A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 439 439 gram setting. It is believed that the machine is underfilling or overfilling the bags. A 26 26 bag sample had a mean of 443 443 grams with a variance of 225 225 . Assume the population is normally distributed. Is there sufficient evidence at the 0.01 0.01 level that the bags are underfilled or overfilled?

Answers

Answer 1

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447.0 gram setting.

Find the solution ?

So, Null hypothesis :447

It is believed that the machine is under filling the bags

So, Alternate hypothesis :

n = 41

Population standard deviation =

 x = 443

We will use z test since n > 30 and we are given the population standard deviation.

Use z table to find p value

z =  443 - 447/ 21/ √41

z = - 1.2196

p value = 0.1131

α = 0.02

p value > α

So, we fail to reject null hypothesis.

So, its bag filling machine works correctly at the 447.0 gram setting.

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If numbers add up, they reach the predicted total; they make sense. If the numbers don't add up, the overall sum doesn't make sense in light of the individual sums.

How to calculated  numbers add up ?

Only 17 + 19 - 5 = 31 can be used to "add" three of the given numbers to the number 31.

Only these sums can be created from 3 of the numbers if only positive signs are permitted.

{10, 22, 24, 24, 25, 26, 27, 38, 39, 41}

Any of these sums can be earned if either positive or negative signs are permitted.

{1, 3, 4, 5, 6, 7, 9, 10, 11, 12, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 27, 31, 33, 34, 38, 39, 41}.

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Answers

Answer:

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Answers

Answer:

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Suppose that E and F are two events and that P(E)= 0.7 and P(FIE) = 0.3. What is P(E and F)? P(E and F) = (Simplify your answer.)

Answers

The calculated value of P(F|E) is 0.4.

Then the conditional probability that the event  will occur given that  has already occurred is given by the following formula:

P(B|A) = (P(A∩B)) / P(A)

Here the two events given are E and F .

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What in likelihood are E and F?

The capital letters E and F in the discussion that follows stand in for potential experiment results, and P(E) denotes the likelihood that outcome E will be seen. The results of E or F can be listed as the results of E followed by the results of F for events that don't happen simultaneously.

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