Let f(x) = (1/2)^x. Find f(2), f(0), and f(-3), and graph the function.
The calculated values of the functions are f(2) = 1/4, f(0) = 1 and f(-3) = 1/8
How to calculate the values of the functionsFrom the question, we have the following parameters that can be used in our computation:
f(x) = (1/2)ˣ
Using the above as a guide, we have the following:
f(2) = (1/2)² = 1/4
Also, we have
f(0) = (1/2)⁰ = 1
Lastly, we have
f(-3) = (1/2)⁻³ = 1/8
The graph of the function is attached
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What is 1/4 of 32? Whoever answers first gets Brainliest.
Answer:
8
Step-by-step explanation:
it is
Answer:
8
Step-by-step explanation:
1/4 of 32
1/4 = 25%
25% of 32
32 × 25 ÷ 100
= 8
or
32 ÷ 4 =8
Find the value of x to the nearest tenth.
Answer:
2.8
Step-by-step explanation:
√(4² - 2²) = √12
=> √[(√12)² - 2²] = √8 ≈ 2.8
The options are -63/16, -61/16,-59/16, -31/8, -15/4, -29/8
Answer:
-31/8. That's the answer to your question
How many solutions does the equation 3(x-5)-7=-3x8 have
Answer:
not really good at maths. 15.33
Step-by-step explanation:
3(x-5)-7=3×8
3x-15-7=24
3x =24+15+7
3x = 46
Three will divide it's self to give you one and divide 46 to give you 15.333
(correct me if i'm wrong)
The speed of a garden snail is about 8.5×10−6 miles per second. If a garden snail moves at this speed in a straight line for 2×103 seconds, how far would the snail travel in standard notation and scientific notation.
Answer:
17*10^-3 miles
Step-by-step explanation:
Given data
Speed= 8.5×10^−6 miles per second
Time taken=2×10^3 seconds
We know that the expression for the speed is given as
speed= distance/time
distance= speed* time
substitute
distance= 8.5×10^−6* 2×10^3
distance= 8.5*2*(10^-6+3)
distance= 17*10^-3 miles
Molly drew this sketch of a house. Which of the following best describes the shape
of the roof?
A Rectangle
B Trapezoid
C Parallelogram
D Rhombus
Answer:
the trapezoid .it is the only one that resembles that of a roof.hope this helped
let f(x) = x2/3 + 4x, then by the Fundamental Theorem of Calculus where F(x) = ∫f(x) then F'(x) = f(x) so we are looking for the function F whose derivative is x2/3 + 4x.
By the power rule, the function F (whose derivative is x2/3 + 4x) would have to be an x3 and an x2 function since the power rule reduces the exponent by 1. But notice that if it was just x3 and x2 then the derivative of that would be 3x2 and 2x while f(x) is x2/3 + 4x. That means F(x) must be composed of x3/9 and 2x2 so the derivative turns out right.
The Fundamental Theorem of Calculus also states that 0∫b f(x)dx = F(b) - F(0) therefore we can say 0∫b f(x)dx = (b3/9 + 2b2) - (03/9 + 2(0)2) which is just b3/9 + 2b2
By the Fundamental Theorem of Calculus where F(x) = ∫f(x) then F'(x) = f(x).
We are looking for the function F whose derivative is x^(2/3) + 4x.
By the power rule, the function F (whose derivative is x^(2/3) + 4x) would have to be an x³ and an x² function since the power rule reduces the exponent by 1.
The derivative of x^3 is 3x² and the derivative of 2x² is 4x. As F'(x) = x^(2/3) + 4x.
But notice that if it was just x^3 and x^2 then the derivative of that would be 3x² and 2x while f(x) is x^(2/3) + 4x.
That means F(x) must be composed of x^(2/3+1)/(2/3+1) and 2x^1/(1+1) so the derivative turns out right.Hence, the function F(x) = 3x^(5/3)/5 + 2x^2/2 = 3x^(5/3)/5 + x^2.
The Fundamental Theorem of Calculus also states that ∫(from 0 to b) f(x)dx = F(b) - F(0).
Therefore we can say 0∫b f(x)dx = (b^(3/9) + 2b²) - (0^(3/9) + 2(0)²) which is just b^(3/9) + 2b².
Hence, the answer is b^(3/9) + 2b².
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HELP ASAP! first one to answer gets brainliest and 15 points
No links or fake answers
5 questions attached
Answer:
1st: x-120
2nd: 0
3rd: x+12
4th: 120 + x
5th: x+12
im pretty sure that's right...?
I won't get brainliest lol
What is the value of x?
Answer:
A
Step-by-step explanation:
the total angles can only add up to 180°, therefore 35 + 70 = 105, 180 - 105 = 75°. 75° = A.
Use Cramer's vale to solve the following system of equation: J2X1 - X2-3 = 0 ./) X1 + 3X2-7= 0 3X1 + 2X2-1=0 4X1 + 5X2 = 14
Using Cramer's rule the solutions to the system of equations are:
X1 = 21 / (-J2 - 9)
X2 = -12 / (-J2 - 9)
Using Cramer's rule, we can solve the system of equations:
J2X1 - X2 - 3 = 0
X1 + 3X2 - 7 = 0
3X1 + 2X2 - 1 = 0
4X1 + 5X2 = 14
The values of X1 and X2, we'll calculate the determinants.
Let D be the determinant of the coefficient matrix:
D = |J2 -1 0| = J2(-1) - 3(3) = -J2 - 9
D1 is the determinant obtained by replacing the first column of the coefficient matrix with the constants:
D1 = |0 -1 0| = 0(-1) - (-7)(3) = 21
D2 is the determinant obtained by replacing the second column of the coefficient matrix with the constants:
D2 = |J2 0 0| = J2(0) - 3(4) = -12
Now, we can calculate the values of X1 and X2 using the determinants:
X1 = D1 / D = 21 / (-J2 - 9)
X2 = D2 / D = -12 / (-J2 - 9)
Therefore, the solutions to the system of equations are:
X1 = 21 / (-J2 - 9)
X2 = -12 / (-J2 - 9)
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IO. Write an
an equation
m=4
(0,0)
y=-
Please don’t use those link things they don’t work for me please just answer the question, brainliest for the first
You read that a nationwide survey found that the preferences for ice cream (people had to
choose ONE) are: chocolate: 31%; vanilla: 25%; strawberry: 4%; cookie dough: 17%; and "other":
23%. You live in Berryville, where growing strawberries is a major industry. You suspect that
this may affect the distribution of preferences in your area. You get a sample of 500 Berryville
residents and have them make a choice.
a. State the null hypothesis in words. b. State the alternative hypothesis in words
Answer : Null Hypothesis (H0) The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is equal to or greater than the national average of 4%.”
Alternative Hypothesis (Ha) The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is significantly lower than the national average of 4%.”
Explanation :
a. Null Hypothesis (H0) is a statement which suggests that there is no significant difference between two populations or samples in the study. In this scenario, the null hypothesis can be stated as follows:“The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is equal to or greater than the national average of 4%.”
b. Alternative Hypothesis (Ha) is a statement that counters the null hypothesis by suggesting that there is a significant difference between two populations or samples in the study. In this scenario, the alternative hypothesis can be stated as follows:“The proportion of people choosing strawberry as their preferred flavor of ice cream in Berryville is significantly lower than the national average of 4%.”
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Let X = {a, b, c) and A = {4, X, {a}, {b,c}}, Ag = {4, X, {b}, {a, c}} be two o-algebras over X. Then a. An.A, is not a o-algebra over X. b. An A, is a o-algebra over X and A, UA, is not a g-algebra over X. c. A, UA, is a o-algebra over X. d. None of the above. O O b. e. O d. a Let (X, 4) be a measurable space and let f, g: X → R be two mea- surable functions. Which of the following statements is false? a. 52 . 108>1] + \S1g
An A is a -algebra over X and A ∪ Ag is not a -algebra over X.
In this case, let's analyze the properties of the sets in question:
X = {a, b, c}
A = {4, X, {a}, {b, c}}
Ag = {4, X, {b}, {a, c}}
To determine if An A is a -algebra over X, we need to check if it satisfies the three conditions of a -algebra:
1. X ∈ An A: In this case, X = {a, b, c} ∈ An A, since X is a subset of itself.
2. An A is closed under complementation: For any set E ∈ An A, we need to ensure that its complement, X \ E, is also in An A. Let's check the sets in A:
- {4} ∈ An A: The complement is X \ {4} = {a, b, c}, which is not in An A.
- X ∈ An A: The complement is X \ X = ∅, which is in An A.
- {a} ∈ An A: The complement is X \ {a} = {b, c}, which is in An A.
- {b, c} ∈ An A: The complement is X \ {b, c} = {a}, which is in An A.
Since not all sets in A have complements in An A, An A is not closed under complementation and therefore not a -algebra over X.
Now let's analyze A ∪ Ag to determine if it is a -algebra over X:
1. X ∈ A ∪ Ag: Since X is a subset of itself, X ∈ A ∪ Ag.
2. A ∪ Ag is closed under complementation: For any set E ∈ A ∪ Ag, we need to ensure that its complement, X \ E, is also in A ∪ Ag. Let's check the sets in A and Ag:
- {4} ∈ A ∪ Ag: The complement is X \ {4} = {a, b, c}, which is in A ∪ Ag.
- X ∈ A ∪ Ag: The complement is X \ X = ∅, which is in A ∪ Ag.
- {a} ∈ A ∪ Ag: The complement is X \ {a} = {b, c}, which is in A ∪ Ag.
- {b, c} ∈ A ∪ Ag: The complement is X \ {b, c} = {a}, which is in A ∪ Ag.
Since all sets in A and Ag have complements in A ∪ Ag, A ∪ Ag is closed under complementation and is a -algebra over X.
In conclusion, option b is the correct answer: An A is a -algebra over X, and A ∪ Ag is not a -algebra over X.
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ill give brainliest
Write and solve the equation for the following situation:
Angles 1 and 2 are complementary. The measure of angle 1 is 16° larger than the measure of angle 2.
A. x + 16 = 90 x = 74
B. x + (x - 16) = 90 x = 53
C. 2x + 16 = 90 x = 37
D. x + 16 = 180 x = 164
F is a function that describes a sequence and is therefore defined over the positive
integers. Find the first four terms of the sequence.
f(n) = 100(-0.1)n-1
f(0) = -1000, f(1) = 100, f (2) = -10, f(3) = 1
f(1) = -10, f (2) = 1, f (3) = -0.1, f (4) = 0.01
f(1) = 100, f (2) = 10 f(3) = 1, f (4) = 0.1
f(1) = 100, f (2) = -10, f(3) = 1, f (4) = -0.1
Answer:
Suppose we add up alternate Fibonacci numbers, Fn-1 + Fn+1; that is, what do ... L(1)=1 and L(3)= 4 so their sum is 5 whereas F(2)=1; L(2)=3 and L(4)= 7 so their ... What is the relationship between F(n-2), and F(n+2)? You should be able to find a ... Fib(N); K (an EVEN number!), Lucas(K) and Fib(K) in each expression like ...
Step-by-step explanation:
On a coordinate plane, a triangle is located at (3, 4), and a square is located at
(10, 4). What is the distance between the square and triangle?
Answer:
7
Step-by-step explanation:
Answer:
7 units north
Step-by-step explanation:
Count from 3,4 to 10,4 and there are seven units
find Measure angle WZY QUICK PLEASE
Answer:
<WZY = 31°
Step-by-step explanation:
First, we can see that <XZW is equal to <WZY.
Given that, we know we can set the two equations equal to each other to find "x".
8x - 1 = 5x + 11
Now that the two equations are set equal to each other, all we have to do is simplify to find x.
Bring 5x over and subtract it from 8x.
3x - 1 = 11
Bring -1 over and add it to 11.
Since you're subtracting a negative, it becomes positive allowing you to add it to 11.
3x = 12
Now you need to get x by itself. Do do that, you need to divide three by itself, and whatever you do to one side, you must do to the other.
3x/3 = 12/3
Now you have:
x = 4
____________________________________________________
Now that you know the value of x, all you need to do is plug x back into the equation for <WZY
5(4) + 11
20 + 11
31.
And there is your answer - <WZY = 31°
Korey kept track of the number of miles he ran each week for five weeks. The median number of miles he ran during the five weeks was 20, and the mean was 21. Which list could show the number of miles Korey ran each of the five weeks?
Options:
A. 18, 20, 20, 22, 25
B. 20, 20, 20, 25, 25
C. 16, 19, 21, 22, 22
D. 20, 20, 21, 22, 22
Answer:
A. 18, 20, 20, 22, 25
Step-by-step explanation:
Required
Which list has a mean of 21 and median of 20
Each of the list have 5 numbers and they've all been sorted.
The median is the number at the 3rd position (i.e. the middle number)
So, list C and D are out because they do not have a median of 20.
Next, calculate the mean of lists A and B
[tex]\bar x = \frac{\sum x}{n}[/tex]
A. 18, 20, 20, 22, 25
[tex]\bar x = \frac{18 + 20 + 20 + 22 + 25}{5}[/tex]
[tex]\bar x = \frac{105}{5}[/tex]
[tex]\bar x = 21[/tex]
B. 20, 20, 20, 25, 25
[tex]\bar x = \frac{20 + 20 + 20 + 25 + 25}{5}[/tex]
[tex]\bar x = \frac{110}{5}[/tex]
[tex]\bar x = 22[/tex]
Only list A has a median value of 20 and a mean value of 21
I would love some help pls, if anyone could talk me through it, that would be phenomenal I have no clue what’s going on lol
Answer:
B) 7x - 3 = 4
Step-by-step explanation:
3x - 12 = -9
3x = 3
x = 1
A) NOPE
x - 5 = -6
x = -1
B) YES
7x - 3 = 4
7x = 7
x = 1
please help me ........
2.
Is (x+2) a factor of r + 8x + 12
Answer:
no because it is not factorable
Step-by-step explanation:
2. Including the outlier, what is the Q1, Q3, and IQR of the data set?
id
A.Q1 = 29; Q3 = 29; IQR = 2
B.Q1 = 27; Q3 = 29; IQR = 28
C.Q1 = 28; Q3 = 27; IQR = 1
D.Q1 = 27; Q3 = 29; IQR = 2
2 hot
A solid wooden cone of a diameter 14 cm and vertical length 24 cm is vertically cut into two equal halves. One half is to be covered by colourful paper at the rate of Rs. 7 per sq. cm, find the total cost of the paper required.
(The answer must come Rs. 5950)
plz anyone ASAP help.
Answer:
The answer given is incorrect
The correct answer is Rs. 3640
The total cost of the paper required to cover one-half of the wooden cone is Rs. 3846.5.
What is the surface area of a cone?The surface area of a cone is given by the formula:
surface area = π x r x s
where r is the radius of the base of the cone and s is the slant height of the cone. The slant height of the cone is the distance from the apex of the cone to the base, measured along the surface of the cone.
In this case, the diameter of the base of the cone is 14 cm, so the radius is half the diameter or 14 cm / 2 = 7 cm.
The vertical length of the cone is 24 cm, so the slant height of the cone is the square root of the vertical length squared plus the radius squared:
s = √(24² + 7²)
s = √(576 + 49)
s = √(625)
Which simplifies to:
s = 25 cm
Now that we have the radius and slant height of the cone, we can use the formula for the surface area of a cone to find the surface area of one-half of the cone:
surface area = π x 7 cm x 25 cm = 175π cm²
To find the total cost of the paper required, we need to multiply the surface area by the cost per square centimeter:
total cost = 175 x 3.14 cm² x Rs.7/cm² = Rs. 3846.5
Therefore, the cost of the paper needed to cover one-half of the wooden cone is Rs. 3846.5.
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Bayshore College staff are planning an end of the year meeting between students, parents and staff. They are to seat 5 parents, 5 students and 1 teacher in a circular arrangement around a table. In how many ways can this be done if no student is to sit next to another student and no parent is to sit next to another parent? (b) (4 pt) There are 20 student representatives who are already seated in a row of 20 seats. Out of the 20 representatives, 6 are to be chosen to give a speech. How many choices are there if no two of the chosen representatives occupy neighbouring seats?
The total number of choices for selecting 6 representatives without any two occupying neighboring seats is 77597520 .
(a) The number of ways to arrange 5 parents, 5 students, and 1 teacher in a circular arrangement around a table such that no student sits next to another student and no parent sits next to another parent, we can use the principle of inclusion-exclusion.
First, let's consider the arrangements without any restrictions. We have a total of 11 people to arrange around the table (5 parents + 5 students + 1 teacher), which can be done in (11 - 1)! = 10! ways.
Now, let's consider the arrangements where at least two students sit next to each other. We can treat the two adjacent students as a single entity, resulting in 10 entities to arrange around the table (4 parents + 5 student pairs + 1 teacher). This can be done in (10 - 1)! = 9! ways. However, within each student pair, the students can be arranged in 2! ways. Therefore, the total number of arrangements with at least two students sitting next to each other is 9! × 2! ways.
Similarly, we consider the arrangements where at least two parents sit next to each other. Again, we treat the two adjacent parents as a single entity, resulting in 10 entities to arrange around the table (4 parent pairs + 5 students + 1 teacher). This can be done in (10 - 1)! = 9! ways. Within each parent pair, the parents can be arranged in 2! ways. Therefore, the total number of arrangements with at least two parents sitting next to each other is 9! × 2! ways.
By the principle of inclusion-exclusion, the number of valid arrangements is given by
Valid arrangements = Total arrangements - Arrangements with at least two students sitting next to each other - Arrangements with at least two parents sitting next to each other
Valid arrangements = 10! - 9! × 2! - 9! × 2!
Valid arrangements = 2177280
(b) The number of choices for selecting 6 representatives out of 20, where no two chosen representatives occupy neighboring seats, we need to use a combination of counting techniques.
First, choose 6 seats out of the 20 seats in which the representatives will be seated. This can be done in C(20, 6) ways.
Now, since no two chosen representatives can occupy neighboring seats, we can think of the remaining 14 seats as dividers between the chosen representatives. We need to place these dividers in such a way that each chosen representative occupies a separate section.
To ensure that no two representatives occupy neighboring seats, we need to place the dividers such that each section contains at least one seat. We have 6 chosen representatives, so we need to place 5 dividers among the 14 remaining seats. This can be done in C(14, 5) ways.
Therefore, the total number of choices for selecting 6 representatives without any two occupying neighboring seats is given by:
Total choices = C(20, 6) × C(14, 5)
Total choices = 38760 × 2002
Total choices = 77597520
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1
Problem 1.
The force system shown is to be replaced with an equivalent system consisting of a horizontal force applied at b and a vertical force applied to the horizontal leg.
1.1. What is the magnitude of the vertical force, in Newton, applied to the horizontal leg? (rounded-off to the nearest whole number; do not write the unit)
The magnitude of the vertical force applied to the horizontal leg in the equivalent force system.
To determine the magnitude of the vertical force applied to the horizontal leg, we need to find the vertical component of the given force system. Looking at the diagram, we observe that the force system consists of a vertical force at point A and a horizontal force at point B. We can use trigonometry to find the vertical component of the force at point A.
Let's denote the magnitude of the force at point A as F_A and the angle it makes with the horizontal leg as θ. The vertical component of the force can be calculated using the formula: Vertical component = F_A * sin(θ).
Since the vertical component of the force should be equal to the force we are trying to find, we can set up the equation: Vertical component = F_vertical.
Now, we can substitute the given values into the equation and solve for F_vertical. Once we have the value, we can round it off to the nearest whole number, as instructed.
Please note that without specific values or angles provided in the problem statement or accompanying diagram, it is not possible to provide a precise numerical answer.
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A polynomial of degree 3 is multiplied by a polynomial of degree 5. What is the degree of the product?
Answer:
8
Step-by-step explanation:
The degree of a polynomial refers to the term with the highest exponent. Thus the highest exponent in a degree 3 polynomial is x3; for a degree 5 polynomial, it's x5. When you multiply
x3*x5 = x3+5 = x8.
So the product of a degree 3 polynomial and a degree 5 polynomial is a degree 8 polynomial.
Your leading term will result from the 3-degree term of the first polynomial, and the 5-degree term of the second. So you'll have something like ax3 * bx5. That will result in x3*x5=x8, so your product will have degree 8.
Catherine Destivelle was the first woman rock climber to complete a solo ascent in 1992. She is helping to design an inside rock-climbing wall on which other climbers can practice. She draws the figure
below on the coordinate grid to represent part of the wall. Each square represents one foot
Answer:
count the unit squares
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Use multiplication to explain why 3/4 ÷ 2/5 =15/8 please help me
Answer:
See below
Step-by-step explanation:
[tex] \frac{3}{4} \div \frac{2}{5} \\ \\ = \frac{3}{4} \times \frac{5}{2} \\ \\ = \frac{3 \times 5}{4 \times 2} \\ \\ = \frac{15}{8} [/tex]
Find the matrix representation of the derivative map P3(R) → P3(R), with respect to the basis {1, x, x2, x}. 21. Suppose h : P1(R) + R² is a linear transformation with the following matrix representation with respect to the bases B = {1+2, X} and D - = = {(1),(-1)} Repp,p(h) = [ [Ź 2 2 1 4 2 Find the image of the polynomial 2x – 1 under h.
After considering the given data we conclude that the matrix representation of the derivative map [tex]P_3(R) - - - > P_3(R)[/tex]with respect to the basis[tex](1, x, x^2, x)[/tex]is:
[0 1 0 0]
[0 0 2 0]
[0 0 0 3]
[0 0 0 0]
And the image of the polynomial is [tex]3 + 3x + 10x^2.[/tex]
The first part of the question asks for the matrix representation of the derivative map [tex]P_3(R) - - - > P_3(R)[/tex]with respect to the basis [tex](1, x, x^2, x)[/tex] To find this matrix, we have to apply the derivative map to each basis vector and express the result as a linear combination of the basis vectors. The coefficients of these linear combinations will form the columns of the matrix representation.
Applying the derivative map to each basis vector, we get:
[tex]d/dx(1) = 0 = 0(1) + 0(x) + 0(x^2) + 0(x^3)[/tex]
[tex]d/dx(x) = 1 = 0(1) + 1(x) + 0(x^2) + 0(x^3)[/tex]
[tex]d/dx(x^2) = 2x = 0(1) + 0(x) + 2(x^2) + 0(x^3)[/tex]
[tex]d/dx(x^3) = 3x^2 = 0(1) + 0(x) + 0(x^2) + 3(x^3)[/tex]
Therefore, the matrix representation of the derivative map [tex]P_3(R) - - - > P_3(R)[/tex]with respect to the basis [tex](1, x, x^2, x)[/tex] is:
[0 1 0 0]
[0 0 2 0]
[0 0 0 3]
[0 0 0 0]
The second part of the question concerns for the image of the polynomial 2x - 1 under the linear transformation h with matrix representation:
[0 2]
[2 1]
[4 2]
with respect to the bases B = {1+2, x} and D = {(1), (-1)}.
To evaluate the image of 2x - 1, we first need to express it as a linear combination of the basis vectors in B:
[tex]2x - 1 = (-1/2)(1+2) + (2)(x)[/tex]
Next, we need to evaluate the coordinate vector of this linear combination with respect to the basis B. The coordinate vector is:
[-1/2]
Now, we can evaluate the image of 2x - 1 under h by multiplying the matrix representation of h by the coordinate vector:
[0 2]
[2 1]
[4 2]
[-1/2]
Therefore, the image of 2x - 1 under h is [tex]3 + 3x + 10x^2.[/tex]
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