A large water tank is completely filled with water. The tank is 3.0 m high and its surface is open. If a small hole is made on one side of the tank at a height of 0.8 m, calculate the speed with which the water comes out of the pipe.

Answers

Answer 1

The speed of the water through the pipe is 4.96 m/s

How to calculate the speed at which the water comes out of the pipe?

Since a large water tank is completely filled with water. The tank is 3.0 m high and its surface is open. If a small hole is made on one side of the tank at a height of 0.8 m, to find the speed with which the water comes out of the pipe, we use Bernoulli's equation

What is Bernoulli's equation?

Bernoulli's equation governs flows through pipes. It is given by

P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂² where

P₁ = pressure at point 1,h₁ = height at point 1,v₁ = speed at point 1,P₂ = pressure at point 2,h₂ = height at point 2, andv₂ = speed at point 2

Given that

P₁ = atmospheric pressure = 1.013 × 10⁵ Pa,h₁ = height of tank = 3 m,v₁ = speed at top ot tank = 0 m/s (since it is stationary there),P₂ = pressure at bottom of tank = 0 Pa,h₂ = height at hole = 0.8 m, andv₂ = speed at hole = speed of water through pipe and ρ = density of water = 1000 kg/m³

So, susbstituting the values of the variables into the equation, we have

P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂²

1.013 × 10⁵ Pa + 1000 kg/m³ × 9.8 m/s² × 3 m + 1/2 × 1000 kg/m³ × (0 m/s)² = 0 + 1000 kg/m³ × 9.8 m/s² × 0.8 m + 1/2 × 1000 kg/m³ × v₂²

1.013 × 10⁵ Pa + 29400kg/ms² + 0 = 0 Pa + 7840kg/ms² + 5000v²

130700 Pa = 7840kg/ms² + (5000 kg/m³)v²

130700 Pa - 7840 Pa = (5000 kg/m³)v²

122860 Pa = (5000 kg/m³)v²

Making v subject of the formula, we have

v = √(122860 Pa/5000 kg/m³)

= √(130.7/5 Pam³/kg)

= √(24.572 Pam³/kg)

= 4.96 m/s

So, the speed of the water through the pipe is 4.96 m/s

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Related Questions

A motorcyclist heading east accelerates after he passes a sign post at x=0m marking the city his acceleration is constant a= 4m/s2 at time=0 he is 5m east of the sign post and has a velocity of v=15 m/s where is the motorcyclist when his velocity is 25m/s

Answers

Answer:

55m east of the sign post

Explanation:

Use this equation

final velocity^2 = initial velocity^2+2(a)(x) x is displacement.

Substitute values:

25^2= 15^2+ 2(4)(x)

625=225+8x

x=50 m

REMEMBER TO ADD INITIAL DISPLACEMENT!!!! :D

Displacement (positive is east in this case)

=50 m+ 5m

=55m.

So the answer is the motorcyclist is 55m east of the sign post.

What is the resulting acceleration when a 120 N force acts on an object with a mass of 360kg?

Answers

Answer:

Below

Explanation:

Remember:

F = m a    

F/m = a    =  120 / 360 =  1/3   m/s^2

need these answered with explanation please, i need this asap.

Answers

1. a. Frequency of the wave is equal to 2 cycles per second.

Wavelength of the wave is equal to 1.5 m.

2.a. The frequency of the wave is 3 cycles per second.

b, It is a longitudinal wave of wavelength is equal to 40 cm.

What is wave?

An energy disturbance in a medium without net particle mobility is referred to as a wave. Among the probable manifestations are elastic deformation, pressure changes, variations in electric or magnetic intensity, electric potential, and temperature changes.

From picture 1.

1. a. frequency  of the wave is = 2 cycles per second.

Wavelength of the wave is = 3 m/2 =1.5 m.

From picture 2.

2.a. As it moves forward and backward 3 times in very second, frequency of it is given by  3 cycles per second.

b, It is a longitudinal wave of wavelength is 40 cm.

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Which quantities (initial horizontal speed, initial vertical speed, range, flight time, or maximum height) are proportional to the square of the initial velocity?

(This is about angled projectiles)
(Include an explanation please)

Answers

Range and Maximum height are proportional to the square of the initial velocity.

In projectile motion, Range of the particle is the horizontal distance travelled by the projectile between launch and the landing points and is denoted as R,

R = u^2sin2θ/g

Here u is initial velocity.

Maximum height is the maximum height from the point of projection, a projectile can reach.

And at maximum height (h) attained, velocity of the object is zero (v=0)

we can use , v^2 - (u sinθ)^2= 2ah     (acceleration due to gravity is a= -g)

Or 0 -  (u sinθ)^2 = 2(-g)h

⇒ h = u^2 sin^2 θ / 2g

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what is solenoid? define solenoid in simple words​

Answers

[tex]{ \red{ \underline{ \green{ \sf{solenoid}}}}}[/tex]

Solenoid is a coil of circular turns made up of insulated copper wire wrapped closely in the cylindrical form

solenoid is formed by circular turns of copper wire in cylinder form

18. A man dived horizontally with a velocity of 1.5 ms from a 100 kg boat. If the recoil velocity of the boat is 0.9 ms what is the mass of the man? ​

Answers

166.6 kg  is the mass of the man

initial momentum=final momentum

m1v1=m2v2

1.5×100=0.9×m2

m2=166.6 kg

Mass is used in physics to express inertia, a fundamental characteristic of all matter. Essentially, it is a mass of matter's resistance to changing its direction or speed in response to the application of a force. The change that an applied force produces is smaller the more mass a body has. The kilogram, the unit of mass in the International System of Units, corresponds to 6.62607015 1034 joule seconds using Planck's constant (SI). One joule is produced by multiplying one kilogram by one square meter per second. The kilogram is determined by exact measurements of Planck's constant since the second and the meter have previously been defined in terms of other physical constants.

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An airplane on a runway accelerates at 4.0 meters/second^2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before
takeoff?

Answers

Answer:1568 meters

Explanation:

we will make a speed time graph and we will calculate the speed by multiplying acceleration with time and we will have the speed then we will draw it on the speed time graph this will make a triangle and we will calculate its area and we will have the distance.

A grandfather clock is operated by a slowly falling mass attached to a pulley system. Winding the clock lifts the mass up again. A typical grandfather clock has a 0.750 kg mass that can fall and be lifted a height of 1.80 m. Calculate the increase in gravitational potential energy of the mass when the clock is wound.​

Answers

13.23 joule is gravitational potential energy of the mass when the clock is wound.​

potential energy, p = mgh

m= 0.750 kg

h= 1.80 m

g=9.8 m/s²

p = mgh

p=0.750×1.80 m×9.8 m/s²

p=13.23 joule

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or extended, its potential energy increases. If a steel ball is lifted above the ground as opposed to falling to the ground, it has higher potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has greater potential energy as they get further apart.

Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.

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In a crash, when a head hits an airbag, what is observed when the head first touches the
airbag and when the head stops? (keywords: speed, time, force)

Answers

When a head collides with an airbag in a collision, the head's initial velocity and its final velocity are measured.

What is the definition of force?

In economics, a power is defined as the pull or draw that modifies an object's velocity. Ingredients that might affect a person's sense of personal work or sleepiness are invisible to the human eye. Its dimensions and form are distinctive.

What does force mean in Example?

In daily life, there are many instances of forces, including: weight and force (i.e. the weight of something) the pressure a bat puts on a ball. the amount of force used to brush hair using a brush. the force used by your foot to press the pedal.

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how would the shape of electric field lines change if you increased the voltage across the electrodes

Answers

Answer:

Explanation:

If the electric field is inhomogeneous, then the magnitude of the strength (and voltage) is determined by the density of the field lines: where the field lines are thicker, the field strength is greater

What do we call the number of waves that pass by a given point in one
second?
OA. The wavelength
OB. The frequency
о C. The amplitude
о D. The period

Answers

B: the frequency of the wave.



I need assistance with these questions asap.

Answers

Answer:

Explanation:

9a)  Velocity North

30 m/s  * Sine(60) = 25.98076..  m/s

9b) Distance North

25.98076 m/s * (3 hour)  but we need hours in seconds b/c that's our velocity units

25.98076 m/s * 10800 s = 280,592.23 m

9c) Velocity East

30 m/s * Cosine(60) = 15 m/s

9d) Distance East

15 m/s * (3 hours)

15 m/s * 10800 s = 162,000 m

9e) Total displacement ( total distance  also known as  magnitude)

Total Distance = [tex]\sqrt{(Distant North)^{2} + (Distant East)^{2} }[/tex]

TD = [tex]\sqrt{280592.23^{2} + 162000^{2} }[/tex]

TD = 323999.99 m

let's round it to  324,000 m

324 Km

A body moving with uniformly acceleration A has two point (5,15) and ( 20,60) on the velocity time graph of its motion. Calculate A. Pls I would like if the graph can be drawn I have the workings

Answers

Answer:

3 m/s

Explanation:

The slope of a velocity-time graph will give the acceleration for the object over the given interval.

Finding the slope:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1} = \frac{60 - 15}{20 - 5} = \frac{45}{15} = 3\\[/tex]

The acceleration A would be 3 m/s

Which has more kinetic energy, a car of mass 500 kg traveling at 15 m/s or a motorcycle of mass 250 kg traveling at 30 m/s?

Answers

The motorcycle of mass 250 kg traveling at 30 m/s will have the greater kinetic energy.

What is Kinetic energy?

This is the kind of energy possessed by any body that is in motion. It is also known as the moving energy.

From the question,

the mass of the car = 500kg

velocity = 15m/s

Kinetic energy for the car is;

[tex]K = \frac{1}{2} mv^{2}[/tex]

K = 1/2 x 500 x 15 x 15

K = 56, 250J

the mass of the motorcycle = 250kg

velocity = 30m/s

Kinetic energy for the motorcycle is;

[tex]K = \frac{1}{2} mv^{2}[/tex]

K = 1/2 x 250 x 30 x 30

K = 112, 500J

In conclusion, from calculating for both, the kinetic energy possessed by the motorcycle is higher, that means it has more kinetic energy.

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A machine works with an efficiency of 20%. The energy input is 200 joules/second. How
much useful energy will the machine generate in 10 minutes?

A. 36 kJ

B. 24 kJ

C. 40 kJ

D. 600 kJ

Answers

The quantity of useful energy which this machine would generate in 10 minutes is equal to: B. 24 kJ.

How to determine the efficiency of a machine?

Mathematically, energy efficiency can be calculated by using this formula:

Energy efficiency = WO/WI × 100

Where:

WO represents the output energy.WI represents the input energy.

For the output energy, we have:

20 = WO/200 × 100

4000 = 100WO

Output energy, WO = 4000/100

Output energy, WO = 40 joules/second.

Note: A minute is equal to 60 seconds.

In 10 minutes, the time is given by:

10 minutes = 10 × 60

10 minutes = 600 seconds.

Now, we can determine the useful energy generated by this machine:

Useful energy = 40 joules/second × 60 seconds

Useful energy = 24,000 Joules or 24 Kilojoules (24 kJ).

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A 1.0 kg block is pushed 3.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 28.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s2
.If the coefficient of kinetic friction between
the block and the wall is 0.30, find
a) the work done by the force on the block.
Answer in units of J.
b) the work done by gravity on the block.
Answer in units of J.
c) the magnitude of the normal force between
the block and the wall.
Answer in units of N.

Answers

(a) The work done by the force on the block is 9.99 J.

(b) The work done by gravity on the block is 29.4 J.

(c) The magnitude of the normal force between the block and the wall is 9.8 N.

What is the work done by the applied force on the block?

The work done by the applied force on the block is calculated as follows;

W = Fd cosθ

where;

θ is the angle of inclination of the applied forced is the displacement of the blockF is the applied force

F - μmg = ma

since the block is moving as constant velocity, acceleration = 0

Fcosθ - μmg = 0

F = μmg/cosθ

W = μmgd/cosθ

W = 0.3 x 1 x 9.8 x 3 / cos(28)

W = 9.99 (J)

The work done by gravity on the block is calculated as follows;

W = mg d cosθ

where;

m is mass of the block

W = 1 x 9.8 x 3 x cos(0)

W = 29.4 J

The magnitude of the normal force between the block and the wall is calculated as;

Fn = mg

Fn = 1 x 9.8

Fn = 9.8 N

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Shandra is studying Earth's magnetic field in her science class. She leams that a giant shield around her planet protects all living things from dangerous charged particles from the sun.
How does the magnetic field protect life on Earth?

O A. The magnetic field directs charged particles toward the poles and then past Earth.
O B. The magnetic field directs charged particles toward the equator and then past Earth.
O C. The magnetic field absorbs the charged particles coming from the sun.
O D. The magnetic field directs charged particles toward the poles then absorbs them.

Answers

The magnetic field protect life on Earth by directing the charged particles toward the poles and then past Earth.

The giant shield around Earth that protects all living things from dangerous charged particles from the sun is called as Earth's magnetosphere. It is generated by the motion of molten iron in Earth's core. It also provides the basis for navigation using a compass.

The magnetosphere shields the life on Earth from the constant bombardment by charged particles emitted from the sun which is called as solar wind.

Therefore, the magnetic field protects life on Earth by directing the charged particles toward the poles and then past Earth.

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What are the smaller bulbs called?

Answers

Answer:

E10 Miniature Edison Screw (MES) Also called “Miniature Screw

The smaller light bulbs are the E5 Lilliput Edison Screw (LES).

What are the common light bulb base sizes ?

Today, there are many applications that make substantial use of light bulbs. Lighting bulb bases come in a wide variety.

Based on the letter-number references, you can tell what size light bulb base it is. In contrast to the number, which designates the base's breadth, the first letter indicates the base's shape or form.

Following are the most typical diameters for light bulb bases:

Standard-Medium, normal sized screw in base: E26 or E27

Candelabra, a smaller screw in base: E12

Intermediate: E17

Bi-pin, having pin-in base including two points of contact: G4 or GU24

Twist-And-Lock base: GU10

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Circle the letter of the cell layer that produces new phloem and xylem.
A. heartwood
B. sapwood
C. bark
D. cambium

Answers

Answer:

D: Cambium

Explanation:

The Answer is cambium

1. A student tests the second law of motion by accelerating a block of ice at a rate of 3 m/s².
If the ice has a mass of 12.6 kg, what is the force must the student apply to the ice?

Answers

Answer: 37.8 N

Explanation:

F = ma (Newton's 2nd Law)

Force = mass x acceleration

F = (12.6 kg)(3 m/s2) = 37.8 N

A car is traveling at 18.25 meters per second for 5.27 seconds. How far did it travel in meters? Round your answer to two decimal places. A car is traveling at 18.25 meters per second for 5.27 seconds. How far did it travel in meters? Round your answer to two decimal places.

Answers

96.18 meters

(96.1776 rounded to two decimal places is 96.18)

Which of the following is accurate when discussing specific heat?
A) Specific heat values for solids will never vary for different ranges of temperature.
B) The specific heat of a gas can be measured at constant pressure.
C) Specific heat values for liquids will never vary for different ranges of temperature. D) The specific heat of a gas can be measured at constant volume only.

Answers

The statement indicating that the specific heat of a gas can be measured at constant pressure is accurate when discussing specific heat (Option B).

What is the specific heat of a gas?

The specific heat of a gas is a measurement that makes reference to the relative molecular position of the molecules in a substance in the gas state, which is a state of matter where particles are more separated in space when compared with liquid and solid states.

Moreover, specific heat can be defined as the amount of heat energy that may be able to increase the temperature of 1 gr (gram) of a given material to 1 Celssius degree.

Therefore, with this data, we can see that the specific heat of a gas depends on the temperature and it expresses a given amount of heat energy in a substance or material.

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URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!

Answers

Wouldn’t it be inertia, because going straight down.

Answer:

The answer is C inertia

Explanation:

This action is a result of the disks.

URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!

Answers

Answer:

1. B (graph A) 2. A (graph D) 3. D (graph B) 4. C (graph C)

Explanation:

1. Graph A gives the relationship between the speed of a car and time. Over time, the speed of the car is decreasing (moving closer to 0). Therefore, the car is slowing down.

2. Graph D gives the relationship between the distance of a car and time. Over time, the distance the car has traveled is increasing at a steady rate. Because the distance is changing, we know the car is moving. And because the slope of the line is constant, the car is moving at a constant speed.

3. Graph B gives the relationship between the distance of a car and time. This distance is not changing over time, meaning that if the car started 5 meters away, the car is still 5 meters away. Therefore, the car is not moving.

4. Graph C gives the relationship between speed and time. The speed is increasing, and therefore not constant. This means that the car is either speeding up or slowing down. Since speed is increasing (the inverse of graph A), we know the car is speeding up. When an object is speeding up, the velocity/speed and the acceleration have the same sign (both positive or negative). Our speed values are all positive, so our acceleration must also be positive.

Radio waves and microwaves have what type of frequency and
wavelength?
A.low frequency & long wavelength
B.high frequency & short wavelength
C.medium frequency & long wavelength
D.High frequency & long wavelength

Answers

Radio waves and microwaves have A.)low frequency and long wavelength.

What type of frequency and wavelength do radio and microwaves have?

Microwaves are classified as radio waves, but they have higher frequencies than other radio waves. And so with higher frequencies, they also have more energy. That's is the reason, microwaves are useful for heating food in microwave ovens.

Microwaves have a long wavelength, but not as long as radio waves. The  atmosphere of earth is transparent to some wavelengths of microwave radiation. The longer wavelengths pass through the atmosphere of earth more easily than the shorter wavelength microwaves.

Radio waves have photons with the low energies and microwaves have more energy as compared to radio waves.

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Can an object have momentum in space?​

Answers

Answer: Objects in space can have momentum space because momentum depends on mass and velocity. Unlike other quantities, like weight, mass does not change if an object is on space or on Earth.

Explanation: Because momentum depends on mass and velocity and unlike other quantities, like weight, mass does not change if an object is on space or on Earth.

please respond my question

Answers

The astronomy of the star and the parameters of the star in terms of solar units are;

Radius of the star ≈ 5.03 [tex]R_{Sun}[/tex]

Temperature of the star ≈ 0.92 [tex]T_{Sun}[/tex]

Luminosity of the star ≈ 18 [tex]L_{sun}[/tex]

What is the system for astronomy units?

The astronomical system of units are a special class of units designed for astronomy.

First part;

One solar radius is specified as [tex]R_{Sun}[/tex] = 6.9551 × 10⁵ km

The radius of the star = 3.50 × 10⁶ km

The radius of the star in units of the solar radius is therefore;

Radius = 3.50 × 10⁶ km ÷ (6.9551 × 10⁵ km) [tex]R_{Sun}[/tex] ≈ 5.03 [tex]R_{Sun}[/tex]

Second part;

One unit of the solar temperature, [tex]T_{Sun}[/tex] = 5777 K

The temperature of the star = 5305 K

The stars temperature in units of the solar temperature, is therefore;

Temperature = 5305 K/(5777 K) ≈ 0.92

The temperature of the star in units of the solar temperature is 0.92 [tex]T_{Sun}[/tex]

Third part;

The function for the luminosity of a star, L, is; L = 4·π·R²·σ·T⁴

The luminosity of the star = 4 × π × (3.50 × 10⁶)² × σ × 5305⁴

The luminosity of the Sun = 4 × π × (6.9551 × 10⁵)² × σ × 5777⁴

The solar luminosity of the star = (4 × π × (3.50 × 10⁶)² × σ × 5305⁴) ÷ (4 × π × (6.9551 × 10⁵)² × σ × 5777⁴) ≈ 18

The solar luminosity of the star is 18 [tex]L_{Sun}[/tex]

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look at the two models of charges

Answers

Answer: im looking

explination

Which of the following is a true statement about the conservation of energy?

Answers

According to the law of conservation of energy, statement which is true about conservation of energy is that the total energy is always conserved.

What is law of conservation of energy ?

According to law of conservation of energy, it is evident that energy is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Julius Mayer in the year 1842.

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Calculate the combined mass of the two people if the tension of the cable is 1205.4 N

Answers

Answer:

Let

T

be the tension of the cable and m

g

be the force of gravity. If the upward direction is positive, then Newton’s second law is T−mg=ma, where a is the acceleration. Thus, the tension is T=m(g+a). We use constant acceleration kinematics (Table 2-1) to find the acceleration (where v=0 is the final velocity, v

0

=−12m/s is the initial velocity, and y=−42m is the coordinate at the stopping point). Consequently, v

2

=v

0

2

+2ay leads to

a=−

2y

v

0

2

=−

2(−42m)

−12m/s

=1.71m/s

2

We now return to calculate the tension:

T=m(g+a)

=(1600kg)(9.8m/s

2

+171m/s

2

)

=1.8×10

4

N

Answer:

Explanation:

Given:

P = 1205.4 N

g = 9.8 m/s²

___________

m - ?

m = P / g

m = 1205.4 / 9.8 ≈ 123 kg

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