Answer:
D<28
Step-by-step explanation:
The required inequality for the given situation can be, d > 28 or d < 28
What is an inequality?A relationship between two expressions or values that are not equal to each other is called inequality.
Given that, write an inequality for the situation.
Situation :-
A number of days, d, of sunshine is not 28.
Here, the number of days is said to be not equal to 28, we are not given if is less or more,
It can be less or more than 28 but not 28
So, here we get two situations,
Either, the number of days, d, of sunshine is less than 28, or the number of days, d, of sunshine is more than 28.
If we write these situations, mathematically, the inequalities we will have, are :-
1) The number of days, d, of sunshine is less than 28 :-
d < 28
2) The number of days, d, of sunshine is more than 28 :-
d > 28
Therefore, the two inequalities, are :- d < 28 or d > 28
Hence, the required inequality for the given situation can be, d > 28 or d < 28
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The complete question is :-
Write an inequality for the situation.
A number of days, d, of sunshine is not 28 .
Roads connecting the towns of Oceanside, River City, and Lake View form a triangle. The distance from Oceanside to River City is 38 kilometers. The distance from River City to Lake View is 26 kilometers. What is the smallest possible whole number of kilometers between Lake View and Oceanside?
Answer:
13 km
Step-by-step explanation:
By Triangle Inequality Theorem: The sum of two smallest sides is greater than the third side.
Small Values of X:
X + 26 > 38
X > 38 - 26
X > 12
If we know that 38 km is the longest side, then the sum of other two sides must be greater than 38 km. Therefore the minimum value of X is 13 km.
help║...................
A regular heptagon is shown below. What is the value of x?
Answer:
108+x=180
X=180-108
X=72
The value of the exterior angle (x) in a regular heptagon is approximately 51.43 degrees.
Given is a regular heptagon with one of the exterior angle be x we need to find the value of x
To find the value of the exterior angle of a regular heptagon, we can use the formula:
Exterior Angle = 360 degrees / Number of Sides
In this case, the heptagon has seven sides, so we can substitute the values into the formula:
Exterior Angle = 360 degrees / 7
Exterior Angle ≈ 51.43 degrees
Therefore, the value of the exterior angle (x) in a regular heptagon is approximately 51.43 degrees.
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if the third term is 20 and 7th is 1.25, find the 11th term
Answer:
the 11th term is 0.0000488 or 4.88*10^-5.
Step-by-step explanation:
a3 = 20, a7 = 1.25
a7 = a3r^7-3
1.25 = 20r^4
r^4 = 0.0625
r = 4th root of 0.0625
r = 0.5
a3 = a1r^3-1
20 = a1(20)^2
400a1 = 20
a1 = 0.05
a11 = 0.05(0.5)^11-1 = 0.0000488 or 4.88*10^-5
I need help on this question and answering it
Answer:
75 feet
Step-by-step explanation:
the shadow to the object would be a 4:5 ratio
since the shadow of the flagpole is 60 ft,
4x=60 so x would =15
then you multiply 15 by 5 and end up with 75
Answer: 75 feet
Step-by-step explanation: trust me
Explain what you think that term dilation means.
Answer:
the action or condition of becoming or being made wider, larger, or more open.
Step-by-step explanation:
Find the distance between (5, -1) and (1,-5).
4 units I assume. that it is a very basic answer tho and I am not sure if a specific formula or lesson was supposed to be applied to that andwer
help ASAP! Ill mark brainliest!
Answer:
55 students
Step-by-step explanation:
Just write down the answer.
Answer:
Step-by-step explanation:
Football: 500(.38)= 190
Basketball: 500(.25)= 125
55 students (65 students)
Let V be the set of all ordered triples of real numbers with addition and scalar multiplication defined as follows: (x, y, z) + (x'. y' z') = (x + x'.0,2 + z!) and k(x,y,z) (kx,ky, kz) for all real numbers k. Prove that V is not a vector space.
The set V, defined as the set of all ordered triples of real numbers with the given addition and scalar multiplication operations, is not a vector space. Therefore, we can conclude that V is not a vector space, as it does not fulfill the required vector space axioms.
To prove that V is not a vector space, we need to demonstrate that it fails to satisfy at least one of the vector space axioms.
Let's consider the closure under scalar multiplication axiom. According to the given scalar multiplication operation, k(x, y, z) = (kx, ky, kz) for all real numbers k. However, in a vector space, scalar multiplication should be distributive over both addition of vectors and scalar addition.
Let's choose a specific example to illustrate the issue. Consider the vector (x, y, z) = (1, 1, 1) in V and the scalar k = 2. According to the defined scalar multiplication operation, 2(x, y, z) = 2(1, 1, 1) = (2, 2, 2).
Now, let's compute (1 + 1)(x, y, z) = 2(x, y, z) = 2(1, 1, 1) = (2, 2, 2).
However, in a vector space, the distributive property should hold, meaning that (1 + 1)(x, y, z) should equal (1, 1, 1) + (1, 1, 1) = (2, 2, 2).
Since (1 + 1)(x, y, z) ≠ (1, 1, 1) + (1, 1, 1), V fails to satisfy the closure under scalar multiplication axiom.
Therefore, we can conclude that V is not a vector space, as it does not fulfill the required vector space axioms.
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Find the area of the figure.
Answer:
353.93 ft²
Step-by-step explanation:
Step 1:
Find the area of the Trapezoid.
(a + b) ÷ 2 × height
20 + 17 = 37
37 ÷ 2 = 18.5
18.5 × 13 = 240.5 ft²
Step 2:
Find the Area of the Semicircle:
1/2 × πr²
1/2 × 3.14 = 1.57
1.57 × 8.5² = 113.43 ft²
Step 3:
Add the two areas together:
240.5 + 113.43 = 353.93 ft²
Which of the following is the correct alternative hypothesis constructed in the binomial test? A. H, :P Previous question
The correct alternative hypothesis constructed in a binomial test is (a) H₁ :P < Q
How to determine the correct alternative hypothesis constructed in a binomial test?From the question, we have the following parameters that can be used in our computation:
A. H₁ :P < Q
B. H₁: P - Q
C. H₁ : P = Q
D. H₁ : P ≤ Q
As a general rule of test of hypothesis, alternate hypothesis are represented using inequalities
This means that we make use of <, > or ≠
Hence, the correct alternative hypothesis is (a) H₁ :P < Q
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Question
Which of the following is the correct alternative hypothesis constructed in the binomial test?
A. H₁ :P < Q
B. H₁: P - Q
C. H₁ : P = Q
D. H₁ : P ≤ Q
Which of these describe a unique polygon
Answer: d
Step-by-step explanation:
What is the volume of a cone with a radius 3 cm and a height 6 cm?
Answer:
56.55
Step-by-step explanation:
Complete the table below for the equation y=1+2x
Find the sum of the interior angle measures of the polygon.
Answer:
360
Step-by-step explanation:
All the angles of a polygon add up to 360, thats kinda just how it is haha
Find the missing length.
= ✓ [?]
C =
с
6
Pythagorean Theorem: a2 + b2 = c2
Enter
Answer:
Pythagoras theorem= 6 squared +11 squared
= 36 + 121
= 157
Step-by-step explanation:
9y8tyfstoylhlh
Which solution for z makes the equation true?? 10+10+z=40=10 (pls explain why. Thanks)
Answer:
z=30
Step-by-step explanation:
40-10=30
10+10+?=30
30-10-10=10
I'm sorry cuz I don't know how to explain it
Answer:
z = 10
Step-by-step explanation:
10 + 10 + z = 40 - 10
10 + 10 + z = 30
10 + 10 + 10 = 30
since 40 - 10 = 30, then Z has to equal 10 because 10 + 10 + z needs to be 30
A company has dump trucks that repeatedly go through three activities: loading, weighing, and travelling. Assume that there are eight trucks and that, at time 0, all eight are at the loaders. Weighing time per truck on the single scale is uniformly distributed between 1 and 9 minutes, and travel time per truck is exponentially distributed with mean 85 minutes. An unlimited queue is allowed before the loader(s) and before the scale. All truck can be travelling at the same time. Management desires to compare one fast loader against the two slower loaders currently being used. Each of the slow loaders can fill a truck in from 1 to 27 minutes, uniformly distributed. The new fast loader can fill a truck in from 1 to 19 minutes, uniformly distributed. The basis for comparison is mean system response time over a 40 hour time horizon, where a response time is defined as the duration of time from a truck arrival at the loader queue to that truck's departure from the scale. Perform statistically valid comparison of the two options simulated using common random numbers. a
To perform a statistically valid comparison of the two loader options, we can use simulation and common random numbers. We simulate the process over a 40-hour time horizon and compare the mean system response times for each loader option.
For the two slower loaders, we generate random numbers uniformly distributed between 1 and 27 minutes to represent the time taken to fill a truck. For the fast loader, we generate random numbers uniformly distributed between 1 and 19 minutes.
By simulating the process multiple times using the same set of random numbers (common random numbers), we can compare the mean system response times between the two loader options.
After running the simulation, we calculate the mean system response time for each loader option by averaging the response times of all trucks. We repeat the simulation multiple times (e.g., 100 or more) to obtain reliable estimates of the mean system response times.
Once we have the mean system response times for each loader option from multiple simulation runs, we can perform a statistical analysis to determine if there is a significant difference between the two options.
This analysis can be done using a suitable statistical test, such as a t-test or confidence interval analysis, depending on the distribution of the response time data and the assumptions made.
The statistical analysis will provide insights into whether the fast loader option significantly reduces the mean system response time compared to the slower loader options. A lower mean system response time would indicate better performance in terms of faster truck processing.
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Are the ratios 18:6 and 3:1 equivalent?
Answer: no
Step-by-step explanation: here are all the ratios equivalent to 18:6 18 : 636 : 1254 : 1872 : 2490 : 30108 : 36126 : 42144 : 48162 : 54180 : 60198 : 66216 : 72234 : 78252 : 84270 : 90288 : 96306 : 102324 : 108342 : 114360 : 120378 : 126396 : 132414 : 138432 : 144450 : 150468 : 156486 : 162504 : 168522 : 174540 : 180558 : 186576 : 192594 : 198612 : 204630 : 210648 : 216666 : 222684 : 228702 : 234720 : 240738 : 246756 : 252774 : 258792 : 264810 : 270828 : 276846 : 282864 : 288882 : 294900 : 300918 : 306936 : 312954 : 318972 : 324990 : 3301008 : 3361026 : 3421044 : 3481062 : 3541080 : 3601098 : 3661116 : 3721134 : 3781152 : 3841170 : 3901188 : 3961206 : 4021224 : 4081242 : 4141260 : 4201278 : 4261296 : 4321314 : 4381332 : 4441350 : 4501368 : 4561386 : 4621404 : 4681422 : 4741440 : 4801458 : 4861476 : 4921494 : 4981512 : 5041530 : 5101548 : 5161566 : 5221584 : 5281602 : 5341620 : 5401638 : 5461656 : 5521674 : 5581692 : 5641710 : 5701728 : 5761746 : 5821764 : 5881782 : 5941800 : 600
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Answer:
yes
Step-by-step explanation:
18:6
18/6=3
6/6=1
3:1 is a simpler version of 18:6
20 POINTS‼️‼️Which of the following does NOT represent the number of months in a year?
A and b are in the attached photo.
C. y= 12x, where x represents the number of years and y represents the number of months
D. There are 96 months in 8 years.
‼️PLEASE DO YOUR BEST TO SHOW WORK FOR BRAINLIEST‼️
Answer:
B because when you multiply the first number by twelve the first two are correct but the second ones are not
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
12 times 6 = 72, not 60
3 questions
4 is about what percent of 9?
About what percent of 7560 is 3000?
1.3 is about what percent of 27?
Please help me my teacher does not explain how to do this well..
Test whether there is a difference in the pattern of freshman class ranks (an ordinal scale variable) of the newly-inducted sophomore members across five sororities at Mega University.
The required answer is by conducting the Kruskal-Wallis test, we can determine if there are statistically significant differences in the pattern of freshman class ranks among the sophomore members across the five sororities at Mega University.
To test whether there is a difference in the pattern of freshman class ranks among the sophomore members across five sororities at Mega University, we can use a statistical test called the Kruskal-Wallis test. The Kruskal-Wallis test is a non-parametric test used to compare the distributions of three or more independent groups.
In this case, the five sororities represent the independent groups, and the freshman class ranks of the sophomore members within each sorority are the ordinal scale variable of interest. The Kruskal-Wallis test will assess whether there are statistically significant differences in the distribution of freshman class ranks across the five sororities.
Here is a step-by-step explanation of how to conduct the Kruskal-Wallis test:
Step 1: Formulate the null and alternative hypotheses.
Null hypothesis (H₀): There is no difference in the pattern of freshman class ranks across the five sororities.
Alternative hypothesis (H₁): There is a difference in the pattern of freshman class ranks across the five sororities.
Step 2: Collect the data.
Gather the freshman class ranks of the sophomore members for each sorority. Ensure that the data is properly coded and organized.
Step 3: Perform the Kruskal-Wallis test.
Apply the Kruskal-Wallis test to the data. The test will compare the distributions of the ordinal data across the five sororities and determine if there are significant differences.
Step 4: Interpret the results.
Analyze the output of the Kruskal-Wallis test, which typically provides a test statistic and a p-value. If the p-value is below a predetermined significance level (e.g., 0.05), we reject the null hypothesis and conclude that there is evidence of a difference in the pattern of freshman class ranks across the five sororities.
Step 5: Post-hoc analysis (if necessary).
If the Kruskal-Wallis test indicates significant differences, further analyses, such as pairwise comparisons or Dunn's test, can be conducted to identify which specific sororities differ from each other.
By conducting the Kruskal-Wallis test, we can determine if there are statistically significant differences in the pattern of freshman class ranks among the sophomore members across the five sororities at Mega University.
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Please Help, GodBless
Answer:
-3/2
Step-by-step explanation:
The rate of change is the same as slope
Find the distance between the points (–10,3) and (–2,3).
Answer:
8
Step-by-step explanation:
10 - 2
need help plz im struggling
Answer:
12057.6
Step-by-step explanation:
V = πr²h
3.14 x 16² x 15
3.14 x 16² = 803.843.14 x 803.84 = 12057.6
2. (1 point each) Let f(x) = √x and g(x) = 1/x. In the space
provided, compute each of the following, if possible:
(a) f(36)
(b) (g+f)(4)
(c) (f · g)(0)
(a) f(36) is equal to 6.
(b) (g+f)(4) = g(4) + f(4) = 9/4
(c) we cannot compute (f · g)(0).
(a) To find f(36), we substitute x = 36 into the function f(x) = √x:
f(36) = √36 = 6
Therefore, f(36) is equal to 6.
(b) To find (g+f)(4), we need to evaluate g(4) and f(4), and then add the results:
g(4) = 1/4
f(4) = √4 = 2
(g+f)(4) = g(4) + f(4) = 1/4 + 2 = 1/4 + 8/4 = 9/4
Therefore, (g+f)(4) is equal to 9/4 or 2.25.
(c) To find (f · g)(0), we need to evaluate f(0) and g(0), and then multiply the results:
f(0) = √0 = 0
g(0) = 1/0
However, g(0) is undefined because division by zero is not defined in mathematics.
Therefore, we cannot compute (f · g)(0) in this case.
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please help with right answers xoxo
On Saturday, a local hamburger shop sold a combined total of 261 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number of hamburgers sold. How many hamburgers were sold on Saturday?
Answer:
134 hamburgers
Step-by-step explanation:
Let H = # of hamburgers
# of cheeseburgers = 2H
H + 2H = 402
3H = 402
H = 402/3
H = 134
PLEASE ANSWERS FAST
how do you find the perimeter of the base?
A. Multiply the side lengths
B. Divide the side lengths
C. Add all sides of the base shape
D. Take the square root after multiplying the side lengths
Answer:
C. Add all sides of the base shape
Step-by-step explanation:
perimeter = sum of length of sides of a polygon
Answer: C. Add all sides of the base shape
Cody did not understand the concepts of the “special cases” when factoring. Explain the concept of the perfect square binomial. Use an example to help explain to her how it is a special case and how to factor it using the special case rules.
A binomial expression of the form (a + b)² or (a - b)² is called a perfect square binomial.
This expression can be factored using the special case rules by rewriting it in the form
(a + b)(a + b) or (a - b)(a - b), respectively.
A perfect square binomial is a quadratic trinomial in which the first term is a perfect square and the second term is twice the product of the square root of the first term and the square root of the last term.
In the context of special cases, the perfect square binomial is a binomial that is formed by squaring a binomial.
This is a special case because it has a unique factorization, as we will see later.
An example of a perfect square binomial is (x + 4)².
This is because the first term, x², is a perfect square, and the second term, 8x, is twice the product of the square root of x² and the square root of 4, which is 2.
Hence, (x + 4)² can be factored using the special case rules as:
(x + 4)(x + 4),
which simplifies to
(x + 4)².
A perfect square binomial is a quadratic trinomial in which the first term is a perfect square and the second term is twice the product of the square root of the first term and the square root of the last term.
It is a special case because it has a unique factorization, which is given by the formula:
(a + b)² = a² + 2ab + b²
or
(a - b)² = a² - 2ab + b².
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