A car of mass 900kg starting from rest has a constant acceleration of 3.5m/s² . calculate it's momentum after it has travelled a distance of 40m​

According to the question the tensile stress of circular rod is 3142.85M Pa

The minimum tensile stress (force per unit area) required to break the material is how it is represented. The material has a tensile strength of 1,000 pounds of force, for instance, if a metal rod with a cross - sections of one square inch can bear a pulling force of 1,000 pounds but snaps with further pressure.

Briefing:

Tensile stress = Tensile load /Cross section area

Given load = 100kn = 100*10^3 = 10^5N

Area = 100πmm^2

Tensile Stress = 3142.85M Pa

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The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.

Kinetic energy is the energy of a body in motion.

To calculate the kinetic energy of the cell phone, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the Kinetic energy of the cell phone is 9 J.

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The magnitude of the net electric field at the center of the square is

5.38799 x 10^4 N/C.

An electric field is described as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

Qa = Charge at point

A = −2.4× 10 −12C

Qb = Charge at point

B = 2.4 × 10 −12C

Qc = Charge at point

C = 2.4×10−12C

Q = Charge at point

D = 2.4 ×10−12C

a= side of the square = 4cm = 0.04 m

Ea = magnitude of the electric field at center of the square due to charge

QAEb

= magnitude of the electric field at center of the square due to charge

QBEc

= magnitude of the electric field at center of the square due to charge

QCEd

= magnitude of the electric field at center of the square due to charge

QDE x = Net electric field in X-axis.

Ey

= Net electric field in Y-axis

Magnitude of electric field at distance R due to a charge q = kx q/R^2

Where k = 8.98 X 10^9

Magnitude of net electric field in X-axis is

Ex = Ea×cos45 + Ec × cos45 +Eb × cos45 − Ed × cos45

Ex =

3.80989 × 10^4 N/C (If you substitute values)

Magnitude of net electric field in Y-axis is

Ex = Ea× Sin45 + Ec × Sin45 +Eb × Sin45 − Ed × Sin45

Ex =  5.38799 × 10^4 N/C

Therefore, the magnitude of the net electric field at the center of the square is

5.38799 x 10^4 N/C.

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Despite being only 38 billion kilometers (24 billion miles) big, that black hole contains a mass equivalent to six and a half billion Suns. It was the first black hole that had been directly pictured.

We need to know the black hole's mass, brightness, and energy-radiation timescale in order to calculate the total energy emitted by the accretion disk during the course of its existence. Using Einstein's equation for general relativity, we can determine the black hole's mass.

Then, using the Stefan-Boltzmann formula, we may utilize that knowledge to determine the luminosity of the accretion disk. Finally, we may utilize that knowledge to determine how long it will emit energy given its luminosity. The entire energy emitted by the accretion disk throughout the black hole's existence comes from the mass-energy that passes through it. The accretion disk's brightness is W/m2, on average.

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The tangential acceleration and length of chain of rocket is 0.5708 and 9.4m respectively.

Initial angular velocity, w = 65rpm = 65(rad/s = 6.594rad/s

Final angular velocity, w = 91rpm = 91(rad/s = 9.734rad/s

time taken, t= 11s

Then let total radians covered in this much time be 0 and angular acceleration be a, using equations of motion.

a). 9.734 6.59  and 0.2854rad/s

= (9.734)(6.594) +2(0.2854)/3

A=0.5708

b).Then radius of sprocket R= diameter/2= (25/2)cm E =12.5cm

Then length of chain passes over the top of sprocket in this intervalis

r= (0-12.5m)(89/ 821)

r=9.4m

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The box gains potential energy as it travels  between points 3 and 4 according to the figure.

The energy held within an object is known as potential energy. There are several different types of potential energy, including gravitational potential energy, elastic potential energy, and electric potential energy.

Here, the energy that an object possesses as a result of its position in relation to other objects is referred to as its gravitational potential energy.

When the box travels from point 3 to point 4, its height increases, that's why, the box gains potential energy as it travels between points 3 and 4.

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Answer:

5×10-5 farads

Explanation:

Indications:

Q = charge

I = Current

t = Time

C = Capacitance

V = Voltage

Now, we know, Q = IT = 2×10^-5 ×30 = 6×10^-4 C

again, we know, Q = VC

⇒ C = Q/V = 6×10^-4/12 = 5×10^-5 Farads

The paddle will experience a force from the water equal to the product of the water pressure and the paddle's surface area.

what is pressure ?

Pressure (symbol: p or P) is the force applied perpendicular to the surface of an object per unit area across which that force is distribute  Gauge pressure (sometimes called gauge pressure)[a] is the pressure relative to the ambient pressure.

Various units are used to express pressure. Some of these are derived from dividing a unit of force by a unit of area; for example, the SI unit of pressure, the pascal (Pa), is one newton per square metre (N/m2); similarly, the pound-force per square inch (psi) is the conventional unit of pressure in the imperial and US customary systems. Pressure can also be stated in terms of normal atmospheric pressure; this pressure equals the atmosphere (atm).

The paddle will experience a force from the water equal to the product of the water pressure and the paddle's surface area. Any more power will only go to raise the speed of the paddle. Because of this, more water may be forced into a smaller space.

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Answer: The answer is ture

Explanation: Newtons third law which says

The primary cause of the decision-making and construction process delays is a lack of knowledge. Never criticize a teammate in front of other teammates or the manager when giving them constructive criticism.

A great deal is that more information is required to portray the current structure, its background, and its make-up. They can go get another dam consulting engineer if it is too much trouble for them or if they don't like it.

However, there are a few things that are quite challenging to adhere to:

The absence of information in the query is what makes all of these challenges difficult. Thus, it is clear that the main cause of the decision-making and construction process delays is a lack of knowledge.

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The temperature of hydrogen molecules with a molar mass of 2.016 g/mol in a certain gas have an rms speed of 390 m/s in kelvins is 3.01K.

The RMS speed of gas molecules is the measure of the speed of the particles in a gas. It is the average squared velocity of molecules in a gas.

The formula for rms speed as follows
Vrms = √3*K*T / m

where

K = Boltzmann constant

T = temperature

m = mass of the gas molecules

to find T, the formula can be rearranged like this

T = m*v²rms / 3k

Now, let's find the mass of hydrogen molecules

m = molecular weight / avogadro's number

molecular weight = 2.016 g/mol

avogadro's number = 6.022 * 10^23

m = (2.016 g/mol / 6.022 * 10^23) * 10^-3 kg / mol

= 3.347 * 10^-27 kg

Next, we want to find the temperature of this gas.

T = m* v²rms / 3k

m = 3.347 * 10^-27 kg

k = 1.38 * 10^-23 J/K

Vrms = 390 m/s

T = (3.347 * 10^-27 kg) * (390 m/s)² / 3 * (1.38 * 10^-23 J/K)

= 12.3K (rounded)

Therefore, the temperature of this gas is 12.3Kelvins.

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Answer:

The answer is S

Explanation:

Amplitude is defined as the height of a wave from its undisturbed level.

An exposed wiring system for indoor wet locations where walls are frequently washed must be mounted so that there is at least 6 mm (1/4 in.) air gap between the mounting surface and electrical equipment.

This is to prevent water from entering the electrical equipment and causing an electrical shock. Since, the air gap provides a barrier between the wet walls and the electrical equipment and helps prevent shocks from occurring.

Is a collection of cables and associated hardware used to provide physical connectivity between two or more systems. It is also used to carry signals between computers and other network devices such as printers and modems. The cabling systems include:

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The length of the pendulum is 0.910m if acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex] and it takes 24 s to go 14 cycles.

First we will calculate Time period of pendulum

T = no of oscillations/ time

= 14/24

= 0.5833

We can find length of pendulum using formula

L=g(T/2π)^2

= 9.8(0.583/2×3.14

=9.8(0.583/6.28)

= 0.910 m

A simple pendulum is an arrangement of oscillating bob that has periodic motion. The simple pendulum has a small bob of mass ‘m’ suspended by a thin string fixed to a platform and length of string is L.

The time taken to complete one oscillation is defined as the time period of the pendulum. For simple pendulum of length L , time period is T = 2π √R/2g.

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The acceleration of gravity in the new planet is 0.41 m/s^2.

What is gravitational acceleration?

Gravitational acceleration is the acceleration that an object experiences due to the force of gravity. It is the rate at which an object's velocity changes as it falls toward the center of a gravitational field, such as the Earth or another planet.

The magnitude of gravitational acceleration is often denoted by the symbol "g," and it is equal to the acceleration an object would experience if it were dropped from rest at the surface of the Earth. On the surface of the Earth, g is approximately 9.8 meters per second squared or 1 g. However, the value of g can vary slightly depending on the location and the strength of the gravitational field. For example, g is slightly weaker at the Earth's poles than it is at the equator due to the Earth's slightly oblate shape.

According to the problem:

The acceleration due to gravity on the planet can be determined by the equation:

acceleration = (distance fallen) / (time taken)^2

Substitute 4.07 meters for the distance and 4.97 seconds for the time to determine the acceleration as the following:

acceleration = (4.07 meters) / (4.97 seconds)^2 = 0.41 m/s^2

So the acceleration of gravity on this planet is approximately 0.41 meters per second squared.

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Answer:

bro what is this

The vehicle's last speed if −3.00 MJ of work was finished by the brakes will be 398.45 km each hour.

What is the conservation of energy?

According to the principle of conservation of mass, energy cannot be gained or lost; it can only be converted from one form of energy to another. This indicates that only if energy is introduced from outside, a unit always uses the same quantity of energy.

In 1979, Dr. Hans Liebold of Germany drove a race vehicle 12.6 km with a typical speed of 404 km/h. Assume Liebold applied the brakes to decrease his speed. Expect the consolidated mass of the vehicle and driver to be 1.00 and 103 kg.

The final speed is given as,

1/2 x m [(v₂)² - (v₁)²] = 3 x 10⁶

1/2 x (1 + 103) x [(v₂)² - (404 x 18/5)²] = 3 x 10⁶

(v₂)² = 2057687.06

v₂ = 1,434.43 m/s

v₂ = 398.45 km per hour

The vehicle's last speed if −3.00 MJ of work was finished by the brakes will be 398.45 km each hour.

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The body mass index (BMI) is a measurement based on a person's mass (weight) and height.

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The time interval required for the proton to travel 4.50 cm horizontally is  1.07 x 10⁻⁷ s , vertical displacement during the time interval in which it travels 4.50 cm horizontallyis  0.0043 m, and the horizontal and vertical components of its velocity after it has traveled 4.50 cm horizontally_ j km/s.

a. Let t be the amount of time needed for a proton to move 4.50 cm 0.045 m horizontally. It is calculable as follows:

t = d/v

where t is time, d is distance and v is velocity

t= d/v

t = 0.045m / 4.20 x 10⁵ m/s = 1.07 x 10⁻⁷ s

b. because the initial speed in the vertical direction is 0. So,

Thus, q E = ma.

ay= (Ey q)/m

Displacement is given by :

y=ut + 1/2ayt²

y =1/2 ((Ey q)/m) t²

y =(1/2)(7.60 x 10³ N/C x 1.67 x 10⁻¹⁹)(1.07 x 10⁻⁷)²

y= 0.0043 m

c.Use the following kinematics equation for the vertical component of velocity:

V(y)²-u²= 2ayd

[tex]v_y=\sqrt{\frac{E_{y}q}{m}d_{y} } \\v_y=\sqrt{\frac{7.60 X 10^3 N/C _{} X 1.67 x 10^{-19}}{ 1.67 x 10^{-27}} 0.045[/tex]

v=1.8493 X10⁵ m/s

velocity horizontal component,

vₓ =d/t

vₓ= 0.045/( 1.07 x 10⁻⁷ s) = 4.20 x10⁵

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when the temperature is kept constant, to increase the volume of the gas, you will decrease the pressure (Option D)

The volume of a gas at constant temperature is explained by the Boyle's law equation which is states as follow:

The volume of a fixed mass of gas is inversely proportional to the pressure at conctant temperature. Mathematically, it is expressed as follow:

P ∝ = 1/V

P = K / V

P₁V₁ = P₂V₂

Where

From the above formula, we can see that volume and pressure exist in inverse proportionality. This means that when the volume increases, the pressure will decrease and also, when the volume decreases, the presure will increase.

With the above information, we can conclude that the correct answer to the question is: You would decrease the pressure (Option D)

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The increase in the kinetic energy was found to be 300000 J

define kinetic energy ?

The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort while slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that contains a derivative with respect to time in the Lagrangian of a system.

kinetic energy was mentioned as ⇒1/2(m)v^2

kinetic energy =1/2(m)v^2

=1/2x2000x(10)^2

=100000 J

=1/2(m)v^2

=1/2x2000x(20)^2

=400000 J

therefore the increase in the kinetic energy was 400000-100000=300000 J

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(a) T = 4.12 cm.

(b) T ∝ [tex]\sqrt{m}[/tex], time period doesn't depends on velocity. Thus, a pendulum clock wouldn't work.

(c) A = 0.0795 m

Pendulum clocks were the main timekeeping devices used in 18th and 19th-century houses, industries, offices, and train stations for scheduling daily activities, shifts at work, and public transit. Their increased precision enabled the quicker pace of living required for the Industrial Revolution.

(a)

[tex]g_m[/tex] = 1.625 m/sec²

T = 1 sec

T = 2Π × [tex]\sqrt{l/g}[/tex]

or, T = 2Π × [tex]\sqrt{l/1.625}[/tex]

or, T = 1.625 × [4 × (3.19)²]

or, T = 0.0412 m

or, T = 4.12 cm.

(b)

T ∝ [tex]\sqrt{l}[/tex]     and T = 2Π × [tex]\sqrt{m/k}[/tex]

or, T ∝ [tex]\sqrt{1/g}[/tex]  then, T ∝ [tex]\sqrt{m}[/tex]

So, time period doesn't depends on velocity. Thus, a pendulum clock wouldn't work.

(c)

m = 655 gm = 0.655 kg

V(max) = 0.5 m/sec

T = 1 sec

A = ?

V(max) = A × ω

or, V(max) = A ×  (2Π/T)

or, 0.5 = A ×  (2Π/ 1)

or, A = 0.0795 m

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Speed is the rate of motion, and velocity contains a direction of the rate of motion, so the blank space is filled by "direction".

When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.

Speed is only given the magnitude of the rate of motion, while velocity is given the direction of the rate of motion,

Therefore, Speed is the rate of motion, and velocity contains a direction of the rate of motion.

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The wavelength of the electron, given that it is travelling at 1.0×10⁷ m/s is higher than that of the ball travelleing at 35 m/s

To compare the wavelength of both the electron and ball, we shall determin the the wavelength of both the electron and ball. Details below:

For electron:

λ = 2h / mv

λ = (2 × 6.626×10⁻³⁴) / (9.1×10⁻³¹ × 1.0×10⁷)

λ = 1.46×10⁻¹⁰ m

For ball:

λ = 2h / mv

λ = (2 × 6.626×10⁻³⁴) / (0.10 × 35)

λ = 3.79×10⁻³⁴ m

From the above calculation we obtained:

Thus, we can conclude that the the wavelength of the electron is higher than that of the ball.

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Answer: Omitting g for weigh because problem omits g

Taking torque about left sawhorse

Mr * 6 = 3 * 10.5 + 4.45 * 1.8 = 31.5 + 8.0 = 39.5

Mr = 39.5 / 6 = 6.60       mass exerted upward by right sawhorse

6.6 + Ml = 10.5 + 4.45      balancing upward and downward mass

Ml = 8.4 kg        upward force (kg) exerted by left sawhorse

Check: take torque about right end

8.4 *  6 = 3 * 10.5 + 4.45 * 4.2

50.4 = 31.5 + 18.7  = 50.2       balances within rounding error

The upward force that the left sawhorse exerts on the board is 164 N.

Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.

Here,

Mass of the board, m₁ = 10.5 kg

Length of the board, L = 6 m

Torque of the board, τ₁ = m₁g x r₁

    τ₁ = 10.5 x 9.8 x (6/2)

    τ₁ = 308.7 Nm

Mass of the saw, m₂ = 4.45 kg

Length of the saw, r₂ = 6 - 1.8 = 4.2 m

Torque of the saw, τ₂ = m₂g x r₂

    τ₂ = 4.45 x 9.8 x 4.2

    τ₂ = 183.2 Nm

So,

Torque on the left saw = Torque on the board + torque on the saw

τ' = 308.7 + 183.2

τ' = 491.9

Therefore force exerted by the left saw, F = τ'/(L/2) = 491.9/3

  F = 164 N

Hence,

The upward force that the left sawhorse exerts on the board is 164 N.

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The  length of X components is 3,708 and Y component is 11,412

Another method for locating vector components is to use the angle measured in the opposite direction from the +x axis. Then, the x-component will always be cos and the y-component will always be sin.

A vector's rectangular component Ax, Ay, and Az, respectively, are the projections of vector A along the x, y, and z directions. Space coordinates of a point: The triplet (x, y, z) denotes a point's coordinates.

Given ,

x-component

= 12 * cos 72

= 12 * 0,3090

= 3,708

y component

= 12 . sin 75

= 12 . 0,9510

= 11,412

Therefore The  length of X components is 3,708 and Y component is 11,412

The complete question is : What are the lengths of the x and y components of this vector?

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Electrical stimulation of the brain (ESB) is used on humans during the brain surgery used to map out the brain and critical structures.

Surgical operation is a medical distinctiveness that makes use of operative manual and instrumental techniques on a person to research or deal with a pathological circumstance together with a disorder or damage, to help improve physical characteristics, and appearance, or to repair undesirable ruptured areas.

A patient may additionally have surgical treatment to in addition discover the situation for the motive of prognosis. cast off or repair diseased tissues or organs.

Sushruta is the father of surgical operations. If the history of science is traced back to its origin, it likely starts from an unmarked technology of ancient instances.

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As the object moves from point A to B, the kinetic energy of the object decreases and the mechanical energy of the object increases.

In this problem, the law of energy conservation is applied. It is given that the work done by conservative force is -70J and the work done by non-conservative force is 50J.

The resulting forces between these two forces is -70J + 50J = -20 J.

The conservative force is linked with the movement caused by the sum of two energies, therefore there is a decrease in kinetic energy. The increase in mechanical energy is due to the positive non-conservative force.

Thus, the correct answer is kinetic energy of the object decreases and the mechanical energy increases.

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The work done by the crane in lifting the crate is calculated to be 100 KJ.

Energy is transferred as a gain in the object's gravitational potential energy when work is done to increase the height of the item. Potential energy refers to the work that an object does as a result of its height. An object with mass m at a height h has a gravitational potential energy PE, which is given by the relationship:

PE = m × g × h

where,

m = mass of the object

g = gravitational force acting upon the object

h = height of the object at which it is lifted

Now, it is given that,

Force provided by the crane = mg = 5 KN = 5000 N           (∵ 1kN = 1000N)

Height = 20 m

On substituting the given values in the above relation, we get:

PE = 5000N × 20m

PE = 100000 Joules or 100 kilo Joules

Hence, the work done by the crane in lifting a crate upwards is found to be 100 KJ in the form of potential energy.

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Height h = 20 m and force F = 5 kN are provided.

To Discover: Work Done, W

Work Done, as we are all aware, is the result of force and displacement. Here, we must compute the work performed by the crane in opposition to gravity.

Where,

W = mgh

The mass is m.

Gravitational acceleration, or g,

h is the height the item has gained.

mg = 5 kN for force.

1 kN = 1000 N

As a result, 5 kN equals 5*1000 N.

Replace with the value we obtain

→ W = 5000 × 20

→ W = 100000 J

→ W = 100000/1000 Kj

→ W = 100Kj

As a result, the crane's labour to raise the cargo was 100 KiloJoules.

According to work energy theorem Word Done = Energy Used

Thus, 100KJ is the required amount of Kinetic Energy required by the Crane.

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The equilibrium position from the above was the position only at the C.

define equilibrium ?

1. A situation when all acting effects are neutralised by other factors, leaving a system that is stable, balanced, or unchanging.

2. Emotional or mental equilibrium.

3. Physics The state of a body or physical system when it is at rest or moving slowly, during which all forces acting on it result in zero and all torques about all axes add up to zero.

4. Chemistry a. A chemical reaction in which both the forward and reverse reactions proceed at the same rate, preventing a change in the concentration of the reactants and products over time.

b. The condition of a system in which there are several phases and interchange between them happens at equal rates, resulting in a net loss of energy.

The sole position at the C was the equilibrium position from the above.

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The work done by the gas is 405.2 J.

The work done by the gas at the constant pressure is calculated by applying the following equation.

W = PΔV

W = P ( V₂ - V₁)

Where;

The given parameters include the following;

final volume of the gas = 5 L

initial volume of the gas = 3 L

constant pressure of the gas = 2 atm

The work done by the gas is calculated as follows;

W = 2 atm ( 5 L - 3 L )

W = 4 atm.L

1 atm.L = 101.3 J

4 atm.L = ?

= 405.2 J

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