Answer:
6
Explanation:i dont know
Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. When 3.31 g of magnesium ribbon burns with 8.45 g of oxygen, a bright, white light and a white, powdery product are formed. Enter the balanced chemical equation for this reaction. Be sure to include all physical states.
Answer:
2Mg(s) + O2(g) ----->2MgO(s)
Explanation:
In writing a balanced chemical reaction equation, the rule of thumb is that the number of atoms of each element on the reactant side must be the same as the number of atoms of the same elements on the products side.
Hence for the reaction of magnesium and oxygen shown below;
2Mg(s) + O2(g) ----->2MgO(s)
We notice that there are two atoms each of magnesium and oxygen on both sides of the reaction equation hence the equation is balanced.
What would the IUPAC name be?
Answer:
methyl ethanoate
Explanation:
To name the compound given above, the following must be obtained:
1. Determine the functional group of the compound.
In this case, the functional group is R–COOR' where R and R' are alkyl groups. Thus, the compound is an ester.
2. Determine the longest chain before the functional group and the compound after the functional group.
In this case, the longest chain before the functional group is carbon 2 i.e ethane and the compound after the functional group is methyl.
3. Name the compound by naming the compound after the functional group first, followed by the compound before the functional group and ending it with –oate.
This is illustrated below:
After the functional group => methyl
Before the functional group => ethane
Name of the compound => methyl ethanoate
How many moles are 4.20 * 10 ^ 25 atoms of Ca?
Answer:
~69.744 moles of Ca
Explanation:
Using Avogadro's constant , we know that:
1 mole = 6.022 x 10^23 atoms
S0, the number of moles in 4.20 x 10^25 atoms of Ca:
=(4.20 x 10^25 x 1 )/(6.022 x 10^23)
~69.744 moles of Ca
Q2:How many atoms are in 0.35 moles of oxygen?
1 mole = 6.022 x 10^23 atoms
S0, the number of atoms in 0.35 moles of oxygen:
=[0.35 x (6.022 x 10^23)]
=2.1077 x 10^23 atoms of Oxygen
Hope it helps:)
Which change to an object would double its kinetic energy?
A. Increasing its velocity to twice its original value
B. Increasing its mass to four times its original value
C. Increasing its mass to twice its original value
Ο Ο
D. Increasing its velocity to four times its original value
Answer:
Increasing its mass to twice its original value
Explanation:
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Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2, what is the limiting reactant? (3 points)
SO2
O2
Fe2O3
FeS2
Answer:
O2
Explanation:
for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:
MM FeS2 = 120n = 26.2g / 120g/mol = 0,218 mol
MM O2 = 32n = 5,44g/32g/mol = 0,17 mol
The limiting reactant is
O2
what is the minimum mass of ethylene glycol that must be dissolved in 14.5 kg of water to prevent the solution from freexing at -14.2
Answer:
The minimum mass of ethylene glycol = 6.641 Kg
Explanation:
[tex]\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f[/tex]
Where T_f = freezing point of pure solvent water, 0°C
T_f'= Freezing point of solvent after mixture
K_f = Freezing point depression constant = 1.86 °C/m
Moecular weight of ethylene glycol = 60 g/mol
Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g
molality of ethylene glycol
[tex]m = \frac{weight}{mol.wt} \times\frac{1000}{V}[/tex]
Substitute the values to calculate m
[tex]m = \frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]
by formula
[tex]0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]
calculating we get w = 6641.93 g
Therefore, The minimum mass of ethylene glycol = 6.641 Kg
25.0 g of HCl is added to 100.0 g of water. The density of the resulting solution is 1.19 g/mL. Calculate the molality of
Answer:
The molality is "6.86 m".
Explanation:
Given:
Mass of of HCL,
= 25 g
Mass of water,
= 100 g
Density,
= 1.19 g/mL
Total mass of solution,
= 125 g
Now,
The number of moles of HCl will be:
= [tex]\frac{25}{36.458}[/tex]
= [tex]0.6857[/tex]
The solution volume will be:
= [tex]\frac{125}{1.19}[/tex]
= [tex]105.04 \ mL[/tex]
hence,
The molality will be:
= [tex]\frac{No. \ of \ moles \ of \ solute}{Mass \ of \ solvent (Kg)}[/tex]
= [tex]\frac{0.6857}{0.1}[/tex]
= [tex]6.857 \ m[/tex]
or,
= [tex]6.86 \ m[/tex]
When light is refracted
A.
it changes its direction as it passes into a new medium.
B.
it changes it direction and stays in the same medium.
C.
it keeps moving in the same direction as it passes into a new medium.
D.
it is absorbed as it strikes the surface of a new medium.
[tex]\huge{ \mathfrak{ \underline{ Answer }}}[/tex]
Refraction is a phenomenon in which, light bends itself while moving from from one Medium to another. This occurs due to change in speed of light in different mediums.
Therefore correct option is :
A. it changes its direction as it passes into a new medium.
I hope it helped you !!
[tex] \boxed{ \boxed{\huge{ \mathrm{ \underline{ Answer} \: \: }}}}[/tex]
The Correct option will be : -
A. it changes its direction as it passes into a new medium.
because, light travels with different speeds in different mediums, and this occurs due to difference in optical density of different mediums.
And bending of light depends upon the change in medium,
for example :
when travelling from optically denser medium to optically rarer medium it bends away from normal.when travelling from optically rarer medium to optically denser medium it bends towards the normal._____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \: ☠}[/tex]
What is the entropy change in the environment when 5.0 MJ of energy is transferred thermally from a reservoir at 1000 K to one at 500 K
Answer:
The entropy change in the environment is 3.62x10²⁶.
Explanation:
The entropy change can be calculated using the following equation:
[tex]\Delta S = \frac{Q}{k_{B}}(\frac{1}{T_{f}} - \frac{1}{T_{i}})[/tex]
Where:
Q: is the energy transferred = 5.0 MJ
[tex]k_{B}[/tex]: is the Boltzmann constant = 1.38x10⁻²³ J/K
[tex]T_{i}[/tex]: is the initial temperature = 1000 K
[tex]T_{f}[/tex]: is the final temperature = 500 K
Hence, the entropy change is:
[tex] \Delta S = \frac{5.0 \cdot 10^{6} J}{1.38 \cdot 10^{-23} J/K}(\frac{1}{500 K} - \frac{1}{1000 K}) = 3.62 \cdot 10^{26} [/tex]
Therefore, the entropy change in the environment is 3.62x10²⁶.
I hope it helps you!
i. What is this process of forming energy through combustion called when it occurs in the body?
Answer:
Respiration
Explanation:
Energy, steam and carbondioxide formed.
(1 point) Which compound produces the greatest number of ions when one mole of it is dissolved in water
The question is incomplete, the complete question is;
Which produces the greatest number of ions when one mole dissolves in water? a. NaCl b. NH4Cl c. NH4NO3 d. Na2SO4
Answer:
Na2SO4
Explanation:
If we consider the compounds listed in the options one after the other;
NaCl produces two moles of ions in solution
NH4Cl produces two moles of ions in solution
NH4NO3 produces two moles of ions in solution
Na2SO4 produces three moles of ions in solution
We can see that Na2SO4 produces the greatest number of ions when one mole of the substance is dissolved in water, hence the answer above.
At what temperature do KCl and NaCl have the same solubility?
Answer:
they have the same molar solubility at 44.5 degrees celsius
In the following reaction, C5H12(1) + 8 O2 (g) - 6 H2O (g) + 5 CO2 (g), how many
moles of water (H20) are produced by 14.2 moles of O2?
Answer:
10.65 moles
Explanation:
O2:H2O
8:6
14.2:x
x= 10.65 moles
how many grams of cacl2 can be produced from 50.0 grams of hcl
Answer:
76.0 g
Explanation:
Step 1: Write the balanced equation
2 HCl + Ca(OH)₂ ⇒ CaCl₂ + 2 H₂O
Step 2: Calculate the moles corresponding to 50.0 g of HCl
The molar mass of HCl is 36.46 g/mol.
50.0 g × 1 mol/36.46 g = 1.37 mol
Step 3: Calculate the number of moles of CaCl₂ produced from 1.37 moles of HCl
The molar ratio of HCl to CaCl₂ is 2:1. The moles of CaCl₂ produced are 1/2 × 1.37 mol = 0.685 mol.
Step 4: Calculate the mass corresponding to 0.685 moles of CaCl₂
The molar mass of CaCl₂ is 110.98 g/mol.
0.685 mol × 110.98 g/mol = 76.0 g
a gas tank contains 15 moles of oxygen and 20 moles helium what is apertial pressure of helium in this mixture
Answer:
D0wnload Phot0Math......................
Explanation:
How many atoms in 0.35 moles of Oxygen?
Answer:
11 grams of atoms are in 0.35 moles of oxygen.
A state government is trying to decide between using biomass or solar power
to generate electricity. What advantage does solar power have over biomass?
A. Solar power can be used all day and night.
B. Solar power produces radioactive waste.
C. Solar power is a renewable energy source.
O
D. Solar power produces no carbon dioxide.
Answer: D.Solar power produces no carbon dioxide
Explanation:
Solar power produces no carbon dioxide. The solar panel's carbon footprint is roughly 20 times less than the carbon output of coal-powered electricity sources. Hence, option D is correct.
What is a solar power plant?A solar power plant uses sunlight to get energy. As the sunlight is ample and renewable, one can use it to power up the home and business premises.
Biomass energy is an energy source that comes from plant materials such as wood, corn, sugarcane, and grasses, etc.
However, it needs less capital investment than setting up a solar power plant.
Solar Energy: The major advantage of solar is that the source of energy (sun) is free.
Hence, option D is correct.
Learn more about the solar power plant here:
https://brainly.com/question/23810774
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If 10.0 moles of NO are reacted with 6.0 moles of O2, How many moles of NO2 are produced?
Answer:
We have to find out which of the reactants that is the Limiting Reagent.
The Limiting Reagent is the reactant that finishes before reaction is complete or simply put... Its the reactant that's NOT IN EXCESS.
We use the reactant that's not in excess to find the Number of moles of product because once that reactant is used up.... The reaction also ends or stops(hence the name;Limiting reactant).
Now
We have 10moles of NO
We also have 6moles of O2
The balanced equation of Reaction is
2NO + O2 ===> 2NO2
Now
looking at this equation
2moles of NO is required to react with 1mole of O2
So since we have NO=10moles and O2 = 6moles
It means that
20moles of NO is required to react with 6 moles of O2.
We were only given 10moles of NO and this is not even enough to react with the whole 6moles of Oxygen because from what we just discovered... We need 20moles of NO to react with all 6moles of O2.
So
This means that NO is the LIMITING REACTANT. It is in short supply and would be used up before the whole reaction takes place.
So we use the limiting reactant to find the Number of Moles of Product formed.
Now
From the eqn of reaction
2moles of NO forms 2Moles of NO2.
Their Mole ratio is 2:2 or 1:1...
This simply means that an equal amount of NO2 will be Produced
MEANING.... 10 MOLES OF NO2 IS PRODUCED.
HAVE A GREAT DAY!!!
An archaeologist finds 14C in a sample of material to be decaying at 20 Geiger Counter clicks per second. A modern equivalent sample of the same material decays at 160 clicks per second. The half-life of 14C is 5,730 years. How old is the sample
Answer:
17188 years
Explanation:
Recall the formula;
0.693/t1/2 = 2.303/t log(No/N)
t1/2 = half life of 14C
No = initial activity of 14C
N = activity of 14C at time t
t = age of the sample
Substituting values
0.693/5730= 2.303/t log(160/ 20)
1.21 * 10^-4= 2.0798/t
t = 2.0798/1.21 * 10^-4
t = 17188 years
What volume of O2 at NTP is generated from 7.84 g of
FeSO, (NH4)2SO4.6H2O?
Answer:1.12 g
Explanation:Molar mass of compound FeSO4(NH4)2SO4.6H2O = 392.14 g mol-1
Number of moles of compound in 7.84g sample = 7.84 g/ 392.14 g mol-1
= 0.02 mole
1 mole of sample contain 1 mole of Fe
So, 0.02 mole of sample would contain 0.02 moles of Fe.
Mass of Fe equivalent to 0.02 mole = 0.02 mol x molar mass of Fe
= 0.02 mol x 55.84 g mol-1
= 1.12 g
If 2.45 g of iron are placed in 1,5 L of 0.25M HCl, how many grams of FeCl2 are obtained? Identify the limiting and excess reactants in this single replacement reaction. Fe + 2HCl = FeCl2 + H2
Answer:
5.56g of FeCl2 can be produced
Explanation:
To solve this question we must find the moles of each reactant. With the moles and the chemical equation we can find limiting reactant. With limiting reactant we can find the moles of FeCl2 and its mass as follows:
Moles HCl:
1.5L * (0.25mol / L) = 0.375 moles HCl
Moles Fe -Molar mass: 55.845g/mol-
2.45g * (1mol / 55.845g) = 0.0439 moles Fe
For a complete reaction of 0.375 moles HCl are needed:
0.375 moles HCl * (1mol Fe / 2mol HCl) = 0.1875 moles Fe
As there are just 0.0439 moles Fe, Fe is limiting reactant
1mol of Fe produce 1 mole of FeCl2, 0.0439 moles Fe produce 0.0439 moles of FeCl2. The mass is:
Mass FeCl2 -Molar mass: 126.751g/mol:
0.0439 moles Fe * (126.751g / mol) =
5.56g of FeCl2 can be producedIs HNO3 an acid or a base
I NEED HELP ASAP
Answer:
HNO3 is a potent acid, a base, a nitrating agent and a heavy oxidising agent at times. In the presence of a stronger acid, it serves as a base.
Explanation:
Answer:
It is a strong acid
Explanation:
How many molecular orbitals are present in the valence band of a sodium crystal with a mass of 4.14 g
Answer:
Explanation:
Given that:
The mass of sodium crystal = 4.14 g
As a result, the number of atoms in the sodium crystal is:
[tex]=4.14 \g \times \dfrac{ 1 \ mol}{23.0 \ g }\times \dfrac{6.023 \times 10^{23} \ atoms}{1 \ mol}[/tex]
= 1.084 × 10²³ atoms
In the valence orbital of the sodium atom, there is just one electron.
As a result, the number of molecular orbitals produced by these atoms is= 1.084 × 10²³ molecular orbital
Because valence bands are created from occupied molecular orbitals, the number of valence bands created from the aforementioned molecular orbitals is:
[tex]= \dfrac{ 1.084 \times 10^{23}}{2}[/tex]
= 5.420 × 10²² orbitals.
Jared has a genetic disorder.
which is the most likely reason Jared has the disorder?
Answer:
parents / genetics
Explanation:
a genetic disorder most likely comes from a family relative weather it being mom,dad, grandpa, uncle,ect.
The largest pieces being dragged along the streambed are undergoing the process called ________. pushing saltation traction suspension solution
Answer:
saltation
Explanation:
Saltation is the transportation of particles by fluids such as by winds and water. It takes place when loose matter is removed from the sea bed and gets carried by the fluid back to the surface. Examples include pebbles, sand, and soil. Saltation layers can form during avalanches.I need help Type th temperature (in Kelvin) in the left column and the volumes in the right column, being sure to keep pairs of data together. then click resize window to fit data.
the data appears to be
linear
quadratic
exponential
logarithmic
Answer:
Linear
Explanation:
If 143.56 mL of 0.6653 M ammonium carbonate reacts with 175.37 mL of 0.8732 M chromium(III) sulfate in a double replacement reaction and produces 7.543 g of chromium(III) carbonate, what is the percent yield of the reaction
hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((
Answer:
Boiling - The process of a liquid changing to gas.
Boiling point - The temperature at which a liquid boils.
Condensing - The process of a gas changing to a liquid.
Distillate - The liquid collect from the condenser.
Residue - The liquid left behind in the distillation flask.
Vapour - Another name for gas.
Hope it helps :)
Brainiest and 10 Points
Which has a HIGHER frequency?
A. Visible
B. Ultraviolet
Answer:
B. Ultraviolet
Explanation:
UV has a higher frequency and shorter wavelength than visible light
What mass of Cu(s) is electroplated by running 30.0 A of current through a Cu2 (aq) solution for 4.00 h
Answer:
The correct answer is "142 g".
Explanation:
According to the question,
⇒ [tex]Cu^2+(aq)+2e^ ------> Cu(s)[/tex]
where,
Z = 2
F = 96500c
C = 30 A
t = 4h
= [tex]4\times 60\times 60[/tex]
= [tex]14400 \ sec[/tex]
We know that,
Atomic mass of Cu(M) = 63.5 g/mole
Now,
⇒ [tex]W=\frac{Mct}{ZF}[/tex]
On putting the values, we get
[tex]=\frac{63.5\times 30\times 14400}{2\times 96500}[/tex]
[tex]=\frac{27432000}{193000}[/tex]
[tex]=142 \ g[/tex]