A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track. The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?

Answers

Answer 1

Answer:

Final velocity, V = 2.1213 m/s.

Explanation:

Given the following data;

Force, F = 1.50N

Mass, m = 0.2kg

Displacement, S = 30cm to meters = 30/100 = 0.3m

To find the acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is given by the formula;

[tex] F = ma[/tex] .......equation 1

Where;

F represents force.m represents the mass of an object.a represents acceleration.

Making acceleration (a) the subject, we have;

[tex]Acceleration (a) = \frac{F}{m}[/tex]

Substituting into the above equation, we have;

[tex]Acceleration, a = \frac{1.5}{0.2}[/tex]

Acceleration, a = 7.5m/s²

Now to find the final velocity, we would use the third equation of motion;

[tex] V^{2} = U^{2} + 2aS [/tex] .....equation 2

Where;

V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square. S represents the displacement measured in meters.

Note: Since the trolley is starting from rest, we know that it's initial velocity is 0.

Substituting the values into equation 2, we have;

[tex] V^{2} = 0^{2} + 2*7.5*0.3[/tex]

[tex] V^{2} = 0 + 4.5[/tex]

[tex] V^{2} = 4.5[/tex]

Taking the square root, we have;

[tex] V = \sqrt {4.5}[/tex]

V = 2.1213 m/s.

Therefore, the speed of the trolley after accelerating from rest through 0.3 m, if friction is negligible is 2.1213 m/s.


Related Questions

Enrique is given information about a satellite orbiting
Earth.
In order to calculate the tangential speed of the
satellite, what should Enrique do first?
r=3.8 x 108 m
T= 18 days
- convert the radius to kilometers
- convert the orbital period to seconds
-find the square root of the radius
- find the square root of the orbital period

Answers

Answer:

B, convert the orbital period to seconds

Explanation:

edge 2o2o

In order to calculate the tangential speed of the satellite,  Enrique should do first converted the orbital period to seconds. The correct option is b.

What is the tangential speed?

Any item moving along a circular path has a linear component to its speed called tangential velocity. An object's velocity is always pointed tangentially when it travels in a circle at a distance r from the center. Tangential velocity is the name given to this.

Satellites can go over the Earth's North and South Poles, orbit the equator, or travel anywhere in between. They travel thousands of miles into space or only a few hundred miles above the surface of the Earth to perform their orbits. Enrique has given:

r=3.8 x 108 m

T= 18 days

Therefore, the correct option is b. convert the orbital period to seconds.

To learn more about tangential speed, refer to the link:

https://brainly.com/question/3444782

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A ball rotates on a string as shown below.



If the string in the image above breaks at point 1, which of the following images best shows the direction the ball will travel?

Question 8 options:

Diagram A

Diagram B

Diagram C

Diagram D

Diagram E

Answers

Answer:

Diagram A

Explanation:

When an object is travelling in a circular path it has an acceleration called centripetal acceleration, even if it is moving with uniform speed. This acceleration is attributed to the object due to change in the direction of velocity at every instant during the motion.

The direction of the velocity of the object is tangent to the circular path at every instant and if the object beaks free of the circular motion, such as breaking of the string, then it will go in the direction tangent to the circle at that instant. Hence, the diagram that best shows the direction ball will travel is:

Diagram A

Shani poses as the Statue of Liberty for an art class. She holds a torch above her head with her right hand and a book against her side with her left hand. She holds the pose for ten minutes. At the end of the session, she mentions to her friend that it was a lot of work to pose and that her arms are really tired.

Which describes the work Shani did while she posed?(assume the starting work position is when her hand is already raised )

She did more work with her right hand than with her left because the right was held up higher.
She did no work while she posed because she did not move the torch or the book.
She did work while she posed because she was tired at the end of the session.
She did no work while she posed because she did not exert a force on anything.

Answers

Answer: she did no work while she posed because she did not move the torch or the book

Explanation: just did it on edge

Answer:

Which describes the work Shani did while she posed?(assume the starting work position is when her hand is already raised )

She did more work with her right hand than with her left because the right was held up higher.

******* CORRECT******* >She did no work while she posed because she did not move the torch or the book.

She did work while she posed because she was tired at the end of the session.

She did no work while she posed because she did not exert a force on anything.

Explanation:  January 2021 Edge test

In a football game the running back is running up the field. He starts from rest and runs 4 seconds with an acceleration of 1.3m/s. What is the magnitude of his displacement

Answers

We are given:

initial velocity (u) = 0 m/s

time (t) = 4 seconds

acceleration (a) = 1.3 m/s²

displacement (s) = x m

Solving for the displacement:

from the second equation of motion

s = ut + 1/2 at²

replacing the variables with the given values

x = (0)(4) + 1/2 (1.3)(4)(4)

x = 1/2 * 20.8

x = 10.4 m

which of the following statements about rapport is not true

Answers

Sorry but I can’t answer the question because I don’t see a statement plz but one up

A soccer ball is kicked with an initial speed of 12m/s at a 30-degree angle above the horizontal. Calculate the horizontal velocity and the initial vertical velocity. [Show all work, including the calculations with substitutions with units.]

Answers

Answer:

x=10.39 m/s

y = 6 m/s

Explanation:

Components of a Vector

A vector can be expressed in several forms, including the rectangular and the polar form.

The rectangular form uses the x-y coordinates of the vector, being the right and up directions considered as positive.

The polar form uses the magnitude r and the angle it forms with the positive x-direction.

Given the polar form (r,θ), we can calculate the rectangular coordinates as follows:

[tex]x=r\cos\theta\\[/tex]

[tex]y=r\sin\theta[/tex]

The soccer ball is kicked with an initial speed of v=12 m/s and an angle of 30 degrees. Thus the horizontal and vertical components are:

[tex]x=12~m/s\cos 30^\circ[/tex]

[tex]x=12~m/s\cdot 0.866[/tex]

x = 10.39 m/s

[tex]y=12~m/s\sin 30^\circ[/tex]

[tex]y=12~m/s\cdot 0.5[/tex]

y = 6 m/s

if a pebble and a boulder are rolling down a hill side by side at the same speed, which object has more kinetic energy?

Answers

Boulder because it has more mass

When observed from earth, how many oscillations does the pendulum on the spaceship undergo compared to the pendulum on earth in a given time interval:__________

Answers

Answer: it’s Fewer oscillations.

Explanation:

according to newtos first law of motion. what is required to make a object slow down.

Answers

Answer:

Friction

Explanation:

Friction is a force that slows down moving objects. If you roll a ball across a shaggy rug, you can see that there are lumps and bumps in the rug that make the ball slow down. The rubbing, or friction, between the ball and the rug is what makes the ball stop rolling. External Force is required.

how much force is needed to accelerate a 1000 kg car at a rate of 3 m/s^2

Answers

Answer:

3000N

Explanation:

hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N

A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
A. 80 m/s
B. 800 m/s
C. 400 m/s
D. 40 m/s SUBMIT​

Answers

Answer:

A. 80 m/s

Explanation:

The velocity of the spacecraft can be found by using the formula

[tex]v = \frac{p}{m} \\ [/tex]

p is the momentum

m is the mass

From the question we have

[tex]v = \frac{20000}{250} = \frac{2000}{25} \\ [/tex]

We have the final answer as

80 m/s

Hope this helps you

ANSWER THIS QUESTION PLS WILL GIVE BRAINLEST
A star has right ascension of 5 hours. Which of these statements is correct about the star?

It is 5 hours to the west of zero hours right ascension.
It is 5 hours to the east of zero hours right ascension.
It is 5 hours north of the celestial equator.
It is 5 hours south of the celestial equator.

Answers

Answer:

A

Explanation:

It is 35 minutes to the east of zero-hours right ascension. Explanation: The right ascension of a star basically determines the position of the star on the east to west co-ordinates system.

Answer:Answer is a

Explanation:

Plz help I don’t know what to do

Answers

a. compression
b. rarefaction
c. longitudinal

Lauren walks 100m in half a minute. What must her speed have been to travel this distance?

Answers

Answer:

3.33 m/s

Explanation:

Using the formula: s = d / t (where s is speed, d is distance, and t is time)

[Convert minutes to seconds then solve]

Half a minute is 30 seconds. Therefore:

s = 100 / 30 = 3.33 m/s

Anne applies a force on a toy car and makes it move forward. What can be said about the forces acting on the toy car at the moment Anne applies the force? The forces acting on the toy car are .

Answers

Answer:

unbalanced.

Explanation

ive taken the test and unbalanced is correct.

Answer:

unbalanced

Explanation:

bc i got it right on a quiz

An object is pulled with a 85 N force inclined at 27° along a horizontal surface ABC
where AB is smooth but BC is rough.
a) Compute the mass of the object if the object moves with an acceleration of 5
ms-1 along AB.​

Answers

Answer:

m = 15.15 kg

Explanation:

Newton's Second Law of motion states that when an unbalanced force is applied on a body, an acceleration is produced in it in the direction of force. The component of force along the horizontal direction here, will be given by the Newton's Second Law as:

Fx = ma

F Cosθ = ma

where,

F = Magnitude of Force = 85 N

θ = Angle with horizontal = 27°

m = mass of object = ?

a = acceleration of object = 5 m/s²

Therefore,

85 N Cos 27° = m(5 m/s²)

m = 75.73 N/5 m/s²

m = 15.15 kg

35 milliseconds?! that is crazy fast. Another
way to write that is 0.035 seconds. If the
airbag has to inflate 1 meters. How fast does
this airbagtravel? (remember velocity =
distance/time)

Answers

Answer:

28 m/s

Explanation:

1m / 0,035 s

v = 28.57 m/s

if you want km/h, multiply witz 3,6

102,85 km/h = 28,57 m/s

So can some take some time to answer number 3 for me?

Answers

Answer:

Positive and negative

Explanation:

In order to attract to form the ionic compound, those charges are needed

E.g

Na+ (sodium)

Cl- (chloride)

Which ultimately forms NaCl (sodium chloride) which is a ionic compound

The distance from point a to point b is known as

Answers

Answer:

6

Explanation:

Answer:

Slant Hight

Explanation:

According to the Universal Law of Gravitation, every object attracts every other object in the universe. Why can’t you feel the force of attraction between you and Mars

Answers

Mars is officially frank gallagers son

Which shows the correct order of steps when using wind to generate electricity?


wind turbine blades turn generator → generator changes kinetic energy to electricity → kinetic energy from wind turns blades on wind turbine

kinetic energy from wind turns blades on wind turbine → wind turbine blades turn generator → generator changes kinetic energy to electricity

kinetic energy from wind turns blades on wind turbine → generator changes kinetic energy to electricity → wind turbine blades turn generator

wind turbine blades turn generator → kinetic energy from wind turns blades on wind turbine → generator changes kinetic energy to electricity

Answers

Answer:

kinetic energy from wind turns blades on wind turbine → wind turbine blades turn generator → generator changes kinetic energy to electricity

Explanation:

The order of steps in the energy conversion during the production of electricity from wind turbine are as follows:

1. First of all, the wind transmits its kinetic energy to the turbine blades by striking the blade.

2. The turbine blades are connected to a generator. The kinetic energy of the turbine blades is utilized to turn the generator shaft.

3. The generator then converts the kinetic energy of the blades into electricity.

Hence, the correct option is:

kinetic energy from wind turns blades on wind turbine → wind turbine blades turn generator → generator changes kinetic energy to electricity

Answer:

B

explain: edge test

A2.00 kg block is pulled across a
flat, frictionless floor with a 4.17 N
force directed 40.0° above
horizontal. What is the normal force
acting on the block?
(Hint: It is NOT = mg)
normal force (ND)

Answers

Answer:

Explanation:

R + 4.17sin(40) = mg

R = mg - 4.17sin(40)

= 2(9.8) - 4.17sin(40)

= 16.91957567

= 16.92 N

A 2.00 kg block is pulled across a flat, friction less floor with a 4.17 N force directed 40.0° above horizontal.  The normal force acting on the block  16.92 N.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Given in the question,

R + 4.17 sin(40) = mg

R = mg - 4.17 sin(40)

  = 2(9.8) - 4.17 sin(40)

  = 16.91957567

  = 16.92 N

A 2.00 kg block is pulled across a flat, friction less floor with a 4.17 N force directed 40.0° above horizontal.  The normal force acting on the block  16.92 N.

To learn more about force refer to the link:

brainly.com/question/13191643

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Giving brainiest to whoever can answer it for me with work.

Answers

Answer:

Tension in the 55 degree cable  = 110.56 N

Tension in the 28.5 degree cable = 72.16 N

Explanation:

Decompose the two tensions T1 (on left cable) and T2(on right cable) in vertical and horizontal components using trigonometric functions sine and cosine. Then balance the forces in the vertical and in the horizontal as shown below:

Horizontal components acting on net horizontal force:

T1 cos(55) =T2 cos(28.5)

then  T1 = T2 (cos(28.5) / cos(55))

Vertical components acting on net vertical force:

T1 sin(55) + T2 sin(28.5) = 125

Now replace T1 with T2 (cos(28.5) / cos(55)) in the last equation:

T2 (cos(28.5) * sin(55)/ cos(55)) + T2 * sin(28.5) = 125

T2 ( cos(28.5) * tan(55) + sin(28.5)) = 125

solving for T2 we get: 72.16 N

now we use this T2 result in the substitution equation:

T1 = T2 (cos(28.5) / cos(55))

T1 = 110.56 N

Convert acceleration due to gravity 9.8m/s2 (SI) into cm/s2 (CGS)

Answers

Answer:

980 cm/m²

Explanation:

there are 100 cm in a meter

A parachutist of total mass 70 kg is falling vertically through the air at a constant speed of 8 m s . What is the total upward force acting on the parachutist

Answers

The parachutist is falling at a constant speed, so the net force acting on them is zero. The only forces acting on the parachutist are their own weight (magnitude w, pointing downward) and the drag produced by the parachute (mag. d, pointing upward). By Newton's second law,

d - w = 0

or d = w. The parachutist's weight is

w = (70 kg) (9.80 m/s²) = 686 N

so that the total upward force is also 686 N.

Determine the Vo in the
circuit of the following
figure :​

Answers

Answer:

Vo = 4.5 [V]

Explanation:

In order to calculate this Vo voltage, we must first calculate the current through the entire circuit. For this, we perform a sum of voltages equal to zero.

ΣV = 0

[tex]-9 +6*I+2*I+3 =0\\-6+8*I=0\\I = 6/8\\I=0.75[amp][/tex]

We again perform a sum of voltages equal to zero but this time we do not include the voltage source of 3V as well as the resistance of 2[ohm]. It is as if the circuit is open between the ports of Vo.

ΣV = 0

[tex]V_{o}-9+(6*0.75) = 0\\\\V_{o} = 4.5 [V][/tex]

If someone lifts less weight than you, explain why they can be considered more powerful.

Answers

Answer:

If they lift less weight, each time then they will grow stonger.

Whereas if you lifted more weight than them, and you couldn't do it then that means they are actually stronger than you.

I hope this helps!!!!

If someone lifts less weight that is force due to gravity than you many times than they are powerful.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

If they lift less weight, each time then they will grow stonger.

Whereas if you lifted more weight than them, and you couldn't do it then that means they are actually stronger than you.

If someone lifts less weight that is force due to gravity than you many times than they are powerful.

To learn more about force refer to the link:

brainly.com/question/13191643

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Which (on average) takes the longest to orbit the sun (longest period)?
a) asteroids
b) comets
c) Earth
d) Mars

Answers

I think it’s comets since they take about 200 years on average to orbit the sun while the earth only takes a year

How that answered your question :)

Basim’s robotics team builds a robot that travels at 9 m/s and can fire a tennis ball at a target.

Which would result in a judge who is sitting beside the testing ground observing the tennis ball having a speed of 7 m/s?

The robot fires the ball forward with a speed of 7 m/s.
The robot fires the ball backward with a speed of 7 m/s.
The robot fires the ball backward with a speed of 2 m/s.
The robot fires the ball forward with a speed of 2 m/s.

Answers

Answer:

C. The robot fires the ball backward with a speed of 2 m/s.

Explanation:

The robot fires the ball backward with a speed of 2 m/s.

To find the correct statement among all the options, we need to know about the relative velocity.

What is relative velocity?

Velocity is a relative physical quantity that depends on the chosen frame of reference.

What is the mathematical formulation of relative velocity?Relative velocity=Vi-V'Where Vi is the velocity in inertial frame and V' is velocity with respect to the moving frame. Here, relative velocity=9 m/s and Vi = 7m/sSo, V'= Vi - relative velocity= 7m/s - 9 m/s = -2m/s

Thus, we can conclude that the robot fires the ball backward with a speed of 2 m/s.

Learn more about the relative velocity here:

brainly.com/question/17228388

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A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track. [04 Marks]
The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?

Answers

Answer:

Vf = 2.12 [m/s]

Explanation:

To solve this problem we must first find acceleration using Newton's second law, using mass and force.

ΣF = m*a

where:

F = force = 1.5 [N]

m = mass = 0.2 [kg]

a = acceleration [m/s²]

Now clearing a, we have:

[tex]a = F/m\\a = 1.5/0.2\\a = 7.5 [m/s^{2}][/tex]

Now we must use the following expression of kinematics, to find the final speed, we must take into account that the initial speed is equal to zero, since the car starts from zero.

[tex]v_{f}^{2} =v_{o} ^{2} +2*a*x\\v_{f} ^{2} = 0 + (2*7.5*0.3)\\v_{f} = \sqrt{4.5}\\v_{f} = 2.12 [m/s][/tex]

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