A rectangular dog pen is constructed using a barn wall as one side and 63 m of fencing for the other three sides what is the maximum area of the dog pen

Answers

Answer 1
The answer is 129 meters addition

Related Questions

16) One exterior angle of an isosceles triangle is 70°. a) Find the possible measures of the other two exter angles. b) How many answers can you find? Explain.​

Answers

Answer:

The other exterior angles must be 145 degrees. There is only one answer because there cannot be 2 of 110 degree angles in a triangle, so the other two exterior angles must correspond to the 2 equal angles in the triangle.

Step-by-step explanation:

For an exterior angle, we know that an exterior angle added with its corresponding interior angle is equal to 180 degrees. Thus, 180 = 70 + i, or the interior angle. i is then 110 degrees.

An isosceles triangle has two equal angles. As a triangle can only be 180 degrees. we cannot have 2 of i, as doing so would be equal to 220 degrees. Therefore, for the other two interior angles, they must be equal. Representing o, their angles could be put into an equation of 110 + 2o = 180, so o = 35.

For the other exterior angles, their corresponding interior angles are equal to 35 each, so they must be 145 degrees. There is only one answer because there cannot be 2 of 110 degree angles in a triangle, so the other two exterior angles must correspond to the 2 equal angles in the triangle.

hi pls help me out asap 1

Answers

Answer:

B: 112.5

Step-by-step explanation:

first, we split up the rhombus into two triangles, with the height of 15 and the length of 7.5. when you multiply these you will get 112.5, and normally if you are just getting the area of the triangle, then you would divide it by two, but seeing that we have 2 triangles here, we would multiply it by two afterwards so an easier way to do it is just to not divide.

Find the 7th term in the
sequence.
-1, 2, -4, 8,...
Hint: Write a formula to help you.
1st term . Common Ratio desired term – 1)
Remember to use the correct Order of Operations!
Enter

Answers

Answer: -64 Maybe

Step-by-step explanation:

It look like each term goes up by double of the last term.

Operations on Wh b) 6 X (5 + 4) ​

Answers

Answer:

6X(5 + 4)

6x(9)

54x

Answer:

the answer is 54x hope it will help full to you

GRADE 6 MATH. 10 POINTS
NO FAKE ANSWER OR LINK

Answers

Answer:

11-

3 / 8 * 5 / 5 = 15 / 40

2 / 5 * 8 / 8 = 16 / 40

16 / 45 + 15 / 45 =

31 / 40

12-

5 / 6 * 9 /9 = 45 / 54

4 / 9 * 6 / 6 = 24 / 54

24 / 54 + 45 + 54 = 69 / 54

69 / 54 =

1   15 / 54

Why is (0,0) a Y intercept and isn't an X intercept? ​

Answers

Good question. It is supposed to be both the y-intercept and the x-intercept and is the only point on a graph that can be both. Something in wrong in that thing.

Patty made a banner that has an area of 175 square inches. The length and width of the banner are whole numbers. The length is 7 times greater than the width. What are the dimensions of the​ banner? The banner has a length of nothing ▼ in.In. sq in.Sq in. and a width of nothing ▼ sq in.Sq in. in.

Answers

Answer:

Length = 35

w = 5

Step-by-step explanation:

l x w = area

7y x y = 175

7y^2 = 175

y^2 = 175/7

y^2=25

y=5

The length is 7y, so it's 5 times 7 or 35.

The width is just y, so it's 5.

7(x + y) ex2 − y2 dA, R where R is the rectangle enclosed by the lines x − y = 0, x − y = 7, x + y = 0, and x + y = 6

Answers

Answer:

[tex]\int\limits {\int\limits_R {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Step-by-step explanation:

Given

[tex]x - y = 0[/tex]

[tex]x - y = 7[/tex]

[tex]x + y = 0[/tex]

[tex]x + y = 6[/tex]

Required

Evaluate [tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex]

Let:

[tex]u=x+y[/tex]

[tex]v =x - y[/tex]

Add both equations

[tex]2x = u + v[/tex]

[tex]x = \frac{u+v}{2}[/tex]

Subtract both equations

[tex]2y = u-v[/tex]

[tex]y = \frac{u-v}{2}[/tex]

So:

[tex]x = \frac{u+v}{2}[/tex]

[tex]y = \frac{u-v}{2}[/tex]

R is defined by the following boundaries:

[tex]0 \le u \le 6[/tex]  ,  [tex]0 \le v \le 7[/tex]

[tex]u=x+y[/tex]

[tex]\frac{du}{dx} = 1[/tex]

[tex]\frac{du}{dy} = 1[/tex]

[tex]v =x - y[/tex]

[tex]\frac{dv}{dx} = 1[/tex]

[tex]\frac{dv}{dy} = -1[/tex]

So, we can not set up Jacobian

[tex]j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right][/tex]

This gives:

[tex]j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right][/tex]

Calculate the determinant

[tex]det\ j = 1 * -1 - 1 * -1[/tex]

[tex]det\ j = -1-1[/tex]

[tex]det\ j = -2[/tex]

Now the integral can be evaluated:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex] becomes:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{x^2 - y^2}} \, *\frac{1}{|det\ j|} * dv\ du[/tex]

[tex]x^2 - y^2 = (x + y)(x-y)[/tex]

[tex]x^2 - y^2 = uv[/tex]

So:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{|det\ j|}\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *|\frac{1}{-2}|\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{2}\, dv\ du[/tex]

Remove constants

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 {\int\limits^7_0 {ue^{uv}} \, dv\ du[/tex]

Integrate v

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 \frac{1}{u} * {ue^{uv}} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 e^{uv} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du[/tex]

Integrate u

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0[/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}][/tex]

Open bracket

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}][/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

PLEASE HELP!!
A wooden block in the shape of a rectangular pyramid is shown below:

A shaded right rectangular pyramid is shown.

If a cross section of the block is cut in a plane parallel to the base of the pyramid, which of the following shapes describes the cross section? (5 points)

a
Triangle

b
Rectangle

c
Trapezoid

d
Hexagon

Answers

Step-by-step explanation:

A shaded right rectangular pyramid is shown. where is the shade rectangular pyramid....how do I know the answer when you did post the full

question

the graph of y=3x+=4 is

Answers

Answer:

Step-by-step explanation:

The answer is B.

It's a line that shows every point that satisfies the equation

y = 3x + 4  which is what I think you meant (but I'm not sure). If I am correct then there are a million possible points that could be the answer to this question.

If I am not correct, leave a comment that tells me so, and I'll revise my answer.

Never mind the question has the right equation. And my answer remains as given.

Find the scale factor and determine the type of the dilation.

Answers

Answer:
Both answers are B

The ________ is the distance around a circle.
A. Radius
B. Diameter
C. Circumference
D. area

Answers

Answer:

the distance is called the circumference

A is a set of factors of 12. Which one of the following is not member of A? *
A. 3
B. 4
C. 5
D. 6​

Answers

Answer:

5

Step-by-step explanation:

3*4=12

4*3=12

6*2=12

but 12 is not factor of 5

Answer: 5
Explanation:
3x4=12
4x3=12
6x2=12
But 5 does not equal 12

I will give u brainliest and 5 star and thanks if its correct

Answers

Answer:

5. a) 5b

   b) 3b + 2b

Step-by-step explanation:

a) b + b + b + b + b is the same as

5 * b or 5b

b) 5b = 3b + 2b

or 3 * b + 2* b = 5b

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

The volume of this cone is 83.7 cubic meters. Find the DIAMETER. SHOW ALL WORK

Answers

There for the diameter is 2(4.8 )= 9.6 ft

Given: Volume of the cone is 83.7 m³

We know that:

[tex]\bigstar \ \ \boxed{\sf{\textsf{Volume of cone is given by} : \dfrac{\pi r^2h}{3}}}[/tex]

where r is the radius of the cone and h is the height of the cone

Given: Height of the cone = 5m

Substituting the values in the formula, we get:

[tex]\sf{\implies \dfrac{\pi r^2(5)}{3} = 83.7}[/tex]

[tex]\sf{\implies \pi r^2 = 83.7 \times \dfrac{3}{5}}[/tex]

[tex]\sf{\implies \pi r^2 = 83.7 \times 0.6}[/tex]

[tex]\sf{\implies \pi r^2 = 50.22}[/tex]

[tex]\sf{\implies r^2 = \dfrac{50.22}{\pi}}[/tex]

[tex]\sf{\implies r^2 = 16}[/tex]

[tex]\sf{\implies r = 4}[/tex]

We know that : Diameter is two times the radius

⇒  Diameter of the Cone is 8 meters

A petrol can is a rectangular prism with base measurements 15 cm by 30 cm. If the can has capacity 18 liters, find its height

Answers

Answer:

40cm

Step-by-step explanation:

Given data

Length= 15cm

Width=30cm

Volume= 18liters

1000cm^3= 18liters

18000cm^3= 18liters

We know that volume

Volume= L*W*h

18000= 15*30*h

18000=450h

h= 18000/450

h= 40cm

Hence the height is 40cm

A floor tile is made in the slope of a rectangular polygon the sum of all the interior angles is 1080° if each side is 10cm find perimeter

Answers

Given:

Sum of all the interior angles of a regular polygon is 1080°.

Measure of each side is 10 cm.

To find:

The perimeter.

Solution:

The sum of all interior angles of a regular polygon with n side is:

[tex]S=(n-2)180^\circ[/tex]

Sum of all the interior angles of a regular polygon is 1080°.

[tex]1080^\circ=(n-2)180^\circ[/tex]

[tex]\dfrac{1080^\circ}{180^\circ}=n-2[/tex]

[tex]6+2=n[/tex]

[tex]8=n[/tex]

Number of sides of the regular polygon is 8. The measure of each side is 10 cm. So, the perimeter of the regular polygon is:

[tex]\text{Perimeter}=\text{Number of sides}\times\text{Measure of each side}[/tex]

[tex]\text{Perimeter}=8\times 10[/tex]

[tex]\text{Perimeter}=80[/tex]

Therefore, the perimeter of the regular polygon is 80.

A 2.5m long ladder leans against the wall of a building. The base of the ladder is 1.5m away from the wall. What is the height of
the wall​

Answers

Answer:

2 m

Step-by-step explanation:

The model of the situation is a right triangle with legs 1.5 and h the height of the wall. The hypotenuse is the ladder.

Using Pythagoras' identity

h² + 1.5² = 2,5²

h² + 2.25 = 6.25 ( subtract 2.25 from both sides )

h² = 4 ( take the square root of both sides )

h = [tex]\sqrt{4}[/tex] = 2

The height of the wall is 2 m

The height of the wall od the building is, 2 m.

What is Pythagoras's theorem?

In a right-angled triangle, the sum of the squares of the smaller two sides of a right-angle triangle is equal to the square of the largest side.

Given, A 2.5m long ladder leans against the wall of a building. The base of the ladder is 1.5m away from the wall.

So, Hypotenuse is 2.5 m and Adjacent is 1.5 m.

We know, H² = O² + A².

O² = H² - A².

O² = 6.25 - 2.25.

O² = 4.

O = 2.

Another concept regarding triangles is,

Suppose we have a triangle ABC, with sides a, b and c.

An acute angle triangle is one where a² + b² > c².

It is a right-angle triangle if a² + b² = c2.

It is an obtuse angle triangle if a² + b² < c².

learn more about Pythagoras' theorem here :

https://brainly.com/question/343682

#SPJ6

which of the following constructions must you know how to do in order to construct an inscribed circle for a given triangle

Answers

Answer:

Bisector

Step-by-step explanation:

URGENT: Click on the graph to choose the correct answer to the equation.

x > 2

Answers

Answer:

The 4th graph.

Step-by-step explanation:

Its a horizontal line which indicates that x is known and the line begins over 2.

The correct Graph of x >2 has been given which is the 4th option.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

We have given an equation as x> 2

Clearly, we can see the graph of x> 2 must be an area beyond 2 on the positive X -axis

The points (and only those points) which lie on the graph of the function should satisfy its equation.

Thus, if a point lies on the graph of a function, then it must also satisfy the given equation.

It is a horizontal line that indicates that the x value is known and the line begins over 2.

Hence, The correct Graph of x >2 has been given which is the 4th option.

Learn more about equations here;

https://brainly.com/question/25180086

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identify the slope. giving brainlist if y’all answer more my social is ms.korraa

Answers

Answer:

-2

Step-by-step explanation:

(1 , 3) = (x1 , y1)

(-2 , 9) = (x2 , y2)

slope = y2 - y2/x2 - x1

=9 - 3/-2 -1

=6/-3

=-2

Which is the simplified form?

Answers

Option 2——when we have a number with negative power it turns into fractions with numerator 1 and denominator nr./letter with the same power

Help ASAP ! Find PN triangle proportionality

Answers

This has to do with ratio's.

MQ : QN = 2 : 5
MQ : QN = LP : PN
2 : 5 = 3 : PN

That means PN = 15/2

Pleaseeeee help me!!!

Answers

Answer:

a = -1  b=0  and c=1

Step-by-step explanation:

-x^2 +0x+1

This is in the form

ax^2 +bx+c

a = -1  b=0  and c=1

Find the lcm of ÷ 16a^4+4a^2+169,8a^3+2a(2a+13)+16a^2

Answers

Answer:

Step-by-step explanation:

Hope this helps u !!

The LCM of 2a(4a² + 10a + 13)(4a² + 13 - 10a).

What is Least Common Multiple?

Least Common Multiple, often known as the Lowest Common Multiple, is denoted by the acronym LCM. The lowest number that may be divided by both numbers is known as the least common multiple (LCM) of two numbers. It can also be computed using two or more numbers.

The smallest number among all the common multiples of the provided numbers is the least common multiple of two or more numbers.

We have,

16[tex]a^4[/tex] + 4a² + 169 and 8a³ +2a(2a + 13) + 16a²

First, 16[tex]a^4[/tex] + 4a² + 169

= (4a²)² + (2a)² + (13)²

= (4a²)² + 2 . 4a² . 13 + (13)² + 4a² + 104a²

= (4a² + 13)² - (10a)²

= (4a + 13 - 10a) (4a + 13 + 10a)

= (13 - 6a)(13 + 14a)

Second, 8a³ +2a(2a + 13) + 16a²

= 8a³ + 4a² + 26a + 16a²

= 8a³ + 20a² + 26a

= 2a(4a² + 10a + 13)

So, the LCM is

= 2a(4a² + 10a + 13)(4a² + 13 - 10a)

Learn more about LCM here:

https://brainly.com/question/20739723

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Multiply (x-3)(4x+2) using the distributive property.select the answer choice showing the correct distribution.

Answers

Answer:

4x² - 10x - 6

Step-by-step explanation:

(x-3)(4x+2)

4x² + 2x - 12x - 6

4x² - 10x - 6

Evaluate 15/r - 1 when r =5

Answers

Answer:

3.75

Step-by-step explanation:

calculator because yes:)

(math)not too hard - pls help

Answers

Answer:

x   -   h(x)

0   -   1

1    -   3

2   -   5

3   -   7

Step-by-step explanation:

Just substitute the x value into the function

Find the measure of AB⎯⎯⎯⎯⎯⎯⎯.

A. 4
B. 7
C. 10
D. 5

Answers

Answer: 7

Step-by-step explanation:

find x

6x(6+4)=5x(1+x)

Then x=11

AB= 11-4=7

Answer:

B.) 7

Step-by-step explanation:

I got it correct on founders edtell

Please help thanks! Brainliest

Answers

Answer:

-3

Step-by-step explanation:

[tex]\frac{7-25}{-2(-3)}[/tex]

=[tex]\frac{-18}{-2*-3}[/tex]

=[tex]\frac{-18}{6}[/tex]

=-3

Problem:

[tex]\quad\quad\quad\quad\huge\tt{⟹\frac{7 - 25}{ - 2( - 3)} }[/tex]

Let's try!

[tex]\quad\quad\quad\quad\huge\tt{ ⟹\frac{7 - 25}{ - 2( - 3)} }[/tex]

[tex]\quad\quad\quad\quad\huge\tt{ ⟹\frac{-18}{ - 2( - 3)} }[/tex]

[tex]\quad\quad\quad\quad\huge\tt{ ⟹\frac{-18}{ 6} }[/tex]

[tex]\quad\quad\quad\quad\huge\tt{ ⟹ - 3} [/tex]

Hence, The answer is:

[tex]\quad\quad\quad\quad\huge \boxed{\tt{ \color{green} - 3} }[/tex]

________

#LetsStudy

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