The momentum of the truck is "56250 kgm/s".
According to the question,
Mass,
m = 2250 kgVelocity,
v = 25 m/sAs we know,
→ [tex]p = mv[/tex]
By putting the values, we get
→ [tex]= 2250\times 25[/tex]
→ [tex]= 56250 \ kgm/s[/tex]
Thus the answer is right.
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Which of the following is the BEST example of increasing the intensity of a workout? A. running one mile further than normal B. running one mile faster than normal C. running one mile more every other workout D. jogging for three miles Please select the best answer from the choices provided. A B C D
Answer:
B. Running one mile faster than normal
Explanation:
Just took the quiz, good luck ❤
The best example of increasing the intensity of a workout is running one file faster than normal. Hence, option B is correct.
What is an Exercise?Exercise is a physical activity for the body that improves or preserves physical fitness as well as general health and wellness.
It is done for a variety of objectives, such as support growth and enhance strength, needs to better and also the cardiovascular system, refine sports skills, maintain or lose weight, improve health, or just for fun. Many people like to work outside where they may interact, gather in groups, and enhance their physical and emotional well-being.
The amount of advised exercise for health benefits varies on the objective, the style of activity, and the age of the individual. Exercise is better for you than not at all, even if it is only a little.
Therefore, the best example of increasing the intensity of workout or exercise by running one mile faster than normal.
To know more about Exercise:
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If the velocity of a proton is straight up (thumb pointing up) then RHR2 shows that the force points to the left. What would the direction of the force be if the velocity were
Answer:
a) to the right
b) up
c) down
d) there will be no force on the proton
e) there will be no force on the proton
Explanation:
The complete question is
If the velocity of a proton is straight up(thumb pointing up) then RHR2 (right hand rule) shows that the force points to the left. What would the direction of the force be if the velocity were a)down, b)to the right, c)to the left, d)into the page, and e)out of the page?
The right hand rule for a positive charge states that...
Hold the thumb of the right hand at right angle to the rest of the fingers, and the rest of the fingers parallel to one another, and pointing away from the body. If the thumb shows the velocity of a positive charge in a magnetic field, and the fingers all point in the direction of the magnetic field, then the palm will push in the direction of the force on the positive charge (proton).
From this, we can deduce from the original statement about this proton that the direction of the field is into the screen of this computer. with that field direction held constant, we can work out that
a) if the thumb point down, the force will be to the right
b) if the thumb points to the right, the force will be upwards
c) if the thumb points to the left, the force is downwards
d) if the thumb points into the page, then there will be no force on the proton since the proton must travel perpendicularly to the magnetic field for a force to be induced on it
e) explanation is the same as foe option d.
Consider an embedded system which uses a battery with a 17.15-Amp-Hour capacity. What is the maximum average current draw (in micro Amps to one decimal place) that your embedded processor can have if you want the battery to last 23 years without being replaced
Answer:
85.12 μAmp
Explanation:
The battery power output = 17.15 Amp-hr
If the battery is to last 23 years, we have to calculate how many hours there are in 23 years
in one year there are 24 hours x 365 day = 8760 hrs
in 23 years there are 23 x 8760 = 201480 hours
maximum current to be drawn from the battery = (17.15 Amp-hr) ÷ (201480 hours) = 85.12 x 10^-6 Amp = 85.12 μA
You and a friend are doing the laundry when you unload the dryer and the discussion comes around to static electricity. Your friend wants to get some idea of the amount of charge that causes static cling. You immediately take two empty soda cans, which each have a mass of 120 grams, from the recycling bin. You tie the cans to the two ends of a string (one to each end) and hang the center of the string over a nail sticking out of the wall. Each can now hangs straight down 30 cm from the nail. You take your flannel shirt from the dryer and touch it to the cans, which are touching each other. The cans move apart until they hang stationary at an angle of 10 degrees from the vertical.
Assuming that there are equal amounts of charge on each can, you now calculate the amount of charge transferred from your shirt.
Answer:
Q_total = 2 10⁻⁶ C
Explanation:
Let's apply the conditions of static equilibrium to this case, in the adjoint we can see a diagram of the forces.
X axis
Tₓ - Fe = 0
Tₓ = Fe
Y axis
[tex]T_{y}[/tex] - W = 0
T_{y} = W
Let's use trigonometry to find the stress components, the angle is measured with respect to the vertical
sin 10 = Tₓ / T
cos 10 = T_{y} / T
Tₓ = T sin 10
T_{y} = T cos 10
we substitute
T sin 10 = Fe
T cos 10 = W
T = mg / cos10
T = 0.120 9.8 / cos 10
T = 1,194 N
Fe = 1,194 sin 10
Fe = 0.2073 N
the electric force is
F = k q₁q₂ / r²
in this case, as the cans touch, they have the same charge and the distance r is searched for by trigonometry
sin 10 = y / L
y = L sin 10
y = 0.30 sin 10
y = 0.052 m
this is the distance from the vertical to one can the distance between the two cans is
y_total = 2y
y_totlal = 2 0.052 = 0.104 m
Fe = F = k q² / r²
q = √ (F r² / k)
q = √ (0.2073 0.104²/9 10⁹) = √ (24.913 10⁻¹⁴)
q = 4.99 10⁻⁷ C
This is the charge of a can, as the transfer is carried out by contact, the flannel transfers half of its charge to the cans and these when separating face one keeps half of the transferred charge, therefore the total charge of the flannel is
Q_total = 4 q
Q_total = 19.97 10⁻⁷ C
Q_total = 2 10⁻⁶ C
Which law of motion is this an example of? Newton's 1st Law of Motion
Newton's 2nd Law of Motion
Newton's 3rd Law of Motion
Answer:
first law is your answer, if I'm not wrong
Answer:
i think it's the first law of motion :)
Explanation:
What is the electric field produced by this charge at point P, which is on the x-axis, 9.83 mm from the origin
Given :
Distance of point P from the origin is , d = 9.83 mm .
To Find :
The electric field produced by this charge at point P , if charge is placed at origin .
Solution :
Let , charge on origin is q .
Electric field at point P is given by :
[tex]E=\dfrac{kq}{r^2}[/tex] ..... ( 1 )
Here , k is constant , [tex]k=9\times 10^{9}\ N \ m^2/C^2[/tex] .
Putting value of k and r in above equation , we get :
[tex]E=\dfrac{q\times 9\times 10^9}{(9.83\times 10^{-3})^2}\ N/C\\\\E=(9.31\times 10^{13})q\ N/C[/tex]
Hence , this is the required solution .
The SI system uses three base units. Question 6 options: True False
Answer:
The answer is false
Explanation:
Though the mostly used SI unit of measurement or the most popular units are the
Length,
Time and
Mass
i.e meter (m), seconds (s), kilogram (kg)
Aside all the above stated units for measurements there are other four basic units which are itemized bellow.
they are
1. Amount of substance - mole (mole)
2. Electric current - ampere (A)
3. Temperature - kelvin (K)
4. Luminous intensity - candela (cd)
A kayak on a lake is moving at a constant speed of 4.1 m/s in a direction 41.6° north of west. After 10 min, find the following.(a) how far west the kayak has traveled km (b) how far north the kayak has traveled km
Given :
A kayak on a lake is moving at a constant speed of 4.1 m/s in a direction 41.6° north of west.
To Find :
After 10 min :
(a) how far west the kayak has traveled km.
(b) how far north the kayak has traveled km.
Solution :
a) Time taken in seconds :
[tex]t=10\times 60 \ s = 600\ s[/tex] .
Distance travelled in 600 s is :
[tex]D=s\times t\\\\D=4.1\times 600\ m\\\\D=2460\ m[/tex]
Distance in km is :
[tex]D=\dfrac{2460}{1000}=2.46\ km[/tex]
b) Now , distance from the north is given by :
[tex]d=D\times sin\ 41.6^o\\\\d=2.46 \times sin\ 41.6^o\\\\d=1.63\ km[/tex]
Hence , this is the required solution .
A monkey has a bit of a heavy for on the gas pedal. As soon as the light turns green the monkey pushes the gas pedal to the floor and accelerates from 0 mph to 60 mph (0 m/s - 28.82 m/s) in 4.2 seconds, calculate the cars acceleration.
Answer:
[tex]s=6.86m/s^2[/tex]
Explanation:
Hello,
In this case, considering that the acceleration is computed as follows:
[tex]a=\frac{v_{final}-v_{initial}}{t}[/tex]
Whereas the final velocity is 28.82 m/s, the initial one is 0 m/s and the time is 4.2 s. Thus, the acceleration turns out:
[tex]a=\frac{28.82m/s-0m/s}{4.2s}\\ \\s=6.86m/s^2[/tex]
Regards.
A student releases a marble from the top of a ramp. The marble increases
speed while on the ramp then continues across the floor. The marble travels a
total of 160cm in 4.60s.
What was the marble's final speed?
cm/s
HELP PLEASE
Answer:
Vf = 69.56 cm/s
Explanation:
In order to find the final speed of the ramp, we will use the equations of motion. First we use second equation of motion to find out the acceleration of marble:
s = Vi t + (1/2)at²
where,
s = distance traveled = 160 cm
Vi = Initial Speed = 0 cm/s (since, marble starts from rest)
t = time interval = 4.6 s
a = acceleration = ?
Therefore,
160 cm = (0 cm/s)(4.6 s) + (1/2)(a)(4.6 s)²
a = (320 cm)/(4.6 s)²
a = 15.12 cm/s²
Now, we use first equation of motion:
Vf = Vi + at
Vf = 0 cm/s + (15.12 cm/s²)(4.6 s)
Vf = 69.56 cm/s
During a morning run, Juanita averaged a speed of 4.83 m/s for 11.2 minutes. She then averaged a speed of 5.99 m/s for 7.44 minutes. What total distance did Juanita run during her 20.0 minute jog.
Answer:
I believe the answer is 10.82 m/s.
Explanation:
I just saw that the question asked for the TOTAL DISTANCE.. which means to add. And I added 4.83 and 5.99 together which then lead me to get 10.82 m/s. So yeah i think that's the answer. Hope this helps.
You are driving your car at a speed of 19.0 m/s and you hit the brakes. The car accelerates at -3.50 m/s2. (a) How long does it take the car to cover 10.0 m? (b) What is the final velocity of the car? (show work)
Answer:
Time taken by car to cover 10m is 5.42 seconds and final velocity is 0m/s.
How many standards unti “forces and motion” cover ?
Someone plans to float a small, totally absorbing sphere 0.518 m above an isotropic point source of light, so that the upward radiation force from the light matches the downward gravitational force on the sphere. The sphere's density is 22.2 g/cm3, and its radius is 2.12 mm. (a) What power would be required of the light source
Answer:
Explanation:
From the question we are told that
The height is [tex]h = 0.518 \ m[/tex]
The sphere density is [tex]\rho = 22.2g/cm^3 = \frac{22.2 }{1000} * 1*10^{6} = 22200 kg/m^3[/tex]
The radius is [tex]r = 2.12 \ mm =0.00212 \ m[/tex]
Generally the power required is mathematically represented as
[tex]P = \frac{16 * \pi * \rho * r * g * h^2 * c }{3}[/tex]
substituting values
[tex]P = \frac{16 * 3.142 * 22200 * 0.00212 * 9.8 * 0.518^2 * 3.0*10^{8}}{ 3}[/tex]
[tex]P = 6.22*10^{11} \ W[/tex]
Why are viruses hard to fight
Answer:Compared to other pathogens, such as bacteria, viruses are minuscule. And because they have none of the hallmarks of living things — a metabolism or the ability to reproduce on their own, for example — they are harder to target with drugs.
Explanation:
A substan e has a melting point of 20◦C and a heat of fusion of 3.5 × 104 J/kg. The boiling point is 150◦C and the heat of vaporization is 7.0 × 104 J/kg at a pressure of 1.0 atm. The spe i heats for the solid, liquid, and gaseous phases are 600 J/(kg.K), 1000 J/(kg.K), and 400 J/(kg.K), respe tively. The quantity of heat given up by 0.50 kg of the substan e when it is ooled from 170◦C to 88◦C, at a pressure of 1.0 atmosphere, is losest to (1) 70 kJ (2) 14 kJ (3) 21 kJ (4) 30 kJ (5) None of the above.
Answer: Option (1) 70 kJ
Explanation:
Given that;
melting point of the substance T₁ is 20°C , Boiling point of the substance T₂ is 150°C , heat of fusion L₁ is 3.5 x 10⁴ J/kg , heat of vaporization L₂ is 7 x 10⁴ J/kg , Specific heat in solid state C₁ is 600 J/kg.K , Specific heat in liquid state C₂ is 1000 J/kg.K, Specific heat in gaseous state C₃ is 400 J/(kg.K) , Mass of the substance m is 0.5 kg , Initial temperature of the substance T₃ is 170°C , Final temperature of the substance T₄ is 88°C .
Now Heat given up by the substance to reach boiling point 150°C is
Q₁ = mC₃(T₃ - T₂)
Q₁ = (0.5)(400)(170 - 150)
Q₁ = 4000 J
Heat given up by the substance to turn into liquid from gaseous state at 150°C
Q₂ = mL₂
Q₂ = (0.5)(7x10⁴)
Q₂ = 35000 J
Heat given up by the substance to reach 88°C in liquid state from 150°C
Q₃ = mC₂(T₂ - T₄)
Q₃ = (0.5)(1000)(150 - 88)
Q₃ = 31000 J
Total heat given up by the substance
Q = Q₁ + Q₂ + Q₃
Q = 4000 + 35000 + 31000
Q = 70000 J
Q = 70 kJ
Therefore The quantity of heat given up by 0.50 kg of the substance when it is cooled from 170◦C to 88◦C, at a pressure of 1.0 atmosphere, is closest to 70 kJ
The main functions of the skin are:
ОА.
To protect the human body from foreign bodies from the outside environment.
ОВ.
A sensory organ for the brain.
Ос.
Shock absorption
OD
All of the above
Reset
Next
Answer:To protect the human body from foreign bodies from the outside environment.
Explanation:
A particle is moving along a straight line through a fluid medium such that its speed is measured as v = (2t) m/s, where t is in seconds. If it is released from rest at s = 0, determine its positions and acceleration when t = 3 s.
Answer:
The acceleration of the particle is 2 m/s²
The position of the particle is 9m
Explanation:
Given;
particles velocity, v = 2t m/s
The acceleration of the particle is given by;
a = dv/dt
a = d(2t) /dt
a = 2 m/s²
The acceleration of the particle is 2 m/s²
The position of the particle is given by;
s = ut + ¹/₂at²
Since the particle was released from rest, u = 0
s = 0(3) + ¹/₂(2)(3)²
s = 0 + 9 m
The position of the particle when t = 3 s is 9m
The element that has an average amu of 40 is represented by the symbol Zr on the Periodic Table of Elements. True False Question 2 (2 points) The element found in Period 2, Group 8 is called Argon. True False Question 3 (2 points) Which element would have 4 valence electrons? a Be b Si c H Question 4 (5 points) Put the following elements in order according to the number of protons they contain: S; Si, Sc; Na Reorder answers 1.Si Reorder answers 2.S Reorder answers 3.Sc Reorder answers 4.Na Question 5 (2 points) Argon is a part of what family in the Periodic Table of Elements? a Halogens b Noble Gases c Alkali Metals Question 6 (4 points) (03.02 MC) Match the element with its description. (4 points) Column A 1. Sodium : a Sodium 2. Silicon : c Silicon 3. Bromine : d Bromine 4. Argon : b Argon Column B a. Malleable, soft, and shiny b. Has properties of both metals and nonmetals c. Highly reactive gas d. Nonreactive gas Question 7 (2 points) A period in the Periodic Table of Elements determines the number of _. a protons b valence electrons c shells/energy levels Question 8 (3 points) (03.02 MC) A neutral atom of chlorine (Cl) has an average mass of 35 amu and 17 electrons. How many neutrons does it have? (3 points) a 18 b 17 c 52 Question 9 (2 points) A balanced/neutral atom will have the same number of protons and neutrons. True False Question 10 (2 points) The element Manganese is represented by _ in the Periodic Table of Elements a Mn b Mg c Ma Question 11 (2 points) Which element family below is best described as being very reactive? a Metalloids b Noble Gases c Alkali Metals Question 12 (2 points) The element Lithium is more reactive than Beryllium. True False Someone answer, please.
Answer:
False
Explanation:
Becuase the average amu of 40 is represented
A golfer needs to sink an 8m putt. She hits the ball, giving it an initial speed of 1.6 m/s, but it stops 1.5m short of the hole. c. What initial speed did the ball need to just make the putt? Assume the acceleration of the grass is constant. Hint: to just make the putt, the speed of the ball will be zero right at the hole. d. In order to make the 1.5m putt, what initial speed does she need to give the ball?
Answer:
1.78 m/s
Explanation:
Distance to putt = 8 m
Distance the ball stops to the putt = 1.5 m
therefore distance traveled by the ball = 8 - 1.5 = 6.5 m
The ball stops at this point 1.5 m from the putt, therefore its final velocity at this point = 0 m/s
the ball was struck with an initial velocity of 1.6 m/s
Using the equation
[tex]v^2[/tex] = [tex]u^2[/tex] + 2as
where v is the final velocity of the ball = 0 m/s
u is the initial speed of the ball = 1.6 m/s
a is the acceleration of the grass
s is the distance the ball travels = 6.5 m
substituting values, we have
[tex]0^2[/tex] = [tex]1.6^2[/tex] + 2(a x 6.5)
0 = 2.56 + 13a
13a = -2.56
a = -2.56/13 = -0.197 m/s^2
If this acceleration of the grass is assumed to be constant, then to the initial speed needed to make the putt will be calculated from
[tex]v^2[/tex] = [tex]u^2[/tex] + 2as
where
v is the final speed at the putt = 0 m/s
u is the initial speed with which the ball is struck = ?
a is the acceleration of the grass = -0.197 m/s^2
s is the distance to the putt = 8 m
substituting values, we have
[tex]0^2[/tex] = [tex]u^2[/tex] + 2(-0.197 x 8)
0 = [tex]u^2[/tex] - 3.152
[tex]u^2[/tex] = 3.152
u = [tex]\sqrt{3.152}[/tex] = 1.78 m/s
Andy took a bus and then walked from his home to downtown.
For the first 1.6 hour, the bus drove at an average speed of 15
km/h. For the next 0.4 hours, he walked at an average speed
of 4.5 km/h. What was the average speed for the whole
journey?
Answer:
12.9
Explanation:
1.6x15=24
0.4x4.5=1.8
24+1.8=25.8
1.6+0.4=2
25.8/2=12.9
A truck has a mass of 3000 kg and a velocity
of 10 m/s. Calculate momentum!
Answer:
[tex] \huge{ \boxed{ \sf{30000 \: kg \: {m/s}^{2}}}}[/tex]
Explanation:
[tex] \text{ \underline{ Given}} : [/tex]
[tex] \star[/tex] Mass of a truck ( m ) = 3000 kg
[tex] \star[/tex] Velocity of a truck ( v ) = 10 m / s
Finding the momentum :
[tex] \boxed{ \sf{momentum \: ( \: p \: ) \: = \: mass \: ∗ \: \: velocity}}[/tex]
[tex] \hookrightarrow{ \sf{momentum \: ( \: p \: ) \: = 3000 \: ∗ \: 10}}[/tex]
[tex] \hookrightarrow{ \sf{ \: momentum \: ( \: p \: ) \: = 30000 \: kg \: m/ {s}^{2} }}[/tex]
Hope I helped!
Best wishes ! :D
~[tex] \sf{TheAnimeGirl}[/tex]
Given:-
Mass of the body (m) = 3000 kgVelocity (v) = 10 m/sTo calculate: Momentum of the body.
We know,
p = mv
where,
p = Momentum,m = Mass &v = Velocity.Thus,
p = (3000 kg)(10 m/s)
→ p = 30000 kg m/s (Ans.)
A 130 g copper bowl contains 100 g of water, both at 20.0°C. A very hot 420 g copper cylinder is dropped into the water, causing the water to boil, with 8.63 g being converted to steam. The final temperature of the system is 100°C. Neglect energy transfers with the environment. (a) How much energy is transferred to the water as heat? (b) How much to the bowl? (c) What is the original temperature of the cylinder? The specific heat of water is 1 cal/g·K, and of copper is 0.0923 cal/g·K. The latent heat of vaporization of water is 539 Cal/kg.
Answer:
a) 4652 cal
b) 8000 cal
Explanation:
Amount of heat transferred
Q1 = mL(v)
Q1 = 8.63 * 539
Q1 = 4652 cal
Amount of heat transferred to the water
Q2 = mcΔT
Q2 = 100 * 1 * (100 - 20)
Q2 = 8000 cal
Q = Q1 + Q2
Q = 4652 + 8000
Q = 12652 cal
b)
Heat transferred to the copper bowl
Q(b) = m(b) * c(b) * ΔT
Q(b) = 0.13 * 0.0923 * (100 - 20)
Q(b) = 0.96 cal
c)
Original heat of the cylinder
Q(c) = Q + Q(b)
m(c) * c(c) * ΔT = Q + Q(b), making ΔT subject of the formula
ΔT = (Q + Q(b))/ (m(c) * c(c))
ΔT = (12652 + 0.96) / (0.42 * 1)
ΔT = 12652.96/0.42
ΔT = 30126.1
A penny is dropped from the top of a tower. It hits the ground below after 2.5 s. How tall was the tower?
A. 24,5m
B. 3.92m
C. 30.6m
D. 60m
Answer:
C. 30.6m
Explanation:
To find the height of the tower, we are to use Newtons law of motion to solve this problem. Since the penny is falling from the top of the tower, it is acted by the acceleration due to gravity. The formula to be used is:
[tex]H=ut+\frac{1}{2}gt^2[/tex]
Where H is the height of the tower, t is the time taken to hit the ground, u is the initial velocity and g is the acceleration due to gravity.
Given that, t = 2.5 s, g =9.8 m/s², u = 0 m/s (at the top of tower)
[tex]H=ut+\frac{1}{2}gt^2\\\\H=0(2.5)+ \frac{1}{2}(9.8)(2.5)^2\\\\H=30.6\ m[/tex]
A small plane flies at a speed of 102 km/h in still air. Suppose the wind blows out from the west (with the air moving east) at a speed of 46 km/h.A) In what direction must the pilot head her plane to move directly north across land?B) How long does it take her to reach a point 300 km directly north of her srarting point?
Answer:
2.68 hours
Explanation:
A.) Suppose the wind blows out from the west (with the air moving east). The pilot should then head her plane to northwest direction to move directly north.
B.) Given that plane flies at a speed of 102 km/h in still air. And the wind blows out from the west (with the air moving east) at a speed of 46 km/h.
The plan resultant speed can be calculated by using pythagorean theorem.
Resultant Speed = Sqrt( 102^2 + 46^2 )
Resultant Speed = Sqrt( 12520)
Resultant speed = 111.89 km/h
From the definition of speed,
Speed = distance/time
Where distance = 300 km
Substitute the resultant speed and the distance into the formula.
111.89 = 300/time
Time = 300/111.89
Time = 2.68 hours
Therefore, it take her 2.68 hours to reach a point 300 km directly north of her srarting point
1. A car travels at 55 km/h for 6.0 hours. How far does it travel?
Answer:
330 km
55*6= 330 km. An easy formula for this is multiplying time with speed.
Explanation:
330 kilometros
55 * 6 = 330 km. Una fórmula fácil para esto es multiplicar el tiempo por la velocidad.
Answer:330 km
Explanation:55*6= 330 km. An easy formula for this is multiplying time with speed.
A small mailbag is released from a helicopter that is descending steadily at 1.20 m/s. (a) After 5.00 s, what is the speed of the mailbag?
Answer:
50.2m/s
Explanation:
Using first equation of motion we have
V= u+gt
V= final speed
U= initial speed
So v = 1.2m/s + 9.8(5s)
50.2m/s
What is the final velocity of a 1400 kg drag racer that’s engine applies 910000 N of Force for 120m
Answer:
468,000,000 m/sExplanation:
According to newtons first law of motion;
Force = mass * acceleration
F = ma
where a = v-u/t
v is the final velocity
u is the initial velocity
t is the time taken
F = m(v-u/t)
Ft = m(v-u)
Given parameters;
F = 910,000N
t = 120m = 120 *60 = 7200secs
m = 1400kg
u = 0m/s
Required parameter
Final velocity v
Substituting the given parameters into the formula to get v;
Ft = m(v-u)
910,000 * 72000 = 1400(v-0)
910,000 * 72000 = 1400v
v = (910,000 * 72000)/1400
v = 910,000 * 720/14
v = 910,000 * 60
v = 468,000,000 m/s
Hence the final velocity of the drag racer is 468,000,000 m/s
what are 7 examples of potential energy
Answer:
Hewo Otaku Kun Here! (UwU)
Explanation:
1. A rock sitting at the edge of a cliff has potential energy. If the rock falls, the potential energy will be converted to kinetic energy.
2. Tree branches high up in a tree have potential energy because they can fall to the ground.
3. A stick of dynamite has chemical potential energy that would be released when the activation energy from the fuse comes into contact with the chemicals.
4. The food we eat has chemical potential energy because as our body digests it, it provides us with energy for basic metabolism.
5. A stretched spring in a pinball machine has elastic potential energy and can move the steel ball when released.
6. When a crane swings a wrecking ball up to a certain height, it gains more potential energy and has the ability to crash through buildings.
7. A set of double "A" batteries in a remote control car possess chemical potential energy which can supply electricity to run the car.
happy to help!
from: Otaku Kun ^^
Adolescents required fewer hours of physical activity than adults. True or False?
Answer:
Aerobic physical activity is better for the cardiovascular system than it is for strength endurance, while anaerobic physical activity is better at building strength endurance than it is at increasing cardiorespiratory fitness.
Therefore true