The speed of the car when it is half –way down the hill is 7m/s.
This is another illustration of energy conservation. Set the potential energy at the top to equal the kinetic energy at the bottom, then solve for height h and then speed using the same total energy at h/2.
Top:
mgh = (1/2)mv2
hear m=mass
h=Hight
v= speed
gh = v2/2
h = v2/(2g)
= 102/[2(9.8)] m
= 5.1 m
Half way down:
u = speed
g(h/2) = u2/2
u = √[2g(h/2)]
= √(gh)
= √[(9.8)(5)] m/s
= 7.0 m/s
What is Kinetic energy?
the energy that an object produces as a result of its motion. There is unquestionably a need to apply particular forces when an object is prepared to accelerate. Applying force requires work, and once the job is finished, energy is transmitted to the object, causing it to move with a constant speed.
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a mixture can be classified as a solution, a suspenstion, or a colliod based on the size of its............particles
Answer:
large
Explanation:
A mixture can be classified as a solution, a suspension, or a colloid based on the size of its large particles.
Hope it helps!
Calculate the half-life of a radioactive substance whose disintegration constant
happens to be 0.003 s-¹
231 years is the half-life of a radioactive substance whose disintegration constant happens to be 0.003s⁻¹.
Half-Life: It is the amount of time it takes for half of a Radioactive particular sample to react particular quantity requires to reduce its initial value to half. That means the time taken by the radioactive substance or isotopes to decay half.
Half-Life Formula :t₁/₂ = 0.693/λ
Where as t1/2 is Half-Life of a radioactive substance
λ= decay constant
We have λ=0.003s⁻¹ substitute in the formula
t1/2=[tex]\frac{0.693}{0.003}[/tex] = 231.
Hence 231 years is the half-life of a radioactive substance whose disintegration constant happens to be 0.003s¹.
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1. The figure below shows a partial profile of a roller-coaster. The coaster begins from rest at position A at height ha
30.0 m and hb 10.0 m.
a) Determine the speed of the coaster at position B. Friction and air resistance are negligible.
b) If the efficiency of the coaster is 55%, what would be the value of the coaster speed at point B?
The speed of the coaster at position B is 12mvB2. The value of the coaster speed at point B 3.016 m.
What is speed?Speed is the rate in which something is traveling.
The speed of the coaster at position B can be determined using the work-energy theorem. According to the theorem, the work done by the gravitational force is equal to the change in kinetic energy. Therefore, the kinetic energy of the roller coaster at point B is equal to the potential energy at point A.
The potential energy at point A is equal to mghA, where m is the mass of the roller coaster, g is the acceleration due to gravity, and hA is the height of point A. Similarly, the kinetic energy at point B is equal to 12mvB2, where vB is the speed of the roller coaster at point B.
Therefore, the speed of the roller coaster at point B can be calculated as follows:
vB = √(2ghA/m) = √(2*9.8*30/m) = 5.48 m/s.
b) The efficiency of the roller coaster is 55%, so the actual speed of the roller coaster at point B would be 55% of the calculated speed. Therefore, the actual speed of the roller coaster at point B would be 5.48 * 0.55 = 3.016 m
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please help me Collage and Career prepertation
An external force of 5 n is applied to a 10 kg object over a time of 3 s. Determine the impulse of the object.
The impulse of the 10kg object is 15Ns.
How to calculate impulse?Impulse is the integral of force over time. The impulse of an object in physics is a term that is used to describe or quantify the effect of force acting over time to change the momentum of an object.
It is represented by the symbol J and usually expressed in Newton-seconds or kg m/s.
According to this question, an external force of 5N is applied to a 10kg object over a time of 3 s. The impulse can be calculated as follows:
Impulse = 5N × 3s = 15Ns
Therefore, 15Ns is the impulse of the object.
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if such a laser beam is projected onto a circular spot 1.8 mm in diameter, what is its intensity in w/m2?
The intensity is 0.294*103 W/[tex]m^{2}[/tex].
What does light intensity mean?The pace at which light disperses over a body of a specific region some way from a source is referred to as intensity. The intensity changes depending on the source's power and distance from it.
What is an example of intensity?Occasionally, the adjective "intensity" is associated with fury, fire, and violence. It is used to provide a description of a flame's or even a love affair's intensity. For instance, the bond between Bogart and Bergman in Casablanca was very strong.
Briefing:
Intensity I = energy/(area*time)
= power/area
=0.75*10-3 W/(π/4*1.8*1.810-6 m2)
= 0.294*103 W/[tex]m^{2}[/tex].
Therefore, the intensity is 0.294*103 W/[tex]m^{2}[/tex].
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A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (Assume it to be uniform.) b) What distance does it travel while speeding up?
initially, the car is traveling at 5.0 m/s.
so, we know acceleration for changing velocity is :
a = (v-v[tex]_{o}[/tex])/t ..........(i)
where v is the final velocity
v[tex]_{o}[/tex] is the initial velocity
t is the time taken to change velocity
Now, as per the question :
initial velocity, v[tex]_{o}[/tex]=5.0 m/s
final velocity, v =11 m/s
time taken, t = 3 s
putting the values in equation (i),
a = ( 11-5 )/3
a = 2 m/s²
Therefore, a, after 3 s, is 2 m/s².
7. what is the maximum angle of climb (steady velocity climb) for a turbojet powered aircraft with an (l/d)max equal to 10.5 and a gross weight of 8000 lb. if it is producing a thrust of 2000 lb.?
The maximum angle of climb for a turbojet powered aircraft is 8.97°.
Let us consider the velocity is steady.
T is thrust, W is weight, L for lift force, D for drag and θ is angle of climb
From the given information, we can write the below equations,
T = D + W sinθ -----(1)
L = W cosθ -----(2)
Given that, L/D = 10.5
D = L/10.5 -----(3)
Placing (3) in (1), we have
T = L/10.5 + W sinθ
T = (W cosθ)/10.5 + W sinθ
cosθ + 10.5 sinθ = T/W * 10.5
cosθ + 10.5 sinθ = (2000/8000) * 10.5
cosθ + 10.5 sinθ = 2.625
Solving the above equation, we get θ = 8.97°
Thus, the maximum angle of climb is 8.97°.
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Based on this model, how much of the energy will the tertiary consumers receive if the primary consumers have 3600 joules of energy?.
If the primary consumers have 3600 joules of energy, the tertiary consumers receive 36 joules energy.
What is 10 percent law of energy transfer?The ten percent law was proposed by Lindemann (1942) to explain how energy moves from one trophic level to the next. The law states that only around 10% of the organic substance that is transferred from one trophic level to the next of food is stored as flesh.
The rest is either lost in the transfer process or destroyed during breathing. Only 10% of the energy used by plants for primary production can be stored as net production that is available to herbivores. 10% of the energy in the food gets fixed into animal flesh when plants are eaten by animals, making it available for the next trophic level (carnivores). Only around 10% of the animal's energy is stored in its meat for the higher level when it is eaten by a predator.
So, If the primary consumers have 3600 joules of energy, the tertiary consumers receive 3600×10%×10% joules = 36 joules of energy.
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In music, two notes are said to be an octave apart whenone note is exactly twice the frequency of the other. Suppose youhave a guitar string playing frequency fo.a) To increase the frequency by 4 octave(s), to 16fo, by what factor would you have toincrease the tension?Tv/To= ?b) To increase the frequency by 4 octave(s), to 16 fo, by what factor would you have todecrease the length?
To increase the frequency by 4 octave(s), to 16fo, by a factor of 16 we have to increase the tension. To increase the frequency by 4 octave(s), to 16fo, by a factor of 1/16 we have to decrease the length.
Is the frequency doubled at the octave?An octave is a logarithmic unit for ratios between frequencies in electronics, with one octave equal to a doubling of frequency. For instance, 80 Hz is the frequency one octave above 40 Hz. The phrase comes from the Western musical scale, in which an octave represents a frequency doubling.
Finding octaves between two frequencies: how do you do it?You can get the number of octaves between two frequencies, such as the upper and lower bounds of a band of noise, by first determining their ratio, then calculating the log of it, and then dividing that by the log of 2.
What is an octave's straightforward definition?A musical interval is called an octave. Both in terms of music and physics, an octave is defined as An octave is the distance in pitch between a note, such as C#, and the note that follows it with the same name but is either higher or lower.
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the molecular shape of a covalent species is determined not only by the number of electron groups that join the atoms, but by the number of electron groups as well, since these electrons also occupy space. t or f
A covalent species' molecular structure is influenced by both the number of shared and unshared electron groups that link the atoms together because these electrons take up space as well.
The connection is that the quantity of valence electrons influences which other atoms an atom can form a bond with.A chemical bond involving the exchange of electron pairs between atoms is referred to as a covalent bond. The electron pairs are known as bonding pairs, it should be highlighted.The electrons in the atom's outermost shell are known as the valence electrons. The connection is that the quantity of valence electrons influences which other atoms an atom can form a bond with.
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how far the first bright diffraction fringe is from the strong central maximum if the screen is 13.0 m away.
The first bright diffraction fringe is 13.0 m away from the strong central maximum if the screen is 13.0 m away.
Calculate the wavelength of light.
The wavelength can be calculated using the formula, λ = d/n, where d is the distance between the slits (d = 0.050 mm) and n is the order of the diffraction fringe (n = 1).
Therefore, λ = 0.050 mm/1 = 0.050 mm.
Calculate the distance of the first bright diffraction fringe.
The distance of the first bright diffraction fringe can be calculated using the formula, d = λD/d, where λ is the wavelength of light, D is the distance between the screen and the slits (D = 13.0 m) and d is the distance between the slits (d = 0.050 mm).
Therefore, d = (0.050 mm)(13.0 m)/0.050 mm = 13.0 m.
Therefore, the first bright diffraction fringe is 13.0 m away from the strong central maximum if the screen is 13.0 m away.
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In the example with maya and her bike, which of newton's three laws of motion is best illustrated? why?.
Newton's first law of motion, often known as the law of inertia, is the law that most exemplifies this.
Unless it is operated upon by an external force, the law stipulates that every item will remain in a state of rest or uniform motion. Due to hitting a curb, the bike comes to a stop. A body's resistance to being in its condition of rest or uniform motion is known as inertia. Due to its inertia, Maya is also propelled into the air.Newton's second law of motion serves as an example. Force is directly proportional to mass and acceleration, to sum up this law. The second box accelerates more quickly because its mass is lower than that of the first box.Newton's third rule of motion serves as the clearest example of this. According to this concept, there is an equal and opposite reaction to every action. Air is pushed downward by the bird's wind as it flies. The bird can fly because air pushes upward on it as it utilizes its wind to push air downward. Air moves upward and downward in equal but opposite directions.To know more about laws of motion
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13. Squids and octopuses take in water and forcibly expel it through the
siphon in a sudden spurt that pushes them through the water. This
propulsion is an example of which Newton's Law?
A. 1st Law
B. 2nd Law
C. 3rd Law
D. All of Newton's Laws
Squids and octopuses forcefully expel water through the siphon after ingesting it, propelling themselves through the water. Third Law of Newton.
Describe the third law of Newton's law?His third law asserts that there is an opposite and an equal response in nature for every action (force). When an object A pulls on an object B, the opposite force is applied to the first object by object B. Alternatively said, interactions lead to forces.
What are examples of the third law of Newton?There are numerous real-world applications of Newton's third motion law. For instance, when you leap, the earth exerts an equal and opposing reaction force that propels you into to the air. This is because when you apply a force to it with your legs, it responds in kind. Rockets and other projectiles are designed using Newton's third law by engineers.
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A passenger on an airplane flying across the Atlantic receives an extra radiation dose of about 5 μSv per hour from cosmic rays. Assume there are no other significant radiation sources besides natural background. Suppose that the natural background exposure in a year is 3 mSvHow many hours of flying would it take in one year for a person to double his or her yearly radiation dose?Answer in hr please
The person needs to fly 600 hours to double his radiation.
What is radiation?Radiation is the energy that is comes from a source and it is travels through the space at the speed of light.
The passenger on to the airplane gets an extra dose to the of five microsieverts and per hour when his plane is flying across the Atlantic. We want to know when one person should apply in the double. His early radiation is to good. The person gets a radiation dose due to the background radiations. Background radiations are the what this is about. There are no way to double they can do the irradiation. Does it the person need a lot of time hours to fly? We can definitely find a number of the hours by using the relation gee of total doors to that need to be received extra divided by that power. The double layer radiation of the was added to our Essen. Does the person need to receive an extra dose of the
extremely sure barrier from to a the Cosmic Radiations as a person is receiving the radiation at a rate of five of Microsoft word barrier from Cosmic Radiations? We can be write this as two equal to three giant standard of the power minus three c. Your to support and Seaworld will be deleted from to the numerator and denominator of disk. It will do that if we use it.
Thus ,The person needs to to be fly 600 hours to double his radiation.
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in a region of space where gravitational forces can be neglected, a sphere is accelerated by a uniform light beam of intensity 8.0 mw/m2. the sphere is totally absorbing and has a radius of 1.0 microns and a uniform density of 4500.0 kg/m3. what is the magnitude of the sphere's acceleration (in m/s2) due to the light?
The answer for the magnitude of the sphere's acceleration (in m/s²) due to the light is 4.44×10⁻⁹ m/s²
Newton's second law must be applied in order to determine the acceleration.
F = m×a and a = F/m.
We use the defined pressure and the radiation pressure for an absorbent surface to determine the force.
P=I/c absorbent surface
P = F / A
F / A = I / c
F = I A / c
A circle's total area is
A = π×r²
We swap out
F = I π r² / c
Let's compute
F = 8.0×10⁻³ π (1.0×10⁻⁶)²/3×10⁸
F = 8.375×10⁻²³ N
To measure Density
ρ = m / V
m = ρ V
m = ρ (4/3 π r³)
m = 4500 (4/3 π (1×10⁻⁶)³)
m = 1,885×10⁻¹⁴ kg
Now let's determine the acceleration.
a = 8.375×10⁻²³ / 1.885×10⁻¹⁴
a = 4.44×10⁻⁹ m/s² absorbent surface
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Disk Y of rotational inertia ly=(1/2)MY(RY)^2 about its center is held at rest above disk X of rotational inertia Ix=(1/2)Mx(RY)^2 about its center. Disk
X initially rotates about its center with an angular velocity of +w0. Disk Y is then slowly lowered onto disk X until both disks are in contact and rotate
together with a common angular velocity. Which two of the following predictions are correct about the angular momentum of disk X and disk Y
immediately before and after the rotational collision? Select two answers.
The angular momentum of disk X immediately after the collision is greater than the angular momentum of disk X immediately before the
collision.
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the
collision.
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of the disk X-disk Y system
immediately before the collision.
The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system
immediately before the collision.
The statements that are true are
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.What is angular momentum?Angular momentum is the product of the rotational inertia and angular speed of a rotating object.
How to find which statements are true about the angular momentumLet
I₁ = initial angular momentum of disk X = Ixω₀ where Ix = rotational inertia of disk x and ω₀ = angular velocity of disk y, I₂ = initial angular momentum of disk Y = 0 (since it is initally stationary) where I₃ = final angular momentum of disk x = Ixω and I₄ = final angular momentum of disk Y = Iyω where Iy = rotational inertia of disk y and ω = their common angular velocity after the collisionFrom the law of conservation of angular momentum, we have that
initial angular momentum equals final angular momentum
So, I₁ + I₂ = I₃ + I₄
Ixω₀ + 0 = Ixω + Iyω
Ixω₀ = Ixω + Iyω
From the above, we see that
Since I₄ > I₂ = 0,
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.
Also, since I₁ + I₂ = I₃ + I₄,
The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.
So, the statements that are true are
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.Learn more about angular momentum here:
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2. How much force is needed to accelerate a truck with a mass of 2,200 kg at
an acceleration of 3.8 m/s²?
I
Answer:
8360N
Explanation:
F = ma
= 2200kg × 3.8 m/s²
= 8360 N
if the plane is flying horizontally and suddenly pulls upward, in which direction does the nose of the plane tend to move?
If the plane is flying horizontally and suddenly pulls upward, the nose of the plane tends to move upwards as the tail moves downwards.
A plane (formally an airplane) is a fixed-wing aircraft that is propelled forward by the thrust of a jet engine, propeller, or rocket engine.
All flight controls use the same basic lift principles as wings. When the pilot moves the controls, they produce lift of nose either up or down.
When the pilot pulls on the control column, the elevator moves up. This creates a wing-like curve on the surface that pulls the tail down. By moving the tail down, the nose of the aircraft rises.
When the pilot pushes forward on the controls, the elevator points down. The opposite happens and there is a lift that pulls the tail up. Pulling the tail up causes the nose of the plane to drop down.
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The table shows data about lightning and thunder.
Lightning and Thunder Data
Occurrence Lightning
Observed Thunder Heard Distance to
Lightning (m)
A 8:00:00 p.m. 8:00:01 p.m. 330
B 5:30:00 p.m. 5:30:04 p.m. 1,320
C 6:45:00 p.m. 6:45:06 p.m. 1,980
D 7:20:00 p.m. 7:21:00 p.m. 19,800
According to the table, how fast does the sound of thunder travel?
Answer:
Explanation:
If the question is set up correctly here, we can solve this correctly.
Lightning and Thunder Data
Occurrence Lightning
Observed Thunder Heard Distance to ---- We need this
Lightning (m)
A 8:00:00 p.m. 8:00:01 p.m. 330
B 5:30:00 p.m. 5:30:04 p.m. 1,320
C 6:45:00 p.m. 6:45:06 p.m. 1,980 ---- We need this
D 7:20:00 p.m. 7:21:00 p.m. 19,800
6:45:06 - 6:45:00 = 6
So 6 seconds. We also get 1980. So we do 1980/6, which is 330(m)?
If the unit is meters, then the sound of thunder travels at 330(m)
A coworker did not clean his work area before going home this could cause an accident so you quickly clean up the next day you see the cowoker. what would you be most and least likey to do?
Inform him that he should be more cautious because his work environment could have resulted in an accident. Inform him that you have cleaned up and that he owes you a favour.
What is a work environment ?The setting, social features, and physical conditions in which you perform your job are referred to as your work environment. These factors can have an impact on employee happiness, workplace relationships, collaboration, efficiency, and health.
A workplace culture is the set of shared values, belief systems, attitudes, and assumptions that employees share. Individual upbringing, as well as social and cultural context, influence this.
Taking care of the workplace environment boosts productivity, aids in talent retention, and, most importantly, is beneficial to the company's overall mental health. No job is perfect, not even those with an amazing office, a high salary, or entirely vocational tasks.
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what can you conclude about the time it takes two balls of different mass and different radius to roll down an incline?
Therefore, the time required for an object t roll down an inclination plane will shorten as the weight (body) of the object increases.
What is the best way to define mass?A measurement of how much matter is present in or makes up a physical body. In physical laws, an object's mass is crucial to Newton's laws because it influences the force needed to accelerate it and, consequently, how much inertia it has.
How are masses determined?Digital scientific weights and beams balances, like a triple beam balance, are examples of several sorts of balances. The metric system uses both grams or kilograms as the basic unit of measurement for mass.
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how much work must be done on a particle with a mass of mm to accelerate it from rest to a speed of 0.083 cc ? express your answer in terms of mc2mc2 .
A atom with a size of mm needs to perform work equal to 0.68 mc2 in order to acceleration it from rest to something like a velocity of 0.083 cc.
What is an explain acceleration?The rate about which direction of velocity change over time is referred to as acceleration. It is said to be escalating when it starts to move quickly or slowly.
What three forms of acceleration are there?The three main types of propelled motions are homogeneous acceleration, non-uniform kinetic energy, and average acceleration. The motion in which an item moves in a linear fashion while increasing in velocity at regular intervals is referred to as uniform acceleration.
Briefing:as a mass particle's kinetic energy is,
KE = mc²( - 1 ) ............1
last KE = mc2 (1.68 - 1 )
final KE = 0.68mc²
W = final KE - initial KE
Work = 0.68 mc²
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In figure 1 airbag inflation rates are represented by the
The typical air bags from 1997 and 1998 automobiles are compared in Figure 1. The values depicted are the average of the information provided by 11 separate cars.
What do we mean by inflation?Inflation is a unit of measurement used to determine how much a group of goods and services have increased in cost over a given period of time, usually a year. Possibly one of the most well-known economics terms. Because of inflation, nations have gone through protracted periods of instability. In the field of economics, inflation refers to an increase in the overall cost of goods and services in a country.
What is the causes of inflation?The majority of economists concur that chronic excessive expansion in the money supply is the primary driver of high inflation and hyperinflation, both of which have profoundly disruptive consequences on the actual economy. John Taylor, a Stanford economist, claims that when the Federal Reserve sets an interest rate that is too low or when the expansion of the money supply is too rapid, inflation rises. As of right now, it is moving too quickly.
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a 45.5-g super ball traveling at 27.5 m/s bounces off a brick wall and rebounds at 21.0 m/s. a high-speed camera records this event. if the ball is in contact with the wall for 3.30 ms, what is the magnitude of the average acceleration of the ball during this time interval?
Throughout this period of time, the ball's average acceleration was 1.46*104m/s2.
What is an explain acceleration?Acceleration refers to the amount of change in a moving object's speed and direction over time. When something moves faster or slower, it is considered to be accelerating. Motion within a single circle speeds despite the fact that velocity is constant since the variable is always moving.
What three forms of acceleration are there?Speeding bullet, non-uniform energy density, and uniform acceleration are the three primary categories of rapid motion. Uniform acceleration describes a motion in which a object moves in some kind of a straight path while accelerating gradually over time.
Briefing:Vi = 27.5m/s
Vf = 21m/s
Vf = Vi + at
a= Δt/Δv
a= 21m/s-(-27.5m/s)/3.30*10⁻³
a = 1.46*10⁴m/s²
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One important way astronomers can learn in some detail about what happens when galaxies collide is.
Astronomers can learn to simulate the galaxy's collisions on a large computer and watch what the simulation will predict.
What is a galaxy?A galaxy can be described as a system of stars, interstellar gas, dust, and dark matter, bound together by gravity. Galaxies from 100 million stars range in size from dwarf to million stars to the largest galaxies known as supergiants.
Most of the mass in a galaxy is in the form of dark matter, with only a few percentages of that mass visible as stars and nebulae. Supermassive black holes are a common characteristic at the centers of galaxies.
Galaxies can be categorized according to their visual morphology as elliptical, spiral, or irregular. The Milky Way's central black hole or Sagittarius A* has a mass 4 million times greater than the Sun.
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the time constant of an rc circuit is 8.0 s. how much time t is required for the capacitor (uncharged initially) to gain one-half of its full equilibrium charge?
Time t is required for the capacitor to gain one-half of its full equilibrium charge is 5.54 sec.
What is RC circuit?An electrical circuit consisting of passive components like resistors and capacitors, driven by current source or the voltage source is called resistor-capacitor circuit. The capacitor stores energy and resistor that is connected to the circuit controls the rate of charging or discharging.
Given, τ is 8 and q is charge
As we know, q= qo (1−e ^−t/τ )
1/2= 1- e^-t/8
0.5= e^-t/8
t/8 = -ln 0.5
t= 5.54 sec
Time t is required for the capacitor to gain one-half of its full equilibrium charge is 5.54 sec.
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A car is moving at 30.0 m/s, east in a straight line approaching the red traffic light as shown. The
time it takes for the car to stop is .6 seconds.
What is the acceleration of the car?
Answer:
–5
Explanation:
u = 30m/s , v = 0(comes to a stop) , t = 6s, a = ?
a = v – u/t
a = 0 – 30/6
a = –30/6
a = –5
A car is moving at 30.0 m/s, east in a straight line approaching the red traffic light as shown. The time it takes for the car to stop is 0.6 seconds. The acceleration of the car is -5 m/s.
What is speed?Speed is defined as the pace at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined.
Given
u = 30m/s ,
v = 0(comes to a stop) ,
t = 6s
To calculate acceleration we use formula
a = v – u/t
a = 0 – 30/6
a = –30/6
a = –5 m/s
Thus, a car is moving at 30.0 m/s, east in a straight line approaching the red traffic light as shown. The time it takes for the car to stop is 0.6 seconds. The acceleration of the car is -5 m/s.
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Explanation:
Refer the explanation in the picture
a guitar string is fixed at both ends. if you tighten it to increase its tension
a guitar string is fixed at both ends. if you tighten it to increase its tension the frequencies of its vibrational modes will increase but its wavelengths will not be affected.
Stretching a string between two points, as in a stringed instrument, will cause tension on the string. Tension is the degree of stretching that is applied to the string. As the string is tightened, the frequency rises; as the string is loosened, the frequency falls. Strings are tightened or loosened by string musicians to change the pitches of their instruments.
We are aware that a tight string's frequency is determined by
v=√(T/μ)
where c is the frequency of sound wave T is tension and μ is mass per unit length
and velocity is provided by
v=νλ
As increases v also increase ν but wavelength remain same because ends of string are fixed.
your question is incomplete but most probably the full question was
Guitar string is fixed at both ends. If you tighten it to increase its tension (explain your answer):
a) the frequencies of its vibrational modes will increase but its wavelengths will not be affected.
b) both the frequency and the wavelength increase.
c) the wavelength increases but the frequency is not affected.
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