Answer:
0.8 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\[/tex]
From the question
mass = 8 g
volume = 10 cm³
We have
[tex]density = \frac{8}{10} = \frac{4}{5} = 0.8 \\ [/tex]
We have the final answer as
0.8 g/cm³Hope this helps you
how much is a city of a body when it covers 600m in 5 min?
it is an answer : 2 m/s
i don't know sloution
Answer:
2m/s
Explanation:
5min × 60sec
=300
now,
600÷300
=2
What combination for distance and mass gives you the STRONGEST or LARGEST force?
Answer:Anything that has mass also has gravity. Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is.
Explanation:
Describe how energy is transferred from 1 form to another
Answer:
Thermal energy may be transferred in three ways: conduction, convection, and radiation. Conduction occurs when heat energy is exchanged between nearby molecules that are in touch with one another.
Hope this helps!
Please give brainliest
Have a nice day :D
A golf ball resting on a tee is hit, and its velocity changes from 0m/s to 50 m/s traveling down the fairway in 5 seconds. What was the golf ball's acceleration?
Answer:
Explanation:
55m/s
is the right answer c?
Answer:
Yea I believe so
Explanation:
Imagine everyone in the United States exhibited the character traits we have been discussing. In what ways would America be different?
Now imagine no one in American exhibited any of those character traits. In what ways would America be different?
Answer:
Characterization is the process by which the writer reveals the personality of a character. Characterization is revealed through direct characterization and indirect characterization. Direct Characterization tells the audience what the personality of the character is.
Explanation:
Mood, or atmosphere, is the feeling created in the reader by a literary work or passage. ... Often, a writer creates a mood at the beginning of a work and then sustains the mood throughout. Sometimes, however, the mood of the work changes dramatically.
Mixtures can be either heterogeneous or homogeneous. Which of the following is
characeristic of a homogeneous mixture?
A mixture in which two or more substances are still distinguished (can tell there is more than one
substance).
A mixture in which large particles are suspended.
A mixture in which large particles are not suspended and eventually settle.
A mixture in which two or more substances are evenly distributed (spread out).
Answer:
Option D
Explanation:
There are two types of mixtures
HomogeneousHeterogeneousThe mixture in which one type of substances are present is called homogeneous mixture.
The mixture on which different types of substances are present is called heterogeneous mixture.
Làm như thế nào v cái bài có hình đính kèm
Answer:
I don't understand that language. This brainly is english.
Explanation:
please help me answer this
Answer:
Earth's atmosphere is made up of a combination of gases. The major components of nitrogen, oxygen, and argon remain constant over time and space, while trace components like CO 2 and water vapor vary considerably over both space and time.
Explanation:
it is C
Answer:
c
Explanation: O n O
Is that statement true or false?
One adaptation of bioluminescent fish is that they may have lures that can produce light to help them hide from predators
A. true
B. false
Please Help!!!
A ship travels 3.20 hours with a velocity of 21.1 mph at theta= 123º, including the effects of the
current. The pilot then turns to a heading of 190.0° with a speed of 18.2 mph, including the effects of
the current. If the pilot stays on this heading for 1.10 hours, what is the ship's final displacement from
its original starting point?
The vector addition and kinematics of uniform motion allows to find the result for where the starting point is:
The ship left a point at a distance of 77,565 miles in a direction of 136.7º from the x-axis.
Given parameters
First speed v₁ = 21.3 pH Angle θ₁ = 123º Time t₁ = 3.20 h Second speed v₂ = 18.2 mph Angle θ₂ = 190.0º Time t₂ = 1.10 hTo find
Distance start point.
Velocity is a vector magnitude, therefore it has direction and module, to make the addition of these magnitudes vector algebra must be used.
There are two methods for adding vectors:
Graphic. In this case, a vector is placed at the tip of the other and the resulting vector goes from the origin of the first to the tip of the last. Analytical. In this case, the vector is decomposed into a coordinate system, the resultants are found and the vector is composed.
In the attached we can see a diagram of the displacement of this ship. We use a Cartesian reference system and using trigonometric to decompose the velocities.
First speed
cos 123 = [tex]\frac{v_1_x}{v_1}[/tex]
sin 123 = [tex]\frac{v_1_y}{v_1}[/tex]
v₁ₓ = v₁ cos 123
[tex]v_{1y}[/tex] = v₁ sin 123
v₁ₓ = 21.1 cos 123 = -11.49 mph
[tex]v_{1y}[/tex] = 21.1 sin123 = 17.70 mph
Second speed
v₂ₓ = v₂ cos 190
[tex]v_{ 2y}[/tex] = v₂ sin190
v₂ₓ = 18.2 cos 190 = -17.92 mph
[tex]v_{2y}[/tex] = 18.2 sin190 = -3.16 mph
Now we can use kinematics of uniform motion.
v = [tex]\frac{d}{t}[/tex]
d = v t
Where v is the velocity, d the distance and t the time
Let's find every distance traveled.
For first speed
x-axis
x₁ = v₁ₓ t₁
x₁ = -11.49 3.20
x₁ = - 36,768 miles
y-axis
y₁ = [tex]v_{1y} \ t_1[/tex]
y₁ = 17.70 3.20
y₁ = 56.64 miles
Travel for 2nd speed
x₂ = v₂ₓ t₂
x₂ = -17.92 1.10
x₂ = -19,712 miles
y₂ = -3.16 1.10
y₂ = - 3,476 miles
Let's find the distance traveled on each axis
x-axis
[tex]x_{total}[/tex] = x₁ + x₂
[tex]x_{total}[/tex] = -36,768 - 19,712
[tex]x_{total}[/tex] = -56.48 miles
y-axis
[tex]y_{total}[/tex] = y₁ + y₂
[tex]y_{total}[/tex] = 56.64 - 3.476
[tex]y_{total}[/tex] = 53,164 miles
Let's construct the total displacement vector, for the module let's use the Pythagorean theorem
[tex]d_{total} = \sqrt{x^2 +y^2} \\d_{total} = \sqrt{56.48^2 +53.164^2}[/tex]
[tex]d_{total}[/tex] = 77,565 miles
Let's used trigonometry for the direction
[tex]tan \theta ' = \frac{y_{total} }{ x_{total} } \\\theta ' = tan^{-1} \frac{y_{total} }{ x_{total} }[/tex]
θ’= 43.3º
This angle is in the second quadrant to indicate the angle with respect to the positive side of the x-axis in a counterclockwise direction.
θ = 180 - θ'
θ = 180 - 43.3
θ = 136.7º
In conclusion using the addition vectors and kinematics of uniform motion we can find the result for where the starting point is:
The ship left a point at a distance of 77,565 miles in a direction of 136.7º from the x-axis.
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Can someone please give me the answers to this? ... please ...
Answer:
tell me if im wrong
Explanation:
ok and thaks sa points
Friction can be reduced by using ___________.
Answer:
Make the surfaces little more smoother. ...
Lubrication is another way to make a surface smoother. ...
Make the object more streamlined. ...
Reduce the Normal force acting between the surfaces in contact. ...
Reduce the contact between the surfaces, so that less number of bonds will be formed.
Hey guys <3
I need some help with this performance task,, physics isn’t my strongest subject so help is much appreciated :)
(3/9 parts)
Answer:
3. B. Decreases
4. A. Increases
5. A. Repel
4. As Juan is going to take a shower, the soap falls out of the soap dish on to the
floor and Juan steps on it with a force of 493 N. If Juan slides forward and the
frictional force between the soap and the shower floor is 40 N, what is the
coefficient of friction between the soap and the floor? *
Your answer
The coefficient of friction between the soap and the floor is 0.081
If Juan steps on the soap with a force of 493 N, this is her weight, W. This weight also equals the normal reaction on the floor, N.
We know that frictional force F = μN where μ = coefficient of friction between soap and floor.
So, μ = F/N
Since F = 40 N and N = W = 493 N,
μ = F/N
μ = 40 N/493 N
μ = 0.081
So, the coefficient of friction between the soap and the floor is 0.081
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Two rocks are at the top of a building. Rock 1 is dropped from rest while Rock 2 is thrown horizontally at a velocity of 5 m/s.What is the horizontal acceleration of Rock 2
The horizontal acceleration of the rock 2 is zero.
The given parameters;
initial velocity of Rock 1 = 0
initial horizontal velocity of Rock 2 = 5 m/s
An object falling under the influence of gravity experiences acceleration due to gravity which is always directed vertically downwards.
An object moving horizontally is not affected by gravity and thus will experience no acceleration in the horizontal direction.
Thus, we can conclude that the horizontal acceleration of the rock 2 is zero.
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A ball accelerates uniformly at +4.0 m/s2
If the ball was initially moving a +0.20 m/s and the average velocity was +4.2 m/s, then how long will it take it to reach the final velocity?
It will take 1 second to reach the final velocity
Acceleration of a body is the change in velocity of the body with respect to time. This is mathematically represented as;
[tex]a=\frac{v-u}{t}[/tex]
Given the following parameters
a = +4.0 m/s²
u = +0.20m/s
v = +4.2m/s
Substitute the given parameters into the formula to get the time "t"
[tex]4=\frac{4.2-0.2}{t}\\4t=4.2-0.2\\4t=4.0\\t=\frac{4}{4}\\t=1sec[/tex]
This shows that it will take 1 second to reach the final velocity
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the speed of light is the ______ of its frequency and wavelength. in a vacuum, this value is a constant, ______.
Answer:
multiplication; 2.99 x 10^8
Explanation:
V = (ε x u)^-1/2 = 1/(8.85 x 10^-15 x 4π x 10^7)^1/2 = 2.99 x 10^8
Q3- It takes you 35 min to walk to the shop. If the distances are A = 0.5 km, 8 - 1.4 km, and C = 0.8 km what was your average speed in km/h?
O 0.025 km/h
0.090 km/h
O 1.5 km/h
4.8 km/h
Q2- supposed you walk from your house to school then from school to the store, then from the store to your friend's house. If the distance is A=375, B=750, and C = 435 what was the magnitude of your displacement?
1125m
375m
1560m
2745m
Q1- Suppose you walk from your house to school then from school to the store and then from the store to your friend's house. If the distance is A=375, B=750 and C= 435, what distance did you travel?
1560
2745
1125
375
Answer: 1. .090km/h
2. I dont know
3. 1560
Explanation:
1. add all the numbers up and divide by 3 bc thats how many numbers there are.
2. I dont know
3. add all distances up
Which one is the right answer?
Newton’s second law of motion relates an objects acceleration to _____.
A. It’s mass
B. It’s velocity
C. The net force acting on it.
D. Two of the above
Answer:
C. The net force acting on it.
why do the lights in your home come on almost instantaneously when you turn on the switch?
Answer:
here you go
Explanation:
Why do your lights actually come on almost instantaneously? ... Wiring the house in parallel does not make a difference – there is no current flowing through the light bulb when the switch is off no matter how the house is wired. If there were a current already, the light would be on!
an object is accelerating if there is a change in speed and which factor?
Answer:
Speed and direction.
Explanation:
When an object accelerates, its velocity changes. Velocity is often thought of as an object's speed with a direction. Thus, objects accelerating are either speeding up, slowing down or changing directions.
When a person speaks, a sound intensity is generated that is 600 times greater than when the person whispers. What is the difference in decibels between the sound level when the person speaks compared to when she whispers
Answer:
Originally : Level = log I / I0
Currently: Level = 10 log I / I0
Level = 10 log 600 = 10 * 2.78 = 27.8
Note the term 1 bel = 10 decibels
Within a period of the periodic table, how do the properties of the elements vary?
Answer:
Elements in the same period have the same number of electron shells; moving across a period (so progressing from group to group), elements gain electrons and protons and become less metallic. This arrangement reflects the periodic recurrence of similar properties as the atomic number increases.
Explanation:
The Periodic Table can predict the properties of new elements, because it organizes the elements according to their atomic numbers. ... They hope that the two nuclei at the centre of these atoms will fuse and form a heavier nucleus. When these heavy elements form, they are usually highly unstable.
I NEED THIS ANSWERED ASAP NO LINKS !!!
I need a answer that is 100% ACCURATE
Answer:
increase
Explanation:
I did the question
What direction would the net force acting on this box be pointed?
northeast
northwest
southeast
southwest
Answer:
The diagram shows a net 2 N in the north direction and 2 N in the east direction - this would result in (4 + 4)^1/2 to the northeast.
A car moving along a straight highway with speed of 126 km 1 h− to brought to stop within a distance of 200 m. how long does it take for the car to stop?
Answer: 11.43 sec
solution:
v2 – u2 = 2as
a = (v2 – u2)/2s
= (0 – 352)/(2 × 200)
= –1225/400
= –3.06 m/s2
v = u + at
0 = 35 – 3.06 × t
t = 35/3.06
= 11.43 sec
The photo shows a sea urchin embryo. A sea urchin is a multicellular organism. جام Which two processes occur as the sea urchin embryo grows? A. The embryo's cells grow larger in size. B. The amount of DNA in the embryo's body cells decreases. C. The total number of cells in the embryo's body decreases. D. The embryo's cells take in water and nutrients. SUBMIT
Answer:
d and a
Explanation:
The embryo's cells grow larger in size, and the embryo's cells take in water and nutrients. The correct options are A and D.
The two processes that occur when the sea urchin embryo matures, according to the information presented, are:
The embryo's cells grow in size: During the embryo's growth and development, individual cells divide and grow in size, contributing to the organism's total growth.
The embryo's cells actively take in water and nutrients from the surrounding environment: As the embryo grows, its cells actively take in water and nutrients from the surrounding environment to support metabolic processes and offer the essential resources for growth and development.
Thus, choices A and D represent the proper processes that occur while the sea urchin embryo develops.
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a constant current flows in the conductor with a magnitude of 1.6 mA. Calculate the charge and number of electrons transferred through the straight cross-section of the conductor in 1 hour.
[tex]\\ \sf\longmapsto I=\dfrac{Q}{t}[/tex]
[tex]\\ \sf\longmapsto Q=It[/tex]
[tex]\\ \sf\longmapsto Q=0.0016(3600)[/tex]
[tex]\\ \sf\longmapsto Q=5.76C[/tex]
When does it have kinetic energy