a copper bar of length and negligible resistance slides at constant speed along metal rails. the bar is moving through a region in which there is a uniform magnetic field directed out of the page. a voltmeter is connected across a resistor of resistance . the resistor is connected to the metal rails as indicated in the diagram. (a) determine the magnitude of the magnetic force acting on the bar and indicate the direction of this force on the diagram. your answer should be in terms of the given variables and known constants.

Answers

Answer 1

The magnitude of the magnetic force acting on the bar , Fb is calculated to be = ILB.

What do you understand by magnetic force?

Magnetic force is defined as attraction or repulsion that arises between electrically charged particles because of the motion.

Given length , L and negligible resistance

uniform magnetic field, B

a) To determine the magnitude of the magnetic force acting on the bar:

If rod slides down with constant velocity then total force is zero

X direction  Fb - NsinФ

= Fb = NsinФ

Y direction, mg - NcosФ

mg = NcosФ

Now, Fb/mg = sinФ / cosФ

Fb = mg tanФ

But: Fb = I L B sinФ

The magnitude of the magnetic force acting on the bar , Fb = ILB.

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Related Questions

In the playground game of tetherball, a ball tied to a rope circles a pole, wrapping the rope around the pole is it goes. Opponents compete to wrap the ball around the pole in one direction or the other; the game ends when the rope is entirely wrapped around the pole and the ball touches the pole. If you get the ball going around in one direction, as the rope shortens and the ball goes in smaller and smaller circles, the ball goes around with a shorter and shorter period.

Required:
Explain why this happens.

Answers

As the rope becomes shorter, the length of the rope is  decreased and the centripetal force decreases according causing the ball to move in smaller circles.

What is centripetal force?

The centripetal force is defined as the force that keeps an object moving in a circular path. Also, the centripetal force is equal to the tension in the rope and the tension in the rope depends on the length of the rope.

As the rope shortens, the tension in the rope decreases and the centripetal force on the ball decreases hence the ball moves in smaller and smaller circles, the ball goes around with a shorter and shorter period.

Learn more about centripetal force: https://brainly.com/question/11324711

. Monochromatic light illuminates two slits that are 0.33 mm apart. The adjacent bright lines of the interference pattern on a screen 2.30 m away from the slits are 0.44 cm apart. What is the wavelength of the light

Answers

Answer:

the wavelength of the light is 6.313 × 10⁻⁷ m

Explanation:

Given the data in the question;

for a double slit interference;

θ = nλ/d

for adjacent lines

θ = λ/d

and d = 0.33 mm = 0.00033 m

and θ = 0.44 × 10⁻² m / 2.30 m

so

λ = θ × d

λ = ( 0.44 × 10⁻² m / 2.30 m ) × 0.00033 m

λ  = 0.001913043478 × 0.00033 m

λ =  6.313 × 10⁻⁷ m

Therefore, the wavelength of the light is 6.313 × 10⁻⁷ m

A rocket weighs 1.000. N on the surface of Earth. What is its weight at a distance of two Earth radii above the
surface of Earth?
P.5B
0 111.0 N
250.0 N
333.0 N
5000 N

Answers

Answer:

0 111.0N be cause the rest do not add up

a solid sphere and a hollow sphere with equal mass are rotated about an axis through their centers. both spheres experience equal torque. which sphere will reach a speed of 10 rad/s first? Explain your answer.​

Answers

Answer:

Solid sphere

Explanation:

According to the given situation, the solid sphere would contain the less moment of inertia because it would carry large mass that closed to the axis of rotation

Also if there is a less moment of inertia so there would be high angular acceleration under a torque

α = τ/I

So the solid sphere would reach a speed of 10 rad/s first

Which one of the statements below is true about mechanical waves?

They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.

Answers

Answer:

The answer is B

Explanation:

Someone please help me...
the distance from the Earth to the sun equals 1 AU. Neptune is 30 AU from the sun. How far is Neptune from the Earth?

Answers

Answer:

1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.

Short Answer: it is 29

Explanation:

sorry if its wrong

Answer:

29

Explanation:

I just took a test! not only that but the other person who answered this question had the corrected answer.

help me besties PLEASE ;-;​

Answers

Answer:

Current in resistors = 1.5 amp

Current in resistors = 0.18 amp

P = 93.75 watts

Explanation:

Given:

1. Three 5 ohm resistor(series)

Voltage = 10 volt

2. Three 5 ohm resistor(parallel)

Voltage = 9 volt

3. Three 5 ohm resistor(series)

Voltage = 6 volt

Find:

Current in resistors

Current in resistors

Total power of circuit

Computation:

1. Total resistor (Series) R = R1 + R2 + R3

Total resistor (Series) R = 5 + 5 + 5

Total resistor (Series) R = 15 ohm

I = V/R

Current in resistors = (15)/(10)

Current in resistors = 1.5 amp

2. Total resistor (Series) R = 1/[1/R1 + 1/R2 + 1/R3

Total resistor (Series) R = 1[1/5 + 1/5 + 1/5]

Total resistor (Series) R = 1.67 ohm

I = V/R

Current in resistors = (1.67)/(9)

Current in resistors = 0.18 amp

3. Total resistor (Series) R = R1 + R2 + R3

Total resistor (Series) R = 5 + 5 + 5

Total resistor (Series) R = 15 ohm

I = V/R

I = (15)/(6)

I = 2.5 amp

P = I²(R)

P = (2.5)²(15)

P = 93.75 watts

. Estimate the buoyant force that air exerts on you. (To do this, you can estimate your volume by knowing your weight and by assuming that your weight density is a bit less than that of water.)

Answers

Answer:

[tex]0.886[/tex] N buoyant force is exerted by air

Explanation:

My weight is [tex]75[/tex] Kg

Weight = mass * gravity

As we know

Buoyant Force is equal to the product of density * acceleration due to gravity and volume of the body

Assuming weight density is a bit less than that of water or equal to water i.e [tex]997.77[/tex] kg/m3

Volume is equal to mass / density

[tex]= 75[/tex] Kg * g/[tex]997.777[/tex]

[tex]= 0.0751[/tex] * g

Buoyant Force

= Volume * g * density

[tex]= 0.0751 * 9.8 * 1.2041[/tex]kg/m3

[tex]= 0.886[/tex] N

1+1=69 how is it possible

Answers

Answer:

you add 67 to 1+1 is this clear also chicken nuggets

Answer:

i dont know

Explanation:

35 POINTSS!!! PLSSSS HELLPPP!!!
Work is the transfer of power from one object to another.


Please select the best answer from the choices provided

T
F

Answers

Answer:

T

beacuse:

Energy can be transferred from one object to another by doing work. ... When work is done, energy is transferred from the agent to the object, which results in a change in the object's motion (more specifically, a change in the object's kinetic energy).

All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguished by their frequency, what basic characteristic of the waves determines their difference

Answers

Answer:

Their different wavelengths.

Explanation:

trust me

All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguished by their frequency, the basic characteristic of the waves that determine their difference is the wavelength of the electromagnetic waves.

What is Wavelength?

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

It is the total length of the wave for which it completes one cycle.

The wavelength is inversely proportional to the frequency of the wave as from the following relation.

C = νλ

where c is the speed of light

ν is the frequency of the wave

λ is the wavelength of the wave

As we know electromagnetic waves (light waves) travel at the same speed through the vacuum of space which is the speed of light which is 3×10⁸ meter/second

All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguished by their frequency, the basic characteristic of the waves that determine their difference is the wavelength of the electromagnetic waves.

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A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m the floor is frictionless, and for the next 10.5 m the coefficient of friction is 0.17.
What is the final speed of the crate after being pulled these 20.5 meters?

Answers

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

[tex] F = ma [/tex]

[tex] a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2} [/tex]

Now, we can calculate the final speed of the crate at the end of 10.0 m:

[tex] v_{f}^{2} = v_{0}^{2} + 2ad_{1} [/tex]                  

[tex] v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s [/tex]    

For the next 10.5 meters we have frictional force:

[tex] F - F_{\mu} = ma [/tex]

[tex] F - \mu mg = ma [/tex]

So, the acceleration is:

[tex] a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2} [/tex]

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

[tex] v_{f}^{2} = v_{0}^{2} + 2ad_{2} [/tex]  

[tex] v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s [/tex]  

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.  

I hope it helps you!                              

A pulley in the shape of a solid cylinder of mass 1.50 kg and radius 0.240 m is free to rotate around a horizontal shaft along the axis of the pulley. There is friction between the pulley and this shaft. A light, nonstretching cable is wrapped around the pulley, and the free end is tied to a 2.00 kg textbook. You release the textbook from rest a distance 0.900 m above the floor. Just before the textbook hits the floor, the angular speed of the pulley is 10.0 rad/s. What is the speed of the textbook just before it hits the floor

Answers

Answer:

the speed of the textbook just before it hits the floor is 2.4 m/s

Explanation:

  Given the data in the question;

mass of pulley = 1.50 kg

radius of pulley = 0.240 m

mass of text book = 2.0 kg

height from which text book was released = 0.9 m

angular speed of the pulley = 10.0 rad/s

the speed of the textbook just before it hits the floor = ?

the speed of the textbook v = angular speed of the pulley × radius of pulley

we substitute

v = 10.0 rad/s × 0.240 m

v = 2.4 m/s

Therefore, the speed of the textbook just before it hits the floor is 2.4 m/s

A drone accelerates from rest to a speed of 300 m/s in 3 s. What is the acceleration of the drone? How far will the drone go?

Answers

Answer:

(i) 100 m/s²

(ii) 450 m

Explanation:

From the question,

Using,

(i) a = (v-u)/t................. Equation 1

Where a = acceleration of the drone, v = final velocity of the drone, u = Initial velocity of the drone, t = time.

Given: v = 300 m/s, u = 0 m/s (from rest), t = 3 s

Substitute these values into equation 1

a = (300-0)/3

a = 300/3

a = 100 m/s²

Hence the acceleration of the drone is 100 m/s²

(ii) using,

s = ut+at²/2.................... Equation 2

Where s = distance traveled by the drone.

also substitute the values above into equation 2

s = 0(3)+100(3²)/2

s = 50×9

s = 450 m

Sound wave with of frequency of 300 HZ is traveling with a wavelength of 1 m what is the speed?

Answers

Answer:

300m/s

Explanation:

f = c/λ

f = frequency

c = speed

λ = wave length

f = c/λ

300 = c/1

c = 300m/s


Cindy follows her dog around a circle having a radius of 7.40 m.
a) What distance did she travel?
b) The trip took 54 seconds. What was her speed?
c) What was the magnitude of her velocity?

Answers

Answer:

a)=46.49 m

b)=0.861 m/s

c)=0.274 m/s

Explanation:

I am quite confuse with ans C . If it is correct but I can explain .lol

A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.35 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged

Answers

Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

Using conservation of momentum,

Initial thrower has a momentum of mv; [tex]m_{total[/tex]v

(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg +  0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

A police siren of frequency fsiren is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude Ap and frequency fp. Use v for the speed of sound. Part A Find the maximum sound frequency that you would hear at a position directly above the siren. At what point in the motion of the platform is the minimum frequency heard

Answers

Answer:

he maximum frequency occurs when the denominator is minimum

 f’= f₀  [tex]\frac{343}{343 + v_s}[/tex]

Explanation:

This is a doppler effect exercise, where the sound source is moving

           f = fo [tex]\frac{v}{v-v)s}[/tex]      when the source moves towards the observer

           f ’=f_o  [tex]\frac{v}{v+v_{sy}}[/tex]  Alexandrian source of the observer

the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects

          f’= f₀  [tex]\frac{343}{343 + v_s}[/tex]

Which is true?
a) A changing magnetic field produces a constant perpendicular magnetic field.
b) A changing magnetic field produces a changing perpendicular magnetic field.
c) A changing magnetic field produces a constant parallel magnetic field.
d) A changing magnetic field produces a changing parallel magnetic field.
e) A changing magnetic field produces an electric field.

Answers

Answer:

e)  A changing magnetic field produces an electric field.

Explanation:

Ok, we start with a magnetic field and let's study how it affects the motion of a single electron. As the magnetic field changes, it will cause an electromotive force, that moves the electron, and because now we have a moving electron, now we will have an electric field. (Such that the direction of the electromotive force opposes the direction in which the magnetic field changes). This also can be deduced if we look at the third Maxwell's equation:

dE/dx = -dB/dt

This says that the spatial change in an electric field depends on how the magnetic field changes as time pass.

Then the correct option is e)  A changing magnetic field produces an electric field.

PLEASE HELP ME WITH THIS ONE QUESTION
A piston has a volume change of 7 x 10^-6 m^3. Assuming atmospheric pressure is 101,325 J, what is the work needed to change the piston volume?

Answers

Correct question:

A piston has a volume change of 7 x 10^-6 m^3. Assuming atmospheric pressure is 101,325 Pa, what is the work needed to change the piston volume?

Answer:

The work needed to change the piston volume is 0.709 J

Explanation:

Given;

volume of the piston, V = 7 x 10⁻⁶ m³

atmospheric pressure, P = 101,325 Pa

The work needed to change the piston volume is calculated as follows;

W = PV

W = (7 x 10⁻⁶ m³) x (101,325 Pa)

W = 0.709 J

Therefore, the work needed to change the piston volume is 0.709 J

Thomson observed that cathode beams can pass undeflected through crossed electric and magnetic fields. Which of the following quantities must then be common to the particles making up these beams? A. Mass B. Size C. Magnitude of charge D. Sign of charge E. Sign and magnitude of charge F. Velocity

Answers

Answer:

e must have the charge of the particle

Explanation:

In this experiment, the particles that the cathode rays are found where from an electric field and another magnetic field, for the particle to pass without deviating the magnetic force must have the same modulus of the entricar force, and be in the opposite direction.

the expression for the magnetic force is

          F_m = q v xB

the expression for the electric force is

          F_e = q E

when warning the check two formulas we must have the charge of the particle

A researcher would like to perform an experiment in a zero magnetic field, which means that the field of the earth must be canceled. Suppose the experiment is done inside a solenoid of diameter 1.0 m, length 4.6 m , with a total of 5000 turns of wire. The solenoid is oriented to produce a field that opposes and exactly cancels the 52 μT local value of the earth's field.
What current is needed in the solenoid's wires?
Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

I = 3.81 x 10⁴ A

Explanation:

The magnetic field of a solenoid must be equal to the field of earth:

[tex]Field\ of\ Earth = Field\ of\ Solenoid\\52\ T = \mu n I\\I = \frac{52}{\mu n}[/tex]

where,

I = current passing through solenoid = ?

μ = permeability of free space = 4π x 10⁻⁷ N/A²

n = no. of turns per unit length = [tex]\frac{5000\ turns}{4.6\ m}[/tex] = 1086.96 /m

Therefore,

[tex]I = \frac{52\ T}{(4\pi\ x\ 10^{-7}\ N/A^2)(1086.96\ /m)}[/tex]

I = 3.81 x 10⁴ A

Two satellites are monitored as they orbit the Earth; satellite X is eight (8) times as far from the Earth's center as is satellite Y. Using Kepler's 3rd Law, by what factor is the the period (or revolution) of satellite X that of satellite Y

Answers

Answer:

  [tex]\frac{T_x}{T_y} = 22.63[/tex]

Explanation:

Kepler's third law is an application of Newton's second law for circular motion

          T² = K a³

let's apply this expression for each satellite

satellite X

            Tₓ² = K aₓ³

satellite Y

            [tex]T_y^2 = K a_y^3[/tex]

 the relation of the periods is

          [tex]\frac{T_x}{T_y} = \sqrt{ (\frac{a_x}{a_y} )^3 }[/tex]

they indicate us

            aₓ = 8 a_y

substitutes

           [tex]\frac{T_x}{T_y} = 8^{3/2}[/tex]

           [tex]\frac{T_x}{T_y} = 22.63[/tex]

a wave travels one complete cycle in20sec and has wavelength of 1000mm.what is the speed​

Answers

Answer:

20000

Explanation:

Speed = Wavelength x Wave Frequency. In this equation, wavelength is measured in meters and frequency is measured in hertz (Hz), or number of waves per second. Therefore, wave speed is given in meters per second, which is the SI unit for speed.

How far could you walk backwards in one hour? Use your speed from the 10m test to calculate the answer. Show your work or you will not receive credit.

Answers

Answer: Sweetheart i'm not walking backward for an hour for your little assignment

Explanation: Do it yourself lazy! Have a great day!

One of the advantages of alternating current (ac) over direct current (dc) is the ease with which voltage levels can be increased or decreased.

a. True
b. False

Answers

Answer:

True

Explanation:

In an alternating current, voltage levels can be easily increased or decreased as per the requirements of the energy distribution in practical world.

Hence, the given statement is true

Let's explore the assumptions we made. Look closely at Jessie's motion as she runs. In calculating her power output, we assumed that the work she did was equal to the work done by the force of gravity on her body. Do you think that is a good assumption

Answers

Answer:

No, it is not a good assumption

Explanation:

From the given information:

The work Jessie did was quite more than the work done by the force of gravity. This is because the gravity of the force on her body is perpendicular to its motion and the work done by Jessie is due to the muscular force of her body. Hence, the total power she produced is more than the calculated amount.

3.
Two Cars, A and B, (starting, at the same time, from the same point) are moving
with average speeds of 40 km/h and 50 km/h, respectively, in the same direction.
Find how far will Car B be from Car A after 3 hours.

Answers

Answer:

car B will be 30 Km ahead of car A.

Explanation:

We'll begin by calculating the distance travelled by each car. This is illustrated below:

For car A:

Speed = 40 km/h

Time = 3 hours

Distance =?

Speed = distance / time

40 = distance / 3

Cross multiply

Distance = 40 × 3

Distance = 120 Km

For car B:

Speed = 50 km/h

Time = 3 hours

Distance =?

Speed = distance / time

50 = distance / 3

Cross multiply

Distance = 50 × 3

Distance = 150 Km

Finally, we shall determine the distance between car B an car A. This can be obtained as follow:

Distance travelled by car B (D₆) = 150 Km

Distance travelled by car A (Dₐ) = 120 Km

Distance apart =?

Distance apart = D₆ – Dₐ

Distance apart = 150 – 120

Distance apart = 30 Km

Therefore, car B will be 30 Km ahead of car A.

(20 points) You are at the center of a boat and have been rowing the boat for a long time. You weigh only 80 kg and your 120 kg buddy Bubba has been riding at the front of your 60 kg, 4 m long boat. You come to a stop in the water and then switch places. A) What is the center of mass before you switch places

Answers

Answer:

Explanation:

From the given information:

Let the first weight be [tex]m_ 1[/tex] = 80 kg

The weight of the buddy be [tex]m_2[/tex] = 120 kg

The weight of  Bubba be [tex]m_3[/tex] = 60 kg

Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:

[tex]x_1 = x_3 = \dfrac{4}{2} \\ \\ = 2[/tex]

The length of the boat be [tex]x_2[/tex] = 4 m

We can find the center of mass of the system by using the formula:

[tex]X_{CM} = \dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X_{CM} = \dfrac{(80 \times 2)+(120\times4)+(60\times2)}{80+120+60} \\ \\ X_{CM} = \dfrac{160+480+120}{260} \\ \\ \mathbf{X_{CM} = 2.923}[/tex]

3. Provide two examples of static electric charge.

Answers

Answer: 1.  walking across a carpet and touching a metal door handle            2. pulling your hat off and having your hair stand on end.

Explanation

:)

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equal treatment under the law innocent until proven guilty burden of proof rests with accuser unreasonable laws could be set aside_______. At 2 p.m., two cars leave Eagle River, WI, one headed north and one headed south. If the car headed north averages 45 mph and the car headed south averages 40 mph, when will the cars be 170 miles apart? Use the information below to determine cash flow from operations for 2016. Summary Balance Sheet Information 2016 2015 Cash $300 Summary Balance Sheet Information 2016 2015 Cash $300 $.2.40 Accounts receivable 200 180 Inventory 120 240 Prepaid insurance 90 120 Plant and equipment 600 510 Accumulated depreciation (240) (180) Accounts payable $380 $. 3.00 Bonds payable 150 120 Common stock 420 420 Retained earnings 120 270 Summary Income Statement Information Revenue $ 3., 300 COGS (1.000) Gross Profit 2, 300 Depreciation Expense (120) Rent Expense (800) Salary Expense (870) Income from Operations 510 Gain on Sale 30 Net Income $ 540 Cash Flow from Operations for 2016 is: A. $ 660 B. $ 540 C. $ 840 D. $810 E. none of the above What are the 5 main types in the chart of accounts? What is the difference between atherosclerosis and multiple sclerosis? Hubble's law expresses a relationship between __________. who of the following can overrule a traffic signal? a. crossing guard b. police officer c. state trooper d. all of the above(1 point) Describe three major environmental challenges facing Oceania. each year, team marketing report (tmr) publishes its fan cost index (fci). the fci measures ______. What z-score is 3 standard deviations? How do I get a Selective Service exemption letter? What is the purpose of the Bill of Rights according to the preamble? What is y 2x 5 on a graph? A reduction in government borrowing can:Question 19 options:a)decrease the incentive to invest.b)increase the interest rate.c)crowd out private investment in human capital.d)give private investment an opportunity to expand.If the state of Washington's government collects $75 billion in tax revenues in 2013 and total spending in the same year is $74.8 billion, the result will be a:Question 20 options:a)budget deficit.b)budget surplus.c)decrease in payroll tax.d)decrease in proportional taxes. body images of women please under what style would a room interior have softened architectural lines, sinuous curves, decorative stucco and walls, often pastel, that melt into the ceiling or vault? Simplify (m^4n)^3. m^12n^3 m^4n^3 m^12n mn^15 What is the volume of this cylinder?Use3.14 and round your answer to the nearest hundredth.6 in2 incubic inches How did the Civil War affect American society ? Where do candidates get the funds to pay for their campaigns?