A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.
The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.
When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.
Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.
Answers
Free fall motion is motion in which the only force acting on the body is gravity.
What is free fall motion?A free-falling object is one that moves only due to the effect of gravity, and its motion is defined by Newton's second law of motion. We can use algebra to calculate the acceleration of a free-falling particle.
The student should launch the sphere at 2v₀, for the sphere will land at approximately 1.41D, which is in the 3 point zone
The given parameter are;
The distance covered by the sphere when launched at height, H = D
The velocity with which the ball reaches D = v₀
The current available height of launcher= H/2
The available velocities = v₀, and 2v₀
Now,
From H = ut + (1/2)gt², where, initial velocity of the vertical motion of the ball, u = 0
we know;
H = (1/2)gt²
Therefore, the time it takes the ball to drop from H, t = √(2H/g)
The distance, D = v₀ × √(2H/g)
When the height is H/2, we get;
t = √(2H/(2g)) = √(H/g)
Thus, the distance covered, D₁ = v₀ × √(H/g)
Therefore, D = (√2) × v₀ × √(H/g) = (√(2))D₁
Now, D₁ = D/(√2) ≈ 0.71D
D₁ ≈ 0.71D
At speed 2v₀, we have;
D₂ = 2v₀ × √(H/g) = √2 × v2 × v₀ × √(H/g) = √2 × v₀ × √(2H/g) = √2D₁ ≈ 1.41D
D₂ ≈ 1.41D
The 2 point zone = D/2 < x < D = 0.5D < x < D (Position D₁ ≈ 0.71D is located here)
The 3 Point Zone = D < x < 3D/2 = D < x < 1.5D (Position D₂ ≈ 1.41D is located here)
Given that at D₂, the ball lands in the 3 Point Zone, the student should launch the sphere at the speed, 2v₀, so that the ball will land at D₂ ≈ 1.41D, which is in the 3 Point Zone
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The complete question is as follows:
A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.
The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.
When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.
Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.
Related Questions
PLEASE HELP!
Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg.
Answers
The acceleration of the luggage across the airport is 0.42 m/s².
What is the acceleration of the luggage?
The acceleration of the luggage across the airport is calculated by applying Newton's second law of motion as follows;
Mathematically, the Newton's second law of motion is given as;
F(net) = ma
where;
F(net) is the net force on the luggagem is the mass of the luggagea is the acceleration of the luggageF - Ff = ma
where;
F is the applied force on the luggageFf is the force of friction33.3 - 12.3 = 50a
21 = 50a
a = 21/50
a = 0.42 m/s²
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The complete question is below:
Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg. find the acceleration of the luggage.
Find A mass of 10 kg is moving in a circular path of radius 2 m with a uniform speed of 50 ms the centripetal acceleration and the corresponding centripetal force
Answers
Answer:
Centripetal acceleration: [tex]1250\; {\rm m\cdot s^{-2}}[/tex].
Resultant force on the object should be [tex]12500\; {\rm N}[/tex].
(Assuming that the speed of the object is [tex]50\; {\rm m\cdot s^{-1}}[/tex].)
Explanation:
For an object that travels along a circle path of radius [tex]r[/tex] at a speed of [tex]v[/tex], (centripetal) acceleration will be [tex]a = (v^{2} / r)[/tex].
In this example, speed is [tex]v = 50\; {\rm m\cdot s^{-1}}[/tex] while the radius of the circular path is [tex]r = 2\; {\rm m}[/tex]. The (centripetal) acceleration of this object will be:
[tex]\begin{aligned}a &= \frac{v^{2}}{r} \\ &= \frac{(50\; {\rm m\cdot s^{-1}})^{2}}{(2\; {\rm m})} \\ &= 1250\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
For an object of mass [tex]m[/tex], the resultant force to achieve acceleration [tex]a[/tex] is [tex]F(\text{net}) = m\, a[/tex]. In this example, [tex]m = 10\; {\rm kg}[/tex] while [tex]a = 1250\; {\rm m\cdot s^{-2}}[/tex]. The required resultant force will be:
[tex]\begin{aligned}F(\text{net}) &= m\, a \\ &= (10\; {\rm kg})\, (1250\; {\rm m\cdot s^{-2}}) \\ &= 12500\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 12500\; {\rm N} \end{aligned}[/tex].
when a wave pulse on a string reflects from a boundary, how is the reflected pulse related to the incident pulse
Answers
The reflected pulse will be equal to or less than incident pulse when wave pulse on a string reflects from a boundary.
A rigid wall causes an object, like a ball, to bounce back when it is thrown against it. In terms of momentum and energy conservation, the object's "reflection" can be examined. The ball will bounce back at the same speed if the collision between the ball and the wall is perfectly elastic and all incident energy and momentum is reflected. The ball does not bounce back with the same speed if the collision is inelastic because the wall (or ball) absorbs some of the incident energy and momentum.Additionally carrying energy and momentum, waves are reflected by obstacles whenever they come into contact with them. Echoes, radar detectors, and standing waves—which are crucial for musical instrument sound production—are all caused by waves that have been reflected.To learn more about momentum -
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Explain how a convection current can enable a hawk or eagle to soar upward without flapping its wings.
Answers
Answer:hope this helps
pleasee i need the brainliest
Explanation: Warm air rises and is replaced by cooler air from the surrounding area. The warm air eventually cools off, falling down and replacing more warm air. This causes a constant upward flow sometimes called a thermal that allows large birds to soar without effort.
According to ___ in the nec®, unused knockouts and other openings in electrical boxes and cabinets are required to be closed.
Answers
According to sect 110.12 (A) in the NEC, unused knockouts and other openings in electrical boxes and cabinets are required to be closed.
What do you understand by national electrical code?
A United States standard for the secure installation of electrical wiring and equipment is the National Electrical Code (NEC), also known as NFPA 70. It is a component of the National Fire Protection Association's National Fire Codes series (NFPA). While the NEC does not represents a U.S. law, NEC use is typically mandated by state or municipal legislation, as well as in many jurisdictions outside of the United States. The NEC standardizes and codifies the specifications for secure electrical installations. The "authority having jurisdiction" checks to see if these minimum requirements have been met.
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2 The speed-time graph shows the movement of a car.
speed
0
0
T
time
Which feature of the graph represents the distance travelled by the object whilst
moving at a constant speed?
A
area S
B
area S+ area T
C
area T
D the gradient at point X
Answers
Area T represents the distance travelled by the object whilst moving at a constant speed. Option (C) is correct.
What is speed?The distance an object travels in a unit of time is its speed. Speed is a scalar quantity since it has simply magnitude and no direction. SI unit of speed is meter per second.
Hence, mathematically:
Speed = distance travelled/time interval.
Distance travelled = speed × time interval.
In the given graph, area T represents constant speed × time interval. Hence, area T is equal to the distance travelled by the object moving at a constant speed.
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A 5-ohm resistor is connected to a 1.5 V battery. The 5-ohm resistor is replaced with a smaller resistor. In order to keep the current through the resistor the same, what should be done to the voltage of the battery
(A) Increase it
(B) Decrease it
(C) Keep it the same
Explain why
Answers
Answer:
Below
Explanation:
V = IR
V/R = I
Now you can see that if you decrease R, you will need to decrease V to have the same value of I
what is the angular momentum of a hydrogen atom in (a) a state and (b) a state? give your answers as a multiple of
Answers
According to the given statement [tex]\sqrt{2h}[/tex] and [tex]2\sqrt{3h}[/tex] and is the angular momentum of a hydrogen atom.
What does the word "momentum" mean?Momentum may be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a slow-moving bowling ball might have the same acceleration as a baseball being thrown fast.
Briefing:
The angular momentum of a hydrogen atom can be defined as:
[tex]L=\sqrt{l(l+1)}h,[/tex]
where l represents the orbital quantum number which defines the subshells s, p, d, f.
The 4p subshell has an orbital quantum number of 1 . This means that the angular momentum according to equation (I) equals to:[tex]L=\sqrt{1(1+1)}h=\sqrt{2h}[/tex]The 5f subshell has an orbital quantum number of 3 . This means that the angular momentum according to equation (I) equals to:[tex]L=\sqrt{3(3+1)}h=\sqrt{12}h=2\sqrt3h[/tex]To know more about momentum visit:
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1. jupiter has a mass approximately 300 times greater than earth's and a radius about 11 times greater. how will the gravitational acceleration at the surface of jupiter compare to that at the surface of the earth?
Answers
surface gravity formula
[tex]g=\frac{GM}{r^{2} }[/tex]
[tex]g[/tex] is the surface gravity in m/s²
[tex]G[/tex] is the gravitational constant 6.67408x10⁻¹¹ m³/kgs²
[tex]M[/tex] is the mass of the object in kg
[tex]r[/tex] is the radius of the object in m
The Earth’s mass is 5.972x10²⁴kg,
Jupiter’s mass is 1.898x10²⁷ kg,
the Earth’s radius is 6371 km,
Jupiter’s radius is 69911 km
Calculation for earth's surface gravity[tex]g=\frac{6.67408X10^{-11}X5.972X10^{24} }{(6.371X10^{6} )^{2} }[/tex]
[tex]g=9.82 m/s^{2}[/tex]
Calculation for Jupiter's surface gravity[tex]g=\frac{6.67408X10^{-11}X1.898X10^{27} }{(6.9911X10^{7} )^{2} }[/tex]
[tex]g=25.92 m/s^{2}[/tex]
conclusion
[tex]\frac{25.92}{9.82} = 2.63[/tex]
the surface gravity of Jupiter is 2.63 times that of Earth.
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A 5kg block of iron with a specific heat capacity of 450 J/kg °C recieves 0.03 MJ of energy. What is the temperature rise of the iron?
Answers
The temperature rise of the iron is 13.33°C
How to calculate temperature in calorimetry?Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.
The heat gained or released during a calorimetry procedure can be calculated as follows:
Q = mc∆T
Where;
Q = quantity of heat (J)m = massc = specific heat capacity∆T = change in temperatureAccording to this question, a 5kg block of iron with a specific heat capacity of 450 J/kg °C recieves 0.03 MJ of energy. The change in temperature can be calculated as follows:
30,000J = 5 × 450 × ∆T
30000 = 2250∆T
∆T = 30000 ÷ 2250
∆T = 13.33°C
Therefore, 13.33°C is the temperature rise.
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A tow truck pulls a 1225 kg car and accelerates at a rate of 3 m/s^2. What
is the force of the tow truck?
F = ma
Answers
Answer:
[tex] \huge{\boxed{3675 \: N}} [/tex]
Explanation:
The force acting on the tow truck can be found by using the formula
[tex] \bold{F = mass × acceleration} [/tex]
From the question
mass = 1225 kg
acceleration= 3 m/s²
F = 1225 × 3 = 3675
We have the final answer as
3675 Ng what best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?
Answers
The action that best describes the camera motion in the scenes directly prior to the Old Man's Defiant hand gesture is: "Zooming in and out" (Option C)
What are the various types of Camera Motions and why are they important?Some interesting camera motions are:
Static shot - The camera is stationary and does not move during the shot. This can create a sense of stability and calm.Panning shot - The camera moves horizontally from left to right or vice versa, following the action or moving to reveal a new part of the scene.Tilt shot - The camera moves vertically up or down, following the action or revealing a new part of the scene.Tracking shot - The camera moves horizontally, vertically, or diagonally while following the action or a moving object.Note that the different camera motions described above are important because they allow filmmakers to convey mood and emotion, create visual interest, and guide the audience's attention within a scene.
For example, a static shot can create a sense of calm or stability, while a handheld shot can create a sense of intimacy or instability. A panning shot can follow the action and keep the audience engaged, while a zoom shot can draw attention to a specific part of the scene.
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Full Question:
What best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?
O Static and secured on a tripod
O Moving chaotically
O Zooming in and out
O Filming at 96 frames a second
scouts at a camp shake the rope bridge they have just crossed and observe the wave crests to be 5.45 m apart. if they shake the bridge three times per second, what is the propagation speed of the waves (in m/s)?
Answers
The propagation speed of the waves is v = 1.1009 m/s
What is propagation of wave ?Waves' progression and transformation through space and time. The article will examine several definitions in addition to the usual one for wave propagation.
There are numerous crests and troughs that sound waves travel over. II Sound waves need a physical medium to travel through. III The movement of particles is thought to be responsible for the propagation of sound waves.
Transverse waves include electromagnetic waves like X-rays, radio waves, and visible light. Electric and magnetic fields moving in a perpendicular direction make up these waves. The best examples of longitudinal waves, which vibrate parallel to the direction of the wave, are sound waves.
The formula is
v = fλ
given distance is 5.45 m
and the number of times the bridge is shaken is 3 times
this implies
v = 3 / 5.45 × 2
v = 1.1009 m/s
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A 14 kg box is being pushed across a floor with an applied force of 12 N at a constant velocity of 6 m/s. The surface then becomes very rough, and with the same applied force, the box comes to rest in 2 seconds. What is the acceleration of the box while at constant velocity?
*
Answers
acceleration during the constant speed is the friction acceleration which is 3 ms^-2.
What is accelaration?Accelaration is the eate of the change of the velocity of an object with respect by time.
Accelaration (a) id the reason that change in velocity over to the change in time.
Represented by the equation to a= ∆v/∆t. This is allowa you to measure how fast velocity by the changes in meters per second squars (m/s^2).
Here mass is 14 KG box
Here friction force applied by the because of rough place so that it stopped in 2 seconds
So acceleration by friction is negative sense and 6/2 or 3 ms^-2
So static frictional force is = 14×3 or 54 which is greater than the applied force
So the acceleration during the constant speed is the friction acceleration which is 3 ms^-2.
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An object is rolled horizontally off a table. It lands on the floor 1 meter away from the base of the table. The height of the table is 2.5m. What is the initial vertical velocity of the object?
Answers
The initial vertical velocity of the object is 2.5 m/s .
How to calculate intial velocity?Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: (1) The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.
Keep in mind that the INITIAL VERTICAL VELOCITY of the projectile is equal to ZERO because it is launched horizontally.
Given,
base =1m
height = 2.5
vertical velocity =2.5/1
The initial vertical velocity of the object is 2.5 m/s .
A projectile's initial velocity has both a horizontal component and a vertical component if it is thrown at an angle to the horizontal. The projectile's displacement horizontally as a result of velocity is shown by the horizontal velocity component (vx).
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disregarding air drag, how fast must you toss a ball straight up in order for it to take 2 seconds to return to the level from which you tossed it?
Answers
The ball should be tossed with speed 10 m/s in order for it to take 2 second to return to the level from which it was tossed.
The Time of flight of projectile motion is defined as the total time taken during ascent and fall to the ground.
Here, time of flight is given 2 seconds. So, Time of ascent is 1 second. Time of ascent is time taken to reach the highest height.
We have to apply the formula
v= u +at
At the maximum height, v =0 m/s.
0 = u - 10×1
So, u = 10 m/s
So, our answer depends on the value of g. If we take the value of g as 9.8, then speed required will be 9.8 m/s
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A figure skater is spinning slowly with arms outstretched. Shebrings her arms in close to her body and her moment of inertiadecreases by 1/2. Her angular speed increases by a factor of
A. 2
B. 1
C. 4
D. square root of 2
E. 1/2
Answers
The angular speed increase by a factor of 2 i.e. option (a). 2 is correct
The rate of change of angular displacement is referred to as angular speed. Radian per second is used to measure angular speed. Both angular velocity and angular speed are represented using the same formula.
Utilizing the angular momentum conservation law,
Li = Lf
Thus ,Li is the initial angular momentum and Lf the final angular momentum are, respectively.
L = IW, where I is the inertia momentum and W is the angular velocity, can also be used to determine angular momentum.
so, [tex]IiWi = IfWf[/tex]
[tex]L_{f} =\frac{1}{2} L_{i}[/tex]
According to the given condition, then from above two equation,
[tex]L_{i}W_{f} = \frac{1}{2}L_{i}W_{f}[/tex]
[tex]2W_{i} = W_{f}[/tex]
Thus the angular speed of the skater is factor of 2.
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the total magnification achieved using a 10× objective lens with a 10× eyepiece lens is 20×.
Answers
The given statement that 'The total magnification achieved using a 10x objective lens with a 10x eyepiece lens is 20x' is false.
A stereomicroscope is a good option for viewing large and opaque specimens.
The magnification of eyepiece is either 10x or 15x.
The magnification of objective lens can be 10x, 40x or 100x.
The total magnification is nothing but the multiplication of the magnification of eyepiece and the magnification of objective lens.
Given that, magnification of objective lens is 10x
Magnification of eyepiece lens is 10x
So, the total magnification is,
⇒ 10x × 10x = 100x
But the total magnification is given as 20x.
Thus, the given statement is false.
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Fill in the blanks using the appropriate letters from the bottom.
A mass m is attached to an ideal spring with a spring constant k.
It has a period of [tex]T_{A}[/tex]=1.00 seconds measured in Boston, where g=9.80 [tex]m/s^{2}[/tex].
A simple pendulum of mass m and L has the exact same period [tex]T_{B}[/tex] =1.00s right there.
What will happen to the period of (A) the spring-mass system and (B) the pendulum,
A. when they are both moved to the moon; [tex]T_{A}[/tex]___, [tex]T_{B}[/tex]___
B. when they are both moved to the north pole where g = 9.83 m/s2; [tex]T_{A}[/tex]___
,[tex]T_{B}[/tex] ___
C. or when they are both moved to the equator where g = 9.78 m/s2? [tex]T_{A}[/tex]___
, [tex]T_{B}[/tex] ___
Select from below:
A. Stay the same.
B. Reduce by a factor of 6.
C. Increase by a factor of 6.
D. Reduce by a factor of 2.45.
E. Increase by a factor of 2.45.
F. Reduce by roughly 0.1%
G. Increase by roughly 0.1%
Answers
The force required to extend or compress a spring, divided by the lengthening or shortening of the spring, is known as the spring constant.
If a vertical is coupled to a mass M, when?A vertical spring with mass M that is attached steadily lowers to its equilibrium position. This causes the spring x to lengthen. Suppose the same thing was still tied to the same vertical spring, but it was allowed to fall suddenly instead.
How can you determine a spring's top speed?The maximum velocity is equal to the amplitude times the angular frequency, or v max=A v max = A, since the sine function oscillates between -1 and +1. The mass is travelling toward x=+A when the maximum velocity occurs at the equilibrium location (x=0).
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a. If there is to be no relative motion between the train and the edge of the platform, how fast must
the train move compared to the rim speed of the rotating platform?
b. Why is the stairway located at the center of the platform?
2. The design below shows a train that makes round trips from Station A to Station B in a
continuous loop.
a. How is the size of the round platform and train speed related to the amount of time that
passengers have for boarding?
b. Why would this rotating platform be impractical for high-speed trains?
CONCEPTUAL PHYSICS
Answers
Train must move with equal speed as of platform in opposite direction i order to maintain zero relative velocity.
What is velocity?Velocity is the speed in which something move in a paticular Direction.
From the question it is given that
relative velocity between platform and train = 0
since relative velocity of train with respect to platform is given by
where, is the velocity of train and is the velocity of platform
⇒ vt = vp
since platform is always at stationary i.e.,
thus train velocity = 0
Therefore, train does not move
If, Platform is moving then train must move with equal speed as of platform in opposite direction.
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two straight rods 50-cm long with axes 1.5-mm apart in a current balance carry currents of 15 a each in opposite directions. what mass must be placed on the upper rod to balance the magnetic force of repulsion?
Answers
After doing the equation the total mass is 1.53×10^-3kg .
What is the magnetic force of attraction?
Similar poles or charges will typically repel one another. Thus, the two magnets will push against one another. Repulsion is the name given to a force that causes objects to move apart from one another.
between two or more comparable or similar charges there is a force. Similar charges are attracted to one another. Charges that share a similar appearance separate. Chemical bonding is characterized by repulsive forces.
Create a formula for the magnetic force to equal the normal force, and then enter the necessary values into the expression to obtain the mass.
FN=F
mg=µo I1 I2 L÷2πr
m=µo I1 I2 L÷2πrg
= 4π×10^-7T-m/A (15A) (15A)(0.50m)÷2π(0.0015m)(9.8m/s²)
= 1413÷0.0923×10^-7
= 1.53×10^-3kg
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Insert tab A into slot B" is something you might read in the assembly instructions for pre-fabricated bookshelves. Suppose that tab A varies in size according to a Normal distribution with a mean of 30 mm. And a standard deviation of 0. 5 mm. , and the size of slot B is also Normally distributed, with a mean of 32 mm. And a standard deviation of 0. 8 mm. The two parts are randomly and independently selected for packaging. What is the probability that tab A won’t fit into slot B?
Answers
0.017 is the probability that tab A won’t fit into slot B
What is probability?Probability is related to possibility. Random event generation is the subject of this branch of mathematics. Values range from 0 to 1. Probabilities are built into mathematics to predict the likelihood of certain events.
P(tab A won't fit into slot B) = P (A>B)
= P( A-B > 0)
Given that, A ≈ N(30,0.5) B ≈ N(32, 0.8)
Here,
E (A-B) = 30-32 = -2
V(A-B) = V(A) + V(B) = (0.5)² + (0,8)²
= 0.89
SD (A-B) = [tex]\sqrt{0.89}[/tex]
So, (A-B) ≈ N (-2, 0.9433)
P( A-B > 0) = 1 - P(A-B ≤ 0)
= 1 - P [(A - B +2 / 0.9433) ≤ (+2 / 0.9433)]
= 1 - P (Z₁ ≤ 2.12)
= 1 - 0.98300
= 0.017
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Which of the following is not a benefit of stressing
a. Poor circulation
b. Increase speed and power
c.Increased flexibility
d. Minimized change injuries
Answers
Poor circulation is not a benefit of stretching.
How many minutes of stretching should a person perform before participating in physical activities?
Stretching for 5 to 10 minutes is probably enough for most activities. It's important, however, to adequately stretch all the muscles you'll be using. Three benefits of stretching before a workout include increased blood flow.
What are the 5 benefits of stretching?
Improve your performance in physical activities.Decrease your risk of injuries.Help your joints move through their full range of motion.Increase muscle blood flow.Enable your muscles to work most effectively.Improve your ability to do daily activities.Which benefit comes with flexibility?
Activities that lengthen and stretch muscles can help you prevent injuries, back pain, and balance problems. A well-stretched muscle more easily achieves its full range of motion.
Thus, poor circulation is the correct option.
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A carousel with a radius of 4.0 m spins at 7.2 revolutions per minute. What centripetal force would a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel
Answers
The centripetal force that a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel is 127.9 N.
What is the centripetal force of the child?
The centripetal force of the child is the inward force that must maintain the circular motion of the child at the given point in the circular axis without falling.
Mathematically, the formula for centripetal force is given as;
Fc = ma
where;
m is the mass of the childa is the centripetal acceleration of the childThe centripetal acceleration of the child is calculated as;
a = v²/r
where;
v is the linear speed of the childr is the radius of the circular path from point of the childa = (ω²r²) / r
a = ω²r
where;
ω is angular speed of the childr is the distance from the circle center to point of the child = 4 m + 1 m = 5 mω = 7.2 rev/min = 7.2 rev/min x 2π rad/rev x 1 min/60s = 0.754 rad/s
Fc = ma
Fc = m(ω²r)
Fc = 45(0.754² x 5)
Fc = 127.9 N
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Calculate the gravitational force between two objects when they are 0.750m
apart. Each object has a mass of 5.00kg.
A- 2.23x10^-8N
B- 3.00x10^-6N
C- 2.22x10^9N
D- 2.96x10^-9N
Answers
The gravitational force of attraction between two objects is 2.964 x 10⁻9 N. So, the correct option is D.
What is meant by gravitational force ?Gravitational force is defined as the force of attraction experienced by a body due to the gravity of earth.
Here,
Mass of each body,
m₁ = m₂ = 5 kg
Distance between the masses, r = 0.75 m
The equation for gravitational force is given by,
F = Gm₁m₂/r²
where G is the gravitational constant.
Therefore,
F = (6.67 x 10⁻¹¹x 5 x 5)/(0.75)²
F = 166.75 x 10⁻¹¹/0.5625
F = 2.964 x 10⁻9 N
Hence,
The gravitational force of attraction between two objects is 2.964 x 10⁻9 N.
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If only 10% of the energy gets passed to the next tropic level, what happens to the rest of the energy?.
Answers
Answer:
As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.
Explanation:
What is the kinetic energy of a 1,854.50 kg car that travels at 8.61 m/s?
Answers
Answer:
[tex] \huge{\boxed{68,738.99 \: J}} [/tex]
Explanation:
The kinetic energy of the car can be found by using the formula
[tex] \bold{k = \frac{1}{2} \times m \times {v}^{2} \\ }[/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 1854.5 kg
v = 8.61 m/s
[tex]k = \frac{1}{2} \times 1854.5 \times {8.61}^{2} \\ k = 927.25 \times 74.1321 \\ \\ k = 68738.989[/tex]
We have the final answer as
68,738.99 Jneed urgent help with this!!!! please provide working
Answers
Answer:
Heat Loss = Heat Gain
(60 - T) K1 M1 = (T - 10) K2 M2
M1 = metal M2 = liquid
K1 = metal K2 = liquid
(60 - T) K1 * 1 = (T - 60) K2 * 5
60 K1 - T K1 = 5 T K2 - 300 K2
T (5 K2 + K1) = 300 K2 + 60 K1
T = (300 K2 + 60 K1) / (5 K2 + K1)
Need to find largest T
(probably ethanol and iron - you will need to check)
to study problems concerned with the motion of matter under the influence of forces, i.e., dynamics, it is necessary to locate a point called
Answers
The center of mass must be found in order to analyze issues involving the flow of matter when subjected to forces, or dynamics.
Motion: A Simple DefinitionMotion is the alteration of a skin's position or orientation over time. The movements of people and animals is just one illustration of how everything in the cosmos is always moving. In addition, the fundamental building block of matter, the atom, is likewise constantly in motion.
Describe a motion example.Motion is the free flow of a body in relation to time. For instance, the fan, the carpet's dust blowing off of it, the water running from the faucet, a ball rolling about, a moving car, etc. Even just the universe is always changing.
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a floating leaf oscillates up and down three complete cycles in one second as a water wave passes by. the wave's wavelength is 10 meters. what is the wave's speed?
Answers
This water wave passes past while a floating leaf cycles down and up three times in a second. The wave's velocity will be 2 hertz.
What does that mean 2 hertz?Use this illustration The amount of waves that travel through a fixed location in a specific amount of time is known as frequency. The duration of a wave passing is therefore half a second. If so, the rate is 2 Hertz per second. Four Hertz is the frequency if 240 waves per hour are sent.
What does one Hz represent?One cycle per second, or hertz, is the SI unit for frequency (Hz). Cycles per second are represented as a hertz.
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