Answer:
Approximately [tex]281.25\; \rm m[/tex]. (Assuming that the drag on this ball is negligible, and that [tex]g = 10\; \rm m \cdot s^{-2}[/tex].)
Explanation:
Assume that the drag (air friction) on this ball is negligible. Motion of this ball during the descent:
Horizontal: no acceleration, velocity is constant (at [tex]v(\text{horizontal})[/tex] is constant throughout the descent.)Vertical: constant downward acceleration at [tex]g = 10\; \rm m \cdot s^{-2}[/tex], starting at [tex]0\; \rm m \cdot s^{-1}[/tex].The horizontal velocity of this ball is constant during the descent. The horizontal distance that the ball has travelled during the descent is also given: [tex]x(\text{horizontal}) = 30\; \rm m[/tex]. Combine these two quantities to find the duration of this descent:
[tex]\begin{aligned}t &= \frac{x(\text{horizontal})}{v(\text{horizontal})} \\ &= \frac{30\; \rm m}{4\; \rm m \cdot s^{-1}} = 7.5\; \rm s\end{aligned}[/tex].
In other words, the ball in this question start at a vertical velocity of [tex]u = 0\; \rm m \cdot s^{-1}[/tex], accelerated downwards at [tex]g = 10\; \rm m \cdot s^{-2}[/tex], and reached the ground after [tex]t = 7.5\; \rm s[/tex].
Apply the SUVAT equation [tex]\displaystyle x(\text{vertical}) = -\frac{1}{2}\, g \cdot t^{2} + v_0\cdot t[/tex] to find the vertical displacement of this ball.
[tex]\begin{aligned}& x(\text{vertical}) \\[0.5em] &= -\frac{1}{2}\, g \cdot t^{2} + v_0\cdot t\\[0.5em] &= - \frac{1}{2} \times 10\; \rm m \cdot s^{-2} \times (7.5\; \rm s)^{2} \\ & \quad \quad + 0\; \rm m \cdot s^{-1} \times 7.5\; s \\[0.5em] &= -281.25\; \rm m\end{aligned}[/tex].
In other words, the ball is [tex]281.25\; \rm m[/tex] below where it was before the descent (hence the negative sign in front of the number.) The height of this cliff would be [tex]281.25\; \rm m\![/tex].
A standing wave experiment is performed to determine the speed of waves in a rope. The standing wave pattern shown below is established in the rope. The rope makes exactly 90 complete vibrational cycles in one minute. The speed of the waves is ____ m/s.
Answer:
The speed of the waves is __6__ m/s.
Explanation:
Given
Total number of vibrations = 90
Total time taken for 90 vibrations = 60 seconds
Frequency of the wave = 90/60 = 1.5 Hz
The length of the rope as shown in the attached figure is 6 meters
The wavelength = 6/1.5 = 4.0 meters.
As we know
v=f*w
v = velocity
f = frequency
w = wavelength
Substituting the given values we get -
speed = 6.0 m/s
The speed of the waves obtained is 6 m/s
Data obtained from the question Number of complete cycles = 90Time = 1 min = 60 sLength of rope = 6 mVelocity (v) =? How to determine the frequency Number of complete cycles (n) = 90Time (t) = 1 min = 60 sFrequency (f) =?f = n/t
f = 90 / 60
f = 1.5 Hz
How to determine the velocity
Frequency (f) = 1.5 HzLength of rope (L) = 6 mWavelength (λ) = 2L / 3 = (2×6)/3 = 4mVelocity (v) =?v = λf
v = 4 × 1.5
v = 6 m/s
Complete question
See attached photo
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What is the speed of a wave with a period of 25 sec/cycle and a wavelength of 15 m/cycle?please help me !
What is urea? plz help me
Answer:
It is a colorless crystalline compound which is the main nitrogenous breakdown product of protein metabolism in mammals and is excreted in urine.
Answer:
Urea is a compound of nitrogen that is the chief solid substance dissolved in the urine of a mammal and is formed by the breaking down of protein.
(Hope this helps! Btw, I answered first. Brainliest please! :D)
Consider the following situation, in which a compass is influenced by not only the force of Earth's magnetic field, but also an additional applied force.
1. Which of the following is true of the angle of deflection of the compass relative to FEarth if FEarth > FApplied?
a. The angle of deflection will be exactly 45°
b. The angle of deflection will be greater than 90°
c. The angle of deflection will be less than 45°
d. The angle of deflection will be exactly 0°
e. The angle of deflection will be greater than 45° but less than 90°
2. Which of the following is true of the angle of deflection of the compass relative to FEarth if FEarth < FApplied?
a. The angle of deflection will be exactly 45°
b. The angle of deflection will be greater than 90°
c. The angle of deflection will be less than 45°
d. The angle of deflection will be exactly 0°
e. The angle of deflection will be greater than 45° but less than 90°
Answer:
1) The angle of deflection will be less than 45° ( C )
2) The angle of deflection will be greater than 45° but less than 90° ( E )
Explanation:
1) Assuming that the force applied has a direction which is perpendicular to the Earth's magnetic field
∴ Fearth > Fapplied hence the angle of deflection will be < 45°
2) when the Fearth < Fapplied
the angle of deflection will be : > 45° but < 90°
What is the average speed for a runner who finished the 100 meter dash in 9.8 seconds?
A. 0.98 m/s
B. 10.2 m/s
C. 1.02 m/s
D. 980 m/s
Answer:
10.2
the average speed of the runner is 10.2m/s.
Determine the amount of potential energy of a 5N book that is 1.5m high on a shelf.
Answer:
Potential energy of book = 7.5 J
Explanation:
Given:
Weight of book = 5 N
Height of shelf = 1.5 meter
Find:
Potential energy of book
Computation:
Weight = Mass x Acceleration of gravity
Mass x Acceleration of gravity = 5 N
Potential energy = Mass x Acceleration of gravity x Height
Potential energy of book = Mass x Acceleration of gravity x Height
We know that;
Mass x Acceleration of gravity = 5 N
So,
Potential energy of book = 5 x 1.5
Potential energy of book = 7.5 J
s the gravitational force greater between the objects in Pair 1 or Pair 2? Explain why. (Picture shown below)
Answer:
Pair 1
Explanation:
The gravitational force greater between the objects in Pair 1 because in Pair 2 the objects are far apart and in pair 1 the object are more closer to each other.
So, Gravitational force directly proportional to distance
Thus, Increase in distance = Increased in gravitational force
-TheUnknownScientist
The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering. View Available Hint(s) The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering. traveling in the x direction traveling toward the listener traveling away from the listener
Explanation is[tex]^{}[/tex] in a file
bit.[tex]^{}[/tex]ly/3tZxaCQ
The speed of sound is calculated to be 343m/s. If a sound wave has a frequency of 20Hz, what is the wavelength?
Choose the statement(s) that are FALSE. A. An object will undergo constant acceleration if it is in equilibrium. B. Subject to the same net force, a larger mass will accelerate at a greater rate than a smaller mass. C. If the vector sum of the forces on an object is not zero, the object is in equilibrium. D. A net force of 125 N acts horizontally on an object that weighs 125 N. Therefore, the object does not accelerate. E. If an object is at rest, then there are no forces acting on the object. F. None of these statements are false.
Answer:
A, B, C, D and E
Explanation:
A. An object will undergo constant acceleration if it is in equilibrium.
This is false because an object in equilibrium has no acceleration.
B. Subject to the same net force, a larger mass will accelerate at a greater rate than a smaller mass.
This is false because, since F = ma and a = F/m where a is acceleration and m = mass. Since F is constant, a ∝ 1/m. So acceleration is inversely proportional to mass. So, the smaller mass would accelerate at a greater rate than the larger mass.
C. If the vector sum of the forces on an object is not zero, the object is in equilibrium.
This is false because an object can only be in equilibrium if the vector sum of the forces acting on it is zero.
D. A net force of 125 N acts horizontally on an object that weighs 125 N. Therefore, the object does not accelerate.
This is false because, the weight acts in the vertical direction and has no effect in the horizontal direction. The only forces in the horizontal direction are the frictional force and the 125 N horizontally applied force.
The objects accelerates if the 125 N applied force is greater than the frictional force and since frictional force = μN = μW where μ = coefficient of friction, N = normal force and W = weight of the object. Since μ < 1, f < W. So f < 125 N. So, the object accelerates.
E. If an object is at rest, then there are no forces acting on the object.
This is false because, an object might be at rest when the net force acting on it is zero not only when no force acts on it.
Two 6 ohm resistors in parallel gives an equivalent resistance of
1/Req = 1/R1 + 1/R2 + 1/R3...
3 ohm
6 ohms
9 ohms
12 ohms
Answer:
3 ohms
Explanation:
6×6/6+6 =3 .............
A vector starts at the point (0.0) and ends at (3,-3). What is the angle of the displacement?
4.24
18
45 degrees
90 degrees
Answer:
135degrees
Explanation:
Given that a vector starts at the point (0.0) and ends at (3,-3)
y component value = -3
x component value = 3
angle of the displacement theta = arctan(y/x)
theta = arctan(-3/3)
theta = arctan (-1)
theta = -45degrees
Since tan is negative in the second quadrant
theta = 180 - 45
theta = 135degrees
Hence the angle of the displacement is 135degrees
imagine a single charge creating an electric field. what is the relationship between electric field strength and the distance from the charge?
a. direct
b. inverse
c. inverse squared
d. indirect
Answer:
b. inverse
Explanation:
[tex]E = \frac{V}{d} \\ d \: is \: the \: distance \\ [/tex]
Define specific heat capacity and latent heat of fusion.
Answer:
A substance's basic heat of fusion is the amount of heat needed to transform a unit mass of the substance from liquid to gaseous at its boiling point. B)... A substance's latent heat is known as the amount of energy emitted or consumed when the substance changes states.
Explanation:
A honey bee's wings beat at 230 beats per second. If the speed of sound in air is 340 m/s, what is the wavelength of
the sound waves?
Answer:
[tex]from \: the \: wave \: equation \\ velocity = frequency \times wavelength \\ 340 = 230 \times \lambda \\ \lambda = \frac{340}{230} \\ \lambda = 1.5 \: m[/tex]
An object is placed in front of a thin converging lens of focal length 12 cm. The image of the object is upright and 2.5 times as tall as the actual object. What is the distance of the object to the lens?
7.2 cm
6.0 cm
4.2 cm
15 cm
The distance of the object to the lens will be a) 7.2 cm
What is focal length?The distance between the convex lens or a concave mirror and the focal point of a lens or mirror is called the focal length. It is the point where parallel rays of light meet or converge.
magnification (m) = h(image )/ h(object ) = image distance / object distance
given
h(image ) = 2.5 * h(object)
m = 2.5 * h(object) / h(object ) = 2.5
2.5 = image distance / object distance
2.5 = v / u
v = 2.5 u
using lens formula
given
focal length (f) = + 12cm
1/v - 1/u = 1/focal length
1/2.5 u - 1/u = 1/12
u = - 7.2 cm
correct option a)7.2 cm
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Select the correct arrows. Identify the arrows that show the correct direction of heat transfer.
Answer:
Explanation:I Did the test and it said this was the right answer so it probally is
Answer:
That's the question that I wanted to ask!!
Explanation:
A person hears sounds with a frequency in the range of about 16 Hz to 20000 Hz. What is the wavelength of sound in air and water corresponding to these frequencies?
Please let me know the answer and how you got the answer (what formula you used)
Answer:
v=f×λ
Explanation:
v=f×λ
v is the speed of sound
f is the frequency of sound
λ is the wavelength
The speed of sound in air and water is different, but the frequency can be calculated from the given range above.
HAVE FUN LEARNING!!!( sorry im just to lazy to get the number so...)
The equation used to predict the theoretical period Ty of a simple pendulum assumes a small amplitude of oscillation. A student builds a pendulum by attaching one end of a string of known length to the ceiling and the other end to a small solid sphere. The sphere is pulled back so the string makes a 5 angle with the vertical and released from rest with a theoretical amplitude of Oscillation At The student measures the resulting experimental period Tg and after the sphere makes several oscillations, measures the experiment oscillation. In the absence of air resistance, T T and A. Which of the following best explains how air resistance affects the results of the experiment?
A) with resistance because the sphere will speed up
B) With air resistance As , because although the sphere slows down, it also will travel for a greater time
C) With resistance because the sphere will travel a greater distance
D) With air resistance, 7>7y, because the sphere will slow down
E) with resistance because although the sphere slows down, also will travel shorter distance
Answer:
The answer is "Choice E".
Explanation:
In this situation the option e is right because its resistance decreases through time, however, the time is the same for the same reason, whereas the sphere deteriorates, somehow it travels shorter distances however if the air resistance becomes are using the amplitude of movement declines, that's why other choices were wrong.
solve this with figure.help me ......
Answer:
[tex] \huge\mathfrak\pink{Hope \: it \: helps}\ [/tex]
a problem solving method that involves trying all possible solutions until one works is using_____.
Answer:
trial and error.
Explanation:
a problem solving method that involves trying all possible solutions until one works is using trail and error.
move the compass around the edge of the black screen far away from the bar magnet does the needle still interact with the poles of the bar magnet?
Answer: Yes
Explanation:
Answer:
Yes. The behavior of the bar magnet and the needle is similar to that in part A.
Explanation:
plato
On the Earth's surface, how much does a 100kg mass weigh? 1
Answer:
100kg
Explanation:
100kg=100kg
:P
Answer: 50 because thats the mass weight
Explanation: Its the obviouse answer.
1) A rock of mass 1.50kg is released from rest at a height of 30m. Ignore air resistance and
calculate;
(a) its speed half way down
(b) its speed on reaching the ground
(c) its total mechanical energy
(i) at a height of 30m
(ii) its kinetic energy half way through
(iii) its potential energy on striking the ground
Here's link to the answer:
bit.[tex]^{}[/tex]ly/3a8Nt8n
5. What is the elevation along the shoreline (sea level)?
O ft
1 ft
10 ft
100 ft
A 1220-N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A 1960-N crate hangs from the far end of the beam. FTis the Tension in the cable. FVand FHare the vertical and horizontal components of the force on from the wall on the beam. Why is the direction of FVup and not down
Answer:
Suppose the cable was vertical.
Vertical forces have to cancel to zero.
If you added weight to the beam the vertical force (supposed down)
the cable has to support the added weight as well as the weight added to the cable.
One could create a perpetual motion machine by using the additional downward force on the wall from weight applied to the beam. That is because
2 forces must be offset by the force Fv. That is, both the cable and the additional weight would contribute to the downward force at Fv.
There is a current of 0.83 A through a light bulb in a 120.0v circuit. What is the
resistance of the light bulb?
Answer:
144.6ohms
Explanation:
v=IR
R =V/I=120/0.83
R=144.6
The 10-lb block A attains a velocity of 2ft/s in 5 seconds, starting from rest. Determine the tension in the cord and the coefficient of kinetic friction between block A and the horizontal plane. Neglect the weight of the pulley. Block B has a weight of 8 lb. Please work on this by using the principle of linear impulse-momentum
Answer:
Explanation:
Let T be the tension in the cord.
Impulse by cord = change in momentum of block A .
T x 5s = 10 ( 2 -0) = 20
T = 4 poundal .
acceleration of block B = 2 / 5 = 0.4 m /s²
Net force applied on A = m ( g + a ) where m is mass of block B , a is acceleration of block B .
= 8 ( 32 + .4 ) = 259.2 poundal
Frictional force on block A = 259.2 - 4 = 255.2 poundal
μ x 10 x 32 = 255.2
320μ = 255.2
μ =0 .8 .
how do people in your community deal with loud sound
Answer: Nothing they mind thier own business instead of being really noisy.
Explanation
Now if someone was screaming they probley would go investagate investigate but something else nah.
Can someone please help me with this one
Answer:
im pretty sure the answer is A. up but im not 100% sure