5.6t for t=0.7
(evaluate the expression)

-Q->P is proved from the contrapositive of 1.-P->Q.

What is Contrapostive ?

In logic, the contrapositive of a conditional statement of the form "if A, then B" is a statement of the form "if not B, then not A".

Here is a possible formal proof of the contrapositive of 1.-P->Q, which is -Q->P:

-P->Q Premise

Assume -Q Assume for sub proof

Assume -P Assume for subproof

From 2 and 1, we have P Modus tollens (MT)

From 4, we have P and -P Conjunction (CONJ)

From 3 and 5, we have # Contradiction (CONTR)

From 3-6, we have -Q-># Conditional proof (CP)

From 2 and 7, we have P Proof by contradiction (PC)

From 2-8, we have -Q->P Conditional proof (CP)

Therefore, -Q->P is proved from the contrapositive of 1.-P->Q.

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Answer: 18 pieces

Step-by-step explanation:

If she took 10 pieces and then each child received 2 pieces and she has four children then

10+2+2+2+2=

10+8=

18

The Taylor polynomials T2(x) and T3(x) for f(x) = sin(x) centered at x = 0 are given by T2(x) = x and T3(x) = x - x^3/6.

The Taylor polynomials for a function f(x) centered at x = a are given by

Tn(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + ... + f^(n)(a)(x-a)^n/n!

where f^(n)(a) represents the nth derivative of f(x) evaluated at x = a.

For f(x) = sin(x), we have

f(0) = sin(0) = 0

f'(x) = cos(x)

f'(0) = cos(0) = 1

f''(x) = -sin(x)

f''(0) = -sin(0) = 0

f'''(x) = -cos(x)

f'''(0) = -cos(0) = -1

Using these derivatives, we can calculate the Taylor polynomials

T2(x) = f(0) + f'(0)x/1! + f''(0)x^2/2!

= 0 + x/1! + 0x^2/2!

= x

T3(x) = f(0) + f'(0)x/1! + f''(0)x^2/2! + f'''(0)x^3/3!

= 0 + x/1! + 0x^2/2! - x^3/3!

= x - x^3/6

Therefore, the Taylor polynomials T2(x) and T3(x) for f(x) = sin(x) centered at x = 0 are

T2(x) = x

T3(x) = x - x^3/6

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The given differential equation xy" + 2y' - xy = 0 has a regular singular point at x=0, and the indicial roots of the singularity differ by an integer.

To show that the indicial roots of the singularity differ by an integer, we need to use the Frobenius method to obtain a series solution about x=0. The differential equation can be written as:

x^2y" + 2xy' - x^2y = 0

Assuming a series solution of the form y(x) = ∑n=0∞ anxn+r, we can substitute this into the differential equation and simplify the terms to obtain a recurrence relation for the coefficients an:

n(n+r)an + (n+2)(r+1)an+1 = 0

To ensure that the series solution converges, we require that the coefficient an does not become zero for all values of n, except for a finite number of cases. This condition leads to the indicial equation:

r(r-1) + 2r = 0

which gives the two indicial roots:

r1 = 0, r2 = -2

Since the difference between the two roots is an integer (2), we have shown that the indicial roots of the singularity differ by an integer.

Using r1 = 0 as the dominant root, the series solution for y(x) can be written as:

y1(x) = c0 + c1x - (c1/4)x^2 + (c1/36)x^3 - (c1/576)x^4 + ...

Using the formula (23) in Section 6.3, we can find a second linearly independent solution y2(x) in terms of y1(x) as:

y2(x) = y1(x) ∫ (e^-∫P(x)dx / y1^2(x))dx

where P(x) = 2/x - x. After simplification, we get:

y2(x) = c2x^2 + c3x^3 + (2c1/9)x^4 + ...

Therefore, the general solution of the given differential equation on (0,0) can be written as:

y(x) = c1x - (c1/4)x^2 + (c1/36)x^3 - (c1/576)x^4 + c2x^2 + c3x^3 + (2c1/9)x^4 + ...

or, simplifying further:

y(x) = x[c1 + c2x + c3x^2] + c1x[1 - (1/4)x + (1/36)x^2 - (1/576)x^3] + ...

where c1, c2, and c3 are constants determined by the initial/boundary conditions.

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The probability that all four switches work is 0.0033 or approximately 0.33%.

Given that each switch has a probability of .24 of working, we can use the following steps:

1. Understand that the probability of all four switches working is the product of their individual probabilities, since they work independently.
2. Multiply the probabilities: .24 (switch 1) × .24 (switch 2) × .24 (switch 3) × .24 (switch 4).

The probability that each switch works is 0.24. Since the switches work independently, we can multiply the probabilities to find the probability that all four switches work:

P(all four switches work) = 0.24 x 0.24 x 0.24 x 0.24

P(all four switches work) = 0.00327648

Rounding to four significant figures, we get:

P(all four switches work) ≈ 0.0033

Your answer: The probability that all four switches work is .24 × .24 × .24 × .24 = 0.0033.

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Your answer is :-skew-symmetric.

We will show that if A is any n x n matrix, then (i) AAT is symmetric, and (ii) A - AT is skew-symmetric.

(i) To show that AAT is symmetric, we need to prove that (AAT)T = AAT. Here's the step-by-step explanation:

1. Compute the transpose of AAT, denoted as (AAT)T.
2. Using the reverse rule of transposes, we get (AAT)T = (AT)T * AT.
3. Since the transpose of a transpose is the original matrix, we have (AT)T = A.
4. Therefore, (AAT)T = A * AT = AAT, proving that AAT is symmetric.

(ii) To show that A - AT is skew-symmetric, we need to prove that (A - AT)T = -(A - AT). Here's the step-by-step explanation:

1. Compute the transpose of A - AT, denoted as (A - AT)T.
2. Using the properties of transposes, we get (A - AT)T = AT - A.
3. Now, we can observe that AT - A is the negation of A - AT, which is -(A - AT).
4. Therefore, (A - AT)T = -(A - AT), proving that A - AT is skew-symmetric.

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The calculated t-value is 1.75. To determine whether this t-value is significant, we would need to compare it to the critical t-value for df = 8 and the desired level of significance. However, the question only asks whether the t-value is +1.75, which is true.

To determine if the statement is true or false, we will first calculate the t statistic for the given data using the formula for a repeated-measures t-test:
t = (M - μ) / (s / sqrt(n))
where M is the mean of the difference scores, μ is the population mean (in this case, 0 because we're testing for differences), s is the standard deviation (square root of the variance), and n is the number of difference scores (df + 1).
Given:
Mean of difference scores (M) = 3.5
Variance (s^2) = 36
Degrees of freedom (df) = 8
First, calculate the standard deviation (s) and the sample size (n):
s = sqrt(s^2) = sqrt(36) = 6
n = df + 1 = 8 + 1 = 9
Now, calculate the t statistic:
t = (3.5 - 0) / (6 / sqrt(9)) = 3.5 / (6 / 3) = 3.5 / 2 = 1.75
The calculated t statistic is indeed 1.75, which matches the provided value in the statement. Therefore, the statement is true.

True.
To calculate the t-statistic for a repeated-measures design, we use the formula:
t = (Mdiff - μdiff) / (sd_diff / √n)
where Mdiff is the mean of the difference scores, μdiff is the population mean of the difference scores (which we assume is 0), sd_diff is the standard deviation of the difference scores, and n is the sample size.
We are given that the mean of the difference scores (Mdiff) is 3.5 and the variance (s2) is 36. To find the standard deviation, we take the square root of the variance:
sd_diff = √s2 = √36 = 6
The sample size is not given, but we know that the degree of freedom (df) is 8. For a repeated-measures design, df = n - 1. Solving for n:
8 = n - 1
n = 9
Now we can plug in all the values into the t-formula:
t = (3.5 - 0) / (6 / √9) = 1.75

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The area of the triangle is 3.535533, whose vertices are  (0,0,0), (1,3,−1), and (2,1,1) .

Explanation: -

To find the area of the triangle with vertices (0,0,0), (1,3,-1), and (2,1,1), you can use the formula for the area of a triangle in 3D space:

Area = 0.5 * ||AB x AC||

Here, AB and AC are the vectors representing the sides of the triangle, and "x" denotes the cross product.

STEP 1:- Find the vectors AB and AC:
AB = B - A = (1,3,-1) - (0,0,0)

     = (1,3,-1)
AC = C - A = (2,1,1) - (0,0,0)

     = (2,1,1)

STEP 2: - Compute the cross product AB x AC:
AB x AC = (3 * 1 - (-1) * 1, -(1 * 1 -(- 1 )* 2), 1 * 1 - 3 * 2)
AB x AC = (3 + 1, 3, 1 - 6)

              = (4, 2, -5)

STEP 3: - Compute the magnitude of the cross product ||AB x AC||:
||AB x AC|| = √(4² + (-3)² + (-5)²)

                  = √(16 + 9 + 25)

                  = √50

                  =7.071060

STEP 4: - Calculate the area of the triangle:
Area = 0.5 * ||AB x AC|| = 0.5 * (7.071060)

Therefore, the area of the triangle is 3.535533.

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Algebraically, the behaviour of the integral ∫(0 to ∞) (1/4x²) dx is that it diverges to infinity.

To determine the behaviour of the integral ∫(0 to ∞) (1/4x²) dx algebraically. Here's a step-by-step explanation:
1. First, rewrite the integral using proper notation:
  ∫(0 to ∞) (1/4x²) dx
2. Use the power rule for integration, which states that the integral of x^n is (x^(n+1))/(n+1), where n is a constant:
  ∫(1/4x²) dx = -1/(4(x))
3. Now, we will evaluate the indefinite integral from 0 to ∞:
  -1/(4(∞)) - (-1/(4(0)))
4. As x approaches ∞, the value of -1/(4x) approaches 0:
  0 - (-1/(4(0)))
5. As x approaches 0, -1/(4x) approaches infinity. However, since this is an improper integral, we need to consider a limit:
  lim(a->0) (-1/(4(a))) = ∞
So, algebraically, the behaviour of the integral ∫(0 to ∞) (1/4x²) dx is that it diverges to infinity.

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Answer:

72

Step-by-step explanation:

12x12 is 144

and 144/2 is 72

Answer:

72

Step-by-step explanation:

12 X 12 = 144

Then you divide the answer to 2 and you get 72

You're Welcome! :D

The probability of x' bar to be greater than 59 is equal to 0.1193.

What is Mean value?

Apart from mode and median, mean is the one of the measures of central tendency. When we do the average of given set of values, it is called mean. Here in this question we need to check if the data meets the criterion for a normal distribution. One of these criterion is that data should be symmetric & bell shaped and another one is that mean and median should be approximately equal. By adding the total values given in the datasheet and dividing the sum by total no of values we will get the value of mean.

Here, the mean is = 162 point, the standard deviation = 140 point and x is considered as a variable for household water use in the country

μ=162

σ=140

X:- household water use for country

i.e., approx. Normal

(b) n=50

    n>30

i.e., approx. normal

(c) P(X'>59) = 1 - P(X'≤59)

                  = 1- P((X'-μ)/(σ/√n)≤59-57/(12/√50))

                  = 1- P(z ≤ 1.178)

                  = 1-0.8807

    P(X'>59)= 0.1193

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To evaluate the integral ∫1−1(|2x|+2) dx exactly using the technique of example 2 in the text, we first split the integral into two parts:

∫1−1(|2x|+2) dx = ∫1^0 (-2x + 2) dx + ∫0^-1 (2x + 2) dx

Next, we can simplify the absolute values:

∫1^0 (-2x + 2) dx + ∫0^-1 (2x + 2) dx = ∫1^0 (-2x + 2) dx + ∫0^-1 (-2x + 2) dx

Now we can integrate each part:

∫1^0 (-2x + 2) dx + ∫0^-1 (-2x + 2) dx = [-x^2 + 2x]1^0 + [-x^2 + 2x]0^-1

Simplifying further, we get:

[-1^2 + 2(1)] - [0^2 + 2(0)] + [0^2 + 2(0)] - [-(-1)^2 + 2(-1)]
= 1 + 1 + 1 = 3

Therefore, the exact value of the integral ∫1−1(|2x|+2) dx is 3.
To evaluate the integral ∫₁₋₁ (|2x|+2) dx, we first need to split the integral into two parts due to the absolute value function.

For x >= 0, |2x| = 2x, and for x < 0, |2x| = -2x.

Now, we split the integral into two parts:

∫₁₋₁ (|2x|+2) dx = ∫₀₋₁ (-2x+2) dx + ∫₁₀ (2x+2) dx.

Now, we evaluate each integral separately:

∫₀₋₁ (-2x+2) dx = [-x²+2x]₀₋₁ = (1-2)-(0) = -1.

∫₁₀ (2x+2) dx = [x²+2x]₁₀ = (1+2)-(0) = 3.

Finally, we add the two results together:

∫₁₋₁ (|2x|+2) dx = -1 + 3 = 2.

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We can use similar methods to rewrite the expressions in problems 19 through 22 as single power series.

To rewrite each of the expressions in problems 18 through 22 as a single power series whose generic term involves xn, we can use the formula for a geometric series. This formula states that a geometric series with first term a and common ratio r can be expressed as:

a + ar + ar² + ar³ + ...

We can rewrite this formula in terms of xn by letting a = f(21) and r = (x - 21)/21. Then, the nth term of the series is given by:

f(21) ˣ [(x - 21)/21]^n

Using this formula, we can rewrite each of the given expressions as a single power series whose generic term involves xn.

For example, in problem 18, we are given the expression:

f(x) = 1/(x² - 4x + 3)

We can factor the denominator as (x - 1)(x - 3) and write:

f(x) = 1/[(x - 1)(x - 3)]

Using partial fractions, we can express f(x) as:

f(x) = 1/(2(x - 1)) - 1/(2(x - 3))

Now, we can use the formula for a geometric series with a = 1/2, r = (x - 21)/21, and n = k - 21 to write:

f(x) = 1/2 ˣ [(x - 21)/21]²¹ - 1/2 * [(x - 21)/21]²³ + ...

This is a single power series whose generic term involves xn. We can use similar methods to rewrite the expressions in problems 19 through 22 as single power series.

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This series is an arithmetic series, as the difference between consecutive terms is a constant, the series goes to infinity, meaning it has an infinite number of terms. Since the arithmetic series has an infinite number of terms, it is divergent. Therefore, the answer is DIVERGES.

To determine whether the series ∑n=1∞(4n+1)/(5−n) is convergent or divergent, we can use the ratio test:

lim┬(n→∞)⁡|((4(n+1)+1)/(5-(n+1)))/((4n+1)/(5-n))|

= lim┬(n→∞)⁡|(4n+5)(5-n)/(4n+1)(6-n)|

= 4/6 = 2/3

Since the limit is less than 1, the series is convergent by the ratio test.

To find the sum of the series, we can use the formula for the sum of a convergent geometric series:

S = a/(1-r)

where a is the first term and r is the common ratio. In this case, we have:

a = (4(1)+1)/(5-1) = 5/4

r = (4(2)+1)/(5-2) / (4(1)+1)/(5-1) = 13/6

Therefore, the sum of the series is:

S = (5/4) / (1-(13/6)) = 15/23
The given series is:

∑(4n + 15 - n) from n=1 to infinity.

First, simplify the series:

∑(3n + 15) from n=1 to infinity.

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The correct result for solving the radical equation √(2x - 7) = 9 is derive to be 2x - 7 = 81, which makes the variable x = 44

In mathematics, the symbol √ is used to represent or show that a number is a radical. Radical equation is defined as any equation containing a radical (√) symbol.

The radical symbol for the equation √(2x - 7) = 9 can be removed squaring both sides as follows;

[√(2x - 7)]² = 9²

(2x - 7)^(2/2) = 9 × 9

2x - 7 = 81

the value of the variable x can easily then be derived as follows:

2x = 81 + 7 {collect like terms}

2x = 88

x = 88/2 {divide through by 2}

x = 44

Therefore, removing the radical symbol by squaring both sides of the equation will result to 2x - 7 = 81, and the variable x = 44

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If a straight line joins the points A (2, 1) and B (8, 10) and the point C (6, y) lies on the line AB. Then the y-coordinate of C is 7.

A line is a geometric object in mathematics that extends infinity in both directions and is symbolised by a straight line that never ends.

Two points, referred to as endpoints, define it as being one-dimensional and lacking in both width and depth.

A line equation has the slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.

A number of real-world situations, such as the motion of an object or the direction of a force, can be modelled and described using lines.

We can find the equation of line AB using the two given points A and B:

Slope of AB = (change in y) / (change in x) = (10 - 1) / (8 - 2) = 9/6 = 3/2

Using point-slope form with point A:

y - 1 = (3/2)(x - 2)

Simplifying, we get:

y - 1 = (3/2)x - 3

y = (3/2)x - 2

Now we substitute x = 6 to find the y-coordinate of C:

y = (3/2)(6) - 2

y = 7

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The critical point of f(x) in the interval [0,2π] is x = π/4.

To find the critical points of a function, we need to find the values of x where the derivative of the function is zero or undefined.

First, let's find the derivative of f(x):

f'(x) = 5(cos^2(x) - sin^2(x))

Next, we need to find the values of x where f'(x) = 0 or is undefined.

Setting f'(x) = 0:

5(cos^2(x) - sin^2(x)) = 0

cos^2(x) - sin^2(x) = 0

Using the identity cos^2(x) - sin^2(x) = cos(2x), we get:

cos(2x) = 0

This means that 2x = π/2 or 2x = 3π/2, since the cosine function is zero at these angles.

Solving for x, we get:

x = π/4 or x = 3π/4

However, we need to check if these points are in the interval [0,2π]. Only x = π/4 is in this interval.

Therefore, the critical point of f(x) in the interval [0,2π] is x = π/4.

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A. The expression for the fish population P(t) at time t in years is:
P(t) = 20,000 / (1 + (25 - 1) * e^(-ln(2)t))

B. It will take approximately 7.637 years for the fish population to reach 10,000.

(A) To find an expression for the size of the fish population P at time t in years, we can use the logistic model:
P(t) = K / (1 + e^(-kt))

where P(t) is the population size at time t, K is the carrying capacity (in this case, K = 20000), and k is a constant representing the rate of growth.

To find k, we can use the fact that the number of fish doubled in the first year:
800 * 2 = 1600

So the initial population size P(0) is 800, and the population size after one year (t=1) is 1600. Substituting these values into the logistic model, we get:
1600 = 20000 / (1 + e^(-k*1))

Solving for k, we get:
k = 1.098612
Rounding to six decimal places, k ≈ 1.098612.

Now we can plug in this value of k and the given value of K to get the expression for P(t):
P(t) = 20000 / (1 + e^(-1.098612t))

(B) To find out how long it will take for the fish population to reach 10000, we can set P(t) equal to 10000 and solve for t:
10000 = 20000 / (1 + e^(-1.098612t))

Multiplying both sides by the denominator and simplifying, we get:
1 + e^(-1.098612t) = 2

Subtracting 1 from both sides, we get:
e^(-1.098612t) = 1

Taking the natural logarithm of both sides, we get:
ln(e^(-1.098612t)) = ln(1)

Simplifying, we get:
-1.098612t = 0

Dividing both sides by -1.098612, we get:
t ≈ 0.693

Rounding to three decimal places, it will take approximately 0.693 years (or about 8 months) for the fish population to reach 10000.

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The correct answer is (b) fraction numerator cos squared x over denominator 2 end fraction minus fraction numerator cos cubed x over denominator 3 end fraction plus C.

To evaluate the integral, we can use the identity sin²(x) + cos²(x) = 1 to write sin³(x) = sin²(x) × sin(x) = (1 - cos²(x)) × sin(x). Then, we can use u-substitution with u = cos(x) and du = -sin(x) dx to get:

integral sin³(x) cos²(x) dx = -integral (1 - u²) u² du
= integral (u⁴ - u²) du
= (1/5)u⁵ - (1/3)u³ + C
= (1/5)cos⁵(x) - (1/3)cos³(x) + C

Using the identity cos²(x) = 1 - sin²(x), we can also write the answer as:

(1/2)cos²(x) - (1/3)cos³(x) + C

Therefore, the correct answer is (b) fraction numerator cos squared x over denominator 2 end fraction minus fraction numerator cos cubed x over denominator 3 end fraction plus C.

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These are the z-scores that correspond to the 0.005 area in each tail. If a test statistic falls beyond these boundaries (either below -2.576 or above 2.576), it would be in the critical region, and you would reject the null hypothesis.

The critical region, tails, and z-score are essential concepts in hypothesis testing. Let's explore how these terms relate to the given alpha level (α = 0.01).

The critical region is the area in the tails of a distribution where we reject the null hypothesis if the test statistic falls within this region. In other words, it's the area where the probability of finding the test statistic is very low if the null hypothesis were true.

Tails refer to the extreme ends of a distribution. In a standard normal distribution, tails are the areas to the left and right of the main portion of the curve.

The z-score (or standard score) is a measure that expresses the distance of a data point from the mean in terms of standard deviations.

For an alpha level (α) of 0.01, you want to find the z-score boundaries that correspond to the critical region. In this case, the critical region will be in both tails, with a total area of 0.01. Since there are two tails, each tail will contain an area of 0.005 (0.01 / 2).

Using a z-score table or calculator, you can find the z-score boundaries for α = 0.01 as:

z = 2.576 and z = -2.576

These are the z-scores that correspond to the 0.005 area in each tail. If a test statistic falls beyond these boundaries (either below -2.576 or above 2.576), it would be in the critical region, and you would reject the null hypothesis.

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After simplification, the exact value of the expression "4/5 × 15/8 × 14/5" is 21/5.

To find the simplified-value of the expression, we simply multiply the numerators and denominators of the fractions in the order given, and then simplify the resulting fraction:

The expression given for simplification is : 4/5 × 15/8 × 14/5;

So, We first write and multiply all the numerators and denominators together,

We get,

4/5 × 15/8 × 14/5 = (4×15×14)/(5×8×5),

⇒ 840/200,

Now, we simplify the above fraction,

We get,

= 21/5.

Therefore, the simplified value is 21/5.

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The given question is incomplete, the complete question is

Find the exact value of the expression "4/5 × 15/8 × 14/5".

The maximum profit Katie can earn is $85.

To find this, we need to use the vertex formula, which gives us the x-coordinate of the vertex of the parabola representing the profit function.

The formula is x = -b/2a, where a is the coefficient of the x-squared term (-1 in this case) and b is the coefficient of the x term (14 in this case). So, x = -14/(2*(-1)) = 7. Plugging this value into the profit function gives us P(7) = -7² + 14(7) + 57 = 85.

The profit function given is a quadratic function, which has a parabolic graph. The vertex of the parabola represents the maximum or minimum point of the function, depending on whether the leading coefficient is negative or positive. In this case, the leading coefficient is negative, so the vertex represents the maximum profit.

To find the x-coordinate of the vertex, we use the formula x = -b/2a, which gives us the value of x that makes the profit function equal to its maximum value. Once we have this value, we plug it back into the profit function to find the corresponding maximum profit. In this case, the maximum profit is $85.

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The maximum profit Katie can earn is $85.

To find this, we need to use the vertex formula, which gives us the x-coordinate of the vertex of the parabola representing the profit function.

The formula is x = -b/2a, where a is the coefficient of the x-squared term (-1 in this case) and b is the coefficient of the x term (14 in this case). So, x = -14/(2*(-1)) = 7. Plugging this value into the profit function gives us P(7) = -7² + 14(7) + 57 = 85.

The profit function given is a quadratic function, which has a parabolic graph. The vertex of the parabola represents the maximum or minimum point of the function, depending on whether the leading coefficient is negative or positive. In this case, the leading coefficient is negative, so the vertex represents the maximum profit.

To find the x-coordinate of the vertex, we use the formula x = -b/2a, which gives us the value of x that makes the profit function equal to its maximum value. Once we have this value, we plug it back into the profit function to find the corresponding maximum profit. In this case, the maximum profit is $85.

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4 mugs are required to fill if David made 4/3 of a quart of fruit juice. In each mug, he held 1/3 of a quart as per the fractions.

Fruit juice quart = 4/3

Holdes of quart =  1/3

This can be calculated by using the division of fractions. The number of mugs that can be filled will be calculated by using the fraction equation of division of quart of juice and holdes.

Mathematically,

number of mugs  = 4/3 ÷ 1/3

number of mugs  = 4/3 × 3/1

number of mugs = 4

Therefore we can conclude that David will able to fill in 4 mugs.

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Answer:  [DISCLAIMER]: All answers are rounded to the nearest hundredth of a decimal

f(1) = 5.20 ; f(2) = 14.70 ; f(3) = 27 ; f(4) = 41.57

Step-by-step explanation:

f(1) = (1 + [2×1])[tex]^{3/2}[/tex]

f(1) = (1 + 2)[tex]^{3/2}[/tex]

f(1) = (3)[tex]^{3/2}[/tex]

f(1) ≈ 5.20

f(2) = (2 + [2×2])[tex]^{3/2}[/tex]

f(2) = (2 + 4)[tex]^{3/2}[/tex]

f(2) = (6)[tex]^{3/2}[/tex]

f(2) ≈ 14.70

f(3) = (3 + [2×3])[tex]^{3/2}[/tex]

f(3) = (3 + 6)[tex]^{3/2}[/tex]

f(3) = (9)[tex]^{3/2}[/tex]

f(3) = 27

f(4) = (4 + [2×4])[tex]^{3/2}[/tex]

f(4) = (4 + 8)[tex]^{3/2}[/tex]

f(4) = (12)[tex]^{3/2}[/tex]

f(4) ≈ 41.57

The probability that the next person will purchase no costume is 36% to the nearest whole number.

We have,

To express the probability that the next person will purchase no costume as a percent to the nearest whole number, we need to use the total number of visitors to the website as the denominator and the number of visitors who purchased no costume as the numerator.

The total number of visitors to the website is:

168 + 252 + 47 = 467

The number of visitors who purchased no costume is 168.

So the probability that the next person will purchase no costume is:

168/467 = 0.3609

To express this as a percent, we multiply by 100:

0.3609 × 100

= 36.09

Rounding this to the nearest whole number, we get:

36%

Therefore,

The probability that the next person will purchase no costume is 36% to the nearest whole number.

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The interval of convergence is (-18/5, 18/5).

To express f(x) as a power series, we first need to decompose it into partial fractions:

f(x) = 11/(x^2 - 7x - 18) = 11/[(x - 9)(x + 2)]

Using partial fractions, we can write:

11/[(x - 9)(x + 2)] = A/(x - 9) + B/(x + 2)

Multiplying both sides by the denominator (x - 9)(x + 2), we get:

11 = A(x + 2) + B(x - 9)

Setting x = 9, we get:

11 = A(9 + 2)

A = 1

Setting x = -2, we get:

11 = B(-2 - 9)

B = -1

Therefore, we have:

f(x) = 1/(x - 9) - 1/(x + 2)

Now, we can write the power series of each term using the formula for a geometric series:

1/(x - 9) = -1/18 (1 - x/9)^(-1) = -1/18 * sigma^n=0 to infinity (x/9)^n

1/(x + 2) = 1/11 (1 - x/(-2))^(-1) = 1/11 * sigma^n=0 to infinity (-x/2)^n

So, putting everything together, we get:

f(x) = 1/(x - 9) - 1/(x + 2) = -1/18 * sigma^n=0 to infinity (x/9)^n + 1/11 * sigma^n=0 to infinity (-x/2)^n

The interval of convergence can be found using the ratio test:

|a_n+1 / a_n| = |(-x/9)^(n+1) / (-x/9)^n| + |(-x/2)^(n+1) / (-x/2)^n|

= |x/9| + |x/2|

= (|x|/9) + (|x|/2)

For the series to converge, we need |a_n+1 / a_n| < 1. This happens when:

(|x|/9) + (|x|/2) < 1

Solving for |x|, we get:

|x| < 18/5

Therefore, the interval of convergence is (-18/5, 18/5).

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Answer:

Graph X

since it works ...............................................

The inflection points occur at x = 0 and x = 5.

To find the x-coordinates of the inflection points for the polynomial p(x) = [tex]x^5/20 - 5x^4/12[/tex] + 2022/π, follow these steps:

1. Compute the second derivative of p(x):
  First derivative: p'(x) =[tex](5x^4)/20 - (20x^3)/12[/tex]
  Second derivative: p''(x) = [tex](20x^3)/20 - (60x^2)/12 = x^3 - 5x^2[/tex]
2. Set the second derivative equal to zero and solve for x:
[tex]x^3 - 5x^2 = 0[/tex]
 [tex]x^2(x - 5) = 0[/tex]

3. Find the x-coordinates where the second derivative is zero:
  x = 0 and x = 5

These x-coordinates are the inflection points for the polynomial p(x) = [tex]x^5/20 - 5x^4/12[/tex] + 2022/π. So, the inflection points occur at x = 0 and x = 5.

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Using a t-table or calculator, the t-distribution for an upper tail area of 0.025 with 15 degrees of freedom. The final answer (a) -2.021 and 2.021 (b) -1.675 (c) 0.873, (d) -2.845 and 2.845. (e) -2.021 and 2.021,

a. Using a t-table or calculator, the t-distribution for an upper tail area of 0.025 with 15 degrees of freedom is 2.131. T-values, where 95% of the area falls between, are -2.021 and 2.021.

b. Using a t-table or calculator, the t-value for a lower tail area of 0.05 with 55 degrees of freedom is -1.675.

c. Using a t-table or calculator, the t-value for an upper tail area of 0.20 with 35 degrees of freedom is 0.873.

d. The t-values corresponding to 0.01 and 0.99 quantiles for a t-distribution with 20 degrees of freedom are -2.845 and 2.845, respectively. Therefore, the t-values where 98% of the area falls between are -2.845 and 2.845.

e. The t-values corresponding to 0.025 and 0.975 quantiles for a t-distribution with 40 degrees of freedom are -2.021 and 2.021, respectively.

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The set corresponding to (a∪b)∩c is {3, 4, 5, 7, 9}.

To find the set corresponding to (a∪b)∩c, first perform the union of sets a and b, and then find the intersection with set c.

1. Union (a∪b):

a={x∈:x is a prime number}, b={4,7,9,11,13,14}.

Combine prime numbers and elements of set b:

{2, 3, 5, 7, 11, 13, 4, 7, 9, 11, 13, 14} and remove duplicates to get

{2, 3, 4, 5, 7, 9, 11, 13, 14}.

2. Intersection with c: (a∪b)∩c:

c={x∈:3≤x≤10}, meaning c={3, 4, 5, 6, 7, 8, 9, 10}.

Find the elements that are common between (a∪b) and c, so we get the set as {3, 4, 5, 7, 9}.

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