6 soccer players share 5 oranges as fraction

The dimensions of the rectangle with the largest possible area and a perimeter of 120 meters are 30 meters by 30 meters.

Explanation: -

To find the dimensions of a rectangle with a perimeter of 120 meters and the largest possible area, we need to follow these steps:

Step 1: Given the dimensions x and y, we have the area A = xy. then the perimeter of the rectangle is 2x + 2y = 120. Solving for y, we get y = 60 - x.

Step 2: To maximize the area A = xy, we substitute y with the expression from step 1: A(x) = x(60 - x) = 60x - x^2, where 0 < x < 60.

To find the maximum area, we can use calculus to find the critical points.

Step 3: Find the derivative of the area function, use the formula

d/dx(x^n) =nx^n-1

so that derivative is A'(x) = 60 - 2x.

Step 4: Set A'(x) = 0 and solve for x. In this case, 60 - 2x = 0, so x = 30.

Step 5: Plug x = 30 back into the expression for y: y = 60 - x = 60 - 30 = 30.

The dimensions of the rectangle with the largest possible area and a perimeter of 120 meters are 30 meters by 30 meters.

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According to the information, we can express the vector w as a linear combination of v1, v2, and v3 like this: w = -v1 - 5v2 - 3v3

We can express the vector w as a linear combination of v1, v2, and v3. Let's say:

w = c1 v1 + c2 v2 + c3 v3

We can find the values of c1, c2, and c3 using the dot product properties of orthogonal vectors. Since v1, v2, and v3 are orthogonal:

w ⋅ v1 = (c1 v1 + c2 v2 + c3 v3) ⋅ v1 = c1 (v1 ⋅ v1) = 6c1

w ⋅ v2 = (c1 v1 + c2 v2 + c3 v3) ⋅ v2 = c2 (v2 ⋅ v2) = 18c2

w ⋅ v3 = (c1 v1 + c2 v2 + c3 v3) ⋅ v3 = c3 (v3 ⋅ v3) = 25c3

Using the given values, we can set up a system of equations:

-6 = 6c1 + 0c2 + 0c3

-90 = 0c1 + 18c2 + 0c3

-75 = 0c1 + 0c2 + 25c3

Solving for c1, c2, and c3, we get:

c1 = -1

c2 = -5

c3 = -3

Therefore, we have:

w = -v1 - 5v2 - 3v3

Note: The solution is not unique, as any linear combination of v1, v2, and v3 that satisfies the given dot product conditions would work.

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The maximum amount of funds that Entrepreneur Bill should raise typically depends on various factors such as the growth potential of the business, the market demand, and the financial needs of the company.

However, a general rule of thumb is that entrepreneurs should not raise more than 25% to 30% of the company's worth in a single fundraising round.

So, if his company is worth $15 million, the maximum amount of funds that Entrepreneur Bill should raise is around $3.75 million. This will help him maintain a fair ownership stake in the company while also ensuring that he has enough funds to achieve his business goals.

It is important to note that this is just a rough estimate and every business is unique. Entrepreneur Bill should seek the advice of experienced investors or financial advisors to determine the appropriate amount of funds to raise for his specific business needs.

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Answer:

∠ A = 60° , ∠ B = 30°

Step-by-step explanation:

using the cosine ratio in the right triangle

cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{7}{14}[/tex] = [tex]\frac{1}{2}[/tex] , then

∠ A = [tex]cos^{-1}[/tex] ( [tex]\frac{1}{2}[/tex] ) = 60°

the sum of the 3 angles in Δ ABC = 180°

∠ A + ∠ B + ∠ C = 180°

60° + ∠ B + 90° = 180°

∠ B + 150° = 180° ( subtract 150° from both sides )

∠ B = 30°

The range for the southern cities is 145 mi² greater than the range for the northern cities.

We must determine the difference between the largest and smallest areas in each group in order to determine the range of the cities.

Minneapolis has the smallest area (58 miles2) and the largest (305 miles2) of the northern cities. Therefore, the northern cities' range is:

305 mi² - 58 mi² = 247 mi²

For the southern cities, the smallest area is 111 mi² (Orlando) and the largest area is 503 mi² (Los Angeles). So the range for the southern cities is:

503 mi² - 111 mi² = 392 mi²

To find how much greater the range is for the southern cities, we subtract the range for the northern cities from the range for the southern cities:

392 mi² - 247 mi² = 145 mi²

As a result, the cities in the south have a range that is 145 miles longer than the cities in the north.

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Answer:

54 square centimeters

Step-by-step explanation:

The area of a trapezium can be calculated by taking the average of the parallel sides and multiplying by the height. So, the area of this trapezium is:

(7 + 11) / 2 * 6 = 9 * 6 = 54 cm^2

Therefore, the area of the trapezium is 54 square centimeters.

Hope this helps!

Answer:

the area of the trapezium is 54 square centimeters.

Step-by-step explanation:

Given:

Parallel side 1 = 7cm

Parallel side 2 = 11cm

Height = 6cm

We can use the formula for the area of a trapezium, which is:

Area = (Sum of parallel sides / 2) × Height

Plugging in the values we have:

Area = ((7 + 11) / 2) × 6

Now, let's simplify the equation:

Area = (18 / 2) × 6

Area = 9 × 6

Area = 54

So, the area of the trapezium is 54 square centimeters.

The inverse Laplace transform of 1/s(s^2 + 36) using the convolution theorem is (1/6)sin(6t) + (1/6)cos(6t).

First, we need to find the Laplace transform of the given function 1/s(s^2 + 36). We can use the table of Laplace transforms to find that L{1/s(s^2 + 36)} = (1/6)sin(6t).

Next, we need to find the Laplace transform of the function f(t) = cos(6t)u(t), where u(t) is the unit step function. Using the table of Laplace transforms, we find that L{cos(6t)u(t)} = (s)/(s^2 + 36).

Now, we can apply the convolution theorem, which states that the inverse Laplace transform of the product of two functions in the frequency domain is equal to the convolution of their inverse Laplace transforms in the time domain.

The convolution of (1/6)sin(6t) and (s)/(s^2 + 36) is given by the integral of (1/6)sin(6(t - τ)) * (s)/(s^2 + 36) dτ from 0 to t.

To solve the integral, we can use partial fraction decomposition. We can express (s)/(s^2 + 36) as (A/s) + (B(s)/(s^2 + 36)), where A and B are constants to be determined.

Solving for A and B, we get A = 1/6 and B(s) = -s/6.

Substituting A and B(s) back into the integral and evaluating the integral, we get (1/6)sin(6t) + (1/6)cos(6t).

Therefore, the inverse Laplace transform of 1/s(s^2 + 36) using the convolution theorem is (1/6)sin(6t) + (1/6)cos(6t).

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Answer:

(x, y) (124/7, 62/7)

Step-by-step explanation:

substitute x with 2y we get

4(2y)-y=62

8y-y=62

7y=62

y=62/7

substitute the value of y into the second eqaution

2(62/7)=x

124/7=x

substitute your values of x and y into the first eqaution to check if they are solutions

4(124/7)-62/7=62

you will get

62=62

which means they are solutions

Answer:

4

Step-by-step explanation:

(b + c)/2 = 6

b + c = 12

(a + b + c + d)/4 = 5

(a + 12 + d) = 20

a + d = 8

Hence,

the sum of the largest and smallest is 8. The mean has to be 8/2 = 4.

Hope this helps and be sure to mark this as brainliest! :)

The following parts can be answered by the concept of Combination.

a.  The total number of ways to award prizes is 100 x 99 x 98 = 970,200.

b. The total number of ways to award prizes in this scenario is 99 x 98 x 97 = 941,094.

c.  The total number of ways to award prizes in this scenario is 98 x 97 x 96 = 912,192.

d. The grand prize winner is a person holding ticket 8,11 or 23 is 3 x 99 x 98 = 29,178.

a) There are a total of 100 choices for the first prize, 99 choices for the second prize (since one person already won a prize), and 98 choices for the third prize (since two people already won prizes). So, the total number of ways to award prizes is 100 x 99 x 98 = 970,200.

b) If person holding the ticket 23 must get a prize, then there are only 99 choices for the first prize (since ticket 23 is already taken), 98 choices for the second prize, and 97 choices for the third prize. So, the total number of ways to award prizes in this scenario is 99 x 98 x 97 = 941,094.

c) If the person holding ticket 8 and the person holding ticket 11 must win prizes, then there are only 98 choices for the first prize (since tickets 8 and 11 are already taken), 97 choices for the second prize, and 96 choices for the third prize. So, the total number of ways to award prizes in this scenario is 98 x 97 x 96 = 912,192.

d) If the grand prize winner is a person holding ticket 8,11 or 23, then there are only 3 choices for the first prize (since only these three tickets are eligible for the grand prize), 99 choices for the second prize (since one person already won a prize and the grand prize winner is not eligible for the second prize), and 98 choices for the third prize (since two people already won prizes). So, the total number of ways to award prizes in this scenario is 3 x 99 x 98 = 29,178.

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The arrow symbolizes the directional connection from each member in set x to its corresponding member in set y. The members of set y are evident squares of their respective counterparts in set x.

Here is an arrow diagram to show the relation between the sets x and y, where y is the set of all elements in x squared:

     (1, 4, 9)

        / \

       /   \

      /     \

  1, 4, 9  -->  1, 4, 9, 16, 25, 36

       \     /

        \   /

         \ /

(3, 2, 1, -1, -2, -3)

      The arrow symbolizes the directional connection from each member in set x to its corresponding member in set y. The members of set y are evident squares of their respective counterparts in set x.

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The average length of the queue (Lq) for an M/G/1 system with λ = 20, μ = 35, and σ = 0.005 is Lq = 0.3926 (option B).

To find the average length of the queue (Lq) in an M/G/1 system, we can use the Pollaczek-Khintchine formula:

Lq = (λ² * σ² + (λ/μ)²) / (2 * (1 - (λ/μ)))

Given λ = 20 (arrival rate), μ = 35 (service rate), and σ = 0.005 (standard deviation of service time):

1. Calculate λ/μ: 20/35 = 0.5714
2. Calculate 1 - (λ/μ): 1 - 0.5714 = 0.4286
3. Calculate λ² * σ²: (20²) * (0.005²) = 0.01
4. Calculate (λ/μ)²: (0.5714²) = 0.3265
5. Plug these values into the Pollaczek-Khintchine formula:

Lq = (0.01 + 0.3265) / (2 * 0.4286) = 0.3926 . (B)

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The distance across the lake (DE) is 207.68 m.

The corresponding side lengths of two triangles that are similar are always proportional to each other.

Thus,

ΔCDE  and ΔCFG are similar to each other

FG = 142.1 m

FC = 130 m

DF = 60 m

DC = 130 + 60 = 190 m

Thus, DE/FG = DC/FC

Substituting

DE/142.1 = 190/130

DE = (190*142.1)/130

DE =  207.68 m (nearest hundredth).

Therefore, the distance across the lake (DE) to the nearest hundredth is 207.68 m.

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Complete Question

Check attached image

Answer:

1) Statistical

2)Not statistical

3)Not statistical

Step-by-step explanation:

If your not sure just visit  it will tell you the answers.

Hope it helps!!

To complete the table and find the derivative of the function y = (9x^(3/2))/x without using the quotient rule, we'll rewrite, differentiate, and simplify the function and get dy/dx =  27/2x^(1/2) - 9x^(1/2) .

Step 1: Rewrite the function
y = 9x^(3/2) * x^(-1) (multiply the x term in the denominator by -1 to rewrite the division as multiplication)
Step 2: Differentiate the function using the power rule (dy/dx = nx^(n-1))
dy/dx = 9(3/2)x^(3/2 - 1) - 9x^(3/2 - 1)
Step 3: Simplify the expression
dy/dx = 27/2x^(1/2) - 9x^(1/2)

Your answer: To find the derivative of the function y = (9x^(3/2))/x without using the quotient rule, we rewrote the function, differentiated it, and simplified the result to obtain the derivative dy/dx = 27/2x^(1/2) - 9x^(1/2).

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The perimeter is 58.9

Here we have an isosceles triangle.

To find the length of the sides that aren't the base we can use a trigonometric equation.

sin(60°) = 4*√15/hypotenuse

hypotenuse = 4*√15/sin(60°) = 18.8

The side in the left also measures that.

Now we need the base, we can define the base as:

(b/2)² + (4√15)²  = 18.8²

b²/4 + 16*15 =  18.8²

b = √((18.8² - 16*15)*4)

b = 21.3

Then the perimeter is:

21.3 + 18.8 + 18.8 = 58.9

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Step-by-step explanation:

Part 1:

We know that y(x,θ) = θ0 + ∑d=1Dθdxnd and x′n = xn + ϵn.

So,

y(x′,θ) = θ0 + ∑d=1Dθd(xnd+ϵnd)

= θ0 + ∑d=1Dθdxnd + ∑d=1Dθdϵnd

Since ϵn is independent of the weights θ, we can take it outside the summation:

y(x′,θ) = y(x,θ) + ∑d=1Dθdϵnd

Therefore, we have shown that y(x′,θ) = y(x,θ) + ∑d=1Dθdϵnd.

Part 2:

The sum-of-squares error function for the noise sample set x′ is given by:

ED'(θ) = 1/2 ∑n=1N [y(x′n,θ) - yn]^2

Using the expression for y(x′,θ) derived in part 1, we have:

ED'(θ) = 1/2 ∑n=1N [y(xn,θ) + ∑d=1Dθdϵnd - yn]^2

Expanding the square term and taking the expectation with respect to the noise ϵ, we get:

E[ED'(θ)] = E[1/2 ∑n=1N [(y(xn,θ) - yn)^2 + 2(y(xn,θ) - yn)∑d=1Dθdϵnd + (∑d=1Dθdϵnd)^2]]

Now, since ϵ is a zero-mean Gaussian noise with variance 2σ^2, we have:

E[ϵnd] = 0

E[ϵnd^2] = σ^2

Using these properties, we can simplify the above expression:

E[ED'(θ)] = E[1/2 ∑n=1N [(y(xn,θ) - yn)^2 + 2(y(xn,θ) - yn)∑d=1DθdE[ϵnd] + (∑d=1Dθd^2E[ϵnd^2])]]

= E[1/2 ∑n=1N (y(xn,θ) - yn)^2] + E[θ]^T E[Z] E[θ]

where Z is a (D-1) x (D-1) matrix with (i,j)-th element being E[ϵiϵj], and E[Z] is the matrix obtained by adding σ^2 to the diagonal elements of Z. The terms involving the cross-product of ϵ are ignored as they are zero.

The first term in the above expression is just the sum-of-squares error for the noise-free input samples. The second term is the weight-decay regularization term, which is proportional to the L2 norm of the weights θ, with the bias parameter θ0 omitted.

Therefore, we have shown that:

E[ED'(θ)] = (theta)^T(theta) + z

where z is the weight-decay regularization term.

Sample size of at least 23 is required to be 99% confident that our estimate of the population mean is within ±6.

To calculate the required sample size, we can use the formula:

n = (Zα/2 * σ / E)²
Where:
n = sample size
Zα/2 = the Z-score for the desired confidence level, which is 2.58 for 99%
σ = the population standard deviation (assumed to be given)
E = the desired margin of error, which is 6 in this case.

Substituting these values, we get:

n = (2.58 * σ / 6)²

Since the population standard deviation is not given, we cannot find the exact sample size. However, we can use an estimated value of σ based on prior knowledge or a pilot study.

For example, if we assume σ = 10, then the sample size required would be:

n = (2.58 * 10 / 6)² = 22.25 ≈ 23

Therefore, we would need a sample size of at least 23 to be 99% confident that our estimate of the population mean is within ±6.

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The average rate of change of the function between the given values of x. y = 6 3x 0.5x2 between x = 4 and x = 6 is 8

To find the average rate of change of the function y = 6 + 3x + 0.5x^2 between x = 4 and x = 6, we need to find the difference between the y-values at x = 6 and x = 4, and divide by the difference between the x-values.
When x = 4, y = 6 + 3(4) + 0.5(4)^2 = 22
When x = 6, y = 6 + 3(6) + 0.5(6)^2 = 36
The difference in y-values is 36 - 22 = 14.
The difference in x-values is 6 - 4 = 2.
Therefore, the average rate of change of the function between x = 4 and x = 6 is 14/2 = 7.
So, the average rate of change of the function is 7 units per 1 unit change in x between the given values of x.
To find the average rate of change of the function y = 6 + 3x + 0.5x^2 between x = 4 and x = 6, follow these steps:
1. Evaluate the function at x = 4 and x = 6:
y(4) = 6 + 3(4) + 0.5(4^2) = 6 + 12 + 8 = 26
y(6) = 6 + 3(6) + 0.5(6^2) = 6 + 18 + 18 = 42
2. Calculate the average rate of change:
Average rate of change = (y(6) - y(4)) / (6 - 4) = (42 - 26) / 2 = 16 / 2 = 8
So, the average rate of change of the function between x = 4 and x = 6 is 8.

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The area of the kite the new one is 70 cm^2.

The area of a kite is given by half the product of its diagonals. Let's call the diagonals of kite ABCD d1 and d2, and the diagonals of the new kite d1' and d2'.

We know that d1' = 2d1 and d2' = 2d2, so we can write:

Area of new kite = 1/2 * d1' * d2'

= 1/2 * (2d1) * (2d2)

= 2 * (1/2 * d1 * d2)

= 2 * Area of kite ABCD

= 2 * 35 cm^2

= 70 cm^2

Therefore, the area of the new kite is 70 cm^2.

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Answer: 8,600

Zach's gross capital gain can be calculated as follows:

Total proceeds from selling the stock = 200 shares x $43/share = $8,600

Total cost of buying the stock = 200 shares x $21.35/share = $4,270

Gross capital gain = Total proceeds - Total cost = $8,600 - $4,270 = $4,330

Therefore, Zach's gross capital gain from selling 200 shares of Goshen stock is $4,330.

The required answer is 2y = x / (x + 2)

To find the equation of the slant asymptote for y = (x^2)/(2x + 2), we can perform long division or synthetic division to divide x^2 by 2x + 2. The result is y = (1/2)x - 1. Therefore, the equation of the slant asymptote is y = (1/2)x - 1.

The asymptotes most commonly encountered in the study of calculus are of curves of the form y = ƒ(x). These can be computed using limits and classified into horizontal, vertical and oblique asymptotes depending on their orientation. Horizontal asymptotes are horizontal lines that the graph of the function approaches as x tends to +∞ or −∞. As the name indicates they are parallel to the x-axis. Vertical asymptotes are vertical lines (perpendicular to the x-axis) near which the function grows without bound.

It seems there might be some typos in the given function. I believe you meant the function to be written as y = (x^2 + 2x) / 2y. To find the equation of the slant asymptote, follow these steps:

Step 1: Rewrite the given function with proper notation:
y = (x^2 + 2x) / (2y)

Step 2: Solve for x in terms of y:
2y = x^2 + 2x
2yx = x^2 + 2x

Step 3: Factor out x on the right side:
2yx = x(x + 2)

Step 4: Divide both sides by (x + 2):
2y = x / (x + 2)

This equation represents the slant asymptote of the given function.

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The linear interpolation spline between points (0,1) and (1,0) for x=1/2 is y=1/2. The quadratic interpolation spline using (0,1), (1,0), and (5/2,0) is y=-8/5x^2 + 9/5x + 1 for x in [1/2,5/2].

To find the linear interpolation spline and quadratic interpolation spline, we can use the following formulas

For linear interpolation, the spline between data points (x1,y1) and (x2,y2) is given by

y = y1 + (y2-y1)/(x2-x1)*(x-x1)

For quadratic interpolation, the spline between data points (x1,y1), (x2,y2) and (x3,y3) is given by

y = y1*((x-x2)(x-x3))/((x1-x2)(x1-x3)) + y2*((x-x1)(x-x3))/((x2-x1)(x2-x3)) + y3*((x-x1)(x-x2))/((x3-x1)(x3-x2))

To find the linear interpolation spline, we can use the points (0,1) and (1,0) since they are the nearest neighbors to x = 1/2:

y = 1 + (0-1)/(1-0)*(1/2-0) = 1/2

Therefore, the linear interpolation spline is y = 1/2 for x in [1/2,1].

To find the quadratic interpolation spline, we need to use three neighboring points. We can use (0,1), (1,0), and (5/2,0) since they are the three nearest neighbors to x = 1/2. Substituting these values into the formula, we get

y = 1*((x-1)(x-5/2))/((0-1)(0-5/2)) + 0*((x-0)(x-5/2))/((1-0)(1-5/2)) + 0*((x-0)(x-1))/((5/2-0)(5/2-1))

Simplifying, we get:

y = -8/5x^2 + 9/5x + 1

Therefore, the quadratic interpolation spline is y = -8/5x^2 + 9/5x + 1 for x in [1/2,5/2].

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Answer:

The shape formed is a quadrilateral.

Step-by-step explanation:

The four points A(-1,0), B(0,2), C(4,0), and D(3,-2) can be used to form a quadrilateral. To identify the shape formed by these points, we can use the distance formula to find the length of each side of the quadrilateral, and then compare the side lengths.

AB: Distance between A(-1,0) and B(0,2)

= sqrt((0 - (-1))^2 + (2 - 0)^2)

= sqrt(1 + 4)

= sqrt(5)

BC: Distance between B(0,2) and C(4,0)

= sqrt((4 - 0)^2 + (0 - 2)^2)

= sqrt(16 + 4)

= sqrt(20)

= 2 sqrt(5)

CD: Distance between C(4,0) and D(3,-2)

= sqrt((3 - 4)^2 + (-2 - 0)^2)

= sqrt(1 + 4)

= sqrt(5)

DA: Distance between D(3,-2) and A(-1,0)

= sqrt((-1 - 3)^2 + (0 - (-2))^2)

= sqrt(16 + 4)

= 2 sqrt(5)

Since the length of AB is not equal to the length of CD, and the length of BC is not equal to the length of DA, we can conclude that the quadrilateral formed by these four points is not a parallelogram or a rhombus. Additionally, since the length of AB is not equal to the length of CD, we can conclude that the quadrilateral is not a kite.

By comparing the angles formed by the line segments AB, BC, CD, and DA, we can see that the angle at B is a right angle, while the other three angles are all acute angles. This indicates that the quadrilateral is a trapezoid. Specifically, it is a right trapezoid, since it has one right angle.

The probability that z is between -2.33 and 2.33 for a standard normal distribution with a mean of 0 and standard deviation of 1 is approximately 0.9802, or 98.02%. Here, he probability that z is between -2.33 and 2.33 for a standard normal distribution with a mean of 0 and a standard deviation of 1, you'll need to use a standard normal distribution table or a calculator with a built-in z-table function.

Step-by-step explanation:
Step:1. Identify the given values: Mean (µ) = 0, Standard Deviation (σ) = 1, and the range of z-scores is between -2.33 and 2.33.
Step:2. Use a standard normal distribution table or a calculator with a built-in z-table function to find the probabilities associated with z = -2.33 and z = 2.33.
Step:3. Look up the probability of z = -2.33 in the table, which should be approximately 0.0099.
Step:4. Look up the probability of z = 2.33 in the table, which should be approximately 0.9901.
Step:5. Subtract the probability for z = -2.33 from the probability for z = 2.33 to find the probability of z being between these two values: P(-2.33 < z < 2.33) = P(z = 2.33) - P(z = -2.33) = 0.9901 - 0.0099 = 0.9802
The probability that z is between -2.33 and 2.33 for a standard normal distribution with a mean of 0 and standard deviation of 1 is approximately 0.9802, or 98.02%.

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Answer:

9

Step-by-step explanation:

because if she can make 3 in 15minutes then 45 minutes is triple the time so triple the bracelets please give brainliest bye have a good day :D

Answer:

yes clearly

Step-by-step explanation:

using rules of divisibility it is divisible

using your calculator it is divisible

the answer is 44

Answer:

To find the best deal, we must get the value of 1 oz for each of the boxes.

Box 1: 1.12 divided by 16 equals 0.07 / oz

Box 2: 1.92/32 equals 0.06 / oz

5 LB Box = 80 OZ

Box 3: 4/80 = 0.05 / oz

The third box is the best deal.

In a right-skewed distribution, the correct answer is b. the median is less than the mean. In a right-skewed distribution, the data has a longer tail on the right side, indicating that there are more values greater than the mean. This causes the mean to be greater than the median.

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