A 60.0-cm, uniform, 5.00-kg shelf is supported horizontally by two vertical wires attached to a sloping ceiling. The front wire is inset by a distance of 20 cm. A very small 2.50-kg tool is placed on the shelf midway between the points where the wires are attached to it.


Required:

Find the tension in the back wire.

Answer:

Fₓ = maₓ

Fy = may

Explanation:

The Newton's Second Law tells us about the force. It says whenever an unbalanced force is applied to a body, an acceleration is produced in that body. The direction of this acceleration is in the direction of the force itself. Hence, the law can be written as:

F = ma

where,

F = Unbalanced force

m = mass of body

a = acceleration magnitude

We, can write two equations separately for x-direction and y-direction as follows:

Fₓ = maₓ

Fy = may

where,

Fₓ = x-component of unbalanced force

aₓ = x-component of acceleration

Fy = y-component of unbalanced force

ay = y-component of acceleration

Answer:

The speed of the sound wave on the string is 545.78 m/s.

Explanation:

Given;

mass per unit length of the string, μ = 4.7 x 10⁻³ kg/m

tension of the string, T = 1400 N

The speed of the sound wave on the string is given by;

[tex]v = \sqrt{\frac{T}{\mu} }[/tex]

where;

v is the speed of the sound wave on the string

Substitute the given values and solve for speed,v,

[tex]v = \sqrt{\frac{T}{\mu} }\\\\v = \sqrt{\frac{1400}{4.7*10^{-3}} }\\\\v = \sqrt{297872.34}\\\\v = 545.78 \ m/s[/tex]

Therefore, the speed of the sound wave on the string is 545.78 m/s.

Answer:

She should bend her hips so her head is closer to the handlebars

Explanation:

Answer:

Yea its A

Explanation:

Answer:

Resistance decreases the flow of current in a circuit.

EXPLANATION:

The resistance of an electrical circuit is defined as the opposition to the flow of current in that particular circuit.

From Ohm's law, we know that current flowing  through a wire I =

Here,V is the potential across the two ends of a conductor or wire, and R is the resistance of that wire.

Hence, more is the resistance, the less will be the current flow in the current.

Answer:

196200N

Explanation:

Fg=mg

Fg=?

m=20000

g=9.81

Fg= (20000kg)(9.81[tex]m/s^{2}[/tex])=196200N

Answer:

O C. Light energy

Explanation:

it conducts energy in it and is an energy itself.

Answer:

c. 7.7 eV

Explanation:

The computation of the photon emitted is shown below:

Given that

From level 1 to level 3, the energy absorbed by electrons is 11.8eV

And, when from level 3 to level3, the energy released by electron is 4.1eV

So, from level 2 to level 1, the energy released is

= 11.8 - 4.1

= 7.7

= 7.7eV

Hence, the third option is correct

The same is to be considered

And, the other options are wrong

Answer:

2.12m/s

Explanation:

Given parameters:

Force on trolley  = 1.5N

Mass of trolley  = 0.2kg

Unknown:

Velocity of the trolley  = ?

Solution:

To solve this problem, we first find the acceleration of the trolley;

          Force  = mass x acceleration

         Acceleration  = [tex]\frac{Force }{mass}[/tex]

Insert the parameters and solve;

          Acceleration  = [tex]\frac{1.5}{0.2}[/tex]   = 7.5m/s²

Now to find the acceleration;

  Initial velocity  = 0m/s

  v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

  Distance  = 30cm and this is 0.3m

     v² = 0² + 2(7.5)0.3  = 4.5

     v = √4.5 = 2.12m/s

The ball rolls off the table with speed v from a height of 0.35 m, so that it covers a horizontal distance x with height y at time t of

x = v t

y = 0.35 m - 1/2 g t ²

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Solve for t when y = 0, i.e. the time it takes for the ball to reach the ground:

0 = 0.35 m - 1/2 g t ²

t ² = (0.70 m) / g

t ≈ 0.267 s

Now solve for v given that the ball falls 3 m away from the table:

3 m = v (0.27 s)

v = (3 m) / (0.27 s)

v ≈ 11.2 m/s

Taking the downward direction as positive

Stone 1:

Initial velocity (u) = 0 m/s

Acceleration (a) = 10 m/s²

Time taken to reach the ground (t) = t seconds

Distance covered (s) = 20 m

Stone 2:

Initial velocity (u) = u m/s

Acceleration (a) = 10 m/s²

Time taken to reach the ground (t) = (t-1) seconds  

[where t is the time taken by stone 1]

Distance covered (s) = 20 m

__________________________________________________________

Stone 1:

Using the second equation of motion:

s = ut + 1/2*at²

replacing the variables for Stone 1

20 = (0)(t) + 1/2(10)(t)²

20 = 5t²

Dividing both sides by 5

t² = 4

Taking the square root of both the sides

t = 2 seconds

Hence, Stone 1 reaches the ground in 2 seconds

Stone 2:

The time taken by Stone 2 to reach the ground depends on the time taken by stone 1. Since we defined the time taken by stone 2 as:

Time taken by Stone 2 = (Time taken by Stone 1) - 1

replacing the values:

Time taken by Stone 2 = 2 - 1

Time taken by Stone 2 = 1 second

Hence, Stone 2 will reach the ground in 1 second

__________________________________________________________

According to the second equation of motion:

s = ut + 1/2 at²

replacing the values for Stone 2

20 = (u)(1) + 1/2(10)(1)²

20 = u + 5

u = 15 m/s

Therefore, the Stone 2 is thrown at a velocity of 15 m/s downwards

Answer:

The peak value of the Magnetic field is 6.67 x 10⁻⁸ T

Explanation:

Given;

peak value of the electric-field, E₀ = 20 V/m

The peak of the magnetic field, B₀ = ?

The peak value of the magnetic field is given by;

B₀ = E₀/C

Where;

C is the speed of light = 3 x 10⁸ m/s

Substitute the givens and solve for B₀

B₀ = E₀ / C

B₀ = (20) / (3 x 10⁸)

B₀ = 6.67 x 10⁻⁸ T

Therefore, the peak value of the Magnetic field is 6.67 x 10⁻⁸ T

B₀ =

Answer:

Free points

Explanation:

Answer:

wdym??

Explanation:?

Answer:

4.24nm

0.385eV

Explanation:

Maximum wavelength (λmax) :

λmax = ( hc) /Φ

h = plancks constant = 6.63 * 10^-34

c = speed of light = 3*10^8

1ev = 1.6 * 10^-19

Φ = 2.93eV = 2.93* (1.6*10^-19) = 4.688*10^-19

λmax = [(6.63 * 10^-34) * (3 * 10^8)] / 4.688*10^-19

λmax = 19.89 * 10^-26 / 4.688*10^-19

λmax = 4.242 * 10^-7 m

λmax= 4.24nm

B.)

E = hc / eλ eV

λ = 3.75nm = 3.75 * 10^-7m = 375 *10^-9

E = (6.63 * 10^-34) * (3 * 10^8) / (1.6 * 10^-19) * (375 * 10^-9)

E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

E = 0.03315 * 10^2

E = 3.315 eV

Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

Answer:

Liquid

Explanation:

A liquid will fill its container and are neither tightly packed like a solid nor very loosely packed like a gas.

Answer: Its Solid

Explanation:

Answer:

The end of the ramp is 38.416 m high

Explanation:

Horizontal Motion

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

If the maximum horizontal distance is known, we can solve the above equation for h:

[tex]\displaystyle h=\frac {d^2g}{2v^2}[/tex]

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

[tex]\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}[/tex]

[tex]\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}[/tex]

h= 38.416 m

The end of the ramp is 38.416 m high

Answer: They were randomly preassigned to the condition of social rejection.

Explanation:

Humans are said to be social beings which means that we survive in part due to our social connections. The experiment from the video was meant to research and evaluate what happens to human beings when they experience social rejection instead of acceptance.

There were four participants being Alexandria, Mike, Brittany and Michael. For the purpose of the research, Brittany and Michael were preassigned to the condition of social rejection whilst the other two were preassigned to acceptance with the goal being to observe the reactions of the parties after they find that they were either accepted or rejected.

Attached is the transcript to the video of the research summary.

Answer:

c

Explanation:

1- First electrons are transferred.

2-The ions are formed

3-The ions are attracted to form the compound

Answer:

answer is c.........

Explanation:

Answer: B. 0 kg*m/s

Explanation:

Answer:

Answer: A

Explanation:

Why??   Two objects meaning they have the same force pair must remain the same

Using Newton's third law, we find that the correct answer to the reaction force is  a: the force of the glove on the ball

Given parameters

to find

Newton's third law say that forces are produced in pairs, that is, when two bodies interact, one body feels the action of the other and responds with an interaction of equal magnitude but in the opposite direction. In general, these two forces are called action and reaction, they have the following characteristics:

let's analyze the given options using Newton's third law:

a. True. The force of the ball is on the glove, it must respond with a force of equal magnitude on the ball, therefore these are two forces of action and reaction

b. False. The grip or the player's hand does not receive the action of the ball, it receives the action of the glove

c) False. the player's shoes do not interact with the ball, interact with the ground

In conclusions by using Newton's third law the correct answer is a:  the force of the glove on the ball

learn more about Newton's third law  here: brainly.com/question/23772134

Answer:

Explanation:

Pressure on the hydraulic system is expressed as;

Pressure = Force/Area

Given

Force on the fluid = 400N

Area = 0.001m²

Pressure in the fluid = 400/0.001

Pressure in the fluid = 400,000N/m²

1N/m² = 0.001kPa

400,000N/m² = x

x = 400,000 × 0.001

x = 400kPa

Hence the pressure in kPa is 400kPa

b) Using the formula;

Pa = Pb

Fa/Aa = Fb/Ab

Pa = Fb/Ab

Fb = PaAb

Fb = 400,000(0.2)

Fb = 80,000N

Hence the magnitude of the force exerted on the load bearing piston by the hydraulic fluid is 80,000N

Answer:

(a) V₁ =  1.06 m/s

(b) V₂ = 4.24 m/s

(c) Q = 4.08 x 10⁻³ m³/s

Explanation:

(b)

The formula derived for Venturi tube can be used here:

P₁ - P₂ = (ρ/2)(V₂² - V₁²)

where,

P₁ - P₂ = Difference in Pressure = (2x 10⁴ Pa) - (1.25 x 10⁴ Pa) = 0.75 x 10⁴ Pa

ρ = Density of Oil = 890 kg/m³

V₂ = Velocity at Higher End = ?

V₁ = Velocity at Lower End = ?

Therefore,

0.75 x 10⁴ Pa = [(890kg/m³)/2](V₂² - V₁²)

V₂² - V₁² = (0.75 x 10⁴ Pa)/(445 kg/m³)

V₂² - V₁² = 16.85 m²/s²   ------------------- equation (1)

Now, we will use continuity equation:

A₁V₁ = A₂V₂

where,

A₁ = Lower End Area = πd₁²/4 = π(0.07 m)²/4 = 3.848 x 10⁻³ m²

A₂ = Higher End Area = πd₂²/4 = π(0.035 m)²/4 = 9.621 x 10⁻⁴ m²

Therefore,

(3.848 x 10⁻³ m²)V₁ = (9.621 x 10⁻⁴ m²)V₂

V₁ = (9.621 x 10⁻⁴ m²)V₂/(3.848 x 10⁻³ m²)

V₁ = 0.25 V₂   -------------------- equation (2)  

using this value in equation (1):

V₂² - (0.25 V₂)² = 16.85 m²/s²

0.9375 V₂² = 16.85 m²/s²

V₂² = (16.85 m²/s²)/0.9375

V₂ = √(17.97 m²/s²)

V₂ = 4.24 m/s

(a)

using the value of V₂ in equation (2):

V₁ = 0.25(4.24 m/s)

V₁ =  1.06 m/s

(c)

For fluid flow rate we use the following equation:

Flow Rate = Q = A₂V₂ = (9.621 x 10⁻⁴ m²)(4.24 m/s)

Q = 4.08 x 10⁻³ m³/s

The speed if the fluid increases as pressure decreases.

(a)  The speed of the flow in the lower section is 1.06 m/s

(b)  The speed of the flow in the higher section is  4.24 m/s

(c) The volume flow rate in the pipe [tex]\bold {4.08 x 10^-^3m^3/s}[/tex].

The relation pressure and volume in constricted pipe can be derived by the formula formula ,

[tex]\bold {P_1 - P_2 = (\rho /2)(V_2^2 - V_1^2)}[/tex]

Where,

P₁ - P₂ -Difference in Pressure = [tex]\bold { 0.75 x 10^4}[/tex]

[tex]\rho[/tex] - Density of Oil = 890 kg/m³

V₂ - Velocity at Higher End = ?

V₁ - Velocity at Lower End = ?

put the values in the formula,

[tex]\bold {0.75 x 10^4 Pa = \dfrac{(890kg/m^3)}{2(V_2^2 - V_1^2)}}\\\\\bold {V_2^2 - V_1^2 = \dfrac {0.75 x 10^4 Pa}{445 kg/m^3}}\\\\\bold {V_2^2 - V_1^2 = 16.85 m^2/s^2}[/tex]

The continuity equation,

[tex]\bold {A_1V_1 = A_2V_2}[/tex]

Where,

[tex]\bold {A_1 }[/tex] - Area of lower end = [tex]\bold {3.848 x 10^-^3m^2}[/tex]

[tex]\bold {A_2 }[/tex] - Area of higher end = [tex]\bold {9.621 x 10^-^4m^2}[/tex]

Put the value in the formula above,

[tex]\bold {(3.848 x 10^-^3m^2)V_1= (9.621 x 10^-^4m^2)V^2}\\\\\bold {V_1 = \dfrac {(9.621 x 10^-^4 m^2)V_2}{(3.848 x 10^-^3 m^2)}}\\\\\bold {V_1 = 0.25 \times V_2}[/tex]

Put the value of [tex]\bold {V_1}[/tex], we get

[tex]\bold {V_2= 4.24 m/s}[/tex]

Therefore,

[tex]\bold {V1 = 0.25 (4.24 m/s)}\\\\\bold {V_1 = 1.06 m/s}[/tex]

The flow rate

[tex]\bold {Q = A_2V_2}[/tex]

[tex]\bold {Q = (9.621 x 10^-^4 m^2)(4.24 m/s)}\\\\\bold {Q = 4.08 x 10^-^3m^3/s}[/tex]

Therefore, the flow rate of the oil in the pipe is [tex]\bold {4.08 x 10^-^3m^3/s}[/tex].

To know more about Bernoulli's equation, refer to the link:

https://brainly.com/question/5531068

This question is incomplete, the complete question is;

An engineer is tasked with developing a model to study a cylindrical heat exchanger in a steam system. The prototype cylinder is 2.54 cm in diameter and the steam properties are: velocity = 30 m/s; density = 0.6 kg/m³; and absolute viscosity = 1.197 X 10⁻⁵ N-s/m², respectively. The model is going to be tested in a water tunnel where the water temperature is 20°C and the velocity is 3 m/s

a) what is the prototype Reynolds number, based on using the cylinder diameter as the characteristic length?

b) what should be the diameter of the model be to ensure dynamic similitude?

Answer:

a) the prototype Reynolds number is 38195.488

b) 0.01278 m or 1.278 cm should be the diameter of the model be to ensure dynamic similitude

Explanation:

Given that;

1 prototype ; d = 2.54 cm = 0.0254 m, Vp = 30 m/s, Sp = 0.6 kg/m³, Up = 1.197 × 10⁻⁵ N-s/m²

Model{ water at 20°C}; dm = ?, Vm = 3 m/s, Pm = 998.23 kg/m³, Um = 1.002 × 10⁻³ N-s/m²

a) what is the prototype Reynolds number,

to calculate prototype Reynolds number we use the expression;

(Re)p = SpVpdP / Up

we substitute our value

(Re)p =  (0.6 × 30 × 0.0254) / 1.197 × 10⁻⁵

(Re)p = 38195.488

Therefore the prototype Reynolds number is 38195.488

b)

what should be the diameter of the model be to ensure dynamic similitude?

i.e dm = ?

so dynamic similarity [ viscous flow]

(Re)m = (Re)p

[PmVmdm / Um] = [SpVpdP / Up]

we substitute

[998.23 × 3 × dm / 1.002 × 10⁻³] = (0.6 × 30 × 0.0254) / 1.197 × 10⁻⁵

2994.69dm / 1.002 × 10⁻³ = 38195.488

2994.69dm = 38.2718

dm = 38.2718 / 2994.69

dm = 0.01278 m or 1.278 cm

Therefore 0.01278 m or 1.278 cm should be the diameter of the model be to ensure dynamic similitude

Answer:

um

Explanation:

Answer: Dang thats tough g but u did it

Explanation:

Answer:

The first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.

Explanation:

Given;

radius of the first object, r₁ = 10 cm = 0.1 m

radius of the second object, r₂ = 0.2 m

let the mass of the two objects, = m

let the speed of the two objects = v

The centripetal force of the first object is given by;

[tex]F_c_1 = \frac{mv^2}{r_1} \\\\F_c_1 = \frac{mv^2}{0.1}\\\\F_c_1 = 10mv^2[/tex]

The centripetal force of the second object is given by;

[tex]F_c_2 = \frac{mv^2}{r_2} \\\\F_c_2 = \frac{mv^2}{0.2}\\\\F_c_1 = 5mv^2[/tex]

Therefore, the first object is experiencing a larger centripetal force because its radius is smaller compared to the second object.

a). My estimate is 18.75 mph.

b). The average speed is 18.75 mph.

I nailed it.

Answer:

D. upright, same size as object, virtual

Explanation:

it is a plane mirror, it has no changes

The characteristics of the image produced by the object placed in front of a plane mirror will be upright, the same size as the object, and virtual.

The law of reflection states that when a ray of light reflects back from a surface the angle of incidence of light on a surface is equal to the angle of reflection.

The image produced by an object in front of a plane mirror will be upright, the same size as the object, and virtual.

learn more about the law of reflection

https://brainly.com/question/18772331

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