How old was Antoine Lavoisier's wife when they married
jsjshebsjsusunxndj 78
how would the acceleration of an object change if you doubled (2x) the force and quadrupled (4x) the mass
a. acceleration remains the same
b. acceleration would be twice as much
c. acceleration would be half as much
d. acceleration would be one-fourth as much
Answer:
acceleration will be twice as much
When liquid water gets into cracks of rock and freezes, it _____ and ______.
A contracts, splits apart the rock
B contracts, washes aways pieces of rock
C expands, splits apart the rock
D expands, washes away pieces of rock
Answer: it eventually cracks the rock and breaks pieces of the rock off
Explanation:
If 1 kg = 2.2046 Ib, how many pounds equal 5.0 kilograms?
A)What is the acceleration at 1 second?
Answer in units of m/s 2.
B) What is the velocity at 2 seconds?
Answer in units of m/s.
C) What is the position at 2 seconds?
Answer in units of m
If an area has limited types of wildlife, this means that it has __________. A. animals that are about to go extinct B. animals that have adapted well to their environments C. a wide variety of animals D. very few varieties of animals Please select the best answer from the choices provided A B C D
Answer:
It is d
Explanation:
Answer:
D !!!!!
Explanation:
help me please ( im past my limit for getting answers for today :/)
A cow is eating green grass that grows in a field.
Which type of organism is the grass in this scenario?
consumer
decomposer
prey
producer
Answer:
producer
Explanation:
grass is producing
by photosynthesis
n the diagram, the arrow shows the movement of electric charges through a wire connected to a battery.
A battery with an arrow at its top running from left to right. A black line connects the right end of the battery to the left end by making a series of straight lines to form a rectangular box with the battery as part of the bottom side.
What causes the electric charges to flow from one end of the battery to the other?
a balance in electric potential
a balance in resistance
a difference in electric potential
a difference in resistance
Answer:
D. A difference in resistance
How long does it take for light to travel 1m? and a 1mm?
Answer:
Hi. U should do like this
Answer:
3.335641 nanoseconds for meters
A girl throws a pebble into a deep well at 4.0 m/s (downward). It hits the water in 2.0 s. How far below the ground is the water's surface? What is the pebble's average velocity?
Answer:
27.6 m13.8 m/sExplanation:
(b) The initial velocity is added to that due to acceleration by gravity. The velocity is increased linearly by gravity at the rate of 9.8 m/s². The average velocity of the pebble will be its velocity halfway through the 2-second time period.* That is, it will be ...
4 m/s + (9.8 m/s²)(2 s)/2 = 13.8 m/s . . . . average velocity
__
(a) The distance covered in 2 seconds at an average velocity of 13.8 m/s is ...
d = vt
d = (13.8 m/s)(2 s) = 27.6 m
The water is about 27.6 m below ground.
_____
* We have chosen to make use of the fact that the velocity curve is linear, so the average velocity is half the sum of initial and final velocities:
vAvg = (vInit + vFinal)/2 = (vInit + (vInit +at))/2 = vInit +at/2
__
If you work this in a straightforward way, you would find distance as the integral of velocity, then find average velocity from the distance and time.
[tex]\displaystyle d=\int_0^t{(v_0+at)}\,dt=v_0t+\dfrac{1}{2}at^2=t\left(v_0+a\dfrac{t}{2}\right)\\\\v_{avg}=\dfrac{d}{t}=v_0+a\dfrac{t}{2}\qquad\text{the formula we started with}[/tex]
The force F⃗ pulling the string is constant; therefore the magnitude of the angular acceleration α of the wheel is constant for this configuration. Find the magnitude of the angular velocity ω of the wheel when the string has been pulled a distance d. Note that there are two ways to find an expression for ω; these expressions look very different but are equivalent.
Answer:
The answer is "[tex]\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}[/tex]"
Explanation:
[tex]\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}[/tex]
The angular velocity of the wheel is [tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]
Angular Velocity :Given that the force applied is F, and the displacement of the string is d.
If the radius of the wheel is r and the wheel has an angular displacement of θ, then:
d = rθ
θ = d/r
now, the angular acceleration is given by:
α = F/mkr
The initial angular velocity will be zero and let the final angular velocity is ω.
According to the third equation of motion:
ω² = 0 + 2αθ
ω² = 2(F/mkr)(d/r)
[tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]
Learn more about angular velocity:
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A skydiver, with a mass of 60 kg is falling at a velocity of 30 m/s. Calculate his kinetic energy.
Answer:
27000 J
Explanation:
in number one is Mirna is pregnant and must consult a medical professional, What kind of doctor should she seek?
guys plss help me
plss answers all i needed the answer
Wonderwoman, from rest, runs until reaching m her flight takeoff speed of 15 to the west. A S graph of her acceleration over time is shown below, where eastward is the positive acceleration direction. Which graph shows her velocity over time?
Answer:it’s the graph starts on the origin but is going down
Explanation: khan academy
A car moving at a speed of 20m/s has a kinetic energy of 300,000 J what’s the cars mass
Answer:
1500 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{2k}{ {v}^{2} } \\ [/tex]
From the question we have
[tex]m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ [/tex]
We have the final answer as
1500 kgHope this helps you
Jill is pulling a 200. Newton sled through the snow at constant velocity using a horizontal force of 10. Newtons. What is the kinetic coefficient of friction of the sled on the snow?
Answer:
The kinetic coefficient of friction of the sled on the snow is 0.05
Explanation:
The given parameters are;
The weight of the sled Jill is pulling, W = 200 N
The force with which Jill is pulling the the sled = 10 Newtons
The nature of the speed with which the sled is pulled = Constant speed
Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;
The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction, [tex]F_k[/tex]
The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow, [tex]\mu _k[/tex]
[tex]F_k[/tex] = W × [tex]\mu _k[/tex]
[tex]\mu _k[/tex] = [tex]F_k[/tex]/W = 10 N/(200 N) = 0.05
The kinetic coefficient of friction of the sled on the snow = [tex]\mu _k[/tex] = 0.05.
Which of the following statements does NOT apply to Newton’s second Law of Motion? *
5 points
a. The more mass something has, the more force it would take to accelerate it.
b. The more force applied to an object’s mass, the more it will accelerate.
c. The force required to accelerate an object equals the objects mass times it’s acceleration.
d. Objects of the same size will accelerate equally if they have different forces applied to them.
Answer:
d
Explanation:
it is never stated in science
Objects of the same size will accelerate equally if they have different forces applied to them. This statement (D) does NOT apply to Newton’s second Law of Motion.
What is Newton's second Law of Motion?Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
As momentum is product of mass and velocity, the more mass something has, the more force it would take to accelerate it. So option (A) is correct.
As rate of change of momentum of a body refers product of mass and acceleration of a body, the more force applied to an object’s mass, the more it will accelerate and the force required to accelerate an object equals the objects mass times it’s acceleration. So, option (B) and (C) is correct.
But force has no direct elation with size of the body. So, option (D) is not correct.
Learn more about Newton's second law of motion here:
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What is the angular displacement (in radians) of a person standing at the Earth's equator for 6 hours assuming the Earth has a diameter of 13750 km
Answer:
π/2 radians.
Explanation:
Angular Displacement
It's the angle expressed in radians, degrees, revolutions, etc. through which a point revolves around a point called the center.
To find the angular displacement, we must recall a full revolution, or turn around the center measures 360 degrees, or 2π radians.
The Earth completes a turn every 24 hours. This means that in 6 hours, it has given 6/24 = 1/4 of a turn.
This means that, measured in radians, the angular displacement of a person during 6 hours is:
1/4*2π radians
Simplifying:
π/2 radians.
Jessica does not like how her BestFriend has been treating her around others. When confronted, the friend says Jessica is being emotional. Which beat describes the relationship between Jessica’s emotional and mental health
A pinball bangs against a bumper giving the ball a speed of 42cm/s if the ball has a mass of 50.0g what is the ball’s kinetic energy in joules
Explanation:
Given:-mass=50g
velocity=42cm/s
To find:-Kinetic energy
Solution:-As we know that
[tex]{\boxed{\sf kinetic\:energy={\dfrac {1}{2}}mv^2}}[/tex]
Substitute the values[tex]{:}\longrightarrow[/tex][tex]\sf k.v={\dfrac {1}{{\cancel{2}}}}\times 50\times {\cancel{42}}^2 [/tex]
[tex]{:}\longrightarrow[/tex][tex]\sf k.v=50\times 21^2 [/tex]
[tex]{:}\longrightarrow[/tex][tex]\sf k.v=50×441 [/tex]
[tex]{:}\longrightarrow[/tex][tex]\sf k.v=22050MJ [/tex]
1Joule=1000milijoules22050MJ=[tex]{\dfrac {22050}{1000}}=22.05J[/tex]=22J(Approximately)[tex]\therefore[/tex][tex]{\underline{\boxed{\bf Kinetic\:energy=22Joule}}}[/tex]
Find the force of gravity between a cubic meter of water (1000kg) and the Sun. The Sun's mass is 1.99 x10^30 kg and is 1.50 x10^11 m away.
A) 17.0 N
B) 5.90 N
C) 2.0 N
D) 47.20 N
Answer:
F = 5.9 N
Explanation:
Given that,
Mass of water, m₁ = 1000 kg
Mass of the Sun, [tex]m_2=1.99\times 10^{30}\ kg[/tex]
Distance between two bodies, [tex]r=1.5\times 10^{11}\ m[/tex]
We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N[/tex]
or
F = 5.9 N
Hence, the correct option is (b).
Which would be least likely to completely dissolve in water?
o hydrochloric acid
sulfuric acid
O nitric acid
O acetic acid
Answer:
nitric acid
Explanation:
because it is a solvent
Answer:
acetic acid
Explanation:
Not sure but I think so :) hope its right and helps
The average acceleration is the ratio of which of the following quantities?
A 10-kg wagon is pulled by a force of 70 Newtons while friction provides 20 Newtons of force. How much acceleration will the wagon have?
Answer:
5m/s²
Explanation:
Given parameters:
Mass of wagon = 10kg
Force of pull = 70N
Frictional force = 20N
Unknown:
Acceleration of the wagon = ?
Solution:
Frictional force is a force that opposes motion.
The net force is given as:
Net force = mass x acceleration
Force of pull - Frictional force = mass x acceleration
Insert the parameters and solve;
70 - 20 = 10 x acceleration
50 = 10 x acceleration
Acceleration = 5m/s²
You turn on a light in a room to read a book. Not all the energy from the lightbulb becomes light energy. What happens to the rest of the energy from the lightbulb?
A. It is transformed into magnetic energy.
B. It is transformed into chemical energy.
D. It is transformed into electrical energy.
C. It is transformed into thermal energy.
Answer: it is turned into thermal energy
C. it is transformed into thermal energy
If Juan upgrades from a sports car to a large truck, what will happen to the
force needed to keep the truck going at the same speed? Use this
sentence frame:
Answer:
The force must increase
Explanation:
According to newton's second law "force is the product of mass and acceleration".
Force = mass x acceleration
Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.
There must be an increase in the force in order to make both automobiles attain the same speed.
Why did scientists gather at Los Alamos in 1945?
Answer:
Oppenheimer suggested that the bomb laboratory operate secretly in an isolated area but allow free exchange of ideas among the scientists on the staff.
Explanation:
A block slides down an incline of angle 30° with an
g
acceleration of where 'g' is acceleration due to gravity.
4
Find the coefficient of kinetic friction.
A baseball is thrown straight upward with a speed of 30 m/s. (a) How long will it rise? (6) How high will it
rise? (c) How long after it leaves the band will it return to the starting point? (ch) When will its speed be
16 m/s?
Answer:
(a) 3.06 s
(b) 45.92 m
(c) 6.12 s
(ch) 1.43 s
Explanation:
Vertical Launch Upwards
In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.
If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:
[tex]\displaystyle h_m=\frac{v_o^2}{2g}[/tex]
Similarly, the time it needs to reach the maximum height is:
[tex]\displaystyle t_m=\frac{v_o}{g}[/tex]
The object's speed (vf) after time t is:
[tex]v_f=v_o-g.t[/tex]
The baseball is thrown up at vo=30 m/s.
(a) It's required to calculate the time it needs to reach the maximum height:
[tex]\displaystyle t_m=\frac{30}{9.8}=3.06[/tex]
[tex]t_m=3.06~s[/tex]
(b) The maximum height is:
[tex]\displaystyle h_m=\frac{30^2}{2(9.8)}=45.92[/tex]
[tex]h_m=45.92~m[/tex]
(c) The time needed to travel up is the same time required to return to the starting point:
[tex]t_f=2*t_m=2*3.06[/tex]
[tex]t_f=6.12~s[/tex]
(ch) The speed will be vf=16 m/s at a certain time. Using the equation
[tex]v_f=v_o-g.t[/tex]
We solve for t:
[tex]\displaystyle t=\frac{v_f-v_o}{g}[/tex]
[tex]\displaystyle t=\frac{30-16}{9.8}[/tex]
t = 1.43 s
Can someone please check my answer
Answer:The answer is circular orbits I hope this helps
Explanation: