(9)
2 in
5 in
Perimeter:
Area:

Answer:

B

Step-by-step explanation:

Squares can not be rectangles, Rectangles always have 2 parallel line was longer or shorter then another two but squares' 4 line will always be the same length

Answer:

it will be $1.50 (sure yan ah diyan joke)

Answer:

=8

Step-by-step explanation: becuase this inst high school this is like third grade

Answer:

Hope this helps

Step-by-step explanation:

Answer:

77/180

Step-by-step explanation:

x = 0.42777....

Multiply by 1000   (the number of digits in decimal)

1000x = 427.7777......

  100x =  42.7777......    {Now subtract}

900x =  385

      x = 385/900

x = 77/180

Answer:

5)

V= 1,-4

S) x=1

Min= 1,-4

zeros= (-1,0)(3,0)

6)

V= -2,0

S= x=-2

min= -2,0

zeros= -2,0

Answer:

Simplify the expression.

3x2/2

hope this makes sense lol

Step-by-step explanation:

Answer:

1.5 : 1 (or) 3/2

Step-by-step explanation:

Given expression,

→ 3x/2x

Let's simplify the expression,

→ 3x/2x

→ (3 ÷ 2)(x ÷ x)

→ (1.5)(1)

→ 1.5

Now the required ratio will be,

→ 3 : 2

→ 1.5 : 1

Hence, required ratio is 1.5 : 1.

Step-by-step explanation:

the equation of the line simplify your answer type using integers are fraction indication points are the graph this is that what is the answer is

Answer:

my brother said it is 5 and 10... but i do not know if it is

86.4

....................

Answer:

m<2 = 94°

Step-by-step explanation:

just have to subtract 132-39=94

Answer:

Step-by-step explanation:

[tex] \frac{1}{5} (4x - 7) + \frac{2}{5} x[/tex]

[tex] = \frac{4}{5} x - \frac{7}{5} + \frac{2}{5} x[/tex]

[tex] = \frac{4}{5} x + \frac{2}{5} x - \frac{7}{5} [/tex]

[tex] = \frac{4 + 2}{5} x - 1 \frac{2}{5} x[/tex]

[tex] = \frac{6}{5} x - 1 \frac{2}{5} [/tex]

[tex] = 1 \frac{1}{5} x - 1 \frac{2}{5} x \: (ans)[/tex]

Answer:

Step-by-step explanation:

find the gradient ( M)

M = y2- y1 ÷ x2-x1

M= -3 - (-1)÷(-5)-3 = ¼

find C in the equation (y=mx+c)

(use in y and x values provided)

now replace the values you find in the equation (y=Mx+C)

final answer is

y = ¼x + (-7/4) is the standard form for the line that passes through (3, −1) and (−5, −3)

y=mx=c is the slope intercept form of a line, m is the slope.

We need to find equation of line passing through (3, −1) and (−5, −3)

First we need to calculate slope 'm'.

slope m = y2- y1 / x2-x1

y2=-3, y1=-1, x2=-5, x1=3

m= -3 - (-1)/(-5)-3 = -2/-8=1/4

Equation of line, y=mx+c

find C in the equation (y=mx+c)

C = y-mx

C = -1-1/4(3)= -7/4

now replace the values you find in the equation (y=Mx+C)

y =1/4x-7/4

Hence y =1/4x-7/4 is the equation of line  passes through (3, −1) and (−5, −3).

To learn more on slope intercept form click:

https://brainly.com/question/9682526

#SPJ2

Answer:

0=0

Step-by-step explanation:

Step-by-step explanation:

Here we are given that , the Value of

And we need to find the prove that ,

We know a identity as ,

On cubing both sides of the given equation,

Simplify and then substitute ,

Hence Proved !

Answer:

3500

Step-by-step explanation:

if you rounding 0.7306 up to nearest euro its equal to a dollar

The number of euros that Varia can expect to pay per month to the university will be € 213.

Unit modification is the process of converting the measurement of a given amount between various units, often by multiplicative constants that alter the value of the calculated quantity without altering its impacts.

Varia is studying abroad in Europe. She is required to pay $3,500 (in US dollars) per year to the university, however, she must pay in euros.

We know that the conversion is 0.7306 euros = 1 US dollar. Then the number of euros per year is given as,

⇒ $3,500 x 0.7306

⇒ €2,557.1

Then the number of euros that Varia can expect to pay per month to the university will be given as,

⇒ €2,557.1 / 12

⇒ € 213.09

⇒ € 213

The number of euros that Varia can expect to pay per month to the university will be € 213.

More about the conversion link is given below.

https://brainly.com/question/9414705

#SPJ2

Answer: X=5

Step-by-step explanation:  Because if you subtract 10-(-5) it = 5

The quantity of items you must sell to break even are = 17 items.

To rent a table = $100

The cost of each item = $4

You sold each item at prize = $10

Therefore the gain for each item = 10 - 4

= $6

Therefore, the quantity of items to sell to recover the cost from renting of the table is =

[tex] \frac{100}{6} [/tex]

= 16.6 items

which is approximately = 17 items.

Learn more here:

https://brainly.com/question/21770087

answer:

-8.3733995^12

Answer:

The -1 came from factoring.

The equation is multiplied by 8 because 8 could be pulled from 16x-8.

16 can be divided by 8 2 times and 8 can only divided by 8 once.

so factoring it makes the equation 8(2x-1)

Answer:

270.15

Step-by-step explanation:

Answer:

270.15

Step-by-step explanation:

u just add 52 and 18.72 and subtract it from 340.87

Answer:

(2,2)

Step-by-step explanation:

To draw a graph you find the y value for a couple of x values. For a linear equation like the one given, two points are enough because the graph is always a straight line.

First graph

First, convert the equation into the y=... form:

x - y = 0 => y = x

No choose two x values at random, e.g., 0 and 5:

for x=0, you find y=0, so (0,0) is a point on  the graph

for x=5, you find y=5, so (5,5) is a point on the graph

Now plot these two points and draw a line through them.

Second graph

First, convert the equation into the y=... form:

x + y = 4 => y = 4 - x

No choose two x values at random, e.g., 0 and 5:

for x=0, you find y=4, so (0,4) is a point on  the graph

for x=5, you find y=-1, so (5,-1) is a point on the graph

Now plot these two points and draw a line through them.

Answer:

18°

Step-by-step explanation:

because it is ratio let represent by x

1x+4x+5x=180

10x=180

x=18°

hope that helps

Answer:

10, 80 and 90 degrees.

Step-by-step explanation:

The third angle will  90 - 10 = 80 degrees.

Answer:

yes

Step-by-step explanation:

for every 60 is 90 right so if you take 30 ( half of 60) how much are the 7th graders gonna raise half of 90 is 45 (may I please have brainliest I need it to rank up)

Answer:

hope this helps

Answer:

17 books

Step-by-step explanation:

Answer:

Either [tex]x = (-\pi / 6)[/tex] or [tex]x = (\pi / 6)[/tex].

Step-by-step explanation:

Angle sum identity for cosine:

[tex]\cos(a + b) = \cos(a)\, \cos(b) - \sin(a) \, \sin(b)[/tex].

Double-angle identity for cosine and sine:

[tex]\begin{aligned}& \cos(2\, a)\\ &= \cos^{2}(a) - \sin^{2} (a) \\ &= (\cos^{2}(a) + \sin^{2}(a) - 2\, \sin^{2}(a) \\ &= 1 - 2\, \sin^{2}(a)\end{aligned}[/tex].

[tex]\sin(2\, a) = 2\, \cos(a) \, \sin(a)[/tex].

The secant of an angle is the inverse reciprocal of the cosine of that angle:

[tex]\displaystyle \text{$\sec(x) = \frac{1}{\cos(x)}$ if $\cos(x) \ne 0$}[/tex].

Apply these identities to rewrite the left-hand side of the equation.

[tex]\begin{aligned} & \sec(x) \, \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot (\cos(x)\, \cos(2\, x) - \sin(x)\, \sin(2\, x)) \\ =\; &\cos(2\, x) \\ & - \frac{1}{\cos(x)} \cdot (\sin(x)\, \sin(2\, x)) \\ =\; & \cos(2\, x)\\ & - \frac{1}{\cos(x)} \cdot (\sin(x) \cdot (2\, \sin(x)\, \cos(x))) \\ =\; & \cos(2\, x) - 2\, \sin^{2}(x) \\ =\; & (1 - 2\, \sin^{2}(x)) - 2\, \sin^{2}(x) \\ =\; &1 - 4\, \sin^{2}(x) \end{aligned}[/tex].

Solve the rewritten equation:

[tex]\displaystyle \sin^{2}(x) = \frac{1}{4}[/tex].

Either [tex]\sin(x) = (1/2)[/tex] or [tex]\sin(x) = (-1/2)[/tex].

The question required that [tex](-\pi / 2) \le x \le (\pi / 2)[/tex]. The sine function is one-to-one over this range. In other words, for each [tex]y[/tex] between [tex](-1)[/tex] and [tex]1[/tex], there is exactly one [tex]x[/tex] between [tex](-\pi / 2)[/tex] and [tex](\pi / 2)[/tex] such that [tex]\sin(x) = y[/tex].

If [tex]\sin(x) = (-1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (-\pi / 6)[/tex].

Otherwise, if [tex]\sin(x) = (1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (\pi / 6)[/tex],

Verify that [tex]\cos(x) \ne 0[/tex] for either of the two [tex]x[/tex] values, such that the [tex]\sec(x)[/tex] in the original equation takes a real value.