6. Find the principal value of each of the following to the nearest minute:
Arccsc (1.607)
A. 38°64
B. 39°24'
C. 38°48'
D. 38°32'
E. 39°37'
F. 38°29'

Answer:

For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range

Step-by-step explanation:

The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2.

The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2.

The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2.

Answer:

see explanation

Step-by-step explanation:

the equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

f(x) = 3(x - 1)² + 2 ← is in vertex form

with vertex = (1, 2 )

The domain of a parabola exists for all real values of x

domain : x ∈ R

the range of the parabola are the values of y from the y- coordinate of the vertex, upwards.

range : y ≥ 2

Answer:

.35 < 38% < 3/5

Step-by-step explanation:

.35 is the same as 35 percent which is less than 38, and 3/5 when divides is .60 turned into percent is 60 percent

Answer:

5.7 and 4.2

Step-by-step explanation:

Outside diagonal = √a² + a² = √4² + 4² = 4√2

= 5.7

Inside diagonal = √b² + b² = √3² + 3² = 3√2

= 4.2

To increase sales, an online clothing store began giving a 50% off coupon to random customers Six customers each made purchases from the website the binomial random variable and  mean and standard deviation of X  is mathematically given as

[tex]X ~ Bin(n = 6, p = 0.2)[/tex]

x= 0.9798

Generally, the equation for is mathematically given as

P(coupon) = 1/5

P(coupon)= 0.2

the binomial distribution

[tex]X ~ Bin(n = 6, p = 0.2)[/tex]

Therefore, The mean and standard deviation of X

[tex]пВ = np \\np= 6* 0.2 = 1.2\\[/tex]

[tex]x=\sqrt{ np(1 - p)} \\ x=\sqrt{ 6 * 0.2 + (1 -0.2)} \\[/tex]

x= 0.9798

In conclusion, mean and standard deviation of X

x= 0.9798

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Answer:

[tex]\tan U = 1[/tex]

Step-by-step explanation:

[tex]\text{Apply Pythagorean theorem,}\\\\~~~~~~\text{Hypotenuse}^2 = \text{Base}^2 + \text{Perpendicular}^2\\\\\implies UT^2 = UV^2 +VT^2\\\\\implies UV^2 = UT^2 -VT^2\\\\\implies UV^2 = \left(7\sqrt 2 \right)^2 - 7^2\\\\\implies UV^2 = 49(2)-49\\\\\implies UV^2 = 49\\\\\implies UV = \sqrt{49} \\\\ \implies UV = 7[/tex]

[tex]\text{Now,}\\\\~~~~~~~~\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}\\\\\\\implies \tan U = \dfrac{7}{7}\\\\\\\implies \tan U = 1[/tex]

Answer:

2

Step-by-step explanation:

Start by simplifying the expression:

[tex]4(x-3)+5x-x^2[/tex]

Use distribution:

[tex]4x-4(3)+5x-x^2\\4x-12+5x-x^2[/tex]

Add like terms:

[tex]9x-12-x^2[/tex]

Now, substitute the given value of x into the expression:

[tex]9(2)-12-2^2\\18-12-4\\6-4\\2[/tex]

Answer:

2

Step-by-step explanation:

Given: 4(x − 3) + 5x − x²

Substitute 2 for the value of x in the expression and simplify:

➜ 4(2 − 3) + 5(2) − (2)²

➜ 4(−1) + 10 − 4

➜ -4 + 10 - 4

➜ 2

Therefore, the value of the expression when x equals 2 is 2.

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Step-by-step explanation:

= 5 • ( 4• x )

= 5 ( 4x )

= 20x

[tex]...[/tex]

Well, let's use the Euclidean algorithm:

164 = 4×37 + 16

37 = 2×16 + 5

16 = 3×5 + 1

Then working backwards,

1 = 16 - 3×5

1 = 16 - 3×(37 - 2×16) = 7×16 - 3×37

1 = 7×(164 - 4×37) - 3×37 = 7×164 - 31×37

so that x = 7 and y = -31.

Answer:

Kelly has read more of the book

Answer:

E 150

Step-by-step explanation:

The coordinates of the mid - point of the line AB is (-1, -5).

A midpoint is a point that divides a given line into two equal parts.

Given is that AB has endpoints at A(4, -8) and B(-6, -2). It is asked to find the coordinates of the midpoint of AB.

We can write the coordinates of the midpoint of AB as -

{x} = (x₁ + x₂)/2

{x} = (4 - 6)/2

{x} = - 2/2

{x} = -1

{y} = (y₁ + y₂)/2

{y} = (-8 - 2)/2

{y} = - 10/2

{y} = - 5

Therefore, the coordinates of the mid - point of the line AB is (-1, -5).

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Using proportions, it is found that the scale factor of the transformation is of 1/3.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, during the transformation, each coordinate was divided by 3, hence, applying the proportion, the scale factor of the transformation is of 1/3.

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Answer:

20 inches

Step-by-step explanation:

there is only 12 inches in a foot

Step-by-step explanation:

oksosjaoqkqeand

[tex]66 \sqrt[3x9 \frac{ \sqrt[xx. \sqrt[36 \sqrt[3136(2 > kaki \: kwl{]{?} ]{?} ]{?} }{?} ]{?} [/tex]

Answer:

Step-by-step explanation:

Answer: 123 boxes

Step-by-step explanation:

Find how many nails she used.

692-200=492

she used 492 nails

we know that 4 nails are needed to set up a box

so we divide.

492/4=123

Sally set up 123 boxes

Answer:

GCF=3[tex]x^{2}y[/tex]

Step-by-step explanation:

First, take a look at the numbers.

GCF of 15 and -18 = 3

Then, look at the variables.

GCF of (x^2)(y^3) and (x^3)(y)(z) = (x^2)(y)

Lastly, combine the two expressions

GCF = 3(x^2)(y)

Answer: 3(x^2)(y)

Hope this helps!

Answer:

0.267

Step-by-step explanation:

4/15 as a decimal is 0.26 repeating so rounded to the nearest thousandth would be 0.267

Answer:

option c

Step-by-step explanation:

a) NOT TRUE

A composite number is a positive integer that can be formed by multiplying two smaller positive integers.

3 and 7 are not composite numbers because each of them can only be divided by one and itself

b) NOT TRUE

2 is also a prime number so 3 and 7 are not the only numbers

c) TRUE

All the number listed are prime numbers hence why they are all at the bottom of the tree (only have 1 and itself as factors)

d) NOT TRUE

21 is not a prime number. The number 21 is divisible by 1, 3, 7, 21. For a number to be classified as a prime number, it should have exactly two factors. Since 21 has more than two factors, i.e. 1, 3, 7, 21, it is not a prime number.

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}[/tex]

[tex](\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}[/tex]

Answer:

Step-by-step explanation:

(2,1) and (4,2) are on the line.

slope

[tex]=\frac{2-1}{4-2} =\frac{1}{2} \\[/tex]

eq. of line is

[tex]y-1=\frac{1}{2} (x-2)\\2y-2=x-2\\2y=x\\or \\x-2y=0\\[/tex]

in slope intercept form

[tex]y=\frac{1}{2} x[/tex]

Answer:

38% is your answer boss. hope that helps :)

The percentage of people who supported the home team is 38 %

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

The total number of people attending the baseball game = 3500 people

The number of people supporting the home team = 1300 people

The number of people supporting the visiting team is = 2170

Now , the equation will be

The percentage of people supporting the home team is = number of people supporting the home team / total number of people attending the baseball game

Now , the equation will be

The percentage of people supporting the home team is A = ( 1300 / 3500 ) x 100

The percentage of people supporting the home team is A = 0.38 x 100

The percentage of people supporting the home team is A = 38 %

Therefore , the value of A is 38 %

Hence , The percentage of people who supported the home team is 38 %

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They want you to solve the iterative process to a point where the value of x is greater than or equal to 6 decimal places.

An iterative process is a mathematical approach that employs an initial value to build a series of improving estimated solutions for a problem, where the nth-term estimation is generated from the prior ones.

You're required to put the value of x₁ = -1 into the equation:

[tex]\mathbf{x_{n+1}= \dfrac{(x_n)^3-1}{4}}[/tex]

So;

[tex]\mathbf{x_{2}= \dfrac{(-1)^3-1}{4}}[/tex]

[tex]\mathbf{x_{2}=-0.5}[/tex]

[tex]\mathbf{x_{3}= \dfrac{(-0.5)^3-1}{4}}[/tex]

[tex]\mathbf{x_{3}=-0.28125}[/tex]

[tex]\mathbf{x_{4}=\dfrac{(-0.28125)^3-1}{4}}[/tex]

[tex]\mathbf{x_{4}=-0.2555618286}[/tex]

x₄ ≅ -0.255562  ( to 6 decimal places)

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#Part A

Volume of rectanglular prism

Volume of one cube

Total cubes

#2

Volume=

No of cubes ×volume of 1 cube

Answer:

A)  84 cubes

B)  Volume = 4 x 3 x 7 = 84 small cubes

    [tex]\sf Volume=3 \frac{1}{9}\:\:ft^3[/tex]

Step-by-step explanation:

As the lengths of each side of the small cube are ¹/₃ ft each, to find the number cubes in the rectangular prism, first find how many thirds are in each dimension of the prism:

[tex]\sf Length=1 \frac{1}{3}\:ft=\dfrac{4}{3}\:ft=4\:thirds[/tex]

[tex]\sf Width=1 \:ft=\dfrac{3}{3}\:ft=3\:thirds[/tex]

[tex]\sf height=2 \frac{1}{3}\:ft=\dfrac{7}{3}\:ft=7\:thirds[/tex]

Now simply multiply the number of thirds:

Number of cubes in prism = 4 x 3 x 7 = 84

As we have already found the dimensions of the prism in terms of the number of cubes, the volume of the prism in terms of the small cube is:

⇒ Volume = 4 x 3 x 7 = 84 small cubes

To find the volume of the prism in ft³, calculate the actual volume of the small cube:

[tex]\textsf{Volume of small cube}=\sf \dfrac{1}{3} \times \dfrac{1}{3} \times \dfrac{1}{3}=\dfrac{1}{27}\:ft^3[/tex]

Now multiply the volume in terms of number of cubes by the actual volume of a cube:

[tex]\begin{aligned}\textsf{Volume} &= \sf \textsf{Volume in cubes} \times \textsf{Volume of cube in ft}^3\\\\& = \sf 84 \times \dfrac{1}{27}\:ft^3\\\\& =\sf \dfrac{84}{27}\:ft^3\\\\& =\sf 3\frac{1}{9}\:ft^3\end{aligned}[/tex]

The regression equation of the data values is y = 0.3x^2 - 2.8x +4.2

Using a technology such as a graphing calculator, we simply input the data values in the graphing calculator and then wait for the result.

The x coordinates must be entered into the x values and the y coordinates must be entered into the y values

Using a graphing technology, the regression equation of the data values is y = 0.3x^2 - 2.8x +4.2

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Answer:

the unit cost per rubber tile is $$$$$$$$$$$$$6

Step-by-step explanation:

..

Using the line of best fit, it is found that the projected time for a man who is 166 cm tall is of 7.966 minutes.

It gives the project time in minutes to run the 3000 meters for a men of a height of x centimeters, according to the following function:

y = -0.081x + 21.412.

Hence, for a men of 166 centimeters, x = 166 and the projected time in minutes is given as follows.

y = -0.081(166) + 21.412 = 7.966.

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The products of the polynomials are:

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

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Answer:

V = 3053.63 mm^3

Step-by-step explanation:

radius : 9mm

V = 4/3 * pi * r^3

V = 4/3 * (3.1415926535898...) * 9^3

V = 3053.63 mm^3

Answer:

2

Step-by-step explanation:

because (x,y)=(1,2)

Therefore, domine(d)=(x)=1

And, range(r)=(y)=2

So the ans is 2