]\frac{x}{3\,\,\,10^{-5}} =\frac{3000}{2000} \\x=\frac{9}{2} \,10^{-5} =4.5\,\,\,10^{-5}\,\,\,N[/tex]
Since the triangle below contains an obtuse angle what type of angle must angle x be
Answer:
greater than 90 degrees
Explanation:
Explain why increasing the mass of a car affects how the car rolls down a ramp.
Answer:
Q1) Explain why increasing the mass of a car affects how the car rolls down a ramp
Ans1) Weight affects speed down the ramp but it's the mass that affects speed after a car leaves the ramp. Heavier cars have more momentum, so they travel further, given the same amount of friction
Which best describes her speed and velocity? (There are 60 seconds in 1 minute.) Her speed is 4.4 m/s, and her velocity is 0 m/s. Her speed is 1.1 m/s, and her velocity is 0 m/s. Her speed is 0 m/s, and her velocity is 2400 m/s. Her speed is 4.4 m/s, and her velocity is 4.4 m/s.
Answer:
A
Explanation:
Yw :)
Answer:
a
Explanation:
27.0 mL to the nearest milliliter
Answer:
27.0 milliliters is the nearest mililiter so 27.0 is the answer
Explanation:
Which of the following elements is more reactive than the
Answer:
you need to attach a picture so I can answer it
Which statements describe the types of energy emitted by the Sun? Check all that apply.
It emits most of its energy in gamma rays.
It emits all wavelengths in the electromagnetic spectrum.
It emits most of its energy as visible light.
Its peak wavelength is in the orange-yellow range.
It emits no X-rays or radio waves.
Its peak wavelength is in the yellow-green range.
The statement that describes the types of energy emitted by the Sun is that It emits all wavelengths in the electromagnetic spectrum, therefore the correct answer is option B.
What is electromagnetic radiation?Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons.
As given in the problem we have to find out which statements describe the types of energy emitted by the Sun from the given list of options,
Thus, Sun emits all wavelengths in the electromagnetic spectrum, which means that option B is the appropriate response.
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Suppose we measure the energy stored in some inductor to be E when there is a current I running through it. If I double the current in the inductor, the new total energy will become _____.
a. 8E
b. 2E
c. E
d. E/4
e. E/2
f. 4E
Answer:
If I double the current in the inductor, the new total energy will become 4E (option f).
Explanation:
The coil or inductor is a passive component made of an insulated wire that stores energy in the form of a magnetic field due to its form of coiled turns of wire, through a phenomenon called self-induction. In other words, inductors store energy in the form of a magnetic field. The energy stored in the space where there is a magnetic field in the inductor is:
[tex]E=\frac{1}{2} *L*I^{2}[/tex]
where E is Energy [J], L is Inductance [H] and I is Current [A].
If you double the current in the inductor, then the new value of the current is I'= 2*I. So replacing the new total energy is:
[tex]E'=\frac{1}{2} *L*I'^{2}=\frac{1}{2} *L*(2*I)^{2}=\frac{1}{2} *L*4*I^{2}=4*\frac{1}{2} *L*I^{2}[/tex]
Then:
[tex]E'=4*E[/tex]
If I double the current in the inductor, the new total energy will become 4E (option f).
The explosions that take place during a fireworks show are an example of which of the following?
Image of fireworks exploding in air
Chemical change
Chemical property
Physical change
Physical property
Answer:
I think it’s the 1rst one chemical change
Explanation:
Answer: A) Chemical Change
Explanation: When a firework explodes it realeses all of its chemical energy, thats why, (A)
is the correct answer
Plz help I don’t know what to do
A bird flies with a constant velocity of 100m/s for 10 minutes. calculate the magnitude of the displacement.
Answer:
s = ut
= 100 m/s * 10*60 s
= 60000m
= 60km
Answer:
60 km
Explanation:
velocity (v) = 100m/s
t = 10 minutes = 10(60) = 600 seconds
displacement = velocity × time
s = v × t
s = 100 × 600
s = 60,000m
s = 60,000/1000 km
s = 60km